Answers
18 people living in an apartment have a pet.
So percentage of people living in an apartment who have a pet = [tex] \frac{18}{54}*100=33 [/tex]%
Total number of people living in a house = 43 + 24 = 67
43 people living in a house have a pet.
So percentage of people living in a house who have a pet = [tex] \frac{43}{67}*100=64 [/tex]%
So answer in first blank is 33% and answer in second blank is 64%.
Related Questions
The dimensions of an office conference room are 10 feet by 18 feet. If the conference room blueprint dimensions are 5 centimeters by 9 centimeters, what is the scale of the blueprint?
A. 1 centimeter = 9 feet
B. 1 centimeter = 2 feet
C. 1 centimeter = 5 feet
D. 1 centimeter = 10 feet
Answers
mrs. west is 14 years younger than her aunt. if mrs. west’s age in years is as much below 60 as her aunt’s age is over 40, how old is each?
Answers
Mrs. west is [tex]14[/tex] years younger than her aunt. if mrs. west’s age in years is as much below [tex]60[/tex] as her aunt’s age is over [tex]40[/tex], So, Mrs. West is [tex]43[/tex] years old, and her aunt is [tex]57[/tex] years old.
Let's represent Mrs. West's age as W and her aunt's age as A.
Given that Mrs. West is [tex]14[/tex] years younger than her aunt, we can write the equation:
[tex]W=A-14[/tex]
Also, it's given that Mrs. West's age is as much below [tex]60[/tex] as her aunt’s age is over [tex]40[/tex] . This can be represented as:
[tex]W=60-(A-40)[/tex]
Simplify the equation:
[tex]W=60-A+40\\W=100-A[/tex]
Now, we have two equations for [tex]W[/tex]:
[tex]W=A-14\\W=100-A[/tex]
Since both equations equal [tex]W[/tex], we can set them equal to each other:
[tex]A-14=100-A[/tex]
Now, solve for A:
[tex]A+A=100+14\\2A=114\\A=57[/tex]
Now, plug the value of [tex]A[/tex] into either equation to find [tex]W[/tex]:
[tex]W=57-14\\W=43[/tex]
So, Mrs. West is [tex]43[/tex] years old, and her aunt is [tex]57[/tex] years old.
COMPLETE QUESTION:
Mrs. west is [tex]14[/tex] years younger than her aunt. if mrs. west’s age in years is as much below [tex]60[/tex] as her aunt’s age is over [tex]40[/tex], how old is each?
solve the inequality -×/2 <4
Answers
x > -8
_____
Multiplying or dividing by a negative number causes the direction of the relationship to change.
A jar of crunchy peanut butter contains 1.35 kg of peanut butter. if you use 8.0 % of the peanut butter for a sandwich, how many ounces of peanut butter did you take out of the container?
Answers
-The jar of crunchy peanut butter contains 1.35 kilograms of peanut butter.
-You use 8.0 % of the peanut butter.
2. You must convert 1.35 kilograms to ounces, as below:
1 kilogram=35.2739 ounces
=(1.35 kilogram)(35.2739 ounces/1 kilogram)
=1.35x35.2739 ounces
=47.61 ounces
3. Then, you have:
47.61 ounces-----100%
x-----8%
8%/100=0.08
100%/100=1
x=(0.08x47.61 ounces)/1
x=3.80 ounces
How many ounces of peanut butter did you take out of the container?
The answer is: 3.80 ounces
Experts/ace/geniuses
Answers
What is the sum of 4.2 × 105 and 5.3 × 10^5?
A.)95 × 10^5
B.)95 × 10^10
C.)9.5 × 10^5
D.)9.5 × 10^10
Answers
441 + 530000
530441
-----------
If your problem is (4.2*10^5)+(5.3*10^5), it would be
420000 + 530000
950000
Answer:
Option C.
Step-by-step explanation:
The two expressions are [tex]4.2\times 10^{5}[/tex] and [tex]5.3\times 10^{5}[/tex]
We have to find the total of these two terms.
[tex](4.2\times 10^{5}[/tex] + [tex]5.3\times 10^{5})[/tex]
Now we take out [tex]10^{5}[/tex] as a common term.
[tex]10^{5}(4.2+5.3)[/tex]
= [tex]9.5\times 10^{5}[/tex]
Therefore, Option C. will be the answer.
Find all integer solutions to the pair of congruences (if any) x ≡ 17 (mod 23) 70x ≡ 3 (mod 93).
Answers
[tex]70x\equiv3\pmod{93}\implies\begin{cases}70x\equiv3\equiv0\pmod3\\70x\equiv3\pmod{31}\end{cases}[/tex]
so in fact we're dealing with the system
[tex]\begin{cases}x\equiv17\pmod{23}\\70x\equiv0\pmod3\\70x\equiv3\pmod{31}\end{cases}[/tex]
Now, 3, 23, and 31 are relatively prime, so we can use the Chinese remainder theorem. But before we do that, we need to rework and ultimately eliminate the coefficients of [tex]x[/tex].
From the second equivalence, it follows immediately [tex]x[/tex] is some multiple of 3; this is because [tex]70x[/tex] is divisible by 3, but 3 doesn't divide 70, so it must divide [tex]x[/tex].
For the third equivalence, we can write [tex]70x=62x+8[/tex]. Then modulo 31, we have that [tex]62x\equiv0[/tex], which leaves us with [tex]8x\equiv3\pmod{31}[/tex]. We want a congruence of the form [tex]x\equiv\cdots[/tex], and to get that we can multiply [tex]8x[/tex] and 3 by the inverse of 8 modulo 31.
To find this inverse, we solve for [tex]y[/tex] in the relation
[tex]8y\equiv1\pmod{31}[/tex]
by using the Euclidean algorithm, or making just making the observation that [tex]8\times4\equiv32\equiv1\pmod{31}[/tex], so [tex]8^{-1}\equiv4\pmod{31}[/tex]. Distributing 4 across the third equivalence in our system gives [tex]x\equiv4\pmod{31}[/tex].
So to recap, we now have
[tex]\begin{cases}x\equiv17\pmod{23}\\x\equiv0\pmod3\\x\equiv12\pmod{31}\end{cases}[/tex]
and we're ready to use the CRT.
As a starting point, let's take
[tex]x=(17)+(23)+(23)=63[/tex]
It's clear that taken modulo 23, the latter two terms vanish and we have a remainder of 17, as desired. 63 is already a multiple of 3, but just to avoid doing more work later, let's multiply each term by 3 anyway to keep getting a remainder of 0:
[tex]x=(17\times3)+(23\times3)+(23\times3)=146[/tex]
Now multiply the first two terms by 31 to make sure they vanish when taken modulo 31. Meanwhile, [tex]23\times3\equiv69\equiv7\pmod{31}[/tex], but we want to get 12, so we would multiply this term by the inverse of 7 mod 31, and again by 12.
We can make a quick observation that [tex]7\times9=63=31\times2+1[/tex], so [tex]7^{-1}\equiv9\pmod{31}[/tex]. Alternatively, you can use the Euclidean algorithm to find this inverse. Either way, we get
[tex]x=(17\times3\times31)+(23\times3\times31)+(23\times3\times9\times12)=11,172[/tex]
So we're told that
[tex]x=11,172+(23\times3\times31)k=11,172+2139k[/tex]
is our solution set, where [tex]k\in\mathbb Z[/tex]. We can "simplify" this slightly by finding the least positive residue modulo the product of our moduli, which would be
[tex]11,172\equiv477\pmod{2139}[/tex]
so we end up with
[tex]x=477+2139k[/tex]
for integers [tex]k[/tex].
The center of a circle is at the origin. An endpoint of a diameter of the circle is at (-3, -4). How long is the diameter of the circle? 5, 10, or 25?
Answers
The diameter of the circle is 10.
In which graph does y vary directly as x? It’s not C, I got it wrong.
Answers
What is the value of log0.5^16? a.–4.00 b.–0.25 c.1.51 d.2.41
Answers
Answer:
The correct option is a.
Step-by-step explanation:
The given expression is,
[tex]log(0.5)^{16}[/tex]
Use property of logarithm
[tex]loga^b=bloga[/tex]
[tex]log(0.5)^{16}=16\times log(0.5)[/tex]
The value of log(0.5) is -0.30103.
[tex]log(0.5)^{16}=16\times -0.30103[/tex]
[tex]log(0.5)^{16}=-4.81648[/tex]
The value of given expression is -4.81648.
If the final answer appromatted to preceding integer, then the correct option is -4.00.
tossing a number cube numbered from 1 to 6 and getting an odd number that is less than or equal to 3
Answers
2/6=1/3
Find the area under the curve y = 5/x3 from x = 1 to x = t. evaluate the area under the curve for t = 10, t = 100, and t = 1000. t = 10 t = 100 t = 1000 find the total area under this curve for x ≥ 1.
Answers
The area under the curve from x = 1 to x = t is [tex]-\frac{5}{2} (\frac{1}{t^2} -1)[/tex].
For, t = 10, 100, and 1000, the areas are 2.475, 2.49975, and 2.4999975 respectively.
The total area is 2.5.
Given that:
[tex]y=\frac{5}{x^3}[/tex]
In order to find the area integrate it with limits from x = 1 to x = t.
[tex]A=\int\limits^t_1 {\frac{5}{x^3} } \, dx[/tex]
This can be written as:
[tex]A=\int\limits^t_1 {5x^{-3} } \, dx[/tex]
[tex]=5[\frac{x^{-2}}{-2} ]_1^t[/tex]
[tex]=-\frac{5}{2} (t^{-2}-1^{-2})[/tex]
So, the area is [tex]A=-\frac{5}{2} (\frac{1}{t^2} -1)[/tex].
When t = 10,
[tex]A=-\frac{5}{2} (\frac{1}{10^2} -1)[/tex]
[tex]=2.475[/tex]
When t = 100,
[tex]A=-\frac{5}{2} (\frac{1}{100^2} -1)[/tex]
[tex]=2.49975[/tex]
When t = 1000,
[tex]A=-\frac{5}{2} (\frac{1}{1000^2} -1)[/tex]
[tex]=-2.4999975[/tex]
To find the total area, the value of t = ∞.
Now, ∞⁻² is always 0, since any negative number to the power of infinity is 0.
So, the area is:
[tex]A=-\frac{5}{2} (0-1)[/tex]
[tex]A=2.5[/tex]
Hence, the total area is 2.5.
Learn more about Area using Integrals here :
https://brainly.com/question/34160198
#SPJ4
Indicate whether each of the following fractions is proper or improper. a. 4⁄16 b. 75⁄70 c. 2⁄15 d. 6⁄6
Answers
An improper fraction is a fraction where the numerator is larger than or equal to the denominator.
a. 4/16
The denominator is 16. The numerator is 4. The denominator is larger than the numerator; thus, this is a proper fraction.
b. 75/70
The denominator is 70. The numerator is 75. The numerator is larger than the denominator; thus, this is an improper fraction.
c. 2/15
The denominator is 15. The numerator is 2. The denominator is larger than the numerator; thus, this is a proper fraction.
d. 6/6
The denominator is 6. The numerator is 6. The numerator is equal to the denominator; thus, this is an improper fraction.
what is -10+2 because this is really confusing to me.
Answers
Hope this helps!
Let me know if i'm wrong.
a coin is tossed twice what is the probability of the coin landing heads up both times
Answers
The successful result is 1/2 * 1/2 = 1/4.
You can make a table to show this.
H H
T H
H T
T T
1/4 ways gives 2 heads. <<<< answer
What is the y-intercept of the line that has a slope of -1/2 and passes through the point (2, 3)?
Answers
y - 3 = -1/2(x) + 1
y = -1/2(x) + 4
y intercept is 4
answer
y intercept (0,4)
Which of the following describes the roots of the polynomial function f(x)=(x-3)^4(x-6)^2? –3 with multiplicity 2 and 6 with multiplicity 4 –3 with multiplicity 4 and 6 with multiplicity 2 3 with multiplicity 2 and –6 with multiplicity 4 3 with multiplicity 4 and –6 with multiplicity 2
Answers
For example, this term is used to refer to the number of times a certain polynomial has a root at a certain point.
For this polynomial we have:
f (x) = (x-3) ^ 4 (x-6) ^ 2
3 with multiplicity 4 and 6 with multiplicity 2
Answer:
3 with multiplicity 4 and 6 with multiplicity 2
Answer:
3 with multiplicity 4 and -6 with multiplicity 2
if 5 lemons cost £1 and a bag of 4 oranges cost £1.80, how much more does one orange cost than the lemon?
Answers
the average adult human has approximately 2.5 x 10 ^ 13 red blood cells + 7 x 10 ^ 9 white blood cells about how many times as great is the number of red blood cells than the number of white blood cells
Answers
N = (red blood cells) / (white blood cells)
Substituting values we have:
N = (2.5 * 10 ^ 13) / (7 * 10 ^ 9)
N = 3571.428571
Nearest whole number:
N = 3571
Answer:
The number of red blood cells is 3571 as great as the number of white blood cells
Jim Abbott purchased a $60,000 recreational vehicle (RV) with a 40 percent markup on selling price. a. What was the amount of the dealer’s markup? Markup amount $ b. What was the dealer’s original cost? Original cost $
Answers
Hope this helped!
Answer:
24,000 dealer paid
mark up : 36,000
Step-by-step explanation:
60,000 * 0.40= 24,000
60,000-24,000= 36000
Which of the following functions is graphed below?
Answers
observing the graph of the problem, it is evident that the solution is option D, since the graph of the parabola presents a domain for x <4 and the line presents a domain for x> = 4 and the only option with these two conditions is option D
using a graph tool
I proceed to verify
see the attached figure
the answer is the option D
The graph consists of two parts: left part (with sign < or ≤) - parabola and right part (with sign > or ≥) - straight line.
Determine signs:
From the diagram you can see that the right endpoint (4,19) of parabola is not included. This means that x cannot be equal to 4 at this part of graph and the sign should be <.
Also you can see that the left endpoint (4,8) of line is included. This means that x=4 belongs to the right part and the sign should be ≥.
Using previous conclusions, you can state that correct choice is D.
What is greater than 1 kg
Answers
1.
Find the Compound Amount.
Round to the nearest cent.
Amount = $980
Rate = 8%
Compounded = Quarterly
Time (Years) = 5
2.
Find the Interest Earned.
Round to the nearest cent.
Amount = $980
Rate = 8%
Compounded = Quarterly
Time (Years) = 5
Answers
Principal Amount = P = $980
Interest rate = r = 8% = 0.08
Compounding periods = n = 4
Time = t = 5 years
Formula to be used for finding compounding amount:
[tex]A=P (1+ \frac{r}{n} )^{nt} [/tex]
Using the values in the formula, we get:
[tex]A=980 (1+ \frac{0.08}{4} )^{5*4} =1456.23[/tex]
Therefore, the amount compounded over a period of 5 years will be $1456.23
2)
Principal Amount = $980
Compounded Amount = $1456.23
Interest Earned = Compounded Amount - Principal Amount
Interest Earned = 1456.23 - 980 = $ 476.23
Therefore, $476.23 interest will be earned over a period of 5 years.
0.698 to the bestest hundreth
Answers
Is the answer ok.
The 9 is in the hundredths place
Since 9 is greater than 5 we will round up.
0.70 is your answer
what are the slope and why intercept shown on the graph below
Answers
Let's start by finding the slope of the line. You can calculate the slope by dividing the change in y-values by the change in x-values using the following formula:
[tex] \frac{ y_{1}- y_{2} }{ x_{1} - x_{2} } [/tex]
The plotted coordinates are (0, 5) and (4, -5); let's plug those into the formula:
[tex] \frac{5(-5)}{0-4} [/tex]
Simplify:
[tex] \frac{5+5}{-4} [/tex]
[tex] \frac{10}{-4} [/tex]
[tex] \frac{-5}{2} [/tex]
The slope is [tex] \frac{-5}{2} [/tex].
Now, the y-intercept is where the line intersects the y-axis, or when x equals 0. x equals 0 when y equals 5, so the y-intercept is 5.
I hope this helps!
y2 = -5
y1 = 5
x2 = 4
x1 = 0
Let's subtract. -5 - 5 is -10. 4 - 0 is 4. -10/4 is -2 1/2 in simplest form or -5/2 as a mixed number. We found the slope. The y-intercept is where the line crosses, where the x-axis is 0. In this case, we can see by the point given out that the slope intercept is 5. There. The slope is -5/2 and the slope-intercept is 5. The answer is B.
2/3 of the product of 3/8 and 16
Answers
To solve this problem, we should first find the product of 3/8 and 16 and multiply the solution by 2/3.
Let's find the product first.
3/8 × 16 = 48/8
Simplify.
48/8 = 48 ÷ 8 = 6
Now, we find 2/3 of 6.
6 ÷ 3 × 2 = 2 × 2 = 4
So, your answer is 4.
Hope this helps!
Estimate by division ..70/9.24
Answers
hope this helped :)
alisa202
Here we have to divide 70 by 9.24.
we can first covert the decimal 9.24 into fraction, shifting the decimal two units to the right and dividing by 100, we have
9.24 = 924/100
Now let us divide 70 by 924/100
in division of fraction we take reciprocal of second fraction and multiply it with first.
reciprocal of 924/100 is 100/924.
multiplying 70* 100/924, we have
[tex] 70 * \frac{100}{924} [/tex]
[tex] = \frac{7000}{924} [/tex]
converting into decimal we have
[tex] \frac{7000}{924} = 7.5757..... [/tex]
Experts/ace/geniuses
Answers
a puppy weighs 9/10 pound. it's mother weighs 8 times as much. how much does the mother weigh?
Answers
G let z be a random variable with a standard normal distribution. find the indicated probability. p(z ≤ −0.27)
Answers
The probability P(Z <= -0.27) in a standard normal distribution is determined by finding the corresponding right-tail probability of Z = 0.27 and subtracting it from 1, reflecting the distribution's symmetry.
To find the probability P(Z \<= -0.27), we use the properties of the standard normal distribution, which is symmetric about zero. The probability of Z scoring below -0.27 is equal to the probability of Z scoring above 0.27 due to this symmetry. Looking up the corresponding value for Z = 0.27 in a standard normal table, or using a calculator, we would find the right-tail probability. To get our desired left-tail probability for Z = -0.27, we subtract this from 1. For example, if the right-tail probability for Z = 0.27 was 0.3936, then P(Z \<= -0.27) would be 1 - 0.3936 = 0.6064.