Answers
[tex] \frac{5}{6} \times 3 = 5 \times \frac{3}{6} = 5 \times \frac{1}{2} = \frac{5}{2}[/tex]
[tex] \frac{1}{2} \times 3 = \frac{3}{2}[/tex]
[tex] \frac{1}{9} \times 3 = \frac{3}{9} = \frac{1}{3}[/tex]
40. Division by 1/2 is the same as multiplication by 2.
[tex]x \times 2 = \frac{6}{8}[/tex]
[tex]x = \frac{6}{8} \times \frac{1}{2} = \frac{3}{8}[/tex]
[tex]3 \times 2 = 6[/tex]
[tex]x \times 2 = 5[/tex]
[tex]x = \frac{5}{2}[/tex]
Related Questions
The graph of the function g(x) is shown on the coordinate plane below. For what value of x does g(x)=0
Answers
:)
:)
Answer:
the answer is 6 on algebra nation
Step-by-step explanation:
Determine whether the equation defines y as a function of x. y = 2x + 8
Answers
y = 2x + 8
for x=1-----------> y=2*1+8=10
for x=2-----------> y=2*2+8=12
for x=3-----------> y=2*3+8=14
.
.
.
the equation y = 2x + 8 ----------- > defines y as a function of x, because for each x there is only one value of y.
the answer is
yes, the equation y = 2x + 8 defines y as a function of x
A polygon has 8 sides. What is the sum of its interior angles? use formula
s = ( n - 2 ) (180°)
A. 1260°
B. 720°
C. 1620°
D. 1080°
Correct answer will be rewarded with full points as well as the mark of the brainliest
Answers
.. s = (8 -2)(180°)
.. s = 1080°
Selection D is appropriate.
_____
Put the number into the formula where the corresponding variable is, then do the arithmetic. A calculator can do the arithmetic for you, if necessary.
if a sample of 21 runners were taken from a population of 580 runners, μ could refer to the mean of how many runners times?
Answers
Answer:
the answers is 580
find the circumferences
Answers
so... notice, the larger green circle, has a radius of 22.
now, the blue smaller circle, is taking up half of the diameter of the green one, so, the diameter for the small one is 22, and its radius is half that, or 11.
[tex]\bf \textit{circumference of a circle}\\\\ C=2\pi r\\\\ -------------------------------\\\\ \stackrel{\textit{large green circle}}{C=2\cdot \pi \cdot 22}\implies C=44\pi \qquad\qquad \qquad \stackrel{\textit{small blue circle}}{C=2\cdot \pi \cdot 11}\implies C=22\pi [/tex]
Can someone explain to me how this problem is solved? Thanks.
The height of a coconut falling from a tree is represented by the function h(t)=-16t^2+24 where h(t) is the height of the coconut, in feet, and t is time, in seconds
what is the initial height, in feet, of the coconut?
Answers
h(0)=-16(0)^2+24 = 24 feet. Therefore, the initial height of the coconut is 24 feet
A land mass is roughly in the shape of a rectangle whose perimeter is 1180 miles. the width is 110 miles less than the length. find the length and the width?
Answers
Explanation:
1) Shape: rectangle
2) dimensions:
length = l
width = w
3) Formula of the perimeter of a rectangle, p = 2 * l + 2 * w
4) Data:
p = 1180 miles
length = x
width = x - 110 miles
5) Equation: p = 2x + 2(x - 110)
2x + 2(x - 110) = 1180
2x + 2x - 220 = 1180
4x = 1180 + 220
4x = 1400
x = 1400 / 4
x = 350
=> length = 350
and width = 350 - 110 = 240
6) Verification:
p = 2*length + 2 * width
1180 = 2 * 350 + 2*240
1180 = 700 + 480
1180 = 1180 => check.
Answer: length = 350 miles, widht = 240 miles
Using the fafsa, you can apply for
Answers
FAFSA stands for Free Application for Federal Student Aid. it is used to apply for student loans, grants, and scholarships sometimes.
Dylan works 30 hours a week. His hours are decreased by 20%. How many hours does he now work each week?
Answers
Answer:
He now work 24 hours each week
Step-by-step explanation:
Dylan works 30 hours a week. His hours are decreased by 20%.
The number of work hours 30 is decreased by 20%
we need to find 20% of 30
[tex]30 \cdot \frac{20}{100} =6[/tex]
So number of hours should be decreased by 6
[tex]30-6= 24[/tex]
he now work 24 hours each week
I will go to the mall if and only if I get paid today.
Determine the conditions that will make the biconditional true.
A. It is true if I go to the mall and I get paid. It is true if I go to the mall and I don’t get paid.
B. It is true if I go to the mall and I get paid. It is true if I don’t go to the mall and I don’t get paid.
C. It is true if I go to the mall and I don’t get paid. It is true if I don’t go to the mall and I don’t get paid.
D. It is true if I go to the mall and I get paid. It is true if I don’t go to the mall and I get paid.
Answers
Final answer:
The correct answer is Option B, covering both true-true and false-false scenarios.
Explanation:
To determine the conditions that make the biconditional statement true, let's analyze it step by step. The statement in question is: "I will go to the mall if and only if I get paid today." A biconditional statement is true in two scenarios: both parts are true or both parts are false.
Looking at the options provided:
Option A is incorrect because if the statement is true, I cannot go to the mall without getting paid.Option B is correct because it encompasses both scenarios where the biconditional statement holds true: If I go to the mall, then I must have gotten paid, and if I don’t go to the mall, then I must not have gotten paid.Option C is incorrect because according to the biconditional, I cannot go to the mall unless I have been paid.Option D is incorrect because if I don’t go to the mall, it must mean that I didn't get paid, which is not covered in this option.Therefore, the correct answer is Option B: It is true if I go to the mall and I get paid today. It is also true if I don't go to the mall and I don't get paid today. This matches the requirements of a biconditional statement where either both conditions are true or both are false.
if xy=c^2, prove that x^2 dx/dy+c^2=0
Answers
xy=c²==>y=c²/x
==>y'=dy/dx=-c²/x²==>x² dy/dx+c²=0 (there is a mistake)
Solve and show steps. will award brainliest.
Answers
For the first question please find the attached diagram.
As per the diagram, P is the upstream point and Q is the downstream point. The distance between P and Q is 22.5 miles.
Let the speed of the boat in the still waters of the lake be represented by S.
Then, when the boat travels upstream, the net speed of the boat will be (S-6) miles per hour because the river flows downstream and thus the speed of the boat will have to be subtracted from the speed of the river.
Now, we know that the relationship between the net speed, distance and time of travel is give as:
Distance = Net Speed x Time of travel
For the upstream ride of the board we know that Distance is 22.5 miles and Net Speed is (S-6). Therefore, the above equation will become:
[tex] 22.5=(S-6)\times T_{1} [/tex] where [tex] T_{1} [/tex] represents the time taken to travel upstream.
We can rearrange the above equation to be:
[tex] T_{1}=\frac{22.5 }{S-6} [/tex]......................(Equation 1)
By similar arguments we know that the downstream speed of the boat is S+6 and the distance travelled is the same and so the time taken to travel downstream (represented by [tex] T_{2} [/tex]) will be:
[tex] T_{2}=\frac{22.5}{S+6} [/tex]................(Equation 2)
Now, we know that the total time of travel should be 9 hours.
This means that: [tex] T_{1}+T_{2}=9 [/tex]............(Equation 3)
Plugging in the values of [tex] T_{1} [/tex] and [tex] T_{2} [/tex] from (Equation 1) and (Equation 2) into (Equation 3), we get:
[tex] \frac{22.5 }{S-6} +\frac{22.5 }{S+6}=9 [/tex]
Simplifying the above we will get a quadratic equation:
[tex] 9S^2-45S-54=0 [/tex]
The roots of this quadratic equation are:
[tex] S=-1 [/tex] and [tex] S=6 [/tex]
Since, speed cannot be negative, [tex] S=-1 [/tex] is out of consideration.
The speed of the boat in the lake is thus [tex] S=6 [/tex] miles per hour.
But we have a problem with S=6 too. The problem is that if S=6, then the boat will not be able to move upstream.
Let us solve problem 2
We are given that: [tex] \frac{x-2}{x+3}+\frac{10x}{x^2-9} [/tex]
We can rewrite it as:
[tex] \frac{x-2}{x+3}+\frac{10x}{(x-3)(x+3)} [/tex]
[tex] \frac{(x-3)(x-2)+10x}{(x-3)(x+3)} =\frac{x^2-5x+6+10x}{(x-3)(x+3)} [/tex]
Now, the numerator can be simplified as:
[tex] \frac{x^2+10x+6}{(x-3)(x+3)} =\frac{(x+3)(x+2)}{(x-3)(x+3)} =\frac{x+2}{x-3} [/tex]
Thus, our final simplified answer is:
[tex] \frac{x+2}{x-3} [/tex]
The restriction on the variable x is that it cannot be equal to either +3 or -3 as that would make the denominator of the original question equal to zero.
Thus, the restriction is [tex] x\neq \pm 3 [/tex]
The average monthly amount Isabella has spent on gasoline since 1990 is shown in the table. Use the data in the table to complete the statements. Let x be the number of years since 1990. The year 2005 corresponds to an x-value of . The function that best models the data, with numerical values rounded to the nearest hundredth, is f(x) = x + 22.08. Models have their limitations. For which year would this model not make sense to use?
Answers
Answer 2: 11.55
Answer 3: 1985
if a and b are independent events then it must be true that P(A|B)=P(A) TRUE OR FALE
Answers
Because two events A and B are called independent if P(A|B)= P(A), i.e., if conditioning on one does not effect the probability of the other.
PLEASE HELP
Use the domain {½ , 1, 2, 4, 8} to plot the points on the graph for the given equation.
[tex]y=log_{2}x[/tex]
WILL MARK AS BRAINLIEST
Answers
- for x=[tex] \frac{1}{2} [/tex], [tex]log x_{2} ( \frac{1}{2} )=-1[/tex]. Now we have our first ordered pair: [tex]( \frac{1}{2} ,-1)[/tex]
- for [tex]x=1[/tex], [tex]log_{2} (1)=0[/tex] which gives us our next ordered pair: [tex](1,0)[/tex]
- for x=2, [tex]log_{2} (2)=1[/tex], so (2,1)
- for x=4, [tex]log_{2} (4)=2[/tex], so (4,2)
- for x=8, [tex]log_{2} (8)=3[/tex], so our last order pair is (8,3)
Finally we can plug the points and joint them to create our graph:
Answer:
Warning the guy above is correct just make sure you count each line as 1,2,4,8. On the graph if you count the bold big lines for the domain you will run out of room for the last domain for 8. Like the person above did.
Step-by-step explanation:
Look at the picture below // 99 points // PLEASEE HELPP
Answers
The polygon won't change shape or size, just its position.
Please mark Brainliest!
-Belle
Write the polynomial −11x^3 − 2 − 9x^5 − 4x^2 − 6x^4 − 14x in standard form. Then give the leading coefficient. HELP ASAP!
Answers
− 9x^5− 6x^4 −11x^3− 4x^2− 14x − 2
the leading coefficient refers to the coefficient of the highest degree, which is -9 in this case.
Writing a polynomial is standard form means arranging them accordingly, in descending power form:
-11x³ - 2 - 9x⁵ - 4x² - 6x⁴ - 14x
The highest power is 5, now we should arrange in decreasing manner
-9x⁵ - 6x⁴ - 11x³ - 4x² - 14x - 2
The leading coefficient is -9
30 POINTS + BRAINLIEST.. PLEASE CHECK MY ANSWER
Answers
Good job!
Answer:
you are correct good job
Three times the number of blue marbles exceeds twice the number of red marbles by 18 also five times the number blue marbles is two less than six times number of red marbles how many of each are there
Answers
x----------> number of blue marbles
y----------> number of red marbles
we know that
3x=2y+18----------> y=(3x-18)/2------> equation 1
and
5x=6y-2-----------> y=(5x+2)/6----------> equation 2
(1)=(2)
(3x-18)/2=(5x+2)/6----> 3*(3x-18)=5x+2
9x-54=5x+2
9x-5x=2+54-------> 4x=56---------> x=14
y=(3x-18)/2-------> y=(3*14-18)/2=24/2-------> y=12
the answer is
14 blue marbles
12 red marbles
which of the numbers below could be terms in the sequence an=4n-7 A)29 B)21 C)20 D)28
Answers
Answer:
A)29 and B) 21,
Step-by-step explanation:
First,in the sequence[tex]a_n=4n-7[/tex] , the parameter [tex]n[/tex] must to be a integer.
Second, we need to solve the equations by [tex]n[/tex].
[tex]n=(a_n+7)/4[/tex]
All the option in the problem represent an [tex]a_n[/tex]
Then, we need to prove all number in the options, if the result is a integer number, this option can be part of the sequence.
For A)
[tex]n=(29+7)/4=9\\[/tex]
For B)
[tex]n=(21+7)/4=7\\[/tex]
For C)
[tex]n=(20+7)/4=6.75\\[/tex]
For D)
[tex]n=(28+7)/4=8.75\\[/tex]
Only A) and B) only A and B meet the requirement
How was his payment
Answers
So he'll pay 630 over 8 equal payments
Divide: 630/8 = 78.75
His monthly payment is $78.75
describe the transformation of the following function y=tan(2x-pi)
Answers
[tex]\bf \bullet \textit{ horizontal shift by }\frac{C}{B}\\ ~~~~~~if\ \frac{C}{B}\textit{ is negative, to the right}\\\\ ~~~~~~if\ \frac{C}{B}\textit{ is positive, to the left}\\\\ \bullet \textit{vertical shift by }D\\ ~~~~~~if\ D\textit{ is negative, downwards}\\\\ ~~~~~~if\ D\textit{ is positive, upwards}\\\\ \bullet \textit{function period or frequency}\\ ~~~~~~\frac{2\pi }{B}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\ ~~~~~~\frac{\pi }{B}\ for\ tan(\theta),\ cot(\theta)[/tex]
with that template in mind, let's check this one,
[tex]\bf y=tan(\stackrel{B}{2}x\stackrel{C}{-\pi })\\\\ -------------------------------\\\\ \textit{horizontal shift of }\cfrac{C}{B}\implies \cfrac{-\pi }{2},\textit{ so of }\frac{\pi }{2}\textit{ to the right} \\\\\\ \textit{horizontal shrinkage of }B\implies 2, \textit{so by }\frac{1}{2}[/tex]
help:
quadrilateral ABCD is located at A(-2,2) B(-2,4) G(2,4) D(2,2). the quadrilateral is then transformed using the rule (x+2,y-3) to form the image A'B'C'D'. what are the new coordinates of of A'B'C'D'? describe what characteristics you would find if the corresponding vertices were connected with line segments.
Answers
In order to find the new coordinates, you need to take the given x and add 2 and the given y and subtract 3.
Therefore:
A' (-2+2 , 2-3) --> (0,-1)
B' (-2+2 , 4-3) --> (0,1)
C' (2+2 , 4-3) --> (4,1)
D' (2+2, 2-3) --> (4,-1)
Since the quadrilaterals ABCD and A'B'C'D' are rectangles, connecting the corresponding vertices would give you a parallelepiped, which means that AA', BB', CC', DD' are parallel and congruent segments.
Which equation is y = –6x2 + 3x + 2 rewritten in vertex form?
Answers
y = -6(x^2 - 0.5x) + 2
y = -6[ (x - 0.25)^2 - 0.0625] + 2
y = -6(x - 0.25)^2 + 2.375 Answer
Answer:
c
Step-by-step explanation:
twelve inches longer than width
Answers
w+12
*longer indicates addition
My teacher says everything is there to answer this question but I don't know. Someone please explain.
Two travellers spend from 12 o'clock to 6 o'clock walking along a level road, up a hill and back again. Their pace is 4 mph on the level, 3 mph uphill, and 6 mph downhill.
How far do they walk and at what time do they reach the top of the hill?
Answers
A level mile takes 1/4 of an hour (15 minutes). An uphill mile takes 1/3 of an hour (20 minutes). A downhill mile takes 1/6 of an hour (10 minutes). So, to go and return over the same mile takes half an hour. This means that in 6 hours, they went 12 miles and came 12 miles back. So they went a total of 24 hours.
If the 12 miles had been all level, it would have taken approximately 3 hours. It the 12 miles had been all uphill, it would have taken approximately 4 hours. When reaching the peak, 3.5 hours would have been the approximate time it took them to reach the top since it is in between.
Please guys help me with this question!
Answers
what is the sum of (5xy + x - 8) and (13x + 2)
Answers
Combine like terms
5xy+14x-6
Ann buys a dress in a sale. The normal price of the dress is reduced by 20%. The normal price is £36.80. Work out the sale price!
Also explain how you calculated it ...
Answers
Let's do this step by step!
#1
"Reducing" means to make something smaller, like a discount. So we are reducing the price of the dress by 20%. This means we must first find what 20% of the dress's price is and then subtract that from the price.
#2
36.80 * 20% = 7.36
So, 20% of 36.80 is 7.36. Subtract that:
#3
36.80 - 7.36 = 29.44
Answer:
The sale price of the dress is $29.44.
Good day!
A company's advertising budget is split between newspaper ads, magazine ads, television ads, and Internet ads. The company spends the same amount of money on newspaper and magazine ads. It spends 4 times the amount of money on television ads as it does on newspaper ads. It spends 2 times the amount of money on Internet ads as newspaper ads. If the budget is $22,000, how much money is spent on magazine ads?
Answers
2,750+2750=(2750x4)+(2750x2)=22,000
Answer:
2,750+2750=
2750 x 4+2750 x 2=
22,000
Step-by-step explanation: