If the Earth and distant stars were stationary (motionless) in space, what would we observe about the wavelength from these stars?

A.Wavelengths measured would match the actual wavelengths emitted.
B.Wavelengths measured would be shorter than the actual wavelengths emitted.
C.Wavelengths measured would be longer than the actual wavelengths emitted.

If a star is moving toward us in space, what would we observe about the wavelength from these stars?

A.Wavelengths measured would be shorter than the actual wavelengths emitted.

B.Wavelengths measured would match the actual wavelengths emitted.

C.Wavelengths measured would be longer than the actual wavelengths emitted.

Answer:

C

Explanation:

Because the north and the south pole are like the earth if they didn't attracted  we would all die.

Magnetic fields have north and south magnetic poles. This statement best describes magnetic fields. So, option(C) is correct.

In the presence of a magnet, an electric current, or a shifting electric field, there is a vector field called a magnetic field where magnetic forces can be seen.

Electric charges in motion and the intrinsic magnetic moments of elementary particles connected to the fundamental quantum characteristic known as spin create a magnetic field.

As parts of the electromagnetic force, one of the four fundamental forces of nature, magnetic field and electric field are interdependent.

In magnetic field, there always be a north pole and a south pole because magnetic monopole doesn't exists. So, option (C) is correct.

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Answer: Option C

Explanation: The carbon dioxide is major green house gas that traps heat. But due to global warming the amount of carbon dioxide in the environment is increasing day by day.

The carbon dioxide gets in the ocean water and harms the organisms present in the ocean water. The coral present inside the water covers a very large area and is a major part of the marine ecosystem.

The carbon dioxide in excess leads to coral bleaching. This is a phenomenon in which the algae that is found inside the coral leaves the coral due to stress condition.

Thus, carbon dioxide in water increase the acidification in ocean which leads to coral bleaching.

Due to the magnitudes, as mentioned in the problem, being equal, B has components Acos(θ)x along the x-axis and Asin(θ) along the y-axis. 

The solution is as follows:

A+B has: 
total x-component = A + Acos(θ) = A(1+cos(θ)) 
total y-component = 0 + Asin(θ) = Asin(θ) 
Resultant = √[( A(1+cos(θ)))² + (Asin(θ))²] 
= A√[1 + 2cos(θ) + cos²(θ) + sin²(θ)] 
=A√[2 + 2cos(θ)] 

A-B has: 
total x-component = A - Acos(θ) = A(1-cos(θ)) 
total y-component = 0 - Asin(θ) = -Asin(θ) 
Resultant = √[( A(1-cos(θ)))² + (-Asin(θ))²] 
= A√[1 - 2cos(θ) + cos²(θ) + sin²(θ)] 
=A√[2 - 2cos(θ)] 

A+B/A-B = [A√[2 + 2cos(θ)]] / A√[2 - 2cos(θ)] 
= [√[2 + 2cos(θ)]] / [√[2 - 2cos(θ)]] 

110 = [√[1 + cos(θ)]] / [√[1 - cos(θ)]] 
12100 = [1 + cos(θ)] / [1 - cos(θ)] 

12100 - 12100cos(θ) = 1 + cos(θ)
12101cos(θ)] = 12099 
cos(θ)= 0.999834724
θ = 1.04º

The time it would take for the sound wave to travel to a subject 3.42m away and back, with a sound speed of 343 m/s, is approximately 0.01995 seconds.

The time it takes for the sound wave to return to the camera can be found by applying the equation distance = speed * time. This principle is often utilized in technologies such as sonar and ultrasound imaging. Here the distance is doubled since the sound has to travel to the subject and back to the camera. If the subject is 3.42 m away, the total distance covered by the sound wave is 3.42m * 2 = 6.84m. Given that the speed of sound is 343 m/s, we can rearrange the equation to solve for time: time = distance/speed. Hence, time = 6.84m / 343 m/s = 0.01995 s, rounded to 5 decimal places.

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It takes 0.02 seconds for the sound wave to return to the camera if the subject were 3.42 metres away.

The given question can be solved by simple use of kinematic equations. It is given that the camera determines the distance to the subject by sending out a sound wave. The speed of the sound wave is v = 343 m/s

Now, for a subject at a distance of 3.42 metres away the sound wave has to travel to the subject and travel back to the camera as well. Therefore the total distance covered by the sound wave will be twice the distance of the subject from the camera.

d = 2 × 3.42 m = 6.84 m

From the kinematic equation;

[tex]v = \frac{d}{t}[/tex], where t = time taken

rearranging for t, we get:

[tex]t = \frac{d}{v}[/tex]

substituting the values,

[tex]t = \frac{6.84 m}{343 m/s}[/tex]

or, t = 0.019 s ≈ 0.02 s

Answer:

Work can transfer energy between objects and can cause a change in the form of energy.

Explanation:

The best explanation can be done with an example.Consider an apple of mass m falling from a tree. Initially, the apple is at rest on the tree, at a certain height h above the ground, so it has a form of energy called gravitational potential energy, equal to: where g is the acceleration due to gravity.As the apple falls, the force of gravity acts on it, and so this force does work on the apple. As a result, the potential energy of the apple is converted into another form of energy, kinetic energy, which is the energy due to the motion of the apple: where v is the speed of the apple.Consider another example: a man pushing a box along the floor with a force F. The man is doing work on the box, and this work is equal towhere d is the displacement of the box. As a result of this work, some of the chemical energy contained in the muscles of the man is transferred into the box and converted to kinetic energy of the box, which is put in motion and it gains a certain speed v. In particular, if there are no frictional forces involved, the work done by the man is equal to the kinetic energy gained by the box.

Answer:

The linear  velocity of the tip of the blade is 940.94 ft/min.

Explanation:

It is given that,

A mixing blade on a food processor extends out 3 inches from its center, r = 3 inches = 0.0762 meters

Angular speed of the blade, [tex]\omega=600\ rev/minute=62.83\ rad/s[/tex]  

Let v is the linear velocity of the tip of the blade. The relation between the angular velocity and the linear velocity is given by :

[tex]v=r\times \omega[/tex]

[tex]v=0.0762\times 62.83[/tex]    

v = 4.78 m/s

or

Since, 1 m/s = 196.85 ft/min

4.78 m/s = 940.94 ft/min

So, the linear  velocity of the tip of the blade is 940.94 ft/min. Hence, this is the required solution.          

Final answer:

The units of specific heat, which indicate the amount of energy needed to raise the temperature of 1 g of a substance by 1°C, are joules per kilogram Kelvin (J/(kg·K)) or joules per kilogram degree Celsius (J/(kg·°C)) in the SI system, and calories (cal) in non-SI units.

Explanation:

The units of specific heat are an important aspect in understanding how much energy is required to change the temperature of a substance. The specific heat of a substance is the amount of energy needed to increase the temperature of 1 gram of the substance by 1°C. In the International System of Units (SI), the unit of specific heat is joules per kilogram Kelvin (J/(kg·K)) or joules per kilogram degree Celsius (J/(kg·°C)). Additionally, the non-SI unit called the calorie (cal) is sometimes used, where 1 calorie is the energy required to raise the temperature of 1 gram of water by 1°C.

It's important to note that the value of specific heat remains the same whether measured in J/(kg·K) or J/(kg·°C), since the temperature change is the same whether expressed in Kelvin or degrees Celsius. For practical and historical reasons, other units like the calorie and the kilocalorie (kcal) are also used, particularly in contexts like food energy where 'calories' commonly refer to kilocalories.

Answer:

hypotenuse² = base² +height²

Explanation:

Let us suppose a right angled triangle having b as base, h as hypotenuse and p as perpendicular distance.

The relation between the length of legs, the base and the hypotenuse is called Pythagoras theorem. It is given by :

[tex]h^2=b^2+p^2[/tex]

or

hypotenuse² = base² +height²

Answer:

The relation between the length of the hypotenuse in a right triangle and  lengths of the legs is [tex]H^{2} = p^{2}+b^{2}[/tex].

Explanation:

The legs of right angled triangle is also known as perpendicular and base respectively.

Let p be length of perpendicular and b be the length of base. Then by Pythagoras theorem,

[tex]H^{2} = p^{2}+b^{2}[/tex]

here, H is the length of Hypotaneous.

Thus, relation between the length of the hypotenuse in a right triangle and  lengths of the legs is [tex]H^{2} = p^{2}+b^{2}[/tex].

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The chromosphere is a thin layer of the atmosphere of the sun (or any other star) above the photosphere and below the corona. It consists mainly of hydrogen and helium.

This layer is very faint and reddish when it becomes visible, for a few seconds, at the beginning and end of a Solar  eclipse and its appearance is not homogeneous.

Answer:

chromosphere

Explanation:

I got it right on study island

Final answer:

According to Ohm's law, since circuit A has a resistor four times larger than circuit B and both have identical voltage sources, the current in circuit A is one fourth as large as in circuit B.(Option D)

Explanation:

If two circuits have identical voltage sources and resistors and the resistance in circuit A is four times as large as the resistance in circuit B (RA = 4RB), we can apply Ohm's law (V = IR) to determine the relationship between the currents in each circuit. Since the voltage (V) across both circuits is the same, and the resistance (R) is four times higher in circuit A compared to circuit B, the current in circuit A will be four times smaller than the current in circuit B. Ohm's law rearranged to solve for current (I) is I = V/R.

Therefore, with a higher resistance in circuit A, the current is inversely proportional to the resistance. Hence, the correct statement is:

The current flowing through circuit A is one fourth as large as the current flowing through circuit B (Option D).

Answer:

c)charged

Explanation:

The Modified Mercalli scale is used measures the amount of damage done during an earthquake. This helps to locate the epicenter of the earthquake.  It depicts the intensity of the earthquake based on the damage occurred due to the earthquake. The responses from many people who experienced the earthquake are collected by the scientists, assigned a value and plotted on a map

The plotted number can change with the reference place within the region of disturbance. It depends on the location of the observer with reference to the epicenter of the earthquake. The reporting depends on the witness. Some can exaggerate the extent of damage caused. All  the above mentioned are possible sources of error  when using the Modified Mercalli scale to locate the earthquake's epicenter.

Answer:

150

Explanation:

edg 2022, electric potential difference assignment (slide 4/9)

Answer:

i think it's b

Explanation:

The group incorrectly assumes that ozone layer depletion is connected to global warming when they are separate issues. Ozone depletion is about the loss of stratospheric ozone that protects from ultraviolet radiation, while global warming concerns the greenhouse gas effect and climate change.

The major flaw in the reasoning of the political action group that wants to overturn the Montreal Protocol is c. The loss of stratospheric ozone is not connected to global warming. There is a common misconception that ozone layer depletion and global warming are directly related, but they are in fact separate phenomena resulting from different processes in the atmosphere. The ozone layer, consisting of ozone (O3) molecules, is crucial for absorbing harmful ultraviolet radiation from the sun and thereby protecting living organisms. The Montreal Protocol aimed to reduce the production and release of industrial chemicals like chlorofluorocarbons (CFCs), which were proven to contribute to ozone depletion. While the protocol led to a significant reduction in CFCs and a gradual recovery of the ozone layer, this effort is different from initiatives like the Kyoto Protocol, which address greenhouse gas emissions and aim to mitigate global warming.

Answer: 1. B) 720 N

2. D) 2500 m

3. D) 408 Hz

4. C) 4m

5. A) 246 hz

6. D) 31st

7. B) the frequency of the sound is 100 Hz

8. C) 0.78 m

9. B) 16 Hz

10. B) 311 m/s