Graph -3x + 9y = -27

Answer:

B.

Step-by-step explanation:

So [tex]2x^2+5x+3[/tex] will have two factors if one factor in the form [tex](ax+b)[/tex] is given.

The other factor will also be in the form of [tex](cx+d)[/tex].

So we have

[tex](x+1)(cx+d)[/tex]:

Let's use foil.

First:  x(cx)=cx^2

Outer: x(d)=dx

Inner: 1(cx)=cx

Last: 1(d)=d

---------------------Adding like terms:

cx^2+(d+c)x+d

We are comparing this to:

2x^2+     5x+3

So we see that c=2 and d=3 where the other factor is cx+d=2x+3.

Also this works since c+d=5 (we know this because 2+3=5).

Answer:

B

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Given

5(x - 7) = 55, then using the distributive property, that is

a(b - c) = ab - ac, then

5x - 35 = 55

The property that was used to write the equation in step 2 is option A) distributive property

Given that,

So here we have to use the distributive property i.e.

So,  

5x - 35 = 55

Therefore we can conclude that The property that was used to write the equation in step 2 is option A) distributive property

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Answer:

y = - 2

Step-by-step explanation:

The equation of a horizontal line parallel to the x- axis is

y = c

where c is the value of the y- coordinates the line passes through.

The points (2, - 2) and (0, - 2) have the same y- coordinate and therefore lie on a horizontal line with equation

y = - 2

Answer:

Step-by-step explanation:

[tex]\text{The distributive property:}\ a(b+c)=ab+ac\\\\15=3\cdot5\\21=3\cdot7\\\\15+17=3\cdot5+3\cdot7=3\cdot(5+7)[/tex]

[tex]\huge{\boxed{\text{2000 pounds}}}[/tex]

One ton is equal to [tex]\boxed{\text{2000 pounds}}[/tex].

For example, two tons is equal to [tex]4000[/tex] pounds, because [tex]2000*2=4000[/tex].

Answer is provided in the image attached.

Answer:

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

(There are more values since we can go around the circle from 67 degrees numerous times.)

Step-by-step explanation:

You can use a co-function identity.

The co-function of sine is cosine just like the co-function of cosine is sine.

Notice that cosine is co-(sine).

Anyways co-functions have this identity:

[tex]\cos(90^\circ-x)=\sin(x)[/tex]

or

[tex]\sin(90^\circ-x)=\cos(x)[/tex]

You can prove those drawing a right triangle.

I drew a triangle in my picture just so I can have something to reference proving both of the identities I just wrote:

The sum of the angles is 180.

So 90+x+(missing angle)=180.

Let's solve for the missing angle.

Subtract 90 on both sides:

x+(missing angle)=90

Subtract x on both sides:

(missing angle)=90-x.

So the missing angle has measurement (90-x).

So cos(90-x)=a/c

and sin(x)=a/c.

Since cos(90-x) and sin(x) have the same value of a/c, then one can conclude that cos(90-x)=sin(x).

We can do this also for cos(x) and sin(90-x).

cos(x)=b/c

sin(90-x)=b/c

This means sin(90-x)=cos(x).

So back to the problem:

cos(23)=sin(90-23)

cos(23)=sin(67)

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

Answer: Second Option

[tex]P (-1.17 <z <1.17) = 0.7580[/tex]

Step-by-step explanation:

The shaded area corresponds to the interval

[tex]-1.17 <z <1.17.[/tex]

By definition, for a standard normal distribution the area under the curve in the interval (b <z <h) is equal to:

[tex]P (b <z <h)[/tex]

So in this case we look for:

[tex]P (-1.17 <z <1.17)[/tex]

This is:

[tex]P (-1.17 <z <1.17) = P (z <1.17) - P (z <-1.17)[/tex]

Looking at the standard normal table we have to:

[tex]P (z <1.17) = 0.8790\\P (z <-1.17) = 0.1210[/tex]

So:

[tex]P (-1.17 <z <1.17) = 0.8790- 0.1210\\\\P (-1.17 <z <1.17) = 0.7580[/tex]

For this case we have a function of the form[tex]y = g (x)[/tex]

Where:

[tex]g (x) = 2 (x-4)[/tex]

We must find the value of "x" when the function has a value of 20, that is, [tex]g (x) = 20[/tex]:

[tex]2 (x-4) = 20[/tex]

We apply distributive property:

[tex]2x-8 = 20[/tex]

We add 8 to both sides of the equation:

[tex]2x = 20 + 8\\2x = 28[/tex]

We divide between 2 on both sides of the equation:

[tex]x = \frac {28} {2}\\x = 14[/tex]

Answer:

Option C

Answer:

option c 14

Step-by-step explanation:

did the test

[tex]\huge{\boxed{c+148}}[/tex]

We need to find the number of pies baked in years 1 and 2.

There were 148 pies baked in year 1. [tex]148[/tex]

There were [tex]c[/tex] pies baked in year 2. [tex]148+c[/tex]

Rearrange the terms so the variable is first. [tex]c+148[/tex]

Answer:

since we know that there were 148 pies sold the first year, and c number of pies sold this year. You would add these two to find the total amount of both years.

148+c

Answer:

-55/4

Step-by-step explanation:

-4 1/4 - (9 1/2)

Both the terms are given in whole fraction:

Change the terms into improper fraction

4*-4+1 = -17/4

2*9 + 1=19/2

Now,

-17/4 - 19/2

Now take the L.C.M of the denominator.

L.C.M of 4 and 2 is 4

Solve for numerator:

L.C.M (4) divided by denominator of first term will give quotient 1. Then 1 multiply by the numerator -17 will give us 1* -17 = -17

Then 4 divided by denominator of 2nd term will give us 2 as a quotient. Then quotient multiplied by numerator of 2nd term will give us 19*2 = 38

Therefore,

-17 - 38/4

= -55/4

The answer is -55/4....

The expression -4 1/4 - (9 1/2), is simplified to be expressed as -53/4

To simplify the expression -4 1/4 - (9 1/2), we need to convert the mixed numbers to improper fractions and perform the subtraction.

First, let's convert the mixed numbers to improper fractions:

-4 1/4 = -4 + 1/4 = -4 * 4/4 + 1/4 = -16/4 + 1/4 = -15/4

9 1/2 = 9 + 1/2 = 9 * 2/2 + 1/2 = 18/2 + 1/2 = 19/2

Now we can substitute these values back into the original expression:

-15/4 - 19/2

To subtract fractions, we need a common denominator. The least common multiple (LCM) of 4 and 2 is 4, so we can rewrite the fractions with a common denominator of 4:

-15/4 - 19/2 = -15/4 - 38/4

Now we can subtract the fractions:

-15/4 - 38/4 = (-15 - 38)/4 = -53/4

Therefore, the expression -4 1/4 - (9 1/2) simplifies to -53/4.

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Answer:

(6,6) only goes with Line 2

(3,4) goes with neither

(7,2) goes with both

Step-by-step explanation:

Ok to decide if a point is on a line you plug it in.  If you get the same thing on both sides, then that point is on that line.  If you don't get the same thing on both sides, then that point is not on that line.

Test (6,6) for -5x+6y=-23.

(x,y)=(6,6) gives us

-5x+6y=-23

-5(6)+6(6)=-23

-30+36=-23

6=-23

So (6,6) is not on -5x+6y=-23.

Test (6,6) for y=-4x+30

(x,y)=(6,6) give us

y=-4x+30

6=-4(6)+30

6=-24+30

6=6

So (6,6) is on y=-4x+30.

Test (3,4) for -5x+6y=-23.

(x,y)=(3,4) gives us

-5x+6y=-23

-5(3)+6(4)=-23

-15+24=-23

9=-23

So (3,4) is not on -5x+6y=-23.

Test (3,4) for y=-4x+30.

(x,y)=(3,4) gives us

y=-4x+30

4=-4(3)+30

4=-12+30

4=18

So (3,4) is not on y=-4x+30.

Test (7,2) for -5x+6y=-23.

(x,y)=(7,2) gives us

-5x+6y=-23

-5(7)+6(2)=-23

-35+12=-23

-23=-23

So (7,2) is on -5x+6u=-23.

Test (7,2) for y=-4x+30.

(x,y)=(7,2) gives us

y=-4x+30

2=-4(7)+30

2=-28+30

2=2

So (7,2) is on y=-4x+30

(x,y)  Line 1    Line 2     Both     Neither

(6,6)                  *

(3,4)                                                   *

(7,2)                                  *

(6,6) only goes with Line 2

(3,4) goes with neither

(7,2) goes with both

Answer:

(D) 6 & 7

Step-by-step explanation:

You are plugging in numbers into the question marks to make the equation true. In this case, plug in the numbers, 6 & 7 or (D)

Plug in 6 in the first ? mark and 7 in the second:

?1 - 2? = 34 = (61) - (27) = 34

61 - 27 = 34

34 = 34 (True) ∴ 6 & 7 is your answer.

~

Answer:
it’s a circle graph

Dotted linear inequality shaded below passes through (0, 4) & (4,3). Dotted parabolic inequality shaded above passes through points (negative 6,4), (negative 4, 0) & (negative 2, 4).

Hello! Let me help you to find the correct option to this problem. First of all, we have the following system of inequalities:

[tex]\left\{ \begin{array}{c}y< -\frac{1}{4}x+4\\y>(x+4)^{2}\end{array}\right.[/tex]

To solve this, let's write the following equations:

[tex]y=-\frac{1}{4}x+4[/tex]

This is a linear function written in slope-intercept form as [tex]y=mx+b[/tex]. So, the slope [tex]m=-\frac{1}{4}[/tex] and the y-intercept is [tex]b=4[/tex]. Since in the inequality we have the symbol < then the graph of the line must be dotted. To get the shaded region, let's take a point, say, [tex](0, 0)[/tex] and let's test whether the region is above or below the graph. So:

[tex]y< -\frac{1}{4}x+4 \\ \\ Let \ x=y=0 \\ \\ 0<-\frac{1}{4}(0)+4 \\ \\ 0<4 \ True![/tex]

Since the expression is true, then the region is the one including point [tex](0, 0)[/tex], that is, it's shaded below.

[tex]y=(x+4)^{2}[/tex]

This is a parabola that opens upward and whose vertex is [tex](-4,0)[/tex]. Since in the inequality we have the symbol > then the graph of the parabola must be dotted. Let's take the same point [tex](0, 0)[/tex] to test whether the region is above or below the graph. So:

[tex]y>(x+4)^{2} \\ \\ Let \ x=y=0 \\ \\ 0>(0+4)^2\\ \\ 0>16 \ False![/tex]

Since the expression is false, then the region is the one that doesn't include point [tex](0, 0)[/tex], that is, it's shaded above

____________________

[tex]y=-\frac{1}{4}x+4 \\ \\ \\ \bullet \ (0,4): \\ \\ y=-\frac{1}{4}(0)+4 \therefore y=4 \\ \\ \\ \bullet \ (4,3): \\ \\ y=-\frac{1}{4}(4)+4 \therefore y=3[/tex]

So the line passes through these two points.

[tex]y=(x+4)^2 \\ \\ \\ \bullet \ (-6,4): \\ \\ y=(-6+4)^2 \therefore y=(-2)^2 \therefore y=4 \\ \\ \\ \bullet \ (-4,0): \\ \\ y=(-4+4)^2 \therefore y=0 \\ \\ \\ \bullet \ (-2,4): \\ \\ y=(-2+4)^2 \therefore y=(2)^2 \therefore y=4[/tex]

So the line passes through these three points.

Finally, the shaded region is shown below.

Answer:

12

Step-by-step explanation:

Given expression is:

[tex](x^16)^\frac{3}{4}[/tex]

By the rues of exponents, when there is exponent on exponent then the exponents are multiplied.

So,

[tex]= x^{16*\frac{3}{4}}\\ = x^{4*3}\\=x^{12}[/tex]

The exponent of x will be 12 after the simplification ..

Answer:

B

Step-by-step explanation:

Using the Sine Rule in ΔABC

[tex]\frac{a}{sinA}[/tex] = [tex]\frac{b}{sinB}[/tex] = [tex]\frac{c}{sinC}[/tex]

∠C = 180° - (82 + 58)° = 180° - 140° = 40°

Completing values in the above formula gives

[tex]\frac{a}{sin58}[/tex] = [tex]\frac{b}{sin82}[/tex] = [tex]\frac{8.4}{sin40}[/tex]

We require a pair of ratios which contain b and 3 known quantities, that is

[tex]\frac{b}{sin82}[/tex] = [tex]\frac{8.4}{sin40}[/tex]

OR

[tex]\frac{sin40}{8.4}[/tex] = [tex]\frac{sin82}{b}[/tex] → B

Answer:

B

Step-by-step explanation:

Answer: The outlier in this scatter plot is Point D.

Step-by-step explanation:

The reason its Point D because its the only one that is the farest away from the rest of the points on the plot.

The reason why "Point D" would be the correct answer because the point is no where near the "trend" of the scatter plot.

When you look at the scatter plot, you would notice that there following a "trend" when the graph increases.

However, you would notice that point D is not really near there, therefore making it an outlier.

An outlier is pretty much something that is left out, and in this case, point D would be the outlier since it's left out of the typical growth of the scatter plot.

Answer:

x = 8/9

Step-by-step explanation:

5x + 2(x - 3) = -2(x - 1)

Distribute on both sides.

5x + 2x - 6 = -2x + 2

Combine like terms on the left side.

7x - 6 = -2x + 2

Add 2x to both sides.

9x - 6 = 2

Add 6 to both sides.

9x = 8

Divide both sides by 9.

x = 8/9

Answer:

[tex]\large\boxed{x^\frac{4}{5}}[/tex]

Step-by-step explanation:

[tex]\sqrt[n]{a}=a^\frac{1}{n}\Rightarrow\sqrt[5]{x}=x^\frac{1}{5}\\\\\sqrt[5]{x}\cdot\sqrt[5]{x}\cdot\sqrt[5]{x}\cdot\sqrt[5]{x}=x^\frac{1}{5}\cdot x^\frac{1}{5}\cdot x^\frac{1}{5}\cdot x^\frac{1}{5}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=x^{\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}}=x^\frac{4}{5}[/tex]

Answer:

[tex]x^{\frac{4}{5}}[/tex]

Step-by-step explanation:

fifth root of x can be written in exponential for as:

[tex]x^\frac{1}{5}[/tex]

[tex]x^\frac{1}{5}[/tex] times  [tex]x^\frac{1}{5}[/tex] times  [tex]x^\frac{1}{5}[/tex] times  [tex]x^\frac{1}{5}[/tex]

WE apply exponential property to multiply it

a^m times a^n= a^{m+n}

[tex]x^\frac{1}{5}[/tex] times  [tex]x^\frac{1}{5}[/tex] times  [tex]x^\frac{1}{5}[/tex] times  [tex]x^\frac{1}{5}[/tex]

[tex]x^{\frac{1}{5} +\frac{1}{5}+\frac{1}{5}+\frac{1}{5}}[/tex]

The denominator of the fractions are same so we add the numerators

[tex]x^{\frac{4}{5}}[/tex]

Answer:

[tex]\large\boxed{V=\pi r^3}[/tex]

Step-by-step explanation:

The formula of a volume of a pyramid:

[tex]V=\dfrac{1}{3}BH[/tex]

B - base area

H - height

Let r - radius of the cone.

We have H = 3r.

The base of the cone: [tex]B=\pi r^2[/tex].

Substitute:

[tex]V=\dfrac{1}{3}\pi(r^2)(3r)[/tex]           cancel 3

[tex]V=\pi r^3[/tex]

Answer:

For plato users is option A

Step-by-step explanation:

A. V =[tex]\pi[/tex]r3

Answer:

19/24

Step-by-step explanation:

Since you are looking for the fraction he spend, you have to add 3/8 and 5/12 with one another. To do this you have to change those fractions to have the same denominators. so you multiply 3/8 by 3/3 to get 9/24 and you multiply 5/12 by 2/2 to get 10/24. You then add 9/24 with 10/24 to get 19/24. Since you cannot simplify this further, 19/24 is your answer.

Bob spent [tex]\frac{19}{24}[/tex] of his birthday money

For given question,

Bob spent 3/8 of his birthday money at a baseball game and 5/12 on a new bat and glove.

We need to find the fraction of his birthday money he spent.

so we add given two fractions.

[tex]\frac{3}{8}+ \frac{5}{12}\\\\ =\frac{3\times 3}{8\times 3}+ \frac{5\times 2}{12\times 2}\\\\=\frac{9}{24}+ \frac{10}{24}\\\\=\frac{9+10}{24}\\\\ =\frac{19}{24}[/tex]

Therefore, Bob spent [tex]\frac{19}{24}[/tex] of his birthday money.

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Answer:

The answer is def. A.

Answer: OPTION A.

Step-by-step explanation:

By definition:

A number is Rational when it can be written as a simple fraction.

A number is Irrational when it cannot be written as a simple fraction.

Notice that:

[tex]\frac{2}{5}[/tex] is a Rational number.

[tex]\sqrt{88}=2\sqrt{2}[/tex] It is an irrational number.

Therefore, the sum of these numbers is an Irrational number:

[tex]\frac{2}{5} + \sqrt{88}=\frac{2}{5} + 2\sqrt{22}=9.78083151...[/tex]

Answer:

The officer saves $91.45 per month

~Step-by-step explanation~

Ok this is how I do fractions and its not very good, but it works.

First I divided 6400 by 5, 6, and 7, (I didn't do 3 because you can just multiply the answer to 6 by 2.) the reason I divided these is to see how much 1 part of their fraction is worth. So in total I got  1066.66 (irrational number) for insurance which means I got 2133.32 for his monthly living ( had to multiply by 2). For his car payment I got 1828.57 (I divided and then multiplied by 2) and for his rent I got 1280. I added these all together to get the total he spends each month which was 6308.55, and I subtracted that from 6400 to figure out that he puts $91.45 in his savings account

Answer:

The answer is R91.43.

Step-by-step explanation:

Monthly salary of the worker = R6400

The monthly expenses are 1/5 for rent that is [tex]\frac{1}{5}\times6400= 1280[/tex]

The car payment is 2/7 that is [tex]\frac{2}{7}\times6400= 1828.57[/tex]

The insurance is 1/6 that is [tex]\frac{1}{6}\times6400= 1066.67[/tex]

Few other monthly living expenses are 1/3 that is [tex]\frac{1}{3}\times6400= 2133.33[/tex]

We will total these values:

[tex]1280+1828.57+1066.67+2133.33=6308.57[/tex]

So, the amount that is saved per month = [tex]6400-6308.57=91.43[/tex]

The answer is R91.43.

Answer:

No

Step-by-step explanation:

Given a function f(x)

For the function to be odd then f(- x) = - f(x)

f(- x) = 3(- x)² + (- x) = 3x² - x

- f(x) = - (3x² + x) = - 3x² - x

Since f(- x) ≠ - f(x) then f(x) is not an odd function

Answer:

7 friends multiply $2

Its product is: $14

Step-by-step explanation:

Answer:

Please read explanation below.

Step-by-step explanation:

Let's go over what some of the symbols of inequalities represent:

[tex]>[/tex]: greater than

[tex]<[/tex]: less than

[tex]\ge[/tex]: greater than or equal to

[tex]\le[/tex]: less than or equal to

The symbol in the equation that is given to you is [tex]\ge[/tex]. It seems as though each of the answer choices have everything written as the same thing except for the description of the inequalities. Check the one that applies.

Answer:

3x² - 2x + 5 ; will be a polynomial ⇒ answer A

Step-by-step explanation:

* Lets explain what is the polynomial

- A polynomial is an expression containing two or more algebraic terms.

- Polynomial is often the sum of some terms containing different powers

 of variables.  

- If you add or subtract polynomials, you get another polynomial.

- If you multiply polynomials, you get another polynomial.

* Lets solve the problem

∵ 5x² + 3x + 4 is polynomial

∵ 2x² + 5x - 1 is polynomial

- When we subtract them the answer will be polynomial

∵ (5x² + 3x + 4) - (2x² + 5x - 1)

- Open the second bracket by multiplying the negative sign by

  each term in the bracket

∵ -(2x²) = -2x²

∵ -(5x) = -5x

∵ -(-1) = 1

∴ (5x² + 3x + 4) - (2x² + 5x - 1) = 5x² + 3x + 4 - 2x² - 5x + 1

- Add the like terms

∴ (5x² - 2x²) = 3x²

∴ (3x - 5x) = -2x

∵ (4 + 1) = 5

∴ (5x² + 3x + 4) - (2x² + 5x - 1) = 3x² - 2x + 5

∴ 3x² - 2x + 5 is a polynomial

∴ (5x² + 3x + 4) - (2x² + 5x - 1) = 3x² - 2x + 5 ; will be a polynomial

* The answer is A

Answer:

A. 3[tex]x^{2}[/tex] − 2x + 5; will be a polynomial

Step-by-step explanation:

Give The Dood Above Brainliest

Answer:

111

Step-by-step explanation:

a1 = -12

a27 = 66

Now using the formula  an = a1+(n-1)d we will find the value of d

here n = 27

a1 = -12

a27 = 66

Now substitute the values in the formula:

a27 = -12+(27-1)d

66= -12+(26)d

66 = -12+26 * d

66+12 = 26d

78 = 26d

now divide both the sides by 26

78/26= 26d/26

3 = d

Now put all the values in the formula to find the 42 term

an = a1+(n-1)d

a42 = -12 +(42-1)*3

a42 = -12+41 *3

a42 = -12+123

a42 = 111

Therefore 42 term is 111....

Answer:

Assuming it is arithmetic, the 42nd term is 111.

Assuming it is geometric, the conclusion says it isn't geometric.

Step-by-step explanation:

Let's assume arithmetic first.

Arithmetic sequences are linear. They go up or down by the same number over and over.  This is called the common difference.

We are giving two points on our line (1,-12) and (27,66).

Let's find the point-slope form of this line.

To do this I will need the slope.  The slope is the change of y over the change of x.

So I'm going to line up the points and subtract vertically, then put 2nd difference over 1st difference.

(1  , -12)

-(27,66)

------------

-26   -78

The slope is -78/-26=78/26=3.  The slope is also the common difference.

I'm going to use point [tex](x_1,y_1)=(1,-12)[/tex] and [tex]m=3[/tex] in the point-slope form of a line:

[tex]y-y_1=m(x-x_1)[/tex]

[tex]y-(-12)=3(x-1)[/tex]

Distribute:

[tex]y+12=3x-3[/tex]

Subtract 12 on both sides:

[tex]y=3x-3-12[/tex]

[tex]y=3x-15[/tex]

So we want to know what y is when x=42.

[tex]y=3(42)-15[/tex]

[tex]y=126-15[/tex]

[tex]y=111[/tex]

So [tex]a_{42}=111[/tex] since the explicit form for this arithmetic sequence is

[tex]a_n=3n-15[/tex]

-----------------------------------------------------------------------------------------

Let's assume not the sequence is geometric. That means you can keep multiplying by the same number over and over to generate the terms given a term to start with.  That is called the common ratio.

The explicit form of a geometric sequence is [tex]a_n=a_1 \cdot r^{n-1}[/tex].

We are given [tex]a_1=-12[/tex]

so this means we have

[tex]a_n=-12 \cdot r^{n-1}[/tex].

We just need to find r, the common ratio.

If we divide 27th term by 1st term we get:

[tex]\frac{a_{27}}{a_1}=\frac{-12r^{27-1}}{-12r^{1-1}}=\frac{-12r^{26}}{-12}=r^{26}[/tex]

We are also given this ration should be equal to 66/-12.

So we have

[tex]r^{26}=\frac{66}{-12}[/tex].

[tex]r^{26}=-5.5[/tex]

So the given sequence is not geometric because we have an even powered r equaling a negative number.

Answer:

The equation of the line is y = -x + 1

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope-intercept form of the equation is y = mx + c, where m is

 the slope of the line and c is the y-intercept

- To make this equation you need slope (m) and a point on the line to

 find the value of c

- The parallel lines have same slopes

* Lets solve the problem

- The line is parallel to the line y = -x - 5

∵ y = mx + c

∵ The slope of the line y = -x - 5 is the coefficient of x

∴ m = -1

∵ Parallel lines have same slopes

∴ The slope of the line is -1

∴ the equation of the line is y = -x + c

- To find c substitute x and y in the equation by the coordinates of

  any point lies on the line

∵ The line passes through point (3 , -2)

∵ y = -x + c

∴ -2 = -(3) + c

∴ -2 = -3 + c ⇒ add 3 for both sides

∴ c = 1

∴ The equation of the line is y = -x + 1

Answer:

x= 3

y= 2

Step-by-step explanation:

The given equations are :

2x-5y = -4    equation 1

x +6y = 15    equation 2

We will multiply the equation:2 by 2

2(x+6y=15)

2x+12y=30   equation 3

Lets call this equation:3

Now we will use the elimination method:

Subtract equation 3 from equation 1:

2x-5y = -4

2x+12y=30

_________

   -17y = -34

y= -34/-17

y = 2

Now put the value of y in any equation:

We will use equation 1

2x-5y = -4

2x-5(2)= -4

2x-10= -4

Move the constant to the R.H.S

2x= -4+10

2x=6

Divide both the terms by 2

x= 3

Therefore the solution set is (x,y){(3,2)}....