Answer:
The answer to your question is: 6.8 g of water
Explanation:
Data
2.6 moles of HCl
1.4 moles of Ca(OH)2
2HCl + Ca(OH)2 → 2H2O + CaCl2
MW 2(36.5) 74 36 g 111 g
73g
1 mol of HCl ---------------- 36.5 g
2.6 mol -------------- x
x = (2.6 x 36.5) / 1 = 94.9 g
1 mol of Ca(OH)2 -------------- 74 g
1.4 mol --------------- x
x = (1.4 x 74) / 1 = 103.6 g
Grams of water
73 g of HCl ------------------ 36g of H2O
94.9 g ------------------- x
x = (94.9 x 36) / 73 = 46.8 g of water
The amount of water is theoretically produced for the following reaction given we have 2.6 moles of HCl and 1.4 moles of Ca(OH)₂ - C) 46.8.
Given:
2HCl + Ca(OH)₂ -------------> CaCl₂ + 2H2O
in this reaction, 2 moles HCl reacts with 1 mole Ca(OH)₂
which means 2.6 moles of HCl reacts with 2.6 x = 1.3
but we have 1.4 moles Ca(OH)₂ it is the excess reagent
Solution:
HCl is a limiting reagent in this reaction as it allows producing the mole of water on the base of the number of moles it has,
=> 2 mole HCl - 2 moles of H₂O
Here, 2.6 moles of HCl would give 2.6 moles of H₂O only
=> convert moles to mass
moles = mass / molar mass
and,
mass = [tex]\frac{mass}{molar\ mass}[/tex]
mass = 2.6 x 18
= 46.8 g
Thus, the amount of water is theoretically produced for the following reaction given we have 2.6 moles of HCl and 1.4 moles of Ca(OH)₂ - C) 46.8.
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A container has the dimensions of 10 cm x 50 mm x 0.2 m. It is filled completely with 5.0 kg of a powdery ore. What is the density of the ore in g/cm3 ? (D=m/V)
0.05 g/cm3
5.0 g/cm3
50 g/cm3
500 g/cm3
Answer:
B
Explanation:
5 kg = 5 kg * 1000 grams / kg = 5000 grams
10 cm does not require any conversion.
50 mm = 50 mm * 1 cm/10 mm = 5 cm
0.2 m = 0.2 m * 100 cm / 1 m = 20 cm
V = 10 cm * 5 cm * 20 cm
V = 1000 cm^3
Density = 5000 grams / 1000 cm^3 = 5 grams / cm^3
B
Elements that have atoms with full outer shells of electrons
Elements with full outer shells of electrons are more stable. Atoms tend to donate, accept, or share electrons to fill their outermost shells, following the octet rule.
Explanation:Elements with atoms that have full outer shells of electrons are more stable compared to those with incomplete outer shells. The octet rule states that atoms tend to donate, accept, or share electrons with other elements to fill their outermost shells and satisfy the octet rule.
Oxygen is an example of an element that reacts with other elements to achieve an octet configuration. Thus, elements with complete outer electron shells are more stable because they have low reactivity and are less likely to form chemical bonds. This stability is a fundamental principle in the periodic table, guiding chemical behavior.
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Ammonia can be produced via the chemical reaction N2(g)+3H2(g)⇌2NH3(g) During the production process, the production engineer determines the reaction quotient to be Q = 3.56×10−4. If K = 6.02×10−2, what can be said about the reaction?
Answer:
Q<K so N2(g) +3H2(g) → 2NH3(g)
Explanation:
Step 1: Data given
For the balanced equation N2(g)+3H2(g)⇌2NH3(g) We have the following data:
⇒ Reaction quotient Q = 3.56 *10^-4
Where Q is defined as Q = [NH3]^2/{[N2]*[H2]^3]
⇒ Equilibrium constant K = 6.02 * 10^-2
If we compare Q and K, there are 3 options
⇒ Q > K : The reaction favors the reactants. This means that in the Q equation, the ratio of the concentration or pressure of the products) to the concentration or pressure of the reactants is larger than that for K.
This means that more products are present than there would be at equilibrium.
Following Le chatelier's principle reactions always tend toward equilibrium, this means the reaction will produce more reactants from the excess products, and will therefore cause the system to shift to the LEFT.
Doing this, it will allow the system to reach equilibrium.
⇒ Q = K : The reaction is already at equilibrium. There is no tendency to form more reactants or more products at this point. No side is favored and no shift will occur.
⇒ Q < K : The reaction favors the products. The ratio of products to reactants is less than that for the system at equilibrium—the concentration or the pressure of the reactants is greater than the concentration or pressure of the products.
Following Le chatelier's principle reactions always tend toward equilibrium, the system shifts to the RIGHT to make more products.
In this case K > Q since 6.02*10^-2 > 3.56*10^-4
This means that forward reaction will be favored or the reaction will shift to the right
N2(g) +3H2(g) → 2NH3(g)
As a result, the reaction will consume nitrogen gas (N2) and hydrogen gas (H2), and produce more ammonia (NH3).
The reaction will proceed in this direction until equilibrium is established
The reaction quotient (Q) is less than the equilibrium constant (K), indicating that the forward reaction is favored. Therefore, the reaction shifts towards the production of more ammonia (NH3) to achieve equilibrium.
Explanation:The reaction quotient (Q) and the equilibrium constant (K) are critical in determining the direction of a chemical reaction. In this scenario, the reaction of nitrogen and hydrogen to generate ammonia is considered. The reaction quotient Q is 3.56×10-4, while the equilibrium constant K is 6.02×10-2.
In situations where Q < K, the reaction progresses in the forward direction to reach equilibrium, meaning the formation of ammonia (NH3) is favored. On the other hand, if Q > K, the reaction would proceed in the reverse direction, favoring the formation of nitrogen and hydrogen. Therefore, given Q is less than K in this case, the reaction will shift toward the production of ammonia to establish equilibrium.
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a faucet is leaking water at a speed of 5 drops per minute. If 1 ml is equivalent to 10 drops, how many liters of water will be wasted in one day
Answer: 0.72 litres of water is wasted in one day.
Explanation:
First you need to find out how many minutes are in a day. Do this by multiplying the number of minutes in an hour (60) by the number of hours in a day (24). 24 x 60 = 1440. If the faucet is dripping at 5 drops per minute, then multiply 5 by the number of minutes in a day (1440) to see how many drops drip in one day. 5 x 1440 = 7200. Now we need to figure out how many mL fo water that is. if 10 drops is 1 mL, then we need to divide the total number of drops (7200) by 10. 7200 divided by 10 is 720. That means 720 mL of water is dripping per day. Finally, we must convert mL to litres. There are 1000 mL in one litre, so divide 720 by 1000. The final answer is 0.72
Why does the borate-crosslinked PVA release a dye upon the action of acid? Explain the release chemically, and list any intermolecular interactions that are formed and/or disrupted. Use drawings to illustrate these changes.
Answer:
Poly(ethenol), ie poly(vinyl liquor), PVA, has a rehashing vinyl liquor unit with a sub-atomic equation of [-CH2 CHOH-]n. Its atomic weight can go from 25000 to 300000, contingent upon its chain length, which influences its consistency.
Borax, ie sodium tetraborate decahydrate, Na2B4O7.10H2O, when broken down in water, hydrolyses to frame a boric corrosive borate particle arrangement with a pH of around nine.
B4O72–(aq) + H2O(l) → HB4O7–(aq) + OH–(aq)
B4O72–(aq) + 5H2O(l) + 2H+ (aq) → 4H3BO3 (aq)
B(OH)3 (aq) + H2O(l) → B(OH)4–(aq) + H+ (aq)
Explanation:
Borax is intriguing since it contains boron molecules with both tetrahedral and trigonal planar stereo chemistry. Boric corrosive's acridity is clarified by electron pair acknowledgment as opposed to proton gift, and it is in this manner a monoprotic corrosive, not triprotic true to form.
At the point when arrangements of poly(ethanol) and sodium tetraborate are blended, the borate particles, B(OH)4–(aq) respond with the hydroxyl gatherings (OH) of the poly(ethenol). Frail cross-connecting inside the polymer strikes produce a viscoelastic gel. The high dissolvability in water proposes that broad hydrogen holding exists.
An administrator in a very large company wants to estimate the mean level of nitrogen oxides (NOX) emitted in the exhaust of a particular car model in their very large fleet of cars. Historically, nitrogen oxide levels have been known to be Normally distributed with a standard deviation of 0.15 g/ml. What is the parameter of interest that the administrator wants to estimate?
Answer:
Explanation:
For very well describe a normal distribution, it is needed the mean and the standard deviation. We are only lacking the mean to properly describe the nitrogen levels emitted by the vehicles. He would like to measure the emitted NOX so he could properly model this phenomena.
Avogadro's law states that the _____ of a gas is directly proportional to the _____ of the gas when _____ stay the same
Answer:
The three blanks for this answer, are
1. volumen
2. moles
3. Temperature and pressure.
So, Avogadro's law states that the volume of a gas is directly proportional to the moles of the gas when temperature and pressure stay the same
Explanation:
Imagine you have 10 moles of a gas which is contained in 50 L. How many moles of that gas, you will have if the volumen has been reduced to 10 L. (Of course, don't forget that T° and pressure are the same)
There is an equation like this, initial moles /initial volume = moles at the end/volume at the end, (Avogadro law for gases), so 10/50 =moles at the end/10. When u operate, moles at the end = (10 x 10) / 50.
Moles at the end are 2. Did u get it?. Volumen has been reduced, also the moles.
Avogadro's law states that the volume of a gas is directly proportional to the amount of the gas when temperature and pressure stay the same.
Explanation:Avogadro's law states that the volume of a gas is directly proportional to the amount (moles) of the gas when temperature and pressure stay the same. This law is based on Avogadro's principle which states that equal volumes of gases, at the same temperature and pressure, contain an equal number of particles (atoms, molecules, or ions).
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As the Collection of physical evidence begins
a.The police chief has primary responsibility of maintaining the chain of custody.
b.All observations should be recorded through photographs, sketches and notes.
c.The district attorney should be consulted for admissibility of physical evidence in court.
d.The medical examiner should oversee the collection of the evidence at the crime scene.
5.The most important prerequisite for photographing a crime scene is:
a.For items to be placedinto indirect light so that nuances can be picked up in the photograph.
b.For the crime scene to be in an unaltered condition.
c.For the photographer to start with close-ups of any important object and back up to get the full scale.
d.For rulers or other items to be placed into the photographs to show scale.
Explanation:Once the crime scene has been thoroughly documented and the locations of the evidence noted, then the collection process can begin
Answer: d.The medical examiner should oversee the collection of the evidence at the crime scene.
Explanation:
The physical evidence includes all the evidences which shows the proximity of victim or culprit with the crime scene. The medical examiner should help in collection of the evidences at the scene of crime. The medical examiner can search and identify physical evidences such as blood, sweat, vomit, fecal matter, urine, bodily tissues as an evidence and can begin the process of collection without contamination.
Identifying Physical and Chemical Changes.Matter has both physical and chemical properties and can undergo physical or chemical changes. Physical properties are those that a substance displays without changing its composition, whereas chemical properties are evident only during a chemical change (also called a chemical reaction). In contrast, when a substance undergoes a physical change, it may change appearance, but not its composition.Part A: Classify each of the changes as a physical change or a chemical change.Part B: Classify each of the properties as a physical property or a chemical property.
Answer: Part A: Physical change: Status changes of matter
chemical change: Any Chemical reaction
Part B: Physical property: Color, odor, etc
Chemical property: Flammability
Explanation:
Part A: A physical change: It´s change of form but not chemical composition.
Examples of Physical change are the Status changes of matter like boiling, melting, chooping wood, breaking a bottle and shredding paper.
A chemical change: It´s a change in the chemical composition of the compounds and generate new ones. That is called "chemical reaction" and it implies a rearrange of atoms generating new compounds.
Examples of chemical change are oxidation of Iron, burning, cooking, digesting food, rusting of iron.
Part B: Physical property: Are properties that can be measured or observed directly with our senses
Examples of physical Property: density,, appearance, texture, polarity, color, odor, melting point, solubility.
Chemical property: Are properties that can be observed when tey participate in a chemical reaction.
Examples of chemical Property: Reactivity , Radioactivity, Flammability , Acidity or basicity
Final answer:
A physical property of a substance can be observed without changing its chemical identity, such as melting point, while a chemical property, like flammability, involves a substance's propensity to change chemically. Physical changes do not alter a substance's chemical identity, unlike chemical changes which result in the formation of new substances.
Explanation:
Physical and Chemical Changes
Chemists categorize the properties of matter into physical and chemical properties. A physical property is an aspect of matter that can be observed or measured without altering the substance's chemical identity. Examples include color, density, melting and boiling points.
In contrast, a chemical property describes the substance's ability to undergo a specific chemical change, which alters its chemical composition. Flammability is a chemical property because it describes a substance's ability to burn, changing it into different substances as a result of this process.
Classifying Properties and Changes
Part A: One might observe a physical change when ice melts into water or when water vapor condenses - these are changes in state that do not involve altering the chemical identity of the substance. Chemical changes, however, such as the rusting of iron or the burning of wood, result in the formation of new substances.
Part B: Reflecting on the information given, properties like size, shape, and mass are physical, as they can be measured or observed without changing the material's chemical composition. In contrast, properties like reactivity with acids or the ability to oxidize would be classified as chemical properties, as they imply a change in chemical composition.
Which element is most likely to gain an electron?
A. Helium (He)
B. Fluorine (F)
C. Arsenic (As)
D. Sulfur (S)
Since, fluorine is an electronegative element ,therefore it is most likely to gain an electron ,so option (b) is correct.
What do mean the electronegativity of an element ?Electronegativity is referred to as a chemical property that describes the tendency of an atom of an element to attract shared electrons while forming a chemical bond.
Electronegativity of elements across a period-
As we move from left to right through a period in the modern periodic table, the nuclear charge increases and the atomic size decreases, as a result it increases the value of electronegative elements.
Fluorine has the highest electronegativity element on periodic table.
Hence it concludes that fluorine is an electronegative element ,and it is most likely to gain an electron ,so option (b) is correct.
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At −15.0 ∘C , a common temperature for household freezers, what is the maximum mass of sucrose (C12H22O11) you can add to 1.50 kg of pure water and still have the solution freeze? Assume that sucrose is a molecular solid and does not ionize when it dissolves in water.
To determine the maximum mass of sucrose that can be added to 1.50 kg of pure water and still have the solution freeze at -15.0 °C, you can use the molality and freezing point depression equations.
Explanation:To determine the maximum mass of sucrose you can add to 1.50 kg of pure water and still have the solution freeze at -15.0 °C, we need to calculate the molality of the solution and use the colligative property of freezing point depression.
The molality is the moles of solute per kilogram of solvent. Since sucrose does not ionize, it remains as molecules in the solution. We can use the equation:
m = moles of sucrose / mass of water (kg)
With the molality, we can use the freezing point depression equation to determine the change in freezing point:
ΔTf = Kf * m
The freezing point of pure water is 0.0 °C, so the new freezing point will be -15.0 °C. We can then solve for the moles of sucrose and convert it to mass using the molar mass of sucrose. The maximum mass of sucrose that can be added to the water without it freezing will be the calculated mass of sucrose.
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In two or more complete sentences, compare singe displacements reactions and double displacement reactions
Answer:
The answer is in the explanation
Explanation:
Single displacement reactions: In these reactions, a more reactive element kicks out a less reactive element from a compound.
Ex. Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g)
In this example, Zn is more reactive than H, then Zn displaces H from the compound.
Double displacement reactions: In these kind of reactions 2 elements are displaced from the different compounds, these elements interchange positions.
Ex. CuCl2(aq) + 2 AgNO3(aq) → Cu(NO3)2(aq) + 2 AgCl(s)
In the example, Cu displaces Ag and Ag displaces Cu, they interchange positions.
Single displacement reactions involve one element replacing another in a compound, whereas double displacement reactions involve the exchange of ions between two compounds, often forming a precipitate.
Explanation:Single displacement reactions and double displacement reactions are two different types of chemical reactions. In a single displacement reaction, an element replaces another element in a compound, typically following the pattern A + BC → AC + B, where A is a single element and BC is a compound. By contrast, a double displacement reaction, also known as a metathesis, involves the exchange of ions between two compounds, conforming to the general form AB + CD → AD + CB, often resulting in the formation of a precipitate when one of the new compounds is insoluble.
What is true about a positively charged ion?
It is formed when an atom loses electrons.
It is usually a nonmetallic element.
It has more electrons than protons.
It is formed when an atom gains protons.
The answer you're looking for is
It is formed when an atom loses electrons.
Explanation ??
Well, the electrons are the negative part of an atom right? And protons are the positive part of the atom! We learned that when all of us were younger and first learning about atoms. The main reason it isn't "It is formed when an atom gains protons" is because most atoms have protons, it can still be negative as long as it has more electrons than protons. So that leaves us with, "It is formed when an atom loses electrons." I believe this is correct because since it is losing electrons, it is losing the negativity!
(( Max ))
A positively charged ion is formed during reactions when an atom loses
electrons.
During chemical reactions, electrons are lost and gained as elements strive
to obtain a stable octet configuration. This is done through series of bonding techniques and processes such as covalent bond etc.
When an atom loses electrons it becomes a positively charged ion and
when an atom gains an electron it becomes negatively charged.
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A sugar crystal contains approximately 1.6×1017 sucrose (C12H22O11) molecules.
What is its mass in mg?
The mass (in mg) of 1.6×10¹⁷ molecules of sucrose, C₁₂H₂₂O₁₁ is 9.09×10¯² mg
From Avogadro's hypothesis,
6.02×10²³ molecules = 1 mole of any substanceThus,
6.02×10²³ molecules = 1 mole of C₁₂H₂₂O₁₁
Recall,1 mole of C₁₂H₂₂O₁₁ = (12×12) + (1×22) + (16×11)
= 144 + 22 + 176
= 342 g
Next, we shall convert 342 g to mg. This can be obtained as follow
1 g = 1000 mg
Therefore,
342 g = 342 × 1000
342 g = 342000 mgTherefore, we can say that:6.02×10²³ molecules = 342000 mg of C₁₂H₂₂O₁₁Finally, we shall determine the mass (in mg) of 1.6×10¹⁷ molecules of C₁₂H₂₂O₁₁. This can be obtained as follow:6.02×10²³ molecules = 342000 mg of C₁₂H₂₂O₁₁
Therefore,
1.6×10¹⁷ molecules = [tex]\frac{1.6X10^{17} X342000}{6.02X10^{23} }[/tex]
1.6×10¹⁷ molecules = 9.09×10¯² mgTherefore, the mass (in mg) of 1.6×10¹⁷ molecules of sucrose, C₁₂H₂₂O₁₁ is 9.09×10¯² mg
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To find the mass of a sugar crystal, we calculate the mass of a single sucrose molecule and then multiply it by the total number of molecules in the crystal. The result is that the sugar crystal has a mass of approximately 9.101 milligrams.
Explanation:To calculate the mass of a sugar crystal in milligrams (mg), we need to find the mass of one sucrose molecule and then multiply it by the total number of sucrose molecules present. The molar mass of sucrose (C12H22O11) is 342.30 grams per mole (g/mol), which we can use to find the mass of one molecule.
First, we convert the molar mass to milligrams per molecule:
342.30 g/mol × (1 mol / 6.022×1023 molecules) × (106 mg / 1 g) = 5.688×10-19 mg/molecule
Then, we multiply the mass of one molecule by the number of molecules in the sugar crystal:
5.688×10-19 mg/molecule × 1.6×1017 molecules = 9.101 mg
Therefore, the mass of the sugar crystal is approximately 9.101 mg.
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The atomic weight of antimony is 121.75 u. There are two naturally occurring isotopes of antimony. 121Sb has an isotopic mass of 120.9038 u and has a natural abundance of 57.25%. What is the isotopic mass of the other isotope 123Sb?
1. 122.93 u
2. 122.88 u
3. 123.06 u
4. 122.97 u
5. 122.82 u
The isotopic mass of 123Sb can be calculated using the equation for atomic weight, taking into account the percentage abundance of each isotope of antimony. Solving this equation, the isotopic mass of 123Sb is determined to be approximately 122.93 u.
Explanation:To calculate the isotopic mass of 123Sb, we should make use of the equation that defines atomic weight. The atomic weight is the weighted average of the isotopic masses, factoring in the percentage abundance of each isotope.
The equation can be represented as follows:
Atomic weight = (mass isotope 1 x percentage abundance isotope 1) + (Mass isotope 2 x percentage abundance isotope 2)
Plugging in the known values,
121.75 u = (120.9038 u x 57.25%) + (Mass 123Sb x (100% - 57.25%))
By rearranging the equation and solving it, we can find the mass of 123Sb to be around 122.93 u
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Is monosodium glutamate an element, compound, homogeneous mixture, or heterogeneous mixture?
Final answer:
Monosodium glutamate is a compound made up of sodium, carbons, hydrogen, nitrogen, and oxygen.
Explanation:
Monosodium glutamate is a compound.
It is the sodium salt of glutamic acid, a naturally occurring non-essential amino acid.
Compounds are substances made up of two or more elements that are chemically bonded together.
In this case, monosodium glutamate is made up of the elements sodium (Na), carbon (C), hydrogen (H), nitrogen (N), and oxygen (O).
When water and hydroxide approach, will the two oxygen atoms attract or repel one another? They will attract by bonding like the oxygens in hydrogen peroxide, h-o-o-h. They will attract because they both carry negative charges. They will repel because they both carry negative charges. They will repel because atoms of the same element always repel?
Answer:
They will repel because they both carry negative charges.
Explanation:
When water approaches hydroxide ions, the oxygen atoms will repel each other. Water on its own is a polar covalent compound. It has a positive and negative end.
Hydroxide is radical that is negatively charged. It consists of oxygen and hydrogen atoms.
The like charges on the oxygen atom will repel one another as a general rule of attraction. The oxygen will have more affinity for the hydrogen.
Which half-reaction correctly describes an oxidation?
Answer:
The answer to yourquestions is the last option
Explanation:
Cr(s) -------------------- Cr +3 (aq) + 3e-
Two solutions A and B are separated by a membrane, which is permeable to water but not salts. Solution A is a 2% NaCl solution, while solution B is a 3% NaCl solution. Which will occur?
Answer:
Water of solution A will go through membrane until solution B.
Explanation:
That phenomenon occurs by mass transfer.
Mass transfer is the movement from a location to another that occurs when you have mass gradient. In a membrane with different concentration solutions the system will try to equal both concentrations.
In the problem, Solution B is more concentrated than A. Thus, water will transport from solution A to solution B increasing concentration of A and decreasing concentration of B until the system stay in equilibrium.
I hope ot helps!
Osmosis is the diffusion of water through a semipermeable membrane. In this case, water will move from Solution A to Solution B.
Osmosis is the diffusion of water through a semipermeable membrane down its concentration gradient.
In this case, the membrane is permeable to water but not salts.
Solution A is a 2% NaCl solution and Solution B is a 3% NaCl solution. Since water moves from an area of higher water concentration to one of lower concentration, water will move from Solution A to Solution B.
This will cause Solution B to become diluted and Solution A to become more concentrated.
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Which statement about hydrogen bonding is true? Select one:
a. Hydrogen bonding is the intermolecular attractive forces between two hydrogen atoms in solution.
b. The hydrogen bonding capabilities of water molecules cause CH3CH2CH2CH3 to be more soluble in water than CH3OH.
c. Hydrogen bonding of solvent molecules with a solute will not affect the solubility of the solute.
d. Hydrogen bonding interactions between molecules are stronger than the covalent bonds within the molecule.
e. Hydrogen bonding arises from the dipole moment created by the unequal sharing of electrons within certain covalent bonds within a molecule.
Answer:
E.
Explanation:
All answers other than E have the incorrect bonding capabilities or other incorrect information.
Final answer:
The true statement about hydrogen bonding is e. Hydrogen bonding arises from the dipole moment created by unequal sharing of electrons within certain covalent bonds within a molecule, making hydrogen bonds a special type of intermolecular force.
Explanation:
The correct statement about hydrogen bonding is that it arises from the dipole moment created by the unequal sharing of electrons within certain covalent bonds within a molecule. Therefore, the answer to the question is e. Hydrogen bonding arises from the dipole moment created by the unequal sharing of electrons within certain covalent bonds within a molecule. Hydrogen bonds are a significant intermolecular force found in molecules where a hydrogen atom is covalently bonded to a very electronegative atom, such as nitrogen (N), oxygen (O), or fluorine (F). These bonds are quite polar, leading to a strong dipole-dipole interaction that falls under a particular intermolecular force category referred to as hydrogen bonding. Hydrogen bonds are notably stronger than van der Waals interactions but are much weaker than covalent or ionic bonds. A typical hydrogen bond's strength is about 5% of a covalent bond's strength.
need help with chem! (multiple choice)
Answer:
C
Explanation:
Atoms undergoing alpha decay lose 2 protons and two neutrons to become a different atom. Those two protons and neutrons are represented by an α (the symbol for alpha) particle which also represents a helium nucleus (2 neutrons and 2 protons).
Based on the data gathered in Millikan's oil-drop experiments, the concept of atomic structure was modified. Which of the following aspects of the structure of the atom was validated by these experiments?1.mass of the atom2.mass of an electron3.charge on an electron4.charge on a proton5. mass of a proton
Final answer:
Robert A. Millikan's oil-drop experiment validated the charge on an electron. He determined the fundamental electric charge by analyzing the behavior of electrically charged oil droplets in an electric field.
Explanation:
In 1909, Robert A. Millikan's pioneering oil-drop experiment led to a major advancement in our understanding of atomic structure. Millikan was able to measure the electric charge on microscopic oil droplets, which he had electrically charged. By analyzing the behavior of these drops in the presence of an electric field and by balancing the gravitational and electrical forces, he could determine the charge on the droplets.
The significance of Millikan's findings is that he validated the existence of a fundamental electric charge, which is the charge of an electron. His experiments did not directly measure the charges on protons or the masses of protons or atoms, and while he later used the charge of the electron to calculate its mass, the oil-drop experiment itself did not directly validate the mass of an electron.
Therefore, from the options provided, Millikan's oil-drop experiments specifically validated 3. charge on an electron.
Which of the following is NOT a type of carbohydrate molecule? Choose one: A. A disaccharide B. A glucose molecule C. A triglyceride D. A polysaccharide
Answer:
The correct answer is C: A triglyceride
Explanation:
A carbohydrate is a biomolecule consisting of carbon (C), hydrogen (H) and oxygen (O) atoms. A carbohydrate is is a synonym of saccharide.
A triglyceride is an ester derived from glycerol and three fatty acids. So not a saccharide. The other 3 options all are saccharides. Triglycerides are the main constituents of body fat.
Triglyceride is not a type of carbohydrate molecule. It's a type of fat found in the blood, while disaccharides, glucose molecules and polysaccharides represent different types of carbohydrates.
Explanation:Among the choices A. A disaccharide, B. A glucose molecule, C. A triglyceride, and D. A polysaccharide, option C. A triglyceride is NOT a type of carbohydrate molecule. Instead, triglycerides are a type of fat found in the blood. A person's body converts calories it doesn't need for energy into triglycerides. On the other hand, disaccharides, glucose molecules and polysaccharides are all different types of carbohydrates, which are molecules consisting of carbon, hydrogen, and oxygen atoms.
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In a titration of hno3, you add a few drops of phenolphthalein indicator to 50.00 ml of acid in a flask. You quickly add 20.00 ml of 0.210 m naoh but overshoot the end point, and the solution turns deep pink. Instead of starting over, you add 30.00 ml of the acid, and the solution turns colorless. Then, it takes 7.23 ml of the naoh to reach the end point. What is the concentration of the hno3 solution
Answer:
The HNO3 solution has a concentration of 0.07 M
Explanation:
Step 1: find a balanced equation
HNO3 (aq) + NaOH (aq) → NaNO3 (aq) + H2O (l)
⇒ for 1 mole of HNO3 reacted, there will also react 1 mole of NaOH, and be produced 1 mole of NaNO3 and 1 mole of H2O, since the ratio is 1:1
Step 2: Calculating moles
Since we know that for 1 mole of HNO3 there will react 1 mole of NaOH, we can calculate the number of moleNaOH
⇒ Concentration = mole / volume
⇒ 0.210 = mole / ((20 + 7.23 ml) *10^-3)
mole = 0.005733 mole NaOH = 0.005733 mole HNO3
Step 3: Calculating the concentration of HNO3
Concentration = mole / volume
C(HNO3) = 0.005733 mole / ((50 + 30 ml) *10^-3)
C(HNO3) = 0.07 M
The HNO3 solution has a concentration of 0.07 M
To control this we can calculate through the following formule:
0.02723L x 0.21 M x ( 1mol HNO3 / 1 mol NaOH) x (1/ 0.08L) = 0.07M
In a titration using phenolphthalein as an indicator, the concentration of HNO3 can be determined by considering the amount of NaOH used to reach the end point twice. The final concentration of the nitric acid (HNO3) solution is calculated to be approximately 0.0715 M.
Explanation:We need to calculate the concentration of the HNO3 solution. In a titration of HNO3, we used a phenolphthalein indicator and added 20.00 mL of 0.210 M NaOH, passed the end point and reached a deep pink color solution. After erroneously overshooting the end point, you add 30.00 mL of HNO3 to the solution which then turns colorless. Finally, you add an additional 7.23 mL of NaOH to once again reach the end point.
Let's write out the balanced equation for the reaction:
HNO3 + NaOH → NaNO3 + H2O
From the complete balanced equation above, we can see that one mole of NaOH reacts with one mole of HNO3, so the same amount of moles of NaOH that react is the number of moles of HNO3 in the acid solution.
The total volume of NaOH solution used to neutralize the HNO3 is 20.00 + 7.23 = 27.23 mL, which is 0.02723 L.
We can find the number of moles of NaOH by multiplying the volume (in liters) by the molarity: 0.02723 L * 0.210 mol/L = 0.0057213 moles of NaOH
Since the total volume of HNO3 solution is 50.00 + 30.00 =80.00 ml or 0.080 L, the concentration of HNO3 can therefore be calculated as follows:
Concentration = mole / volume = 0.0057213 mol / 0.080 L = 0.0715 M.
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A sample of aluminum is placed in a 25 ml graduated cylinder containing 10 mL of water. The level of water rises to 18 mL. Aluminum has a density of 2.7 g/mL. Calculate the mass of the sample
Please include explanation if possible
To determine the mass of the sample, first find the volume difference after and before the aluminum was placed, the volume change is equal to the volume of the submerged object, in this case aluminum.
Then knowing volume of aluminum and the density of it, we can solve for the mass.
D = m/v
Dv = m
2.7 g/ml • 8 ml = 21.6 grams.
Answer: The mass of sample is 21.6 grams.
Explanation:
We are given:
Volume of cylinder without object, [tex]V_1[/tex] = 10 mL
Volume of cylinder with object, [tex]V_2[/tex] = 18 mL
Volume of object = [tex]V_2-V_1=18-10=8mL[/tex]
To calculate volume of a substance, we use the equation:
[tex]\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}[/tex]
We are given:
Density of sample (aluminum) = 2.7 g/mL
Volume of sample (aluminum) = 8 mL
Putting values in above equation, we get:
[tex]2.7g/mL=\frac{\text{Mass of a sample}}{8mL}\\\\\text{Mass of object}=21.6g[/tex]
Hence, the mass of sample is 21.6 grams.
One of the first mixtures of metals called amalgam used by densities for tooth fillings consisted of 26 g of silver, 10.8 g of tin, 2.4 g of copper, and .8 g of zinc, how much silver is in a 26 g sample of amalgam?
Answer:
The answer to your question is : 16.9 g of Ag
Explanation:
Data
26 g Ag
10.8 g of Sn
2.4g Cu
0.8 Zn
Ag = ? in 26 g of sample
Total mass in the amalgam = 26 + 10.8 + 2.4 + 0,8 = 40 g
Rule of three
40 g of sample -------------- 26 g of silver
26 g of sample -------------- x
x = (26 x 26) / 40
x = 16.9 g of Silver
Final answer:
A 26 g sample of amalgam contains 16.9 g of silver, which is calculated based on the proportion of silver in the original amalgam mixture.
Explanation:
The student's question pertains to the calculation of the amount of silver in a 26 g sample of amalgam, which is a mixture of several metals. The total mass of the original amalgam mixture consists of 26 g of silver, 10.8 g of tin, 2.4 g of copper, and 0.8 g of zinc, which adds up to a total of 40 g. To find the amount of silver in a 26 g sample of this amalgam, we use the concept of proportion.
First, we calculate the percentage of silver in the original amalgam:
(mass of silver / total mass of amalgam) × 100 = (26 g / 40 g) × 100 = 65%
Now, we can find the mass of silver in the given 26 g sample of amalgam by multiplying the total mass of the sample by the percentage of silver:
(percentage of silver / 100) × mass of sample = (65 / 100) × 26 g = 16.9 g
Therefore, a 26 g sample of amalgam contains 16.9 g of silver.
Consider the solutions, 0.04 m urea [(NH2)2C=O)], 0.04 m AgNO3 and 0.04 m CaCl2. Which has (i) the highest osmotic pressure, (ii) the lowest vapor pressure, (iii) the highest boiling point?
The solution with the highest number of particles in solution (CaCl2 in this case), experiences the highest osmotic pressure, lowest vapor pressure and highest boiling point due to the principles of colligative properties.
Explanation:The question pertains to the colligative properties of solutions, which would be governed by the number of particles in the solution. The solutions are 0.04 m urea [(NH2)2C=O)], 0.04 m AgNO3, and 0.04 m CaCl2. For (i) Highest osmotic pressure, the solution with the highest ion count would yield the highest osmotic pressure. CaCl2 dissociates into three ions (Ca²+, and 2 Cl¯), therefore, it would exhibit the highest osmotic pressure. For (ii) Lowest vapor pressure, this would coincide with the solution with the highest osmotic pressure, again making it CaCl2, due to the greatest decrease in vapor pressure. For (iii) the highest boiling point, this too would be CaCl2 for the reasons stated above. The presence of more particles in a solution interferes more with the evaporation process, requiring more energy (higher temperature) to achieve boiling.
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An atom has 27 protons and 32 neutrons. Which of the following symbols is correct for this atom?
59Co
32Co
59Ge
27Ge
The atom with 27 protons and 32 neutrons is represented as 59Co. The number is calculated by adding protons and neutrons which is the mass number, and the protons determine the element symbol.
Explanation:The correct symbol for the atom is based on the number of protons it contains. The atomic number, which is what the number of protons is known as, identifies the element. In this case, 27 protons correspond to the element cobalt (Co). The mass number of an element is the sum of protons and neutrons, so in this atomic configuration, the total would be 27 protons + 32 neutrons = 59. Therefore, the correct symbol for this atom is 59Co.
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You determine that your compound is soluble in the acetone, but not the water, aqueous hydrochloric acid or aqueous sodium hydroxide solutions. You therefore conclude that the one characteristic of your compound is that it is ____________________ .
Answer:
Explanation:
Given the characteristics:
acetone is a non polar molecule
water, NaOH and HCl in water, the three of them are highly polar molecules
So then, the unknown compound is a non polar molecule.
Which element would have this representation: 43 ? 21 Question 4 options: Technetium Scandium Titanium Cobalt
Answer:
The naswer to your question is Scandium
Explanation:
43 means the atomic mass is normally presented as a power
21 means atomic number is always a subscript
₂₁ ? ⁴³
Technetium ₄₃Tc⁹⁸
Scandium ₂₁Sc⁴⁴
Titanium ₂₁Ti⁴⁷
Cobalt ₂₇Co⁵⁹
Answer:
B. Scandium is the answer
Explanation:
[tex]Sc^{43}_{21}[/tex]
When we look at this Nuclide symbol we get to know that 21 is the atomic number as it is in the subscript and 43 is the mass as it is in the superscript.
We identify an element from its atomic number by looking at the periodic table.
Atomic number 21 is element Scandium. Sc-43 is one of the isotope mentioned here.
We don’t use mass number to identify an atom.