Answer: A single oxygen atom is gaining 2 electrons in the given reaction.
Explanation:
Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.
[tex]X\rightarrow X^{n+}+ne^-[/tex]
Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.
[tex]X^{n+}+ne^-\rightarrow X[/tex]
For the given chemical reaction:
[tex]H_2+\frac{1}{2}O_2\rightarrow H_2O[/tex]
The half cell reactions for the above reaction follows:
Oxidation half reaction: [tex]H_2\rightarrow 2H^{+}+2e^-[/tex]
Reduction half reaction: [tex]\frac{1}{2}O_2+2e^-\rightarrow O^{2-}[/tex]
As, hydrogen is loosing 2 electrons to form hydrogen cation. Thus, it is getting oxidized. Oxygen is gaining 2 electrons to form oxygen anion. Thus, it is getting reduced.
Hence, a single oxygen atom is gaining 2 electrons in the given reaction.
In the reaction [tex]H_2 + O_2 - H_2O,[/tex] oxygen (O2) gains two electrons.
How do we explain?Oxidation reaction is described as the chemical reaction in which an atom looses its electrons and we see that the oxidation number of the atom gets increased during this reaction.
we need to consider the oxidation states of the elements involved in order to determine the electron gain or loss,
In its elemental form , oxygen is in a neutral state with an oxidation state of 0. However, in the water molecule , oxygen has an oxidation state of -2.
In conclusion, since oxygen gains two electrons to achieve an oxidation state of -2 in the water molecule, we can say that oxygen gains two electrons in the reaction.
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Waves with longer wavelengths have more energy than waves with shorter wavelengths.
True
False
Answer:
FALSE
Explanation:
[tex]E = \dfrac{hc}{\lambda}[/tex]
Energy is inversely proportional to wavelength.
∴ Waves with longer wavelengths have less energy than waves with shorter wavelengths.
Which of these is an example of food engineering?
O
A. The development of irrigation
O
B. Using glass containers to reheat food
O
C. Choosing foods that are high in omega-3 to improve your diet
O
D. Growing a home garden
Answer:
A
Explanation:
People engineered things to help with irrigation to bring water to crops(food)
Answer:
A
Explanation:
engineering has to do with creating something, and A is the only option of that kind. process of elimination
If 156 grams of chromium react with an excess of oxygen, as shown in the balanced chemical equation below, how many grams of chromium oxide can be formed? (1 point) 4Cr + 3O2 yields 2Cr2O3
Answer:
=759.95 grams.
Explanation:
The molar mass of chromium is 51.9961 g/mol
Therefore the number of moles of chromium in 156 grams is:
Number of moles =mass/RAM
=156g/51.9961g/mol
=3 moles.
From the equation provided, 3 moles of chromium metal produce 2 moles of Chromium oxide.
Therefore 3 moles of chromium produce:
(3×2)/4 moles =1.5 moles of chromium oxide.
I mole of chromium oxide has a mass of 151.99 g
Thus 1.5 moles= 1.5mole ×151.99 g/mol
=759.95 grams.
What is the final pressure (expressed in atm) of a 3.05 L system initially at 724 mm Hg and 298 K, that is compressed to a final volume of 3.00 L at 273 K?
Hey there!:
V1 = 3.05 L
V2 = 3.00 L
P1 = 724 mmHg
P2 = to be calculated
T1 = 298 K
T2 = 273 K
Therefore:
P1*V1 / T1 = P2*V2 / T2
P2 = ( P1*V1 / T1 ) * T2 / V2
P2 = 724 * 3.05 * 273 / 298 * 3.00
P2 = 602838.6 / 894
P2 = 674.31 mmHg
1 atm ----------- 760 mmHg
atm ------------- 674.31 mHg
= 674.31 * 1 / 760
= 0.887 atm
Hope this helps!
Final answer:
The final pressure of the gas after being compressed and temperature changed is calculated using the combined gas law. By converting the initial pressure from mm Hg to atm and plugging the values into the equation, we find that the final pressure of the gas is approximately 0.885 atm.
Explanation:
To calculate the final pressure of the gas after it has been compressed and its temperature changed, we can use the combined gas law, which is derived from the ideal gas law and expressed as: P1V1/T1 = P2V2/T2, where P represents pressure, V represents volume, and T represents absolute temperature (in Kelvin). Because pressure is initially given in mm Hg, we need to convert it to atmospheres (atm) by using the conversion factor that 1 atm = 760 mm Hg. Now, we have:
Initial pressure, P1 = 724 mm Hg = 724/760 atmInitial volume, V1 = 3.05 LInitial temperature, T1 = 298 KFinal volume, V2 = 3.00 LFinal temperature, T2 = 273 KFirst, convert P1 to atm:
P1 = 724 mm Hg * (1 atm / 760 mm Hg) = 0.953 atm
Now, apply the combined gas law and solve for P2:
P2 = (P1V1T2) / (V2T1) = (0.953 atm * 3.05 L * 273 K) / (3.00 L * 298 K)
Calculating this, we get:
P2 ≈ (0.953 * 3.05 * 273) / (3.00 * 298) atm ≈ 0.885 atm
___________. Is a process that breaks water down into the gases hydrogen and oxygen
The answer is electrolysis
Answer:
Water electrolysis
Explanation:
What is the purpose of a unit conversion?
The unit conversion is a fundamental process that enables accurate and coherent communication and computation across various fields and applications.
Unit conversion maintains a quantity's value in different units, crucial for consistency and clarity.
It enables comparisons between measurements using diverse units.
Facilitates communication across different measurement systems.
Ensures meaningful and applicable calculation results in various contexts.
For instance, converting grams to ounces allows accurate measurement in recipes using different units.
[tex]\[ 500 \text{ grams} \times 0.035 \frac{\text{ounces}}{\text{gram}} = 17.5 \text{ ounces} \][/tex]
For the recipe, 17.5 ounces of flour are needed for precise measurement.
In scientific research, unit conversion is vital for standardizing data presentation.
International trade relies on unit conversion to ensure consistent pricing across different measurement systems.
Overall, unit conversion is fundamental for accurate communication and computation in diverse fields and applications.
Calculate the molar solubility of Ag2 CrO4 in water. Use 1.10 x 10-12 as the solubility product constant of AgzCro4
7.42 x 10-7M
1.05 x 10-6M
6.50 x 105M
1.03 x 10-4M
Answer:
6.50 x 105M
Explanation:
how many atoms of sulfur are in 1.00 mol of iron(II) sulfate, FeSO4
Answer:
1.26 x 10²³atoms
Explanation:
Given parameters:
Number of moles = 1mol
Unknown:
Number of atoms of sulfur = ?
Solution
From the given parameters, we can find the number of moles of sulfur in the given compound FeSO₄.
We use the formula mass of atoms to find the number of moles:
Atomic number of Fe = 56g
S = 32g
O = 16g
Formula mass = 56 + 32 + 4(16) = 152
Number of moles of sulfur = [tex]\frac{32}{152}[/tex] x 1
= 0.21mol
Using the number of moles of sulfur, we can now calculate the number of atoms:
Number of atoms = number of moles x 6.02 x 10²³
Number of atoms = 0.21 x 6.02 x 10²³ = 1.26 x 10²³atoms
How long would it take a typical jet to travel the sun from earth?
Answer:
To travel this far, it would take 19 years.
If 45.0 mL of 0.25 M HCl is required to completely neutralize 25.0 mL of NH3, what is the concentration of the NH3 solution? Show all of the work needed to solve this problem.
HCl + NH3 yields NH4Cl
molar concentration = number of moles / volume
number of moles = molar concentration × volume
Number of moles of HCl = 0.25 × 45 = 11.25 mmoles
From the reaction:
11.25 mmoles of HCl will neutralize 11.25 mmoles of NH₃
Molar concentration of NH₃ solution = 11.25 / 25 = 0.45 M
Answer:
The balanced chemical equation is
[tex]1HCl+1NH_3>1NH_4 Cl[/tex]
The conversions are
Molarity of HCl and volume gives us moles HCl
Moles HCl to moles [tex]NH_3[/tex] (using mole ratio 1 : 1)
Moles [tex]NH_3[/tex] to Molarity [tex]NH_3[/tex]
Molarity HCl = (moles solute HCl) / (volume of solution in L)
Rearranging the formula
We get moles HCl = Molarity × volume
[tex]=0.25M \times 45.0mL = 0.25 mol/L \times 0.045L = 0.01125 mol HCl[/tex]
moles HCl = moles [tex]NH_3[/tex] = 0.01125 mol [tex]NH_3[/tex]
Molarity [tex]NH_3[/tex] =(moles solute [tex]NH_3[/tex]) / (volume of solution in L)
[tex]=\frac {(0.01125 mol )}{25.0mL} = \frac {(0.01125 mol )}{0.025L}[/tex]
=0.450 mol/L or M (Answer)
Which equation describes a reduction?
A reduction in a chemical reaction involves the gain of electrons by a reactant. The equation describing a reduction typically follows the format:
Reductant + e⁻ → Product of Reduction
In this equation, the reductant (the species being reduced) gains electrons (e⁻) and undergoes a reduction reaction, resulting in the formation of a product. The reduction process leads to a decrease in the oxidation state of the reductant as it becomes more negatively charged or less positively charged. It is a fundamental concept in redox reactions and plays a crucial role in various chemical and biological processes.
Reductant + e⁻ → Product of Reduction
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NF3 has three F atoms bonded to a central N atom, with one lone electron
pair on the N. What is the shape of this molecule?
O
A. Tetrahedral
O
B. Trigonal planar
O
C. Bent
O
D. Trigonal pyramidal
D Trigonal pyramidal
Explanation:
NF3 exhibits a trigonal pyramidal shape due to its sp³ hybridization, with three bonded fluorine atoms and one lone pair of electrons on the nitrogen atom.
Explanation:The molecule in question is NF3, which consists of one nitrogen atom (N) and three fluorine atoms (F). The nitrogen atom in NF3 is sp³ hybridized, utilizing one sp³ hybrid orbital to form a bond with each of the three fluorine atoms, and the remaining sp³ hybrid orbital accommodates a lone pair of electrons. Considering the presence of three bonded pairs and one lone pair of electrons on the nitrogen atom, the molecular geometry of NF3 is trigonal pyramidal. This geometric shape resembles a tetrahedron with one vertex missing, due to the presence of the lone electron pair on nitrogen, which slightly distorts the angles between the bonds.
Which of the following is an example of chemical weathering?
A. Frost wedging
B. Animal activity
C. Oxidation
D. Abrasion
Answer:
C. Oxidation
Explanation:
To make it short
Given the following equation: 2K + Cl2 -> 2KCl How many grams of KCl is produced from 4.00 g of K and excess Cl2?
Answer:
42.65g
Explanation:
Given parameters:
Mass of K = 4g
Unknown: Mass of KCl
Solution:
Complete equation of the reaction:
2K + Cl₂ → 2KCl
To solve this problem, we know that the reactant in short supply is potassium K and this dictates the amount of products that would be formed. The chlorine gas is in excess and we can't use it to determine the amount of product that would form.
Now, we work from the known to the unknown. Since we know the mass of K given in the reaction, we can simply find the molar relationship between the reacting potassium and the product. We simply convert the mass to mole and compare to the product. From there we can find the mass of KCl that would be produced.
Calculating number of moles of K
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
Number of moles of K = [tex]\frac{4}{39}[/tex] = 0.103mol
From the given reaction equation:
2 moles of K will produce 2 moles of KCl
Therefore 0.103mol of K will produce 0.103mol of KCl
To find the mass of KCl produced,
Mass of KCl = number of moles of KCl x molar mass
Molar mass of KCl = 39 + 35.5 = 74.5gmol⁻¹
Mass of KCl = 0.103 x 74.5 = 42.65g
Answer:
Grams of KCl produced = 7.60 g
Explanation:
The given reaction is:
2K + Cl2 → 2KCl
It is given that Cl2 is in excess which implies that potassium K is the limiting reagent
Based on the reaction stoichiometry:
2 moles of K produces 2 moles of KCl i.e the molar ratio of K:KCl = 1:1
[tex]Moles(K)= \frac{Mass}{Atomic mass}=\frac{4.00g}{39.09g/mol}=0.102moles[/tex]
Therefore, moles of KCl produced = 0.102
[tex]Mass(KCl)=moles*mol.wt = 0.102moles*74.55g/mol=7.60g[/tex]
A sample of N2 gas occupying 800.0 mL at 20.0°C is chilled on ice to 0.00°C. If the pressure also drops from 1.50 atm to
1.20 atm, what is the final volume of the gas?
Which equation should you use
Answer:
We will use the combined gas equation.
The final volume V₂=931.74 mL
Explanation:
The combined gas equation shows the interrelationship between the volume, the pressure and the absolute temperature of a fixed mass of an ideal gas,
P₁V₁/T₁=P₂V₂/T₂
Because we are looking for the volume after the initial conditions havre been varied, we will call this volume, volume 2 ( V₂)
Let us make it the subject of the equation.
V₂=(P₁V₁T₂)T₁P₂
P₁=1.50 ATM
P₂=1.20 ATM
V₁=800 mL
V₂=?
T₁=(20+273)K=293 K
T₂=0+273 K=273 K
V₂=(1.50 ×800×273)/(293×1.2)
V₂=931.74 mL
Answer:
Explanation:A sample of N2 gas occupying 800.0 mL at 20.0°C is chilled on ice to 0.00°C. If the pressure also drops from 1.50 atm to
1.20 atm, what is the final volume of the gas?
Which equation should you use
What is the total number of electrons in p orbitals in a ground-state iron atom?
a. 6
b. 18
c. 12
d. 24
e. 30
Answer:
6
Explanation:
2×3=6,that is why it is the answer
Final answer:
The total number of electrons in p orbitals in a ground-state iron atom is 12, with 6 electrons each in the 2p and 3p subshells.
Explanation:
To find out the total number of electrons in p orbitals in a ground-state iron atom, we can look at the electron configuration of iron, which is Fe: 1s²2s²2p¶3s²3p¶4s²3d⁶. Iron has an atomic number of 26, which also equals the number of electrons in the neutral atom.
The p orbitals can be found in the 2p and 3p subshells. The 2p subshell can hold a maximum of 6 electrons, and the 3p subshell can also hold up to 6 electrons. As can be seen from iron's electron configuration above, both the 2p and the 3p subshells are fully occupied, therefore, the total number of electrons in p orbitals is 12 (6 from 2p and 6 from 3p).
16. Calculate the amount of heat energy that is needed (7. Calcula
to raise the temperature of 1000.0 g of sand from ll released
21.1 °C to 37.8 °C
temperat
q=m*C*A+
a = (1000.0 g)(0.670 J/g°C)(37.8 °C-21.1 °C)
a = 11189 J
q = 11200 J (sig figs)
18. If 11.500 T of energy is added to a 1000,0 9
19. If 11
Answer:
=11189 J
Explanation:
The temperature change i caused by the enthalpy change of the sand and the consequent increase in kinetic energy.
Change in enthalpy= Mass of substance × Specific heat capacity× Temperature change.
ΔH= MC∅
M=1000.0g
C= 0.670 Jg°C
∅= 37.8°C-21.1°C=16.7°C
ΔH= 1000.0g × 0.670J/g°C × 16.7 °C
=11189 J
Therefore the heat supplied to raise the temperature from 21.1 °C to 37.8°C is 11189 J.