If a gas is heated from 263 to 298 k, the volume is 24 l to 35 l at 1.00 atm pressure. what is the final pressure?

Answers

Answer 1
There is a formula for this:
P1*V1/T1=P2*V2/T2

just plug in the numbers and solves!!
if you have any more issues, let me know!!
Answer 2

If a gas is heated from 263 to 298 k, the volume is 24 l to 35 l at 1.00 atm pressure. Then, the final pressure is approximately 0.725 atm.

We, can use the combined gas law. This law relates the pressure, volume, and temperature of a gas with the formula (P₁ x V₁)/T₁ = (P₂ x V₂)/T₂, where P is pressure, V is volume, and T is temperature in Kelvin.

First, we will plug in the initial conditions:

Initial pressure (P₁) = 1.00 atmInitial volume (V₁) = 24 LInitial temperature (T₁) = 263 KFinal volume (V₂) = 35 LFinal temperature (T₂) = 298 K

We want to find the final pressure (P₂), so we rearrange the formula to solve for P₂:

After plugging in the values:

P₂ = (1.00 atm x 24 L x 298 K) / (35 L x 263 K)

P₂ ≈ 0.725 atm

Therefore, the final pressure of the gas is approximately 0.725 atm after it is heated and the volume expands.


Related Questions

was the supernova named after kepler becausae he was the first person to see it

Answers

Hi, the super nova was named after Johannes Kepler because he was the first person to discover it. He discovered it in 1604.

Which example best demonstrates the benefit of understanding physical properties?

Engineers can design safer structures because they understand flammability of building materials

Engineers can design better bridges because they know how metal changes shape

Scientists can easily classify mixtures of unknown substances

Scientists can predict how well two substances will react

Answers

I'd assume the second one because all the others deal with a chemical property. Not 100% sure. Please let me know. :)

Answer:  Engineers can design better bridges because they know how metal changes shape.

Explanation:  Physical Properties are those properties which are also regarded as observable because they can be easily seen or observe through naked eyes like melting point etc.

These are those properties which do not change chemical identity of the species.

Thus out of the given options, only physical property is the change of shape of metal.

And the rest one represents the chemical property as chemical property are the one which changes the chemical identity of the substance.

The total amount of living tissue within a given trophic level is called the select one:
a. organic mass.
b. trophic mass.
c. energy mass.
d. biomass.

Answers

Answer is D- biomass

Biomass indicates that how does the energy flow within tropic levels. It is the amount of energy that a tropic level has consumed. That can be shown in a biomass pyramid. Second tropic level gets the 10% percent of energy from the first tropic level's biomass. Hence from bottom to top levels of the food chain, the biomass decreases.
Final answer:

The correct term for the total amount of living tissue within a given trophic level is biomass. It encompasses the weight of all living organisms within an ecosystem or a specific trophic level. The answer to the student's query is thus d. biomass.

Explanation:

The total amount of living tissue within a given trophic level is referred to as the biomass. Biomass can be considered as the weight of all living organisms within a particular ecosystem or at a specific trophic level. This includes animals, plants, microorganisms and all other living things. For example, in a forest ecosystem, the biomass includes everything from the massive trees to the tiny fungi and bacteria within the soil. Therefore, the answer to the student's question is d. biomass.

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Which coefficients correctly balance the formula equation nh4no2(s)® n2(g) + h2o(l)?

Answers

NH4NO2(s)---> N2(g) + 2H2O(l)

2 is the coefficient that correctly balance the formula equation: NH4NO2 → N2 + H2O.

BALANCING CHEMICAL EQUATION:A balanced equation is one in which the atoms of each element on both sides of the equation are the same.

According to this question, the following unbalanced decomposition reaction is given: NH4NO2 → N2 + H2O

To balance the equation, we make use of coefficients, which are numbers placed in front of the corresponding element or compound involved.

The balanced equation is as follows: NH4NO2 → N2 + 2H2O. This equation shows that 2 is the coefficient placed in front of H2O to correctly balance the equation.

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If the thorium-232 isotope emits an alpha particle, what would be the atomic number of the resulting atom?

Answers

Answer is: atomic number of resulting atom is 88.
Alpha particle is nucleus of a helium-4 atom, which is made of two protons and two neutrons.
Nuclear reaction: ²³²Th → ²²⁸Ra + α (alpha particle).

Alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.

What is the final concentration of a solution prepared by diluting 35.0 ml of 12.0 m hcl to a final volume of 1.20 l? what is the final concentration of a solution prepared by diluting 35.0 ml of 12.0 m hcl to a final volume of 1.20 l?

Answers

We know that, M1V1     =     M2V2
                        (Initial)          (Final)
where, M1 and M2 are initial and final concentration of soution respectively. 
V1 and V2 = initial and final volume of solution respectively

Given: M1 = 12 m, V1 = 35 ml and V2 = 1.2 l = 1200 ml

∴ M2 = M1V1/V2 = (12 × 35)/ 1200 = 0.35 m
Final concentration of solution is 0.35 m
Final answer:

The final concentration of the solution prepared by diluting 35.0 ml of 12.0 M HCl to a final volume of 1.20 L is 0.35 M.

Explanation:

The final concentration of a solution prepared by diluting 35.0 ml of 12.0 M HCl to a final volume of 1.20 L can be calculated using the formula for dilution: M1V1 = M2V2. In this formula, M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.

Firstly, we convert the initial volume from ml to litres because the final volume is given in litres. So, 35.0 ml = 0.035 L. Therefore, the equation becomes: 12.0 M * 0.035 L = M2 * 1.20 L.

On rearranging the equation to solve for M2, the result is 0.35 M.

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Please Help! Will given Brainliest!
What is the product when Bismuth (symbol Bi, atomic number 83, and radioisotope with a mass number of 214) emits an alpha particle? Give name or symbol of new element, its atomic number, and its mass number for full credit. Show work.

Answers

Thallium is the new element
Its symbol is TI
Atomic number is 81
Mass number is 204.3

Answer : The correct answer is Name = Thallium (Th) , atomic mass = 210 and atomic number = 81 .

Alpha decay :

When atomic nucleus emits an alpha particle that process is known as alpha particle decay . The symbol of alpha particle is [tex] _2^4He [/tex] , where 4 is atomic mass ( 2 protons + 2 neutrons ) and 2 atomic number .

When alpha particle is released the resultant nuclei (daughter nuclei) have 4 less atomic mass and 2 less atomic number .

Example for nuclear equation of alpha decay can be expressed as:

[tex] ^{230}_{90}Th \rightarrow _2^4He + ^{226}_{88}Ra [/tex]

Given :

Radioisotope = Bi Atomic mass = 214 Atomic number = 83

When it will release alpha particle , atomic mass will be decreased by 4 and atomic number by 2 .

Atomic mass = 214 - 4 = 210 Atomic number = 83-2 = 81

The atom with atomic number 81 is Thallium (Tl) . Hence the daughter nuclei so produced is [tex] ^{210}_{81}Tl [/tex]

The nuclear reaction can be written as :

[tex] ^{214}_{83}Tl \rightarrow ^4_2He + ^{210}_{81}Tl [/tex]




What is the volume, in liters, of 576 grams of so2 gas at stp?

Answers

The volume  in  liters  of  576 grams  of SO2  gas  at STP  is   calculated as below

calculate the moles of SO2 = mass/molar  mass

= 576 g/64 g /mol  = 9 moles

At  STP  1mole =22.4 L
what  9 mole =? liters

by cross  multiplication

= 22.4 L x  9 moles/ 1moles = 201.6 liters

The volume of 576 grams of SO₂ gas at STP is approximately [tex]\( 200 \, \text{L}} \).[/tex]

To find the volume of 576 grams of SO₂ gas at STP (Standard Temperature and Pressure), we can use the ideal gas law equation:

[tex]\[ PV = nRT \][/tex]

Where:

- P is the pressure (at STP, [tex]\( P = 1 \)[/tex] atm)

- V is the volume of the gas

- n is the number of moles of gas

- R is the ideal gas constant [tex](\( R = 0.0821 \, \text{Latm/(molK)} \))[/tex]

- T is the temperature in Kelvin (at STP, [tex]\( T = 273.15 \)[/tex] K)

First, calculate the number of moles [tex]\( n \)[/tex] of SO₂ gas:

1. Calculate the molar mass of SO₂:

  - Atomic mass of S = 32.07 g/mol

  - Atomic mass of O = 16.00 g/mol (there are 2 oxygen atoms)

  - Molar mass of SO₂ = [tex]\( 32.07 + 2 \times 16.00 = 64.07 \)[/tex] g/mol

2. Convert grams of SO₂ to moles:

[tex]\[ n = \frac{\text{mass}}{\text{molar mass}} = \frac{576 \, \text{g}}{64.07 \, \text{g/mol}} \approx 9.00 \, \text{mol} \][/tex]

Now, use the ideal gas law to find the volume V:

[tex]\[ V = \frac{nRT}{P} \][/tex]

[tex]\[ V = \frac{9.00 \, \text{mol} \times 0.0821 \, \text{Latm/(molK)} \times 273.15 \, \text{K}}{1 \, \text{atm}} \][/tex]

[tex]\[ V \approx 200 \, \text{L} \][/tex]

What type of intermolecular forces exist between br2 and ccl4?

Answers

Induced dipole - induced dipole.
Final answer:

The intermolecular forces between Br2 and CCl4 are London dispersion forces, as both substances are nonpolar molecules.

Explanation:

The intermolecular forces that exist between Br2 and CCl4 are London dispersion forces. These are the weakest type of intermolecular force and exist between all molecules, irrespective of whether they are polar or nonpolar. Br2 and CCl4 both are nonpolar molecules, so they don't exhibit dipole-dipole attractions, which are typically stronger than dispersion forces.

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2) Pick the statement about the Bohr model of the hydrogen atom that is NOT true. A) The energy of each Bohr orbit is quantized. B) An electron in a stationary state does not emit radiation. C) When an electron jumps to a higher state, energy is absorbed. D) When an electron jumps from one state to another, the electron must gain or lose just the right amount of energy to actually travel the distance between the orbits.

Answers

Answer: When an electron jumps from one state to another, the electron must gain or lose just the right amount of energy to actually travel the distance between the orbits.

Explanation:

Bohr in his structure of atom explained that protons which are positively charged particles and neutrons which are neutral particles,  are contained in the center of an atom called as nucleus.

The electrons which are negatively charged particles revolve around the nucleus in fixed orbit or shell or energy levels which are termed as quantized. These energy levels are stable and are stationary along with different energy value.  The electron remains in the state until energy is absorbed or released.

The electrons absorb energy when it moves from lower energy state to higher energy state. The electrons lose energy when it moves from higher energy state to lower energy state and thus emit radiations corresponding to the energy gap.

Thus the statement  when an electron jumps from one state to another, the electron must gain or lose just the right amount of energy to actually travel the distance between the orbits is incorrect because energy is absorbed when electron jumps from one state to another.

The energy is lost when electron falls from one state to another.

Answer: An electron in a stationary state does not emit radiation

Explanation:

I put that on usa test prep and it says correct. the other person who answered this is wrong

Two clear solutions are placed in separate beakers. The first solution has a pH of 4, and the pH of the second solution is unknown. If the two solutions are mixed and the resulting pH is 5, the second solution must have

Answers

The pH of the second solution, given that the mixture of the two solution has a pH of 5, is 4.05

How to calculate the pH of the second solution?

First, we shall obtain the hydogen ion, [tex]H^+[/tex] of the first solution and the mixture solution. Details below:

For first solution:

pH of first solution = 4Hydrogen ion [tex]H^+[/tex] of first solution =?

[tex]H^+ = Antilog (-4)\\\\H^+ = 0.0001\ M\\\\[/tex]

For mixture solution:

pH of mixture solution = 5Hydrogen ion [tex]H^+[/tex] of mixture solution =?

[tex]H^+ = Antilog (-5)\\\\H^+ = 0.00001\ M\\\\[/tex]

Now, we shall obtain the [tex]H^+[/tex] of the second solution. Details below:

Hydrogen ion [tex]H^+[/tex] of first solution = 0.0001 MHydrogen ion [tex]H^+[/tex] of mixture solution = 0.00001 MHydrogen ion [tex]H^+[/tex] of second solution =?

[tex]H^+[/tex] of second solution = [tex]H^+[/tex] of first solution -  [tex]H^+[/tex] of mixture solution

= 0.0001 - 0.00001

= 0.00009 M

Finally, we shall calculate the pH of the second solution. Details below:

Hydrogen ion [tex]H^+[/tex] of second solution = 0.00009 MpH of second solution = ?

pH = -Log Hydrogen ion [tex]H^+[/tex]

pH = -Log 0.00009

pH = 4.05

This is a specific type of dipole-dipole force that exists between molecules with hydrogen atoms and molecules with nitrogen, oxygen or fluorine atoms

Answers

Answer:  This description refers to:  "hydrogen bonding" .
______________________________________________________

         
 Hydrogen bonding   is a specific type of "dipole-dipole force" that exists between  [molecules with hydrogen atoms]  and  [molecules with nitrogen, oxygen, or fluorine atoms.] .
______________________________________________________

Answer:

This is a specific type of dipole-dipole force is known as Hydrogen bonding.

Explanation:

Hydrogen bonding (H-bonding) is an intermolecular force having partial ionic-covalent character. H-bonding takes place between a hydrogen atom attached with an electronegative atom( like : O, N and F) and lone pairs of electrons on an neighboring atoms.

Generally this type of bonding is observed where atoms like nitrogen , oxygen, fluorine attached to another molecule are present in neighbors of a hydrogen atom attached to other molecule. This bonding arises due to the interaction between the  developed partial positive and negative charges on the hydrogen and electronegative atoms.

During which of the following processes does a glucose molecule break down into ethanol? Aerobic respiration, Alcoholic fermentation, Lactic acid fermentation, Photosynthesis

Answers

alchoholic fermentation

Answer:

Alcoholic fermentation

Explanation:

Alcoholic fermentation is an anaerobic process executed by yeasts, molds and some bacteria, which cause chemical changes in organic substances.

Alcoholic fermentation has the biological function of supplying energy to microorganisms in the absence of oxygen. To achieve this, the glucose molecules are dissociated and in this way the energy required to survive is obtained, producing ethanol and CO2 as products.

What effect does the specific heat capacity of water have on weather?

A. It keeps the temperatures on the coast milder.
B. It lowers the temperature at which ocean water freezes.
C. It stops convection currents from turning into storms.
D. It increases the effect of radiation heating of land.

Answers

It keeps the temperatures on the coast milder.

Given the balanced equation: 3fe3+(aq) + al(s) → 3fe2+(aq) + al3+(aq)what is the total number of moles of electrons lost by 2 moles of al(s)?

Answers

Answer is: the total number of moles of electrons lost by two moles of aluminium are six moles (6 mol).
Oxidation half reaction: Al° → Al³⁺ + 3e⁻, lost of electrons.
Reduction half reaction: Fe³⁺ + e⁻→ Fe²⁺ /·3; 3Fe³⁺ + 3e⁻→ 3Fe²⁺; gain of electrons.
One mole of aluminium lost 3 moles of electrons, so 2 moles of alumiunim:
2 · 3 mol = 6 mol.

What is MC2 minus 8?

A. MC2
B. 4
C. 9
D. None of the above

Answers

It’s B , I guess..Good afternoon!

Answer:

d

Explanation:

What mass of CaCO3 is required to react completely with 0.56 L of HCl?

Answers

the balanced equation for the above reaction is as follows;
CaCO₃ + 2HCl ----> CaCl₂ + H₂O + CO₂
stoichiometry of CaCO₃ to HCl is 1:2
molar volume states that 1 mol of any gas occupies a volume of 22.4 L at STP.
volume of 22.4 L occupied by 1 mol
therefore 0.56 L occupied by - 0.56 L / 22.4 L/mol = 0.025 mol
number of HCl moles reacted - 0.025 mol
2 mol of HCl reacts with 1 mol of CaCO₃
therefore 0.025 mol reacts with - 0.025/2 = 0.0125 mol 
mass of CaCO₃ required - 0.0125 mol x 100 g/mol = 1.25 g 
1.25 g of CaCO₃ is required 

The law of conservation of mass and how it applies to chemical changes

Answers

The law of conservarion of mass states that mass can neither be destroyed nor created, but only changed into other forms. So through chemical reactions, the chemical makeup may change but the amount of substance is still equal to the sum of the amount of original chemicals before the reaction.

According to law of conservation of mass, mass is neither created nor destroyed and hence for a chemical reaction the mass of reactants and products is equal.

What is law of conservation of mass?

According to law of conservation of mass, it is evident that mass is neither created nor destroyed rather it is restored at the end of a chemical reaction .

Law of conservation of mass and energy are related as mass and energy are directly proportional which is indicated by the equation E=mc².Concept of conservation of mass is widely used in field of chemistry, fluid dynamics.

Law needs to be modified in accordance with laws of quantum mechanics under the principle of mass and energy equivalence.This law was proposed by Antoine Lavoisier in the year 1789.

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How can i use gland and hormone in a same sentence.?

Answers

You can go like bla..bla.. Gland produces bla.. Bla... Hormone.

What is the total pressure of a gaseous mixture that contains three gases with partial pressures of 0.845 atm, 120 torr and 210 mm hg? 972 torr 0.411 atm 331 torr 1175 torr?

Answers

partial pressure is the pressure that is exerted by individual gases. 
Partial pressure is calculated as the product of total pressure by the mole fraction of the corresponding gas. 
pressures exerted by gases are in three different units, therefore we can convert them all into a common unit - torr
1 - 0.845 atm - 0.854 atm x 760 Torr/atm = 642 torr
2 - 120 torr
3 - 210 mmHg - 1 mmhg is almost equivalent to 1 torr - therefore its 210 torr
total pressure - 642 + 120 + 210 = 972 torr

answer is 972 torr

For an equal mass of each substance, which one will require the least amount of heat to raise its temperature from 20°c to 30°c?

Answers

The substances in question are attached:

and the one will require the least amount of heat to raise its temperature from 20°c to 30°c is the one has the smallest heat capacity which is glass in this case

So the correct answer is B. Glass

a 45.0-ml sample of nitric acid solution is neutralized by 119.4 ml 0.200M NaOH solution. What is the molarity of the nitric acid solution?

Answers

The molarity  of nitric  acid  solution  is = 0.53M

calculation

calculate the  moles   of NaOH

moles =  molarity  x volume
= 119.4  x0.200 =  23.88 moles

write the   equation for reaction

NaOH  +HNO3  = NaNO3  +H2O

by  use of mole  ratio  between  NaOH  to  HNO3   which is 1:1  the  moles of HNO3  is also = 23.88 moles

molarity = moles/volume

23.88/45  =  0.53 M

A sample of a compound contains 60.0 g C and 5.05 g H. Its molar mass is 78.12 g/mol. What is the compound’s molecular formula? CH C2H2 C6H6 C6H

Answers

Step 1: Calculate Moles for each Element:

Mole of C  =  60.0 / 12  =  5

Mole of H  =  5.05 / 1.008  =  5.009

Step 2: Calculate Mole Ratio:
                                             Divide each mole value with least mole value.

                                 H     :      C

                     5.009/5       :     5/5

                                  1    :     1
So,
           Empirical Formula  =  C₁H₁ or CnHn      ------ (1)

Step 3: Calculate Molecular Formula:
By using formula,
                               n  =  Molecular Mass / Empirical Formula Mass

Molecular Mass  =  78.12 g/mol

Empirical Formula Mass  =  12 + 1  = 13          ∴ C = 12 & H = 1
So,
                               n  =  78.12 / 13 

                               n  =  6

Putting value of n in eq. 1,
  
                                                  C₆H₆
Result:
            
The correct answer is C₆H₆.

A sample of a compound contains 60.0 g C and 5.05 g H.

divide by molar mass of C(12) and H(1) to get molar ratio

C: 60/12=5 and H: 5/1=5

so C:H=5:5=1:1

total molar mass=78

divide by 1C+1H to find the formula: 78/(12+1)=78/13=6

compound is C6H6


If the number of particles in a mole is 6.022x1023, what is the total mass of 1.81×1024 particles of nitrogen gas (N2)?
A. 42 g
B. 4.2 g
C. 84 g
D. 8.4 g

Answers

 the total mass  of 1.81 x10^24  particle  nitrogen  gas  is calculated as follows

find the moles of nitrogen

1 moles = 6.022 x10 ^23  particles
what about 1.81 x10^23 =? moles

= (1.81 x10^ 24)/(6.022 x10^23) = 3 moles

mass = moles x molar mass of nitrogen gas = 14 x2 = 28 g/mol

= 3  moles x28 g/mol = 84 grams

Answer:

56 g

Explanation:

According to the Arrhenius theory a substance that yields hydrogen ions as the only ion in an aqueous solution is

Answers

According to the Arrhenius theory a substance that yields hydrogen ions as the only ion in an aqueous solution is Acid.

What are acids?

Acids are those substances which are having pH range from 0 to 7.

According to the Arrhenius theory of acid and base, acids are those compounds which donate H⁺ ion or proton in the aqueous medium and bases are those substances which donate OH⁻ ion in the aqueous medium.

Example of Arrhenius acids are HCl, CH₃COOH, HNO₃, etc.

Hence, those substance which yields H⁺ ions is acids.

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How can the spontaneous redox reaction of a voltaic cell be reversed?

Answers

The spontaneous redox reaction can be reversed by applying an outside current greater than the maximum voltage capacity of the cell.

Which will diffuse through a membrane more rapidly, co or n2? assume that the samples contain only the most abundant isotopes of each element, 12c, 16o, and 14n?

Answers

I think the answer for the above question is none.  The two gases will diffuse at the same rate; simply because they have the same molecular mass. N2 = 28 g and CO = 28 g. From the Graham's law, the rate of diffusion of a fixed mass of a gas is inversely proportional to the square root of its molecular mass. The heavier the gas is the lower the rate of diffusion and vicevarsa. 

Answer: Both will diffuse at the same rate

Explanation:

According to Graham's law, the rate of diffusion is inversely proportional to the square root of the relative molecular mass of the gases. The two gases, carbon II oxide and nitrogen gas has the same relative molecular mass (28). This implies that they must diffuse at the same rate through an membrane.

During glycolysis, for every 6 moles of glucose that enter the pathway, how many moles of atp are used? how many moles atp are generated? how many moles of nadh are used? how many moles of pyruvate are made?

Answers

During the process of glycolysis 1 mole of glucose yields 2 pyruvic acid. In the process 2 ATPs molecules are used up and 4 other ATP molecules are produced by substrate level phosphorylation and 2 NADH are also produced. Therefore; for six moles of glucose; 12 ATP molecules will be used up, 24 ATP molecules will be generated, 12 moles of NADH will be used and 12 moles of pyruvate are made. 

In the reaction: pb + 2ag+ → pb2+ + 2ag, the oxidizing agent is

Answers

With reference to present question, following things may be noted
1) Oxidation is process of lose of electron. Atom//ion undergoing oxidation is refereed as reducing agent
2) Reduction is process of gain of electron. Atom/ion undergoing reduction is refereed as oxidizing agent.

in present system, Ag+ gain an electron to reduced to Ag. Therefore, Ag+ is an oxidizing agent. 

Answer: The oxidizing agent for the given reaction is Silver.

Explanation:

Oxidizing agent is defined as the agent which helps the other substance to get oxidized and itself gets reduced. It undergoes reduction reaction in which a substance gains electrons. The oxidation state of this substance gets reduced and the substance gets reduced.

Reducing agent is defined as the agent which helps the other substance to get reduced and itself gets oxidized. It undergoes oxidation reaction in which a substance looses its electrons. The oxidation state of this substance gets increased and the substance gets oxidized.

For the given chemical reaction:

[tex]Pb+2Ag^+\rightarrow Pb^{2+}+2Ag[/tex]

The half reactions for the given above chemical reaction is:

Oxidation half reaction:  [tex]Pb\rightarrow Pb^{2+}+2e^-[/tex]

Reduction half reaction: [tex]2Ag^++2e^-\rightarrow 2Ag[/tex]

As, lead is loosing electrons. So, it is getting oxidized and is considered as a reducing agent and silver is gaining electrons. So, it is getting reduced and is considered as an oxidizing agent.

Thus, the correct answer is silver.

10) In order to make spaghetti cook faster, a chef adds salt to water. How many moles of salt would he need to add to 1.0 kg water to make the water boil at 105 C? The Kb for water is 0.25°C/m. Assume i 2 for NaCl

Answers

The answer is 4.9 moles.
Solution: 
Using the equation for boiling point elevation Δt,
     Δt = i Kb m 
we can rearrange the expression to solve for the molality m of the solution:
     m = Δt / i Kb 

Since we know that pure water boils at 100 °C, and the Ebullioscopic constant Kb for water is 0.512 °C·kg/mol, 
     m = (105°C - 100°C) / (2 * 0.512 °C·kg/mol)
         = 4.883 mol/kg 

From the molality m of the solution of salt added in a kilogram of water, we can now find the number of moles of salt: 
     m = number of moles / 1.0kg
     number of moles = m*1.0kg 
                                  = (4.883 mol/kg) * (1.0kg)
                                  = 4.9 moles

The chef would need to add approximately 555.2 moles of salt NaCl to 1.0 kg of water to raise its boiling point to 105°C.

To determine how many moles of salt NaCl are needed to raise the boiling point of 1.0 kg of water to 105°C, we can use the concept of boiling point elevation and the colligative property of solutions.

Given data.

- Mass of water, [tex]\( m = 1.0 \) kg = \( 1000 \) g\\[/tex]

- Desired boiling point of water,[tex]\( T_{\text{new}} = 105 \)°C[/tex]

- Boiling point constant for water,[tex]\( K_b = 0.25 \) °C/m[/tex]

- Van't Hoff factor for NaCl [tex]\( i \) = 2 since NaCl dissociates completely into Na+ and Cl- ions in water[/tex]

First, calculate the change in boiling point [tex]\( \Delta T_b \)[/tex] using the formula for boiling point elevation

[tex]\[ \Delta T_b = i \cdot K_b \cdot m_{\text{salt}} \][/tex]

where.

- [tex]\( i \)[/tex] is the Van't Hoff factor,

- [tex]\( K_b \)[/tex] is the boiling point elevation constant,

- [tex]\( m_{\text{salt}} \)[/tex] is the molality of the salt in the solution.

To find [tex]\( m_{\text{salt}} \)[/tex], rearrange the equation:

[tex]\[ m_{\text{salt}} = \frac{\Delta T_b}{i \cdot K_b} \][/tex]

Calculate [tex]\( \Delta T_b \):[/tex]

[tex]\[ \Delta T_b = T_{\text{new}} - T_{\text{normal}} = 105 \text{°C} - 100 \text{°C} = 5 \text{°C} \][/tex]

Substitute the values into the equation.

[tex]\[ m_{\text{salt}} = \frac{5 \text{ °C}}{2 \cdot 0.25 \text{ °C/m}} \][/tex]

[tex]\[ m_{\text{salt}} = \frac{5}{0.5} \][/tex]

[tex]\[ m_{\text{salt}} = 10 \text{ mol/kg} \][/tex]

This molality [tex]10 mol/kg[/tex] represents the number of moles of salt per kilogram of solvent water.

To find the moles of salt [tex]\( n_{\text{salt}} \)[/tex] needed.

[tex]\[ n_{\text{salt}} = m_{\text{salt}} \cdot \frac{m_{\text{water}}}{M_{\text{water}}} \][/tex]

where.

[tex]- \( m_{\text{water}} \) is the mass of water[/tex],

[tex]- \( M_{\text{water}} \) is the molar mass of water.[/tex]

Calculate [tex]\( M_{\text{water}} \)[/tex].

[tex]\[ M_{\text{water}} = 18.015 \text{ g/mol} \][/tex]

Convert [tex]\( m_{\text{water}} \) to grams[/tex].

[tex]\[ m_{\text{water}} = 1000 \text{ g} \][/tex]

calculate [tex]\( n_{\text{salt}} \)[/tex].

[tex]\[ n_{\text{salt}} = 10 \text{ mol/kg} \cdot \frac{1000 \text{ g}}{18.015 \text{ g/mol}} \]\\[/tex]

[tex]\[ n_{\text{salt}} = 10 \cdot \frac{1000}{18.015} \text{ mol} \][/tex]

[tex]\[ n_{\text{salt}} \approx 555.2 \text{ mol} \][/tex]

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