Answer:
Increase in temperature decrease the solubility of games in liquid
Explanation:
Solubility simply means the amount of solute that can be dissolved in a given amount of solute at a given temperature.Gases when heated gains extreme kinetic energy which gives rise to an exothermic reaction,the kinetic energy breaks the individual bonds holding gas molecules leading to their escape,so an increase in temperature decrease the solubility of gas in liquid
A falling skydiver opens his parachute. A short time later, the weight of the skydiver-parachute system and the drag force exerted on the system are equal in magnitude. Which of the following statements predicts the motion of the skydiver at this time? a.The skydiver is at rest. b.A The skydiver is moving downward with constant speed. c.The skydiver is moving downward with an upward acceleration. d.The skydiver is moving downward with a downward acceleration.
A falling skydiver opens his parachute. A short time later, the weight of the skydiver-parachute system and the drag force exerted on the system are equal in magnitude. The following statements predicts the motion of the skydiver at this time
The skydiver is moving downward with constant speed.
Explanation:
Immediately on leaving the aircraft, the skydiver accelerates downwards due to the force of gravity. There is no air resistance acting in the upwards direction, and there is a resultant force acting downwards. The skydiver accelerates towards the ground.
The forces acting on a falling leaf are : gravity and air resistance.
The net force and the acceleration on the falling skydiver is upward.
An upward net force on a downward falling object would cause that object to slow down. The skydiver thus slows down.
As the speed decreases, the amount of air resistance also decreases until once more the skydiver reaches a terminal velocity.
A skydiver falling at a constant speed opens his parachute. When the skydiver is falling, the forces are unbalanced.
The drag force opposes the relative motion of an object in a fluid
The option that gives the statement that predicts the motion of the skydiver when the magnitude of the weight of the skydiver-parachute system and the drag force are equal is option b.
b. The skydiver is moving downward with constant speed
The reason the above option is correct is as follows:
The skydiver is falling through the air which is a fluid and is therefore subject to drag force, [tex]F_D[/tex], which is given as follows;
[tex]F_D = \dfrac{1}{2} \times \rho \times v^2 \times C_D \times A[/tex]
Where;
[tex]F_D[/tex] = The drag force
ρ = The fluid density
v = The relative object speed compared to the fluid
A = Cross sectional area
[tex]C_D[/tex] = The drag coefficient
Therefore, given that the surface area of the falling skydiver is largely increased when the parachute is opened and the drag force is a function of the square of the velocity, we have that the drag force rapidly equals the weight of the skydiver, such that the net force becomes zero, and therefore, the speed of the skydiver becomes constant
Therefore, the correct option is that the skydiver is moving downward with constant speed
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Draw equipotential lines near the positive and negative charges below with dashed lines. b) Draw solid electric field lines based on the fact that they are perpendicular to the equipotential lines at every point. Include arrows on the electric field lines to indicate their direction (since they represent vectors at each location).
Answer: find the attached figure for a and b
Explanation:
A) The second figure depict electric field lines and equipotential lines for two equal but opposite charges. The equipotential lines can be drawn by making them perpendicular to the electric field lines. The potential is greatest (most positive) near the positive charge and least (most negative) near the negative charge.
B) The figure attached depicts an isolated point charge Q with its electric field lines in blue and equipotential lines in green. The potential is the same along each equipotential line, meaning that no work is required to move a charge anywhere along one of those lines. Work is needed to move a charge from one equipotential line to another. Equipotential lines are perpendicular to electric field lines in every case.
Please find the attached file for the figure
The five general principles from the APA are meant to __________. A. be enforceable rules B. be posted in every office C. guide and inspire good conduct D. stand up in court Please select the best answer from the choices provided A B C D
Answer: C
guide and inspire good conduct
Explanation:
APA are rules of proper source documentation to avert difficulty. This makes you feel that you are not alone. Having to follow detailed citation and formatting guidelines as well may seem like just one more task to add to an already-too-long list of requirements.
Final answer:
Correct answer is C. The five general principles of the APA are meant to guide and inspire good conduct among psychologists, offering a values framework rather than serving as enforceable rules.
Explanation:
The five general principles from the American Psychological Association (APA) are meant to guide and inspire good conduct. These principles serve as ethical guidelines for behaviors and decision-making in psychological practice.
In contrast to enforceable rules, which are mandatory and spell out specific prohibitions and mandates, principles and guidelines such as those provided by the APA are not meant to be enforceable or stand up in court but rather to provide a framework for ethical practice.
They offer a set of values that psychologists are encouraged to aspire to in their professional conduct. These principles cover important areas such as respect for people's rights, integrity, and social responsibility in practice.
Which part of the motor is responsible for reversing the flow of current?
Answer:
Commutator.
Explanation:
It is electrical switch and consist of cylinder. Split rings are two halves of a ring that act as a Commutator. When current in the coil is Zero and is about to change the direction.
Which moon has a thick atmosphere made mostly of nitrogen?
Titan, Saturn's moon, has a thick atmosphere primarily composed of nitrogen. Its unique chemistry and thick atmosphere make it an interesting place for scientific study.
Explanation:Titan, Saturn's moon, has a thick atmosphere made mostly of nitrogen. The atmosphere on Titan is thicker than Earth's and is primarily composed of nitrogen, with about 5% methane. The thick atmosphere and unique chemistry of Titan make it an interesting place for scientific study, as it may provide clues about the early chemistry of the solar system and the potential for life.
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Tire inflation is very important to the safe and economical operation of any vehicle. Technician A says that the tire pressure should never exceed the maximum pressure imprinted on the sidewall of the tire. Technician B says to inflate tires to the pressures recommended on the tire information decal or placard on the drivers door. Which technician is correct? Group of answer choices: a) Technician A only b) Tehnician B only c) Both tehnicians A and B d) Neither tehnicians A nor B.
Answer:
The correct option is;
c) Both technicians A and B
Explanation:
Normally the pressure required for a normally inflated tire is included on the side or sidewall of the tire along with the instruction as to the qualification and training required to inflate the vehicle tire. Other information on the sidewall includes the tire model, brand name and manufacturer.
The proper inflation pressure can also be located on the tire information manual or decal as well on the door on the driver's side.
Technician B is correct in recommending that tires should be inflated to the pressure specified on the vehicle's placard. It is more accurate than the maximum pressure imprinted on the tire sidewall.
When considering tire inflation for safe and economical operation of a vehicle, there seem to be conflicting recommendations from two technicians on the correct pressure. Technician A suggests that tire pressure should never exceed the maximum pressure imprinted on the sidewall of the tire. However, this is not necessarily the recommended operating pressure; it is simply the maximum pressure that the tire can safely handle. Technician B provides a more accurate recommendation by advising to inflate tires to the pressures recommended on the tire information decal or placard on the driver's door. This placard usually lists the optimal pressure for the vehicle's tires based on the manufacturer's specifications, and accounts for the best performance and safety.
Most vehicle manufacturers specify the optimal tire pressure for cold tires, which might differ from the maximum pressure on the tire sidewall. Maintaining the proper air pressure in the tires ensures smoother and safer rides, better gas mileage, and longer tire life. Therefore, the correct answer to the question is (b) Technician B only.
Which explains earthquakes and volcanic eruptions
Answer: plate tectonics
Explanation: plate tectonics move constantly movement in narrow zones along plate boundaries causes earthquakes and plate tectonics come together and create pressure upon the magma deposit underground forcing it up into a volcanic eruption
The High Speed Industrial Drill With Diameter Of 98 Cm Develops 5.85hp At 1900 Rpm. What Torque And Force Is Applied To The Drill Bit? This problem has been solved! See the answer. The high speed industrial drill with diameter of 98 cm develops 5.85hp at 1900 Rpm. What torque and force is applied to the drill bit?
Answer:
The torque applied by the drill bit is T = 16.2 Nm and the cutting force of the drill bit is F = 33 N.
Explanation:
Given:-
- The diameter of the drill bit, d = 98 cm
- The power at which drill works, P = 5.85 hp
- The rotational speed of drill, N = 1900 rpm
Find:-
What Torque And Force Is Applied To The Drill Bit?
Solution:-
- The amount of torque (T) generated at the periphery of the cutting edges of the drilling bit when it is driven at a power of (P) horsepower at some rotational speed (N).
- The relation between these quantities is given:
T = 5252*P / N
T = 5252*5.85 / 1900
T = 16.171 Nm
- The force (F) applied at the periphery of the drill bit cutting edge at a distance of radius from the center of drill bit can be determined from the definition of Torque (T) being a cross product of the Force (F) and a moment arm (r):
T = F*r
Where, r = d / 2
F = 2T / d
F = 2*16.171 / 0.98
F = 33 N
Answer: The torque applied by the drill bit is T = 16.2 Nm and the cutting force of the drill bit is F = 33 N.
Answer:
1) Torque = 21.934 Nm
2) force = 44.76 N
Explanation:
Power = 5.88 hp
1 hp = 746 W
Power = 5.88 x 746 = 4364.1 W
Angular speed in Rpm = 1900 rpm
But angular speed w = (2¶N)/60 rad/s
= (2 x 3.142 x 1900)/60 = 198.968 rad/s
From,
1) Power P = T x w
Where T = torque
T = P/W = 4364.1/198.968 = 21.934 Nm
2) diameter of drill = 98 cm
Radius = 98/2 = 49 cm = 49x10^-2 m
From torque T = Force x radius
Force = Torque /radius
F = 21.934/49x10^-2 = 44.76 N
Why do some quasars have red shifts greater than 1?
A) They are made of tachyons and thus are able to move away from us faster than the speed of light.
B) They are made of different elements than any other objects in the universe.
C) They are moving towards us, which throws off our spectrometers.
D) Einstein proved it is impossible to have a redshift greater than 1; these are all due to gravitational lensing tricking us
Answer:
D) Einstein proved it is impossible to have a redshift greater than 1; these are all due to gravitational lensing tricking us
Explanation:
By Einstein's theory of relativity the maximum value of the red shift is 1. This correspond to a case in which the observed frequency equals the emitted frequency:
[tex]z=\frac{f_e-f_o}{f_o}[/tex]
in other cases the red shift is lower than one.
Hence, the gravitational lens change the measurements of the observed frequency and because of that we calculate a greater red shift.
Hence, the answer is:
D) Einstein proved it is impossible to have a redshift greater than 1; these are all due to gravitational lensing tricking us
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Listed following are three possible models for the long-term expansion (and possible contraction) of the universe in the absence of dark energy. Rank each model from left to right based on the ratio of its actual mass density to the critical density, from smallest ratio (mass density much smaller than critical density) to largest ratio (mass density much greater than critical density).Smallest to largesta.coasting universeb.critical universec.recollapsing universe
Answer:
From smallest ratio to the largest ratio:
Coasting Universe - Critical Universe - Recollapsing Universe(From left to right)
Explanation:
The coasting universe is one that expands at a constant rate given by the Hubble constant throughout all of cosmic time. It has a ratio of actual density to critical density that is less than 1
The critical universe is one that is at balance with no expansion .I.e. the actual density and the critical density are equal, which makes the ratio of actual density to critical density to be equal to 1
Recollapsing Universe: The expansion of the universe reverses in the future and the universe eventually recollapses. The recollapsing universe has the ratio of the actual density to the critical density to be greater than 1
From smallest to largest ratio of actual mass density to critical density, the models are: coasting universe, critical universe, and recollapsing universe. In a coasting universe, expansion continues at a decreasing rate. A critical universe's expansion slows to an eventual stop. A recollapsing universe's expansion ultimately reverses, leading to contraction.
Explanation:The long-term expansion and possible contraction of the universe under different scenarios or models, in the absence of dark energy, can be ranked based on the ratio of its actual mass density to the critical density.
Continuing from the smallest mass density ratio to the largest, it would be: the coasting universe, the critical universe, and finally the recollapsing universe.
In a coasting universe, the actual density is lower than the critical density. Thus, it would continue to expand forever but at a decreasing rate. In a critical universe, the actual density equals the critical density, which means the universe's expansion will gradually slow to a stop in an infinitely far future. Lastly, in a recollapsing universe, the actual density is greater than the critical density. This leads to an eventual reversal of the expansion, causing the universe to start contracting.
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A Swinging Monkey A 8.72 kg monkey is hanging by one arm from a branch and swinging on a vertical circle. As an approximation, assume that the radial distance between the branch and the point where the monkey's mass is located to be 84.1 cm. As it swings through the lowest point on the circle, the monkey has a speed of 2.53 m/s. Calculate the magnitude of the centripetal force acting on the monkey.
Answer:
Centripetal force, F = 66.36 N
Explanation:
Given that,
Mass of the monkey, m = 8.72 kg
The radial distance between the branch and the point where the monkey's mass is located to be 84.1 cm, r = 84.1 cm
The speed of the monkey, v = 2.53 m/s
We need to find the magnitude of the centripetal force acting on the monkey. It is given by :
[tex]F=\dfrac{mv^2}{r}\\\\F=\dfrac{8.72\times (2.53)^2}{84.1\times 10^{-2}}\\\\F=66.36\ N[/tex]
So, the magnitude of the centripetal force acting on the monkey is 66.36 N.
symbols for components of electrical circuit
Answer:
an electronic symbol is a pictogram used to represent various electrical and electronic devices or functions such as wires batteries resistors and transistors in a symptomatic diagram of an electrical or electronic circuit.
Explanation:
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Final answer:
Electrical circuit diagrams use specific standardized symbols to represent various components like wires, batteries, resistors, ground, and capacitors. Symbols for wire, resistor, and battery are straightforward, while capacitors have variations depending on type. ANSI and IEC provide different standard symbol guidelines.
Explanation:
Symbols for Components of Electrical Circuits
Electrical circuit diagrams use standardized symbols to represent different components. The wire is depicted as a thin black line and is assumed to be a perfect conductor in diagrams, although in reality it is not perfect but typically close enough for practical purposes. A battery or voltage source is represented by a set of parallel lines, with the longer line denoting the positive terminal and the shorter line the negative terminal. The resistor is illustrated with a zigzag symbol, which includes any resistance within the circuit connections. Ground is typically shown as a set of one to three horizontal lines, sometimes with one of the lines angled towards the bottom.
When it comes to alternating current (AC) sources, the symbol is a sine wave enclosed in a circle. This shows the oscillating nature of the AC voltage. Capacitors are represented with two parallel lines for a fixed capacitor; an electrolytic capacitor is shown with one curved line indicating the negative terminal and one straight line for the positive terminal. A variable-capacitance capacitor is represented with an arrow through the parallel lines, signifying adjustability.
Standards such as the American National Standard Institute (ANSI) and the International Electrotechnical Commission (IEC) provide guidelines for these symbols. While the ANSI standard is widely used for its recognizability, the IEC standard might be preferred for more complex circuits due to its cleaner presentation.
7. What is the acceleration of the box?
a. 2.5 m/s2
b. 4 m/s2
c. 6 m/s2
d. 10 m/s2
Where is the image located in the case of an object placed at a distance to the left of a converging lens?
Answer:
the object is placed at 2f
Explanation:
Converging lens are convex lens, as the name emanates , they are light rays that converge at a point via a certain distance at the opposite side. Often times , any incident rays that is moving and is parallel to the principal axis is usually termed as Converging lens.
So when the object is placed at 2f , the image will be formed at 2f to the right for converging lens.
At 20 ◦C, a rod is exactly 20.05 cm long on a steel ruler. Both the rod and the ruler are placed in an oven at 270 ◦C, where the rod now measures 20.11 cm on the same ruler. What is the coefficient of linear expansion for the material of which the rod is made? Take αsteel = 1.2 × 10−5 K−1 .
The coefficient of linear expansion for the material of the rod can be calculated using the formula ΔL/L = α ΔT to be α = 2 x 10⁻⁵ °C⁻¹.
Explanation:The subject of this question is the calculation of the coefficient of linear expansion for a certain material. The relevant formula here is: ΔL/L = α ΔT, where ΔL is change in length, L is original length, α is coefficient of linear expansion and ΔT is change in temperature.
Firstly, we calculate the change in length of the rod (ΔL) which is the final length minus initial length, 20.11 cm - 20.05 cm = 0.06 cm. Then, the change in temperature (ΔT) is the final temperature minus the initial one: 270°C - 20°C = 250°C.
After substitution into the formula, we get 0.06 cm / 20.05 cm = α × 250°C. Solving for α, we get the coefficient of linear expansion for the material of the rod to be α = 2 x 10-5 °C⁻¹.
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The coefficient of linear expansion for the material of the rod is approximately 0.011974 cm/°C.
Explanation:Solution:To find the coefficient of linear expansion for the material of which the rod is made, we can use the equation for linear thermal expansion:
ΔL = αLΔT
where ΔL is the change in length, α is the coefficient of linear expansion, L is the initial length of the rod, and ΔT is the change in temperature.
Given that the initial length of the rod is 20.05 cm, the final length is 20.11 cm, and the change in temperature is 270 °C - 20 °C = 250 °C, we can substitute these values into the equation to solve for α:
ΔL = αLΔT20.11 cm - 20.05 cm = (α)(20.05 cm)(250 °C)0.06 cm = 5.0125 α °Cα = 0.06 cm / 5.0125 °Cα = 0.011974 cm/°CHence, the coefficient of linear expansion for the material of which the rod is made is approximately 0.011974 cm/°C.
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When the batter hit the foul ball, the baseball moved upward to a delighted fan in the top deck.
A. KE increases and PE increases.
B> KE increases and PE decreases.
C. KE decreases and PE increases.
D. KE decreases and PE decreases.
We can see here that the correct answer is: A. KE increases and PE increases.
As the ball moves upward against gravity, its height increases, indicating a rise in its potential energy (PE). Since the ball moves, its speed increases, implying an increase in its kinetic energy (KE) as well.
KE (kinetic energy) is the energy possessed by an object due to its motion. When the batter hits the foul ball, the baseball is set in motion, and its kinetic energy increases as it moves upward.
PE (potential energy) is the energy possessed by an object due to its position or condition.
A stone is thrown vertically upwards with an initial velocity of 30meter per second from the top of a tower 20metes high find the time taken to reach the maximum height and the total time which elapses before it reaches the ground and gravity is 10meter per second .
Answer:
time taken to reach maximum height(t)=3seconds
Explanation:
1st equation of motion:v=u-gt ,but v=0 at maximum height.so 0=u-gt
t=u÷g where,u=30m/s,h=20m,g=10m/s square
so t=30÷10
t=3seconds
Nuclear power stations transfer useful energy to other energy stores. How is this useful energy carried from the power stations?
I
Nuclear power stations transfer energy by nuclear fission to heat water, producing steam. This steam drives turbines connected to generators, producing electricity. The electricity is transported through power lines across the national grid.
Explanation:In a nuclear power station, the useful energy is primarily carried from the power plant through the national grid system. Here's how it works: nuclear power stations transfer energy via a process called nuclear fission where atoms are split, releasing a large amount of energy. This energy is used to heat up water, even to the point of converting it to steam. The steam drives the turbines which are connected to generators. These generators produce electricity, which is then distributed through power lines across the national grid, reaching homes, factories, offices and so on.
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In an inelastic collision, a steel ball of mass 200 g was hit hard into a large ball of dough of mass 700 g. The velocity of the steel ball was 25 m/s. After the collision, the steel ball was stuck in the dough, and this combined system rolled for some time. What was the velocity of the system of the steel ball and dough after the collision?A) 5.6 m/sB) 7.5 m/sC) 8.8 m/sD) 11.1 m/s
Answer:
Velocity after collision will be 5.56 m/sec
So option (a) will be correct answer
Explanation:
Mass of steel ball [tex]m_1=200gram=0.2kg[/tex]
Speed of steel ball before collision [tex]v_1=25m/sec[/tex]
Mass of large ball [tex]m_2=700gram=0.7kg[/tex]
Velocity of large ball [tex]v_2=0m/sec[/tex]
According to conservation of momentum
[tex]m_1v_1+m_2v_2=(m_1+m_2)v[/tex]
[tex]0.2\times 25+0.7\times 0=(0.7+0.2)v[/tex]
[tex]v=5.56m/sec[/tex]
So velocity after collision will be 5.56 m/sec
So option (a) will be correct answer
An inverted image of an object is viewed on a screen from the side facing a converging lens. An opaque card is then introduced covering only the upper half of the lens. What happens to the image on the screen?
Answer:
d) The image would be dimmer
Explanation:
When inverted image of an object is viewed on a screen from the side facing a converging lens, the
lens focuses the diverging, and blurred light rays from the distance object through refraction of the rays two times.Then the rays is converge by the double bending cl at a focal point behind the lens inorder for a sharper image to be be observed.
But when an opaque card is then introduced to cover only the upper half of the lens then the image becomes dimmer because of the reduction in the light intensity on the screen by 50%
When the opaque card should be introduced so here the image should be considered as the dimmer.
Inverted image:At the time when the inverted image should be viewed on the screen that faced the converging lens so here the lens should be focused on the diverging also there should be blurred light rays from the distance object via the refraction of the rays.
However, at the time there is the opaque card so here the image should be dimmer since there is the decrease in the light intensity by 50%/
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A car is moving with speed 20 m/s and acceleration 2 m/s2 at a given instant. Using a second-degree Taylor polynomial, estimate how far the car moves in the next second. Do you think it would be reasonable to use this polynomial to estimate the distance traveled during the next minute? Why or why not?
Answer:
[tex]T(1)=21 [/tex]
Explanation:
The equation of the position in kinematics is given:
[tex]x(t)=x_{0}+v_{0}t+0.5at^{2}[/tex]
x(0) is the initial position, in this it is 0 v(0) is the initial velocity (20 m/s)a is the acceleration (2 m/s²)So the equation will be:
[tex]x(t)=20t+0.5*2*t^{2}[/tex]
[tex]x(t)=20t+t^{2}[/tex]
Now, the Taylor polynomial equation is:
[tex]f(a)+\frac{f'(a)}{1!}(x-a)+\frac{f''(a)}{2!}(x-a)^{2}+...[/tex]
Using our position equation we can find f'(t)=v(t) and f''(x)=a(t). In our case a=0, so let's find each derivative.
[tex]f(t)=x(t)=20t+t^{2}[/tex]
[tex]f'(t)=\frac{dx(t)}{dt}=v(t)=20+2t[/tex]
[tex]f''(t)=\frac{dv(t)}{dt}=a(t)=2[/tex]
Using the Taylor polynomial with a = 0 and take just the second order of the derivative.
[tex]f(0)+\frac{f'(0)}{1!}(x)+\frac{f''(0)}{2!}(x)^{2}[/tex]
[tex]f(0)=x(0)=0[/tex]
[tex]f'(0)=v(0)=20[/tex]
[tex]f''(0)=a(0)=2[/tex]
[tex]T(t)=f(0)+\frac{f'(0)}{1!}(t)+\frac{f''(0)}{2!}(t)^{2}[/tex]
[tex]T(t)=\frac{20}{1!}(t)+\frac{2}{2!}(t)^{2}[/tex]
[tex]T(t)=20t+t^{2}[/tex]
Let's put t=1 so find the how far the car moves in the next second:
[tex]T(1)=20*1+1^{2}[/tex]
[tex]T(1)=21 [/tex]
Therefore, the position in the next second is 21 m.
We need to know if the acceleration remains at this value to use this polynomial in the next minute, so I suggest that it would be reasonable to use this method just under this condition.
I hope it helps you!
An ideal vapor-compression refrigeration cycle that uses refrigerant-134a as its working fluid maintains a condenser at 800 kpa and the evaporator at -12 degrees
c. if the cooling load is 150 kw, determine the cop and the power required for this service in kw.
Answer:
cop = 4.859
power = 30.87 KW
Explanation:
the pictures attached herewith shows the calculation
By calculating the work input to the compressor (Wc) using the COP formula and known cooling load (Qc), and assuming a COP of 4, the power required is 37.5 kW.
To determine the Coefficient of Performance (COP) and power required for the ideal vapor-compression refrigeration cycle, we'll use the following steps and equations:
Find the Heat Transfer in the Evaporator (Qc):
Given Cooling Load (Qc) = 150 kW.
Calculate Work Input to the Compressor (Wc):
Using the first law of thermodynamics:
Qc = Wc + Qh
Rearrange to find Wc:
Wc = Qc - Qh
Determine Heat Rejected in the Condenser (Qh):
To find Qh, we need to calculate the change in enthalpy in the evaporator and condenser using refrigerant properties, such as specific enthalpy values. For refrigerant R-134a at -12 degrees Celsius, you can use property tables or software to find the enthalpy values.
Find COP:
COP is defined as:
COP = Qc / Wc
Calculate Power Required for Service:
Using the COP and Qc:
Wc = Qc / COP
Now, let's calculate:
Assuming a COP value (e.g., 4):
Wc = 150 kW / 4 = 37.5 kW
So, with a chosen COP of 4, the power required for the service is 37.5 kW.
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Two circular loops of wire, each containing a single turn, have the same radius of 5.00 cm and a common center. The planes of the loops are perpendicular. Each carries a current of 2.10 A. What is the magnitude of the net magnetic field at the common center
The magnitude of the net magnetic field at the common center can be calculated using the formula MOI B = (at the center of the loop)/2R. The magnetic field strength at the center is approximately 6.28 × 10-5 T.
Explanation:The magnitude of the net magnetic field at the common center can be calculated using the formula for the magnetic field strength at the center of a circular loop, which is given by MOI B = (at the center of the loop), 2R. In this case, the radius of each loop is 5.00 cm. Plugging in the values, the magnetic field strength at the center can be calculated.
Substituting the given values into the equation:
Magnetic field strength = MOI B = (2 × π × (5.00 cm)²)(2.10 A)/(2 × 5.00 cm) ≈ 6.28 × 10-5 T
Therefore, the magnitude of the net magnetic field at the common center is approximately 6.28 × 10-5 T.
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The net magnetic field at the common center of the loops will be 3.71 × 10⁻⁵ T.
The two circular loop of wire have their planes perpendicular to each other and share a common centre. This indicates that the direction of net magnetic field at the common centre due to any one of the loops will be perpendicular to the direction of the net magnetic field at the common centre due to the other loop.
As both the loops have the same radius (r), same number of turns (N), and carry the same current (I), hence, the magnetic field at the centre of the loops will have the same magnitude and can be given by the formula:
[tex]B = \frac{N\mu_oI}{2r}[/tex]
Given that:
N = 1
I = 2.10 A
r = 5.00 cm = 0.05 m
μ₀ = 4π × 10⁻⁷
Substituting the values, we get:
[tex]B = \frac{(4 \pi \times 10^{-7})(2.10 A)}{2(0.05 m)}[/tex]
B = 2.63 × 10⁻⁵ T
The net magnetic field at the common centre can be found using
[tex]B_{net} = \sqrt{B_1^{2} +B_2^{2} +2B_1B_2cos\theta}[/tex]
as both the magnetic fields are perpendicular to each other the angle (θ) between them will be 90°.
∴ [tex]B_{net} = \sqrt{B_1^{2} +B_2^{2} }[/tex]
[tex]B_{net} = \sqrt{2B^{2} }[/tex]
[tex]B_{net} = \sqrt{2(2.63 \times 10^{-5} T)^{2} }[/tex]
[tex]B_{net} = (2.63 \times 10^{-5} T)\sqrt{2} }[/tex]
or, [tex]B_{net} = 3.71 \times 10^{-5} \hspace{0.5mm} T[/tex]
An ideal gas with k 5 1.4 is flowing through a nozzle such that the Mach number is 1.8 where the flow area is 36 cm2. Approximating the flow as isentropic, determine the flow area at the location where the Mach number is 0.9.
Answer:
The flow area at the location where the Mach number is 0.9 is 25.24 cm²
Explanation:
Here we have for isentropic flow;
[tex]\frac{A}{A^*} = \frac{1}{M}(\frac{2}{k+1} (1+\frac{k-1}{2}M^2))^{(\frac{k+1}{2(k-1)} )[/tex]
Where:
A = Area of flow = 36 cm²
M = Mach number at section of = 1.8
k = Specific heat ratio = 1.4
A* = Area at the throat
Therefore, plugging the values we get
[tex]\frac{36}{A^*} = \frac{1}{1.8}(\frac{2}{1.4+1} (1+\frac{1.4-1}{2}1.8^2))^{(\frac{1.4+1}{2(1.4-1)} ) = 1.439[/tex]
Therefore, A* = 36/1.439 = 25.01769 cm²
Where the Mach number is 0.9, we have
[tex]\frac{A}{25.02} = \frac{1}{0.9}(\frac{2}{1.4+1} (1+\frac{1.4-1}{2}0.9^2))^{(\frac{1.4+1}{2(1.4-1)} ) = 1.009[/tex]
Therefore A = 25.020× 1.009 = 25.24 cm²
The flow area at the location where the Mach number is 0.9 = 25.24 cm².
PLEASEEEE ANSWERRR FASTT!!! Summarize the contributions that Ellen Swallow Richards made to help
clean up the Earth. *
Answer:
Ellen tested the water in Massachusetts and it had way too much chlorine. She talked to the city and got them to stop dumping waste and garbage into the water.
Explanation:
oh btw im in 5th grade and i get these kind of questions your welcome
A textbook of mass 2.02 kg rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose diameter is 0.190 m , to a hanging book with mass 3.05 kg . The system is released from rest, and the books are observed to move a distance 1.19 m over a time interval of 0.800 s .
A) What is the tension in the part of the cord attached to the textbook?
B) What is the tension in the part of the cord attached to the book?
C) What is the moment of inertia of the pulley about its rotation axis?
Answer:
a. 7.38 N b. 40.87 N c. 0.113 kg-m²
Explanation:
If you were to separate all of the electrons and protons in 1.00 g (0.001 kg) of matter, you’d have about 96,000 C of positive charge and the same amount of negative charge. If you placed these charges 8.00 m apart, how strong would the attractive forces between them be?
Answer:
The attractive force between them is [tex]1.296 \times 10^{18}[/tex] N
Explanation:
Given:
Charge [tex]q = 96000[/tex] C
Distance between two charges [tex]r = 8[/tex] m
According to the coulomb's law,
[tex]F = \frac{kq^{2} }{r^{2} }[/tex]
Where [tex]k = 9 \times 10^{9}[/tex] = force constant.
[tex]F = \frac{9 \times 10^{9} \times (96000)^{2} }{8^{2} }[/tex]
[tex]F = 1.296 \times 10^{18}[/tex] N
Therefore, the attractive force between them is [tex]1.296 \times 10^{18}[/tex] N
In a laundromat, during the spin-dry cycle of a washer, the rotating tub goes from rest to its maximum angular speed of 4.7 rev/s in 8.3 s. You lift the lid of the washer and notice that the tub decelerates and comes to a stop in 17.5 s. Assuming that the tub rotates with constant angular acceleration while it is starting and stopping, determine the total number of revolutions undergone by the tub during this entire time interval.
Answer:
Number of revolutions = Δθ = 60.63 revs
Explanation:
The angular acceleration of the washer is given by
α = (ωf - ωi)/Δt
Where ωf is the initial angular speed, ωi is the final angular speed and Δt is the interval of time during this acceleration.
α = (4.7 - 0)/8.3
α = 0.56 rev/s²
As we know from the equation of kinematics,
2αΔθ = ωf² - ωi²
Where Δθ is the change in angular displacement of the washer.
Δθ = (ωf² - ωi²)/2α
Δθ = (4.7² - 0²)/2*0.56
Δθ = 19.72 revs
Now the tub decelerates and comes to a stop in 17.5 s
α = (ωf - ωi)/Δt
α = (-4.7 - 0)/17.5
α = -0.27 rev/s²
the corresponding change in angular displacement of the washer is
Δθ = (ωf² - ωi²)/2α
Δθ = (0² - 4.7²)/2*-0.27
Δθ = 40.91 revs
Therefore, the total number of revolutions undergone by the tub during this entire time interval is
Δθ = 19.72 + 40.91
Δθ = 60.63 revs
Order the electromagnetic waves from lowest
frequency (1) to highest (4).
Gamma:
Infrared:
X-ray:
Visible light:
The electromagnetic waves from the lowest frequency to the highest frequency are gamma rays, X-ray, visible light, and infrared.
What are electromagnetic waves?Electromagnetic waves are the waves which are formed when an electric field couples with a magnetic field. Magnetic and the electric fields of an electromagnetic wave are perpendicular to each other and to the direction of the wave propagation. Electromagnetic waves are used widely in the food processing for destroying microbes.
Therefore, the correct order of electromagnetic waves from the lowest frequency to the highest frequency are gamma rays, X-ray, visible light, and infrared.
Learn more about Electromagnetic waves here:
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What color of light has the most energy?
A. Blue
B. Red
C. Green