Ideal meters problem. What internal resistance is ideal for a voltmeter? What internal resistance is ideal for an ammeter?

Explanation:

Galileo observed that Venus presented phases (such as those of the moon) together with a variation in size; observations that are only compatible with the fact that Venus rotates around the Sun and not around Earth.  

This is because Venus presented its smaller size when it was in full phase and the largest size when it was in the new one, when it is between the Sun and the Earth.  

In other words: When Venus is in its full phase it is not possible to observe it from the Earth because always in this phase, Venus, the Sun and the Earth are in conjunction (or aligned).  This means the Sun is between Venus and Earth, in the orbit that both planets describe around this star.

Therefore, from the Earth, the Sun covers Venus.

This fact along with other discoveries were presented by Galileo to the Catholic Church (which supported the geocentric theory at that time) as a proof that completely refuted Ptolemy's geocentric system and affirmed Copernicus' heliocentric theory.

Answer: Ions are formed when atoms from group 1/3/2/17 gains or loses a small number of electrons.

Explanation: Let's take Na(Sodium) and Cl(chlorine), their atomic number are consecutively 11 and 17. Sodium's closest noble element is Neon(10) and Cl's is Argon(18). Now all atoms want to gain stability like the noble gases, they want their outer shell to be filled so that they don't have to wander around with other atoms. So to have stability Na will lose one of its electrons and Cl will take in one. Thus they consecutively will become plus charged and minus charged as the balance between their proton and electron numbers are gone

An ion is formed when a neutral atom gains or loses an electron.

A neutral atom has the same number of protons (+) and electrons (-).

If it gains another electron, it has too many negative charges, so it's a negative ion.

If it loses an electron, it has too many positive charges, so it's a positive ion.

=================================

What if it gains or loses a proton ?

That's a great question.  I'm glad you asked.

Under normal circumstances, this hardly ever happens.  But if it did ...

- If it somehow lost a proton from its nucleus, first of all, it would change the number of protons in the nucleus, so the atom would immediately become an atom of a different element.

- If it didn't lose an electron at the same time, then it would have too many electrons for the number of protons in the nucleus, so it would be a negative ion of the new element.

-  If it somehow added a proton to its nucleus, it would change the number of protons in the nucleus, so the atom would  become an atom of a different element.  If it didn't add another  electron at the same time, then it would have too few electrons for the number of protons in the nucleus, so it would be a  positive ion of the new element.

Answer: Option (A) is the correct answer.

Explanation:

A diamagnetic material does not contain any unpaired electrons and therefore, in a magnetic field direction they will always flow in the direction opposite to the magnetic field.

Hence, a diamagnetic material will always repel the magnetic field whenever it comes in contact with that.

Thus, we can conclude that when the other end of the cylinder is brought near the North pole of the magnet then the other end of the cylinder will be repelled by the magnet.

Answer: 624.98 mL

Explanation:

According to the Ideal Gas Law:

[tex]\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}[/tex] (1)

Where:

[tex]P_{1}=2.4 atm[/tex] is the pressure of the bubble under the surface

[tex]V_{1}=250 mL[/tex] is the volume of the bubble under the surface

[tex]T_{1}=15\°C + 273.15=288.15 K[/tex] is the temperature of the bubble under the surface

[tex]P_{2}=1 atm[/tex] is the pressure of the bubble at the surface

[tex]V_{2}[/tex] is the volume of the bubble at the surface

[tex]T_{2}=27\°C + 273.15=300.15 K[/tex] is the temperature of the bubble at the surface

So, we have to find [tex]V_{2}[/tex]:

[tex]V_{2}=\frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}}[/tex] (2)

[tex]V_{2}=\frac{(2.4 atm)(250 mL)(300.15 K)}{(288.15 K)(1 atm)}[/tex] (3)

Finally:

[tex]V_{2}=624.98 mL[/tex]  This is the volume of the bubble when it reaches the surface

The volume of the bubble when it reaches the surface is about 625 mL

The basic formula of pressure that needs to be recalled is:

Pressure = Force / Cross-sectional Area

or symbolized:

[tex]\large {\boxed {P = F \div A} }[/tex]

P = Pressure (Pa)

F = Force (N)

A = Cross-sectional Area (m²)

Let us now tackle the problem !

In this problem , we will use Ideal Gas Law as follows:

Given:

Initial Volume = V₁ = 250 mL

Initial Pressure = P₁ = 2.4 atm

Initial Temperature = T₁ = 15 + 273 = 288 K

Final Pressure = P₂ = 1.0 atm

Final Temperature = T₂ = 27 + 273 = 300 K

Unknown:

Final Volume = V₂ = ?

Solution:

[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}[/tex]

[tex]\frac{2.4(250)}{288} = \frac{1.0V_2}{300}[/tex]

[tex]\frac{600}{288} = \frac{1.0V_2}{300}[/tex]

[tex]\frac{25}{12} = \frac{V_2}{300}[/tex]

[tex]V_2 = \frac{25}{12} \times 300[/tex]

[tex]V_2 = 625 \texttt{ mL}[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Physics

Chapter: Pressure

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant , Liquid , Pressure

Explanation:

Force = Mass × Acceleration

1.6 = 2.2 × a

a = 1.6/2.2

= 0.73 m/s^2

Note that the acceleration will be negative.

Answer: The acceleration of the book is [tex]0.73m/s^2[/tex]  

Explanation:

Force is defined as the push or pull on an object with some mass that causes change in its velocity.

It is also defined as the mass multiplied by the acceleration of the object.

Mathematically,

[tex]F=ma[/tex]

where,

F = force exerted on the book = 1.6 N

m = mass of the book = 2.2 kg

a = acceleration of the book = ?

Putting values in above equation, we get:

[tex]1.6kg.m/s^2=2.2\times a\\\\a=\frac{1.6}{2.2}=0.73m/s^2[/tex]

Hence, the acceleration of the book is [tex]0.73m/s^2[/tex]

Answer:

Explanation:

A) mass of displaced water = loss of mass in water = 63 - .0975 = 62.9025 kg

B) her volume = volume of displaced water

= mass of displaced water / density of water = 62.9025 / 1000 m³.

= 62.9025 x 10⁻³ m³

C) her average density = her mass / her volume = 63 / 62.9025 x 10⁻³

= 1.00155 x 10³ kg / m³

D) lung capacity = 1.75 L = 1.75 x 10⁻³ m³

buoyant force created by air in the lungs = 1.75 x 10⁻³ ( 1000- 1.29 ) =  1.74 kg

As it is more than 0.0975 kg , the apparent weight  in water so woman will float in water .

A. Mass of Water Displaced: ≈ 62.99 kg

B. Volume of Woman: ≈ 0.06299 m³

C. Average Density: ≈ 1000 kg/m³

D. Yes, she can float with lungs filled with air.

We can solve this problem using the concepts of buoyancy and density. Here's how to find the answers:

A. Mass of Water Displaced:

1. Buoyant Force: The difference between her mass in air and apparent mass underwater represents the buoyant force exerted by the water.

2. Buoyant Force = Weight in Air - Apparent Weight = (63 kg * 9.81 m/s²) - (0.0975 kg * 9.81 m/s²) (We can multiply mass by gravitational acceleration to convert it to weight, but for this problem, it cancels out)

3. Buoyant Force ≈ 618.27 N (Newtons)

Since buoyant force equals the weight of the water displaced, the mass of water displaced is:

Mass of Displaced Water = Buoyant Force / Gravitational Acceleration

Mass of Displaced Water ≈ 618.27 N / 9.81 m/s² ≈ 62.99 kg (rounded to two decimal places)

B. Volume of Woman:

1. Density of Water: We can assume the density of water to be 1000 kg/m³ (a standard value).

2. Volume of Displaced Water = Mass of Displaced Water / Density of Water

3. Volume ≈ 62.99 kg / 1000 kg/m³ ≈ 0.06299 m³ (rounded to five decimal places)

C. Average Density of Woman:

1. Woman's Volume (from part B): 0.06299 m³

2. Woman's Mass: 63 kg

3. Density = Mass / Volume

4. Average Density ≈ 63 kg / 0.06299 m³ ≈ 1000 kg/m³ (rounded to three decimal places)

D. Ability to Float:

1. Density of Air: 1.29 kg/m³

2. Volume of Air in Lungs: 1.75 L = 0.00175 m³ (convert liters to cubic meters)

3. When lungs are filled with air, her effective volume increases by the volume of air in her lungs.

4. Effective Volume with Air: 0.06299 m³ (woman's volume) + 0.00175 m³ (air in lungs) ≈ 0.06474 m³

5. When considering air in her lungs, her effective density becomes:

Effective Density = Mass / Effective Volume

Effective Density ≈ 63 kg / 0.06474 m³ ≈ 973.3 kg/m³ (rounded to one decimal place)

Since her effective density (with air in lungs) is lower than the density of water (1000 kg/m³), she would be able to float with her lungs filled with air.

Answers:

A. Mass of Water Displaced: ≈ 62.99 kg

B. Volume of Woman: ≈ 0.06299 m³

C. Average Density: ≈ 1000 kg/m³

D. Yes, she can float with lungs filled with air.

Answer:

0.6375 m/s

Explanation:

Let x be the distance of the man from the building

from the figure attached

initially the value of x=12

Given:

[tex]\frac{dx}{dt}=-1.7m/s[/tex]

where the negative sign depicts that the distance of the man from the building is decreasing.

Now, Let The length of the shadow be = y

we have to calculate [tex]\frac{dy}{dt}[/tex] when x=4

from the similar triangles

we have,

[tex]\frac{2}{12-x}=\frac{y}{12}[/tex]    

or

[tex]y=\frac{24}{12-x}[/tex]

Differentiating with respect to time 't' we get

[tex]\frac{dy}{dt}=-\frac{24}{12-x}^2\frac{-dx}{dt}[/tex]

or

[tex]\frac{dy}{dt}=\frac{24}{12-x}^2\frac{dx}{dt}[/tex]

Now for x = 4, and [tex]\frac{dx}{dt}=-1.7m/s[/tex]  we have,

[tex]\frac{dy}{dt}=\frac{24}{12-4}^2\times (-1.7)[/tex]

or

[tex]\frac{dy}{dt}=-0.6375m/s[/tex]

here, the negative sign depicts the decrease in length and in the question it is asked the decreasing rate  thus, the answer is 0.6375m/s

Answer:

Explanation:

tube:

f=v/4L = 343/(4*1.2)= 71.4583Hz tube's fundamental frequency  

wire:  

f=v/2L -> v=2Lf

v= 2*0.323*71.4583= 46.162m/s  

ρ= 0.0095/0.323= 0.02941kg/m  

v=√(T/ρ) -> T=v^2*ρ

T= 46.162^2*0.02941= 62.67[N] Tension of wire.

Answer:

Charge, [tex]q=1.72\times 10^{-16}\ C[/tex]    

Explanation:

It is given that, two tiny spheres have the same mass and carry charges of the same magnitude. Let charge on both sphere is q.

Also, the gravitational force that each sphere exerts on the other is balanced by the electric force i.e.

[tex]F_g=F_e[/tex]

[tex]G\dfrac{m^2}{r^2}=k\dfrac{q^2}{r^2}[/tex]

[tex]q=\sqrt{\dfrac{Gm^2}{k}}[/tex]

Where

G is the universal gravitational constant

k is the electrostatic constant

[tex]q=\sqrt{\dfrac{6.67\times 10^{-11}\ Nm^2/kg^2\times (2\times 10^{-6}\ kg)^2}{9\times 10^9\ Nm^2/C^2}}[/tex]

[tex]q=1.72\times 10^{-16}\ C[/tex]

So, the charge on both the spheres is [tex]1.72\times 10^{-16}\ C[/tex]. Hence, this is the required solution.

Answer:

[tex] q =5.439\times 10^{-17}C[/tex]

Explanation:

Given:

Mass of the tiny sphere, M = 2.0 × 10⁻⁶ kg

also masses are equal i.e M₁ = M₂

Now,

the gravitational force between the two masses M₁ and M₂ is given as:

[tex]F_G = \frac{GM_1M_2}{r^2}[/tex]

where,

G is the gravitational force constant = 6.67 x 10⁻¹¹ m³/kg.s²

r = center to center distance between the masses

also,

Electric force between the charges is given as

[tex]F_e=\frac{kq_1q_2}{r^2}[/tex]

where,

q₁ and q₂ are the charges and also it is given that q₁=q₂=q

k is the coulomb's law constant =  9.0 x 10⁹ N.m²/C²

since it is mentioned that [tex]F_G = F_e[/tex]

we have

[tex]\frac{kq_1q_2}{r^2} = \frac{GM_1M_2}{r^2}[/tex]

or

[tex]{9\times 10^9\times q^2} ={6.67\times 10^{-11}(2.0\times 10^{-6})^2}[/tex]

or

[tex] q =5.439\times 10^{-17}C[/tex]

Answer: 1.024 N

Explanation:

Step 1:

Using Coulomb's law: F=kQ1Q2/d^2

We can rearrange the terms to get :

kQ1Q2=Fxr^2

Substituting: kQ1Q2=0.0224N x (1.63m)^2

Thus kQ1Q2=0.0595

We know that this value will not change when the balls are brought closer together.

Step 2:

Change from cm to m : 1cm=0.01m

24cm=0.24 m

Substitute into the new distance and the calculated value for kQ1Q2 into the coulomb law formula to calculate the new force

F=kQ1Q2/d^2=0.059/(0.24)^2

F=1.024N

Final answer:

The force between the ping-pong balls will be approximately 1.665 N when they are brought closer to a separation of 24.0 cm.

Explanation:

The force between two charged objects can be calculated using Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

In this case, the initial force between the ping-pong balls is 0.0224 N when they are separated by 1.63 m. To find the force when they are brought closer to a separation of 24.0 cm, we can use the fact that the force is inversely proportional to the square of the distance.

We can set up a proportion:

(0.0224 N) / (1.63 m)²= (x) / (0.24 m)²

Solving for x, we find that the force will be approximately 1.665 N.

Answer:

The speed on boat in still water is  [tex]56 \frac{km}{h}[/tex]  and the rate of the current is   [tex]10 \frac{km}{h}[/tex]

Explanation:

Since speed , [tex]v= \frac{Distance\, traveled(D)}{Time\, taken(t)}[/tex]

Therefore speed of motor boat while traveling upstream is

[tex]v_{upstream}=\frac{92}{2}\frac{km}{h}=46\frac{km}{h}[/tex]

and  speed of motor boat while traveling downstream is

[tex]v_{downstream}=\frac{132}{2}\frac{km}{h}=66\frac{km}{h}[/tex]

Let speed of boat in still water be [tex]v_b[/tex] and rate of current be [tex]v_w[/tex]

Therefore [tex]v_{upstream}=v_b-v_w=46\frac{km}{h}[/tex]   ----(A)

and  [tex]v_{downstream}=v_b+v_w=66\frac{km}{h}[/tex]     ------(B)

Adding equation (A) and (B)  we get

[tex]2v_b= (46+66) \frac{km}{h}=112 \frac{km}{h}[/tex]

=>[tex]v_b= 56 \frac{km}{h}[/tex]   ------(C)

Substituting the value of  [tex]v_b[/tex] in equation (A) we get

[tex]v_w= 10 \frac{km}{h}[/tex]

Thus the speed on boat in still water is  [tex]56 \frac{km}{h}[/tex]  and the rate of the current is   [tex]10 \frac{km}{h}[/tex]

Answer:

CONCAVE

Explanation:

Convex lenses bend light rays so they come together at focus. Concave lenses spread light rays apart so they do not come together at a focus.

hope this answer help u!!

Answer:

Concave lens

Explanation:

Concave lenses are thicker at ends and thinner at middle. When parallel rays of light pass through the concave lens, they are refracted and spread out so that they appear to come from a common point known as principle focus. Due to this reason, Concave lens also called as diverging lens.

Answer:

28.5 deg

Explanation:

The resistance of a nichrome wire at 0.0 ∘c if its resistance is 120.00 ω at 11.5 ∘c is 28.5 deg.

R = R0[1+ alpha(T-T0)]

R(28.5)=0.2000[1-0.005(28.5-0)]

The resistance of a nichrome is 28.5 deg.

The resistance of a nichrome wire at 0.0 ∘c if its resistance is 120.00 ω at 11.5 ∘c is 28.5 deg.

R = R0[1+ alpha(T-T0)]

R(28.5) = 0.2000[1-0.005(28.5-0)]

Nichrome is continuously silvery-grey in shade, is corrosion-resistant, has an excessive melting thing of approximately 1, four hundred °C (2,550 °F), and has an electrical resistivity of around 112 microOhm-cm, that's around 66 times better resistivity than copper of one.678 microOhm-cm.

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Answer:

15.8 cm

Explanation:

In 20.8 seconds, the number of vibrations = 42

In 1 second, the number of vibrations = 42 / 20.8 = 2.019

Frequency is defined as the number of vibrations in one second.

f = 2.019 Hz

Crest travel 371 cm in 11.6 s

v = 3.71 / 11.6 = 0.319 m / s

Use

v = f x λ

λ = v / f = 0.319 / 2.019 = 0.158 m = 15.8 cm

Answer:

[tex]p_2 = 1.76 atm[/tex]

Explanation:

given data:

v_1 = 2.37 L

v_2 = 1.68 L

p_1 =1.15 atm

p_2 = ?

t_1 = 280 K

t_2 = 304 K

from Gas Law Equation

, WE HAVE

[tex]\frac{p_1 v_1}{t_1} =\frac{p_2 v_2}{t_2}[/tex]

Putting the values

[tex]\frac{1.15*2.37}{280}  =\frac{p_2 *1.68}{304}[/tex]

[tex]9.733*10^{-3} = \frac{p_2 *1.68}{304}[/tex]

[tex]9.733*10^{-3}*304 = p_2*1.68[/tex]

[tex]\frac{9.733*10^{-3}*304}{1.68} =p_2[/tex]

[tex]p_2= 1.76 atm[/tex]

Answer:

u = 4.6 m/s

h = 8.01 m

Explanation:

Given:

Mass of the tennis ball, m = 44.0 g

Mass of the basket ball, M = 594 g

Height of fall, h = 1.08m

Now,

we have

[tex]u^2-u'^2 = 2as[/tex]

where, s = distance = h

a = acceleration

u = final speed before the collision

u' = initial speed

since it is free fall case

thus,

a = g = acceleration due to gravity

u' = 0

thus we have

[tex]u^2-0^2 = 2\times9.8\tiimes1.08[/tex]

or

[tex]u = \sqrt{21.168}[/tex]

or

u = 4.6 m/s

b) Now after the bounce, the ball moves with the same velocity

thus, v = v₂

thus,

final speed ([tex]v_f[/tex]) = v = 4.6 m/s

Then conservation of energy says  

[tex]\frac{1}{2}mu_1^2+\frac{1}{2}Mu_2^2 = \frac{1}{2}mv_1^2+\frac{1}{2}Mv_2^2[/tex]  

also

applying the concept of conservation of momentum

we have

mu₁ + Mu₂ = mv₁ + Mv₂

u₁ =velocity of the tennis ball before collision = -4.6 m/s  

u₂ = velocity of the basketball before collision= 4.6 m/s  

v₁ =  velocity of the tennis ball after collision  

v₂ = velocity of the basketball  after collision

substituting the values in the equation, we get

Now,

solving both the equations simultaneously we get

[tex]v = (\frac{2M}{m+M})u_1+(\frac{m-M}{m+M})u_2[/tex]

substituting the values in the above equation we get

[tex]v = (\frac{2\times594}{44+594})(-4.6)+(\frac{44-594}{44+594})4.6[/tex]

or

[tex]v = -8.565-3.965[/tex]

or

[tex]v = -12.53m/s[/tex]

here negative sign depicts the motion of the ball in the upward direction

now the kinetic energy of the tennis ball

[tex]K.E = \frac{1}{2}mv^2[/tex]

or

[tex]K.E = \frac{1}{2}44\times 10^{-3}kg\times 12.53^2[/tex]

or

K.E = 3.45 J

also at the height the K.E will be the potential energy of the tennis ball

thus,

3.45 J = mgh

or

3.45 = 44 × 10⁻³ × 9.8 × h

h = 8.01 m

The magnitude of the downward velocity with which the basketball reaches the ground is 4.51 m/s. The height to which the tennis ball rebounds after an elastic collision with the basketball can be found by solving for the velocity of the tennis ball after the collision and using the equation h = (v2')² / (2g).

To find the magnitude of the downward velocity with which the basketball reaches the ground, we can use the equation v = gt, where g is the acceleration due to gravity. Since both the basketball and tennis ball are released from rest and fall through the same distance, they will reach the ground at the same time. Therefore, the time it takes for the basketball to reach the ground is the same as the time it takes for the tennis ball to fall and bounce back up:

t = sqrt(2h/g)

where h is the distance the balls fall. We can substitute the given values into the equation to find the time:

t = sqrt(2 * 1.08m / 9.8m/s²) = 0.46 s

Therefore, the magnitude of the downward velocity with which the basketball reaches the ground is given by v = gt:

v = 9.8m/s² * 0.46s = 4.51 m/s

For part (b), to find the height to which the tennis ball rebounds after an elastic collision with the basketball, we can use the conservation of momentum and the conservation of kinetic energy. Since the collision is elastic, the total momentum and the total kinetic energy of the two balls before the collision are equal to the total momentum and total kinetic energy after the collision:

m1v1 + m2v2 = m1v1' + m2v2'

1/2m1v1² + 1/2m2v2² = 1/2m1v1'² + 1/2m2v2'²

We can substitute the given values into the equations and solve for v2', the velocity of the tennis ball after the collision:

0.044kg * 0m/s + 0.594kg * 4.51m/s = 0.044kg * v1' + 0.594kg * v2'

1/2 * 0.044kg * 0m/s² + 1/2 * 0.594kg * (4.51m/s)² = 1/2 * 0.044kg * v1'² + 1/2 * 0.594kg * v2'²

From these equations, we can solve for v2', the velocity of the tennis ball after the collision. The height to which the tennis ball rebounds can be found using the equation:

h = (v2')² / (2g)

We can substitute the calculated value of v2' into the equation to find the height:

h = (v2')² / (2 * 9.8m/s²)

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The equation is T = KPV

Using the initial information you have, solve for K:

300 = K(4)(4)

Simplify:

300 = K(16)

Divide both sides by 16

K = 300/16

K = 18.75

Now if pressure increases by 7%, the new pressure would be 4 x 1.07 = 4.28

Volume increases by 0.07, so the new volume would be 4 + 0.07 = 4.07

Now solve for t:

T = 18.75(4.28)(4.07)

T = 326.6175

Now subtract the new temperature from the original one:

326.6175 - 300 = 26.6175 increase ( Round answer as needed).

Answer:

Nuclear energy originates from the splitting of uranium atoms – a process called fission. This generates heat to produce steam, which is used by a turbine generator to generate electricity. Because nuclear power plants do not burn fuel, they do not produce greenhouse gas emissions.

Explanation:

Nuclear energy primarily comes from the process of nuclear fission, specifically the splitting of Uranium-235 atoms. This process releases immense energy which is utilized to generate power in nuclear power plants.

Nuclear energy, used feasible in power plants, comes primarily from the process of splitting atoms of Uranium-235, a process known as nuclear fission. In this process, a neutron collides with a Uranium atom, causing the atom to split and release more neutrons along with a large amount of energy. This energy, in the form of heat, is then used to produce steam which drives turbines, thereby generating electricity.

Thus, it's clear that the process of splitting large, complex atomic nuclei, particularly those of Uranium-235, not only induces a chain reaction (due to the release of more neutrons) but also provides us with a sophisticated method of generating power in the form of nuclear energy.

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a) we can answer the first part of this by recognizing the player rises 0.76m, reaches the apex of motion, and then falls back to the ground we can ask how

long it takes to fall 0.13 m from rest: dist = 1/2 gt^2 or t=sqrt[2d/g] t=0.175

s this is the time to fall from the top; it would take the same time to travel

upward the final 0.13 m, so the total time spent in the upper 0.15 m is 2x0.175

= 0.35s

b) there are a couple of ways of finding thetime it takes to travel the bottom 0.13m first way: we can use d=1/2gt^2 twice

to solve this problem the time it takes to fall the final 0.13 m is: time it

takes to fall 0.76 m - time it takes to fall 0.63 m t = sqrt[2d/g] = 0.399 s to

fall 0.76 m, and this equation yields it takes 0.359 s to fall 0.63 m, so it

takes 0.04 s to fall the final 0.13 m. The total time spent in the lower 0.13 m

is then twice this, or 0.08s

Answer:

Part a)

[tex]T = 0.35 s[/tex]

Part b)

[tex]T' = 0.041 s[/tex]

So for top 15 cm the time interval is sufficiently larger than the time interval of last 15 cm

Explanation:

Part a)

Maximum height reached is

H = 76 cm

now the velocity of the player at starting position is given as

[tex]v_f^2 - v_i^2 = 2ad[/tex]

[tex]0 - v^2 = 2(-9.81)(0.76)[/tex]

[tex]v = 3.86 m/s[/tex]

time taken by it in top 15 cm position is given as

[tex]y = \frac{1}{2}gt^2[/tex]

[tex]0.15 = \frac{1}{2}(9.81)t^2[/tex]

[tex]t = 0.175 s[/tex]

so total time in that position is double because in that position first it will go up and then go down

[tex]T = 0.35 s[/tex]

Part b)

Now for bottom position of 15 cm first we will find the time to reach (76 - 15)cm have

[tex]H = \frac{1}{2}gt^2[/tex]

[tex](0.76 - 0.15) = \frac{1}{2}(9.81)t^2[/tex]

[tex]t_1 = 0.352 s[/tex]

now for total time to drop

[tex]t_2 = \sqrt{\frac{2H}{g}}[/tex]

[tex]t_2 = 0.394 s[/tex]

so time interval of last 15 cm is given as

[tex]t' = 0.394 - 0.352[/tex]

[tex]T' = 0.041 s[/tex]

So for top 15 cm the time interval is sufficiently larger than the time interval of last 15 cm

Final answer:

The magnitude of the magnetic field at the origin when t = 0.15 μs can be found using the formula for the magnetic field produced by a moving charge.

Explanation:

The magnitude of the magnetic field at the origin when t = 0.15 μs can be found using the formula for the magnetic field produced by a moving charge:

B = (μ₀Iv)/(2πr)

Where B is the magnetic field, μ₀ is the permeability of free space, I is the current, v is the velocity of the charge, and r is the distance from the charge to the point where we want to find the magnetic field. In this case, the charge is moving parallel to the x-axis, so the current can be calculated using the formula:

I = (Qv)/L

Where Q is the charge and L is the length of the moving charge. Plugging in the values and solving the equations will give the magnitude of the magnetic field at x = 4 m when t = 0.15 μs.

Answer:

height from where rock was thrown is 27.916 m

Explanation:

speed = 7.50 m/s

θ = 30°

g= 9.8 m/s²

horizontal distance = 18 m

time require for vertical displacement

[tex]time = \frac{distance}{velocity} \\t = \frac{18}{7.5\ cos30^0}[/tex]

t = 2.8 sec

now for calculation of height

s = ut + 0.5 a t²

-h = v sinθ× t + 0.5 ×(-9.8)× (2.8²)

-h = 7.5 sin30°× 2.8 - 0.5 ×(9.8)× (2.8²)

-h = -27.916 m

h= 27.916 m

height from where rock was thrown is 27.916 m

Final answer:

To find the height from which the rock was thrown, we can use the equations of projectile motion to calculate the time it takes for the rock to hit the ground and then find the height using another equation. The rock was thrown from a height of 5.7 meters.

Explanation:

To find the height from which the rock was thrown, first, we need to determine the time it takes for the rock to hit the ground.

Using the equation d = v_iy * t + (1/2) * g * t^2, where d is the vertical distance, v_iy is the initial vertical velocity, t is the time, and g is the acceleration due to gravity, plug in the values:

d = 0 (since the rock starts and ends at the same height)

v_iy = 7.5 m/s * sin(30°)

g = 9.8 m/s^2

Solving for t, we get t = 1.22 s.

Next, we can find the height by using the equation d = v_iy * t - (1/2) * g * t^2 and plugging in the values:

d = ?, the height we want to find

v_iy = 7.5 m/s * sin(30°)

t = 1.22 s

g = 9.8 m/s^2

Solving for d, we get d = 5.7 m.

Therefore, the rock was thrown from a height of 5.7 meters.

Answer:

The intensity increases by a factor 100.

Explanation:

Given that,

Sound intensity = 20 db

We need to calculate the intensity factor

[tex]F=10^{\dfrac{LI}{10}}[/tex]

Where, LI = sound intensity

Put the value into the formula

[tex]F=10^{\dfrac{20}{10}}[/tex]

[tex]F=10^2[/tex]

[tex]F=100[/tex]

Hence, The intensity increases by a factor 100.

Final answer:

A 20 dB increase in sound level corresponds to a 100 times increase in sound intensity, as each 10 dB increase represents a tenfold increase in intensity.

Explanation:

A sound level increase of 20 dB signifies a substantial increase in sound intensity. Given that each 10 dB increase corresponds to a tenfold increase in intensity, a 20 dB increase would mean the intensity is 10 times 10, or 100 times greater than the original level. This is derived from the logarithmic scale used to measure sound intensity in decibels (dB), where an increase of 10 dB represents a tenfold increase in sound intensity. Therefore, we can say that a 20 dB increase in sound level would result in the new sound being 100 times more intense than the original. To provide an example, if one sound measures 60 dB and another sound measures 80 dB, the latter is 100 times more intense than the former.

The IKAROS spacecraft, propelled by the force of light from the sun, would have its speed increased by 30 m/s after 3 months of flight under the assumption that this is the only force acting on the 290 kg spacecraft.

The increase in speed of the IKAROS spacecraft can be calculated using the formula force = mass x acceleration. The force exerted by the sunlight is given as 1.12 mN or 0.00112 N. The mass of the spacecraft is given as 290 kg. So, the acceleration can be calculated as force/mass which is (0.00112 N)/(290 kg) = 3.86 x 10⁻⁶ m/s². This acceleration is continuous, so over time it imparts a speed increase to the spacecraft.

The time over which the acceleration is acting is 3 months or 3 x 30 x 24 x 60 x 60 seconds = 7.776 x 10⁶ s. Using the formula speed = acceleration x time, the increase in speed can be calculated as (3.86 x 10⁻⁶ m/s²) x (7.776 x 10⁶ s) = 30 m/s. So, the speed of the spacecraft would increase by 30 m/s after 3 months of flight assuming this force is the only one acting on it.

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The speed of the spacecraft would increase by 100800 m/s after 3.0 months of flight.

To calculate the increase in speed of the spacecraft after 3.0 months of flight, we can use the equation:

F = m * a

Where F is the force, m is the mass, and a is the acceleration. Rearranging the equation, we get:

a = F / m

Plugging in the force value of 1.12 mN and the mass of the spacecraft which is 290 kg, we can calculate the acceleration:

a = 1.12 mN / (290 kg)

Next, we need to convert the time of 3.0 months into seconds. Since there are 30 days in each month, and each day has 24 hours and 60 minutes, we can calculate:

3.0 months = 3.0 * 30 days * 24 hours * 60 minutes * 60 seconds

After converting the time into seconds, we can use the equation:

v = u + at

Where v is the final velocity, u is the initial velocity (assumed to be 0 since the spacecraft is starting from rest), a is the acceleration, and t is the time. Rearranging the equation, we get:

v = at

Plugging in the calculated acceleration and the converted time, we can calculate the final velocity:

v = (1.12 mN / (290 kg)) * (3.0 * 30 days * 24 hours * 60 minutes * 60 seconds)

Simplifying the calculation, we get:

v = 100800 m/s

Therefore, the speed of the spacecraft would increase by 100800 m/s after 3.0 months of flight, assuming the force from the solar sails is the only force acting on the spacecraft.

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Answer:

Strong nuclear force

Explanation:

Strong nuclear force (which is the strongest of the forces of the universe) is responsible for the attractive force between quarks to form nucleons (protons and neutrons). It is the reason why the protons (that are positive in charge) do not fly apart due to electromagnetic repulsion in the nucleus of an atom.

Answer:

560 m

Explanation:

"A projectile is fired at time t = 0.0 s from point 0 at the edge of a cliff, with initial velocity components of v₀ₓ = 30 m/s and v₀ᵧ = 100 m/s.  The projectile rises, and then falls into the sea at point P. The time of flight of the projectile is 25 s.  Assume air resistance is negligible.  What is the height of the cliff?"

Use constant acceleration equation in the y direction.

y = y₀ + v₀ t + ½ gt²

0 = h + (100 m/s) (25 s) + ½ (-9.8 m/s²) (25 s)²

h = 560 m

The height of the cliff is 560 m.

1. With this statement, the author is referring to the fact that the vehicles are one of the largest polluters of the air. In order to reduce the pollution, the vehicles that are used will need to be changed, and with it the pollution will decrease significantly. The reduction of the pollution will come because the vehicles on hydrogen will not cause any pollution, so the enormous amounts of carbon dioxide released from the combustion of the engines will be thing of the past.

2. There are several challenges with this type of vehicles in order for them to replace the fossil fuel driven ones. The big price is one of the factors, as the majority of the people can not afford these cars. Another problem is that these vehicles are not as fast as the fossil fuel driven ones, and lot of people enjoy fast driving, despite it not being safe. There are millions of vehicles out there on the roads, and changing all of them with hydrogen vehicles will take a lot of time, as lot of those vehicles are new ones, so the people will not be willing to just throw them away and leave them rot in their garages. In order for the change of the driving park to be accomplished, the prices should go down, the people to be more serious about the environment and its protection, and patience as several decades will probably be needed for a change like this to be competed.

3. The fuel celled cars are a viable answer to decrease the pollution, as they are not causing any pollution, but instead will stop the process of large emissions of carbon dioxide from the fossil fueled cars. While this method is a good one, it should not be the only, as on its own it can not have the desirable effect, but instead all the major polluters should be included in the process. The industry and the production of energy are one of the major polluters as well, so they will need to follow the example, as if they not, the problem will stay, considering that the industry is constantly growing and the demand for energy is constantly growing too.

Answer:

t = 025 s

Explanation:

We know

weight, W =  4 pounds

spring constant, k = 2 lb/ft

Positive damping, β = 1

Therefore mass,  m =  W / g

                             m = 4 / 32

                                  = 1 / 8 slug

From Newtons 2nd law

[tex]\frac{d^{2}x}{dt^{2}}=-kx-\beta .\frac{dx}{dt}[/tex]

where x(t) is the displacement from the mean or equilibrium position. The equation can be written as

[tex]\frac{d^{2}x}{dt^{2}}+\frac{\beta }{m}.\frac{dx}{dt}+\frac{k}{m}x=0[/tex]

Substituting the values, the DE becomes

[tex]\frac{d^{2}x}{dt^{2}}+8\frac{dx}{dt}+16x=0[/tex]

Now the equation is

[tex]m^{2}+8m+16=0[/tex]

and on solving the roots are

[tex]m_{1}[/tex] = [tex]m_{2}[/tex] = -4

Therefore the general solution is [tex]x(t)=e^{-4t}\left ( c_{1}+c_{2}t \right )[/tex]

Now for initial condition x(0) = -1 ft

                                        x'(0)= 8 ft/s

Now we can find the equation of motion becomes,

[tex]x(t)=e^{-4t}\left ( -1+4t \right )[/tex]

Therefore, the mass passes through the equilibrium when

x(t) = 0

[tex]e^{-4t}\left ( -1+4t \right )[/tex] = 0

-1+4t = 0

t = [tex]\frac{1}{4}[/tex]

  = 0.25 s

Explanation:

The diffraction angles [tex]\theta_{n}[/tex] when we have a slit divided into [tex]n[/tex] parts are obtained by the following equation:

[tex]dsin\theta_{n}=n\lambda[/tex] (1)

Where:

[tex]d[/tex] is the width of the slit

[tex]\lambda[/tex] is the wavelength of the light  

[tex]n[/tex] is an integer different from zero

Now, the first-order diffraction angle is given when [tex]n=1[/tex], hence equation (1) becomes:

[tex]dsin\theta_{1}=\lambda[/tex] (2)

We know:

[tex]\theta_{1}=34\°[/tex]

In addition we are told the diffraction grating has 750 slits per mm, this means:

[tex]d=\frac{1mm}{750}[/tex]

Solving (2) with the known values we will find [tex]\lambda[/tex]:

[tex]\lambda=(\frac{1mm}{750})sin(34\°)[/tex] (3)

[tex]\lambda=0.00074559mm[/tex] (4)

Knowing [tex]1mm=10^{6}nm[/tex]:

[tex]\lambda=745.59nm[/tex]  >>>This is the wavelength of the light, wich corresponds to red.

Answer: composition, its size and shape.

Explanation:

All objects have a frequency that characterizes them, which is called natural frequency. This means that if a disturbance or vibration is emitted near the object, it will begin to vibrate due to its natural frequency.

It should be noted that there are objects that have more than one natural frequency, and this depends on the composition of the object, its elasticity, its shape and size.

The natural frequency of an object refers to the frequency at which it naturally tends to vibrate or oscillate when disturbed.

The specific factors that determine the natural frequency of an object are:

1. Mass: The mass of an object plays a significant role in determining its natural frequency.

2. Stiffness: The stiffness or rigidity of an object is another important factor in determining its natural frequency.

3. Geometry: The shape and size of an object also influence its natural frequency.

These factors interact with each other to determine the natural frequency of an object. Generally, objects with higher mass and/or higher stiffness will have lower natural frequencies, while objects with lower mass and/or lower stiffness will have higher natural frequencies.

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