HELP PLEASE
Daniel, a 37-year-old male, bought a $160,000, 10-year life insurance policy. What is Daniel’s annual premium? Use the table. (table in attachment) $611.20 $728.00 $1268.80 $1652.80
Kara, a 25-year-old female, bought a $50,000, 10-year life insurance policy through her employer. Kara is paid semimonthly. How much is deducted from each of her paychecks for life insurance? Use the table below. $4.81 $5.21 $6.25 $6.77
Answers
Answer:
1) Option B- $728
2) Kara's annual premium is $62.5.
Step-by-step explanation:
1) Given : Daniel, a 37-year-old male, bought a $160,000, 10-year life insurance policy.
To find : What is Daniel's annual premium?
Solution :
In the table given,
Annual premium is per $1000 of coverage.
Daniel's life insurance policy buy is $160,000
Annual premium per $1000 coverage Daniel buy at $160
37 year old male 10 year cost is $4.55
(marked in the attached table below)
Daniel's annual premium is [tex]4.55\times 160[/tex]
[tex]=\frac{455}{100}\times 160[/tex]
[tex]=728[/tex]
Daniel's annual premium is $728
Therefore, Option B is correct.
2) Given : Kara, a 25-year-old female, bought a $50,000, 10-year life insurance policy through her employer. Kara is paid semimonthly.
To find : How much is deducted from each of her paychecks for life insurance?
Solution :
In the table given,
Annual premium is per $1000 of coverage.
Kara's life insurance policy buy is $50,000
Annual premium per $1000 coverage Kara buy at $50
25 year old female 10 year cost is $2.50
(marked in the attached table below)
Kara is paid semimonthly
So, cost is[tex]\frac{2.50}{2}=1.25[/tex]
Kara's annual premium is [tex]1.25\times 50[/tex]
[tex]=\frac{1.25}{100}\times 50[/tex]
[tex]=62.5[/tex]
Kara's annual premium is $62.5.
Related Questions
Jen has 12 ounces milkshake. 4 ounces in the milkshake are vanilla, and the rest is chocolate. What are two equivalent fractions that represent the fractions of the milkshake that is vanilla?
Answers
There are two parts two a fraction. The top part is called the numerator, which shows how many of the parts indicated by the denominator are taken.
The bottom part is called the denominator, which is the total amount of that particular thing.
In this case, 12 would be the denominator and the and 4 would be the numerator. Your fraction would look like:
4/12
Now, this question asks for equivalent fractions. An equivalent fraction is a fraction that is equivalent to the first fraction.
To equivalent fractions could be:
2/6 and 1/3
How I got these fractions? I simply divided the numerator and denominator by 2, and then again by 2 to get 1/3.
Good Day!
At the start of a race, a runner’s velocity changes from 0 to 4.0 m/s. It takes him 2 seconds to speed up. His acceleration is ______ m/s2.
Answers
Change of velocity: 4 m/s
Change of time: 2 s
Acceleration = [tex] \frac{4}{2} = 2[/tex]
So the answer: his acceleration is 2 m/s^2
His acceleration is, 2 m/s^2!
Hope this helps! :)
WILL GIVE A BRAINLEST !!!!
The graph of a logarithmic function is shown below.
What is the domain of the function?
x < 0
x > 0
x < 1
all real numbers
Answers
Hope this helps!
Answer: The correct option is second, i.e., x>0.
Explanation:
As we know that the domain is the set of all possible inputs. If function is defined as, f(x) then all possible value of x for which the function f(x) is defined is called domain.
In a graph the domain is defined on the x axis and the range of the function is defined on y-axis.
In the given graph the function is defined from x=0 to [tex]x=\infty[/tex] because for [tex]x\leq 0[/tex] the graph is not defined. It means for [tex]x\leq 0[/tex] the function is not defined.
Sicen the graph is defined for all positive values of x, therefore the domain of the function is al real number greater than 0. It can be written as x>0 and the second option is correct.
3 less than the quotient of a number y and 4
Answers
Quotient ⇒ division
The required algebraic expression can be written as [tex](y\div4)-3[/tex].
Given: a statement is [tex]3[/tex] less than the quotient of a number [tex]y[/tex] and [tex]4[/tex].
According to question,
An algebraic expression can be written by use of [tex]3[/tex] less than the quotient of a number [tex]y[/tex] and [tex]4[/tex].
Here, expression is [tex](y\div4)-3=\frac{y}{4}-3[/tex].
Therefore, the algebraic expression for the statement [tex]3[/tex] less than the quotient of a number [tex]y[/tex] and [tex]4[/tex] is written as [tex]\frac{y}{4}-3[/tex].
Learn more about Algebraic expression here:
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Use the grouping method to factor the polynomial below completely.
2x3 + 16x2 + 7x + 56
A. (x2 + 8)(x + 7)
B. (x2 + 7)(x + 8)
C. (2x2 + 7)(x + 8)
D. (2x2 + 8)(x + 7)
Answers
Which is C. (2x2+7)(x+8)
Hope I helped! :)
The shorter leg of a 30-60-90 triangle is 4. How long is the hypotenuse?
Answers
Therefore it is 8
In a 30-60-90 triangle, the hypotenuse is twice the length of the shortest leg. Hence, if the shortest leg is 4, then the hypotenuse is 8.
Explanation:In a 30-60-90 triangle, the ratios of the sides are specific and constant. The shortest side, the one opposite the 30-degree angle, is considered to be x. The longest side (hypotenuse), directly across from the 90-degree angle, is 2x, and the remaining side is x√3. In this case, the shortest side (x) is indicated to be 4.
So, in this triangle, the hypotenuse (2x) would be 2*4 = 8.
The Pythagorean theorem, as mentioned in the reference content, will also hold, but in the case of this special triangle, the ratios of the sides simplify the process of determining side lengths.
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helpppppppppppppppppppppp
Answers
7x (x^2 * y)^1/3 which is the last option
Explanation:
5x (x^2 * y)^1/3 + 2 (x^5 * y)^1/3
5x (x^2/3 * y^1/3) + 2 (x^5/3 * y^1/3)
5 * x^5/3 * y^1/3 + 2 * x^5/3 * y^1/3
(5+2) * x^5/3 * y^1/3
7* x^5/3 * y^1/3
which can be rewritten as:
7x (x^2 * y)^1/3 which is the last option
Hope this helps :)
in a pile of coins there are 7 more quarters than nickels if there is a total of $2.65 in coins how many quarters are there guess check and revise to solve
Answers
A quarter is worth $0.25 and a nickle is worth $0.05. Suppose the number of quarters is represented by q and the number of nickels is represented by n.
First Equation
"There are 7 more quarters than nickels" could be written as
⇒ q = n + 7
Second Equation
"There is a total of $2.65" could be written as
⇒ 0.25q + 0.05n = 2.65 (change to whole number, multiply both side by 100)
⇒ 25q + 5n = 265
Work on the system of equation
Substitute q = n + 7 to the second equation
25q + 5n = 265
25(n + 7) + 5n = 265
25n + 175 + 5n = 265
30n + 175 = 265
30n = 265 - 175
30n = 90
n = 90/30
n = 3
The number of nickels is 3
Substitute n = 3 to the first equation
q = n + 7
q = 3 + 7
q = 10
The number of quarters is 10
What transformation has changed the parent function f(x) = 3(2)x to its new appearance shown in the graph below?
exponential graph passing through point 0, 5.
f(x) + 2
f(x) + 4
f(x + 2)
f(x + 4)
Answers
f (x) = 3 * (2) ^ x
Then, we have the following fact that is a fact of the problem:
"exponential graph passing through point 0, 5"
Thus,
Original graphic:
f (x) = 3 * (2) ^ x
f (0) = 3 * (2) ^ 0
f (0) = 3
Graph with transformation:
g (x) = 3 * (2) ^ x + 2
g (0) = 3 * (2) ^ 0 + 2
g (0) = 3 + 2
g (0) = 5
Go through the point (0, 5)
Therefore the graph is:
g (x) = 3 * (2) ^ x + 2
g (x) = f (x) + 2
answer:
f (x) + 2
Northbound buses with tourists leave Waco for Dallas at 10 minute intervals. The trip takes exactly one hour. Southbound tourist buses leave Dallas for Waco at the same moment as their northbound counterparts and arrive an hour later. How many southbound buses does a northbound bus encounter between Waco and Dallas, including the one that is arriving in Waco just as the northbound bus leaves for Dallas and the one that is departing from Dallas just as the northbound bus arrives there?
Answers
Explanation:
When a Northbound bus leaves Waco there are 7 buses on the way from Dallas, including the one that is arriving at Waco and one departing from Dallas.
If you do not visualize it, think that the Northbound bus departs at 6:00 am, then the bus arriving at Waco departed at 5:00 am, other departed at 5:10am, other at 5:20, other at 5:30, other at 5:40, other at 5:50 and other at 6:00 am. Those are 6 buses that the Northbound bus will encounter on its way.
After that, there will departure other 6 buses that the Nortbound bus will encounter. The times for those departures are: 6:10am, 6:20am, 6:30am; 6:40am, 6:50am and, the last one, 7:00am just when it is arriving.
Therefore, the Northbound bus will encounter 7 buses + 6 buses = 13 buses, which is the answer.
Find the balance in the account after the given period. $3500 deposit 6.75% compounded monthly, after 6 months
Answers
[tex]\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to &\$3500\\ r=rate\to 6.75\%\to \frac{6.75}{100}\to &0.0675\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\to &12\\ t=years\to \frac{6}{12}\to &\frac{1}{2} \end{cases} \\\\\\ A=3500\left(1+\frac{0.0675}{12}\right)^{12\cdot \frac{1}{2}}\implies A=3500(1.005625)^6[/tex]
What term can you add to 5/6x-4 to make it equivalent to 1/2x-4
Answers
Answer:
-1/3
Step-by-step explanation:
We need a c number that:
5/6x + cx = 1/2x
We clear the equation:
cx = 1/2x -5/6x
c = 1/2 -5/6
c= -2/6 = -1/3
What is the slope of a line parallel to line B?
Answers
Answer:
[tex]\frac{5}{2}[/tex]
Step-by-step explanation:
The slope of a line parallel to b has the exact same slope as b. Therefore, by finding the slope of b, you will find the slope of a line parallel to be as well.
The following formula is used to find m, the slope of the line, using the two given points:
[tex]m=\frac{y_{1}-y_{2} }{x_{1}-x_{2} } \\m=\frac{5--5}{3--1} \\m=\frac{5+5}{3+1} \\m=\frac{10}{4} \\m=\frac{5}{2}[/tex]
Find the values of sand y
VR=y
TS=x+11
VT=y-3x
RS=x+2
Answers
therefore, y=x+11 and x+2=y-3x
y=x+11 , 2=y-4x
y=x+11 , y=4x+2
then use the process of elimination:
y=4x+2 then plug in: y=3+11
- y=x+11 y=14
0=3x-9 I think this is how you'd do it, tbh it's just an educated
3x=9 , x=3 guess. Btw, sorry if it looks weird
what expression represents a number t increased by 10
Answers
t+10
Which statement about BC←→ is correct?
BC←→ is a tangent line because △ABC is a right triangle.
BC←→ is a tangent line because the sum of the angles in △ABC is 180º.
BC←→ is not a tangent line because m∠ABC≠90°.
BC←→ is a tangent line because m∠ABC is acute.
Answers
So a tangent line is perpendicular to the radius, which means it creates a 90 degree angle with the radius of the circle. The sum of the interior angles of any triangle is 180 degrees. To determine if line BC is a tangent line, we have to determine if angle ABC is 90 degrees. Well we know the degrees of the other two angles of the triangle, so let's set up an equation:
180 = 48 + 47 + x
180 = 95 + x
85 = x
Since angle ABC must be 85 degrees (not 90), line BC is not a tangent line.
Answer:
BC←→ is not a tangent line because m∠ABC ≠ 90°.
The measure of angle at the tangent of a circle is a right angle.
The correct statement about BC is (c) BC is not a tangent line because m∠ABC≠90°.Start by calculating the measure of angle ABC using the following angle in a triangle theorem
[tex]\angle ABC + 48 + 47 = 180[/tex]
[tex]\angle ABC + 95 = 180[/tex]
Subtract 95 from both sides of the equation
[tex]\angle ABC = 180 - 95[/tex]
[tex]\angle ABC = 85[/tex]
For line BC to be a tangent, then the following must be true
[tex]\angle ABC = 90[/tex]
Hence, the correct statement about BC is (c)
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Which values are solutions to the inequality below? Check all that apply [tex] \sqrt{x} [/tex]>13
a) 26
b) 28560
c) 15
d) 170
e)1
f)251
Answers
Find the ordered triple of these equations. 2x - 3y - 4z = -21 -4x + 2y - 3z = -14 -3x - 4y + 2z = -10
Answers
The ratio of the segments into which the altitude to the hypotenuse of a right triangle divides the hypotenuse is 9 : 4. what is the length of the altitude? 6 36 3 cannot be determined
Answers
√(4*9) : 4 : 9 = 6 : 4 : 9
Since these are ratios, not measures, the actual length of the altitude cannot be determined. (4th selection)
question 1
Solve the system of equations and choose the correct answer from the list of options.
d + e = 15
−d + e = −5
Label the ordered pair as (d, e).
A (0, 0)
B (10, −5)
C (5, 10)
D (10, 5)
question2
A set of equations is given below:
Equation S: y = x + 9
Equation T: y = 2x + 1
Which of the following steps can be used to find the solution to the set of equations?
A x = 2x + 1
B x + 9 = 2x
C x + 1 = 2x + 9
D x + 9 = 2x + 1
Question 3
A set of equations is given below:
Equation C: y = 6x + 9
Equation D: y = 6x + 2
Which of the following options is true about the solution to the given set of equations?
A One solution
B No solution
C Two solutions
D Infinite solutions
question 4
Solve the system of equations and choose the correct answer from the list of options.
2x + y = −4
y = 3x + 2
A negative 6 over five comma negative 8 over 5
B negative 8 over 5 comma negative 6 over 5
C negative 5 over 6 comma negative 11 over 5
D negative 11 over 5 comma negative 6 over 5
question 5
A system of equations is given below:
y = –2x + 1
6x + 2y = 22
Which of the following steps could be used to solve by substitution?
A 6x + 2(−2x + 1) = 22
B −2x + 1 = 6x + 2y
C 6(−2x + 1) + 2y = 22
D 6(y = −2x + 1)
Answers
2. d
3. b
4. a
5. a
those are the answers to the questions
Answer:
1.D
2.D
3.B
4.A
5.A
Step-by-step explanation:
1.We are given that two equations
[tex]d+e=15[/tex]
[tex]-d+e=-5[/tex]
Adding two equations then we get
[tex]2 e=10[/tex]
[tex]e=\frac{10}{2}=5[/tex]
Substitute e=5 in equation one then we get
[tex]5+e=15[/tex]
[tex] d=15-5[/tex]
[tex]d=10[/tex]
Hence, the ordered pair as (10, 5).
Therefore,Option D is true.
2.We are given that two equations
Equation S:[tex]y=x+9[/tex]
Equatin T:[tex]y=2x+1[/tex]
Using substitution method
Substitute the value of y from equation one in equation second then we get
[tex]x+9=2x+1[/tex]
Therefore, option D is true.
3.We are given that two equations
Equation C :[tex]y=6x+9[/tex]
Equation D[tex]:y=6x+2[/tex]
The two equations can be written as
[tex]6x-y+9=0[/tex]
[tex]6x-y+2=0[/tex]
[tex]a_1=6,b_1=-1,c_1=9[/tex]
[tex]a_2=6,b_2=-1,c_2=2[/tex]
[tex]\frac{a_1}{a_2}=\frac{6}{6}=1:1[/tex]
[tex]\frac{b_1}{b_2}=\frac{-1}{-1}=1:1[/tex]
[tex]\frac{c_1}{c_2}=\frac{9}{2}[/tex]
[tex]\frac{a_1}{a_2}=\frac{b_1}{b_2}\neq\frac{c_1}{c_2}[/tex]
Therefore, system of equations have no solution
Hence, option B is true.
4.We are given that two equations
[tex]2x+y=-4[/tex]
[tex]y=3x+2[/tex]
Using substitution method
Substitute value of y from equation second in equation one
Then we get
[tex]2x+3x=2=-4[/tex]
[tex]5 x=-4-2[/tex]
[tex]5 x=-6[/tex]
[tex]x=-\frac{6}{5}[/tex]
Substitute the value of x in equation second then we get
[tex]y=3\times( -\frac{6}{5})+2[/tex]
[tex]y=\frac{-18+10}{5}[/tex]
[tex]y=-\frac{8}{5}[/tex]
Hence, option A is true.
5.We are given that two equations
[tex]y=-2x+1[/tex]
[tex]6x+2y=22[/tex]
Using substitution method
Substitute value of y from equation one in second equation then we get
[tex]6x+2(-2x+1)=22[/tex]
Hence, option A is true.
Does the interest rate increase at a constant rate?
6 months = 2.4%
9 months = 2.9%
12 months = 3.0%
18 months = 3.1%
Answers
From 6 mo to 12 mo, it increases 0.6%.
From 12 mo to 18 mo, it increases 0.1%. The change over a 6 mo period gets smaller as the period gets longer or the rate gets higher.
it seems what's being asked is, "is the change from a month to the next, constant", as in an arithmetic sequence, well, check the picture below, those coordinates do not give us a straight line, and therefore, we don't have an arithmetic sequence, and therefore, we don't have a "common difference".
and since we don't have a common difference, the rate is not constant.
Write the equation of the line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0.
Answers
x + 2y + 4 =0
Explanation:
1) You know a point (4 - 1) and that the line is perpendicular to a given line.
2) From the equation of the perpendicular line whose equation was given, you determine the slope, for which you can use the slope-intercept form of the equation:
2x - y - 7 = 0 => y = 2x + 7.
The slope is the coeffiicient of x, which is 2.
Therefore, slope = 2.
3) The slope of the other line is the negative inverse of the slope of the perpedicular line:
slope = - 1/2
4) Now that you have the slope of your line and the point (4, - 1) you determine the equation with this procedure:
y - b
------- = slope
x - a
where a y b are the coordinates of the point (4, - 1) and the slope is -1/2
=>
y - (-1)
---------- = - 1/2
x - 4
5) Simplify
2(y + 1) = - (x - 4)
2y + 1 = - x + 4
2y + x +1 + 4 = 0
x + 2y + 4 =0 <---------- this is the equation searched.
Find the area of circle B in terms of π.
Answers
Answer:
(2.25π) yd²
Step-by-step explanation:
The area of a circle is given by the formula:
[tex]\boxed{\text{Area of circle}=\pi r^{2} }[/tex] , where r is the radius.
In this question, the radius is 1.5 yd.
Substitute r= 1.5 into the formula:
Area of circle B
[tex]=\pi (1.5)^2[/tex]
= (2.25π) yd²
Additional:
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https://brainly.com/question/15245049What is the derivative of e^(2x)
I am confused because the derivative e^x is e^x.
But they say you need to use the chain rule.
Which is f'(g(x))*g'(x).
I have used that on exponents but in this I just get, 2x * e^(2x-1) *e
Which is not the answer =/
Answers
Let u=2x. So u'=2
So the derivative of e^u is e^(2x)*2 This can also be written as 2e^(2x).
the radius of a circular park is 120 m. to nearest meter, what is the circumference of the park.
Answers
A=πr²
2 x 3.14 x 120 = 754
Given: a quadrilateral with sides of 12 yards, 14 yards, 16 yards, and 18 yards. On a drawing, 1 inch = 2 yards, how long are the sides of the quadrilateral on the drawing?
A. 6,7,8 and 9 inches
B. 24,28,32 and 36 inches
C. 60, 70, 80 and 90 inches
Answers
[tex] \frac{12}{2} \: \: \: \frac{14}{2} \: \: \: \frac{16}{2} \: \: \: \frac{18}{2} \: \: \: \\ 6 \: \: \: \: \: 7 \: \: \: \: \: 8 \: \: \: \: \: 9[/tex]
so A is true
Answer:
The correct answer is option A, 6 , 7, 8, 9 inches
Step-by-step explanation:
Given the scale of drawing ,
[tex]1 inch = 2 yards\\[/tex]
The size of each side of a quadrilateral when converted as per the scale pf map
[tex]= \frac{12}{2} , \frac{14}{2} , \frac{16}{2} , \frac{18}{2} \\= 6, 7, 8 , 9 inches\\[/tex]
A pool in the shape of s rectangle has a perimeter 80 feet. The pool is 8 feet less wide than it is long
Answers
44 for length and 36 for width
Which two equations would be most appropriately solved by using the zero product property? Select each correct answer. 4x² = 13 0.25x2+0.8x−8=0 −(x−1)(x+9)=0 3x2−6x=0
Answers
Answer:
−(x−1)(x+9)=0
And..
3x2−6x=0
Step-by-step explanation:
Final answer:
The two equations most appropriately solved by using the zero product property are −(x−1)(x+9)=0 and 3x²−6x=0, as they can be directly factored into a product of terms equaling zero.
Explanation:
The question involves finding which two equations would be most appropriately solved by using the zero product property. The zero product property states that if the product of two numbers is zero, then at least one of the multiplicands must be zero. Therefore, equations that can be factored into a product of terms equaling zero can be solved using this property.
−(x−1)(x+9)=0: This equation is already in a factored form and directly applies the zero product property. Set each factor equal to zero and solve for x: x−1=0 or x+9=0, which gives x = 1 or x = −9.3x²−6x=0: This equation can be factored as 3x(x−2)=0. By applying the zero product property, set 3x=0 and x−2=0, solving for x gives x = 0 or x = 2.The other options, 4x² = 13 and 0.25x²+0.8x−8=0, are not immediately in a form that uses the zero product property without further manipulation or do not directly apply to this property.
Find X. This is Big Ideas Geometry Chapter 9.3
Answers
You can set up a ratio with the largest triangle to the second largest.
30/50=x/40
50x=1200 x=24 units
The value of x of the triangle is: x = 24 units
How to find the length of similar triangles?Pythagoras Theorem is defined as the way in which you can find the missing length of a right angled triangle.
The triangle has three sides, the hypotenuse (which is always the longest), Opposite (which doesn't touch the hypotenuse) and the adjacent (which is between the opposite and the hypotenuse).
Pythagoras is in the form of;
a² + b² = c²
Thus, the length of the base is:
c² = 30² + 40²
c² = 2500
c = √2500
c = 50 units
Using the concept of similarity ratio, we have:
30/50 = x/40
Cross multiply to get:
50x = 1200
x = 24 units
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Which of the following best describes the intersection of two planes? (Points : 5)
line
line segment
point <
ray
I think its Point?