How much ice (in grams) would have to melt to lower the temperature of 353 mL of water from 26 ∘C to 6 ∘C? (Assume the density of water is 1.0 g/mL.) Express your answer using two significant figures.

the correct (answer) is (c.) a light particle

Answer:

The structural level of a protein least affected by a disruption in hydrogen bonding is the primary level.

Answer: (a) [tex]\Delta G^0=-432.25kJ[/tex] , (b) [tex]\Delta G^0=55.96kJ[/tex] and (c)  [tex]\Delta G^0=-171.74kJ[/tex]

Explanation: (a) Oxidation half reaction for the given equation is:

[tex]Mg(s)\rightarrow Mg^2^+(aq)+2e^-E^0=2.37V[/tex]

The reduction half equation is:

[tex]Pb^2^+(aq)+2e^-\rightarrow Pb(s)E^0=-0.13V[/tex]

[tex]E^0_c_e_l_l=E^0_r_e_d_u_c_t_i_o_n+E^0_o_x_i_d_a_t_i_o_n[/tex]

[tex]E^0_c_e_l_l=-0.13V+2.37V[/tex]

[tex]E^0_c_e_l_l=2.24V[/tex]

[tex]\Delta G^0=-nFE^0_c_e_l_l[/tex]

where n is the number of moles of electrons transferred and F is faraday constant.

2 moles of electrons are transferred in the cell reaction which is also clear from both the half equations.

[tex]\Delta G^0=-2mol*96485\frac{C}{mol}*2.44V[/tex]

[tex]\Delta G^0=-432252.8J[/tex]

or [tex]\Delta G^0=-432.25kJ[/tex]

(b) Oxidation half reaction for the given equation is:

[tex]2Cl^-(aq)\rightarrow Cl_2(g)+2e^-E^0=-1.36V[/tex]

Reduction half equation is:

[tex]Br_2(l)+2e^-\rightarrow 2Br^-E^0=1.07V[/tex]

[tex]E^0_c_e_l_l=1.07V+(-1.36V)[/tex]

[tex]E^0_c_e_l_l=1.07V-1.36V[/tex]

[tex]E^0_c_e_l_l=-0.29V[/tex]

Now, we can calculate the [tex]\Delta G^0[/tex] same as we did for part a.

[tex]\Delta G^0=-2mol*96485\frac{C}{mol}*(-0.29V)[/tex]

[tex]\Delta G^0=55961.3J[/tex]

or [tex]\Delta G^0=55.96kJ[/tex]

(c) Oxidation half reaction for the given equation is:

[tex]Cu(s)\rightarrow Cu^2^+(aq)+2e^-E^0=-0.34V[/tex]

reduction half equation is:

[tex]MnO_2(s)+4H^+(aq)+2e^-\rightarrow Mn^2^+(aq)+2H_2O(l)E^0=1.23V[/tex]

[tex]E^0_c_e_l_l=1.23V+(-0.34V)[/tex]

[tex]E^0_c_e_l_l=0.89V[/tex]

[tex]\Delta G^0=-2mol*96485\frac{C}{mol}*0.89V[/tex]

[tex]\Delta G^0=-171743.3J[/tex]

or [tex]\Delta G^0=-171.74kJ[/tex]

To calculate the standard Gibbs free energy change (∆G°) for each reaction at 25°C in kJ, we can use tabulated electrode potentials. By writing half-cell reactions and summing the electrode potentials, we can determine the overall reaction's standard potential (E°). Then, using the formula ∆G° = -nFE°, we can calculate the standard Gibbs free energy change.

Use tabulated electrode potentials to calculate ∆G° rxn for each reaction at 25 °C in kJ.

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Answer:

Concentration of sodium bromide required = 2.38 M (around 2.4 M)

Explanation:

The equilibrium representing the complex ion formation is:

[tex]Cd^{2+} + 4Br^{-}\rightleftharpoons [CdBr_{4}]^{2-} .....Kf =5*10^{3}[/tex]-----(1)

where K(f) = formation equilibrium

The equilibrium representing the dissolution of Ca(OH)2 is:

[tex]Cd(OH)_{2}\rightleftharpoons Cd^{2+}+2OH^{-}.....Ksp = 2.5*10^{-14}[/tex]---(2)

where Ksp = solubility product

adding Equation (1)  and equation(2) gives the net reaction:

[tex]Cd(OH)_{2} + 4Br^{-}\rightleftharpoons [CdBr_{4}]^{2-}+2OH^{-}[/tex]

[tex]K = K_{f}*K_{sp} = 5*10^{3}*2.5*10^{-14}=\frac{[CdBr_{4}^{2-}][OH^{-}]^{2}}{[Br{-}]^{4}}[/tex]

[tex]12.5*10^{-11} =\frac{1*10^{-3} *[2*10^{-3}]^{2}}{[Br-]^{4} }\\[/tex]

[tex][Br-] = 2.38 M[/tex]

The study of chemicals is called chemistry. when the amount of reactant or product gets equal is said to be an equilibrium state.

The correct answer is 2.38M.

The data is given in the question is as follows:-

[tex]Kf =5*10^3\\Ksp =2.5*10^{-14}[/tex]

The reaction in the given question is as follows:-

[tex]Cd(OH)_2 +4Br^- +[CdbBr_4]^{2-} +2OH^-[/tex]

The formula we used to solve the question is as follows:-

After placing the value, the correct answer for the bromine is 2.38M.

Hence, the correct answer is 2.38M

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Answer: B.) What is the effect of plastic bags on birds?

Explanation:

A scientific process is a detailed sequential process in which answer of the scientific question can be derived on the basis of the implementation of the scientific methodology. The scientific methodology exhibit the direct observation and experimentation process.

B is the correct option this is because of the fact that this can be answered by direct observation and experimental trails which are the parts of scientific process.

Hydrogen bonds are the broken lines between the DNA molecules. These are the strongest intermolecular forces, so C.

Answer:

c

Explanation:

c

Answer:

=0.5 moles

Explanation:

Let us assume that the sodium chloride solution has a density of 1g/cm³.

Therefore the volume of the 0.5 kg of solution will be calculated as follows.

0.5kg into grams=0.5 kg×1000g/kg

=500g

volume= mass/density

=500g/1g/cm³

=500cm³

The solution is 1.0 M which means that 1.0 moles are in 1000 cm³

500cm³ will have:

(500 cm³×1.0 moles)/1000 cm³

=0.5 moles

Answer: 0.5

Explanation: edge 2021

0.128 M of iodide solution was reacted with thiosulphate.

The equation of the reaction is;

[tex]2S2O2^-3(aq) + I3^-(aq)------->S4O2^-6(aq) + 3I^- (aq)[/tex]

Number of moles of  S2O2^-3- = 29.6/1000 × 0.260 M

= 0.0077 moles

Since 2 moles of thiosulphate reacts with 1 mole of iodide

0.0077 moles of thiosulphate reacts with 0.0077 moles × 1 mole/ 2 moles

= 0.00385 moles of iodide.

Since;

Number of moles = concentration × volume

concentration of iodide = Number of moles/volume

Volume of iodide = 30/1000 = 0.03 L

Concentration of iodide =  0.00385 moles/0.03 L

= 0.128 M

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Answer:

1) Dihydropyridine receptor

2) Rynodine receptor

Explanation:

Rynodine receptor: It is a category of interacellular channels of calcium with different forms like neurons and muscles found in animal tissues.

Dihydropyridine receptor: they are present in muscle tissues and are able to sense voltage in skeleton muscles thus can increase or control the release of calcium.

Final answer:

The T-tubule on the T-tubule and the calcium channel on the membrane of the sarcoplasmic reticulum mediate the increases in cytoplasmic calcium required for muscle contraction.

Explanation:

The coupling between a T-tubule on the T-tubule and a calcium channel on the membrane of the sarcoplasmic reticulum mediates the increases in the amount of cytoplasmic calcium required to initiate a muscle contraction. When the action potential reaches the T-tubules, it triggers the opening of calcium channels in the adjacent sarcoplasmic reticulum, causing calcium ions to diffuse out and into the sarcoplasm. This calcium release from the sarcoplasmic reticulum is essential for the contraction of muscle fibers.

Molarity is defined as the number of moles form a certain compound in one liter of solution.

So the higher the molarity the higher the number of moles in one liter of solution, and we say that the concentration is increased. The lower the molarity the lower the number of moles in one liter of solution, and we say that the concentration is decreased.  

In a nutshell:

High molarity = concentrated solution

Low molarity = diluted solution

(A) concentrated

(B)  dilute

(C)  dilute

(D)  concentrated

(E)  dilute

(F)  concentrated

Answer:

A) C

B) D

C) D

D) C

E) D

F) C

hope it helped

ExpLanation:

Answer:

A. 4.48

Explanation:

3.6/0.804 = 4.48

Answer:

a. 4.48 L is the Answer

Explanation:

Molarity (M),  Molality (m), Normality (N),  Mass %,  Parts per million(ppm), billion(ppb), thousands(ppt)  are some of the terms we use to represent the concentration of the solution that is to represent the amount of solute present in a solvent.

Molarity is moles of solute present in 1L of the solution. The formula to find Molarity is

[tex]Molarity  = \frac {(moles solute)}{(volume of solution in L)}[/tex] and its unit is mol/L

Rearranging the formula

We get                          

Moles = Molarity × Volume

or

[tex]volume= \frac {moles}{Molarity}[/tex]

Plugging in the values  

[tex]volume=\frac {3.6mol}{0.804M}[/tex]

[tex]=\frac {3.6mol}{(0.804 mol/L)}=4.48 L[/tex]

(Answer)

Answer:

Stressing an equilibrium system means altering physical conditions to favor either side of the reaction in progress.

Explanation:

The stress  of equilibrium is achieved either by increasing physical properties or decreasing them eg. properties like pressure,volume or temperature of a substance.

These properties affect the direction of a reaction for a system in equilibrium.

Final answer:

Stressing an equilibrium system means causing a disruption in its balance, which can be done by changing reactant/product concentrations, pressure, or temperature. According to Le Châtelier's principle, the system will react by shifting in a direction to minimize the effects of the stress and re-establish equilibrium.

Explanation:

Le Châtelier's Principle

Stressing an equilibrium system means causing a change in conditions that disturbs the dynamic balance of a system where forward and reverse reactions occur at equal rates. Stress can be applied in several ways, including changes in the concentration of reactants or products, changes in pressure or volume (for gaseous reactions), or changes in temperature. These actions can push the system out of equilibrium, and as summarized by Le Châtelier's principle, when such stress is applied, the equilibrium will shift in a direction that helps to counteract or minimize the stress.

For example, if additional reactant is added to a system at equilibrium, the equilibrium will shift toward forming more products, decreasing the concentration of the added reactants. Conversely, if additional product is added, the equilibrium will tend to shift toward forming more reactants, to reduce the concentration of the added product. This is how Le Châtelier's principle allows us to predict the response of a stressed equilibrium.

Answer:

Here's what I get.

Explanation:

At the end of the reaction you will have a solution of the alcohol in THF.

The microdistillation procedure will vary, depending on the specific apparatus you are using, but here is a typical procedure.

The element of bromine  has entropy of  vaporization as  -93.1 J/(mol∙K) which is calculated as S=-ΔH/T.

It is defined as a substance which cannot be broken down further into any other substance. Each element is made up of its own type of atom. Due to this reason all elements are different from one another.

Elements can be classified as metals and non-metals. Metals are shiny and conduct electricity and are all solids at room temperature except mercury. Non-metals do not conduct electricity and are mostly gases at room temperature except carbon and sulfur.

The entropy of vaporization for bromine is calculated by the formula  S=-ΔH/T,substitution in given formula gives,

S=-30.91/332=-93.1 J/(mol∙K)

Thus, the element of bromine  has entropy of  vaporization  as  -93.1 J/(mol∙K) .

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Final answer:

The entropy of vaporization for bromine is 93.1 J/(mol·K), which means the correct answer is D. 93.1 J/(mol·K).

Explanation:

To find the entropy of vaporization (ΔSvap) for bromine, we can use the formula ΔSvap = ΔHvap / Tb, where ΔHvap is the heat of vaporization and Tb is the boiling point in Kelvin. Given that the heat of vaporization (ΔHvap) for bromine is 30.91 kJ/mol and its boiling point is 59 °C, we first need to convert these units appropriately. The boiling point in Kelvin is 59 °C + 273.15 = 332.15 K.

Converting the heat of vaporization to J/mol (since 1 kJ = 1000 J), we have 30.91 kJ/mol = 30910 J/mol.

Now, we can calculate the entropy of vaporization as follows: ΔSvap = 30910 J/mol / 332.15 K = 93.1 J/(mol·K).

Answer:

0.3 moles of aluminum

Explanation:

The reaction of Aluminium with copper sulfate reacts to give aluminium sulfate and copper metal ,

The balanced chemical reaction is as follows -

To produce 0.45 moles of copper metal, 0.30 moles of aluminum are required.

To determine how many moles of aluminum (Al) are needed to produce 0.45 moles of copper (Cu) metal, we need to refer to the balanced chemical reaction between aluminum and copper (II) chloride (CuCl₂).

The balanced equation is:

2 Al + 3 CuCl₂ → 2 AlCl₃ + 3 Cu

This means that 2 moles of aluminum produce 3 moles of copper. We can set up a ratio to find out how many moles of aluminum are needed to produce 0.45 moles of copper:

(2 moles Al / 3 moles Cu) = (x moles Al / 0.45 moles Cu)

Solving for x,

x = (2/3) x 0.45 = 0.30 moles of Al

Therefore, 0.30 moles of aluminum will be required to produce 0.45 moles of copper metal.

Answer:

CH₃CH₂I >  CH₃CH₂Cl > CH₃CH₂OH

Explanation:

SN₂ reaction -

It is the nucleophilic reaction bimolecular , where the nucleophile replaces the leaving group present in the reaction , this is a one step reaction .

The rate of the reaction depends on -

From the question ,

I is the best leaving group , then is Cl and least is OH .

Hence ,

The fastest to slowest rate of reaction is as follows -

CH₃CH₂I >  CH₃CH₂Cl > CH₃CH₂OH

The order of reactivity in an SN2 reaction for the given species, from fastest to slowest, is CH3CH2I > CH3CH2Cl > CH3CH2OH. Iodine is a better leaving group than chlorine, and chlorine is better than hydroxyl.

In SN2 reactions, the rate of reaction is largely determined by the leaving group. The better the leaving group, the faster the reaction proceeds. In the given species, the order of reactivity in an SN2 reaction, from fastest to slowest, is CH3CH2I > CH3CH2Cl > CH3CH2OH. This is because iodine (I) is a better leaving group than chlorine (Cl), and chlorine is a better leaving group than hydroxyl (OH).

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Answer:

It could be extracted 0.512 g of solute

Explanation:

The equation that relates the [tex]K_{D}[/tex] and the volumes of organic and aqueous phases is:

[tex]q_{solute-aq} =\frac{V_{aq} }{K_{D}xV_{org} + V_{aq}  }[/tex]

Where q_{solute-aq} refers to the fraction of solute remaining in the aqueous phase, V_{aq} is the aqueos phase volume, V_{org} is the organic phase volume and K_{D} is the partition coefficient of the solute in the solvents.

Moreover,for the three consecutive extractions of the same volume of organic phase we can write:

[tex]q_{solute-aq} =(\frac{V_{aq} }{K_{D}xV_{org} + V_{aq}  })^{ 3}[/tex]

So, plugging the values given into the equation we get:

[tex]q_{solute-aq} =(\frac{100 mL }{2.7x10 mL + 100 mL  })^{ 3}[/tex]

[tex]q_{solute-aq} =0.488[/tex]

The result obtained indicates that a fraction of 0.488 of solute remains in the aqueous phase.

Taking in account that the fraction formula is:

[tex]q_{solute-aq} = \frac{mass- of- solute- aq}{initial-mass- of -solute}[/tex]

[tex]0.488= \frac{mass- of- solute- aq}{1.0 g}\\\\0.488 x 1.0 g= {mass- of- solute- aq}\\0.488 g= {mass- of- solute- aq}\\[/tex]

Finally we substract the solute in the aqueous phase form the initial to get the amount in the organic phase:

[tex]1.0g - 0.488g = 0.512 g[/tex]

Final answer:

The weight of compound that can be extracted by three sequential 10mL portions of benzene can be calculated based on the compound's distribution coefficient.Therefore, a weight of approximately 0.05g of compound can be extracted by three sequential 10mL portions of benzene.

Explanation:

The distribution coefficient (K) represents the ratio of the concentration of a compound in one solvent to the concentration in another solvent. In this case, the compound distributes between benzene and water with a K value of 2.7. If 1.0g of the compound is dissolved in 100mL of water, we can calculate the weight of compound that can be extracted by three sequential 10mL portions of benzene.

Since K = 2.7, the ratio of compound in benzene to water is 2.7:1. This means that for every 2.7 parts of compound in water, there is 1 part in benzene. We can use this ratio to calculate the amount of compound that can be extracted.

Starting with 1.0g of compound in water, the first 10mL portion of benzene can extract (1.0g/2.7) = 0.37g of compound. The second 10mL portion can extract (0.37g/2.7) = 0.14g of compound. Similarly, the third 10mL portion can extract (0.14g/2.7) = 0.05g of compound. Therefore, a weight of approximately 0.05g of compound can be extracted by three sequential 10mL portions of benzene.

Answer:

Molar mass of compound = 38.17 g/mol

Explanation:

The mass of compound dissolved = 0.458 g

The mass of acetic acid taken = 30.0g = 0.03 kg

the depression in freezing point =1.50 K or 1.50 ⁰C

the relation between depression in freezing point and molality is:

Depression in freezing point = Kf X molality

Where Kf= cryoscopic constant = 3.90 ⁰C Kg/mol

Putting values

1.50 = 3.90 X molality

[tex]molality=\frac{1.50}{3.90}=0.385[/tex]

molality is moles of solute per Kg of solvent

[tex]molality=\frac{moles}{massofsolvent}=\frac{moles}{0.03}=0.385[/tex]

moles = 0.385 X 0.03 = 0.012

[tex]moles=\frac{mass}{molarmass}[/tex]

[tex]molarmass=\frac{mass}{moles}=\frac{0.458}{0.012}= 38.17g/mol[/tex]

Answer: The molar mass of the compound is 39.69 g/mol

Explanation:

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

To calculate the depression in freezing point, we use the equation:

[tex]\Delta T_f=iK_fm[/tex]

Or,

[tex]\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}[/tex]

where,

[tex]\Delta T_f[/tex] = Depression in freezing point = 1.50 K = 1.50°C   (Change remains constant)

i = Vant hoff factor = 1 (For non-electrolytes)

[tex]K_f[/tex] = molal freezing point elevation constant = 3.90°C/m

[tex]m_{solute}[/tex] = Given mass of solute = 0.458 g

[tex]M_{solute}[/tex] = Molar mass of solute (glucose) = ? g/mol

[tex]W_{solvent}[/tex] = Mass of solvent (acetic acid) = 30.0 g

Putting values in above equation, we get:

[tex]1.50^oC=1\times 3.90^oC/m\times \frac{0.458\times 1000}{\text{Molar mass of solute}\times 30.0}\\\\\text{Molar mass of solute}=\frac{1\times 3.90\times 0.458\times 1000}{1.50\times 30.0}=39.69g/mol[/tex]

Hence, the molar mass of the compound is 39.69 g/mol

Answer : The rate of formation of [tex]NOCl[/tex] is, [tex]8.48\times 10^{-2}M/s[/tex]

Explanation : Given,

Rate of disappearance of [tex]Cl_2[/tex] = [tex]4.24\times 10^{-2}M/s[/tex]

The given rate of reaction is,

[tex]2NO(g)+Cl_2(g)\rightarrow 2NOCl[/tex]

The expression for rate of reaction :

[tex]\text{Rate of disappearance}=-\frac{1}{2}\frac{d[NO]}{dt}=-\frac{d[Cl_2]}{dt}[/tex]

[tex]\text{Rate of formation}=\frac{1}{2}\frac{d[NOCl]}{dt}[/tex]

From this we conclude that,

[tex]\frac{1}{2}\frac{d[NOCl]}{dt}=-\frac{d[Cl_2]}{dt}[/tex]

[tex]\frac{1}{2}\frac{d[NOCl]}{dt}=-\frac{d[Cl_2]}{dt}[/tex]

[tex]\frac{d[NOCl]}{dt}=2\times \frac{d[Cl_2]}{dt}[/tex]

Now put the value of rate of disappearance of [tex]Cl_2[/tex], we get:

[tex]\frac{d[NOCl]}{dt}=2\times (4.24\times 10^{-2}M/s)=8.48\times 10^{-2}M/s[/tex]

Therefore, the rate of formation of [tex]NOCl[/tex] is, [tex]8.48\times 10^{-2}M/s[/tex]

The rate of reaction decides the direction in which the reaction goes. It decides the rate of flow of conversion.

The correct rate of the reaction is [tex]8.48*10^{-2[/tex]

The rate of the reaction of a given element is as follows:-

After solving it from the equation,:-

[tex]\frac{d[NOCL]}{dt} = 2*\frac{d[CL_2]}{dt}[/tex]

After solving it, the value we get is

[tex]2 * 4.24*10^{-2}\\=8.48*10^{-2[/tex]

Hence, the correct answer is [tex]8.48*10^{-2[/tex]

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Final answer:

The volume of water in the cylinder will rise to approximately 0.558 mL.

Explanation:

To find the volume to which the water in the cylinder will rise, we need to calculate the volume of the copper pellets. The density of pure copper is given as 8.96 g/cm³. From the given mass of the copper pellets (5.00 g), we can calculate the volume using the formula:

Volume = Mass / Density

Substituting the values, we get:

Volume = 5.00 g / 8.96 g/cm³ = 0.558 g/cm³

Therefore, the water in the cylinder will rise to a volume of 0.558 mL.

Answer : The correct option is, (A) -101.37 KJ

Explanation :

First we have to calculate the moles of HCl and NaOH.

[tex]\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=1.6mole/L\times 0.087L=0.1392mole[/tex]

[tex]\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=1.6mole/L\times 0.087L=0.1392mole[/tex]

The balanced chemical reaction will be,

[tex]HCl+NaOH\rightarrow NaCl+H_2O[/tex]

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.1392 mole of HCl neutralizes by 0.1392 mole of NaOH

Thus, the number of neutralized moles = 0.1392 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = [tex]87ml+87ml=174ml[/tex]

[tex]\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 174ml=174g[/tex]

Now we have to calculate the heat absorbed during the reaction.

[tex]q=m\times c\times (T_{final}-T_{initial})[/tex]

where,

q = heat absorbed = ?

[tex]c[/tex] = specific heat of water = [tex]4.18J/g^oC[/tex]

m = mass of water = 174 g

[tex]T_{final}[/tex] = final temperature of water = 317.4 K

[tex]T_{initial}[/tex] = initial temperature of metal = 298 K

Now put all the given values in the above formula, we get:

[tex]q=174g\times 4.18J/g^oC\times (317.4-298)K[/tex]

[tex]q=14110.008J=14.11KJ[/tex]

Thus, the heat released during the neutralization = -14.11 KJ

Now we have to calculate the enthalpy of neutralization.

[tex]\Delta H=\frac{q}{n}[/tex]

where,

[tex]\Delta H[/tex] = enthalpy of neutralization = ?

q = heat released = -14.11 KJ

n = number of moles used in neutralization = 0.1392 mole

[tex]\Delta H=\frac{-14.11KJ}{0.1392mole}=-101.37KJ/mole[/tex]

Therefore, the enthalpy of neutralization is, -101.37 KJ

Answer:

Explanation:

A methyl group consists of a carbon bonded to three hydrogen atoms.

A methyl functional group consists of a carbon atom bonded to three hydrogen atoms. Therefore, the correct option is option 1.

The methyl functional group is a basic building block in organic chemistry. It is made up of a carbon atom that is linked to three hydrogen atoms ([tex]CH_3[/tex]). The methyl group is frequently abbreviated as "Me."

Because carbon-hydrogen (C-H) bonds have equal electronegativities, methyl groups are nonpolar in nature. The methyl group's nonpolarity makes it comparatively unreactive in many chemical reactions, especially when contrasted to more polar functional groups.

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Answer:

First step:

7 ml + 5 ml = 12 ml

Second step:

% of A = 7/12 x 100 = 58.33%

% of B = 5/12 x 100 = 41.67%

Third step:

In 1116 ml

compound A = 1116 x (58.33/100) = 651 ml

compound B = 1116 x (41.67/100) = 465 ml

Explanation:

In the 1st step: with what is given, the total volume is 12 ml

In the 2nd step: Find the percentage of each compound in the drug according to what is given.

In the 3rd step: calculate the volume of each compound separately in the new total volume of 1116 ml using the percentage composition.

volume of compound A will therefore be 651 milliliters

By setting up a proportion based on the ratio of 7 milliliters of A for every 5 milliliters of B, solving the subsequent equations yields that 650 milliliters of compound A are needed to make 1116 milliliters of the drug.

To determine how many milliliters of compound A are needed to make 1116 milliliters of the drug, we can set up a proportion based on the ratio given. With 7 milliliters of compound A used for every 5 milliliters of compound B, we get the following equation:

Compound A / Compound B = 7 / 5

Let's let x be the amount of compound A and y be the amount of compound B needed to make 1116 milliliters of the drug, where:

x + y = 1116 mL

Furthermore, we have:

x / y = 7 / 5

From the second equation, we solve for y:

y = 5/7 x

Substituting this into the first equation:

x + 5/7 x = 1116

Multiplying every term by 7 to clear the fraction, we get:

7x + 5x = 1116 × 7

12x = 7804

Dividing both sides by 12:

x = 7804 / 12

x = 650.333...

We round this to the nearest milliliter, since we are dealing with a measurable quantity. Therefore:

x = 650 mL

Answer : The value of [tex]\Delta E[/tex] of the reaction is, -369.2 KJ

Explanation :

Formula used :

[tex]\Delta E=\Delta H-\Delta n_g\times RT[/tex]

where,

[tex]\Delta E[/tex] = internal energy of the reaction = ?

[tex]\Delta H[/tex] = enthalpy of the reaction = -184.6 KJ/mole = -184600 J/mole

The balanced chemical reaction is,

[tex]H_2(g)+Cl_2(g)\rightarrow 2HCl(g)[/tex]

when the moles of [tex]H_2\text{ and }Cl_2[/tex] are 2 moles then the reaction will be,

[tex]2H_2(g)+2Cl_2(g)\rightarrow 4HCl(g)[/tex]

From the given balanced chemical reaction we conclude that,

[tex]\Delta n_g[/tex] = change in the moles of the reaction = Moles of product - Moles of reactant = 4 - 4 = 0 mole

R = gas constant = 8.314 J/mole.K

T = temperature = [tex]25^oC=273+25=298K[/tex]

Now put all the given values in the above formula, we get:

[tex]\Delta E=(-184600J/mole\times 2mole)-(0mole\times 8.314J/mole.K\times 298K)[/tex]

[tex]\Delta E=-369200J[/tex]

[tex]\Delta E=-369.2KJ[/tex]

Therefore, the value of [tex]\Delta E[/tex] of the reaction is, -369.2 KJ

Answer:

Molar mass of vitamin K = 450.56\frac{g}{mol}[/tex]

Explanation:

The freezing point of camphor = 178.4 ⁰C

the Kf of camphor =  37.7°C/m

where : m = molality

the relation between freezing point depression and molality is

Depression in freezing point = Kf X molality

Where

Kf = cryoscopic constant of camphor

molality = moles of solute dissolved per kg of solvent.

putting values

2.69°C = 37.7°C/m X molality

molality = 0.0714 mol /kg

[tex]molality=\frac{molesofvitaminK}{massofcamphor(kg)}=\frac{moles}{0.025}[/tex]

moles of vitamin K = 0.0714X0.025 = 0.00178 mol

we know that moles are related to mass and molar mass of a substance as:

[tex]moles=\frac{mass}{molarmass}[/tex]

For vitamin K the mass is given = 0.802 grams

therefore molar mass = [tex]\frac{mass}{moles}=\frac{0.802}{0.00178}=450.56\frac{g}{mol}[/tex]

The molar mass of vitamin K, involved in normal blood clotting, is calculated to be 450 g/mol using the freezing point depression method with camphor as the solvent.

Vitamin K is involved in normal blood clotting. When 0.802 g of vitamin K is dissolved in 25.0 g of camphor, the freezing point of the solution is lowered by 2.69 °C. To calculate the molar mass of vitamin K, we will use the formula for freezing point depression:

ΔTf = Kf * m, where:

First, we rearrange the formula to solve for molality:

m = ΔTf / Kf = 2.69 °C / 37.7 °C/m = 0.0713 mol/kg

Next, calculate the moles of solute (vitamin K) using the mass of the solvent (camphor):

Moles of solute = m * mass of solvent (kg) = 0.0713 mol/kg * 0.0250 kg = 0.001783 mol

Finally, we find the molar mass (M) of vitamin K by dividing the mass of the solute by the moles:

M = mass of solute / moles = 0.802 g / 0.001783 mol = 450 g/mol

Thus, the molar mass of vitamin K is 450 g/mol.

Answer: Option (B) is the correct answer.

Explanation:

Natural gas is defined as the gas which is formed naturally beneath the surface of Earth that mostly contains methane and small amounts of ethane, propane etc.

Since, natural gas upon burning produces water and carbon dioxide resulting in the release of a clean gas as compared to other fuels. Carbon dioxide produced upon burning of natural gas is 50-60% lesser in amount as compared to release of carbon dioxide upon burning of coal.

Therefore, we can conclude that burning coal produces more carbon dioxide than burning natural gas.

Answer:

B is your answer

Explanation:

i took a test got it wrong and thats how i found out so your welcome

Answer:

A Cake Baking

Explanation:

All of the other options are physical changes because you can always bring it bake to it's original state unlike a cake baking you can't separate the flour, sugar, and eggs as it was before.

Answer: a cake baking

Explanation:

Chemical change can be define as a change in which the substance combines with the another substances so as to form a new substance, this is called as the chemical synthesis. The chemical decomposition can be define as the break down of one substance into different substances. The chemical change brings the change in the chemical composition of substances.

A cake baking is the example of the chemical change which occurs due to the combination various substances like flour, sugar, butter and others so as to form the cake on baking.

Answer:

A

Explanation:

Van der Waals forces are the weak electric forces of attraction between molecules and their strength is dependent on the distance between the molecules. The longer the distance between the molecules the weaker the forces. Weaker Van der Waals forces mean that molecules can easily escape from the liquid  - hence meaning higher volatility.

Answer:

A!!!

Explanation:

Answer:

319.15^{o}C[/tex]

Explanation:

When all other variables are constant, we are allowed to use the formula

[tex]\frac{T_{2} }{V_{2} } = \frac{T_{1} }{V_{1} } \\

Which can be rewritten as T_{2} = \frac{T_{1} V_{2} }{V_{1} }

if you make T2 the subject of the formula. This formula is true only if temperature is in Kelvin not degrees Celsius so T1 must be converted to Kelvin

Now to calculate T2

[tex]T_{2}= \frac{296.15K*3.38.10^{3}L }{1.69.10^{3}L }= 592.3K[/tex] = [tex]319.15^{o}  C[/tex]

By applying Boyle's Law to the given conditions, the volume of the ideal gas compresses to 0.04525 L when the pressure increases to 40.0 atm, assuming constant temperature.

The problem involves calculating the volume of a sample of ideal gas under constant temperature when the pressure changes. This scenario is perfectly described by Boyle's Law, which states that the product of the initial pressure and volume is equal to the product of the final pressure and volume, given by the formula P1V1 = P2V2, where P is pressure and V is volume. In this problem, the initial pressure (P1) is 1.00 atm, the initial volume (V1) is 1.81 L, and the final pressure (P2) is 40.0 atm. Our goal is to find the final volume (V2).

Applying Boyle's Law:

1.00 atm × 1.81 L = 40.0 atm × V2

To find V2, we rearrange the formula to solve for V2:

V2 = (1.00 atm × 1.81 L) / 40.0 atm

This gives us:

V2 = 0.04525 L

Therefore, when the pressure increases to 40.0 atm, the volume of the gas compresses to 0.04525 L.