If 4.8 moles of X and 3.4 moles of Y react according to the reaction below, how many moles of the excess reactant will be left over at the end of the reaction?

3X + 2Y “yields”/ X3Y2

1.7 mol Y left over
1.6 mol X left over
0.2 mol Y left over
0.1 mol X left over

Answers

Answer 1

Answer : The correct option is, 0.2 mole Y left over .

Explanation : Given,

Moles of X = 4.8 mole

Moles of Y = 3.4 mole

The balanced chemical reaction is,

[tex]3X+2Y\rightarrow X_3Y_2[/tex]

From the balanced reaction, we conclude that

As, 3 moles of X react with 2 moles of Y

So, 4.8 moles of X react with [tex]\frac{2}{3}\times 4.8=3.2[/tex] moles of Y

From this we conclude that, the reactant Y is an excess reagent and X is a limiting reagent.

The moles of excess reagent left over at the end of the reaction = Given moles of X - Required moles of X

The moles of excess reagent left over at the end of the reaction = 3.4 - 3.2 = 0.2 mole

Therefore, the moles of excess reagent left over at the end of the reaction is, 0.2 mole Y left over.

Answer 2

Answer:

The correct answer is : '0.2 mol Y left over'.

Explanation:

[tex]3X + 2Y \rightarrow  X_3Y_2[/tex]

Moles of X = 4.8 moles

Moles of Y = 3.4  moles

According to reaction, 3 moles of X react with 2 moles of Y .

Then 4.8 moles of X react with :

[tex]\frac{2}{3}\times 4.8=3.2 [/tex]moles of Y

Moles of Y reacted = 3.2 moles

Moles of Y left unreacted = 3.4 moles - 3.2 moles = 0.2 moles

As we can see that X is in limiting amount and y is present in an excessive amount.And the left over amount of Y is 0.2 moles.


Related Questions

What is the empirical formula of a molecule containing 18.7% lithium, 16.3% carbon, and 65% oxygen?

Answers

Li2CO3 ; variance= 1.26x10^-3

A 25.0 ml sample of an unknown monoprotic acid was titrated with 0.12 m naoh. the student added 31.6 ml of naoh and went past the equivalence point. which procedure could be performed next to more accurately determine the concentration of the unknown acid?

Answers

The procedure, which can be used to determine more accurately the concentration of the unknown acid is TO BACK-TITRATE WITH ADDITIONAL HYDROCHLORIC ACID TO NEUTRALIZE THE ADDITIONAL SODIUM HYDROXIDE THAT WAS ADDED.
Monoprotic acids are acids that can donate only one proton per each molecule and they have only one equivalence point. Examples of monoprotic acids are HCI, HNO3 and CH3COOH.
The back titration method is typically used when one needs to determine the concentration of an analyte provided there is a known molar concentration of excess reactants. 
From the information given in the question above, we are told that excess NaOH was added. To correct this mistake, the right thing to do is to use additional HCl to carry out back titration, taking note of the quantity of acid that will be needed to neutralize the excess NaOH.

what is the temperature of 12.2 moles gas in a 18.35 l tank at 16.4 atm? express in K and C.

Answers

This problem can be solved by using ideal gas equation PV=nRT. The unit used in the pressure is kPa so you will need to convert it. The temperature also use Kelvin, you will need to convert it if you want it in C.

The calculation would be:
PV= nRT 
16.4 atm * (101.35kPa/atm) *  18.35 L = 12.2 mol *T * (8.314 L*kPa/mol*K)
T=30500  /101.4308
T= 300.70 °K = 27.55 °C

The temperature of 12.2 moles gas in a 18.35 l tank at 16.4 atm is 3,071.7 K or 2,798.5 degree celsius.

How do we calculate temperature?

Temperature of the gas will be calculated by using the ideal gas equation as:

PV = nRT, where

P = pressure of gas = 16.4 atm

V = volume of gas = 18.35 L

n = moles of gas = 12.2 mol

R = universal gas constant = 0.0821 L.atm / K.mol

T = temperature of the gas = ?

On putting all these values on the above equation, we get

T = (167.4)(18.35) / (12.2)(0.0821) = 3,071.7 K = 2,798.5 degree celsius.

Hence required temperature is 3,071.7 K or 2,798.5 degree celsius.

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What mass of h2o will be produced if 9.5 g of h2 reacts with 1.2 g of o2?

Answers

Answer is: mass of water is 1,35 grams.
Chemical reaction: 2H₂ + O₂ → 2H₂O.
m(H₂) = 9,5 g.
n(H₂) = m(H₂) ÷ M(H₂).
n(H₂) = 9,5 g ÷ 2 g/mol.
n(H₂) = 4,75 mol.
m(O₂) = 1,2 g.
n(O₂) = 1,2 g ÷ 32 g/mol.
n(O₂) = 0,0375 mol; limiting reactant.
From chemical reaction: n(O₂) : n(H₂O) = 1 : 2.
n(H₂O) = 0,0375 mol · 2 = 0,075 mol.
m(H₂O) = 0,075 mol · 18 g/mol.
m(H₂O) = 1,35 g.

The mass of H₂O produced from the reaction of 9.5 g of H₂ with 1.2 g of O₂ is 1.3515 g. The calculation is based on the molar mass of the substances and the balanced equation for the formation of water.

The question asks for the mass of H₂O produced from the reaction of hydrogen (H₂) with oxygen (O₂). According to the balanced chemical equation of the formation of water, which is 2H₂ + O₂
ightarrow 2H₂O, 2 moles of H₂ react with 1 mole of O₂ to produce 2 moles of H₂O. The molar masses are as follows: H₂ (2.02 g/mol) and O₂ (32.0 g/mol). Since 1 mole of water (H₂O) has a molar mass of 18.02 g, we can use this information to calculate the mass of water produced.

The mass of 9.5 g of H₂ corresponds to 9.5 g / 2.02 g/mol =4.7 moles of H₂, and the mass of 1.2 g of O₂ corresponds to 1.2 g / 32.0 g/mol = 0.0375 moles of O₂. Since oxygen is the limiting reagent here, it will determine how much water can be produced. From the stoichiometry of the reaction, 1 mole of O₂ will produce 2 moles of H₂O. Therefore, 0.0375 moles of O₂ would produce 0.0375 moles * 2 = 0.075 moles of H₂O. To find the mass: 0.075 moles * 18.02 g/mol = 1.3515 g of H₂O.

Therefore, the mass of H₂O produced is 1.3515 g.

-As the temperature increased, what happened to the N2O4 concentration?

Answers

2 NO₂ ↔ N₂O₄ + 61 kJ
The reaction is endothermic so by increasing the temperature the reaction moves to the left (decrease the concentration of N₂O₄)

An unknown compound displays singlets at δ 2.1 ppm and 2.56 ppm in the ratio of 3:2. what is the structure of the compound?

Answers

1) As can be seen from any 1H NMR chemical shift ppm tables, hydrogens which have δ values from 2ppm to 2.3ppm are hydrogens from carbon which is bonded to a carbonyl group. From this, we can conclude that our hydrogens belong to the type, but from 2 different alkyl groups because of 2 different signals.

 

2) So, one alkyl group is CH3 and second one can be CH or CH2.

 

3) If we know that ratio between two types of hydrogens is 3:2, it can be concluded that second alkyl group is CH2. 


4) Finally, we don't have any other signals and it indicates that part of the compound which continues on CH2 is exactly the same as the first part.

The ratio remains the same, 3:2 ie 6:4

How many grams of CO2 are in 4 mol of the compound?

Answers

Answer: 176.04 g

Explanation:

Data:

1) compound CO2
2) n = 4 mol
3) mass in grams = ?

Formula:

mass in grams = n * molar mass

Solution:

molar mass of CO2 = 1 * atomic mass of C + 2 * atomis mass of O

atomic mass of C = 12.01 g/mol
atomic mass of O = 16.00 g/mol

molar mass of CO2 = 1 * 12.01 g/mol + 2 * 16.00 g/mol = 44.01 g/mol

mass in grams = 4 mol * 44.01 g/mol = 176.04 g

Answer: 176.04 g

One form of transportation that uses nuclear power for energy is the
A) airplane.
B) automobile.
C) motorcycle.
D) submarine.

Answers

Submarines use a nuclear reactor.

One form of transportation that uses nuclear power for energy is the  submarine. Therefore, option D is correct.

What do you mean by nuclear energy ?

The term nuclear energy is defined as the energy in the nucleus, of an atom. Atoms are small units that formed all matter in the universe, and energy is what binds the nucleus together. There is a huge amount of energy in an atom's dense nucleus.

Nuclear submarines and aircraft carriers are powered by onboard nuclear reactors. Atoms in the nuclear reactor break, which passes  energy as heat. This heat is used to create high-pressured steam.

U.S. submarines rely on nuclear power for both propulsion and life support. The nuclear reactor heats water to produce steam that drives a turbine to transfer the propeller.

Thus, option D is correct.

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How do sodium and potassium ions transfer in and out of an axon?

A.Through “gates” that open up
B.Through an absorption process
C.Through neural communication
D.Through an electrical process

Answers

Answer:

Option A= through gates that,s open up

Explanation:

The sodium and potassium ions transfer in and out the axon through electrical process. This process is called depolarization and re-polarization.

Depolarization:

Depolarization is occur when stimulus is given to the resting neuron. In this process gates of sodium ions on the membrane become open and sodium ions that are present out side. inter into the cell. because of this process the charge of the nerve changes (-70 mv to -55 mV).

Re-polarization:

when the re-polarization occur, potassium gates are open and the potassium ions goes outside the membrane. During this process electrical potential becomes negative inside the cell until the potential of -70 mV is re-attain i.e, resting potential.

In short we can say that depolarization allow sodium ions to inter into the nerve membrane and re-polarization allow potassium ions to moves out side the membrane.

Answer:

A.) Through gates that open up

Explanation:

Odyssey ware

A solution with a ph of 4 has _________ the concentration of h+ present compared to a solution with a ph of 5.

Answers

A solution with a pH of 4 has ten times the concentration of H⁺ present compared to a solution with a pH of 5.
pH is a numeric scale for the acidity or basicity of an aqueous solution. It is  the negative of the base 10 logarithm of the molar concentration of hydrogen ions.
[H⁺] = 10∧-pH.
pH = 4 → [H⁺]₁ = 10⁻⁴ M = 0,0001 M.
pH = 5 → [H⁺]₂ = 10⁻⁵ M = 0,00001 M.
[H⁺]₁ / [H⁺]₂ = 0,0001 M / 0,00001 M.
[H⁺]₁ / [H⁺]₂ = 10.

Identify the oxidizing agent in the reaction: sn(s) + 2h+(aq) → sn2+(aq) + h2(g)

Answers

In the reaction Sn(s) + 2H+(aq) → Sn2+ (aq) + H2(g)
from this reaction, we get that Sn loses from 0 to 2 electrons so it's oxidized So it is the reducing agent.
and H  gains from 0 to 1 electrons so, it's reduced so ∴ it is the oxidizing agent

Explanation:

An oxidizing agent is defined as a substance which readily accepts an electron and itself gets reduced in order to oxidize another substance in a chemical reaction.

For example, [tex]2H^{+} + 2e^{-} \rightarrow H_{2}[/tex]

Here, hydrogen is getting reduced as its oxidation state is changing from +1 to 0 and hence it acts like an oxidizing agent.  

In an oxidizing agent, a decrease in oxidation state occurs.

Whereas in [tex]Sn \rightarrow Sn^{2+} + 2e^{-}[/tex], tin is getting oxidized by gaining electrons. Therefore, it is acting as a reducing agent. An increase in oxidation state occurs for a reducing agent.

Thus, we can conclude that in the given reaction hydrogen is the oxidizing agent.

Titanium is a metal used to make golf clubs. a rectangular bar of this metal measuring 1.77 cm x 2.08 cm x 2.64 cm was found to have a mass of 48.9 g. what is the density of titanium in g/cm3? answer

Answers

The volume of the bar is
V = l * w * h
l = 2.64 cm
w = 2.08 cm
h = 1.77 cm
V = 2.64*2.08 * 1.77
V = 9.719 cm^3

Formula
density = mass / volume

Find the density
mass = 48.9 g
d = m / V
d = 48.9 / 9.719
d = 5.03 <<<=== answer.

What is the expected oxidation state for the most common ion of element 2

Answers

Answer: 1+

Justification:

The ionization energy is the amount of energy needed to loose electrons and becomes ions.

The first ionization energy is the energy needed to liberate one one electron and form the ion with oxidation state 1+.

The second ionization energy is the energy to release a second electron and form the ion with oxidation state 2+.

The third ionization energy is the energy to leave a third electron free and form the ion with oxidation state 3+.

The relatively low first ionization energy of element 2, shows it  it will lose an electron easily to form the ion with oxidations state 1+.

The second and third ionization energies are very high meaning that the ions with oxidation staes 2+ and 3+ will not be formed.

Therefore, the answer is that the expected oxidation state for the most common ion of element 2 is 1+.

The chemical formula for table sugar is C12H11O22. What can you tell from this formula?

There are 22 protons in an oxygen atom.

There are 12 electrons in a carbon atom.

The ratio of oxygen atoms to hydrogen atoms in a molecule of sugar is 2 to 1.

The ratio of carbon atoms to hydrogen atoms in a molecule of sugar is 2 to 1.

Answers

I say the answer is The ratio of oxygen atoms to hydrogen atoms in a molecule of sugar is 2 to 1 

Answer: The correct answer is the ratio of oxygen atoms to hydrogen atoms in a molecule of sugar is 2 to 1.

Explanation:

The given chemical formula for table sugar is [tex]C_{12}H_{11}O_{22}[/tex].

The above compound contains 12 atoms of carbon atom, 11 atoms of hydrogen and 22 atoms of oxygen.

The ratio of oxygen atoms to hydrogen atoms is [tex]22:11::2:1[/tex] and the ratio of carbon atoms to hydrogen atoms in a molecule of sugar is [tex]12:11[/tex]

An oxygen atom contains 8 protons and a carbon atoms has 6 electrons.

Hence, the correct statement is the ratio of oxygen atoms to hydrogen atoms in a molecule of sugar is 2 to 1.

n the balanced equation 4Fe + 3O2à 2Fe2O3 , how many atoms of iron (Fe) are reacting with every three molecules of oxygen (O2)?

Answers

Answer is: four iron atoms are reacting with every three molecules of oxygen.
Balanced chemical reaction: 4Fe + 3O₂ → 2Fe₂O₃.
From chemical reaction: n(Fe) : n(O₂) = 4 : 3.
Ratios of atoms of iron and molecules of oxygen is 4 : 3..
There is four atoms of iron and six atoms of oxygen on both side of reaction.

Final answer:

Four atoms of iron (Fe) are reacting with every three molecules of oxygen (O₂) in the balanced chemical equation 4Fe + 3O₂ → 2Fe₂O₃.

Explanation:

In the balanced chemical equation 4Fe + 3O₂ → 2Fe₂O₃, for every three molecules of oxygen (O₂) that reacts, there are four atoms of iron (Fe) involved in that reaction. This is because the coefficients in the equation represent the stoichiometric ratios of the reactants and products. Hence, according to the coefficient in front of Fe, four atoms of iron react with three diatomic oxygen molecules to form two molecules of iron (III) oxide (Fe₂O₃).

Which acid is the best choice to create a buffer with ph= 3.19?

Answers

The best choice is hypochlorous acid nitrous acid (HNO2) because it has the nearest value of pK to the desired pH.
pKa of nitrous acid is 3.34 
If we know pKa and pH values,  we can calculate the required ratio of conjugate base (NO2⁻) to acid (HNO2) from the following equation:
pH=pKa + log(conc. of base)/( conc. of acid)
3.19=3.34 + log c(NO2⁻)/c(HNO2)
3.19 - 3.34 = log c(NO2⁻)/c(HNO2)
-0.15 = log c(NO2⁻)/c(HNO2)
c(NO2⁻)/c(HNO2) = 10⁰¹⁵ = 1.41

Which of the following substances is considered to be a base? A. HCl B. HNO3 C. H2SO4 D. Ca(OH)2

Answers

Among all of the choices listed, the only option that is a base would be the last one. As it is unique, whereby Hydrogen is not present in the front of the compound.

Bases also possess OH in their molecular formula.

Among the options given, Ca(OH)2 or calcium hydroxide is considered to be a base. Thus, the correct option for this question is D.

What do you mean by a base?

A base in chemistry is defined as a type of chemical substance that can significantly accept hydrogen ions in water and can neutralize an acid. Bases feel soapy or slippery on the skin in texture and they have the ability to turn certain dyes blue.

According to the context of this question, H2SO4 or sulphuric acid is the strongest acid along with HNO3 (nitric acid) and HCl (hydrochloric acid). An example of a base is sodium hydroxide. Basicity is measured on a scale called the pH scale.

Therefore, Ca(OH)2 or calcium hydroxide is considered to be a base. Thus, the correct option for this question is D.

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How many moles are in 226 g of Fe(NO2)2 ?

Answers

By getting the molar mass of Fe (NO2)2 = 55.85 + ((14+16*2))*2 = 147.85 g/mol

and we have the mass weight of Fe(NO2)2 = 226 g
SO we can get the no.of moles of Fe(NO2)2 from this formula:

∴ n= mass weight / molar mass
   = 226 / 147.85 = 1.53 mol

How many moles of caco3 are there in an antacid tablet containing 0.515 g caco3?

Answers

Answer:

[tex]0.00515molCaCO3[/tex]

Explanation:

Hello,

By following the down below simple mass-mole relationship, the requested moles are computed, considering that the calcium carbonate has a molecular mass of 100g/mol:

[tex]M_{CaCO3}=40+12+16*3=100g/mol\\\\n_{CaCO3}=0.515gCaCO3*\frac{1molCaCO3}{100gCaCO3}=0.00515molCaCO3[/tex]

Best regards.

Final answer:

To calculate the number of moles of CaCO₃ in a 0.515 g antacid tablet, divide the mass of the CaCO₃ by its molar mass, yielding approximately 0.005144 moles of CaCO₃.

Explanation:

To find the number of moles of CaCO₃ in an antacid tablet containing 0.515 g of CaCO₃, we need to use the molar mass of CaCO₃. The molar mass of CaCO₃ (calcium carbonate) is approximately 100.09 g/mol. To calculate the moles, we divide the mass of the sample by its molar mass.

The calculation is as follows:

Mass of CaCO₃ = 0.515 gMolar mass of CaCO₃ = 100.09 g/molNumber of moles = Mass / Molar massNumber of moles = 0.515 g / 100.09 g/mol = 0.005144 moles

Therefore, there are approximately 0.005144 moles of CaCO₃ in the antacid tablet.

A reaction produces 74.10 g Ca(OH)2 after 56.08 g CaO is added to 36.04 g H2O. How should the difference in the masses of reactants and products be explained?

Answers

Final answer:

The difference in masses of reactants and products in the reaction CaO + H2O → Ca(OH)2 could be due to measurement errors, presence of impurities, incomplete reactions, or factors such as the absorption of water if the product mass is greater than that of the reactants.

Explanation:

The 1:1 stoichiometry reaction you are referring to is CaO(s) + H2O(l) → Ca(OH)2(s). In this reaction, 56.08 g of CaO reacts with 36.04 g of H₂O to produce 74.10 g of Ca(OH)₂. The law of conservation of mass states that matter cannot be created or destroyed; hence the total mass of reactants should equal the mass of the products in a chemical reaction.

However, in realistic scenarios, there could be minor deviations due to aspects like measurement errors, the presence of impurities, or incomplete reactions. If the reaction goes to completion, and no gases are created (which may escape the reaction system), the masses should equal.

 

If the resulting mass of the product, Ca(OH)₂, is less than the combined mass of reactants, it suggests that there may be unreacted CaO or H₂O left. If the mass of Ca(OH)₂ is more than the reactants, it could suggest impurities, absorption of water, or some other factors at play.

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An excess of Ba(No3)2 reacts with 250ml of H2SO4 solution to give 0.55g of BaSo4.determine The concentration in moles per litre of the Ba(No3)2 solution?

Answers

Chemical reaction: Ba(NO₃)₂ + H₂SO₄ → BaSO₄ + 2HNO₃.
V(H₂SO₄) = 250 mL ÷ 1000 mL/L = 0,25 L.
m(BaSO₄) = 0,55 g.
n(BaSO₄) = m(BaSO₄) ÷ M(BaSO₄).
n(BaSO₄) = 0,55 g ÷ 233,38 g/mol.
n(BaSO₄) = 0,00235 mol.
From chemical reaction: n(BaSO₄) : n(Ba(NO₃)₂) = 1 : 1.
n(Ba(NO₃)₂) = 0,00235 mol.
c(Ba(NO₃)₂) = n(Ba(NO₃)₂) ÷ V.
c(Ba(NO₃)₂) = 0,00235 mol ÷ 0,25 L.
c(Ba(NO₃)₂) = 0,0095 mol/L.

Carbonic acid is a polyprotic acid. write balanced chemical equations for the sequence of reactions that carbonic acid can undergo when it's dissolved in water.

Answers

carbonic acid (H₂CO₃) dissociation in water takes place in 2 steps. its a polypro tic acid as it has 2 H⁺ ions it can donate.
the dissociation reactions in water are as follows;
H₂CO₃  + H₂O ---> HCO₃⁻ + H₃O⁺
in the first dissociation it releases a proton that combines with water to form a hydronium ion.
HCO₃⁻ + H₂O  ----> CO₃²⁻ + H₃O⁺
second dissociation results in the carbonate ion and hydronium ion formation.
As the ratio of acid dissociation constant ka1/ka2 > 10⁴ , dissociation takes place in 2 steps. 

The sequence of dissociation reactions of carbonic acid is a follows:

 [tex]\text{Step\;1:\;}\text{H}_2\text{CO}_3(aq)+\text{H}_2\text{O}(aq)\overset{\text{K}_{al}}\leftrightharpoons\text{HCO}_3^-(aq)+\text{H}_3\text{O}^+(aq)\\\text{Step\;2:\;}\text{H}_2\text{CO}_3^-(aq)+\text{H}_2\text{O}(aq)\overset{\text{K}_{al}}\leftrightharpoons\text{CO}_3^2\;(aq)+\text{H}_3\text{O}^+(aq)[/tex]

Further Explanation:

An acid is a substance that is able to donate a proton or hydrogen ion [tex]\left( {{{\text{H}}^ + }} \right)[/tex] in aqueous solutions. Hydrochloric acid (HCl), sulphuric acid [tex]\left( {{{\text{H}}_2}{\text{S}}{{\text{O}}_4}} \right)[/tex] and nitric acid [tex]\left( {{\text{HN}}{{\text{O}}_3}} \right)[/tex] are some examples of acids. On the basis of the number of protons an acid can donate, acids can be monoprotic or polyprotic.

Acids that can donate just one proton in aqueous solutions are called monoprotic acids. For example, HCl, [tex]{\text{HN}}{{\text{O}}_{\text{3}}}[/tex] and [tex]{\text{C}}{{\text{H}}_3}{\text{COOH}}[/tex] are monoprotic acids as these can donate only one proton in solutions.

Polyprotic acids can donate more than one proton in aqueous solutions. These can further be divided as diprotic, triprotic and so on. Diprotic acids are the ones that can donate two protons in solutions. For example, [tex]{{\text{H}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex] and [tex]{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}[/tex] are diprotic acids. Triprotic acids are capable to donate three protons in solutions. For example, [tex]{{\text{H}}_{\text{3}}}{\text{As}}{{\text{O}}_{\text{4}}}[/tex] and [tex]{{\text{H}}_3}{\text{P}}{{\text{O}}_4}[/tex] are triprotic acids.

Carbonic acid has the chemical formula of [tex]{{\text{H}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex]. So it dissociates into an aqueous solution, releasing protons or hydrogen ions in it. Since carbonic acid is a diprotic acid, its dissociation takes place in two steps.

Step 1: The first dissociation of [tex]{{\text{H}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex] occurs as follows:

 [tex]\text{H}_2\text{CO}_3(aq)+\text{H}_2\text{O}(aq)\overset{\text{K}_{al}}\leftrightharpoons\text{HCO}_3^-(aq)+\text{H}_3\text{O}^+(aq)[/tex]

Here, [tex]K_a_1[/tex] is the first dissociation constant of [tex]{{\text{H}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex].

Step 2: In the second dissociation, [tex]{\text{HCO}}_3^ -[/tex] dissociates as follows:

 [tex]\text{H}_2\text{CO}_3^-(aq)+\text{H}_2\text{O}(aq)\overset{\text{K}_{al}}\leftrightharpoons\text{CO}_3^2\;(aq)+\text{H}_3\text{O}^+(aq)[/tex]

Here, [tex]{K_{{\text{a2}}}}[/tex] is the first dissociation constant of [tex]{{\text{H}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex].

Learn more:

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Answer details:

Grade: High School

Chapter: Acid, base and salts.

Subject: Chemistry

Keywords: acids, monoprotic, polyprotic, HCl, H2CO3, H2SO4, HNO3, CH3COOH, dissociation, Ka1, Ka2.

A diels–alder reaction of 2,5-dimethylfuran and maleic anhydride gives a compound a that undergoes acid-catalyzed dehydration to give 3,6-dimethylphthalic anhydride.

Answers

The Diels-Alder reaction between 2,5-dimethylfuran and maleic anhydride produces a compound that can be dehydrated to form 3,6-dimethylphthalic anhydride. Maleic anhydride's electron-withdrawing groups and the s-cis configuration of the diene aid the reaction's efficiency and dictate the stereochemistry of the product.

The Diels-Alder reaction between 2,5-dimethylfuran and maleic anhydride is a classic example of a cycloaddition reaction in organic chemistry. This reaction forms a compound that, upon dehydration, can yield 3,6-dimethylphthalic anhydride. Maleic anhydride serves as an excellent dienophile due to the electron-withdrawing effect of the carbonyl groups making the alkene carbons electron-poor and thus more reactive. The s-cis configuration of the diene, as in the case with cyclopentadiene, enhances the reaction's efficiency.

The stereochemistry of the Diels-Alder reaction dictates that the product will generally prefer the endo position, and models can help visualize these reactions and their outcomes. Acid-catalyzed dehydration is commonly used in organic synthesis to generate -unsaturated carbonyl compounds, which can lead to structural rearrangements depending on the nature of the starting materials and reaction conditions.

Calculate the vapor pressure of a solution of 0.99 mol of cholesterol in 5.4 mol of toluene at 32°c. pure toluene has a vapor pressure of 41 torr at 32°c. (assume ideal behavior.)

Answers

Explanation:

No. of moles of cholesterol solute, [tex]n_{1}[/tex] = 0.99 mol

No. of moles of toulene solvent, [tex]n_{2}[/tex] = 5.4 mol

Hence, total number of moles of solution will be as follows.

                  n = [tex]n_{1} + n_{2}[/tex]

                     = 0.99 mol + 5.4 mol

                     = 6.39 mol

Therefore, mole fraction of cholestrol solute ([tex]\chi_{1}[/tex]) is as follows.

                = [tex]\frac{\text{no. of moles of chloesterol}}{\text{Total number of moles of solution (n)}}[/tex]  

     [tex]\chi_{1}[/tex] = [tex]\frac{0.99 mol}{6.39 mol}[/tex]

                      = 0.154

Vapor pressure of pure toulene solvent ([tex]p^{o}[/tex]) = 41 torr

Vapor pressure of solution = P

Hence, formula to calculate relative lowering of vapor pressure is as follows.

     Relative lowering of vapor pressure = [tex]\frac{p^{o} - P}{p^{o}}[/tex]

As per relative lowering of vapor pressure colligative property, the relative lowering of vapor pressure is equal to the mole fraction of solute.

Hence,     [tex]\frac{p^{o} - P}{p^{o}}[/tex] = [tex]\chi_{1}[/tex]

               [tex]\frac{41 torr - P}{41 torr}[/tex] = 0.154

                         41 torr - P = 6.314

                                      P = 34.686 torr

or,                                      = 35 torr

Therefore, we can conclude that vapor pressure of the solution is 35 torr.

Final answer:

To calculate the vapor pressure of a cholesterol-toluene solution, we use Raoult's Law, which gives a vapor pressure of approximately 34.65 torr at 32°C after calculating the mole fraction of toluene and applying the formula.

Explanation:

To calculate the vapor pressure of a solution containing 0.99 mol of cholesterol in 5.4 mol of toluene at 32°C, where pure toluene has a vapor pressure of 41 torr, we use Raoult's Law. This law states that the vapor pressure of a solution (Psolution) is equal to the mole fraction of the solvent (Xsolvent) times the vapor pressure of the pure solvent (Psolvent).

First, calculate the mole fraction of toluene, which is given by the number of moles of toluene divided by the total number of moles in the solution: Xtoluene = moles of toluene / (moles of toluene + moles of solute) = 5.4 / (5.4 + 0.99) = 5.4 / 6.39.

Next, apply Raoult's Law: Psolution = Xtoluene × Ptoluene = (5.4 / 6.39) × 41 torr. By calculating, we find Xtoluene is approximately 0.845, and thus Psolution = 0.845 × 41 torr = 34.645 torr. So, the vapor pressure of the solution is approximately 34.65 torr at 32°C.

) Calculate the molarity of a solution prepared by dissolving 117 g of sodium chloride (NaCl) in enough water to make 2.7 liters of solution.

Answers

The Molarity of the solution is given by:
[tex]Molarity = \frac{moles-of-solute}{liters-of-solution} [/tex] --- (A)

But NaCl, which is a solute, is given in grams.
Therefore, first, we need to convert grams into moles.

Molecular weight of NaCl = 58.44 grams/mole.

So,
117 grams * (moles/ 58.44 grams) = 2.00 moles of NaCl

Now that we have moles of NaCl, plug in the values in (A):
(A) => Molarity = (2 / 2.7 ) = 0.741 moles/litre

The correct answer is: 0.741 moles/litre = Molarity

A substance was analyzed in a laboratory. It was composed of three elements in a fixed ratio. The substance is an ?

Answers

Explanation:

A compound is defined as the substance which contains different type of elements that chemically combine together in a fixed ratio by mass.

For example, [tex]CaCl_{2}[/tex] is a compound as it contains calcium and chlorine which are different elements. And, both Ca and Cl are combining in 1:2 ratio.

And, for every molecule of calcium chloride these elements will always be present in 1:2 ratio.

Thus, we can conclude that when a substance was analyzed in a laboratory. It was composed of three elements in a fixed ratio. The substance is a compound.

Codeine (c18h21no3) is a weak organic base. a 5.0 x 10-3 m solution of codeine has a ph of 9.95. what is the pkb for this base

Answers

Answer is: pKb for codeine is 5,8.
Chemical reaction:  C₁₈H₂₁NO₃ + H₂O ⇄ C₁₈H₂₁NO₃H⁺ + OH⁻.
c(C₁₈H₂₁NO₃) = 5·10⁻³ M = 0,005 mol/L.
pH = 9,95.
pOH = 14 - 9,95 = 4,05.
[OH⁻] = 10∧(-4,05) = 0,000089 mol/L.
[OH⁻] = [C₁₈H₂₁NO₃H⁺] = 8,9·10⁻⁵ mol/L.
[C₁₈H₂₁NO₃] = 0,005 mol/L - 0,000089 mol/L = 0,004911 mol/L.
Kb = [OH⁻] · [C₁₈H₂₁NO₃H⁺] / [C₁₈H₂₁NO₃].
Kb = (0,000089 mol/L)² / 0,004911 mol/L = 1,613·10⁻⁶.
pKb = -log(1,613·10⁻⁶) = 5,8.

Add formal charges to each resonance form of hcno below.based on the formal charges you added above, which structure is favored?

Answers

Q1)
formal charges for atoms are assigned, this charge can be calculated using the following formula;
f.c = number of valence electrons - non bonding electrons around the atom - number of bonds

3 structures have been given, lets calculate for each structure 
A. 
charges for the atoms 
 H = 1-0-1=0
C = 4 -4-2 = -2
N = 5 - 0-4 = 1
O = 6 - 2 - 3 = 1

B.
H = 1-0-1 = 0
C = 4 - 0 - 4 =0
N = 5 - 0 - 4 = 1
O = 6 - 6 - 1 = -1

C.
H = 1-0-1 = 0
C = 4 - 2 - 3 = -1
N = 5 - 0 - 4 = 1
O = 6 - 4 - 2 = 0

Q2)
next we need to see which structure is most favoured.
the structure with least number of atoms that have a charge.
structure B and C have 2 atoms with charges whereas A has three atoms with charges, including an atom with -2 charge which is not common. so structure A can be disregarded.
another rule is that the more electronegative atom should have the more negative charge than less electronegative atoms. In structure C, Carbon the less electronegative atom compared to N and O, has -1 value and its more negative than the charges on N and O.
structure B on the other hand, O the more electronegative atom has -1 charge and C has 0 charge. Therefore the more favoured structure is B.

Answer:

The second structure is the most stable of all three.

Explanation:

The Formal Charge in the different resonance structures of HCNO is,

[tex]\rm FC=V-N+B[/tex]

Where,

FC- Formal charge

V- Valence Electron

N- Non-bonding Electron

B- Number of bonds

So,  Formal charge In the atoms of first resonance structure is

H = 1-0+1=0

C = 4 -4+2 = -2

N = 5 - 0+4 = 1

O = 6 - 2 + 3 = 1

Formal charge In the atoms of Second resonance structure is

H = 1-0+1 = 0

C = 4 - 0 + 4 =0

N = 5 - 0 + 4 = 1

O = 6 - 6+1 = -1

Formal charge In the atoms of Third resonance structure is

H = 1-0 + 1 = 0

C = 4 - 2 +3 = -1

N = 5 - 0 + 4 = 1

O = 6 - 4 +2 = 0  

To Figure out the most stable resonance structure we have to keep two things in mind:

1) The stable molecular structure tend to have the least number of charged atom.

2) In a stable molecular structure the negative charge is present in the more electronegative atom.

Here decreasing order of electronegativity is,

 N > O > C > H

From the Explanation above, the second structure (B) follows both points

Therefore, The second structure is the most stable of all three.

For more details, you can refer to the link:

https://brainly.com/question/23287285?referrer=searchResults

PLEASE HELP! Which clade is composed of eukaryotes which are multicellular and heterotrophs? A) Eubacteria B) Fungi C) Plant D) Animals

Answers

I think your answer would be D

Answer: D) Animals

Explanation:

Eukaryotic organisms are those organisms which exhibit complex cellular composition. They exhibit membrane bound organelles and nucleus is also enclosed inside a membrane which encloses the genetic material of the organisms. Examples include plants, animals and fungi.

Multicellular organisms are those which exhibit multiple layers of the cells to perform a specialized function.

Hetrotrophic organisms are those which are dependent upon other organisms for their food and nourishment.

Among the given options, Animals is the correct option. This is due to the fact that all animals are eukaryotic organisms as they have a membrane bound nucleus and other cellular organelles. All animals are multicellular because of the fact that multicellular system is necessary for performing specialized functions required for survival. They are incapable of synthesizing their own food either by chemosythesis or photosynthesis. They are dependent upon other organisms like plants and other animals for their food.

Which substance found in fossil fuels can form a harmful acid when the fuel is burned?

Answers

fossil fuels are mainly organic compounds.Combustion of fossil fuels also produces other air pollutants, such as nitrogen oxides, sulfur dioxide, volatile organic compounds and heavy metals.so,substances which contain sulphur cause to form harmful acids like sulphuric and sulphurus acids

Answer is: sulfur.

Fossil fuel combustion increases the acidity of rain because the sulfur dioxide is produced.  

Because of fuel combustion, sulfur dioxide goes up into the atmosphere as the hot gases rise, than it reacts with water and oxygen in the air and form sulfuric acid:  

Balanced chemical reaction: SO₂(g) + 2O₂(g) + 2H₂O → 2H₂SO₄.  

pH (potential of hydrogen) is a numeric scale used to specify the acidity or basicity an aqueous solution.

When pH is less than seven (pH<7), solution is acidic.

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