The vapor pressure of the solution can be calculated using Raoult's law. First, we need to calculate the mole fraction of glycerol and water in the solution. Then, we can use the mole fraction to calculate the vapor pressure of the solution.
Explanation:In order to find the vapor pressure of the solution, we can use Raoult's law. Raoult's law states that the vapor pressure of a solution is equal to the mole fraction of the solvent multiplied by the vapor pressure of the pure solvent.
First, we need to calculate the mole fraction of glycerol in the solution. To do this, we need to convert the mass percent of glycerol to moles. Since the molar mass of glycerol is 92.1 g/mol and the solution contains 34.4% glycerol by mass, we can calculate the moles of glycerol:
Moles of glycerol = (34.4 g / 92.1 g/mol)
Next, we need to calculate the mole fraction of water in the solution. Since the solution is 34.4% glycerol, the mass percent of water is 100% - 34.4% = 65.6%. Using the molar mass of water (18.0 g/mol), we can calculate the moles of water:
Moles of water = (65.6 g / 18.0 g/mol)
Now we can calculate the mole fraction of glycerol and water:
Mole fraction of glycerol = (moles of glycerol) / ((moles of glycerol) + (moles of water))
Mole fraction of water = (moles of water) / ((moles of glycerol) + (moles of water))
Finally, we can calculate the vapor pressure of the solution using Raoult's law:
Vapor pressure of solution = (mole fraction of water) * (vapor pressure of water)
Which of the following statements about ethylene and polyethylene is true?
A) The polymer has the same properties as the monomer.
B) The polymer has alternating double and single bonds between carbons, while the monomer has only single bonds between carbons.
C) The polymer has alternating double and single bonds between carbons, while the monomer has only double bonds between carbons.
D) The polymer has only single bonds between carbons, while the monomer has only double bonds between carbons.
Answer:
D is the correct option.
Explanation:
The structure of ethene/ethyelene is : [tex]H_{2}[/tex]C==C[tex]H_{2}[/tex]The carbon atoms are bonded together by a double bond.
The structure of polyethylene/polythene is: (-[tex]H_{2}[/tex]C-C[tex]H_{2}[/tex]-[tex])_{n}[/tex]The carbon atoms are bonded together by single bonds.
Lets analyse each option:
A) Its false. Lets look at the obvious: Ethylene is a gas and polyethylene is a solid. Monomers and polymers have very different properties.
B) Its false. Polyethylene doesnt have double bonds.
C) False as well. Polyethylene doesnt have double bonds.
D) True. It is evident from the structure of the the monomer and polymer that I've shown above. I'll also provide neat structures in the attachments.
What is the hybridization of the central atom of molecules?
Explanation:
The number of electron density regions that encircle an atom is calculated by the steric number, which also defines the hybridisation of the central atom. In that scenario, there are six hybridised orbitals in the central atom, leading to a [tex]\displaystyle sp3d^2[/tex]hybridization.
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Match the following:
Part A
1. matter with no definite shape or volume
2. matter with no definite shape but with definite volume
3. the process of a solid changing directly to a gas without forming a liquid
4. matter in a high-energy state in which electrons are separated from their nuclei
5. matter with definite shape and volume
6. weak electrostatic bonds that form between particles of a substance
Part B
a. gas
b. intermolecular bonds
c. liquid
d. plasma
e. solid
f. sublimation
Answer:
The answer to your questions is below
Explanation:
1.- Gas matter with no definite shape or volume
2.- Liquid matter with no definite shape but with definite volume
3.- Sublimation the process of a solid changing directly to a gas without forming a liquid.
4.- Plasma matter in a high-energy state in which electrons are separated from their nuclei
5.- Solid matter with definite shape and volume
6.- Intermolecular bonds weak electrostatic bonds that form between particles of a substance
Final answer:
The matchings are 1-a, 2-c, 3-f, 4-d, 5-e, and 6-b, identifying the physical state or process corresponding to each description given in Part A using basic knowledge of the properties of the different states of matter.
Explanation:
To match the given descriptions in Part A with the correct terms in Part B, we need to understand the basic properties of the different states of matter and recognize the processes they undergo:
Gas: Matter with no definite shape or volume.
Liquid: Matter with no definite shape but with definite volume.Sublimation: The process of a solid changing directly to a gas without forming a liquid.Plasma: Matter in a high-energy state in which electrons are separated from their nuclei.Solid: Matter with definite shape and volume.Intermolecular bonds: Weak electrostatic bonds that form between particles of a substance.The following ions contain the same number of electrons. Rank them in order of decreasing ionic radii.?A. Na+B. Mg 2+C. Al 3+D. O 2-E. N 3-F. F -
Answer:
N3- > O2- > F- > Na+ > Mg2+ > Al3+
Explanation:
The ionic radio can simply be defined as the distance from the center of the nucleus to the electron in the outermost shell.
It should be noticed that all these ions belong to elements in group 3 of the periodic table.
It must be noted that anions I.e negative ions are generally bigger than anions.
Hence, it is expected that the negative ions are bigger. The arrangement goes thus:
N3- > O2- > F- > Na+ > Mg2+ > Al3+
The ions are ranked according to the number of protons in their nucleus, from least to most, which corresponds to the decreasing ionic radii. Therefore, the order of decreasing ionic radii is: N 3-, O 2-, F -, Na+, Mg 2+, Al 3+.
Explanation:The ions Na+, Mg 2+, Al 3+, O 2-, N 3- and F - all contain the same number of electrons so they are considered isoelectronic. The size of isoelectronic species depends on their nuclear charges, that is, the number of protons in their nucleus. An ion with more protons will have a stronger nuclear charge which attracts the negatively charged electrons more, causing the ion to be smaller.
So, when you put the ions in order of decreasing ionic radii, the ion with the most protons will be the smallest. Therefore, the order of decreasing ionic radii will be: N 3- < O 2- < F - < Na+ < Mg 2+ < Al 3+. This indicates that N 3- has the largest ionic radius while Al 3+ has the smallest ionic radius among these ions.
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In this experiment, direct titration of a base with acid is not used. Instead, a back titration of a base with excess acid will be employed. Why?
a. The CO2 gas is released during the chemical reaction and is a slow step
b. There is a time delay between the addition of the acid and the completion of the reaction
c. The endpoint of the titration would be unclear because straight titration does not allow enough reaction timed
d. none of the above
e. all of the above
None of the options are not used in this experiment, hence "all of the above" is the correct answer.
Option: E
Explanation:
In the above experiment "back titration" is opted because of the need to determine "strength of an analyte" as "molar concentration" of an excess reactant is known. It is done when acid or mostly base is an insoluble salt, when reaction take palce very slowly and definitely when endpoint would be hard to discern for example titration of weak acid and weak base. The procedure to follow back titration is firstly the volatile analyte is reacted with an excess reagent then the titration is done on remaining amount of known solution.
The cost, C C, of producing x x Totally Cool Coolers is modeled by the equation C = 0.005 x 2 − 0.25 x + 12 C=0.005x2-0.25x+12 How many coolers need to be produced and sold in order to minimize the cost? (Round to the nearest whole number.)
Answer:
25 coolers are need to be produce and sell in order to minimize the cost.
Explanation:
[tex]C = 0.005x^2-0.25x+12[/tex] ..[1]
Differentiating the given expression with respect to dx.
[tex]\frac{dC}{dx}=\frac{d(0.005x^2-0.25x+12)}{dx}[/tex]
[tex]\frac{dC}{dx}=0.01x-0.25+0[/tex]
Putting ,[tex]\frac{dC}{dx}=0[/tex]
[tex]0=0.01x-0.25+0[/tex]
[tex]0.01x=0.25[/tex]
x = 25
Taking second derivative of expression [1]
[tex]\frac{d^2C}{dx^2}=\frac{d(0.01x-0.25)}{dx}=0.01[/tex]
[tex]\frac{d^2C}{dx^2}>0[/tex] (minima)
25 coolers are need to be produce and sell in order to minimize the cost.
A 1.2-L container of liquid nitrogen is kept in a closet measuring 1.0m by 1.3m by 2.0m . Assume that the container is completely filled to the top with liquid nitrogen, that the temperature is 23.5?C, and that the atmospheric pressure is 1.2atm .Calculate the percent (by volume) of air that would be displaced if all of the liquid nitrogen evaporated into the closet. The closet is ventilated such that the temperature and pressure remain constant through this process. (Liquid nitrogen has a density of 0.807 g/mL.)
Answer:
26.99 % of air that will be displaced
Explanation:
Step 1: Data given
A 1.2-L container of liquid nitrogen is kept in a closet measuring 1.0m by 1.3m by 2.0m
Temperature = 23.5 °C
Atmospheric pressure = 1.2 atm
Liquid nitrogen has a density of 0.807 g/mL
Molar mass of N2 = 28 g/mol
Step 2: Calculate mass of nitrogen
Mass of nitrogen = density * volume
Mass of nitrogen = 0.807 g/mL * 1200 mL
Mass of nitrogen = 968.4 grams
Step 3: Calculate moles of N2
Moles N2 = mass N2 / molar mass N2
Moles N2 = 968.4 grams /28 g/mol
Moles N2 = 34.586 moles
Step 4: Calculate volume
p*V = n*R*T
⇒ p = the the pressure = 1.2 atm
⇒ V = the volume of N2 = TO BE DETERMINED
⇒ n = the number of moles = 34.586 moles
⇒ R = the gas constant = 0.08206 L*atm/K*mol
⇒ T = the temperature = 23.5 °C = 296.65
V = (n*R*T)/p
V = (34.586 * 0.08206 * 296.65)/1.2
V = 701.61 L
Step 5: Calculate the total volume of the chamber
1.0 m * 1.3 m * 2 m = 2.6 m³ = 2600 L
Step 6: Calculate the percent volume displaced
(701.61 L / 2600 L) * 100% = 26.99%
26.99 % of air that will be displaced
The percent (by volume) of air that would be displaced is 26.99 %.
Given information:Temperature = 23.5 °C
Atmospheric pressure = 1.2 atm
Liquid nitrogen has a density of 0.807 g/mL
Molar mass of N2 = 28 g/mol
The calculation of the percent of air:Mass of nitrogen = density × volume
[tex]= 0.807 g/mL \times 1200 mL[/tex]
= 968.4 grams
Now
Moles N2 = mass N2 ÷ molar mass N2
[tex]= 968.4 grams \div 28 g/mol[/tex]
= 34.586 moles
Now volume
[tex]p\times V = n \times R \times T[/tex]
Here p = the the pressure = 1.2 atm
n = the number of moles = 34.586 moles
R = the gas constant = [tex]0.08206 L\times atm/K\times mol[/tex]
T = the temperature = 23.5 °C = 296.65
[tex]V = (n\times R\times T)\div p\\\\= (34.586 \times 0.08206 \times 296.65)\div 1.2[/tex]
= 701.61 L
Now the total volume of the chamber is
[tex]= 1.0 m \times 1.3 m \times 2 m \\\\= 2.6 m^3[/tex]
= 2600 L
Now finally the percent volume displaced
[tex]= (701.61 L \div 2600 L) \times 100\%[/tex]
= 26.99%
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In the reaction between CO and Fe3O4, the theoretical yield in an experiment is calculated to be 47.2 gFe. When a careless chemistry student carries out the experiment, the actual yield is 42.9 Fe. Calculatethe percentage yield.
A) 88.5%
B) 70.2%
C) 89.9%
D) 74.3%
E) 90.9%
Answer:
The percentage yield is 90.9 % (option e)
Explanation:
A simple rule of three to explain this.
If the theoretical yield of the reaction is 47.2 g Fe, we assume it as 100%, then what percentage of yield means 42.9 g Fe
47.2 g Fe _____ 100 %
42.9 g Fe ______ ( 42.9 . 100)/ 47.2 = 90.88%
Substituting the given values, the percentage yield is approximately E) 90.9%.
To find the percentage yield, we need to use the formula:
Percentage Yield = (Actual Yield / Theoretical Yield) × 100%
Given the actual yield as 42.9 g Fe and the theoretical yield as 47.2 g Fe, we can substitute these values into the formula:
Calculating -
[tex]\text{Percentage Yield} &= \left( \frac{\text{Actual Yield}}{\text{Theoretical Yield}} \right) \times 100\% \\\\\text{Percentage Yield} &= \left( \frac{42.9 \, \text{g}}{47.2 \, \text{g}} \right) \times 100\% \\\\\text{Percentage Yield} &= \left( \frac{42.9}{47.2} \right) \times 100\% \\\\\text{Percentage Yield} &\approx 0.9091 \times 100\% \\\\\text{Percentage Yield} &\approx 90.91\%[/tex]
Therefore, the percentage yield of the reaction is E) 90.9%.
Isotopes are atoms of the same element with different numbers of
Answer:
neutron
Explanation:
which affects mass number
Which elements can form diatomic molecules joined by a single covalent bond?
Answer:
Hydrogen and halogens.
Explanation:
There are seven types diatomic molecules are present in natural state: Hydrogen, chlorine, fluorine, nitrogen, bromine, iodine, and oxygen.
Hydrogen is the first element which have one electron and needs only one electron to fill its valence shell and form 2 hydrogen single bond to form H2.
The halogens, chlorine, fluorine, bromine, and iodine they all contain seven valence electrons. They all need one more electron so, they are sharing their one electron to fill its valence shell, and get Cl2, F2, Br2 and I2 (all single bonds)
Oxygen contains six valence electrons, each oxygen molecule needs 2 more electrons, and they contain 2 unpaired electrons. So, they share both electrons and form double bond.
Nitrogen contains five valence electrons. Each nitrogen atom required 3 more electrons and contains 3 unpaired electrons. The 2 atoms shares all 3 with each other molecule and this form a triple bond.
So, only Hydrogen and halogens form diatomic molecules with the help of single bond
Answer:
Halogen elements and H, O, N.
Explanation:
All halogen elements can form covalent bonds with each other to form a diatomic molecule. You can also add nonmetals, H, O and N.
All halogens have a configuration that differs from that of noble gases in an electron, so these elements tend to form negative species (anions) or form simple covalent bonds.
The Halogen are Cl, F, Br, I, As.
Assume that you react 100 mg of benzoic acid with 10 mL of methanol and 10 microliters of sulfuric acid to produce methyl benzoate. Write a balance chemical equation for this reaction. Determine the limiting reagent and calculate a theoretical yield of both the ester and water. If you isolate 75 mg of methyl benzoate, what is the actual yield of the reaction?
Explanation:
Balanced equation for the reaction between benzoic acid and metanol is as follows.
[tex]C_{6}H_{5}COOH + CH_{3}OH \overset{H_{2}SO_{4}}{\rightarrow} C_{6}H_{5}COOCH_{3}[/tex]
Since, volume of [tex]H_{2}SO_{4}[/tex] is very small so, that is catalytic amount of [tex]H_{2}SO_{4}[/tex] which is used.
As mass of benzoic acid is 100 mg. Hence, moles of benzoic acid are calculated as follows.
No. of moles of benzoic acid = [tex]\frac{mass}{molar mass}[/tex]
= [tex]\frac{100 mg}{122.12 g/mol}[/tex]
= 0.818 mmol
And, mass of methanol = volume × density
= [tex]10 ml \times 0.792 g/mol[/tex]
= 7.92 g
Now, number of moles of methanol is as follows.
No. of moles of methanol = [tex]\frac{mass}{molar mass}[/tex]
= [tex]\frac{ 7.92 g}{32.04 g/mol}[/tex]
= 0.024 mol
= 24.7 mmol
As number of moles of benzoic acid are smaller than the number of moles of methanol. Hence, benzoic acid is the limiting reagent.
As per the balanced equation, 1 mole of benzoic acid produces 1 mole of methyl benzoate.
Hence, 0.818 mmol of benzoic acid would produce 0.818 mmol of methyl benzoate. Therefore, theoretical yield of methyl benzoate is as follows.
Theoretical yield of methyl benzoate = [tex]0.818 mmol \times 136.15 g/mol[/tex]
= 111.48 mg
or, = 111.5 mg (approx)
Now, we will calculate the percent yield of the reaction as follows.
Percent yield = [tex]\frac{\text{Actual yield}}{\text{Theoretical yield}} \times 100[/tex]
= [tex]\frac{75 mg}{111.5 mg} \times 100[/tex]
= 67.27%
Therefore, we can conclude that the actual yield of the reaction is 67.27%.
Final answer:
The limiting reagent in the synthesis of methyl benzoate from benzoic acid and methanol is benzoic acid. The theoretical yield is approximately 111.5 mg of methyl benzoate, and with an actual yield of 75 mg, the percent yield is approximately 67.26%.
Explanation:
The balanced chemical equation for the reaction between benzoic acid (C7H6O2) and methanol (CH3OH) to produce methyl benzoate (C8H8O2) and water (H2O) in the presence of sulfuric acid (H2SO4) as a catalyst is:
C7H6O2 + CH3OH
ightarrow C8H8O2 + H2O
To determine the limiting reagent, we need to compare the mole ratios of the reactants. The molar mass of benzoic acid is about 122.12 g/mol and methanol is about 32.04 g/mol. Converting the mass of benzoic acid (100 mg = 0.1 g) to moles yields 0.000819 moles, while 10 mL of methanol (assuming a density of approximately 0.79 g/mL) gives 0.248 moles. Since benzoic acid has fewer moles, it is the limiting reagent.
The theoretical yield of methyl benzoate can be calculated based on the moles of benzoic acid, which will also be equal to the moles of water produced as this is a 1 to 1 reaction. This yields 0.000819 moles of methyl benzoate, and with a molar mass of 136.15 g/mol, the theoretical mass of methyl benzoate is approximately 111.5 mg.
The actual yield is 75 mg of methyl benzoate. Therefore, the percent yield can be calculated by dividing the actual yield by the theoretical yield and multiplying by 100, which results in approximately 67.26%.
How many electrons will fluorine gain or lose in forming an ion
Answer:
1 electron
Explanation:
Fluorine is a nonmetal with a high electronegativity and electron affinity so it tends to gain electrons to reach stability. According to the octet rule, fluorine will gain enough electrons so as to complete its valence shell with 8 electrons. Fluorine is in the Group 17 in the Periodic Table, which means it has 7 electrons in its valence shell. Therefore, it will gain 1 electron to complete its octet and form the anion F⁻.
Duralin is an alloy of aluminium containing 4.5% manganese, 3.5% copper, and 0.45% magnesium. How much magnesium is present in a 88 g sample of this alloy?
Answer: The mass of magnesium in given amount of alloy is 0.396 g
Explanation:
We are given:
Percent mass of manganese = 4.5 %
Percent mass of copper = 3.5 %
Percent mass of magnesium = 0.45 %
Percent mass of aluminium = (100 - 4.5 - 3.5 - 0.45) = 91.55 %
Mass of alloy = 88 g
We need to calculate the mass of magnesium in 88 g of alloy, we get:
[tex]\Rightarrow 88\times \frac{0.45}{100}=0.396g[/tex]
Hence, the mass of magnesium in given amount of alloy is 0.396 g
Which set of these comparisons is INCORRECT? (More stable means it has a more negative energy.) a) The 1s orbital in H is more stable than the 1s orbital in He+ b) The 2s orbital in He atom is less stable than the 2s orbital in He+ c) The 2s subshell in Li is more stable than the 2p subshell in Li
Answer:
a.
Explanation:
By the Linus Pauling's diagram, we know that the order of the energy of the subshell at the same atom, from the less to the higher, is:
1s < 2s < 2p < 3s < 3p < 4s < 4d ...
As larger is the atom, the attraction energy between the electron and the nuclei is weak. The size of the atom increase from right to left in the periods, and from the top to the bottom in the families. The cations are smaller than the neutral atoms (the attraction is more effective with fewer electrons), and the anions are larger than the neutral atoms. So, in order of size, and also the energy of the similar subshells:
He⁺ < He < H
How higher the energy, less negative it is, so less stable is the orbital.
a. As shown above, the energy of the orbital at H is higher than the energy at the orbital at He⁺, so the 1s orbital is more stable at He⁺, and the sentence is incorrect.
b. As shown above, the energy of the orbital at He is higher than the energy of the orbital He⁺, so the 2s orbital at He is less stable than the 2s orbital at He⁺, and the sentence is correct.
c. From the Linus Pauling's diagram, the energy of 2p is higher than the energy of the 2s, so the 2s subshell is more stable, and the sentence is correct.
A 1.0 M solution of hydrochloric acid is mixed with an equal volume of sodium hydroxide solution. The resulting solution turns pH paper blue, meaning the solution is basic. Which of the following concentrations would be consistent with the experimental results for sodium hydroxide?
A. 1.0 M
B. 2.0 M
C. 0.5 M
D. 0.25 M
Answer:B since it have to be in excess inorder to result into basic salt result to blue colour
An electrochemical cell is constructed using two half-cells: Al(s) in Al(NO2)3(aq) and Cu(s) in Cu(NO3)2(aq). The two half cells are connected by a KNO3 salt bridge and two copper wires from the electrodes to a voltmeter. Based on their respective standard reduction potentials, which half-cell is the cathode?
Answer:
Cu(s) in Cu(NO₃)₂(aq)
Explanation:
The standard reduction potential (E°) is the energy necessary to reduce the atom in a redox reaction. When an atom reduces it gains electrons from other than oxides. As higher is E°, easily it will reduce. The substance that reduces is at the cathode of a cell, where the electrons go to, and the other that oxides are at the anode of the cell.
The standard reduction potentials from Al(s) and Cu(s) are, respectively, -1.66V and +0.15V, so the half-cell of Cu(s) in Cu(NO₃)₂(aq) is the cathode.
What is the solution called in the buret during a titration?
Answer:
The solution in the buret, during a titration is called titrant.
Explanation:
A titration is a useful process, that makes you know the concentration of a solution. A titrant solution (burette) is evaluated against a titrand to control the pH changes against the volume aggregate. Only a strong acid with a strong base, a strong base with a strong acid, a weak acid with a strong base and a weak base with strong acid are valued.
When the pH reaches the equivalence point, it is said that the normality of the acid by the milliequivalents, is equal to the basic normality by its milliequivalents. In conclusion, the entire base / acid became its conjugate pair.
To check this sudden change in pH, a substance is used, called Indicator that changes the color of the titrand (analyte).
In a titration analysis, the substance in the buret is called the 'titrant'. It is used to react with the analyte, the sample solution whose concentration we're measuring. The goal is to reach the endpoint, the point when a distinct visual change indicates that the titrant has completely reacted with the analyte.
Explanation:In a titration analysis, the solution in the buret is called the titrant. This solution contains a known concentration of a substance. During a titration, this titrant is added incrementally to a sample solution, called the analyte, which contains the substance whose concentration is to be measured. The titrant and analyte undergo a chemical reaction of known stoichiometry.
By measuring the volume of the titrant solution needed to completely react with the analyte, scientists can calculate the concentration of the analyte. This point where the titrant has completely reacted with the analyte is termed the equivalence point of the titration. The process of adding the titrant is halted when a distinct change is visually detected in the solution - this could be a color change, for example. This is known as the end point.
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Solid aluminum hydroxide reacts with a solution of hydrobromic acid. Write a balanced molecular equation and a balanced net ionic equation
Answer:
[tex]Al(OH)_{3}(s)+3H^{+}(aq.)+3Br^{-}(aq.)\rightarrow Al^{3+}(aq.)+3Br^{-}(aq.)+3H_{2}O(l)[/tex]
[tex]Al(OH)_{3}(s)+3H^{+}(aq.)\rightarrow Al^{3+}(aq.)+3H_{2}O(l)[/tex]
Explanation:
Aluminium hydroxide ([tex]Al(OH)_{3}[/tex]) is a base and hydrobromic acid (HBr) is a strong acid.
Hence an acid-base reaction occurs between [tex]Al(OH)_{3}[/tex] and HBr
Balanced molecular equation:
[tex]Al(OH)_{3}(s)+3HBr(aq.)\rightarrow AlBr_{3}(aq.)+3H_{2}O(l)[/tex]
Balanced total ionic equation:
[tex]Al(OH)_{3}(s)+3H^{+}(aq.)+3Br^{-}(aq.)\rightarrow Al^{3+}(aq.)+3Br^{-}(aq.)+3H_{2}O(l)[/tex]
Balanced net ionic equation:
[tex]Al(OH)_{3}(s)+3H^{+}(aq.)\rightarrow Al^{3+}(aq.)+3H_{2}O(l)[/tex]
(net ionic equation is written by removing common ions present in both side of total ionic equation)
Caffeine, a stimulant in coffee and tea, has a molar mass of 194.19 g/mol and a mass percentage composition of 49.48% C, 5.19% H, 28.85% N, and 16.48% O. What is the molecular formula of caffeine?
Answer : The molecular formula of a caffeine is, [tex]C_8H_{10}N_4O_2[/tex]
Solution :
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of C = 49.48 g
Mass of H = 5.19 g
Mass of N = 28.85 g
Mass of O = 16.48 g
Molar mass of C = 12 g/mole
Molar mass of H = 1 g/mole
Molar mass of N = 14 g/mole
Molar mass of O = 16 g/mole
Step 1 : convert given masses into moles.
Moles of C = [tex]\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{49.48g}{12g/mole}=4.12moles[/tex]
Moles of H = [tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{5.19g}{1g/mole}=5.19moles[/tex]
Moles of N = [tex]\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{28.85g}{14g/mole}=2.06moles[/tex]
Moles of O = [tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{16.48g}{16g/mole}=1.03moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C = [tex]\frac{4.12}{1.03}=4[/tex]
For H = [tex]\frac{5.19}{1.03}=5.03\approx 5[/tex]
For N = [tex]\frac{2.06}{1.03}=2[/tex]
For O = [tex]\frac{1.03}{1.03}=1[/tex]
The ratio of C : H : N : O = 4 : 5 : 2 : 1
The mole ratio of the element is represented by subscripts in empirical formula.
The Empirical formula = [tex]C_4H_5N_2O_1=C_4H_5N_2O[/tex]
The empirical formula weight = 4(12) + 5(1) + 2(14) + 16 = 97 gram/eq
Now we have to calculate the molecular formula of the compound.
Formula used :
[tex]n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}[/tex]
[tex]n=\frac{194.19}{97}=2[/tex]
Molecular formula = [tex](C_4H_5N_2O)_n=(C_4H_5N_2O)_2=C_8H_{10}N_4O_2[/tex]
Therefore, the molecular of the caffeine is, [tex]C_8H_{10}N_4O_2[/tex]
The electronegativities for the elements vary from 0.7 for cesium to 4.0 for fluorine. The electronegativity for iodine is 2.5. Based entirely on the general guidelines for electronegativities and bond character:
a) binary compounds with iodine should all be polar covalent with a δ- on I.
b) binary compounds with iodine should all polar covalent with a δ+ on I.
c) compounds with iodine may be ionic, polar covalent, or nonpolar covalent.
d) no binary compounds with iodine should be substantially ionic.
Answer:
a) binary compounds with iodine should all be polar covalent with a δ- on I.
Explanation:
Electronegativity can be defined as the ability of an atom to attract shared pair of electrons towards itself.
the correct answer is a) binary compounds with iodine should all polar covalent with a δ- on I.
The binary compounds as the name suggests are compounds made of two elements. Halogens being the most electronegative element in periodic table , tend to attract the shared pair towards themselves. Iodine has high electronegativity and large atomic size hence it polarizes the electron cloud towards itself. Due to this it acquires a negative charge on it. therefore, bonds are polar with δ- charge on iodine.
Final answer:
Compounds with iodine may be ionic, polar covalent, or nonpolar covalent depending on the other element it is bonded with.
Explanation:
Based on the general guidelines for electronegativities and bond character, compounds with iodine may be ionic, polar covalent, or nonpolar covalent. The electronegativity of iodine is 2.5, which falls within the range where both ionic and polar covalent bonds can form. Therefore, binary compounds with iodine can exhibit a range of bond character depending on the other element it is bonded with.
Isopropyl alcohol is mixed with water to produce a 40.0 % (v/v) alcohol solution. How many milliliters of each component are present in 675 mL of this solution? Assume that volumes are additive.
Answer : The volume of water and alcohol present in 675 mL of this solution are 405 mL and 270 mL respectively.
Explanation :
As we are given that 40.0 % (v/v) alcohol solution. That means, 40.0 mL of alcohol present 100 mL of solution.
Now we have to calculable the volume of alcohol in 675 mL solution.
As, 100 mL of solution contains 40.0 mL of alcohol
So, 675 mL of solution contains [tex]\frac{675}{100}\times 40.0=270mL[/tex] of alcohol
Thus, the volume of alcohol = 270 mL
Now we have to calculate the volume of water.
Volume of water = Volume of solution - Volume of alcohol
Volume of water = 675 mL - 270 mL
Volume of water = 405 mL
Thus, the volume of water = 405 mL
Hence, the volume of water and alcohol present in 675 mL of this solution are 405 mL and 270 mL respectively.
Given a reaction between an organic molecule, denoted as A, and NaSH, we observe the following observations. Using the observations, write a rate law for the reaction. (a) The rate triples when the concentration of [A] is tripled and the concentration of [NaSH] is held constant. (b) The rate is decreased when the concentration of [A] is doubled and the concentration of [NaSH] is cut by a factor of 3. (c) The rate doubles when the concentration of [A] is cut in half and the concentration of [NaSH] is quadrupled. (d) The rate increases with an increase in temperature.
The rate law for the reaction can be determined by analyzing the effects of changing reactant concentrations. Based on the given observations, the rate law can be written as rate = k[A]/[NaSH] and rate = [tex]k[A][NaSH]^2[/tex] for the given conditions. Additionally, the rate constant, k, is temperature-dependent.
Explanation:The rate law for the reaction can be determined by examining the effects of changing the concentrations of reactants on the rate of the reaction. Based on the given observations, we can conclude the following:
(a) The rate triples when the concentration of [A] is tripled and the concentration of [NaSH] is held constant. This suggests that the reaction rate is directly proportional to the concentration of A, so the rate law can be expressed as rate = k[A]
(b) The rate is decreased when the concentration of [A] is doubled and the concentration of [NaSH] is cut by a factor of 3. This implies that the rate is inversely proportional to the concentration of [NaSH], so the rate law can be written as rate = [tex]k[A]/[NaSH][/tex]
(c) The rate doubles when the concentration of [A] is cut in half and the concentration of [NaSH] is quadrupled. This indicates that the rate is quadratically proportional to the concentration of [NaSH], so the rate law can be expressed as rate = [tex]k[A][NaSH]^2[/tex]
(d) The rate increases with an increase in temperature. This suggests that the rate constant, k, in the rate law equation is temperature-dependent.
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Exothermic reactions are favored because they release heat to the environment. Would an exothermic reaction be more favored or less favored if it were carried out within a superheated chamber?
Explanation:
No, an exothermic reaction will not be favored or less favored if it were carried out within a super heated chamber. In the super heated chamber the heat will flow back to the reaction( considering heat emitted by the reaction is less than the heat in a super heated chamber). So, the reaction will shift backward instead, the product will again change into reactant.
Organic compounds are distinguished by molecules that contain ________ bonded to other elements.
Use the information in the table to identify the metal with a volume of 1.38 cm3.
Answer:
The metal with a volume of [tex]1.38 cm^3 [/tex] is zinc.
Explanation:
Density is defined as mass of the substance present in the unit volume of the substance.
[tex]Density=\frac{mass}{Volume}[/tex]
For aluminum:
Mass of aluminium metal , M = 4.60 g
Volume of the aluminium metal = V
Density of the aluminium metal = d = [tex]2.70 g/cm^3[/tex]
[tex]V=\frac{M}{d}=\frac{4.60 g}{2.70 g/cm^3}=1.70 cm^3[/tex]
For Zinc :
Mass of zinc metal , M = 9.81 g
Volume of the zinc metal = V
Density of the zinc metal = d = [tex]7.13 g/cm^3[/tex]
[tex]V=\frac{M}{d}=\frac{9.81 g}{7.13 g/cm^3}=1.38 cm^3[/tex]
For chromium :
Mass of chromium metal , M= 6.24 g
Volume of the chromium metal = V
Density of the chromium metal = d = [tex]7.18 g/cm^3[/tex]
[tex]V=\frac{M}{d}=\frac{6.24 g}{7.18 g/cm^3}=0.87 cm^3[/tex]
For nickel :
Mass of nickel metal , M= 3.17 g
Volume of the nickel metal = V
Density of the nickel metal = d = [tex]8.90 g/cm^3[/tex]
[tex]V=\frac{M}{d}=\frac{3.17 g}{8.90 g/cm^3}=0.36 cm^3[/tex]
The metal with a volume of [tex]1.38 cm^3 [/tex] is zinc.
Answer:
B - zinc
Explanation:
Hope this helps! ✌
Which argument(s) for the increasing use of solar energy is/are valid?
I. Solar cells are becoming cheaper and increasingly more efficient.
II. The cost of generating electricity from fossil fuels is increasing.
III. Limited and uncertain supply and the increasing requirements for pollution control are raising the cost of fossil fuels.
A. I only
B. II only
C. I and III only
D. I, II, and III
Answer:
Option D is correct.
Explanation:
Option D is correct.
Solar cells are replacing the conventional ways of making electricity. They are getting cheaper with each coming day. Secondly they use the renewable energy which causes no pollution and is available in large amount as our sun is a continuous source of energy. Another reason fossil fuels are getting out of fashion because they require huge setups and initial cost. Their burning emit green house and other toxic gases which cause rise in temperature and pollution. Also their amount is decreasing which make it expensive to use.
The density of an aqueous solution containing 10.0 percent of ethanol (C2H5OH) by mass is 0.984 g/mL. (a) Calculate the molality of this solution. (b) Calculate its molarity. (c) What volume of the solution would contain 0.125 mole of ethanol
The solution contains 2.41 m (molality) and 2.14 M (molarity) of ethanol. A volume of 58.5 mL of this solution would contain 0.125 mol of ethanol.
Explanation:(a) Let's calculate the molality of this solution. Mass of ethanol in 1000g of solution is 100g (10% of 1000g). The molar mass of ethanol (C2H5OH) is (2*12.01 + 6*1.008 + 1*16.00 + 1*1.008) = 46.07 g/mol. Hence, the number of moles = 100g / 46.07 g/mol = 2.17 mol. Since these moles are in 900g of water (1000g - 100g), molality = 2.17 mol / 0.900 kg = 2.41 m.
(b) To calculate molarity, let's find the volume of 1000g of solution: Volume = mass/density = 1000g / 0.984 g/mL = 1016.26 mL = 1.016 L. Therefore, molarity = 2.17 mol/1.016 L = 2.14 M.
(c) To find the volume of solution that would contain 0.125 mol ethanol, we'll use molarity: Volume = moles/Molarity = 0.125 mol / 2.14 M = 0.0585 L or 58.5 mL.
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The molality of the solution is 2.41 mol/kg, the molarity is 2.135 M, and to contain 0.125 mole of ethanol, 58.57 mL of the solution is required.
(a) Molality is defined as the number of moles of solute per kilogram of solvent. Given the density of the solution, we can determine the mass of 100.0 mL of the solution:
Density = 0.984 g/mL
Mass of 100 mL of solution = 100 mL * 0.984 g/mL = 98.4 g
Mass of ethanol (10% by mass) = 0.10 * 98.4 g = 9.84 g
Mass of water = 98.4 g - 9.84 g = 88.56 g
To convert grams of ethanol to moles:
Molar mass of ethanol (C2H5OH) = 46.07 g/mol
Moles of ethanol = 9.84 g / 46.07 g/mol = 0.2135 mol
To convert grams of water to kilograms:
88.56 g = 0.08856 kg
Therefore, the molality is:
Molality = 0.2135 mol / 0.08856 kg = 2.41 mol/kg
(b) Molarity is defined as the number of moles of solute per liter of solution. We already calculated the moles of ethanol as 0.2135 mol in 100 mL of solution.
Volume of solution = 0.100 L (since 100 mL = 0.1 L)
Therefore, the molarity is:
Molarity = 0.2135 mol / 0.100 L = 2.135 M
(c) We need to find the volume of solution that contains 0.125 mole of ethanol. Using the molarity calculated:
Molarity = 2.135 M = moles of solute / volume of solution (L)
Volume of solution = moles of solute / M
Volume of solution = 0.125 mol / 2.135 M = 0.05857 L = 58.57 mL
Therefore, the volume of the solution that would contain 0.125 mole of ethanol is 58.57 mL.
As atoms gain energy, they move faster and slide past one another more easily. Atoms at the surface of the substance overcome attractions to nearby atoms and break free of the surface. Which change of state is taking place?
- liquid to gas
- gas to liquid
- liquid to solid
- solid to liquid
Answer:
Liquid to gas
Explanation:
There are three states of matter, the solid, liquid and gaseous states. These states can be compared in a number of ways. These comparisms would tell us that the molecules of gases have the highest mobility.
The freedom possessed by these molecules are as a result of there inherent kinetic energy. While we have the highest confinement for solids, molecules of solids still have a level of freedom and hence although confined can move in some directions but are not entirely free from the total confinement of intermolecular forces like solids.
Hence,this total freedom is a character of gaseous molecules. As we were made to know in the question that they already had exhibited degree of movement to an extent,the total breakaway is to the gaseous state.
Thus,the phase transition is from liquid to gaseous state.
Vaporization (evaporation) is the transition from liquid to gas as atoms gain energy, break free of surface attractions, and move freely.
Vaporization (evaporation) is the change of state taking place when atoms at the surface of a substance absorb energy, overcome attractions to nearby atoms, and break free of the surface, transitioning from liquid to gas. This process involves the absorption of energy, which allows particles to move freely and transition into the gas phase.
Which is not a characteristic of metals?
a. Most metal oxides are ionic solids that are basic.
b. They have a shiny luster and various colors, although most are silvery.
c. Solids are malleable and ductile.
d. They are poor conductors of heat and electricity.
Answer: d: They are poor conductors of heat and electricity .
Explanation:
Although is common knowledge that metals are characterized by high electrical conductivity and heat conductivity, these properties can be justified by looking at the metallic bonding.
In a metal, the bonding electrons are delocalized over the entire crystal. In fact, metal atoms in a crystal can be imagined as an array of positive ions immersed in a sea of delocalized valence electrons.The mobility of the delocalized electrons makes metals good conductors of heat and electricity.
an element is a mixture of two isotopes. one isotope has an atomic mass of 34.96885 amu and has an abundance of 75.53%. The other isotope has an atomic mass of 36.96590 amu. Calculate the average atomic mass and identify the element?
Answer:
35.4575 amu
Explanation:
We use the relative abundance of each of the isotopes.
Let the isotopes be A and B.
Since A is having an abundance of 75.53, the abundance of B would be 100 - 75.53 = 24.47%
The average atomic mass is calculated as follows;
(75.53/100 * 34.96885) + (24.47/100 * 36.96590) = 26.4119 + 9.0456 = 35.4575 amu
Final answer:
To find the average atomic mass of an element with two isotopes, multiply each isotope's mass by its fractional abundance and sum the results. The average atomic mass for the element given with isotopic masses of 34.96885 amu and 36.96590 amu is 35.4458 amu, which identifies the element as chlorine.
Explanation:
The average atomic mass of an element that is a mixture of two isotopes can be calculated using the isotopic masses and their abundances. In this case, we have two isotopes with masses of 34.96885 amu and 36.96590 amu and an abundance of 75.53% and 24.47% (100% - 75.53%), respectively. To find the average atomic mass, we multiply each isotope's mass by its abundance (as a decimal), and then add the results.
First, for the isotope with a mass of 34.96885 amu and an abundance of 75.53%, we calculate:
34.96885 amu × 0.7553 = 26.4062 amu
Similarly, for the other isotope with a mass of 36.96590 amu, we use its abundance of 24.47% (100% - 75.53%):
36.96590 amu × 0.2447 = 9.0396 amu
Adding these together gives us the average atomic mass:
26.4062 amu + 9.0396 amu = 35.4458 amu
The average atomic mass is 35.4458 amu. Comparing this with the periodic table, we can identify the element as chlorine since its atomic mass is closest to this calculated average.