Compare a cup of hot coffee with the Pacific Ocean. Which statement about thermal energy and temperature is correct?
Water in the Pacific Ocean has more thermal energy and a higher temperature.
Water in the Pacific Ocean has less thermal energy and a lower temperature.
Water in the Pacific Ocean has less thermal energy and a higher temperature
Water in the Pacific Ocean has more thermal energy and a lower temperature.
Answer:
The Answer Is (D.)
Explanation:
Select the correct answer.
Disturbances inside Earth’s core cause earthquakes. The starting point of the disturbance is called the epicenter. Why does the amplitude of a seismic wave usually decrease as the wave moves away from the epicenter?
A) The waves lose energy in the form of heat.
B) The frequency of the waves continues to increase.
C) The wavelength of the waves continues to decrease.
D) The waves encounter entirely different mediums.
When a wave travels through a material, it loses a small amount of energy as heat. Eventually, the wave will stop when it loses all of its energy.
I think the answer is A.
The amplitude of a seismic wave usually decrease as the wave moves away from the epicenter because the waves lose energy in the form of heat. The correct option is A.
What is an Amplitude of wave?It is the maximum distance from the mean position of the wave.
The amplitude of the seismic waves continues to decrease with distance because waves keeps on spreading in the larger portion of area and dissipates heat.
Therefore, the amplitude of a seismic wave usually decreases when the wave moves away from the epicenter because the waves lose energy in the form of heat. The correct option is A.
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why can hydrogen be placed in either group 1 or group 7 ?
Hydrogen resembles alkali metals i.e. Li , K , Na , K, Rb ,Cs and Fr of group 1 of the periodic table.
1) Electronic configuration : Like alkali metals, hydrogen also contains 1 electron in its outermost shell.
Hydrogen 1s1
Lithium 1s2 2s1
Sodium 1s2 2s2 2p6 3s1
2) Electropositive character: Like alkali metals ,hydrogen also loses its only electron to form hydrogen ion i.e. H+
H ——-> H+ + e‾
Na ———-> Na+ + e‾
Hydrogen like alkali metals exhibit electropositive character.
3) Oxidation State: Like alkali metals, hydrogen exhibits an oxidation state of +1 in its compounds.
H+ Cl‾
Na+ Cl‾
4) Combination with electronegative elements or non metals: Like alkali metals, hydrogen combines with electronegative elements such as oxygen ,halogen and sulphur forming their oxides ,halides and sulphide.
Oxides H2O like Na2O , K2O
Halides HCl like NaCl , KCl
Sulphides H2S like Na2S , K2S
5) Liberation at the cathode : When an aqueous solution of HCl is electrolysed H2 is liberated at the cathode in the same way as alkali metals are liberated at cathode during the electrolysis of their fused halides.
6)Reducing character: Like alkali metals, hydrogen also act as a strong reducing agent.
Fe2O3 + 4 H2 ———> 3Fe + 4H2O
B2O3 + 6 K ————–> 2B + 3 K2O
SIMILARITY with halogens
Hydrogen resemble halogens i. F , Cl, Br , I of group 17 of the periodic table in the following ways:
1) Electronic configuration: All the halogens have 7 electron in their respective outermost shell and thus have one electron less than the stable configuration of the nearest inert gas. Hydrogen has one electron in the outermost shell and thus has one electron less than the stable configuration of the nearest inert gas i.e. helium.
H 1s1 one electron less than He
F 1s2 2s2 2p5 one electron less than Ne 1s2 2s2 2p6
2) Electronegative character: Halogens have a strong tendency to gain one electron to form halide ions. Hydrogen show some tendency to gain one electron to form hydride ions.
H + e‾ ————-> H‾
Cl + e‾ —————-> Cl‾
3) Ionization enthalpy : Ionization enthalpy of hydrogen is quite compatible with those of halogens but much higher than those of alkali metals.
4) Oxidation State: Just like halogens, hydrogen shows an oxidation state of -1.
5)Liberation at the anode: When fused alkali metal hydrides such as Lithium, sodium hydride is subjected to electrolysis ,hydrogen is liberated at the anode. Similarly halogens are liberated at the anode when fused alkali metal halides are electrolysed.
2NaH ( l ) ————> H2 ( g ) + 2Na ( l )
2 NaCl ( l ) ————–> Cl2 ( g ) + 2Na ( l )
6) Atomicity and non metallic character: Just like halogens, hydrogen also exist as a diatomic molecule. Like halogens, hydrogen is a typical non metal.
7) Combination with metals: Hydrogen combines with highly electropositive alkali and alkaline earth metals to form metallic hydrides. Halogens combine with these metals to form metallic halides.
2Na + H2 ——-> 2NaH
Ca + H2 ——–> CaH2
8) Formation of covalent compounds: Hydrogen readily combines with non-metals such as carbon, Silicon ,nitrogen to form covalent compounds.
CH4 , SiH4 , NH3 , CCl4 , SiCl4
9) Replacement or substitution reaction: In many compounds of carbon ,hydrogen can be replaced by halogens and halogens can be replaced by hydrogen.
CH4 + Cl2 ——-> CH3Cl + HCl
CH3Cl + 2 [H] ——–> CH4 + HCl
What is a bright streak of light that results when a meteoroid burns up in earth's atmosphere?
A meteor is the bright streak of light observed when a meteoroid enters and burns up in Earth's atmosphere, due to friction and heat, often colloquially referred to as a shooting star. Larger pieces that reach the ground are known as meteorites. These events are quite common as countless cosmic dust particles enter the atmosphere daily.
A bright streak of light that results when a meteoroid burns up in the Earth's atmosphere is known as a meteor. This phenomenon occurs because as a meteoroid enters the atmosphere at high speeds, often up to 30,000 meters per second, the air in front of it is compressed. The intense heat from this compression and the resulting friction causing the meteoroid to incandesce, creating the visible streak of light we see in the sky, often described as a shooting star.
Most meteoroids are small pieces of rocky or metallic debris from asteroids or comets that enter Earth's atmosphere and burn up completely before reaching the ground. On occasion, larger pieces survive their fiery journey through the atmosphere and land on Earth, which are then called meteorites. It's fascinating to note that meteor sightings are quite common, as millions of these tiny particles enter the Earth's atmosphere daily, producing the brief flashes of light known as meteors.
When skydiver nellie opens her parachute, the air drag pushing the chute upward is stronger than earth's force of gravity pulling her downward. a friend says this means she should start moving upward?
A 98-kg fullback is running along at 8.6 m / s when a 76-kg defensive back running in the same direction at 9.8 m / s jumps on his back. What is the post-collision speed of the two players immediately after the tackle
The question requires calculating the post-collision speed of two football players using the law of conservation of momentum. The initial momenta of the players are summed up and then divided by their combined mass to find the final velocity after collision, using the formula: initial momentum = (combined mass) * final velocity.
Explanation:The subject of this question involves applying the conservation of momentum to find the post-collision speed of two football players. To solve the problem, we use the principle that in an isolated system (without external forces), the total momentum before the collision is equal to the total momentum after the collision. The formula for momentum is p = mv, where m is the mass and v is the velocity. For two objects colliding and moving together:
Given:
- Mass of fullback, m1 = 98 kg
- Velocity of fullback, v1 = 8.6 m/s
- Mass of defensive back, m2 = 76 kg
- Velocity of defensive back, v2 = 9.8 m/s
We calculate the total initial momentum:
initial momentum = (m1 * v1) + (m2 * v2)
Now, because after the collision they move together as one object, their combined mass is (m1 + m2), and let's call their final velocity vf. The conservation of momentum tells us that:
initial momentum = (m1 + m2) * vf
Therefore, we can solve for vf as follows:
vf = initial momentum / (m1 + m2)
By plugging in the given values, we can compute the post-collision speed of the two players immediately after the tackle.
in a human cannonball a person is shot from a cannon with a barrel that is 3.05 m long. 16700 J of work are done to accelerate the acrobat out of the cannon. what is the force exerted on the acrobat
As concentration increases by a tenth,what happens to the pH?
As concentration of a solution, increases by a tenth, the pH will become basic. The pH scale measures how acidic or basic the substance is, where 0 is the most acidic due to increase in H+ in a concentration, 14 is the most basic because of low H+ concentration and 7 is considered neutral with equal number of H+ and OH- ions.
Which of the following make up the three regions of the brain?
A.
anteriorbrain, midbrain, and innerbrain
B.
forebrain, midbrain, and hindbrain
C.
forebrain, middlebrain, and innerbrain
D.
anteriorbrain, betweenbrain, and posteriorbrain
Answer: B. forebrain, midbrain, and hindbrain
The human brain is a complex organ that acts as a control center of a body. Being a component of central nervous system, the brain sends, receives, processes and directs sensory information. There are three regions present in the brain, and each region exhibit specific functions. The three regions named as forebrain, midbrain and hindbrain.
The forebrain: It functions as thinking part of the brain. It processes the sensory information that are collected from various sense organs such as eyes, ears, nose, skin and tongue.
The midbrain: It connects the forebrain and the hindbrain. It functions as a bridge between forebrain and hindbrain, serves to transfer signals from hindbrain and forebrain. It deals with the motor control, hearing, vision, temperature regulation, and alertness.
The hindbrain: It controls the heart rate, blood pressure, sleep and waking functions and breathing.
On a night when the moon rises at 9 pm, what is its phase?
If the moon rises at 9 pm, the lunar phase will be waxing cresent, the 75% of moon is appearable.
Lunar Phase:
It is the degree of apperance of moon in a cycle of 29.5 days. The moon appears to increase in the first half of the cycle and then decrease in the second half of the cycle.
The moon appears more as its time of rise is increase.
Therefore, if the moon rises at 9 pm, the lunar phase will be waxing cresent, the 75% of moon is appearable.
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During an investigation a scientist heated 2.76 g of silver carbonate till it decomposed to leave a silver residue. The total mass of the silver residue formed was 2.16 g. Does the law of conservation of mass hold true in this case? Use complete sentences to justify your answer based on numerical calculations.
No, the law of conservation of mass does not hold true in this case.
The law of conservation of mass states that mass cannot be created or destroyed in a chemical reaction. However, in this case, the mass of the silver residue (2.16 g) is less than the mass of the silver carbonate (2.76 g). This means that some mass was lost during the reaction.
The most likely explanation for the lost mass is that it was converted into carbon dioxide gas. When silver carbonate decomposes, it produces silver metal and carbon dioxide gas. The carbon dioxide gas is not visible, so it is easy to miss.
We can calculate the amount of mass that was lost by subtracting the mass of the silver residue from the mass of the silver carbonate.
Mass lost = 2.76 g - 2.16 g = 0.6 g
This calculation shows that 0.6 g of mass was lost during the reaction. This is a violation of the law of conservation of mass.
The law of conservation of mass does not hold true in this case because some mass was lost during the reaction. The most likely explanation for the lost mass is that it was converted into carbon dioxide gas.
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The power used by an electric tool can be determined by multiplying the _____.
resistance times the current
current times the voltage
resistance times the voltage
Answer:
current time the voltage. Hope this helps:-)
Explanation:
Roman citizenship guaranteed Paul:
protection from injustices
speedy passport to any distant land under Grecian rule
freedom to preach the gospel
quick transport to lands under Roman rule
When the energy of a stimulus falls below the absolute threshold, its presence cannot be detected. true or false?
A TV with a power rating of 400 W uses 0.6 kWh in one day. For how many hours was the TV on during this day? Round answer to the tenths and include the unit.
Final answer:
The TV with a power rating of 400 W, which used 0.6 kWh of energy in one day, was on for 1.5 hours.
Explanation:
The question is asking us to find the number of hours a TV with a power rating of 400 W was on if it used 0.6 kWh in one day. To answer this, we will use the formula for energy consumption:
E = P × t
where E is energy in kilowatt-hours, P is power in kilowatts, and t is time in hours. Since 1 W = 0.001 kW, we first convert the TV's power to kilowatts:
P = 400 W × 0.001 kW/W = 0.4 kW
Now we rearrange the formula to solve for t:
t = E / P
t = 0.6 kWh / 0.4 kW = 1.5 hours
Therefore, the TV was on for 1.5 hours that day.
An electric generator moves a magnet near a coil of wire to produce an electric current. Describe the energy transformation in an electric generator. A) It transforms kinetic energy into electrical energy. B) It transforms electrical energy into kinetic energy. C) It transforms potential energy into electrical energy. D) It transforms electrical energy into potential energy.
The answer is A) It transforms kinetic energy into electrical energy.
Describe the shape of a convex lens and explain what it does to light.
Wave energy can only be transmitted through a material medium. wave energy can only be transmitted through a material medium.
a. True
b. False
It's False that wave energy can only be transmitted through a material medium. While sound waves need a material medium to travel, electromagnetic waves like light or radio waves can travel even in a vacuum.
Explanation:The statement 'wave energy can only be transmitted through a material medium' is False. Although some waves, such as sound waves, require a material medium (like air, water, or a solid substance) to travel, others do not. Specifically, electromagnetic waves, including radio waves, light waves, and X-rays, can travel in a vacuum, i.e., space where there is no material medium present.
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Physics Help Please!!! All multiple choice!
1.) Does an object moving in uniform circular motion have constant centripetal acceleration?
True or False
2.) How do the angular velocities of three knots on a rope compare as it is swung around in a circle? How about their speeds?
a.) the angular velocity and linear velocities are the same
b.) the linear velocities are the same, the angular velocity increases as you move toward the outside dot
c.) the angular velocity is the same, the linear velocities are fastest in the center
d.) the angular velocity is the same, the linear velocities are fastest on the outside
e.) both the linear and angular velocities increase as you move out
3.) An object travels with a constant speed in a circular path. The net force on the object is
a.) zero
b.) toward the center
c.) away from the center
d.) tangent to the object's path
A small fish is dropped by a pelican that is rising steadily at 0.50 m/s. How far below the pelican is the fish after 2.5 s?
A) 61 m
B) 29.3 m
C) 30.6 m
D) 1.1 m
Can you tell me the formula in order to find this?
the highest pitched sound that a human ear can detect is about 21 kHz. on the other hand dolphins can hear ultrasound with frequencies up to 280 kHz. what is the speed of sound in water if the wavelength of ultrasound with a frequency of 2.80 x 10^5 Hz is 0.510 cm?
Final answer:
The speed of sound in water is approximately 1428 m/s, calculated using the equation v = f × λ with the given frequency of ultrasound at 280 kHz and a wavelength of 0.510 cm.
Explanation:
The question asks about the speed of sound in water given the frequency and wavelength of ultrasound. In physics, the relationship between speed (v), frequency (f), and wavelength (λ) is given by the equation v = f × λ. With a frequency of 2.80 × 105 Hz (280 kHz) for dolphins and a wavelength of 0.510 cm or 0.00510 m, the speed of sound in water can be calculated as follows: v = 2.80 × 105 Hz × 0.00510 m, which gives v = 1428 m/s, the approximate speed of sound in water.
How long does it take a 1.51 × 104 W steam engine to do 8.72 × 106 J of work? Round your answer to three significant figures.
It would take 9 minutes and 37 seconds for a 1.51 × 10⁴ Watts steam engine to do 8.72 × 10⁶ J of work.
What is the efficiency of an engine?The efficiency of an Indian can be defined as the ratio of the total useful work done by the engine to the total heat absorbed by the engine.
It can be represented in the form of percentages or in terms of fractions as well.
As given in the problem we have to find out how long it takes a 1.51 × 10⁴ Watts steam engine to do 8.72 × 10⁶ J of work,
Power of the steam engine = work done by the engine/time
=8.72 × 10⁶ / 1.51 × 10⁴
Thus, It would take 9 minutes and 37 seconds for a 1.51 × 10⁴ W steam engine to do 8.72 × 10⁶ J of work.
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(Use the Pythagorean theorem to answer the question.) An airplane takes off going straight west at 340 km/h for 1 hour, then turns and heads south for another hour at 360 km/h before reaching its final destination. What is the airplane's displacement?
Answer:
495km to the southeast is the correct answer.
Explanation:
A race car starting from rest accelerates uniformly at a rate of 4.90 meters per squared. What is the cars speed after it has traveled 200 meters?
The race car's speed after it has traveled 200 meters, starting from rest and accelerating uniformly at a rate of 4.90 m/s², is approximately 44.27 meters per second.
Explanation:Given that the race car starts from rest and accelerates uniformly, we can apply the known physics equation for motion: v² = u² + 2as, where 'v' is the final velocity, 'u' is the initial velocity, 'a' is the acceleration, and 's' is the distance covered.
In this case, the car starts from rest, so 'u' is 0. The acceleration 'a' is given as 4.90 m/s², and the distance travelled 's' is 200 meters. Substituting these values into the equation, we get: v² = 0 + 2 * 4.90 * 200. Solving this, we find that 'v²' equals 1960, and therefore 'v' (the speed of the car) would be the square root of 1960, which is approximately 44.27 meters per second.
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A mass m attached to a horizontal massless spring with spring constant k, is set into simple harmonic motion. its maximum displacement from its equilibrium position is
a. what is the masses speed as it passes through its equilibrium position?
The speed of a mass m attached to a spring with spring constant k as it passes through the equilibrium position is given by the equation v = √{(k/m) [tex]\\cdot A^2[/tex]}, where A is the amplitude of the motion.
When a mass m attached to a horizontal massless spring with spring constant k undergoes simple harmonic motion (SHM), the speed of the mass at the equilibrium position can be determined using energy conservation principles. At maximum displacement, the entire energy of the system is potential energy stored in the spring, which is U = 1/2 k [tex]A^2[/tex], where A is the amplitude of motion.
When the mass passes through the equilibrium point, all the potential energy is converted into kinetic energy, KE = 1/2 m [tex]v^2[/tex]. By setting these two energies equal, we get 1/2 k [tex]A^2[/tex] = 1/2 m [tex]v^2[/tex]. This allows us to solve for the velocity, v, as the mass passes through equilibrium:
v = √{(k/m) [tex]\\cdot A^2[/tex]}.
The velocity at the equilibrium point is the maximum speed of the mass during its motion.
The maximum displacement of the spring is the amplitude A and the maximum speed, occurring at the equilibrium position, is given by option b)[tex]v_{\text{max}} = A \sqrt{\frac{k}{m}}[/tex]
A mass m attached to a horizontal massless spring with spring constant k undergoes simple harmonic motion. The maximum displacement from the equilibrium position is the amplitude A. To find the speed of the mass as it passes through its equilibrium position, we use the principle of conservation of energy.
In simple harmonic motion, the total mechanical energy is conserved and is the sum of kinetic energy (KE) and potential energy (PE). At the equilibrium position, the potential energy is zero, and all the energy is kinetic.
The total energy at maximum displacement (x = A) is given by the potential energy:
[tex]PE_{\text{max}} = \frac{1}{2} k A^2[/tex]
At the equilibrium position (x = 0), this energy converts to kinetic energy:
[tex]KE_{\text{max}} = \frac{1}{2} m v_{\text{max}}^2[/tex]
Setting PEmax equal to KEmax:
[tex]\frac{1}{2} k A^2 = \frac{1}{2} m v_{\text{max}}^2[/tex]
Solving for the maximum velocity vmax:
[tex]v_{\text{max}} = A \sqrt{\frac{k}{m}}[/tex]
Therefore, the speed of the mass as it passes through its equilibrium position is [tex]A \sqrt{\frac{k}{m}}[/tex] and the correct option is b).
Complete question is - A mass m attached to a horizontal massless spring with spring constant k, is set into simple harmonic motion. its maximum displacement from its equilibrium position is?
a. what is the masses speed as it passes through its equilibrium position? (A) 0 (B) A√(k/m) (C) A√(m/k) (D) 1/A√(k/m) (E) 1/A√(m/k)
A car is moving with a speed of 22 m/s. The driver then brakes, and the car comes to a halt after 6.5 s. What is the distance covered by the car after the driver brakes, until it comes to a stop?
The distance covered by the car until it comes to a stop is 71.6 m.
What is speed?Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Given parameters:
Initial speed of the car; v = 22 m/s.
The car stops after time t = 6.5 s.
The distance covered by the car after the driver brakes, until it comes to a stop; s = ?
So, deceleration of the car = ( initial speed - final speed)/time
= ( 22 m/s - 0 m/s )/6.5 s
= 3.38 m/s².
So, by using v² = u² - 2as in this decelerated motion; we get:
⇒ 0² = 22² - 2×3.38×s
⇒ s = 22²/(2×3.38) = 71.6 m.
Hence, the distance covered by the car after the driver brakes, until it comes to a stop is 71.6 m.
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1. A 2.00 kg cart on a frictionless track is pulled by force of 3.00N. What is the acceleration of the cart?
How much energy is need to raise 50 kg of water from 45 c to 80c?
What is the the acceleration of a proton that is 4.0 cm from the center of the bead? input positive value if the acceleration is directed toward the bead and negative if it is directed away from the bead?
1. If the spring of a jack-in-the-box is compressed a distance of 8.00 cm from its relaxed length and then released, what is the speed of the toy head when the spring returns to its natural length? Assume the mass of the toy head is 50.0 g, the spring constant is 80.0 N/m and the toy head moves only in the vertical direction. Also disregard the mass of the spring. (Hint: Remember that there are two forms of potential energy in the problem.)
The speed of the toy head when the spring returns to its normal length is approximately 3.2 m/s. This is found by equating the potential energy stored in the spring to the kinetic energy of the toy head and solving for the speed.
Explanation:The question is regarding the use of the principles of conservation of energy and Hooke's Law in the context of a jack-in-the-box toy. Consider that energy is conserved, we can set the potential energy equal to the kinetic energy. The potential energy stored in the spring while it is compressed is given by the formula PE = 0.5*k*x², where k is the spring constant and x is the distance the spring is compressed. In this case, PE = 0.5*80N/m*(0.08m)² = 0.256 J.
When the spring is released and returns to its natural length, this energy is converted into kinetic energy for the toy head. The kinetic energy is given by KE = 0.5*m*v² where m represents mass and v stands for speed. Setting this equal to the potential energy from above and solving for v, we get v = sqrt((2*0.256J)/(0.05kg)) = sqrt(10.24) m/s = approximately 3.2 m/s.
Therefore, the speed of the toy head when the spring returns to its normal length is approximately 3.2 m/s.
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