Answer : The final temperature of balloon will be, 907 K
Explanation :
Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.
Mathematically,
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where,
[tex]V_1\text{ and }T_1[/tex] are the initial volume and temperature of the gas.
[tex]V_2\text{ and }T_2[/tex] are the final volume and temperature of the gas.
We are given:
[tex]V_1=2.3L\\T_1=25^oC=(25+273)K=298K\\V_2=7L\\T_2=?[/tex]
Putting values in above equation, we get:
[tex]\frac{2.3L}{298K}=\frac{7L}{T_2}\\\\T_2=906.95K\approx 907K[/tex]
Therefore, the final temperature of balloon will be, 907 K
Final answer:
To expand a 2.3 liter balloon to 7 liters at constant pressure, the temperature must be increased to approximately 630.20°C. This calculation is done using Charles's Law by setting up a proportion between initial and final volumes and temperatures and then converting the final temperature from Kelvins to Celsius.
Explanation:
To determine how hot a 2.3 liter balloon will have to get to expand to a volume of 7 liters, we can use Charles's Law. Charles's Law states that at constant pressure, the volume of a gas is directly proportional to its temperature in Kelvins. First, we convert the initial temperature of 25°C to Kelvins: 298.15 K (since 25 + 273.15 = 298.15). We then set up the proportionality constant using the initial conditions: V1 / T1 = V2 / T2. Substituting in our known values:
2.3 L / 298.15 K = 7 L / T2
Solving for T2 we get:
T2 = (7 L * 298.15 K) / 2.3 L
Calculating this we find T2 is approximately 903.35 K. However, to answer the question, we need to give the final temperature in degrees Celsius. Therefore, we subtract 273.15 from our final temperature in Kelvins: 903.35 K - 273.15 = 630.20°C. This is the temperature to which the balloon must be heated for it to expand to 7 liters.
A gas mixture contains the following gases with the mole fractions indicated: nitrogen (0.21), oxygen (0.16), carbon dioxide (0.23), and sulfur dioxide (0.09). The mixture also contains neon gas. What is the mole fraction of neon
Answer:
Mole fraction Ar = 0.31
Explanation:
Remember that the sum of the mole fractions in a mixture of gases = 1
Mole fraction = Moles from a gas / Total moles
Mole fraction N₂+ Mole fraction O₂+ Mole fraction SO₂+ Mole fraction CO₂ + Mole fraction Ar = 1
N₂ = 0.21
O₂= 0.16
CO₂ = 0.23
SO₂ = 0.09
Mole fraction Ar = 1 - 0.21 - 0.16 - 0.23 - 0.09
Mole fraction Ar = 0.31
What pressure in kPa is exerted by 94.60 g CO2 at 57.00 ℃ in 0.7500 L?
Answer:
The correct answer is 8,026 x 10³ kPa
Explanation:
We have gaseous CO₂ at the following conditions:
mass = 94.60 g
T= 57.00ºC = 330 K
V= 0.7500 L
We can use the ideal gas equation to calculate the pressure (P):
P x V = n x R x T
⇒ P = (n x R x T)/V
We need n, which is the number of moles of the gas. In order to calculate this, we have to calculate first the molecular weight (MM) of CO₂ as follows:
MM(CO₂)= Molar mass C + (2 x Molar mass O) = 12 g/mol + (2 x 16 g/mol) = 44 g/mol
Now, we can calculate the number of moles (n) of CO₂ from the mass and the molecular weight as follows:
n = Mass/MM = 96.60 g/44 g/mol = 2.19 moles
Now we have all the data. So, we introduce the data in the previos equation and calculate the pressure P:
P = (n x R x T)/V = (2.19 mol x 0.082 L.atm/K.mol x 330 K)/0.7500 L = 79.0152 atm
Finally, we have to convert the pressure from atm to kPa. For this, we know that 1 atm = 1,01325 x 10⁵ Pa and 1 kPa= 1000 Pa.
79.0152 atm x 1,01325 x 10⁵ Pa/atm x 1 kPa/1000 Pa = 8,026 x 10³ kPa
Answer:
7859.98 KPa
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Mass of CO2 = 94.60g
Temperature (T) = 57℃
Volume (V) = 0.75 L
Pressure (P) =?
Step 2:
Determination of the number of mole of CO2.
Mass of CO2 = 94.60g
Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol
Number of mole of CO2 =?
Number of mole = Mass/Molar Mass
Number of mole of CO2 = 94.60/44
Number of mole of CO2 = 2.15 moles
Step 3:
Conversion of celsius temperature to Kelvin temperature.
Temperature (Kelvin) = temperature (celsius) + 273
Temperature = 57℃ + 273 = 330K
Step 4:
Determination of the pressure. This is illustrated below:
The pressure can be obtained by using the ideal gas equation as shown below:
PV = nRT
Temperature (T) = 330K
Volume (V) = 0.75 L
Number of mole (n) = 2.15 moles
Gas constant (R) = 0.082atm.L/Kmol
Pressure (P) =?
PV = nRT
0.75 x P = 2.15 x 0.082 x 330
Divide both side by 0.75
P = (2.15 x 0.082 x 330)/0.75
P = 77.572 atm
Step 5:
Conversion of the pressure in atm to KPa. This is illustrated below:
1 atm = 101.325 KPa
Therefore, 77.572 atm = 77.572x101.325 = 7859.98 KPa
Which of the following is an acid?
Answer:
H2SO4 ( sulfuric acid )
Explanation:
An acid is a substance that releases hydrogen ions in solution. Strong acids like hydrochloric acid ionize completely and are highly likely to participate in chemical reactions, whereas weak acids, like acetic acid, do not ionize completely. Acids are also classified based on their ability to donate protons, which also indicates their strength.
Explanation:An acid is a substance that releases hydrogen ions (H*) in solution. Strong acids, like hydrochloric acid (HCl), ionize completely; releasing all of their H* and are, therefore, more likely to participate in chemical reactions. On the other hand, weak acids, such as acetic acid (vinegar), don't ionize completely meaning some of their hydrogen ions remain bonded within a compound in solution.
Here are examples of acids:
perchloric acidsulfuric acidhydrogen iodidehydrogen bromidehydrogen chloridenitric acidhydronium ionhydrogen sulfate ionphosphoric acidhydrogen fluoridenitrous acidacetic acidcarbonic acidhydrogen sulfideammonium ionThe strength of an acid is determined by how readily it donates its H*. For instance, Hydrochloric acid (HCl) is a strong acid as it completely dissociates into hydrogen and chloride ions, being highly acidic.
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Solution equilibrium always exists in a solution that is
Answer:
Solubility equilibrium is a type of dynamic equilibrium that exists when a chemical compound in the solid state is in chemical equilibrium with a solution of that compound. The solid may dissolve unchanged, with dissociation or with chemical reaction with another constituent of the solvent, such as acid or alkali
Explanation:
hope it helps
Which of the following best helps explain why the first ionization energy of K is less than that of Ca? The electronegativity of K is greater than that of Ca. A The atomic radius of the K atom is less than that of the Ca atom. B The valence electron of K experiences a lower effective nuclear charge than the valence electrons of Ca. C The nucleus of the K atom has fewer neutrons, on average, than the nucleus of the Ca atom has.
Answer:
B. K valence electron of K experiences a lower effective nuclear charge the valence electrons of Ca
Compared to K+, Ca+ has more shielding and shells. The fact that Ca+ has more protons in its nucleus, which results in a weaker nucleus-electron attraction and lower energy requirements for its removal. Thus, option B is correct.
What is ionization energy?Ionization energy, sometimes referred to as ionization potential, is the amount of energy needed to remove an electron from an isolated atom or molecule in physics and chemistry.
The energy required to expel the outermost, or highest energy, electron from a neutral atom in the gas phase is known as the initial ionization energy of an element.
Ionization energy is conceptually the reverse of electronegativity. The atom converts more easily to a cation the lower this energy is. That an atom will become a cation decreases as this energy increases.
Therefore, The valence electron of K experiences a lower effective nuclear charge than the valence electrons of Ca.
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WILL MARK BRAINLIEST AND 30 POINTS
A radioactive nuclide that is used to label blood platelets has 49 protons and 62 neutrons. Which is the symbol of this nuclide?
Superscript 49 subscript 62 upper I n.
Superscript 62 subscript 49 upper I n.
Superscript 49 subscript 111 upper I n.
Superscript 111 subscript 49 upper I n.
Answer:
The symbol is 111/49 or D
Explanation:
Answer:
The Correct answer here Is D
Explanation:
The answer was 111/49 and i got It right.
How is the size of silver nanoparticles different from normal sized silver?
When it comes to nanoparticles, their size is what gives them their special properties. For example, silver nanoparticles have longer-lasting antibacterial properties than bigger particles of silver. Nanoparticles can be made of many different substances.
The size of silver nanoparticles different from normal sized silver as silver nanoparticles size lies between 1 nm and 100 nm and size of colloidal silver has higher than 100 nm.
What is Colloidal Silver ?Colloidal silver is also called normal silver which is a suspension of silver particles in liquid. The size of colloidal silver particle is higher than 100 nm. Colloidal silver is used in dietary supplements, medication etc.
What is Silver Nanoparticles ?Silver nanoparticles are the nanoparticles of silver the size of these nanoparticles lies between 1nm and 100 nm. Silver nanoparticles are used in medial field, industrial purpose , health care due to their unique physical properties and unique chemical properties.
Thus from the above conclusion we can say that The size of silver nanoparticles different from normal sized silver as silver nanoparticles size lies between 1 nm and 100 nm and size of colloidal silver has higher than 100 nm.
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what is the formula for magnesium nitride
Answer:Mg₃N₂
Explanation: Magnesium nitride possesses the chemical formula Mg₃N₂, is an inorganic compound of magnesium and nitrogen. At room temperature and pressure it is a greenish yellow powder.
The Formula is Mg3N2 with a
Molar mass of 100.9494 g/mol and
Density of 2.71 g/cm³
Scientific explanations of natural phenomena are based on A. opinion polls of scientists. B. only the observations made by a single scientist. C. only the most recent empirical evidence. D. all the empirical evidence available.
Answer: D. all the empirical evidence available.
Explanation:
Answer:
D
Explanation:
How many grams of lithium carbonate are needed to make a concentration of 12.7M in a 5L solution
Answer:
The answer to your question is 4699 g
Explanation:
Data
mass of Li₂CO₃ = ?
concentration = 12.7 M
volume = 5 l
Process
To solve this problem use the formula of Molarity and solve it for moles.
1.- Write the formula of Molarity
Molarity = moles / volume
-Solve it for moles
moles = Molarity x volume
2.- Substitute the values
moles = 12.7 x 5
3.- Result
moles = 63.5
4.- Calculate the molar mass of Li₂CO₃
Li₂CO₃ = (7 x 2) + (12 x 1) + (16 x 3)
= 14 + 12 + 48
= 74 g
5.- Use proportions to calculate the moles
74 g of Li₂CO₃ -------------- 1 mol
x -------------- 63.5 moles
x = (63.5 x 74 ) /
x = 4699 g
Carbon-14 is a radioactive isotope. It is found in the air in carbon dioxide molecules. The amount of carbon-14 in the air has stayed the same for thousands of years. There is a small amount of radioactive carbon-14 in all living organisms because it enters the food chain.
Once an organism dies, it stops taking in carbon-14. The carbon-14 it contained at the time of death decays over a long period of time, and the radioactivity of the material decreases.
The approximate time since the organism died can be worked out by measuring the amount of carbon-14 left in its remains compared to the amount in living organisms.
In 1991, two hikers discovered a mummified man, preserved for centuries in the ice on an alpine mountain. Small samples from his body were carbon dated by scientists and found to contain 50% carbon-14 remaining. Based on this finding, how old are the remains of the body estimated to be?
A.
About 5,700 years
B.
About 11,400 years
C.
About 22,800 years
D.
Over 30,000 years
Answer: A. About 5,700 years
Explanation:
Expression for rate law for first order kinetics is given by
[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]
where,
k = rate or decay constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
Thus the time taken to carbon-14 to reduce to 50% is called as half life.
From the graph, it comes out to be 5750 years which is close to 5700 years
the students should be required to pass a standard safety quiz before being allowed to participate in chemical experiments.The standard safety requirements for heating areAlways wear safety glasses.Always point the test tube away from any other person in the lab.Heat the test tube being held at an angle so there is a way for the gases produced to escape safely.Heat the test tube at the top of the solution not the bottom where a gas bubble can cause an explosion.Heat the test tube gently moving the heat away as the solution begins to boil.
How many moles of salt are in 13.8g of sodium chloride
Answer:
0.236 mol
Explanation:
To find the moles of salt, divide the grams by the molar mass of sodium chloride which is 58.44 g/mol.
13.8/58.44=0.236 moles
Answer:
0.236 moles
Explanation:
which Law relates temperature,pressure,volume,and the number of miles of a gas under perfect conditions
Answer:
the ideal gas law
Explanation:
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What would happen to the density of an ideal gas if its pressure is cut in half and its Kelvin temperature decreases by 10 times the original temperature? Be sure to explain in words and numbers!!!
Answer:
The density increases by 5 times
Explanation:
We can solve this problem by using the equation of state of an ideal gas:
[tex]pV=nRT[/tex]
where
p is the pressure of the gas
V is its volume
n is its number of moles
R is the gas constant
T is the Kelvin temperature
Since n and R are constant during a gas transformation, we can rewrite the equation as
[tex]\frac{p_1 V_1}{T_1}=\frac{p_2 V_2}{T_2}[/tex]
In thhis problem we have:
[tex]p_2=\frac{p_1}{2}[/tex], since the pressure of the gas is cut in half
[tex]T_2=\frac{T_1}{10}[/tex], since the gas temperature decreases by 10 times
Therefore solving for V2, we find how much does the volume of the gas change:
[tex]V_2=\frac{p_1 V_1 T_2}{p_2 T_1}=\frac{p_1 V_1 (T_1/10)}{(p_1/2) T_1}=\frac{V_1}{5}[/tex]
So, the volume decreases by 5 times.
The density of the gas is given by
[tex]d=\frac{m}{V}[/tex]
where m is the mass of the gas and V its volume. Here, the mass of the gas remains constant: so, the density is inversely proportional to the volume. Therefore, if the volume decreases by 5 times, the density will increase by 5 times.
Aluminium reacts with chloride to produce aluminium chloride if you begin with 3.2g of aluminium and 5.4g of chloride which is the limiting reactant and how many grams of aluminium chloride can be produced from the amount of limiting reactant available
Answer:
A. Chlorine (Cl2) is the limiting reactant.
B. 6.77g of AlCl3
Explanation:
The balanced equation for the reaction. This is given below:
2Al + 3Cl2 —> 2AlCl3
Next, we shall determine the masses of Al and Cl2 that reacted and the mass of AlCl3 produced from the balanced equation. This is illustrated below:
Molar Mass of Al = 27g/mol
Mass of Al from the balanced equation = 2 x 27 = 54g
Molar Mass of Cl2 = 2 x 35.5 = 71g/mol
Mass of Cl2 from the balanced equation = 3 x 71 = 213g
Molar Mass of AlCl3 = 27 + (3x35.5) = 133.5g/mol
Mass of AlCl3 from the balanced equation = 2 x 133.5 = 267g
Thus, from the balanced equation above,
54g of Al reacted with 213g of Cl2 to produced 267g of AlCl3.
A. Determination of the limiting reactant. This is illustrated below:
From the balanced equation above,
54g of Al reacted with 213g of Cl2.
Therefore, 3.2g of Al will react will react with = (3.2 x 213)/54 = 12.52g of Cl2.
We can see that it will take a higher mass of Cl2 ( i.e 12.52g) than what was given ( i.e 5.4g) to react with 3.2g of Al.
Therefore, Cl2 is the limiting reactant.
B. Determination of the mass of AlCl3 produced from the amount of the limiting reactant available.
This is illustrated below:
The limiting reactant is Cl2 with a mass of 5.4g
From the balanced equation above, 213g of Cl2 reacted to produced 267g of AlCl3.
Therefore, 5.4g of Cl2 will react to produce = (5.4 x 267)/213 = 6.77g of AlCl3.
Therefore, 6.77g of AlCl3 is produced from the amount of the limiting reactant available.
The correct answer is that chloride is the limiting reactant and 13.25 grams of aluminium chloride can be produced from the amount of limiting reactant available.
To determine the limiting reactant and the amount of aluminium chloride that can be produced, we need to use stoichiometry. The balanced chemical equation for the reaction between aluminium (Al) and chloride (Cl) to form aluminium chloride (AlCl3) is:
[tex]\[ 2\text{Al} + 3\text{Cl}_2 \rightarrow 2\text{AlCl}_3 \][/tex]
First, we need to calculate the moles of Al and Cl2 available:
- For aluminium (Al):
[tex]\[ \text{Moles of Al} = \frac{\text{Mass of Al}}{\text{Molar mass of Al}} = \frac{3.2 \text{ g}}{26.98 \text{ g/mol}} \approx 0.12 \text{ mol} \][/tex]
- For chloride (Cl2):
[tex]\[ \text{Moles of Cl}_2 = \frac{\text{Mass of Cl}_2}{\text{Molar mass of Cl}_2} = \frac{5.4 \text{ g}}{35.45 \text{ g/mol}} \approx 0.15 \text{ mol} \][/tex]
Next, we use the stoichiometry of the balanced equation to determine which reactant is limiting:
- The ratio of the moles of Cl2 to Al required by the balanced equation is 3:2.
- For the given moles of Al (0.12 mol), the required moles of Cl2 would be:
[tex]\[ \text{Required moles of Cl}_2 = \frac{3}{2} \times 0.12 \text{ mol} = 0.18 \text{ mol} \][/tex]
Since we only have 0.15 mol of Cl2, chloride is the limiting reactant.
Now, we calculate the amount of AlCl3 that can be produced from the limiting reactant (Cl2):
- From the balanced equation, 3 moles of Cl2 produce 2 moles of AlCl3.
- Therefore, 0.15 moles of Cl2 will produce:
[tex]\[ \text{Moles of AlCl}_3 = \frac{2}{3} \times 0.15 \text{ mol} = 0.1 \text{ mol} \][/tex]
- The molar mass of AlCl3 is:
[tex]\[ \text{Molar mass of AlCl}_3 = 26.98 \text{ g/mol (Al)} + 3 \times 35.45 \text{ g/mol (Cl)} \approx 133.23 \text{ g/mol} \][/tex]
- Finally, the mass of AlCl3 produced is:
[tex]\[ \text{Mass of AlCl}_3 = \text{Moles of AlCl}_3 \times \text{Molar mass of AlCl}_3 \][/tex]
[tex]\[ \text{Mass of AlCl}_3 = 0.1 \text{ mol} \times 133.23 \text{ g/mol} \approx 13.323 \text{ g} \][/tex]
Rounding to the appropriate number of significant figures, we get approximately 13.25 grams of aluminium chloride.
Which statement describes how Earth compares to the moon?
Answer:
Earth has more inertia than the moon. The moon has more gravitational pull than Earth. The moon rotates at a constant speed while Earth's speed varies.
Explanation:
Answer:its a
Explanation:
If it takes 43.32 ml of 0.1 M NaOH to neutrlize a 50 ml HCI solution, how many moles of HCI were originally present?
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Is 12.0 mv at 25 °c. calculate the concentration of the zn2 (aq) ion at the cathode?
Answer:
the concentration of the Zn²⁺ (aq) ion at the cathode is 0.255 M
Explanation:
The voltage generated by the zinc electric cell that is discribed by the following relation;
[tex]Zn(s)\mid 0.1MZn^{2+(aq)}\parallel 0.2 Zn^{2+}(aq)\mid Zn(s)[/tex]
The Nernst equation is given as follows;
[tex]E = E^0 - \frac{RT}{nF} ln(\frac{a^b_B}{a^a_A} )[/tex]
[tex]E_{anode} = E^0 - \frac{0.0591}{2} logZn^{2+}[/tex]
[tex]E_{anode}-E_{cathode} =-\frac{0.0591}{2} log\frac{[Z^{2+}]}{[x]}[/tex]
[tex]0.012 =-\frac{0.0591}{2} log\frac{0.1}{[x]}[/tex]
x = 0.255 M.
Therefore the concentration of the Zn²⁺ (aq) ion at the cathode = 0.255 M.
Air was put into an automobile tire when the tire was cold, at 5.00 C. The tire’s air pressure was 3.04 atm. Later, the weather warms up. Also, the automobile is driven, further warming the tire. What will the tire’s pressure be when the temperature is 25.0 C?
Answer:
3.26 atm will the tire’s pressure be when the temperature is 25.0°C.
Explanation:
To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
where,
[tex]P_1\text{ and }T_1[/tex] are the initial pressure and temperature of the gas.
[tex]P_2\text{ and }T_2[/tex] are the final pressure and temperature of the gas.
We are given:
[tex]P_1=3.04 atm\\T_1=5.00^oC=5.00+273 K=278.00 K\\P_2=?\\T_2=25^oC=25.0+273K=298.0K[/tex]
Putting values in above equation, we get:
[tex]\frac{3.04 atm}{278.00 K}=\frac{P_2}{298.0 K}\\\\P_2=3.26 atm[/tex]
3.26 atm will the tire’s pressure be when the temperature is 25.0°C.
Using Gay-Lussac's Law, we find that when the temperature of the tire increases from 5.00 C to 25.0 C, the pressure in the car tire will increase from 3.04 atm to approximately 3.26 atm, assuming the volume and amount of gas remain constant.
To determine the tire's air pressure at a higher temperature, we can use the Gay-Lussac's Law which states that the pressure of a gas of fixed mass and fixed volume is directly proportional to the gas's absolute temperature.
The law's formula is given by P1/T1 = P2/T2, where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature respectively. Remember to convert temperatures to Kelvin by adding 273.15 to the Celsius value.
Let's calculate the final pressure, P2, when the temperature changes from 5.00 C (278.15 K) to 25.0 C (298.15 K):
P2 = (P1 x T2) / T1
Substituting the given values:
P2 = (3.04 atm x 298.15 K) / 278.15 K = (3.04 atm x 1.0719) = 3.26 atm
So, when the temperature of the tire increases to 25.0 C, the pressure in the car tire will be approximately 3.26 atm, assuming the volume and the amount of gas remain constant.
What is the specific heat capacity of a 17.5g sample of an unknown metal that
releases 6700J of heat when it cools from 90 to 25 degrees C?
Final answer:
The specific heat capacity of the unknown metal is approximately 0.097 J/g°C.
Explanation:
The specific heat capacity of a substance is the amount of heat energy required to raise the temperature of 1 gram of the substance by 1 degree Celsius. To calculate the specific heat capacity, we can use the formula:
q = mcΔT
where q is the heat energy absorbed or released, m is the mass of the sample, c is the specific heat capacity, and ΔT is the change in temperature.
Plugging in the given values:
6700J = (17.5g) * c * (90°C - 25°C)
6700J = 1225g * c * 65°C
c = 6700J / (1225g * 65°C)
c ≈ 0.097 J/g°C
Therefore, the specific heat capacity of the unknown metal is approximately 0.097 J/g°C.
Ling decided to do a science project on exercise. She wanted to find out how long it takes for a person's heart rate to slow down to normal after exercise.Which of the following was likely the scientific prediction Ling made about her project?
A.
My heart beats 60 times each minute.
B.
Exercise is important.
C.
A person's heart rate slows down in three minutes.
D.
I found out that my heart beat slows down after five minutes.
Final answer:
Ling's scientific prediction was most likely that a person's heart rate slows down to normal in three minutes after exercise, as this directly pertains to the expected outcome of her science project. Option C is correct.
Explanation:
The scientific prediction that Ling likely made about her project is related to the time it will take for a person's heart rate to return to normal after exercise. Based on the options provided, the most relevant prediction is C. A person's heart rate slows down in three minutes. This is because it refers directly to the expected outcome of the experiment regarding heart rate recovery time, while the other options are either base rate information or observations that don't predict the outcome of the experiment.
1.) A gas occupies 3.5L at 2.5 atm pressure. What is the volume at 10 atm pressure?
Answer:
.875
Explanation:
Use Boyle's Law and rearrange formula.
- Hope this helps! Please let me know if you need further explanation.
Which statement is true about sodium chloride (NaCl)?
It is a salt because it decreases the concentration of metallic ions.
It is an acid because it is formed by the reaction of a salt and an acid.
It is a salt because it is formed by the reaction of an acid and a base.
It is an acid because it increases the concentration of nonmetallic ions
Answer:
The correct answer is : It is a salt because it is formed by the reaction of an acid and a base.
Explanation:
Sodium chloride is formed from the neutralization reaction between a strong acid (hydrochloric acid) and a strong base (sodium hydroxide):
HCl + NaOH ---> NaCl + H20
By reacting strong acid and base, they neutralize each other resulting in a salt (NaCl) and water.
Corresponds to an exothermic reaction (heat is released).
The statement that is true about sodium chloride (NaCl) is:
"It is a salt because it is formed by the reaction of an acid and a base."
Sodium chloride is a classic example of a salt, which is a chemical compound formed when an acid reacts with a base through a neutralization reaction. In the case of NaCl, it is formed by the reaction of hydrochloric acid (HCl), which is an acid, and sodium hydroxide (NaOH), which is a base:
HCl + NaOH → NaCl + H2O
In this reaction, HCl (an acid) reacts with NaOH (a base) to produce NaCl (sodium chloride) and water (H2O). The formation of NaCl is a result of the combination of the positive sodium ions (Na+) from the base and the negative chloride ions (Cl-) from the acid. This reaction is an example of neutralization, where the acidic and basic properties are neutralized to form a salt and water.
So, NaCl is indeed a salt because it is formed by the reaction of an acid (HCl) and a base (NaOH).
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Identify which of the following are redox reactions. If a reaction is a redox reaction, name the element oxidized, the element reduced, the oxidizing agent, and the reducing agent. a. Mg(s) + Br2(l) --------> MgBr2(s) b. H2CO3(aq) -----------> H2O(l) + CO2(g)
Answer:
The answer to your question is below
Explanation:
a. Mg(s) + Br₂(l) --------> MgBr₂(s) It is a Redox reaction
- Calculate the Oxidation numbers
Mg(s)⁰ + Br₂(l)⁰ --------> Mg⁺²Br₂⁻¹(s)
Mg⁰ ------------ Mg⁺² Reducing agent
Br₂⁰ ------------- Br₂⁻¹ Oxidizing agent
b. H₂CO₃(aq) -----------> H₂O(l) + CO₂(g) It is not a Redox reaction
Calculate the oxidation numbers
H₂⁺¹C⁺⁴O₃⁻²(aq) -----------> H₂⁺¹O⁻²(l) + C⁺⁴O₂⁻⁴(g)
The first reaction with Magnesium and Bromine is a redox reaction, where Mg is oxidized, Br2 is reduced, Mg is the reducing agent, and Br2 is the oxidizing agent. The second reaction involving H2CO3 is not a redox reaction as there is no transfer of electrons.
Explanation:
In a redox reaction, one element is oxidized (loses electrons), while another element is reduced (gains electrons). Let's see which of these reactions fall into that category:
a. Mg(s) + Br2(l) --------> MgBr2(s) : This is a redox reaction. Here, Magnesium (Mg) is oxidized as it loses its electrons to form Mg2+. On the other hand, Bromine (Br2) is reduced as it gains electrons to form Br-. Therefore, Magnesium acts as the reducing agent (as it causes bromine to reduce), and Bromine is the oxidizing agent (as it causes magnesium to oxidize).
b. H2CO3(aq) -----------> H2O(l) + CO2(g) : This is not a redox reaction as there is no transfer of electrons between H2CO3, H2O, and CO2.
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What is the molarity of the solution with a volume of 19.93 Liters and 21.251 moles?
Answer:Dont know
Explanation:
HELP PLEASE What about winter temperatures of 0 and -3? …………….% 28 and 15? ……………….%
Answer:
45 and 12
Explanation:
- I am concerned with the question, as -3 is not possible to do on your chart or any other chart. The only other possible numbers could be 0 and 3, which give you 45.
- The second problem look at 28 on left hand side and 15 on top. Meet those in the middle and you get 12.
A chemical reaction in which an acid and a base react to produce salt and water is called a neutralization reaction. In the
neutralization reaction shown below, which substance is the salt?
sulfuric acid + ammonium hydroxide -- ammonium sulfate + water
A. water
B.
sulfuric acid
C. ammonium hydroxide
D.
ammonium sulfate
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The pH of a liquid is a measure of how acidic or basic it is. The concentration of hydrogen ions in a liquid is labeled [H+]. Use the formula pH = –log[H+] to find the pH level, to the nearest tenth, of a liquid with [H+] about 6.2 x 10^–14.
A) -14.8
B) 14.8
C) 13.2
D) -13.2
Answer:
The answer to your question is the letter C) 13.2
Explanation:
Data
pH = ?
[H⁺] = 6.2 x 10⁻¹⁴
Process
As is mentioned in the description, pH determines the concentration of H⁺ in a solution. The scale of pH goes from 0 to 14. A solution is acidic if the pH is between 0 and 6.9. The solution is neutral if the pH is 7. And a solution is basic if the pH is between 7.1 and 14.
Formula
pH = -log [H⁺]
Substitution
pH = -log[6.2 x 10⁻¹⁴]
Simplification
pH = -(-13.2)
Result
pH = 13.2
Describe a main goal of secondary treatment in a modern sewage treatment plant.
Answer:
Explanation:
The main goal of secondary treatment is the further treatment of the liquid waste from primary treatment to remove the residual organics and suspended solids. Most times, secondary treatment follows primary treatment and involves the removal of biodegradable dissolved and colloidal organic matter using aerobic biological treatment processes. Aerobic biological treatment as the name implies, it is performed in the presence of oxygen by aerobic microorganisms (principally bacteria) that metabolize the organic matter in the wastewater, thereby producing more microorganisms and inorganic end-products majorly CO2, NH3, and H2O.
Answer:
A wastewater treatment plant serves to evacuate solids, reducing organic matter and present pollutants, thus restoring oxygen. Bacteria and other microorganisms are used to reduce organic matter and pollutants, so that they consume the organic matter present in the waste water.
The primary purpose of secondary treatment is to improve the process so that at least 90% of all contaminants are evacuated. The equipment used for this purpose is an aeration tank, which supplies large amounts of air to a mixture of wastewater, bacteria and microorganisms. The oxygen found in the injected air increases the growth of microorganisms, so that they consume the organic matter found in the waste water.
Explanation: