Go online and search for information about companies that have been harmed or bankrupted by a disaster. Choose one such company and create a brief case study about it. Successful narratives will focus on the manner in which the organization was impacted, including financial losses, losses of sales, or the need for layoffs.

Answer:

Explanation:

Given that,

Omega is a function of the following

ω = f(b, h, v, ρ, k)

Where, all unit have a dimension of

ω = T^-1

b = L

h = L

V = LT^-1

ρ = FL^-4T²

k = FL

Then,

From the pie theorem

The required pi term is 6—3 = 3 terms,

So, we use V, p and b as a repeating term.

For first pi

π1 = ω•b^a•v^b•ρ^c.

Since

ω= T^-1, b = L, v = LT^-1 and

ρ= FL^-4T²

Since π is dimensionless then,

π = F^0•L^0•T^0

(T^-1)•(L^a)•(LT^-1)^b•(FL^-4T²)^c = F^0•L^0•T^0

Rearranging

F^0•L^0•T^0 = F^c•T^(2c-b-1)• L^(a+b-4c)

Comparing coefficient

c = 0

2c - b - 1 = 0

b = 2c - 1 = 0 - 1 = -1

a + b - 4c = 0

a = 4c - b = 0 - -1 = 0+1

a = 1

Then, a = 1, b = -1 and c = 0

So, π1 = ω•b^a•v^b•ρ^c.

π1 = ω•b^1•v^-1•ρ^0

π1 = ω•b / v

Check dimensions

ωb/v = (T^-1)L / LT^-1 = L^0•T^0 = 1

Then, π1 is dimensionless

For second pi

π2 = h•b^a•v^b•ρ^c.

Since

h = L, b = L, v = LT^-1 and ρ= FL^-4T²

Since π is dimensionless then,

π = F^0•L^0•T^0

(L)•(L^a)•(LT^-1)^b•(FL^-4T²)^c = F^0•L^0•T^0

Rearranging

F^0•L^0•T^0 = F^c•T^(2c-b)• L^(1+a+b-4c)

Comparing coefficient

c = 0

2c - b = 0

b = 2c = 0

1 + a + b - 4c = 0

a = 4c - b - 1 = 0 -0 - 1  = -1

a = -1

Then, a = -1, b = 0 and c = 0

So, π2 = h•b^a•v^b•ρ^c.

π2 = h•b^-1•v^0•ρ^0

π2 = h / b

Check dimensions

h / b = L / L = 1

Then, π2 is dimensionless

For third pi

π3 = k•b^a•v^b•ρ^c.

Since

k= FL, b = L, v = LT^-1 and ρ=FL^-4T²

Since π is dimensionless then,

π = F^0•L^0•T^0

(FL)•(L^a)•(LT^-1)^b•(FL^-4T²)^c = F^0•L^0•T^0

Rearranging

F^0•L^0•T^0 = F^(c+1)•T^(2c-b)• L^(1+a+b-4c)

Comparing coefficient

c + 1= 0

Then, c = -1

2c - b = 0

b = 2c = -2

1 + a + b - 4c = 0

a = 4c - b - 1 = -4 +2 - 1  = -3

a = -3

Then, a = -3, b = -2 and c = -1

So, π3 = k•b^a•v^b•ρ^c.

π3 = k•b^-3•v^-2•ρ^-1

Therefore,

π3 = k / b³•v²•ρ

Let check for dimension

π3 = FL / (L³• L²T^-2 • FL^-4T²)

π3 = FL / (L^(3+2-4) • T^(-2+2) •F)

π3 = FL / (L• T^(0) •F)

π3 = FL / LF = 1

π3 is also dimensions less

So.

I. There are three none dimensional pi

II. The none dimensional group are

π1 = ω•b / v

π2 = h / b

π3 = k / b³•v²•ρ

III. Reynolds Number. The Reynolds number is the ratio of inertial forces to viscous forces and it is dimensionless

So, the π3 can be considered as a Reynolds number

Answer:

(a) The mass glow rate of water is 0.0032kg/s

(b) The heat removal from air is 14.17KJ/sec

Explanation:

In this question, we are asked to use the formula to calculate the mass flow rate and the heat removal from water based on the data in the question.

To answer this question, we take values of absolute humidity and enthalpy values from table from corresponding temperature

Please check attachment for complete solution and step by step explanation

Answer:

Here, The CML is used for efficient portfolios whereas the SML applies to all portfolios or securities

Considering the seperation theorem, The separation theorem states that the investment decision is sepaarte from the financing decision.

This implies that The SML can be used to analyze the relationship between risk and requried return for all assets.

Under the separation theorem investors should Hold the same portfolio of risky assets and the same expected return but at different levels of risk

Explanation:

See answer

Answer:

(a) Frequency induced voltage of motor is 120 Hz

(b) The speed at which the machine will produce an average torque is 240π rad/s. Maximum Torque is 1.0 Nm

Explanation:

Answer:

// This program is written in C++ programming language

// Comments are used for explanatory purpose

/* The aim of this program is to to remove all the white space,digits, punctuation, and other special characters, leaving only the letters. */

// Program starts here

#include <stdio.h>

#include<iostream>

using namespace std;

int main()

{

// Declare Variable of 100 characters

char word[100];

// Prompt user for input

cout<<"Your input goes here (max, 100 characters)";

cin>>word;

// Iterate through string to check for non alphabetic characters

for (int i = 0; word[i] != '\0'; ++i) {

// Check for uppercase and lowercase letters

while (!((word[i] >= 'a' && word[i] <= 'z') || (word[i] >= 'A' && word[i] <= 'Z') || word[i] == '\0')) {

for (int j = i; word[j] != '\0'; ++j) {

word[j] = word[j + 1];

}

word[j] = '\0';

}

}

cout<<"The resulting compressed string: "<<word;

return 0;

}

Answer:

w = str(input("input your values: "))

values = ' '.join(filter(str.isalpha, w))

while len(w) < 100:

       print(values)

       break

Explanation:

The code is written in python

w = str(input("input your values: "))

This code ask the user to input any string values with characters, numbers, line spaces , letters etc.

values = ' '.join(filter(str.isalpha, w))

This code filters the inputted value to bring only letters. All the letter are then joined together

while len(w) < 100:

The code check if the inputted value is less than 100 characters. While it is less than 100 characters. If it is less than 100 character the next code will function.

print(values)

This code prints the joined letters after checking with  a while loop to confirm the length of character is less than 100

break

The break function breaks the code whether it print the values or not.

Generally, the letters will only be printed if the character inputted is less than 100 and later break the while loop or will not print any letter if the character is greater than 100 and later break.

Answer:

a) 7.5A

b) 370V

Explanation:

Note that the Line current is the current through any one line between a three-phase source and load.

From the given question, The source line current =7.5A(approximately)

While the Source line voltage = 370V.

Kindly go through the attached file for a step by step detail of how I arrived at these answers.

The source line current in the three-phase system is 2.08 A and the source line voltage is approximately 371 V.

To calculate the source line current and the source line voltage in a three-phase system, we can use the formula:

I = P / (sqrt(3) * V * PF)

Where I is the source line current, P is the power delivered to the load, V is the phase voltage, and PF is the power factor.

Given that the power delivered is 4.8 kVA, the phase voltage is 214 V, and the power factor is 0.9 lagging, we can substitute these values into the formula and calculate:

I = 4.8 kVA / (sqrt(3) * 214 V * 0.9)

Calculating this gives us a source line current of 2.08 A.

To find the source line voltage, we can use the formula:

Vline = sqrt(3) * Vphase

Substituting the phase voltage of 214 V into the formula gives us a source line voltage of approximately 371 V.

Answer:

Q = 2450 KJ/day

Explanation:

We are given;

The amount of moisture produced by a person while taking shower; m = 0.25 kg/person

Total number of persons in the family; N = 4

Latent heat of vaporization of water:

h_fg = 2450 KJ/kg

Since amount of moisture per person is 0.25kg per day,thus for 4 people, total mass; m_total = 4 x 0.25 = 1 kg per day

The formula for the amount of latent heat added to the space due to shower per day, is given as;

Q = m_total x h_fg

Plugging in the relevant values;

Q = 1 x 2450 = 2450 KJ/day

The image of the elevation and wall section is missing, so i have attached them.

Answer:

Number of concrete blocks = 1020 blocks

Number of lintel blocks = 240

Number of plain blocks = 780

Explanation:

First of all, we'll find the net area of the wall as follows:

The height of the wall is 17' - 4", so we need to convert it to ft, thus, h = 17' + (4/12)' = 17.33'

So, Gross wall area = 80′ × 17.333' = 1,387 ft²

From the image, there are 4 doors, thus, Area of doors = 4 × 10′ × 12′ = 480 ft²

Thus, Net area = Gross wall area - area of doors

Net area = 1,387 – 480 = 907 ft²

We are told that the block is 8 inches length by 16inches width. Thus, converting to ft; (8/12)ft by (16/12)ft.

So area of one block = (8/12) x (16/12) = 128/144 ft² = 0.88889 ft²

So, number of blocks per ft² = 1/0.88889 = 1.125 blocks

So, there are 1.125 blocks per ft²

Thus, Number of concrete blocks = 907 ft² × 1.125 blocks per ft² = 1,020 blocks

From the image attached, there are five rows of lintel blocks, located at 4′, 8′, 12′, 16′, and 17′-4″. The bottom three rows pass through the doors and are only a total of (80′ – (4 × 10′) ) = 40′ long .

The top two rows are 80′ long. Thus, there is 40 feet (4 × 10′) of lintel block above the doors.

Lintel blocks = (3 × 40′) + (2 × 80′) + 40′ = 320 ft

Number of Lintel blocks = 320′ × 12 in per ft / 16″ = 240 blocks

Number of Plain blocks = 1,020 blocks – 240 blocks = 780 blocks

Without specific wall dimensions provided, it is not possible to calculate the exact number of plain and lintel concrete blocks required for the construction of the wall. However, the general procedure involves calculating the wall's total area, subtracting the area of doors or windows, and then dividing by the size of one block, while also considering the requirements for lintel blocks above openings and where supports are needed.

Determining the Quantity of Concrete Blocks for a Wall

To determine the number of 8-inch-high by 8-inch-wide by 16-inch-long concrete blocks required to complete a wall, one must calculate the total volume of the wall and then divide by the volume of a single block. Unfortunately, the dimensions of the wall are not provided in the question, so we cannot calculate the exact number of blocks needed. As for the lintel blocks, which are used above the doors and wherever the #4 horizontal bars are located, the number would depend on the linear footage that needs to be covered by the lintels and the length of each lintel block.

Without specific wall dimensions, we must refer to the typical process where one would calculate the wall's total surface area, subtract the area occupied by doors or windows, and divide by the area covered by one block. Then, identify the areas requiring lintel blocks and count the number of lintels needed based on their standard lengths.

The plain blocks and lintel blocks calculation requires detailed measurements of the wall and openings. Since the details provided are related to the overhead doors with known dimensions, one would need to consider the door's dimensions when calculating the plane wall areas and the lintel requirements above them.

The elevation difference between the two reservoirs is 10.28 ft

Given information:

- Length of the 3-in. cast iron pipe = 150 ft

- Number of flanged elbows = 4

- Entrance condition: well-rounded

- Exit condition: sharp-edged

- Fully open gate valve

- Flow rate = 75 gal/min

- Water temperature = 50 °F

Step 1: Convert the flow rate from gal/min to ft³/s.

Flow rate in ft³/s = (75 gal/min) × (1 ft³/7.48 gal) × (1 min/60 s) = 0.167 ft³/s

Step 2: Calculate the velocity of flow.

Velocity of flow, V = Flow rate / Cross-sectional area of the pipe

Cross-sectional area of the 3-in. cast iron pipe = (π/4) × (3/12)² ft² = 0.0491 ft²

Velocity of flow, V = 0.167 ft³/s / 0.0491 ft² = 3.4 ft/s

Step 3: Calculate the Reynolds number to determine the flow regime.

Reynolds number, Re = (ρVD) / μ

Where,

ρ = density of water at 50 °F = 1.94 slugs/ft³ (from tables)

V = velocity of flow = 3.4 ft/s

D = diameter of the pipe = 3/12 ft

μ = dynamic viscosity of water at 50 °F = 2.73 × 10⁻⁵ lb.s/ft² (from tables)

Re = (1.94 slugs/ft³) × (3.4 ft/s) × (3/12 ft) / (2.73 × 10⁻⁵ lb.s/ft²) = 1.9 × 10⁵

Since Re > 4000, the flow is turbulent.

Step 4: Calculate the head loss due to friction in the straight pipe.

Head loss due to friction, hf = f × (L/D) × (V²/2g)

Where,

f = friction factor (depends on Reynolds number and pipe roughness)

L = length of the pipe = 150 ft

D = diameter of the pipe = 3/12 ft

V = velocity of flow = 3.4 ft/s

g = acceleration due to gravity = 32.2 ft/s²

From the Moody diagram or friction factor tables for cast iron pipe, assuming a relative roughness of 0.00085, and Re = 1.9 × 10⁵, the friction factor, f = 0.021.

Substituting the values, hf = 0.021 × (150 × 12/3) × [(3.4)²/(2 × 32.2)] = 8.4 ft

Step 5: Calculate the head loss due to fittings (elbows, entrance, exit, and valve).

Head loss due to fittings, hf_fittings = Σ(K × V²/2g)

Where K is the loss coefficient for each fitting.

For 4 flanged elbows, K = 0.3 (for each elbow)

For a well-rounded entrance, K = 0.03

For sharp-edged exit, K = 1.0

For a fully open gate valve, K = 0.2

Substituting the values, hf_fittings = [4 × 0.3 + 0.03 + 1.0 + 0.2] × [(3.4)²/(2 × 32.2)] = 1.7 ft

Step 6: Calculate the velocity head.

Velocity head, hv = V²/2g = (3.4)²/(2 × 32.2) = 0.18 ft

Step 7: Calculate the total head loss.

Total head loss, H = hf + hf_fittings + hv

H = 8.4 ft + 1.7 ft + 0.18 ft = 10.28 ft

Therefore, the elevation difference between the two reservoirs is 10.28 ft for the given piping system and a flow rate of 75 gal/min of water at 50 °F.

Answer:

a) The temperature of evaporation is -10.09°C

The temperature of condensation is 35.53°C

b) The mass flow of the refrigerant is 0.149 kg/s

c) The COP is 3.65

d) The new COP is 4.05

Explanation:

please look at the solution in the attached Word file

The couplings are not all on the same axis or plane, but if the A and B connector were to be described, it would travel with a magnitude of roughly 15 by the yz axis diagonal to the x axis. The axis would be oriented so that it was pointing upward into the second quadrant.

In terms of physics, magnitude is just "distance or quantity." It displays an object's size, direction, or motion in absolute or relative terms. It is employed to indicate the size or scope of something.

In physics, the term "magnitude" often refers to a size or amount. Magnitude is defined as "how much of a quantity." The magnitude can be used, for instance, to compare the speeds of a car and a bicycle.

It can also be used to indicate how far something has come or how much something weighs relative to its size.

Thus, The couplings are not all on the same axis or plane.

For more details about magnitude, click here:

https://brainly.com/question/14452091

#SPJ2

To determine the relative humidity of the mixed air stream based on the information provided, one would typically use a psychrometric chart or other moist air property calculations. Without access to the required psychrometric data or tables to reference, an accurate calculation cannot be provided here, but principles of moist air mixing and conservation of mass for the water vapor can guide the process.

To determine the relative humidity and temperature of the exiting stream in the mixing chamber problem, we need to use the principles of thermodynamics specifically relating to moist air properties. This requires using a psychrometric chart or similar calculation methods to find the properties of the mixed air stream. The information provided in the initial question about the temperatures, pressures, and humidities of the incoming air streams is used along with conservation of mass and energy principles.

However, as a tutor on Brainly, I do not have access to the necessary tables or psychrometric data through this platform, which are required to calculate the final relative humidity of the exiting stream. Such data typically includes saturation pressure, saturation temperature, and specific enthalpy of the air-water mixture at various conditions.

To solve the problem accurately, you would need to reference the appropriate psychrometric chart or software at the specific temperatures given in the question. Assuming the total pressure remains constant and using the principle of the conservation of mass for the water vapor, the mixing ratio of the incoming streams can be used to determine the mixing ratio of the outgoing stream. Then, with the final temperature known, you could identify the corresponding saturation mixing ratio and use it to calculate the relative humidity.

If we assume that the mass flow rates of both streams are equal, we can consider that the exiting air stream will be a mixture of the two streams. Given the final exit temperature of 17°C, we could interpolate between the saturation mixing ratios at the temperatures given for the two streams to estimate the relative humidity, but a more precise result would come from detailed calculations or a psychrometric chart.

Answer:

inform the readers about Diane and her unusual job.

Explanation:

The purpose of Lorraine Jean Hopping's viewpoint in "Bone Detective" is just to inform the readers about Diane as a person and how what she does has really helped people even though her job was really unusual. It was mainly for the purpose of passing information across to the readers and nothing else.

Answer:

Explanation:she is trying to inform you hope it helps

Answer:

(a) Calculate the rod base temperature (°C). = 299.86°C

(b) Determine the rod length (mm) for the case where the ratio of the heat transfer from a finite length fin to the heat transfer from a very long fin under the same conditions is 99 percent.  = 0.4325m

Explanation:

see attached file below

Answer:

(a) [tex]G(s) = \frac{i_{out(s)}}{v_{in}(s)} = \frac{2S}{S^2+4S+4}[/tex]

(b) see plot in the attached explanation.

(c) [tex]i_{out}(t) = 0.2 Cos(10t-63)[/tex]

Explanation:

See attached solution a to c

Answer:

Copy MATLAB code to plot the magnitude of magnetic field strength with respect to z on the axis of solenoid:

z=-20:0.01:20;

H=120.*(((20-(2.*z))./sqrt((20-(2.*z)).^2+100))+((20+(2.*z))./sqrt((20+(2.*z)).^2+100)));

plot(z,H)

title('plot of |H| vs z along the axis of solenoid')

ylabel('Magnitude of magnetic field 'H")

xlabel('position on axis of solenoid 'z")

Explanation:

full explanation is attached as picture and the resultant plot also.

Answer:

c.if the flow is laminar it could become turbulent.

Explanation:

The Reynolds number (Re) is a dimensionless quantity used to help predict flow patterns in different fluid flow situations. At low Reynolds numbers of below 2300 flows tend to be dominated by laminar, while at high Reynolds numbers above 4000, turbulence results from differences in the fluid's speed and direction. In between these values is the transition region of flow.

In practice, fluid flow is generally chaotic, and very small changes to shape and surface roughness of bounding surfaces can result in very different flows.

Thermodynamic calculations for mass flow rate, compressor power, and coefficient of performance of a heat pump require refrigerant property data, which is not provided in the question. An energy balance and compressor efficiency adjustment are also essential for accurate calculations.

To calculate the properties of the heat pump using refrigerant 134a and determine the refrigerant mass flow rate, compressor power, and coefficient of performance, we need to make use of thermodynamic equations and refrigerant property data under the given conditions (such as pressures and phase states).Normally, these calculations would involve using a thermodynamic properties table or software to find enthalpies for the refrigerant at the specified conditions. An energy balance would be applied around the compressor and condenser. The work done by the compressor can be calculated using the enthalpy values before and after the compressor and assuming an isentropic process initially, and then adjusting for the non-ideal compressor efficiency of 75% in the revised calculation.For the coefficient of performance (COP) of the heat pump, it is calculated as the ratio of heat output to work input for the heating mode. The provided heat output is given here as 35 kW. For ideal conditions, the COP can be calculated without the compressor efficiency factor; for the revised COP with a 75% efficient compressor, this factor is taken into account.Unfortunately, without the enthalpy values or additional data, it is not possible to provide the numerical answers to the student's question.

Answer:

The force on the strut is 909000 lbm ft/s²

Explanation:

please look at the solution in the attached Word file

1. Proton assignments for each isomer: p-bromoaniline: Hd signal around 7.5 ppm (doublet, 2H), Hb signal around 6.7 ppm (doublet, 2H) o-bromoaniline: Ha and Hc signals overlapping around 7.6-7.65 ppm (multiplets, 4H total) o,p-dibromoaniline: Hb signal around 6.6 ppm (doublet, 2H), Hd signal around 7.55 ppm (doublet, 1H) o,o,p-tribromoaniline: No clear signals observed, likely not formed.

2. The isomer not observed to be formed is o,o,p-tribromoaniline. A plausible experimental explanation is that the highly brominated product is less favored due to steric hindrance and deactivation of the ring towards further electrophilic substitution.

3. Diagnostic protons for product ratio calculations: p-bromoaniline: Hb around 6.7 ppm o-bromoaniline: Ha/Hc around 7.6-7.65 ppm o,p-dibromoaniline: Hd around 7.55 ppm o,o,p-tribromoaniline: N/A (not formed)

4. Calculating product ratios using diagnostic proton integrations: p-bromoaniline: Integration of Hb signal ≈ 2.0, relative ratio = 2.0/2.0 = 100% o-bromoaniline: Integration of Ha/Hc signals ≈ 2.8, relative ratio = 2.8/4.8 ≈ 58% o,p-dibromoaniline: Integration of Hd signal ≈ 1.0, relative ratio = 1.0/3.0 ≈ 33% o,o,p-tribromoaniline: 0% (not formed)

5. Theoretical reasons for relative product abundance: i. p-bromoaniline: Dominant product due to the directing effect of the amino group favoring para substitution. ii. o-bromoaniline: Formed in moderate amounts due to some ortho substitution, but less favored than para. iii. o,p-dibromoaniline: Formed in smaller amounts due to the decreased reactivity of the ring after the first substitution. iv. o,o,p-tribromoaniline: Not formed, likely due to high steric hindrance and deactivation of the ring towards further substitution

The complete question:

The chemist’s crude product mixture was submitted for NMR analysis to give Spectrum C. Using the expected splitting patterns and chemical shift changes you predicted in part a, assign each proton for each of the isomers above (see structures on Spectrum C) by labeling each signal on the spectrum with the appropriate letter. Keep the integration ratios in mind when assigning each proton.

2. One of the four potential products above was NOT observed to be formed. Which one? Propose a very brief experimental explanation for the absence of this product.

3. For each of the three products that are observed in Spectrum C, there is a diagnostic proton that can be used to accurately calculate the product ratios. (Remember that a good diagnostic proton has a “clean” signal that has minimal overlap with other signals- see the “Using Integrations to Calculate Compound Ratios” page in the Assignment Information folder on Top Hat.) What diagnostic proton can be used to calculate product ratios for each isomer? If the isomer was not formed, write “N/A.”

4. Using the diagnostic protons you listed in part c, calculate the percent of each isomer. Show calculations for each isomer. If an isomer was not formed, write “0%.”

5. Provide a theoretical reason for the relative abundance of the following products

i. p-bromoaniline

ii. o-bromoaniline

iii. o,p-dibromoaniline

iv. o,o,p-tribromoaniline

Spectrum C bromination of aniline, crude solvent: CDCl Notes 1. Spectrum C is the zoomed-in aromatic region (6.3-7.9 ppm); amine protons are not shown 2. There are 2 overlapping signals from relevant protons at 6.60-6.65 ppm. You should assign both NH2 NH2 NH2 NH2 Br Br Chloroform H Sovent Но Hb He Br Hd ignore (possible oxidation product) 7.8 7.7 7.6 7.5 7.4 7.3 7.2 7.1 7.0 6.9 6.8 6.7 6.6 6.5 6.4 ppm p-bromoaniline o-bromoaniline o,p- dibromoaniline o,o,p- tribromoaniline %p-bromoaniline %o-bromoaniline % o,p- dibromoaniline % o,o,p- tribromoaniline. show all working. solve in hum, and form

Answer:

[tex]D_c(s) = 1.8(\frac{s+1.11}{s+0.2})[/tex]

Explanation:

Code attached with picture.

Answer:

The result seem reasonable.

Explanation:

Relative density shows us how heavy a substance is in comparison to water.It aids us in determine the density of an unknown substance by knowing the density of a known substance. Relative density is defined as the ratio of the density (mass of a unit volume) of a substance to the density of a given reference material. It is very important in the accurate determination of density.

Relative density= emax - e/emax - emin× 100

Relative density ranges between 35 and 65 because the soil is in medium state.

For well graveled sand, maximum friction angle is uo^r

and for minimum friction angle, minimum friction angle is 33°.

Therefore, for given friction angle of 31° (shear strength criteria). This result seem reasonable.

Therefore, it is worthy to note that if friction angle is more, the shear strength is more which implies that it is a densified soil, that is to say, void ratio decreases.

Answer:

a. The fuel formula is C10H20 (dec-1-ene)

b. The heat given-off to the cooling system of the reactor represents the Higher Heating Value (HHV) of the gaseous hydrocarbon fuel

c. LHV = 44.36 KJ/kg

d. ΔH (formation) = -6669.6 KJ/mol

Explanation:

Molecular weight = 140, Molar H/C ratio = 2.0

a) To determine the fuel formula, we represent the information we have as equations

Molecular weight of C = 12, Molecular weight of H = 1

CxHy = 140g

12 · x + 1 · y = 140      ·········Eqn 1

y = 2x                        ·········Eqn 2

Substitute y = 2x into Eqn 1, we have:

12 (x) + 1 (2x) = 140

12x + 2x = 140

14x = 140

x = 10

Substitute x into Eqns 2, we have:

y = 2 x 10 = 20

∴ the fuel formula is C10H20 (dec-1-ene)

b) The heat given-off to the cooling system of the reactor represents the Higher Heating Value (HHV) of the gaseous hydrocarbon fuel . HHV refers to the amount of heat given-off in the combustion of a specified amount of fuel which was initially at 25°C and cooled back to a temperature of 25°C.

c) We will use LHV formula given as:

LHV = HHV – [2.441 (0.09H + M) ÷ 1000]

where:

LHV = lower heating value of fuel in MJ/kg

HHV = higher heating value of fuel in MJ/kg

M = Weight % of moisture in fuel

H = Weight % of hydrogen in fuel

HHV = 47.5 MJ/kg, M = 0, H = mass of hydrogen ÷ total mass of fuel

⇒ H = 20 ÷ 140 = 0.143 * 100 = 14.3 kg per 100 kg, Latent heat of steam (at 25°C) = 2441 KJ/kg

LHV = 47.5 - [2441 * (0.09 * 14.3 + 0) ÷ 1000]

LHV = 47.5 - 3.14 = 44.36

LHV = 44.36 KJ/kg

d) To get the enthalpy of the combustion of the fuel, we have:

fuel + air - - - - > carbon dioxide + water

C10H20 + 15 O2 - - - - > 10 CO2 + 10 H20

Enthalpy (formation) = Enthalpy (product) - Enthalpy (reactant)

ΔH (CO2) = -393.5 kJ/mol, ΔH (H2O) = -285.8 kJ/mol, ΔH (C10h20) = - 123.4KJ/mol

ΔH (formation) = 10 * (-393.5) + 10 * (-285.8) - (-123.4)

ΔH (formation) = -3935 - 2858 + 123.4

ΔH (formation) = -6669.6 KJ/mol

Answer:

a) check the attached files below

b)  What power will be developed by a geometrically and dynamically similar prototype, of diameter 15 m, in winds of 35 m/s at 500 m standard altitude from sea level = 2184.56KW

c) What is the appropriate rotation rate = 122.5 rpm

Explanation:

please kindly check the attachment below.

The following code or the program will be used:

Explanation:

import java.util.Scanner;

public class Authenticate

{

public static void main(String[] args)

{

// Actual password is 99508

int[] actual_password = {9, 9, 5, 0, 8};

// Array to hold randomly generated digits

int[] random_nums = new int[10];

// Array to hold the digits entered by the user to authenticate

int[] entered_digits = new int[actual_password.length];

// Randomly generate numbers from 1-3 for

// for each digit

for (int i=0; i < 10; i++)

{

random_nums[i] = (int) (Math.random() * 3) + 1;

}

// Output the challenge

System.out.println("Welcome! To log in, enter the random digits from 1-3 that");

System.out.println("correspond to your PIN number.");

System.out.println();

System.out.println("PIN digit: 0 1 2 3 4 5 6 7 8 9");

System.out.print("Random #: ");

for (int i=0; i<10; i++)

{

System.out.print(random_nums[i] + " ");

}

System.out.println();

System.out.println();

// Input the user's entry

Scanner keyboard = new Scanner(System.in);

System.out.println("Enter code.");

String s = keyboard.next();

String s = keyboard.next();

// Extract the digits from the code and store in the entered_digits array

for (int i=0; i<s.length(); i++)

{

entered_digits[i] = s.charAt(i) - '0'; // Convert char to corresponding digit

}

// At this point, if the user typed 12443 then

// entered_digits[0] = 1, entered_digits[1] = 2, entered_digits[2] = 4,

// entered_digits[3] = 4, and entered_digits[4] = 3

/****

TO DO: fill in the parenthesis for the if statement

so the isValid method is invoked, sending in the arrays

actual_password, entered_digits, and random_nums as

parameters

***/

if (isValid (actual_password, entered_digits, random_nums)) // FILL IN HERE

{

System.out.println("Correct! You may now proceed.");

}

else

{

System.out.println("Error, invalid password entered.");

}

/***

TO DO: Fill in the body of this method so it returns true

if a valid password response is entered, and false otherwise.

For example, if:

actual = {9,9,5,0,8}

randnums = {1,2,3,1,2,3,1,2,3,1}

then this should return true if:

entered[0] == 1 (actual[0] = 9 -> randnums[9] -> 1)

entered[1] == 1 (actual[1] = 9 -> randnums[9] -> 1)

entered[2] == 3 (actual[2] = 5 -> randnums[5] -> 3)

entered[3] == 1 (actual[3] = 0 -> randnums[0] -> 1)

entered[4] == 3 (actual[4] = 8 -> randnums[8] -> 3)

or in other words, the method should return false if any of

the above are not equal.

****/

public static boolean isValid(int[] actual, int[] entered, int[] randnums)

{

int Index = 0;

boolean Valid = true;

while (Valid && (Index < actual.length))

{

int Code = actual[Index];

if (entered [Index] != randnums [Code])

{

Valid = false;

}

Index++;

}

return Valid;

}

Answer:

6 m²

Explanation:

application of fluid pressure according to  Pascal's principle for the two pistons is given as:

[tex]P_1=P_2[/tex]

Where P₁ is the pressure at the input and P₂ is the pressure at the output.

But P₁ = F₁ / A₁ and P₂ = F₂ / A₂

Where F₁ and F₂ are the forces applied at the input and output respectively and A₁ and A₂ are the area of  the input pipe and output pipe respectively

Since, [tex]P_1=P_2[/tex]

[tex]\frac{F_1}{A_1} =\frac{F_2}{A_2}\\[/tex]

But A₁ = 0.2 m², F₁ = 250 N, F₂ = 7500 N. Substituting values to get:

[tex]\frac{F_1}{A_1} =\frac{F_2}{A_2}\\\frac{250}{0.2}=\frac{7500}{A_2}\\ A_2=\frac{7500*0.2}{250} = 6m^2[/tex]

Therefore, the area of the pipe below the load is 6 m²

Explanation:

a. The output of an ideal full wave rectifier is zero volts only when the input is zero volts.

True

The output of an ideal full wave rectifier is zero volts only when the input is zero since 1st diode is forward biased during one half cycle of the input and 2nd diode is forward biased during the other half cycle of the input therefore, it fully utilizes both the input cycles so the output voltage is only zero when the input is zero.

b. Half-wave rectifier circuits need a minimum of 4 diodes to operate.

False

A Half-wave rectifier circuits need a minimum of 1 diode to operate, whereas a full-wave bridge rectifier need minimum of 4 diodes to operate.

c. In an ideal full wave bridge rectifier, half of the diodes are in the ON state and half of the diodes are in the OFF state at any given time the input voltage is not zero.

True

A full-wave bridge rectifier consists of 4 diodes, where 2 diodes are functional in half of the cycle(so the other 2 are off) and other 2 diodes are functional in the other half cycle( so the other 2 are off).

d. The output of an ideal half wave rectifier is zero volts only when the input is zero volts.

False

The output of an ideal half wave rectifier is zero during half of the cycle when the diode is reversed biased and doesn't conduct even though input voltage is not zero volts at this point.

e. A turn-on voltage of a diode (y,) greater than zero can cause the output of a full wave rectifier to be zero volts even when the input is not zero volts.

False

A turn-on voltage of a diode (y,) greater than zero cannot cause the output of a full wave rectifier to be zero rather there will be a little voltage drop across the output of full wave rectifier due to this turn-on voltage of diode which is usually 0.7 volts for silicon based diodes.

f. An advantage of the half wave rectifier is that is can use a smoothing capacitor, while a full wave rectifier cannot.

False

Smoothing capacitor can be used in both half wave rectifier as well as full wave rectifier.

Answer:

As Ray L zapp is thinking about new strategies to test his new hash Table,hence therefore the best testing technique is  Stubbing& mocking .

Answer:

472,826 lb/hr

Explanation:

As per the given data:

Solids in feed= 2%

Solids in concentrate= 25%

HTA1 = HTA2 = 1000 ft^2

U1 = 500 Btu/ h ft^2 F & U2 = 700 Btu/ h ft^2 F

Overall material balance: Feed= Distillate + concentrate ----> Eq-1

Component balance: Feed * 0.02 = Distillate * 0 + concentrate * 0.25

Feed = 12.5 * concentrate ---> Eq-2

Boiling point rise = negligible, so solution & solvent vapor temperature will be same.

Assumed that the 1st effect is operating under atmospheric pressure (Boiling point - 212F).

As per the data:

Latent heat 212F = 300 Btu/lb

Latent heat 100F = 320 Btu/lb

As per material balance:

Vapor flowrate * latent heat = Overall HT coefficient * HTA * DT

1st effect: M-1= (500 * 1000 * (326-212)) / 300 = 190,000 lb/hr

2nd effect: M-2= (700*1000 * (212-100)) / 320 = 245,000 lb/hr

Distillate = M-1 + M-2 = 190,000+245,000 = 435,000 lb/hr

Substituting the above in Eq-1

Feed = 435,000 + concentrate

Substitute Eq-2 in the above

12.5 * concentrate = 435,000 + concentrate

Concentrate, L1 = 435,000/11.5 = 37826 lb /hr

Feed, F = 435,000 + 37826 = 472,826 lb/hr

1st effect operating pressure is not given, That may be the reason we are not getting the given answer. But procedure is right.

[ Find the figure in the attachment ]

To find the maximum velocity at section (1) in a two-dimensional reducing bend with a linear velocity profile, apply the principle of conservation of mass and the equation Q = Av. The maximum velocity, V1,max, occurs at section (1) where the cross-sectional area is the smallest.

To find the maximum velocity, V1,max, at section (1) in a two-dimensional reducing bend with a linear velocity profile at section (1), we can apply the principle of conservation of mass. As the cross-sectional area decreases, the velocity increases to maintain constant flow rate. At section (1), the velocity is maximum due to the smallest area.

Using the equation Q = Av, where Q is the flow rate, A is the cross-sectional area, and v is the velocity, we can determine the maximum velocity at section (1). The maximum velocity, V1,max, occurs at section (1) where the cross-sectional area is the smallest, resulting in the highest velocity to maintain flow rate continuity.