Answer:
A = 196 pi m^2
Step-by-step explanation:
The area of a circle is given by
A = pi * r^2
The radius is 14
A = pi *14^2
A = 196 pi m^2
Answer:
196π m2
Step-by-step explanation:
What is the explicit rule for the geometric sequence? 4.05, 1.35, 0.45, 0.15, ...
an=4.05(13)n−1
an=4.05(13)n+2
an=4.05(13)n
an=4.05(13)n+1
Answer: First option is correct.
Step-by-step explanation:
Since we have given that
4.05, 1.35, 0.45, 0.15, ...
Since it is a geometric sequence.
So, here, a = 4.05
r = [tex]\dfrac{a_2}{a_1}=\dfrac{1.35}{4.05}=0.33[/tex]
So, we know the formula for nth term in geometric sequence.
[tex]a_n=ar^{n-1}\\\\a_n=4.05(0.3)^{n-1}[/tex]
Hence, First option is correct.
Answer:
an=4.05^(1/3)n−1
Step-by-step explanation:
Determine the scale factor for Δ ABC to Δ A¹B¹C¹.
Answer:
Answer B
Step-by-step explanation:
The triangle has side lengths that are dilated by 2x in the second triangle
Answer:
2
Step-by-step explanation:
A P E X
Xanthia buys hot dogs that come in packages of six, and she buys hot dog buns that come in packages of eight. What is the smallest number of hot dog packages she can buy in order to be able to buy an equal number of hot dogs and hot dog buns?
Answer:
4.
Step-by-step explanation:
The smallest number of hot dogs packages and hot dog buns that has the same amount of is the least common multiple between 6 and 8.
6 = 3*2
8 = [tex]2^{3}[/tex]
So, the least common multiple is the product of each multiple with the biggest exponent, that is [tex]2^{3}*3=24[/tex]. Then, Xanthia has to buy 4 hot dog packages to have 24 hotdogs and 24 hotdog buns.
To solve this problem, we first find the least common multiple (LCM) of 6 and 8. 6=2*3 and 8=2^3, so their LCM is 2^3*3=24. Therefore, Xanthia can buy 24÷6=4 hot dog packages and 24÷8=3 hot dog bun packages to have an equal number of hot dogs and hot dog buns. So you have an answer of 4.
Please give me brainliest, I'm trying to get to a higher rank... You don't have to tho, I respect that someone else deserves it sometimes.
Solve, then check algebraically and graphically. 9x-3=78
Answer:
x=9
Step-by-step explanation:
I have answered ur question
Can someone help me with this math question
Answer:
2/3
Step-by-step explanation:
These two figures are similar since they have the same shape but not the same size
Yellow figure is larger than the orange figure therefore, the yellow figure is a larger or a dilated version of the orange figure.
Scale factor = Small side
Large side
Scale factor = 10/15
Scale factor = 2/3
The scale factor of this dilation is 2/3. The orange figure is dilated 2/3 times to form the yellow figure.
!!
Answer:
It's 2/3
Step-by-step explanation:
Trust me
If events A and B are independent, what must be true?
P(AB) = P(B)
P(AB) = P(A)
P(A) = P(B)
P(AB) = P(BA)
Answer:
The last option is correct for two independent events.
P(A and B) = P(A) P (B)
And P(B and A) = P(B) P(A) which is equal. And other three cases are false.
P(AB) = P(BA) is true.
What are independent events ?
If outcomes of an event doesn't affect the outcomes of other event, the the events are called independent events, i.e. they are independent to each other.
Which option is true ?For two independent events,
P(AB) = P(A)P(B)
Also, P(BA) = P(B)P(A)
And, P(A)P(B) = P(B)P(A)
Hence, we can say that P(AB) = P(BA)
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A mouse traveled a total distance of 3/24 of a mile in a maze over the past three hours the mouse travel the same distance each hour to determine the distance that the mouse traveled age our map reformed the calculations below he concluded that the mouse travel 3/8 of a mile each hour what is Matt's error
i was a
Step-by-step explanation:
Answer:
a
Step-by-step explanation:
Find the length of "a", to
the nearest tenth, using
the Pythagorean Theorem.
Enter
Answer:
[tex]\sqrt{28} \approx 5.3[/tex]
Step-by-step explanation:
The Pythagorean Theorem says if you have a right triangle, then relationship between the three sides is the sum of the square of each leg is the hypotenuse squared.
So [tex]a^2+b^2=c^2[/tex]
where a and b are legs and c is the hypotenuse.
Plug in your a,b, and c. In this case it is a,6, and 8.
This means we have
[tex]a^2+6^2=8^2[/tex]
Simplify where you can before we begin the solving (the moving around of things to other sides).
[tex]a^2+36=64[/tex]
Now time for the solving. We are first going to get [tex]a^2[/tex] by itself.
To do this, we just need to subtract 36 on both sides giving us:
[tex]a^2=64-36[/tex]
[tex]a^2=28[/tex]
Now to get rid of the square on a, just square root both sides:
[tex]a=\sqrt{28}[/tex].
You put the names of all the students in your class in a paper bag. There are 16 boys and 18 girls. If you draw a name at random, what is P(boy’s name)?
Answer:
Step-by-step explanation:
The probability of drawing a boy's name is found in:
number of boys/total number of students
Our ratio then is
16/16+18 which is
16/34 which reduces to
8/17
As a percentage, it would be about 47%
Total students = 16 + 18 = 34
16 boys
Probability of picking boy = 16/34
Which reduces to 8/17
What is the sum of the first 8 terms of the geometric series:
3+6+12+24+
0765
382
286
440
Answer:
765.
Step-by-step explanation:
Sum of n terms = a1 (r^n - 1) / (r - 1) where a1 = the first term and r = the common ratio.
Here r = 6/3 = 2 and a1 = 3.
Sum of 8 terms = 3 * ( 2^8 - 1) / 2 -1)
= 3 * 255
= 765 (answer).
Maggie graphed the image of a 90 counterclockwise rotation about vertex A of . Coordinates B and C of are (2, 6) and (4, 3) and coordinates B’ and C’ of it’s image are (–2, 2) and (1, 4). What is the coordinate of vertex A. (EXPLAIN WORK)
Answer:
A(2,2)
Step-by-step explanation:
Let the vertex A has coordinates [tex](x_A,y_A)[/tex]
Vectors AB and AB' are perpendicular, then
[tex]\overrightarrow {AB}=(2-x_A,6-y_A)\\ \\\overrightarrow {AB'}=(-2-x_A,2-y_A)\\ \\\overrightarrow {AB}\perp\overrightarrow {AB'}\Rightarrow \overrightarrow {AB}\cdot \overrightarrow {AB'}=0\Rightarrow (2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0[/tex]
Vectors AC and AC' are perpendicular, then
[tex]\overrightarrow {AC}=(4-x_A,3-y_A)\\ \\\overrightarrow {AC'}=(1-x_A,4-y_A)\\ \\\overrightarrow {AC}\perp\overrightarrow {AC'}\Rightarrow \overrightarrow {AC}\cdot \overrightarrow {AC'}=0\Rightarrow (4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0[/tex]
Now, solve the system of two equations:
[tex]\left\{\begin{array}{l}(2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0\\ \\(4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0\end{array}\right.\\ \\\left\{\begin{array}{l}-4-2x_A+2x_A+x_A^2+12-6y_A-2y_A+y^2_A=0\\ \\4-4x_A-x_A+x_A^2+12-3y_A-4y_A+y_A^2=0\end{array}\right.\\ \\\left\{\begin{array}{l}x_A^2+y_A^2-8y_A+8=0\\ \\x_A^2+y_A^2-5x_A-7y_A+16=0\end{array}\right.[/tex]
Subtract these two equations:
[tex]5x_A-y_A-8=0\Rightarrow y_A=5x_A-8[/tex]
Substitute it into the first equation:
[tex]x_A^2+(5x_A-8)^2-8(5x_A-8)+8=0\\ \\x_A^2+25x_A^2-80x_A+64-40x_A+64+8=0\\ \\26x_A^2-120x_A+136=0\\ \\13x_A^2-60x_A+68=0\\ \\D=(-60)^2-4\cdot 13\cdot 68=3600-3536=64\\ \\x_{A_{1,2}}=\dfrac{60\pm8}{2\cdot 13}=\dfrac{34}{13},2[/tex]
Then
[tex]y_{A_{1,2}}=5\cdot \dfrac{34}{13}-8 \text{ or } 5\cdot 2-8\\ \\=\dfrac{66}{13}\text{ or } 2[/tex]
Rotation by 90° counterclockwise about A(2,2) gives image points B' and C' (see attached diagram)
(QUICK!!!!!!!!!!!!) Write an equation of the line below.
Answer:
[tex]\large\boxed{y=\dfrac{3}{5}x-2}[/tex]
Step-by-step explanation:
The slope-intercept form of an equation of aline:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
The formula of a slope:
[tex]m=\dfraxc{y_2-y_1}{x_2-x_1}[/tex]
From the graph we have the points:
(-5, -5)
y-intercept (0, -2) → b = -2
Calculate the slope:
[tex]m=\dfrac{-2-(-5)}{0-(-5)}=\dfrac{3}{5}[/tex]
Put the value of the slope and the y-intercept to the equation of a line:
[tex]y=\dfrac{3}{5}x-2[/tex]
Please solve the following complex number system ASAP, show work and please simplify fully.
[tex]x^{2}[/tex]-16x+80=0
Answer:
x= 16±√-64 over 2
Step-by-step explanation:
x= -(-16)±√(-16)²-4×1×80 over 2×1
x= 16±√256-320 over 2
x= 16±√-64 over 2
can also be represented with all real numbers.
Which statement is true?
All rectangles are squares.
All squares are rectangles.
All quadrilaterals are rectangles.
All parallelograms are rectangles.
Answer:
B. All squares are rectangles.
Step-by-step explanation:
B is the correct answer, because all the squares are rectangles have 4 sides.
The accurate statement is that all squares are rectangles.
The statement that is true among the options provided is All squares are rectangles. This is because squares have all the properties of a rectangle, which is a quadrilateral with four right angles, but with the additional property of having all four sides of equal length. Therefore, because a square fulfills all the criteria of a rectangle, we can conclude that all squares are indeed rectangles. On the other hand, not all rectangles are squares since rectangles do not require all sides to be equal, only that the opposite sides are equal. Similarly, not all quadrilaterals are rectangles because other quadrilaterals, like rhombuses or kites, do not have the necessary four right angles. Finally, while all rectangles are parallelograms (a quadrilateral with opposite sides that are equal and parallel), not all parallelograms have right angles and thus are not all rectangles.
To elaborate, a rectangle is defined as a parallelogram with right angles. When it comes to comparing areas, the area of a rectangle is calculated by multiplying its base by its height. And in the case of squares, since all sides are equal, it's just the side length squared. However, when you have two shapes with equal area -- for instance, a square and a rectangle -- the one with the longer perimeter would be the one with the less compact shape, which in most cases would be the rectangle unless it is also a square.
Jose is the water maintenance supervisor for his city. He knows the rate rainwater flows through a pipe is modeled by the equation R(x)= -0.1x^3+1.4x^2-1.5x, where R is the amount of water, in cubic feet, and X is time, in hours. Jose a developer of a new neighborhood that if she decreases the size of the pipe, the water flow will decrease. The function that models the decrease is D(x)-0.04x^3+0.5x^2+x, where D is the amount of water in cubic feet, and X is time, in hours.
Write a function, H(x), for the rate at which rainwater flows in the smaller pipe.
Please Help
so the rainwater flows as R(x), and the decrease of the flow will be D(x), the new smaller pipe after the decrease will have water flowing at R(x) - D(x)
[tex]\bf \begin{cases} R(x)=-0.1x^3+1.4x^2-1.5x\\ D(x)=-0.04x^3+0.5x^2+x \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{R(x)}{(-0.1x^3+1.4x^2-1.5x)}-\stackrel{D(x)}{(-0.04x^3+0.5x^2+x)} \\\\\\ (-0.1x^3+1.4x^2-1.5x)+0.04x^3-0.5x^2-x \\\\\\ -0.1x^3+1.4x^2-1.5x+0.04x^3-0.5x^2-x \\\\\\ -0.10x^3+0.04x^3+1.4x^2-0.5x^2-1.5x-x\implies \stackrel{H(x)}{-0.6x^3+0.9x^2-1.6x}[/tex]
To find the rate of water flow through the smaller pipe, subtract the decrease function from the original rate function.
Explanation:To find the rate at which rainwater flows through the smaller pipe, we need to subtract the decrease function from the original rate function. Let's call this new function H(x). So, H(x) = R(x) - D(x).
Substituting the given values, H(x) = (-0.1x^3 + 1.4x^2 - 1.5x) - (-0.04x^3 + 0.5x^2 + x). Simplifying, H(x) = -0.1x^3 + 1.4x^2 - 1.5x + 0.04x^3 - 0.5x^2 - x.
Combining like terms, H(x) = -0.06x^3 + 0.9x^2 - 2.5x.
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When a boy pulls his sled with a rope, the rope makes an angle of 35° with the horizontal. If a pull of 16 pounds on the rope is needed to move the sled, what is the horizontal component force?
9 lb
13 lb
19 lb
22 lb
Answer:
13 lb
Step-by-step explanation:
The horizontal component of the force is the magnitude of the force multiplied by the cosine of the angle with the horizontal.
(16 lb)·cos(35°) ≈ 13.1 lb ≈ 13 lb
Answer:
b.13 lb
Step-by-step explanation:
We are given that a boy pulls his sled with a rope .
The rope makes an angle with horizontal =[tex]35^{\circ}[/tex]
If a pull on the rope is needed to move the sled=16 pounds
We have to find the horizontal component of force
We know that horizontal component force=[tex]fcos\alpha[/tex]
Therefore, we have f=16 pound
Then, horizontal component of force=[tex]16cos 35^{\circ}[/tex]
Horizontal component of force=[tex]16\times 0.819=13.1lb[/tex]
Hence, horizontal component of force=13 lb
Answer:b.13 lb
Chung has 6 trucks and 5 cars in his toy box. Brian has 4 trucks and 5 cars in his toy box. Which is the correct comparison of their ratios of trucks to cars?
Final answer:
Chung has a ratio of 6 trucks to 5 cars (6:5), and Brian has a ratio of 4 trucks to 5 cars (4:5). Chung has a higher ratio of trucks to cars compared to Brian.
Explanation:
To compare the ratios of trucks to cars for Chung and Brian, we simply write down the number of trucks and cars each has and form a ratio for each. For Chung, the ratio of trucks to cars is 6 trucks to 5 cars, which can be written as 6:5 or ⅓. For Brian, the ratio of trucks to cars is 4 trucks to 5 cars, or 4:5 or ⅔.
Now, by comparing these two ratios, we see that Chung has a higher ratio of trucks to cars (6:5) compared to Brian (4:5), which means Chung has more trucks relative to cars in his toy box than Brian does.
To compare Chung's and Brian's ratios of trucks to cars, we have to calculate each ratio and then compare them.
**Chung's Ratio:**
Chung has 6 trucks and 5 cars. The ratio of trucks to cars for Chung is the number of trucks divided by the number of cars.
Chung's trucks to cars ratio = Number of trucks / Number of cars
= 6 / 5
**Brian's Ratio:**
Brian has 4 trucks and 5 cars. The ratio of trucks to cars for Brian is the number of trucks divided by the number of cars.
Brian's trucks to cars ratio = Number of trucks / Number of cars
= 4 / 5
Both ratios are to be compared now.
**Comparing Ratios:**
Chung's ratio is 6/5, which is 1.2 when converted into a decimal.
Brian's ratio is 4/5, which is 0.8 when converted into a decimal.
Since 1.2 (Chung's ratio) is greater than 0.8 (Brian's ratio), we can conclude that Chung has a higher ratio of trucks to cars compared to Brian.
Therefore, the correct comparison of their ratios is: "Chung has a higher ratio of trucks to cars than Brian."
Given h(x) = x-3 and f(x) = x3-x2-x-15 is h(x) a factor of f(x)?
Answer:
Yes.
Step-by-step explanation:
To see if h is a factor of f, we can use the factor theorem.
h(x)=x-3 has a zero at x=3 because h(3)=3-3=0.
So we want to see if the zero of h is a zero of f.
Is x=3 a zero of f?
You can check using synthetic division or just plug in 3.
Let's do both.
If you use synthetic you are trying to see if you get a remainder of 0.
If you plug it in you are trying to see if you get 0 as the output when plugging your input 3.
Let's do synthetic first:
Since we are checking to see if x=3 is a zero, that will go on the outside:
3 | 1 -1 -1 -15
| 3 6 15
- ------------------------
1 2 5 0
So yep the remainder is 0 so the answer is yes.
Let's plug it in:
f(3)=3^3-3^2-3-15
f(3)=27-9-3-15
f(3)=18-3-15
f(3)=15-15
f(3)=0
The result is 0 so the answer is yes.
You pick your favorite way here.
Research suggests that the pressure of being timed may interfere with performance on tests that involve mathematical problems. A fictional study was conducted with 30 sixth graders. First, the sixth graders were given a math test that contained 50 problems and were told that they had only one hour to complete it (timed condition). The same sixth graders were later given a math test that contained 50 problems and were told that they could have as much time, as needed, to complete the test (unlimited time condition). The total number of correct answers for each sixth grader was then calculated for each condition. Then, for each student, the difference between the two scores (timed − untimed) was calculated. The researchers hypothesized that the sixth graders would get fewer correct answers when they took the test with a time limit than when they had unlimited time. If μ1and μ2 represent the number of correct answers during the timed condition and the unlimited time condition, respectively, and let μd be the mean of the differences in the number of correct answers (timed − untimed) of all sixth graders. Which of the following are the appropriate null and alternative hypotheses? H0: μd = 0 Ha: μd > 0 B. H0: μd = 0 Ha: μd < 0 C. H0: μd < 0 Ha: μd = 0 D. H0: μ1 − μ2 = 0 Ha: μ1 − μ2 < 0
Answer:
B. H0: μd = 0 Ha: μd < 0
Step-by-step explanation:
Let μ1 and μ2 represent the number of correct answers during the timed condition and the unlimited time condition, respectively.
Let μd be the mean of the differences in the number of correct answers (timed − un timed) of all sixth graders.
The answer is B. H0: μd = 0 Ha: μd < 0
Here we have to check that the students will get few correct answers in the timed condition as compared to the unlimited time condition.
To know this, difference was calculated so we get the correct hypotheses as : H0: μd = 0 and Ha: μd < 0 .
Answer:
Also "H0: μ1 − μ2 = 0 Ha: μ1 − μ2 < 0" is correct
Step-by-step explanation:
Find the mean and standard deviation of the probability distribution. Round answer to the nearest hundredth. Would it be unusual to have 3 defective computers in the batch? The probabilities that a batch of 4 computers will contain 0, 1, 2, 3, and 4 defective computers are 0.4096 , 0.4096 , 0.1536 , 0.0256 , and 0.0016 , respectively.
Answer:
Mean = 0.8
Standard Deviation = 0.8
P(x = 3) is unusual event
Step-by-step explanation:
Part A)
The probability distribution with correct formatting is shown in the table attached with:
We have to find the mean and standard deviation of this distribution. The mean of the probability distribution is calculated as summation of the products of "the variable with its respective probability".
[tex]u = \sum x P(x)[/tex]
So, for the given distribution:
Mean = 0(0.4096) + 1(0.4096)+2(0.1536)+3(0.0256)+4(0.0016)
Mean = 0.8
Standard deviation is calculated by the following formula:
[tex]\sigma=\sqrt{\sum x^{2}P(x) - u^{2}}[/tex]
[tex]x^{2}P(x)=1.28[/tex]
Substituting the values, we get:
[tex]\sigma=\sqrt{1.28-(0.8)^{2}}\\\\ \sigma=0.8[/tex]
Part B)
Since the probability of 3 defective computers is less than 0.05, this is an unusual event.
So it would be unusual to have 3 defective computers in the batch.
Find the y value at the point x = -2.
By looking at the graph, we can visually determine that the value of y when point x = -2 is -4.
Answer:
-4
Step-by-step explanation:
The y value at x=-2 is -4 because when you go to -2 on the x-axis the function is below there. You can only go straight up or straight down to determine the y-value that corresponds to x=-2 so we go down because the function is below the x-axis there.
We are going to go down until we get on the graph of the line. Scroll over with eyeballs to see that the y there is -4 (use the y-axis).
So the ordered pair (-2,-4) is on our line and when x=-2, y=-4.
Another example:
y=0 when x=2
Another example:
y=2 when x=4
Another example:
y=-3 when x=-1
For 20 Points.
=============
Answer:
B
Step-by-step explanation:
Answer:
Its B) 60°
Step-by-step explanation:
135°=75°+CAD
135°-75°=CAD
60°=CAD
Can u guys PLEASE do this question 31
Answer:
see below
Step-by-step explanation:
The attached printable graph paper is a scale drawing. The 1 : 100 scale means each meter will be represented by 1 cm.
I need your help with this problem
Answer:
12.9 m
Step-by-step explanation:
Let d represent the length of the diagonal. Then d-2 is the length and d-6 is the width. The Pythagorean theorem can be used to relate these measures, which are the legs and hypotenuse of a right triangle.
d² = (d-2)² + (d-6)²
d² = d² -4d +4 + d² -12d +36 . . . . eliminate parentheses
0 = d² -16d +40 . . . . . . . . . . . . . . . subtract d², collect terms
0 = d² -16d +64 -24 . . . . . . . . . . . rearrange the constant to make a square
0 = (d -8)² -24 . . . . . . write in vertex form
d -8 = √24 . . . . . . . . . add 24 and take the square root
d = 8 + √24 . . . . . . . . the negative square root is extraneous in this problem
d ≈ 12.9 . . . meters
The length of the diagonal is about 12.9 meters.
Find the total area of the solid figure.
Answers:
90 sq. ft.
126 sq. ft.
150 sq. ft.
Answer:
90 sq. ft.
Step-by-step explanation:
To find the "volume," you will need to multiply every the LxWxH.
Length = L
Width = W
Height = H
Then the answer is 90 sq. ft.
Answer:
Surface area = 126 square ft .
Step-by-step explanation:
Given : Rectangular cuboid .
To find : Find the total area of the solid figure.
Solution : We have given Rectangular cuboid .
Length = 3 ft .
Width = 5 ft .
Height = 6 ft .
Surface area = 2 ( l*w + w*h + l *h).
Plug the values
Surface area = 2 ( 3*5 + 5*6 + 3 *6).
Surface area = 2 (15 + 30 + 18).
Surface area = 2 ( 63).
Surface area = 126 square ft .
Therefore, Surface area = 126 square ft .
Find the equation in slope-intercept form that describes a line through (–1, 1) and (2, 3)
Answer:
y = 2/3x + 5/3
Step-by-step explanation:
The slope of the line is ...
slope = (change in y)/(change in x) = (3-1)/(2-(-1)) = 2/3
Then the point-slope form of the desired line can be written ...
y = m(x -h) +k . . . . . slope m through point (h, k)
y = 2/3(x +1) +1 . . . . slope 2/3 through point (-1, 1)
y = 2/3x + 5/3 . . . . . . simplify to slope-intercept form
The equation that describes a line through points (-1, 1) and (2, 3) in slope-intercept form is y = 2/3x + 5/3, determined by calculating the slope and y-intercept.
Explanation:The question asks to find the equation in slope-intercept form that describes a line through (-1, 1) and (2, 3). In order to do this, we need to find the slope and y-intercept of the line.
The slope of the line (m) can be determined by using the formula m = [tex](y_2 - y_1) / (x_2 - x_1)[/tex]. Inserting the given points into this formula gives: m = (3 - 1) / (2 - (-1)) = 2 / 3 = 2/3.
To find the y-intercept (b), we can use the point-slope form of the equation and solve for 'b', y = mx + b, insert the slope we found and one of the given points, let's utilise (-1, 1): 1 = 2/3*(-1) + b, which simplifies to b = 5/3.
So, the equation of the straight line in slope-intercept form is y = 2/3x + 5/3.
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one x-intercept for a parabola is at the point (3.22,0) find the other x-intercept for the parabola defined by this equation y=2x^2-8x+5 round to the nearest hundredth if necessary
Answer:
(0.78,0)
Step-by-step explanation:
I would use the quadratic formula.
[tex]a=3[/tex]
[tex]b=-8[/tex]
[tex]c=5[/tex]
[tex]\text{ The quadratic formula is } x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\text{ Let's find } b^2-4ac \text{ first}\\(-8)^2-4(2)(5)\\64-8(5)\\64-40\\24\\\\\text{ Now let's find } -b\\-b=8\\\text{ And } 2a\\2(2)=4\\\\\text{ Let's plug in this information }\\x=\frac{8 \pm \sqrt{24}}{4}\\\\\text{ We are now going to simplify }\\x=\frac{8}{4} \pm \frac{\sqrt{24}}{4} \\x=2 \pm \frac{\sqrt{4 \cdot 6}}{4}\\x=2 \pm \frac{\sqrt{4} \sqrt{6}}{4} \\x=2 \pm \frac{2 \sqrt{6}}{4}\\[/tex]
[tex] x=2 \pm \frac{\sqrt{6}}{2}[/tex]
So let's put both of these into out calculator
2 + sqrt(6)/2 and 2-sqrt(6)/2
One of them should be approximately 3.22 as the question suggests.
3.22 0.78
So the other x-intercept is approximately (0.78,0)
If (x-2)^2=49 then x could be
-9
-7
2
5
9
Answer:
9
Step-by-step explanation:
Plug the numbers in
The result for each number when plugged in order is:
121
81
0
9
49
So 9 would be the answer
Answer:
9
Step-by-step explanation:
If (x-2)^2=49 then x could be 9.
(x-2)^2 = 49
x or 9 - 2 = 7
7^2 = 49
When a certain tree was first planted, it was 4 feet tall, and the height of the tree increased by a constant amount each year for the next 6 years. At the end of the 6th year, the tree was 1/5 taller than it was at the end of the 4th year. By how many feet did the height of the tree increase each year?
Answer:
[tex]\frac{2}{3}\text{ feet}[/tex]
Step-by-step explanation:
Let the equation that models the height of the tree after x years,
y = mx + c
Where, m is constant amount of increasing and c is any constant,
Given,
When x = 0, y = 4,
⇒ 4 = m(0) + c ⇒ c = 4,
Now, the height of plant after 4th year = m(4) + c = 4m + c
Also, the height of plant after 6th year = m(6) + c = 6m + c
According to the question,
6m + c is [tex]\frac{1}{5}[/tex] more than 4m + c,
[tex]6m+c=4m+c + \frac{1}{5}(4m+c)[/tex]
[tex]6m+c = \frac{6}{5}(4m+c)[/tex]
[tex]30m+5c=24m+6c[/tex]
[tex]6m=c[/tex]
By substituting the value of c
6m = 4
⇒ [tex]m=\frac{4}{6}=\frac{2}{3}[/tex]
Hence, 2/3 feet of height is increased each year.
What is the slope of the line in this graph? a.5/9 b.5/7 c. 7/5 d.9/7
Answer:
b. 5/7
Step-by-step explanation:
The line goes through the points (0, 0) and (7, 5). Let's use those points in the slope formula:
[tex]m=\frac{5-0}{7-0}=\frac{5}{7}[/tex]
The slope of that line is 5/7
The slope of the given line is 5/7
What is slope of a line?Slope of a line is the inclination of that line towards the x-axis.How to find the slope of the given line ?We know that slope of a line passing through the points (a, b) and (c ,d), can be given by the formula: [tex]\frac{d-b}{c-a}[/tex]In the given graph, the line passes through the center (0, 0) and (7, 5)
So the slope will be [tex]\frac{5-0}{7-0} = \frac{5}{7}[/tex]
So option B is correct
Find more about "Slope of a Line" here:https://brainly.com/question/3493733
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