How many grams of silver bromide could dissolve in one liter of 0.350 molar sodium thiosulfate solution?

Answer:

12.82 mol/L the molarity of the HCl.

Explanation:

Suppose in 100 grams of 39.0% (by mass) HCl in water.

Volume of solution = V

Density of the solution = d = 1.20 g/mL

Mass = Density × Volume

[tex]V=\frac{M}{d}=\frac{100 g}{1.20 g/mL}=83.33 mL = 0.08333 L[/tex]

Mass of HCl = 39.0% of 100 grams= [tex]\frac{39}{100}\times 100g=39 g[/tex]

Moles of HCl = [tex]\frac{39 g}{36.5 g/mol}=1.0685 mol[/tex]

[tex]Molarity=\frac{\text{Moles of compound}}{\text{Volume of solution (L)}}[/tex]

The molarity of the HCl = M

[tex]M=\frac{1.0685 mol}{0.0833 L}=12.82 mol/L[/tex]

12.82 mol/L the molarity of the HCl.

Answer:

The commercial grade of HCl solution having a density of 1.20 g/ml has the molarity of 12.8 M.

Explanation:

Let's take the volume of solution to be 1000 ml.

Mass of HCl = [tex]\rm density\;\times\;volume[/tex]

Mass = [tex]\rm 1.20\;\times\;1000[/tex]

Mass of HCl = 1200 g.

In 39 % of HCl,

mass of HCl = [tex]\rm 39\;\times\;1200[/tex]

mass of HCl = 468 grams.

Molarity = [tex]\rm \frac{moles}{Liter}[/tex]

Molarity = [tex]\rm \frac{468}{36.5}\;\times\;\frac{1}{liters}[/tex]

Moalrity = 12.8 moles/liter

Molarity of 39% HCl with a density of 1.20 g/ml is 12.8 M.

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The value densities of cube-1 and cube-2 are not at all similar which means that both the cubes are made up of different materials.

Explanation:

                                              [tex]Density=\frac{Mass}{Volume}[/tex]

Given:

Two different cubes, one with an edge length of 1.05 cm and mass of 14.32 g, and the other cube have an edge length of 2.66 cm and mass of 215.3 g.

To find:

Whether two cubes are of the same material or not.

Solution:

The edge length of the cube-1 = l = 1.05 cm

The volume of cube-1 =v

[tex]v=l^3=(1.05 cm)^3=1.16 cm^3[/tex]

Th mass of cube-1 = m = 14.32 g

The density of the cube-1 =d

[tex]d=\frac{m}{v}\\d=\frac{14.32 g}{1.16 cm^3}=12.3 g/cm^3[/tex]

The edge length of the cube-2 = l' = 2,66 cm

The volume first cube-2 =v'

[tex]v'=l'^3=(2.66 cm)^3=18.8 cm^3[/tex]

Th mass of cube-2 = m = 215.3g

The density of the cube-2 =d'

[tex]d'=\frac{m'}{v'}\\d'=\frac{215.3g}{ 18.8cm^3}=11.4g/cm^3[/tex]

The value density of cube-1 is different from that of cube-2, not at all similar which means that both the cubes are made up of different materials.

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Final answer:

To neutralize the excess 16 M HNO₃, 5.33 mL of 6 M NaOH is required.

Explanation:

The task is to calculate the volume of 6 M NaOH needed to neutralize excess HNO₃ used in dissolving copper. The student used 6.0 mL of 16 M HNO₃, which is 2.0 mL more than the required amount.

First, we need to find the amount of excess HNO₃ in moles, as only 4.0 mL was required. The excess volume is 6.0 mL - 4.0 mL = 2.0 mL. The moles of excess HNO₃ is calculated as 2.0 mL × 16 M / 1000 mL/L = 0.032 moles.

To neutralize the acid, we need the same number of moles of OH-. Since the NaOH is 6 M, the volume V in liters needed is calculated using the molarity equation: moles = Molarity × Volume. Thus, 0.032 moles = 6 M × V, which gives V = 0.032 moles / 6 M. So, the volume of NaOH required is 0.00533 L, or 5.33 mL.

Answer: Option (c) is the correct answer.

Explanation:

A molecule which has hydrogen bonding will have the highest boiling point. So, out of the given options only [tex]NH_{3}[/tex] will have hydrogen bonding.

Whereas in [tex]CHCl_{3}[/tex] there will be dipole-dipole interactions and no hydrogen bonding within the molecule.

In [tex]OF_{2}[/tex] and [tex]C_{6}H_{6}[/tex], there will be dipole-dipole interaction in both the molecules.

Thus, we can conclude that [tex]NH_{3}[/tex] will have the highest boiling point.

Minerals form from water bodies by the process of [tex]\boxed{{\text{precipitation}}}[/tex].

Further Explanation:

The formation of minerals takes place in several ways. The mineral formation depends on the physical and chemical conditions. These conditions include temperature, pressure, pH, and time.

Precipitation

It is a process by which the dissolved minerals get free from water and as a result deposits are formed. It occurs when dissolved substances come out of water. Minerals form when precipitation takes place in aqueous solutions and from gaseous emissions as in case of volcanic eruptions.

Melting

The process that results in the conversion of any substance from a solid state to the liquid state is known as melting. Another term for this process is fusion.

Cooling

The process of removal of heat by lowering the temperature of any substance is known as cooling.

Condensation

This phase transition occurs when a substance is converted from its gaseous state to the liquid state. Variations in temperature and pressure are done in order to achieve this phase change.

Learn more:

Answer details:

Grade: Senior School

Chapter: Phase transition

Subject: Chemistry

Keywords: minerals, precipitation, cooling, melting, condensation, pH, temperature, time, pressure, substance, phase transition, gaseous state, liquid state, heat, dissolved minerals, water bodies.

The answer is A. Glacier

Final answer:

The correct formula for potassium superoxide formed when 0.779 g of potassium reacts with an excess of oxygen to form 1.417 g of the compound is[tex]KO_{2}[/tex]

Explanation:

The formula for potassium superoxide can be determined by considering the mass of potassium reacted and the mass of the resultant compound formed. In this case, 0.779 grams of potassium reacts with oxygen to form 1.417 grams of potassium superoxide. Knowing that the potassium has fully reacted and become part of the potassium superoxide, we can deduce that the difference in mass (1.417 g - 0.779 g = 0.638 g) must be due to the oxygen present in the compound.

The simplest ratio between potassium (K) and oxygen (O) that could form a compound would be a 1:1 ratio, which gives us KO. However, based on the provided information, potassium superoxide has a different stoichiometry where 1 mol of potassium reacts with oxygen to form a compound with the formula [tex]KO_{2}[/tex], which is a superoxide. This means there are two oxygen atoms for every potassium atom in the compound.

Therefore, the correct formula for potassium superoxide, as formed in the reaction with an excess of oxygen, is [tex]KO_{2}[/tex].

The value of Kc for the second reaction is mathematically given as

Kc' = 3.769  

What isthe value of Kc for the second reaction?

Question Parameters:

kc = 7.04 × 10-2 for the reaction

2 hbr(g) ⇌h2(g) + br2(g)

1/2 h2(g) + 1/2 br2 ⇌hbr(g)

Generally, the equation for the reaction  is mathematically given as

2HBr(g) ⇄ H2(g) + Br2(g)

Therefore

Kc = [H2] [Br2] / [HBr]^2

7.04X10^-2 = [H2][Br] / [HBr]^2

Upon final reaction

Kc' = [HBr] / [H2]^1/2*[Br2]^1/2

Hence

[tex]\sqrt{(1/7.04X10^-2)}= [HBr] / [H2]^1/2*[Br]^1/2}\\\\Kc' = \sqrt{(1/7.04X10^-2)[/tex]

Kc' = 3.769  

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Answer:

30

Explanation:

To find out the neutron number of an element we must first know what the mass value of that element is and the value of the atom number of that element. To find out these values, just look for the element in the periodic table. Once discovered simply subtract the values using the formula:

No. of neutrons = mass - atom number.

In the case of Cr, the mass is 54, while the atom number is 24. So we can find the number of neutrons.

Cr Neutrons = 54-24 = 30

The balanced chemical equation for the reaction between carbon monoxide (CO) and oxygen (O₂) to form carbon dioxide (CO₂) is 2 CO(g) + O₂(g) → 2 CO₂(g), adhering to the law of conservation of mass.

The reaction between carbon monoxide (CO) and oxygen (O₂) to form carbon dioxide (CO₂) can be represented by the following balanced chemical equation:

2 CO(g) + O₂(g) → 2 CO₂(g)

In balancing this equation, it is important to ensure that the number of each type of atom on the reactants side is equal to the number on the products side. Here, we have two carbon atoms and two oxygen atoms from the CO molecules and two oxygen atoms from the O₂ molecule, giving us a total of four oxygen atoms on the reactants side, which balance with the four oxygen atoms in the two CO₂ molecules on the right side of the equation.

This reaction demonstrates the law of conservation of mass, where the mass of the reactants equals the mass of the products. In this case, the coefficients used are the smallest possible whole numbers that maintain this balance.

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Answer:

Strengthens the evidence and support for a scientific theory.

Explanation:

Hello,

Scientific method provides a compelling tool scientists use to both develop and demonstrate new theories. As it involves both the observation and experimentation towards a specific subject of matter, it turns out convenient to consider alternative explanations substantiating such subject of matter in light of obtaining a more precise explanation for it. In such a way, this investigation of alternative explanations strengthens the evidence and support for a scientific theory.

Best regards.

Answer:

The rate of the reaction is directly proportional to the concentration of the reactant.

Explanation:

Let's consider a reaction of the kind A → B.

A general rate law has the following form:

r = k . [A]ⁿ

where,

r: reaction rate

k: reaction constant

[A]: molar concentration of the reactant A

n: order of reaction for A

For a first-order reaction, the rate law is:

r = k . [A]

Give the characteristic of a first-order reaction having only one reactant.

The rate of the reaction is proportional to the square root of the concentration of the reactant. NO. This would happen if n = 1/2.

The rate of the reaction is proportional to the square of the concentration of the reactant. NO. This would happen if n = 2

The rate of the reaction is directly proportional to the concentration of the reactant. YES.

The rate of the reaction is proportional to the natural logarithm of the concentration of the reactant. NO. This could never happen.

The rate of the reaction is not proportional to the concentration of the reactant. NO. This would happen if n = 0.

The characteristic of a first order reaction having only one reactant is that the rate of the reaction is directly proportional to the concentration of the reactant.

First order reactions are those reactions in which rate of the chemical reaction will depends on the concentration of the only reactant of the reaction.

Suppose a chemical reaction in which reactant A will form product B as:

A → B

So, Rate of the reaction is directly depends on the concentration of the A reactant.

Hence, option (3) is correct.

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Answer:

False.

Explanation:

Hexanal is a non-polar compound while water is a polar solvent.

We have the role "Like dissolves like".

So, hexanal is insoluble in water.

For a first-order reaction, the rate constant can be determined using the concentration of the reactant at a given time. In this case, the rate constant is 0.25 s^-1.

A first-order reaction is one in which the rate of reaction is directly proportional to the concentration of the reactant. The rate law expression for a first-order reaction is given by rate = k[A], where [A] is the concentration of the reactant and k is the rate constant.

In this case, the concentration of the reactant decreases to 25% of its initial value in 3.0 minutes. We can use this information to determine the rate constant (k).

25% of the initial concentration corresponds to 0.25 times the initial concentration, so the concentration at that time is 0.25[A]. We can substitute this value into the rate law expression and solve for k:

0.25[A] = k[A]

0.25 = k

Therefore, the value for the rate constant (k) for the reaction is 0.25 s-1.

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To find the rate constant (k) for a first-order reaction, we can use the half-life formula. The given information states that it takes 3.0 minutes for the concentration of the reactant to decrease to 25% of its initial value. By substituting these values into the equation, we can find the rate constant.

To determine the rate constant (k) for the first-order reaction, we can use the formula for the half-life of a first-order reaction. The half-life is the amount of time it takes for the concentration of the reactant to decrease to half of its initial value. In this case, it takes 3.0 minutes for the concentration to decrease to 25% of its initial value, which is equivalent to one half-life.

The formula for the first-order half-life is: t1/2 = ln(2)/k
Since the concentration decreases to 25% of its initial value after one half-life, we can use this information to solve for k:

25% = (1/2) * 100% = e-kt1/2
ln(1/2) = -k * t1/2
k = -ln(1/2) / t1/2

Substituting the given values, we have:
k = -ln(1/2) / 3.0 minutes

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The pH of a buffer containing NH3 and NH4Cl is determined by the equilibrium between NH4+ and NH3 in water, with the reaction NH4+ (aq) + H2O(l) → H3O+ (aq) + NH3(aq). The reaction demonstrates the action of the ammonium ion as a weak acid, and its Ka is calculated using the Ka = Kw/Kb relationship. The chloride ion does not undergo significant hydrolysis, so it does not affect the pH of the buffer.

The chemical reaction responsible for the pH of a buffer containing NH3 (ammonia) and NH4Cl (ammonium chloride) involves the equilibrium between NH4+ and NH3 in water:

NH4+ (aq) + H2O(l) ⇒ H3O+ (aq) + NH3(aq)

This represents the dissociation of the ammonium ion, which is a weak acid, in water to produce hydronium ions (H3O+) and ammonia. Since ammonia is a weak base, the corresponding acid dissociation constant (Ka) can be calculated using the relation Ka = Kw/Kb, where Kw is the ion product of water and Kb is the base dissociation constant of ammonia.

The chloride ion, being the conjugate base of the strong acid hydrochloric acid (HCl), does not undergo significant hydrolysis in water:

Cl-(aq) + H2O(l) → HCl(aq) + OH−(aq)

Since HCl is a strong acid, the equilibrium constant (Ka) for its conjugate base, Cl-, is essentially zero, which means Cl- does not affect the buffer solution's pH appreciably.

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The final concentration (C_2) is 20 times less than the initial concentration (C_1), illustrating a dilution factor of 20. For instance, if C_1 were 2 mol/L, C_2 would be 0.1 mol/L.

Calculate the concentration of the diluted solution:

1. Identify the given information:

Initial volume of stock solution (V_1) = 13.0 mL

Final volume of diluted solution (V_2) = 0.260 L = 260 mL

Initial concentration of stock solution (C_1) is unknown (this is what we need to find)

2. Understand the key concept:

When a solution is diluted, the amount of solute (the substance dissolved in the solution) remains constant. Only the volume of the solution changes.

This means that the product of concentration and volume before dilution is equal to the product of concentration and volume after dilution.

3. Apply the dilution formula:

The formula is C_1V_1 = C_2V_2, where:

C_1 = initial concentration

V_1 = initial volume

C_2 = final concentration

V_2 = final volume

4. Solve for the unknown concentration (C_1):

Rearrange the formula to isolate C_1: C_1 = C_2V_2 / V_1

Plug in the known values: C_1 = (unknown) * 260 mL / 13.0 mL

Simplify: C_1 = 20 * C_2

5. Interpret the result:

The final concentration (C_2) will be 20 times less than the initial concentration (C_1). This means the solution has been diluted by a factor of 20.

6. Example:

If the initial concentration (C_1) was 2 mol/L, then the final concentration (C_2) would be 0.1 mol/L (20 times less).

The first-order rate constant for the thermal decomposition of phosphine can be calculated using the relationship between the half-life and the rate constant, resulting in a rate constant of 0.0198 s⁻¹.

The thermal decomposition of phosphine (PH₃) into phosphorus and molecular hydrogen is given as a first-order reaction, and the provided half-life of the reaction is 35.0 seconds at 680°C. To calculate the first-order rate constant for the reaction, we can use the relationship that for a first-order reaction, the half-life (t₁/2) is related to the rate constant (k) by the equation t₁/2 = ln(2) / k. Therefore, we can rearrange this formula to solve for k: k = ln(2) / t₁/2.

By plugging the values into the formula, we can calculate the rate constant as follows:

k = ln(2) / 35.0 s

k = 0.0198 s⁻¹

This is the rate constant for the first-order thermal decomposition of phosphine at the specified temperature.

Final answer:

C6H5CH2CH2Br is not formed during the radical bromination of C6H5CH2CH3 because the intermediate benzyl radical, formed at the carbon adjacent to the aromatic ring, is much more stable than the primary radical needed for the other product. Selectivity is due to bromine's preference for stable radicals, supported by Hammond's postulate.

Explanation:

The reason why C6H5CH2CH2Br is not formed during the radical bromination of C6H5CH2CH3 involves the relative stability of the radical intermediate. Radical bromination tends to occur at the position that forms the most stable radical, which for a benzyl compound is the carbon atom directly adjacent to the aromatic ring. The radical formed at this position, a benzyl radical, is highly stabilized by resonance. In contrast, the radical that would be required to form C6H5CH2CH2Br is a primary radical, which is less stable and thus less likely to form. This selectivity is due to the fact that bromine radicals are relatively selective and prefer to abstract hydrogen atoms from positions that lead to more stable radical intermediates. Moreover, Hammond's postulate suggests that since the radical formation with bromine is endothermic, the transition state will more closely resemble the stable radical intermediate, leading to more selective radical formation.

The basic building block of chemistry is known as the atom. The smallest particle of an element that still retains all the properties of the element is known as the atom. The correct option is C.

The atom can be considered as the basic building blocks of matter which possess the properties of the chemical element. An atom don't exist independently, instead they form ions and molecules which in turn combine in large numbers to form matter.

An atom is an indivisible particle and it contains the sub-atomic particles like protons, electrons and neutrons. The positively charged particles are called protons, the negatively charged particles are called electrons. The neutrons are chargeless particles.

All atoms of the same element are identical but different elements have different types of atoms. The chemical reactions occur when the atoms are rearranged.

Thus the correct option is C.

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Final answer:

Oxygen has three stable isotopes, 16O, 17O, and 18O, all of which have 8 protons but vary in their number of neutrons—8, 9, and 10, respectively. These variances in neutron count alter the atomic mass of the isotopes without affecting their atomic number or chemical properties.

Explanation:

The statement "Oxygen, whose atomic number is eight, has three stable isotopes: 16O, 17O, and 18O" refers to the different forms of the element oxygen which vary in the number of neutrons contained within the nucleus. The atomic number of an element indicates the number of protons within the nucleus; for oxygen, this is always eight. However, the number of neutrons can differ, changing the mass number but not the chemical properties of the element.

For each isotope of oxygen:

16O: 8 protons + 8 neutrons = 16 total nucleons

17O: 8 protons + 9 neutrons = 17 total nucleons

18O: 8 protons + 10 neutrons = 18 total nucleons

These isotopes determine the total number of nucleons (protons plus neutrons) in the atom's nucleus, represented by the mass number (A). Using the formula A - Z (where A is the mass number and Z is the atomic number), we can calculate the number of neutrons: 16O has 8 neutrons, 17O has 9 neutrons, and 18O has 10 neutrons. Isotopes of an element share the same atomic number but differ in the mass number. Oxygen's most abundant isotope is 16O, making up 99.76% of naturally occurring oxygen.

Explanation:

Acetals are geminal diethers derivatives of aldehyde formed by the addition to equivalent molecules of an alcohol and removal of water.

When ethanol is added to the ethanal in acidic medium:

Ethanal + Ethanol → Hemiacetal

Hemiacetal + Ethanol → Acetal

Acetal produced when ethanol is added to ethanal are given in the image attached.