if
[tex] \frac{a + ib}{c + id} [/tex]
is purely real complex number then prove that: ad=bc​

Answers

Answer 1

Rewrite the given number as

[tex]\dfrac{a+ib}{c+id}=\dfrac{(a+ib)(c-id)}{(c+id)(c-id)}=\dfrac{ac+bd+i(bc-ad)}{c^2+d^2}[/tex]

If it's purely real, then the complex part should be 0, so that

[tex]\dfrac{bc-ad}{c^2+d^2}=0\implies bc-ad=0\implies\boxed{ad-bc}[/tex]

as required.


Related Questions

Which equation produces a line that is parallel to the line represented by the function below?

y= 2/5x + 9

A. y= 5x + 2y = 4
B. y= 2x - 5y = 8
C. y= 5x - 2y = -3
D. y= 2x + 5y = -7

Answers

Answer:

B.

I ignored the extra y= part in each equation.

Step-by-step explanation:

The line given is in slope-intercept form, y=mx+b where m is slope and b is y-intercept.

Parallel lines have the same slope.

So the slope of y=(2/5)x+9 is m=2/5.

So we are looking for a line with that same slope.

In slope-intercept form the line would by y=(2/5)x+b where we do not know b since we weren't given a point.

So all of the choices are written in standard form ax+by=c where a,b, and c are integers.

We want integers so we want to get rid of that fraction there.  To do that we need to multiply both sides of y=(2/5)x+b for 5.  This gives us:

5y=2x+5b

Subtract 2x on both sides:

-2x+5y=5b

Now of the coefficients of x in your choices is negative like ours is. So I'm going to multiply both sides by -1 giving us:

2x-5y=-5b

Compare

2x-5y=-5b to your equations.

A doesn't fit because it's left hand side is 5x+2y.

B fits because it's left hand side is 2x-5y.

C doesn't fit because it's left hand side is 5x-2y.

D doesn't fit because it's left hand side is 2x+5y.

I ignored all the extra y= parts in your equations.

From a jar of pennies, 1290 are drawn, marked, and returned to the jar. After mixing,
a sample of 200 pennies is drawn and it was noticed that 50 were marked. Use this
information to predict how many pennies are in the jar.
od to the pain after mising
a) 1,490
b) 258,000
c) 5,160

Answers

Answer:

c) 5,160

Step-by-step explanation:

If from a jar of pennies, 1290 are drawn, marked, and returned to the jar and after mixing,  a sample of 200 pennies is drawn and it was noticed that 50 were marked. Based on the given information there are  5,160 pennies in the jar.

1290 pennies are drawn and returned to the jar.

200 pennies were drawn.

50 pennies were marked.

1,490 is not enough.

258,000 is way too much.

5,160 makes sense.

Final answer:

Using the proportion of marked to sampled pennies, the total number of pennies in the jar is estimated to be 5160.

Explanation:

The task is to use the information given about the marked and sampled pennies to estimate the total number of pennies in the jar.

This is a classic example of using proportions in mathematics. If out of 200 sampled pennies, 50 are marked, this represents 25% of the sample.

Since 1290 pennies were marked to begin with, we assume that the sampled 25% represents a similar proportion of the total jar.

Thus, the equation to solve is 1290 / total number of pennies = 50 / 200. Simplifying the right side of the equation gives 1290 / total number of pennies = 1 / 4.

By cross-multiplication, the total number of pennies is 4 × 1290, which equals 5160.

cos^2a/(1-tana)+sin^3a/(sina-cosa)=sina+cosa

Answers

Answer:

a=2*n*pi where n is an integer

Step-by-step explanation:

[tex]\frac{\cos^2(a)}{1-\tan(a)}+\frac{\sin^3(a)}{\sin(a)-\cos(a)}[/tex]

The denominators are different here so I'm going to try to make them the same.

I'm going to write everything in terms of sine and cosine.

That means I'm rewriting tan(a) as sin(a)/cos(a)

[tex]\frac{\cos^2(a)}{1-\frac{\sin(a)}{\cos(a)}}+\frac{\sin^3(a)}{\sin(a)-\cos(a)}[/tex]

I'm going to multiply top and bottom of the first fraction by cos(a) to clear the mini-fraction from the bigger fraction.

[tex]\frac{\cos^2(a)}{1-\frac{\sin(a)}{\cos(a)}} \cdot \frac{\cos(a)}}{\cos(a)}+\frac{\sin^3(a)}{\sin(a)-\cos(a)}[/tex]

Distributing and Simplifying:

[tex]\frac{\cos^3(a)}{\cos(a)-\sin(a)}+\frac{\sin^3(a)}{\sin(a)-\cos(a)}[/tex]

Now I see the bottom's aren't quite the same but they are almost... They are actually just the opposite. That is -(cos(a)-sin(a))=-cos(a)+sin(a)=sin(a)-cos(a).

Or -(sin(a)-cos(a))=-sin(a)+cos(a)=cos(a)-sin(a).

So to get the denominators to be the same I'm going to multiply either fraction by -1/-1... I'm going to do this to the second fraction.

[tex]\frac{\cos^3(a)}{\cos(a)-\sin(a)}+\frac{\sin^3(a)}{\sin(a)-\cos(a)} \cdot \frac{-1}{-1}[/tex]

[tex]\frac{\cos^3(a)}{\cos(a)-\sin(a)}+\frac{-\sin^3(a)}{\cos(a)-\sin(a)}[/tex]

The bottoms( the denominators) are the same now.  We can write this as one fraction, now.

[tex]\frac{\cos^3(a)-\sin^3(a)}{\cos(a)-\sin(a)}[/tex]

I don't know if you know but we can factor a difference of cubes.

The numerator is in the form of a^3-b^3.

The formula for factoring that is (a-b)(a^2+ab+b^2).

[tex]\frac{(\cos(a)-\sin(a))(\cos^2(a)+\cos(a)\sin(a)+\sin^2(a)}{\cos(a)-\sin(a)}[/tex]

There is a common factor of cos(a)-sin(a) on top and bottom you can "cancel it".  

So we now have

[tex]\cos^2(a)+\cos(a)\sin(a)+\sin^2(a)[/tex]

We can actually simplify this even more.

[tex]\cos^2(a)+\sin^2(a)=1[/tex] is a Pythagorean Identity.

So we rewrite [tex]\cos^2(a)+\cos(a)\sin(a)+\sin^2(a)[/tex]

as [tex]1+\cos(a)\sin(a)[/tex]

So that is what we get after simplifying left hand side.

So I guess we are trying to solve for a.

[tex]1+\cos(a)\sin(a)=\sin(a)+\cos(a)[/tex]

Subtract sin(a) and cos(a) on both sides.

[tex]\cos(a)\sin(a)-\sin(a)-\cos(a)+1=0[/tex]

This can be factored as

[tex](\sin(a)-1)(\cos(a)-1)=0[/tex]

So we just need to solve the following two equations:

[tex]\sin(a)-1=0 \text{ and } \cos(a)-1=0[/tex]

[tex]\sin(a)=1 \text{ and } cos(a)=1 \text{ I just added one on both sides}[/tex]

Now we just need to think of the y-coordinates on the unit circle that are 1

and the x-coordinates being 1 also (not at the same time of course).

List thinking of the y-coordinates being 1:

a=pi/2 , 5pi/2 , 9pi/2 , ....

List thinking of the x-coordinates being 1:

a=0, 2pi, 4pi,...

So let's come up with a pattern for these because there are infinite number of solutions that continue in this way.

If you notice in the first list the number next to pi is going up by 4 each time.

So for the first list we can say a=(4pi*n+pi)/2 where n is an integer.

The next list the number in front of pi is just even.

So for the second list we can say a=2*n*pi where n is an integer.

So the solutions is a=2*n*pi   ,    a=(4pi*n+pi)/2

We really should make sure if this is okay for our original equation.

We don't have to worry about the second fraction because sin(a)=cos(a) only when a is pi/4 or pi/4+2pi*n OR (pi+pi/4) or (pi+pi/4)+2pi*n.

Now the second fraction we have 1-tan(a) in the denominator, and it is 0 when:

tan(a)=1

sin(a)/cos(a)=1                       =>              sin(a)=cos(a)

So the only thing we have to worry about here since we said sin(a)=cos(a) doesn't hurt our solution is the division by the cos(a).

When is cos(a)=0?

cos(a)=0 when a=pi/2 or any rotations that stop there (+2npi thing) or at 3pi/2 (+2npi)

So the only solutions that work is the a=2*n*pi where n is an integer.

Answer:

[tex]\large\boxed{a=2k\pi\ for\ k\in\mathbb{Z}}[/tex]

Step-by-step explanation:

[tex]\bold{a=x}[/tex]

[tex]\text{The domain:}\\\\1-\tan x\neq0\ \wedge\ \sin x-\cos x\neq0\ \wedge\ x\neq\dfrac{\pi}{2}+k\pi\ (from\ \tan x)\\\\\tan x\neq1\ \wedge\ \sin x\neq\cos x\\\\x\neq\dfrac{\pi}{4}+k\pi\ \wedge\ x\neq\dfrac{\pi}{4}+k\pi\ for\ k\in\mathbb{Z}[/tex]

[tex]\dfrac{\cos^2x}{1-\tan x}+\dfrac{\sin^3x}{\sin x-\cos x}=\sin x+\cos x[/tex]

[tex]\text{Left side of the equation:}[/tex]

[tex]\text{use}\ \tan x=\dfrac{\sin x}{\cos x}\\\\\dfrac{\cos^2x}{1-\tan x}=\dfrac{\cos^2x}{1-\frac{\sin x}{\cos x}}=\dfrac{\cos^2x}{\frac{\cos x}{\cos x}-\frac{\sin x}{\cos x}}=\dfrac{\cos^2x}{\frac{\cos x-\sin x}{\cos x}}=\cos^2x\cdot\dfrac{\cos x}{\cos x-\sin x}\\\\=\dfrac{\cos^3x}{\cos x-\sin x}\\\\\dfrac{\cos^2x}{1-\tan x}+\dfrac{\sin^3x}{\sin x-\cos x}=\dfrac{\cos^3x}{\cos x-\sin x}+\dfrac{\sin^3x}{\sin x-\cos x}\\\\=\dfrac{\cos^3x}{\cos x-\sin x}+\dfrac{\sin^3x}{-(\cos x-\sin x)}[/tex]

[tex]=\dfrac{\cos^3x}{\cos x-\sin x}-\dfrac{\sin^3x}{\cos x-\sin x}\\\\=\dfrac{\cos^3x-\sin^3x}{\cos x-\sin x}\qquad\text{use}\ a^3-b^3=(a-b)(a^2+ab+b^2)\\\\=\dfrac{(\cos x-\sin x)(\cos^2x+\cos x\sin x+\sin^2x)}{\cos x-\sin x}\qquad\text{cancel}\ (\cos x-\sin x)\\\\=\cos^2x+\cos x\sin x+\sin^2x\qquad\text{use}\ \sin^2x+\cos^2x=1\\\\=\cos x\sin x+1[/tex]

[tex]\text{We're back to the equation}[/tex]

[tex]\cos x\sin x+1=\sin x+\cos x\qquad\text{subtract}\ \sin x\ \text{and}\ \cos x\ \text{from both sides}\\\\\cos x\sin x+1-\sin x-\cos x=0\\\\(\cos x\sin x-\sin x)+(1-\cos x)=0\\\\\sin x(\cos x-1)-1(\cos x-1)=0\\\\(\cos x-1)(\sin x-1)=0\iff \cos x-1=0\ or\ \sin x-1=0\\\\\cos x=1\ or\ \sin x=1\\\\x=2k\pi\in D\ or\ x=\dfrac{\pi}{2}+2k\pi\notin D\ for\ k\in\mathbb{Z}[/tex]

WHOEVER ANSWERS FIRST GETS BRAINLIEST!!!!

Which statements are true regarding the sequence below?

Check all that apply.


A: The domain is a set of natural numbers

B: The range is a set of natural numbers

C: The recursive formula representing the sequence is f(x + 1) = 3/2(f(x )) when f(1) = 4.

D: An explicit formula representing the sequence is

f(x) = 4 (3/2)^x

E: The sequence shows exponential growth.

Answers

Answer:

A, C and E are true.

Step-by-step explanation:

The domain is a set of natural numbers.

The recursive formula is correct:

When x = 1, f(x) = 4 and f(x + 1) = f(2) = 3/2 f(x) = 3/2 * 4 = 6.

It is also true for the other points on the graph.

D is  incorrect.

E is correct exponential growth with the formula  4(3/2)^(x-1).

Answer:

A and C

Step-by-step explanation:

10/3 x 6/5 is 4                                                                                                                      

It can be represented using the formula f(x + 1) = Six-fifths(f(x)) when f(1) = Ten-thirds

It can be represented using the formula f (x) = ten-thirds (six-fifths) Superscript x minus 1. edge 2020-2021

What is the slope-intercept form of y + 6 = 2(x + 2)?

Answers

Answer:

y=2x-2

Step-by-step explanation:

in slope intercept form we need make in this formula..

y=Mx+c

Answer:

y = 2x - 2

Step-by-step explanation:

Given

y + 6 = 2(x + 2) ← distribute

y + 6 = 2x + 4 ( subtract 6 from both sides )

y = 2x - 2 ← in slope- intercept form

Suppose an airline decides they are comfortable with excluding the 5% of women with the widest hips. How wide should the airline design the seats using the parameters? Womens hip breadths are normally distributed with a mean of 15.2 inches and a standard deviation of 1.1 inches.

Answers

Answer:

17.009 in

Step-by-step explanation:

For a normal distribution with mean of 15.2 in and standard deviation of 1.1 inches, we finnd that 5% are excluded when the width of the seats are greater than 17.009 inches.

Therefore, the seat should have a width of 17.009 in.

To accommodate 95% of women based on hip breadth, airline seats should be designed at least 17.015 inches wide, calculated using the given mean of 15.2 inches, a standard deviation of 1.1 inches, and the z-score for the 95th percentile.

To determine the width of airline seats that would accommodate 95% of women, the airline needs to calculate the 95th percentile of women's hip breadths, modeled by a normal distribution.

Using the provided mean of 15.2 inches and a standard deviation of 1.1 inches, we find the z-score that corresponds to the 95th percentile. In normal distribution, the z-score for the 95th percentile is approximately 1.65.

Using the z-score formula Z =(X - μ / Σ, where Z is the z-score, X is the value we seek, μ is the mean, and Σ is the standard deviation, we can set Z to 1.65 and solve for X:

1.65 = (X - 15.2) / 1.1

X = 1.65 * 1.1 + 15.2

X = approx. 1.815 + 15.2

X = approx. 17.015 inches

Therefore, to exclude only the 5% of women with the widest hips, the airline should design seats that are at least 17.015 inches wide.

find the distance between the points (-3,2) and (0,3).

Answers

Answer:

The distance between (-3, 2) and (0,3) is √10.

Step-by-step explanation:

As we go from (-3,2)  to  (0,3), x increases by 3 and y increases by 1.

Think of a triangle with base 3 and height 1.  Use the Pythagorean Theorem to find the length of the hypotenuse, which represents the distance between the points (-3, 2) and (0, 3):

distance = √(3² + 1²) = √10

The distance between (-3, 2) and (0,3) is √10.

For this case we have that by definition, the distance between two points is given by:

[tex]d = \sqrt {(x_ {2} -x_ {1}) ^ 2+ (y_ {2} -y_ {1}) ^ 2}[/tex]

We have the following points:

[tex](x_ {1}, y_ {1}): (- 3,2)\\(x_ {2}, y_ {2}) :( 0,3)[/tex]

Substituting:

[tex]d = \sqrt {(0 - (- 3)) ^ 2+ (3-2) ^ 2}\\d = \sqrt {(3) ^ 2 + (1) ^ 2}\\d = \sqrt {9 + 1}\\d = \sqrt {10}[/tex]

Answer:

The distance between the points is [tex]\sqrt {10}[/tex]

Which of the following shows the solution set of the inequality
1/2x<-3?​

Answers

Answer:

B

Step-by-step explanation:

1/2x < -3

Multiply each side by 2

1/2x *2 < -3*2

x < -6

Since x is less than -6, there is an open circle at -6

Less than means the line goes to the left

The circumference of a circle is 30t. What is its area? ​

Answers

Answer:

[tex]A=\frac{225t^2}{\pi}[/tex] given the circumference is 30t.

Step-by-step explanation:

The circumference of a circle is [tex]C=2\pi r[/tex] and the area of a circle is [tex]A=\pi r^2[/tex] assuming the radius is [tex]r[/tex] for the circle in question.

We are given the circumference of our circle is [tex]2 \pi r=30t[/tex].

If we solve this for r we get: [tex]r=\frac{30t}{2\pi}[/tex].  To get this I just divided both sides by [tex]2\pi[/tex] since this was the thing being multiplied to [tex]r[/tex].

So now the area is [tex]A=\pi r^2=\pi (\frac{30t}{2 \pi})^2[/tex].

Simplifying this:

[tex]A=\pi (\frac{30t}{2 \pi})^2[/tex].

30/2=15 so:

[tex]A=\pi (\frac{15t}{\pi})^2[/tex].

Squaring the numerator and the denominator:

[tex]A=\pi (\frac{(15t)^2}{(\pi)^2}[/tex]

Using law of exponents or seeing that a factor of [tex]\pi[/tex] cancels:

[tex]A=\frac{(15t)^2}{\pi}[/tex]

[tex]A=\frac{15^2t^2}{\pi}[/tex]

[tex]A=\frac{225t^2}{\pi}[/tex]

What is the value of X ?

Answers

Answer:

=14

Step-by-step explanation:

In a rhombus, opposite angles are equal.

In the one provided in the question, 5x° is opposite the angle 70°

Let us equate the two.

5x=70

x=70/5

=14°

The value of x in the figure is 14°

What is the value of x in the equation 4x + 8y - 40, when y-0.8?
4.6
0 8.4

Answers

Answer:

8.4

Step-by-step explanation:

the equation 4x+8y -40 can be written as 4x-8y-40=0, this represents a line in a space of two dimensions.

solving for x when y=0.8 we have the equation below>

[tex]4x+8*0,8-40=0[/tex]

Which gives that x=42/5, or in more simpler terms, 8.4

Find a if b=5 and c=8cm

Answers

Using the Pythagorean theorem:

a = √(c^2 - b^2)

a = √(8^2 - 5^2)

a = √(64 - 25)

a = √39 ( Exact answer )

Or √39 =  6.244997 as a decimal and you round the decimal answer as needed.

In 1989 a locally-owned car company sold 2,881 cars. 

In 2002, the car sales rose to 4,232. 

What was the average rate of change for the total number of cars sold?

 A. 

1,351 cars per year

 B. 

9.62 cars per year

 C. 

3,557 cars per year

 D. 

104 cars per year​

Answers

D. 103 12/13 or about 104

First sort the data into two sets of points, (1989,2881), (2002, 4232).

Now use the slope equation with your numbers.

(y2-y1)/(x2-x1)

(4232-2881)/(2002-1989)

1351/13=

103 12/13 or about 104

How can 65% be broken down with friendly percents to find 65% of a number?
25% + 25% + 10%
25% + 10% + 10% + 10% + 10%
50% + 10%
50% + 25%

Answers

Answer:

The correct ans would be B, 25%+10%+10%+10%+10%

Step-by-step explanation:

When percentages are found, the best way to calculate them is to break them down to the simplest percentage form, and 10% is the simplest percentage that a person can calculate of whatever digit. So if someone wishes to find out the friendly percents, then the easiest would be to calculate the 10% of the figure, add them four times, then add them 2 times plus the half of 10%, which will become 25%, and then add them all to get the 65% of that figure.

Answer:

B.

Step-by-step explanation:

i took the test

Megan paints her locker red, white, and blue.
She paints 9/20 of the locker red, 15% of the
locker white, and 0.4 of the locker blue.
Complete the table below.​

Answers

Answer:

red: 9/20, 0.45, 45%

White: 15%, 0.15, 3/20

Blue: 0.4, 2/5, 40%

Step-by-step explanation:

For red: you start with 9/20. It’s best to get to a denominator of 10. So divide each number by 2. You would get 4.5/10. Then change to a percent by moving the decimal of the numerator one to the right and changing it to percent. 4.5 -> 45. -> 45%. Then for the decimal, divide 45 by 100. 45/100 = 0.45.

For white: you start with 15%. Divide by 100. 15/100=0.15. Put into a fraction with a denominator of 100. It would be 15/100. Simplify. Each number can be divided by 5, so your fraction would be 3/20.

For blue: you start with 0.4. Turn this into a fraction. Since there is one decimal place, it can have a denominator of 10. The fraction is 4/10, simplified to 2/5. Using the fraction 4/10, the percent would be 40%.

I hope this helps!

Which value for y makes the sentence true? 8 - y = 9 - 3

Answers

Answer:

y=2

Step-by-step explanation:

8 - y = 9 - 3

Combine like terms

8 - y = 6

Subtract 8 from each side

8-8 - y = 6-8

-y = -2

Multiply each side by -1

-1 * -y = -2 *-1

y =2

Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are located.
x2 +3x -4 = 0

Answers

Answer:

x = -4 and x=1

Step-by-step explanation:

The solutions to the equation x^2 +3x -4 = 0 will be given by the points at which the graph intercepts the x-axis.

By looking at the graph, we can clearly see that the graph intercepts the x-axis at x=-4 and x=1.

One of the roots is located between -4 and -3, and the other one between 0 and 1.

Express the hcf of 234 and 111 as 234x and111y.where x and y are integers

Answers

Answer:

The HCF = 3.

Step-by-step explanation:

The prime factors of

234 = 2*3*3*13,

and of 111 = 3*37.

The only common factor is 3.

Answer:

(- 9 × 234 ) + (19 × 111 )

Step-by-step explanation:

Using the division algorithm to find the hcf

If a and b are any positive integers, then there exists unique positive integers q and r such that

a = bq + r → 0 ≤ r ≤ b

If r = 0 then b is a divisor of a

Repeated use of the algorithm allows b to be found

here a = 234 and b = 111

234 = 2 × 111 + 12 → (1)

111 = 9 × 12 + 3 → (2)

12 = 4 × 3 + 0 ← r = 0

Hence hcf = 3

We can now express the hcf (d) as

d = ax + by where x, y are integers

From (2)

3 = 1 × 111 - 9 × 12

From (1)

3 = 1 × 111 - 9( 1 × 234 - 2 × 111)

   = 1 × 111 - 9 × 234 + 18 × 111

   = - 9 × 234 + 19 × 111 ← in required form

with x = - 9 and y = 19

Find the value of the missing coefficient in the factored form of 27f^3 + 125g^3. 27f^3+125g^3=(3f+5g)(9f^2-?fg + 25g)^2

Answers

Answer:

15

Step-by-step explanation:

The formula for factoring a sum of cubes is:

[tex]a^3+b^3=(a+b)(a^2-ab+b^2)[/tex]

We have a=3f and b=5g here.

So a*b in this case is 3f*5g=15fg.

The ? is 15.

The value of the missing coefficient in the factored form of the sum of cubes 27f³ + 125g³ is 15, resulting in the complete factorization being (3f+5g)(9f² -15fg+25g²).

The expression 27f³ + 125g³ can be factored using the sum of cubes formula, which is a³ + b³ = (a + b)(a² - ab + b²).

Given [tex]27f^3+125g^3[/tex], we have [tex]a=3f[/tex] and [tex]b=5g[/tex]

Applying the sum of cubes formula, we get:

[tex]27f ^3+125g ^3 =(3f+5g)((3f) ^2 -(3f)(5g)+(5g)^ 2 )[/tex]

[tex]27f ^3 +125g ^3=(3f+5g)(9f ^2-15fg+25g ^2 )[/tex]

So, the missing coefficient in the factored form is 15.

Therefore, the factored form is,

[tex]27f ^3+125g ^3[/tex] is [tex](3f+5g)(9f^ 2-15fg+25g ^2 )[/tex]

The complete question is:

Find the value of the missing coefficient in the factored form of 27f³ + 125g³ .

27f³ + 125g³ =(3f+5g)(9f² -?fg+25g² )

The value of ? =

x to the 2nd power + 3=12

Answers

Answer:

x = ±3

Step-by-step explanation:

x^2 +3 = 12

Subtract 3 from each side

x^2 +3-3 = 12-3

x^2 = 9

Take the square root of each side

sqrt(x^2) =±sqrt(9)

x = ±3

If a graph of y=-4x+2 we’re changed to a graph of y= - 4x+5, how would the y- intercept change ?

Answers

The y-intercept would elevate up the y-axis by 3

This is because the y-intercept in y= -4x+2 is 2 and when you change it to y= -4x+5 you are moving the intercept to a y of 5.

The area of a circle is 36π. What is the length of a diameter of the circle?

Answers

Answer:

d =12

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

Substituting what we know

36 pi = pi r^2

Divide each side by pi

36 pi/pi = pi r^2/pi

36 = r^2

Taking the square root of each side

sqrt(35) = sqrt(r^2)

6 =r

We want the diameter

d = 2r

d = 2(6)

d = 12

what is the p(x) and profit for selling 100 tickets

Answers

Answer:

P(x) is the profit amount from selling tickets.

P(100) = $160

Step By Step Explanation:

First, plug in r(x) and c(x) into the p(x) equation:

p(x) = r(x) - c(x)

p(x) = (10x) - (8x+40)

Then simplify it:

p(x) = 10x - 8x - 40 {just distribute a +1 into the parentheses}

p(x) = 2x - 40 {combine like terms}

Now substitute 100 for x:

p(100) = 2(100) - 40

Then solve:

p(100) = 200 - 40

p(100) = 160

Find the range of the following set of data.
23,50, 49, 48, 49, 32, 37, 40, 41, 42, 41, 41, 43​

Answers

Answer:

27

Step-by-step explanation:

The range is the greatest value subtract the smallest value

greatest value = 50 and smallest value = 23, so

range = 50 - 23 = 27

Answer:

27

Step-by-step explanation:

23,32,37,40,41,41,41,42,43,48,49,49,50.

Range=50-23=27

What is the area of a rectangle with a length of 9 and a width of 17?

Answers

Answer:

153 units squared

Step-by-step explanation:

To solve, multiply your length by your width.

[tex]A=lw\\A=9(17)\\A=153[/tex]

Answer:

A=153

Step-by-step explanation:

The area of a rectangle with a length of 9 and a width of 17 is 153.

Formula: A=wl

A=wl=17·9=153

I need help with this

Answers

Answer:

B

Step-by-step explanation:

Factor the numerator, that is

x² + 6x + 8 = (x + 4)(x + 2), now

f(x) = [tex]\frac{(x+4)(x+2)}{x+4}[/tex]

Cancel the factor (x + 4) on the numerator/ denominator, leaving

f(x) = x + 2 ← simplified version

Cancelling the factor x + 4 leaves a discontinuity ( a hole ) at

x + 4 = 0 ⇒ x = - 4 and f(- 4) = x + 2 = - 4 + 2 = - 2

There is a discontinuity at (- 4, - 2 )

To find the zero let f(x) = 0, that is

x + 2 = 0 ⇒ x = - 2

The zero is (- 2, 0 )

Which of the following is in the solution set of y < 8x + 3?
(10, 84)
(7, 52)
(7, 69)
(9, 88)

Answers

Answer:(7,52)

Step-by-step explanation:plug those values into the equation.

52<8(7)+3.

52<59.


20 = –d + 16

–4

–6

4

–10

Answers

Answer:

d=-4

Step-by-step explanation:

20 = –d + 16

Subtract 16 from each side

20-16 = –d + 16-16

4 = -d

Multiply each side by -1

-1 *4 = -1 * -d

-4 =d

solve ABC
c=10, B=35°, C=65%​

Answers

Answer:

Part 1) The measure of angle A is [tex]A=80\°[/tex]

Part 2) The length side of a is equal to [tex]a=10.9\ units[/tex]

Part 3) The length side of b is equal to [tex]b=6.3\ units[/tex]

Step-by-step explanation:

step 1

Find the measure of angle A

we know that

The sum of the internal angles of a triangle must be equal to 180 degrees

so

[tex]A+B+C=180\°[/tex]

substitute the given values

[tex]A+35\°+65\°=180\°[/tex]

[tex]A+100\°=180\°[/tex]

[tex]A=180\°-100\°=80\°[/tex]

step 2

Find the length of side a

Applying the law of sines

[tex]\frac{a}{sin(A)}=\frac{c}{sin(C)}[/tex]

substitute the given values

[tex]\frac{a}{sin(80\°)}=\frac{10}{sin(65\°)}[/tex]

[tex]a=\frac{10}{sin(65\°)}(sin(80\°))[/tex]

[tex]a=10.9\ units[/tex]

step 3

Find the length of side b

Applying the law of sines

[tex]\frac{b}{sin(B)}=\frac{c}{sin(C)}[/tex]

substitute the given values

[tex]\frac{b}{sin(35\°)}=\frac{10}{sin(65\°)}[/tex]

[tex]b=\frac{10}{sin(65\°)}(sin(35\°))[/tex]

[tex]b=6.3\ units[/tex]

Bethany wrote the equation X+ (x+2)+(+4)= 91 when she was told that the sum of three consecutive odd integers had a
sum of 91. Which statement about her equation is true?

Bethany is correct because consecutive odd integers will each have a difference of two.
Bethany is correct because there are three xs in the equation and three is an odd number so it represents the sum of odd
numbers.
Bethany is incorrect because 2 and 4 are even numbers, she should use 1 and 3 in their place.
Bethany is incorrect because consecutive integers always increase by 1 each time, not by 2.

Answers

Answer:

Option A) Bethany is correct because consecutive odd integers will each have a difference of two

Step-by-step explanation:

The sum of 3 consecutive odd integers is 91. Let the first odd integer is x. The next odd integer will be obtained by adding 2 in x i.e. (x + 2). The third odd integer will be obtained by adding 2 in the second odd integer i.e. (x + 2) + 2 = x + 4

So, the 3 odd integers will be:

x  , (x+2) and (x+4)

Their sum is given to be 91. So we can write:

x + (x+2) + (x+4) = 91

Hence, we can conclude that: Bethany is correct because consecutive odd integers will each have a difference of two.

Other options are not correct because consecutive odd integers always increase by 2. For example, the next odd integer after 1 is 3, which is obtained by adding two, similarly the next odd will be 5 and so on.

Answer:

a

Step-by-step explanation:

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