: hydrochloric acid reacts with the mineral calcite to produce carbon dioxide gas, water, and calcium chloride. based on what you have learned in activity a and activity b, what are three things you could do to make the reaction occur more quickly?

Answers

Answer 1
Following three things when applied could make the reaction to occur more quickly;

1) Increasing Temperature:
                                          Increase in temperature increases the Kinetic energy of molecules. This results in increase in the velocity and rate of collisions between reactants. Hence, greater the number of collisions between reactants per time greater will be the probability of formation of product per unit time.

2) Grinding Calcite:
                              Grinding of Calcium carbonate results in the increase of surface area of calcite. So greater the surface area greater is the exposure of Calcium carbonate to HCl molecules, hence the rate of formation of product increases.

3) Using Catalyst:
                            Very important. Catalyst when used decreases the activation energy and increase the rate of reaction by following methods.

                       a) Providing new pathway

                       b) weakening the bonds

                       c) providing surface area

                       d) holding up the reactant close to each other.
Answer 2

The things that can be done to make the reaction occur quickly include increasing the temperature, grinding calcite, and using catalyst.

It should be noted that a catalyst is used to speed up the rate of a chemical reaction. Also, increasing the temperature is important in increasing the kinetic energy of the molecules.

Furthermore, it should be noted that grinding calcite results in the rise in the surface area of the calcite. Therefore, the formation of product will rise.

In conclusion, these are important in making hydrochloric acid react with the mineral calcite quickly.

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Related Questions

What is the ground-state electron configuration for the element cobalt (z = 27)?

Answers

Final answer:

The ground-state electron configuration for cobalt (Z = 27) is [Ar] 3d7 4s2.

Explanation:

The ground-state electron configuration for the element cobalt (Co), which has an atomic number (Z) of 27, is as follows:

Co: [Ar] 3d74s2

This configuration indicates that cobalt has 2 electrons in the outermost 4s subshell and 7 electrons in the 3d subshell after the [Ar] noble gas core.

The ground-state electron configuration for the element cobalt (Z = 27) is 1s²2s²2p⁶3s²3p⁶4s²3d⁷. Co has 27 protons, 27 electrons, and 33 neutrons. The electron configuration represents the distribution of electrons in the energy levels and orbitals of an atom.

Which of the two substances would have the higher boiling point ch4 or c?

Answers

Carbon has a higher boiling point.

When 5-hydroxypentanal is treated with methanol in the presence of an acid catalyst, 2-methoxytetrahydropyran is formed. draw the structure of the second intermediate in this reaction?

Answers

The conversion of 5-Hydroxypentanal to 2-methoxytetrahydropyran takes place in two steps. In first step the carbonyl group of 5-hydroxypentanal gets protonated and is being attacked by the hydroxyl group of its own molecule and results in the formation of six membered hetrocyclic ring called tetrahydro-2H-pyran-2-ol
The tetrahydro-2H-pyran-2-ol on protonation looses the water molecule results in the formation of second intermediate called as 2,3,4,5-tetrahydropyrylium (Shown in red). This intermediate when attacked by Methanol molecule results in the formation of 2-methoxytetrahydropyran as shown below.

2,2-dimethyl-4-propyloctane has how many secondary carbons? view available hint(s) 2,2-dimethyl-4-propyloctane has how many secondary carbons? five nine six seven

Answers

Structure of 2,2-dimethyl-4-propyloctane is in the Word document below.
Answer is: six secondary carbons.
Secondary carbon (2°) is attached to two other carbons. Secundary carbons are third, fifth, sixth and seventh in octane and first and second in propyl.
Primary carbon (1°) is  attached to only one carbon.
Tertiary carbon (3°) is attached to three other carbons.
Quaternary carbon (4°) is attached to four other carbons.

What are the products of the chemical reaction that occurs when zinc metal is added to an aqueous solution of hydrochloric acid?

Answers

Zn(s) +2 HCl(aq) ---> ZnCl2(aq) +H2(g) (products are Zinc chloride and hydrogen gas)

n comparison to molecules that interact by London dispersion forces only, the melting point of similar-sized molecules forming hydrogen bonds would most likely be about the same. unpredictable. lower. higher.

Answers

Hydrogen bonds are the strongest intermolecular bonds, so the melting points would be much higher. 

Answer:

d

Explanation:

Why do reactions have activation energies?

Answers

According to the collision theory, the following criteria must be met in order for a chemical reaction to occur: Molecules must collide with sufficientenergy, known as the activation energy, so that chemical bonds canbreak. Molecules must collide with the proper orientation.

If 0.158 g of a white, unknown solid carbonate of a group 2A metal (M) is heated and the resulting CO2 is transferred to a 285 ml sealed flask and allowed to cool to 25 degrees Celsius, the pressure in the flask is 69.8 mmHg. What is the identity of the carbonate?

Answers

using the ideal gas law equation we can find the number of moles of CO₂ formed 
PV = nRT
where 
P - pressure - 69.8 mmHg x 133 Pa/mmHg = 9 283 Pa
V - volume - 285 x 10⁻⁶ m³
n - number of moles 
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in Kelvin - 25 °C + 273 = 298 K
substituting these values in the equation 
9283 Pa x 285 x 10⁻⁶ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 298 K
n = 1.067 x 10⁻³ mol

decomposition of metal carbonate is as follows 
MCO₃ ---> MO + CO₂
stoichiometry of MCO₃ to CO₂ is 1:1
therefore number of moles of MCO₃ heated = number of CO₂ moles formed 
number of MCO₃ moles = 1.067 x 10⁻³ mol
molar mass = mass / number of moles 
molar mass = 0.158 g / 1.067 x 10⁻³ mol = 148 g/mol 
since carbonate molar mass is known -
 (molar mass of C x 1 C atom) + (molar mass of O x 3  O atoms)  
12 + 16x 3 = 12 + 48 = 60 
then mass of metal M - 148 - 60 = 88
group II metal with molar mass of 88 is Ra - Radium 

How many unpaired electrons are present in a neon atom?

Answers

None. Neon has two layers of electrons, both filled completely. This means that there cannot be unpaired electrons in this atom.

Electrons are a  subatomic particle with a negative charge. They are also found present in atoms.

The number of unpaired electrons in a neon atom is zero.

A neon atom is part of the first twenty element and it is the tenth element in the series. Its chemical symbol is represented as Ne, its atomic number is 10 while the atomic mass is approximately 20.

It belongs to period 2 and found in the noble gas group. As the number of protons is the same as the electrons, therefore the number of electrons is 10.

In a neon atom, its electronic configuration is [He] 2S2 2p6. All electrons here are paired (in twos) with none unpaired. Therefore, the number of unpaired electrons in a neon atom is zero.

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A solution with a volume of 1.00 l is 0.450 m in ch 3 cooh(aq) and 0.550 m in ch 3 coona(aq). what will the ph be after 0.0800 mol of hcl is added to the solution?

Answers

Before addition of HCl,

conc. of CH3COOH = 0.450 M
conc. of CH3COONa = 0.550 M

After addition of 0.08 M HCl, following reaction occurs in system:
HCl + CH3COONa ↔  CH3COOH + NaCl

Thus, in reaction system conc. of CH3COOH will increase to 0.53 M (0.08M + 0.450M)
And, conc to CH3COONa will reduce to 0.47 M (0.550M - 0.08M)

Now, conc. of H+ ions = ka [tex] \frac{[acid]}{[conjugated base]}[/tex]
where ka = dissociation constant for acid = 10^-5 for Ch3COOH

∴ conc. of H+ ions = [tex] \frac{0.53}{0.47} [/tex]
                              = 1.1277 x 10^-5

Now, pH = -log [H+] = -log (1.1227 x 10^-5) = 4.94

"at what gas temperature t e would the average translational kinetic energy of a helium atom be equal to that of an oxygen molecule in a gas of temperature 300 k"

Answers

Based on equipartition theorem, the average kinetic energy of molecules is mathematically expressed as,
<K.E.> = [tex] \frac{3kT}{2} [/tex]
where, k = Boltzmann's Constant.
T = temperature in Kelvins.

Thus from above expression, it can be seen that average kinetic energy of molecules is independent of mass and, it is dependent only on temperature.

Hence, at temperature of 300 K the average kinetic energy associated with both helium and oxygen will be same.  

The average translational kinetic energy of helium s equal to that of oxygen at [tex]\boxed{300\;{\text{K}}}[/tex] .

Further Explanation:

One of the states of matter is gas. In gases, the atoms and molecules have space between them and can easily move over each other hence gases are compressible. Gases neither have fixed shape nor volume. It occupies the shape and volume of the container. The examples of matter that are gases are nitrogen and carbon dioxide.

The kinetic theory is based on the following postulates:

1. Gas molecules have a large collection of individual particles with empty space between them and the volume of each particle is very small as compared to the volume of the whole gas.

2. The gas particles are in straight-line motion or random motion until they are not collided with the wall of the container or with each other.

3. The collision between the gas particles and the wall of the containers are an elastic collision that means molecules exchange energy but they don’t lose any energy during the collision. So the total kinetic energy is constant.

The formula to calculate the average translational kinetic energy of helium is as follows:

[tex]{{\text{E}}_{{\text{He}}}} = \frac{3}{2}{\text{k}}{{\text{T}}_{{\text{He}}}}[/tex]           …… (1)

Here,

[tex]{{\text{E}}_{{\text{He}}}}[/tex] is the average translational kinetic energy of helium gas.

k is the Boltzmann constant.

[tex]{{\text{T}}_{{\text{He}}}}[/tex]  is the absolute temperature of helium gas.

The formula to calculate the average translational kinetic energy of oxygen is as follows:

[tex]{{\text{E}}_{{{\text{O}}_{\text{2}}}}} = \frac{3}{2}{\text{k}}{{\text{T}}_{{{\text{O}}_{\text{2}}}}}[/tex]                                                                                                …… (2)

Here,

[tex]{{\text{E}}_{{{\text{O}}_{\text{2}}}}}[/tex] is average translational kinetic energy of oxygen gas.

k is the Boltzmann constant.

[tex]{{\text{T}}_{{{\text{O}}_{\text{2}}}}}[/tex]  is absolute temperature of oxygen gas.

Since both gases have same average translational energy. So left-hand side of equation (1) and (2) becomes equal, and therefore right-hand side of both equations can be compared as follows:

[tex]\frac{3}{2}{\text{k}}{{\text{T}}_{{{\text{O}}_2}}} = \frac{3}{2}{\text{k}}{{\text{T}}_{{\text{He}}}}[/tex]                                                                                                       …… (3)

Rearrange equation (3) to calculate  [tex]{{\text{T}}_{{{\text{O}}_{\text{2}}}}}[/tex]  

[tex]{{\text{T}}_{{{\text{O}}_2}}} = {{\text{T}}_{{\text{He}}}}[/tex]                                                        …… (4)

The value of [tex]{{\text{T}}_{{\text{He}}}}[/tex] is 300 K. So according to equation (4),  [tex]{{\text{T}}_{{{\text{O}}_{\text{2}}}}}[/tex] also becomes 300 K.

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Answer details:

Grade: High School

Subject: Chemistry

Chapter: Ideal gas equation

Keywords: 300 K, helium, oxygen, average translational kinetic energy, k, Boltzmann constant, absolute temperature, gas, kinetic theory, 3/2 kT, same, equal.

Which statement describes a gas condensing into a liquid?

Answers

condensation / hope this helps !

Answer:

The molecules get closer together and move more slowly.

Explanation:

from a gas to a liquid, the atoms or molecules of the substance do not change. Instead, the motion of the atoms or molecules in the substance determines its state of matter.

gas condenses to form a liquid, the molecules get closer together and move more slowly. If the molecules continue to slow down until they move so slowly that they can only vibrate against one another, then the substance becomes a solid.

While studying chemical and physical changes, students added salt to a glass of water. They stirred the salt until it dissolved and could no longer be seen. "That's a chemical change," Sarah stated. Do you agree? Explain. A) Yes, it is a chemical change because something new is formed. B) No, it is a physical change. It is salt and water and you can get the salt back by boiling off the water. C) Yes, it is a chemical change because there was a change in the appearance of one of the components, the salt. D) No, it is a physical change. A chemical change cannot occur when you mix two compounds together like salt, NaCl, and water, H2O, without adding heat.

Answers

B. It's debatable if it's a physical or chemical change, because actual chemists don't have a hard distinction between the two.
B. It's debatable if it's a physical or chemical change, because actual chemists don't have a hard distinction between the two.

How many sucrose molecules are in 3.0 moles of sucrose scientific

Answers

Answer:
             1.80 × 10²⁴ Molecules of Sucrose

Solution:

Number of Moles and Number of Particles (molecules in given case) are related to each other as,

                  Moles  =  Number of Molecules ÷ 6.022 × 10²³

Solving for Number of Molecules,

                  Number of Molecules  =  Moles × 6.022 × 10²³

Data Given;
                     Moles  =  3 moles

Putting values in eq,


                 Number of Molecules  =  3 mol × 6.022 × 10²³


                 Number of Molecules  =  1.80 × 10²⁴ Molecules

Answer:1.80 x 10^24

Explanation:

Two of the substances in part 1 are ionic. which factors will result in a stronger ionic bond overall?

Answers

The factors that result in a stronger ionic bond are greater absolute charges and smaller ions. The similarity of ionic sizes can affect the bond's stability but doesn't directly make the bond stronger or weaker.

The following factors often affect an ionic bond's strength:

Greater absolute charges: Ionic bonds are more powerful when the positive and negative charges of the participating ions are greater. For instance, because the charges are higher in the former situation, the connection between a +2 ion (for instance, Ca²⁺) and a -2 ion (for instance, O₂) is stronger than between a +1 ion (for instance, Na⁺) and a -1 ion (for instance, Cl).

Ion bonds formed by smaller ions are frequently stronger. Ions can move closer to one another when they are smaller, which increases the electrostatic attraction between them.

Therefore, higher absolute charges and smaller ions produce an ionic bond that is stronger. Though it doesn't directly strengthen or weaken the binding, the similarity of the ionic sizes can have an impact on how stable the bond is.

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A stronger ionic bond is characterized by larger ionic charges and smaller ion sizes, resulting in greater attraction and higher lattice energy. For instance, a 2+ cation would form a stronger ionic bond with a chloride ion than a 1+ cation due to the greater charge.

The factors that will result in a stronger ionic bond overall include the magnitude of the charges and the size of the ions. A stronger ionic bond is formed when the ions involved have larger charges because larger charges result in a greater electrostatic force of attraction. Additionally, smaller ions form stronger bonds since they can get closer together, which increases the attraction between them. The lattice energy is a measure of the strength of ionic bonding.

Sodium chloride is an example of a substance with ionic bonds that result in high melting and boiling points due to the strong attractions. The strength of an ionic bond is directly proportional to the quantity of the charges and inversely proportional to the distance between the charged particles. For instance, a cation with a 2+ charge would form a stronger ionic bond with Cl− than a cation with a 1+ charge because of the greater charge magnitude.

A sample of a compound contains 32.0g C and 8.0g H. It’s molar mass is 30.0/mol. What is the compounds molecular formula?

Answers

Answer:
 
Given mass of C is 32.0 grams
Given mass of H is 8.0 grams
Molar mass of C is 1212 g/mol 
Molar mass of H is 1.01 g/mol

Thus
32.0 grams of C 8.0 grams of H →3212=2.66 moles of C→81.01=7.92 moles of H32.0 grams of C →3212=2.66 moles of C8.0 grams of H →81.01=7.92 moles of H

When we divide 7.92 by 2.66 we obtain 2.977 which is approximately 3. This means that the ratio of atoms of CC to the atoms of HH is 1:3.

Thus, empirical formula for the compound is CH3CH3.

Molar mass of CH3CH3 is 1⋅12+3⋅1.01=15.031⋅12+3⋅1.01=15.03. Since molar mass of the compound we have to find is 3030 g/mol we have tu multiply subscripts by 2.

Thus, final compound is C2H6C2H6.

Consider 2NH3(g)+3CuO(s)→N2(g)+3Cu(s)+3H2O(g) 2NH 3 ​ (g)+3CuO(s)→N 2 ​ (g)+3Cu(s)+3H 2 ​ O(g). What volume (in mL) of NH3 NH 3 ​ is required to completely react 45.2 g of CuO at STP? Enter your solution as a numerical value with no units.

Answers

the volume of  in Ml  of NH3  required  to completely  react  with  45.2 g  of CUO   at  STP  is 8489.6 Ml

 calculation
calculate the moles  of CUO  used
moles= mass/molar mass
45.2 g/79.5 g/mol =0.569 moles

Reacting  equation 
2NH3  + 3CUO = N2  +3CU  +3H2O
by  use of reacting  ratio  between  NH3 to CUO  which jis  2:3 the moles of  NH3  = 0.569 x2/3 = 0.379 moles

At STP  1  mole  = 22.4 L
what about  0.379 moles

=0.379  x22.4  = 8.4896  L

in  Ml  = 8.4896  x1000 =8489.6 ml

what is the molarity of 10.0 g of kcl in 0.500 l of solution

Answers

Molarity is defined as number of moles of the solute in 1 liter of solution.

Molarity = Moles of solute (mol) / Volume of the solution (L)

moles of KCl = mass (g) / molar mass (g/mol)
                      = 10.0 g / 74.5 g/mol
                      = 0.134 mol

Hence molarity = 0.134 mol / 0.500 L
                         = 0.268 mol/L

The solubility product for chromium(iii) fluoride is ksp = 6.6 × 10–11. what is the molar solubility of chromium(iii) fluoride?

Answers

Final answer:

To determine the molar solubility of chromium(III) fluoride, we need to use the solubility product constant (Ksp) of 6.6 × 10⁻¹¹. The molar solubility of chromium(III) fluoride is 8.184 × 10⁻⁴M.

Explanation:

To determine the molar solubility of chromium(III) fluoride, we need to use the solubility product constant (Ksp) of 6.6 × 10⁻¹¹ for chromium(III) fluoride. The Ksp expression is Ksp = [Cr³⁺][F⁻]³.

Let's assume the molar solubility of chromium(III) fluoride is x M. Since the stoichiometry of the balanced equation for its dissolution is 1:3 (one chromium ion per three fluoride ions), the equilibrium expression becomes Ksp = x(3x)³.

Now, we can set up the expression and calculate the molar solubility by solving the equation: Ksp = 108x⁴ = 6.6 × 10⁻¹¹. Solving for x gives x = 8.184 × 10⁻⁴ M. Therefore, the molar solubility of chromium(III) fluoride is 8.184 × 10⁻⁴ M.

All changes in chemistry are chemical? True or false?

Answers

False; Along with chemical changes, there are also physical changes.
False. Chemistry has physical and chemical changes. Physical would resemble ripping a piece of paper in half. Chemical would be burning the piece of paper.

What is the standard gibbs free energy of formation, ∆gºf, of nh3(g) at 298 k?

Answers

The standard Gibbs free energy of formation of NH3(g) at 298 K is approximately -16.5 kJ/mol.

The standard Gibbs free energy of formation (ΔG°f) for ammonia (NH3(g)) at 298 K is approximately -16.5 kJ/mol. The standard Gibbs free energy of formation for a substance is the change in Gibbs free energy when one mole of the substance is formed from its elements in their standard states. The standard state for nitrogen gas (N2) is N2(g) at 1 bar pressure, and for hydrogen gas (H2) it is H2(g) at 1 bar pressure.

please note that the given value of -16.5 kJ/mol is an approximation, and it is recommended to refer to the latest thermodynamic data sources for the most accurate and up-to-date information.

help!!
The electron sea is responsible for which of the following properties?
A. All of these
B. Malleable
C. Ductile
D. Conducting electricity and heat

Answers

A. All of these, because these are properties of metals, and the electron sea presets in metals.

Answer:

D.Conducting electricity and heat

Explanation:

Metal : It is defined as that substance which is good conductor of electricity and heat. Metal have  ductile and malleable property.In metal, atoms are held together by metallic bonds .The valence electrons from s and p orbital are delocalised and they form sea of electrons that surround the positively charged nuclei of the interacting metal ion.Then , the electrons are freely move throughout the space between atomic nuclei.

Due to availability of free  electrons, metal conduct electricity and heat.

Therefore, the electron sea is responsible for conducting electricity and heat .

A mixture of 100 g of k2cr207 and 200 g of water is stirred at 60 °c until no more of the salt dissolves. the resulting solution is poured off, leaving the undissolved solid behind. the solution is now cooled to 20°c. what mass of k2cr207 crystallizes from the solution during the cooling?

Answers

One example of a solution is salt water which is a mixture of water and salt. You cannot see the salt and the salt and water will stay a solution if left alone. Parts of aSolution. Solute - The solute is the substance that is being dissolved by another substance.

No K₂Cr₂O₇ will crystallize out of the solution during cooling.

What is crystallization?

Crystallization is a separation technique used to purify a solid substance by selectively dissolving it in a suitable solvent at a high temperature and then cooling the solution to obtain pure crystals of the solute.

Given:

The solubility of K₂Cr₂O₇ in water at 60°C is 127 g/100 mL, and at 20°C is 13.9 g/100 mL.

Dissolved 100 g of  K₂Cr₂O₇ in 200 g of water, which is 200 mL of water.

At 60°C, the solution can dissolve 127 g/100 mL × 2 L

= 254 g of  K₂Cr₂O₇.

100 g of  K₂Cr₂O₇, the solution is saturated and no more of the salt can dissolve.

When the solution is cooled to 20°C, the solubility of K₂Cr₂O₇ is only 13.9 g/100 mL.

The amount of water in the solution at 20°C is 200 mL. The maximum amount of K₂Cr₂O₇ that can remain in solution at this temperature is:

13.9 g/100 mL × 2 L = 278 g

Dissolved 100 g of K₂Cr₂O₇ in the solution, the amount that will crystallize out is:

100 g - 278 g = -178 g

This result is negative, indicating that all the K₂Cr₂O₇ will remain in solution at 20°C.

Therefore, no K₂Cr₂O₇ will crystallize out of the solution during cooling.

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A solution of ammonia and water contains 2.60×1025 water molecules and 6.90×1024 ammonia molecules. how many total hydrogen atoms are in this solution

Answers

1 molecule of NH3 has 3 atoms of H.
6.90*10²⁴ molecules NH3 have 3*6.90*10²⁴ =20.7*10²⁴ atoms H=2.07*10²⁵ atoms H

1 molecule H2O of has 2 atoms of H.
2.60*10²⁵ molecules of H2O have 2*2.60*10²⁵ =5.20 *10²⁵ atoms of H

2.07*10²⁵ + 5.20 *10²⁵ =7.27*10²⁵ atoms of H altogether.

The isotope lithium-7 has a mass of 7.0160 atomic mass units, and the isotope lithium-6 has a mass of 6.0151 atomic mass units. given the information that 92.58 percent of all lithium atoms found in nature are lithium-7 and 7.42 percent are lithium-6, calculate the atomic mass of lithium, li (atomic number 3).

Answers

atomic mass of Li is the weighted average atomic mass with regard to their percentage abundance in nature 
atomic mass of Li - mass of Li-6 x % of Li-6 + mass of Li-7 x % of Li-7
substituting these values in the formula
atomic mass of Li - 6.0151 x 7.42% + 7.0160 x 92.58 %
atomic mass of Li - 0.446 + 6.495 = 6.941 
therefore atomic mass of Li is 6.941

A 3.5 gram sample of a radioactive element was formed in a 1960 explosion of an atomic bomb at Johnson Island in the Pacific test site. The half-life of the radioactive element is 28 years. How much of the original sample will remain in the year 2030? Choose the closest.

DO NOT GUESS, ONLY COMMENT IF YOU KNOW

Answers

0.50 g

That should be the correct answer :)

Answer : The correct answer for amount of radioisotope remain in 2030 is 0.619 g .

Radioactive Decay is emission of radiations ( in form of alpha , beta particle etc ) by unstable atom .

Radioactive decay is FIRST ORDER reaction . So , the equation of first order can be used to find decay constant , amount of radioisotopes or half life .

The equation for radioactive decay is given as :

[tex] ln (\frac{N}{N_0}) = -k * t [/tex]

Where : N = amount of radioisotope at time t

N₀ = amount of radioisotope initially present

k = decay constant t = time

Half life :

It is time when amount of radioisotope decrease to 50 % of its original amount . Half life [tex] (T_\frac{1}{2} ) [/tex] and decay constant can be related :

[tex] T_\frac{1}{2} = \frac{ln 2 }{k} = \frac{0.693}{k} [/tex]

Following are the steps can be used to determine amount of radioisotope (N) :

1) To find decay constant :

Given : [tex] (T_\frac{1}{2} ) [/tex] = 28 yrs

Decay constant can be calculated using half life by plugging value in half life formula :

[tex] 28 yrs = \frac{0.693}{k} [/tex]

On multiplying both side by k

[tex] 28 yrs * k= \frac{0.693}{k} *k [/tex]

On dividing both side by 28 yrs

[tex] \frac{28 yrs * k}{28 yrs} = \frac{0.693}{28 yrs} [/tex]

k = 0.02475 yrs⁻¹

2) To find amount of radioisotope (N):

Given : Amount of radioisotope originally present = 3.5 g

Time = 2030 - 1960 = 70 yrs

decay constant = 0.02475 yrs⁻¹

Amount of radioisotope (N) = ?

Plugging these values in the formula as:

[tex] ln (\frac{N}{3.5 } ) = - 0.02475 yrs^-^1 * 70 yrs [/tex]

[tex] ln (\frac{N}{3.5 } ) = - 1.7325 [/tex]

[tex] ln\frac{N}{No} [/tex] can be converted using the formula ( [tex] ln (\frac{a}{b} ) = ln a - ln b [/tex] )

ln N - ln (3.5 ) = - 1.7325

(ln 3.5 = 1.253 )

ln N -1.253 = -1.7325

Adding both side 1.253

ln N -1.253 + 1.253 = -1.7325 + 1.253

ln N = -0.4795

Taking anti ln of -0.4795

N = 0.619 g

Hence amount of radioisotope remained in 2030 is 0.619 g



The compound aluminum acetate is a strong electrolyte. write the reaction when solid aluminum acetate is put into water:

Answers

When solid aluminum acetate (Aluminum Ethanoate) is put into water, it dissociates into its constituent ions, resulting in the following reaction:

Aluminum Acetate (solid) → Aluminum ions [tex]\rm (Al^3^+)[/tex] + Acetate ions [tex]\rm (CH_3COO^-)[/tex]

When solid aluminum acetate (also known as aluminum ethanoloate) is added to water, aluminum ions [tex]\rm (Al^3^+)[/tex] and acetate ions[tex]\rm (CH_3COO^-)[/tex]are produced. The attraction between the ions and the polar water molecules causes this separation. Hydration is the process through which water molecules surround these ions.

Due to the presence of freely moving ions that promote the flow of electric current, the resulting solution develops into a powerful electrolyte that can conduct electricity. Aluminum acetate dissociates and ionizes in water, which contributes to its function as a powerful electrolyte in aqueous solution and facilitates a variety of chemical and electrochemical reactions.

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Select all that apply.

Which statements concerning this diagram are correct?



X = -ΔH
X = ΔH
Z = A.E.

Answers

Correct answer is X = ΔH

Reason:
1) The graph of enthalpy Vs reaction coordinate  suggest the reaction is endothermic in nature. For endothermic reaction, energy if product is more than that of reactant. Hence,  option 1 i.e. X = -ΔH cannot be correct.
2) Since the reaction is endothermic in nature, energy if product is more than that of reactant. Hence,  option 2 i.e. X = ΔH is correct.
3) Activation energy is energy difference between Reactant (A) and transition state (B). However, as per option C, activation energy (A.E.) is energy difference between product (C) and transition state (B), which is incorrect. 

Answer:

Correct answer is X = ΔH

Explanation:

What is the name of the hybrid orbitals used by sulfur in scl2?

Answers

The name of the hybrid orbital used  by sulfur  in SCl2 is called

      SP^3

This is  because SCl2 has  two single bonds and two pairs of lone electrons on the central  sulfur atom. This is well shown when one draw the Lewis structure of SCl2. The electron geometry reveals that there are four electron pair  which implies that the hybridization of SCl2 is sp^3.
Final answer:

The hybrid orbitals used by sulfur in SCl2 are sp3. These are formed due to bonding with two chlorine atoms, and the presence of a lone pair.

Explanation:

The hybrid orbitals used by sulfur in SCl2 are sp3 hybrid orbitals. In SCl2, sulfur uses three of its valence electrons to form sigma bonds with two chlorine atoms and the remaining two are used to form a lone pair. Hence, we have total 4, i.e., the hybridization of S in SCl2 is sp3.

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What volume of 0.182 m na3po4 solution is necessary to completely react with 90.7 ml of 0.103 m cucl2?

Answers

Answer is: 34.2 mL sodium phosphate solution is necessary to completely react.
Chemical reaction: 2Na₃PO₄ + 3CuCl₂ → 6NaCl + Cu₃(PO₄)₂.
n(CuCl₂) = c(CuCl₂) · V(CuCl₂).
n(CuCl₂) = 0.103 M · 0.0907 L.
n(CuCl₂) = 0.00934 mol.
From chemical reaction: n(CuCl₂) : n(Na₃PO₄) = 3 : 2.
n(Na₃PO₄) = 2 · 0.00934 mol ÷ 3.
n(Na₃PO₄) = 0.00622 mol.
V(Na₃PO₄) = n(Na₃PO₄) ÷ c(Na₃PO₄).
V(Na₃PO₄) = 0.00622 mol ÷ 0.182 M.
V(Na₃PO₄) = 0.0342 L · 1000 mL/L = 34.2 mL.
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