If line segment ab is defined by the endpoints a(4,2) and b(8,6) , write an equation of a line that is the perpendicualr bisector line segment ab

Answers

Answer 1
Slope of line ab  = 6-2 / 8-4  = 4/4 = 1
So the slope of the perpendicular line is -1/1  = -1
This line passes through the midpoint of ab
The midpoint of ab  =  ( 8+4 / 2 , 2+6 / 2) =  (6, 4)
Finding the equation of the perpendicular line:-
y - y1 = -1(x - x1)  where x1 = 6 and y1 = 4:-
y - 6 = -1(x - 4)
y = -x + 10 is the answer
Answer 2

An equation of a line that is the perpendicular bisector line segment AB is y=-x+10.

What is the equation of a line?

The general equation of a straight line is y=mx+c, where m is the gradient, and y = c is the value where the line cuts the y-axis. This number c is called the intercept on the y-axis.

Given that, line segment AB is defined by the endpoints A(4,2) and B(8,6).

Midpoint of line AB is (x, y) =[(x₂+x₁)/2, (y₂+y₁)/2]

= [(8+4)/2, (6+2)/2]

= (6, 4)

Slope of line AB is (y₂-y₁)/(x₂-x₁)

= (6-2)/(8-4)

= 4/4

= 1

The slope of a line perpendicular to given line is m1=-1/m2

So, the slope of a line is -1

Now, substitute m=-1 and (x, y)=(6, 4) in y=mx+c, we get

4=-1(6)+c

c=10

Substitute m=-1 and c=10 in y=mx+c, we get

y=-x+10

Therefore, an equation of a line that is the perpendicular bisector line segment AB is y=-x+10.

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Related Questions

which graph shows the solution set of the compound inequality 1.5x-1>6.5 or 7x+3<-25

Answers

For this case we have the following inequations:
 1.5x-1> 6.5
 7x + 3 <-25
 Clearing x from each one we have:
 For 1.5x-1> 6.5:
 1.5x> 6.5 + 1
 1.5x> 7.5
 x> 7.5 / 1.5
 x> 5
 For 7x + 3 <-25:
 7x <-25-3
 7x <-28
 x <-28/7
 x <-4
 The solution set is:
 (inf, -4) U (5, inf)
 Answer:
 See attached image

Answer:

It's B

Step-by-step explanation:

Randall bought a bond with a face value of $6000 and a coupon rate of 7.25%. the bond will mature in 5 years. how much interest will he receive semiannually?

Answers

i just took a test with this question it's $217.50

Answer:

Face value of bond = $ 6000

Rate of interest =7.25 %

The Bond will mature in 5 years.

If the interest is semiannually , the rate of interest will reduce to half.

So, new rate of interest will be [tex]\frac{7.25}{2}=3.625[/tex]

Formula for simple interest

[tex]=\frac{\text{Principal}\times Rate \times time}{100}[/tex]

   Interest after 6 months will be

   [tex]=\frac{6000 \times 3.625 \times 1}{100}\\\\=60 \times 3.625\\\\=217.5[/tex]

So, interest that Randall will receive after six months = $ 217.50

Whats the distance between points C(0, 4), T(-6, -3)

a √(37)
b √(85)
c √(109)

Answers

[tex]\text{The formula of the distance between points}\ A(x_A;\ y_A)\ \text{and}\ B(x_B;\ y_B):\\\\|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}[/tex]

[tex]\text{We have:}\\C(0;\ 4);\ T(-6;-3)\\\\\text{substitute coordinates of the points to the formula:}\\\\|CT|=\sqrt{(-6-0)^2+(-3-4)^2}=\sqrt{(-6)^2+(-7)^2}=\sqrt{36+49}=\sqrt{85}[/tex]

[tex]\text{Answer:}\ b.\ \sqrt{85}[/tex]

can someone please solve 5-2x<7

Answers

Add 2x and subtract 7
   5 -2x +2x < 7 +2x . . . . . . showing 2x added
   5 < 7 +2x . . . . . . . . . . . .. simplified
   5 -7 < 7 -7 +2x . . . . . . . . showing 7 subtracted
  -2 < 2x . . . . . . . . . . . . . . . simplified
Now, divide by 2
   -1 < x

The solution is -1 < x.

Over the past week, 34 baby boys were born at the hospital. this was 54% of all babies born. how many girls were born over the past week? (enter numeric value only. if grounding is necessary, round to the nearest whole number

Answers

29 because you just have to cross multiply if 34/x= 54/100 just cross multiply and x(the total # of babies born) is about 63 and 63-34=29

Which equations represent the line that is parallel to 3x − 4y = 7 and passes through the point (−4, −2)? Check all that apply.

A. y = –x + 1
B. 3x − 4y = −4
C. 4x − 3y = −3
D. y – 2 = –(x – 4)
E. y + 2 = (x + 4)

Answers

First, we find the slope of the given line.

3x − 4y = 7

-4y = -3x + 7

y = (3/4)x - 7/4

The slope of the given line is 3/4.
The slope of the parallel line is also 3/4.

Now we need the equation of the line that has slope 3/4 and passes through point (-4, -2),

We use the point-slope form of the equation of a line.

y - y1 = m(x - x1)

y - (-2) = (3/4)(x - (-4))

y + 2 = (3/4)(x + 4)     <---- check option E. Is the fraction 3/4 not there?

y + 2 = (3/4)x + 3

y = (3/4)x + 1

4y = 3x + 4

3x - 4y = -4    <------ this is choice B.

What is the domain for the piece of the function represented by f(x) = x + 1?

Answers

Answer:

All real numbers

Step-by-step explanation:

The domain of the function represented by f(x) = x + 1 is the all real numbers as there is only addition involved in the function so putting any number as input will not lead the function to infinity.

If the diameter of a sphere is 12cm, what is its volume to the nearest hundredth

Answers

4/3×3.14×6^3=904.32cm

Would someone Please answer this question please will be thanked and also will pick brainly!! (please be honest)

Answers

The answer to this question is 360ft^2

A cylindrical tank has a radius of 4.5 ft and an altitude of 14 ft. If a gallon of paint will cover 130 ft squared ft2 of​ surface, how much paint in gallons is needed to put two coats of paint on the entire surface of the​ tank? Aswer: To put two coats of paint on the entire surface of the​ tank, ______ full gallons of pain are needed.

Answers

you would need 11 cans of paint to cover it twice

surface area = 2*area circle + area lateral side

circle area = pi * 4.5 * 4.5 = 63.585
circle circumference = 2*pi*4.5 = 28.26
lateral area = 28.26 * 14 =395.64

surface area = 63.585*2 + 395.64 = 522.81

522.81/130 = 4.02gallons

2*4.02= 8.04

To put two coats of paint on the entire surface of the​ tank, EIGHT full gallons of pain are needed.

What is the equation of the line that passes through (7, 4) and (4, -2)?
a) y = 2x - 10
b) y = -2x - 10
c) y = -2x + 18
d) y = 2x + 18

Answers

Solution:

we have been asked to find the equation of the line that passes through (7, 4) and (4, -2).

First we will find the slope of the line using the formula

[tex] m=\frac{y_2-y_1}{x_2-x_1} [/tex]

Plugin the given values we get

[tex] m=\frac{-2-4}{4-7}=\frac{-6}{-3}=2 [/tex]

Now using the point slope form of a straight line

[tex] (y-y_1)=m(x-x_1) [/tex]

Plugin the values

[tex] (y-4)=2(x-7)\\
\\
y=2x-14+4\\
\\
y=2x-10\\ [/tex]

Hence the correct option is a.


What's the diameter of a cirlce eith an area of 615.75?

Answers

area of circle =πr²

πr²=615.75
r²= 615.75*7/22

r=²√196 =14

diameter =2r=2*12 =28

Find the first five terms of the sequence: an = 5an – 1 + 2; a1 = 3.


a) {3, 17, 87, 437, 2187}

b) {3, 15, 75, 375, 1875}

c) {3, 12, 17, 22, 27}

d) {3, 11, 27, 59, 123}

Answers

Given that the series is given by:
an=5an-1+2
where:
a1=3
then the other terms of the sequence will be:
a2=5a1+2
a2=5*3+2=17

a3=5a2+2
a3=5(17)+2
a3=87

a4=5a3+2
a4=5(87)+2
a4=437

a5=5a4+2
a5=(5*437+2)
a5=2187

hence the sequence will be:
3, 17, 87, 437, 2187

Answer: a) {3, 17, 87, 437, 2187}

What is the best first step in solving the equation 4 + squrt(6x) = 5?

Answers

The best answer to this question is to subtract 4 from both sides. This isolates the square root and sets you up for squaring both sides of the equation.

If the radius of a circle is 6 inches, how long is the arc subtended by an angle measuring 70°?
a. 3 7 π inches
b. 7 2 π inches
c. 7 3 π inches
d. 7 6 π inches

Answers

The correct answer to this problem C.)7/3


All ticket for a concert are the same price.

Amy and dan pay £63 altogether for some tickets.
Amy pays 24.50 for 7 tickets.

How many tickets does Dan buy?

Answers

we know that
if Amy pays 24.50 for 7 tickets
so
cost each ticket is=24.50/7-----> £3.50

find the total number of tickets=£63/£3.50-----> 18 ticket
let 
x-----> amount of tickets purchased by Dan
18=7+x -----> x=18-7-----> x=11

the answer is
11

To determine how many tickets Dan bought, we calculate the price per ticket from Amy's purchase as £3.50 each. Then we subtract Amy's payment from the total to find Dan's payment of £38.50, and finally, we divide Dan's payment by the price per ticket to find that Dan bought 11 tickets.

The question involves finding out how many tickets Dan bought for a concert, using the total amount paid by both Amy and Dan and the price Amy paid for her tickets.

First, we need to find out the price per ticket from the information provided about Amy's purchase:

Amy pays £24.50 for 7 tickets.

To find the price per ticket, we divide £24.50 by 7:

Price per ticket = £24.50 / 7 = £3.50

Next, we use the total amount paid to find out how much Dan spent:

Total amount paid by Amy and Dan = £63

Amount paid by Amy = £24.50

So, the amount paid by Dan = Total amount - Amount paid by Amy

Amount paid by Dan = £63 - £24.50 = £38.50

To find out how many tickets Dan bought, we divide the amount he paid by the price per ticket:

Number of tickets Dan bought = £38.50 / £3.50

Number of tickets Dan bought = 11 tickets

The equation $1.50p + $5.00 = $14.00 shows the total cost of picking p pounds of blueberries at a local blueberry farm. how many pounds of blueberres were picked/

Answers

1.5p + 5 = 14
1.5p = 9
p = 6 pounds

Pratap Puri rowed 14 miles down a river in 2 ​hours, but the return trip took him 3 and one half hours. Find the rate Pratap can row in still water and find the rate of the current. Let x equals rate Pratap can row in still water and y equals rate of the current. What is the rate that Pratap rows in still​ water?

Answers

let the rate in still water be x and rate of the current be y.
speed down the river is:
speed=distance/time
speed=14/2=7 mi/h

speed up the river is:
speed=(14)/(3.5)=4 mi/hr
thus total speed downstream and upstream will be:
x+y=7...i
x-y=4.......ii
adding the above equations i and ii we get:
2x=11
x=5.5 mi/hr
thus
y=5-5.5=1.5 mi/r
thus the speed in still waters is 5.5 mi/hr
speed of current is 1.5 mi/hr

Final answer:

By establishing equations based on Pratap's rowing times upstream and downstream, we find that Pratap's rowing rate in still water is 5.5 miles per hour.

Explanation:

Finding Pratap's Rowing Rate in Still Water and the Current Rate

To calculate Pratap Puri's rowing rate in still water and the rate of the current, we need to set up two equations based on the information provided. We know that Pratap rowed 14 miles down a river in 2 hours and the return trip took 3 and a half hours.

Step-by-Step Solution

Let x be the rate at which Pratap can row in still water, and y be the rate of the current.

The downstream speed (with the current) is x + y, and the upstream speed (against the current) is x - y.

Using the formula distance = rate × time, for the downstream trip we have 14 = (x + y) × 2, and for the upstream trip 14 = (x - y) × 3.5.

Simplifying both equations gives us: 7 = x + y and 4 = x - y.

To find x, add the two equations to eliminate y, yielding 11 = 2x, or x = 5.5.

Therefore, Pratap's rowing rate in still water is 5.5 miles per hour.

A line passes through the points (-6,4) and (-2,2). Which is the equation of the line?

Answers

The answer is y= -1/2x + 1

Answer:

The equation of the line is [tex]y=\frac{-1}{2}x+1[/tex]

Step-by-step explanation:

1. The equation of the line that passes through two points can be expresed as:

[tex]\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}[/tex] (Eq.1)

where [tex]x_{1}[/tex], [tex]x_{2}[/tex], [tex]y_{1}[/tex] and [tex]y_{2}[/tex] are the given points.

2. Name the points:

[tex]x_{1}[/tex]=-6

[tex]x_{2}[/tex]=-2

[tex]y_{1}[/tex]=4

[tex]y_{2}[/tex]=2

3. Replace the points in the Eq.1:

[tex]\frac{y-4}{x-(-6)}=\frac{2-4}{-2-(-6)}[/tex]

[tex]\frac{y-4}{x+6}=\frac{2-4}{-2+6}[/tex]

[tex]\frac{y-4}{x+6}=\frac{-2}{4}[/tex]

[tex]\frac{4(y-4)}{x+6}=-2[/tex]

[tex]4(y-4)=-2(x+6)[/tex]

[tex]4y-16=-2x-12[/tex]

[tex]4y=-2x-12+16[/tex]

[tex]4y=-2x+4[/tex]

[tex]y=\frac{-2x+4}{4}[/tex]

[tex]y=\frac{-2x}{4}+\frac{4}{4}[/tex]

[tex]y=\frac{-1}{2}x+1[/tex]

50 points to answer this for me
Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 4−x and y = 8−x−1 intersect are the solutions of the equation 4−x = 8−x−1. (4 points)

Part B: Make tables to find the solution to 4−x = 8−x−1. Take the integer values of x between −3 and 3. (4 points)

Part C: How can you solve the equation 4−x = 8−x−1 graphically? (2 points)

Answers

the correct question is
Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 4−x and y = 8-x^-1 intersect are the solutions of the equation 4−x = 8-x^-1.
Part B: Make tables to find the solution to 4−x = 8-x^-1. Take the integer values of x between −3 and 3. 
Part C: How can you solve the equation 4−x = 8-x^-1 graphically?

Part A.  We have two equations:  y = 4-x   and   y = 8-x^-1
Given two simultaneous equations that are both to be true, then the solution is the points where the lines cross. The intersection is where the two equations are equal. Therefore the solution that works for both equations is when
4-x = 8-x^-1
This is where the two graphs will cross and that is the common point that satisfies both equations.

Part B
see the attached table
the table shows that one of the solutions is in the interval [-1,1]

Part C To solve graphically the equation 4-x = 8-x^-1

We would graph both equations: y = 4-x  and   y = 8-x^-1

The point on the graph where the lines cross is the solution to the system of equations.

using a graph tool

see the attached figure N 2

the solutions are the points

(-4.24,8.24)

(0.24,3.76)




Part A.  We have two equations:  y = 4-x   and   y = 8-x^-1

Given two simultaneous equations that are both to be true, then the solution is the points where the lines cross. The intersection is where the two equations are equal. Therefore the solution that works for both equations is when

4-x = 8-x^-1

This is where the two graphs will cross and that is the common point that satisfies both equations.

Part B

see the attached table

the table shows that one of the solutions is in the interval [-1,1]

Part C To solve graphically the equation 4-x = 8-x^-1

We would graph both equations: y = 4-x  and   y = 8-x^-1

The point on the graph where the lines cross is the solution to the system of equations.

using a graph tool

see the attached figure N 2

the solutions are the points

(-4.24,8.24) (0.24,3.76)

How many ears of corn would equal to 5 pounds?

Answers

7 ears equal five pounds.


I NEED UR HELP PLEASE..

Answers

cos θ = [tex] \frac{adj}{hyp} [/tex]

If θ = 30° ; adj = 2 ; hyp = x

Then cos 30° = [tex] \frac{2}{x} [/tex]

              ⇒  x  = [tex] \frac{1}{(cos30)(2)} [/tex]

                   x   =  2.31

Books spontaneously catch on fire in temperatures at or above 451, degree Fahrenheit. Write an inequality that is true only for temperatures (t)(t)left parenthesis, t, right parenthesis at which books spontaneously catch on fire.

Answers

For this case, the first thing you should do is define a variable.
 We have then:
 t: temperature (degree Fahrenheit).
 We write then the inequation that adapts to the problem:
 t> = 451
 Answer:
 
an inequality that is true only for temperatures at which books spontaneously catch on fire is:
 
t> = 451

Find the area of a trapezoid based on the information given below. H=4√2 b1=5√2 b2=3√2

Answers

The formula of the area of the trapezoid:
[tex]A=\dfrac{b_1+b_2}{2}\cdot h[/tex]
We have:
[tex]b_1=5\sqrt2;\ b_2=3\sqrt2;\ h=4\sqrt2[/tex]
Substitute:
[tex]A=\dfrac{5\sqrt2+3\sqrt2}{2}\cdot4\sqrt2=\dfrac{5\sqrt2}{2}\cdot4\sqrt2=\dfrac{5\cdot4\cdot\sqrt2\cdot\sqrt2}{2}\\\\=\dfrac{20\cdot2}{2}=20[/tex]
Used: [tex]\sqrt{a}\cdot\sqrt{a}=a[/tex]

1. For which angle is secant undefined?
a. 30°
b. 45°
c. 180°
d. 270°

2. Which of the following is csc(-166°) equal to?

a. csc⁡(14°)
b. -csc⁡(14°)
c. -csc⁡(-14°)
d. csc⁡(166°)

Answers

1. 180 aparently
2. stil looking
im in the same delima

1. The secant is defined as the inverse function of co-secant or cos function

Hence when the cosine is 0, the secant is 1/0 which is undefined. So, when cosine is 0, secant is undefined

Cos 30 = [tex] \sqrt{3} /2 [/tex]

Cos 45 = [tex] 1/\sqrt{2} [/tex]

Cos 180 = -1

cos 270 =0

Since cos 270 is 0, secant of 270 is undefined

Answer is d: 270


2. cosec (-x) = - cosec (180 -x)

We have cosec(-166) = - cosec (180-14) = -cosec (14)

Alternatively we can confirm this as csc (-166) = -4.133565 and -csc(14) = -4.133565; Hence, we can reconfirm that the answer arrived at is right

Therefore csc (-166) = -csc(14) (Option B) is the right answer



Please help :)
Solve the system of equations and choose the correct answer from the list of options.

d + e = 1
−d + e = −5

Label the ordered pair as (d, e). (4 points)


(0, 0)

(3, −2)

(−2, 3)

(−3, 0)

Answers

For a system of equations such as this, add both of the equations together. The d values will cancel each other out, making 2e=-4. This means that e=-2. If you plug this into one of the equations, you will have d + (-2) = 1. Isolate the variable by adding -2 to both sides: d=3. Written in the format described above (d,e), your answer is (3, -2).

(3, -2)

Given equations are

d+e=1

-d+e=-5

We need to find d and e.

What is system of equations?

A system of equations is a set of one or more equations involving a number of variables

The system of equations are

d+e=1....(1)

-d+e=-5....(2)

d=1-e (from 1)

Substitute d in (2)

-(1-e)+e=-5

-1+e+e=-5

-1+2e=-5

2e=-5+1

2e=-4

e=-2

Now substitute value of e in (1)

d-2=1

d=1+2

d=3

Therefore the ordered pair for d + e = 1 and −d + e = −5 is (3, -2)

i.e value of d=3 and e=-2

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10 - 3(3x - 40) = -9x A)x = -9 B)no solution C)x = 10 D)all real numbers

Answers

Remove the brackets on the left
10 - 9x + 120 = - 9x You get a bizarre result no matter what you try to do to resolve this. If you say any number will do pick, a number at random for x. Say 10

10 - 90 + 120 = -90 Is this statement true? No. You only need 1 exception but 0 is a popular number to look for answers. Will it work?
10 - 0 + 120 = 0 That doesn't work either.

There is no number you could pick that that would give you anything but 10 + 120 = 0

<<<<<< No Solution 

Iq test scores are normally distributed with a mean of 100 and a standard deviation of 15. find the x-score that corresponds to a z-score of 2.33.

Answers

Answer: 134.95 to be exact

you multiply the zscore with the standard deviation and add the mean

The formula for calculating the z-score:

z = (x - μ) / σ
Where

μ - mean

σ = standard deviation

The x-score that corresponds to a z-score of 2.33 is 134.95.

What is a mean?

It is the average value of the set given.

It is calculated as:

Mean = Sum of all the values of the set given / Number of values in the set

We have,

Iq test scores are normally distributed:

Mean = 100

Standard deviation = 15
z-score = 2.33

The formula for calculating the z-score:

z = (x - μ) / σ

Where

μ - mean

σ = standard deviation

Now,

2.33 = (x - 100) / 15

Multiply 15 on both sides.

2.33 x 15 = x - 100

34.95 = x - 100

Add 100 on both sides.

34.95 + 100 = x

x = 134.95

Thus,

The x-score that corresponds to a z-score of 2.33 is 134.95.

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Base your answer to the question on the diagrams shown below.

What is the probability of drawing a red card and then spinning a 1?

Answers

The probability of drawing a red card and spinning a 1 are independent events, thus to get the probability of them occurring at the same time we shall have:
P(Red)×P(Spinning 1)
P(Red)=2/5
P(Spinning 1)=4/8=1/2
Thus:
P(Red)×P(Spinning 1)=1/2×2/5=1/5

Answer: [tex]\frac{1}{5}[/tex]

Step-by-step explanation:

From the given picture, the total number of cards = 5

The number of red card = 2

Thus, the probability of drawing a red card P(red)=[tex]\frac{2}{5}[/tex]

Also, total number of digits on spinner = 8

Number of 1's=4

Thus, the probability of  spinning a 1 P( spinning 1)=[tex]\frac{4}{8}=\frac{1}{2}[/tex]

Since both the events of drawing a red card and spinning a 1 are independent events, therefore, the probability of drawing a red card and then spinning a 1=[tex]\text{ P(red)}\times\text{P( spinning 1)}=\frac{2}{5}\times\frac{1}{2}=\frac{1}{5}[/tex]

There was a sample of 200 milligrams of a radioactive substance to start a study. since then, the sample has decayed by 5.4% each year. let t be the number of years since the start of the study. let y be the mass of the sample in milligrams. write an exponential function showing the relationship between y and t .

Answers

For this case we have a function of the form:
 y = A * (b) ^ t
 Where,
 A: initial amount
 b: decrease rate
 t: time
 Substituting values we have:
 y = 200 * (0.946) ^ t
 Answer:
 
An exponential function showing the relationship between and and is:
 
y = 200 * (0.946) ^ t

The exponential function representing the relationship between the mass y of a radioactive sample in milligrams and t years since the start of the study is y = 200(1 - 0.054)^t.

The student is given a starting mass of a radioactive substance and the percentage of the mass that decays each year. To write an exponential function that models this situation, we consider the initial mass, which is 200 milligrams, and the decay rate, which is 5.4% per year. The relationship between the mass y and the time t in years can be represented by the formula y = 200(1 - 0.054)^t.

Using an exponential decay model, we understand that the amount of substance decreases by a certain percentage each year. To account for this, we raise the base (1 - 0.054) to the power of t, representing the number of years, which gives us the factor by which the original mass has reduced.

Other Questions
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