If the radius of a cone is doubled and the height is tripled, what happens to the volume?
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Related Questions
What is the slope of the line? A) -3 B) - 1/3 C) 1/3 D) 3
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slope = (y2 - y1)/(x2 - x1)
slope = (4 - 1)/(2 - 1) = 3/1 = 3
answer
D) 3
I suck at math lol. Could someone give me the answers in detail? Picture attached! Thanks
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Volume=πr²h
r=1.7m, h=15 m
plugging in the values in our formula we get:
V=π(1.7)²×15
V=43.35π
Answer: 43.35π m³
12]
Volume of the oblique cylinder will be:
V=πr²h
r=4 in, h=8
thus
V=π×4²×8
V=128π in²
Answer: 128π in²
Q9 Q3.) Solve the matrix equation 4X + 5A = B
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See pictures below for the answer! My handwriting isn't that good. Let me know if you can't read it :)
Which values of x would make a polynomial equal to zero if the factors of the polynomial were (x-2) and (x-11)?
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x-2=0
x=2
x-11=0
x=11
A polynomial will be equal 0 if x=2, or x=11.
Answer:
[tex]x=2\text{ (or) }x=11[/tex]
Step-by-step explanation:
We have been given factors of a polynomial as [tex](x-2)[/tex] and [tex](x-11)[/tex]. We are asked to find the values of x that would make the polynomial equal to zero.
We will use zero product property of polynomials to solve our given problem. The zero product property of polynomials states that if any of two factors of a polynomial is zero, then their product will be equal to zero.
Upon equating our given factors to zero, we will get:
[tex](x-2)(x-11)=0[/tex]
[tex](x-2)=0\text{ (or) }(x-11)=0[/tex]
[tex]x-2=0\text{ (or) }x-11=0[/tex]
[tex]x-2+2=0+2\text{ (or) }x-11+11=0+11[/tex]
[tex]x=2\text{ (or) }x=11[/tex]
Therefore, [tex]x=2\text{ (or) }x=11[/tex] will make the polynomial equal to zero.
what is the solution to the equation 3sqrt(5x-4)=3sqrt(7x+8)
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However this is an extraneous solution since it would make the number under the sqrt a negative number.
Answer:
The answer is: 'no solution'
Step-by-step explanation:
The given equation is: [tex]3\sqrt{5x-4}=3\sqrt{7x+8}[/tex]
Dividing both sides of the equation by 3, we will get.....
[tex]\sqrt{5x-4}=\sqrt{7x+8}[/tex]
Taking square on both sides.....
[tex](\sqrt{5x-4})^2=(\sqrt{7x+8})^2\\ \\ 5x-4=7x+8\\ \\ 5x-7x=8+4\\ \\ -2x=12\\ \\ x=\frac{12}{-2}=-6[/tex]
Plugging this [tex]x=-6[/tex] back to the given equation......
[tex]3\sqrt{5(-6)-4}=3\sqrt{7(-6)+8}\\ \\ 3\sqrt{-34}=3\sqrt{-34}[/tex]
As we are getting a negative number inside the square root, so the equation becomes imaginary. Thus [tex]x=-6[/tex] is a restricted value.
Hence, there is 'no solution' for this equation.
Suppose you have an isosceles triangle, and each of the equal sides has a length of 1 foot. suppose the angle formed by those two sides is 45^\circ. then the area of the triangle is
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The base angles are congruent and measure 67.5 deg.
The congruent sides measure 1 ft.
Use law of sines to find the length of the base.
[tex] \dfrac{\sin 67.5^\circ}{1~ft} = \dfrac{\sin 45^\circ}{b} [/tex]
[tex] b = \dfrac{\sin 45^\circ}{\sin 67.5^\circ}~ft [/tex]
[tex] b = 0.765~ft [/tex]
Draw a height from the vertex of the 45-deg angle to the base.
Half of the base is 0.765 ft/2 = 0.383 ft
We can find the height of the triangle using the small triangles.
0.383^2 + h^2 = 1^2
h = 0.9239 ft
A = bh/2 = 0.765 * 0.9239/2 ft^2
A = 0.354 ft^2
The area of a given isosceles triangle with sides of 1 foot in length and a 45-degree angle between these sides is 0.5 square feet.
Explanation:The area of an isosceles triangle can be calculated using the formula 1/2 base times height. But since we know that the triangle is isosceles and the angle between the equal sides is 45 degrees, this forms a 45-45-90 degree triangle which is a special kind of triangle. In a 45-45-90 degree triangle, the lengths of the sides are in the ratio 1:1:√2. Therefore, the length of the base (which also serves as the height in this case) will be the same length as the equal sides, 1 foot. Substituting these into the formula for area, we get Area = 1/2 * 1 ft * 1 ft = 0.5 square feet.
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A triangle has side lengths of 10 centimeters, 2 centimeters, and c centimeters.
Enter a value to complete the inequality that describes the possible values for c, the length of the third side of the triangle.
HELP ASAP I COULD GET A PRESIDENTIAL AWARD FOR THIS!!!
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Answer:
12
Step-by-step explanation:
The possible values of the third side of the triangle can be written as, 8 < c < 12.
What is Triangle?A triangle is a two dimensional figure which consist of three vertices, three edges and three angles.
Sum of the interior angles of a triangle is 180 degrees.
Given a triangle.
Side lengths of the triangle are 10 centimeters, 2 centimeters, and c centimeters.
We have to find the possible values of c.
By the triangle Inequality Theorem,
10 - 2 < c < 10 + 2
8 < c < 12
Hence the possible values of c are 9, 10 and 11.
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dr. Trekcir has $875 to invest. he invests some of it in account#1 paying 8% annual interest and the rest of it in account#2 paying 4% annual interest. After 1 year total interest is $49.00. find hou much is invested in each account
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0.08n + 0.04(875-n) = 49
Multiply both sides by 100:
8n + 3500 - 4n = 4900
Simplify:
4n+3500=4900
Isolate n:
4n = 1400
n = 350
8% invested: 350
4% invested: 525
What percent of the scores were between 71 and 96
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What is the y-intercept of the quadratic y=-2x^2-4x-5 ?
(-5,0)
(0,-2)
(-1,3)
(0,-5)
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We have: [tex]y=-2x^2-4x-5\to f(0)=-2(0)^2-4(0)-5=-5[/tex]
Answer: (0; -5)
A die is continuously rolled until the total sum of all rolls exceeds 375. what is the probability that at least 90 rolls are necessary?
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Final answer:
To find the probability of at least 90 rolls being necessary for the total sum of all rolls to exceed 375, we need to consider the probabilities associated with each roll.
Explanation:
To find the probability of at least 90 rolls being necessary for the total sum of all rolls to exceed 375, we need to consider the probabilities associated with each roll.
The maximum possible sum from a single roll of a six-sided die is 6, so after 90 rolls, the maximum possible sum is 90 * 6 = 540. If the total sum exceeds 375, it means that at least one roll resulted in a value greater than 2.
To calculate the probability, we need to find the complement of the event that the total sum is less than or equal to 375, which is the event of the total sum being greater than 375. Let's assume that the probability of rolling a value greater than 2 is p. The probability of at least 90 rolls being necessary is 1 - (1 - p)^90.
hello can you please help me posted picture of question
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Number of women = 6
Probability of selecting 1st women = 6/10
Probability of selecting 2nd women = 5/9
Probability of selecting 3rd women = 4/8
Probability that are 3 selected candidates are women = 6/10 x 5/9 x 4/8 = 1/6
So, the correct answer is option A
a cube with side length s has a volume of 216 cubic centimeters. the equation s^3 = 216 shows the volume of a cube. what is the side length of the cube in centimeters
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So you just need to take cubic root of 216.
Since 6³ = 216, then ∛( 216 ) = 6
So the side length of the cube would be 6 cm.
Hope this helps.
The foci of the hyperbola are ( 13 , 0) and (− 13 , 0), and the asymptotes are y = 12 x and y = − 12 x. find an equation of the conic section with the given properties. use x and y as the variables in your answer.
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y=-+12x
12=a/b
a=12b
c²=a²+b²
(13,0) and (-13,0)
13²=(12b)²+b²
169=145b²
b= 13/12
169=a²+169/145
a²= 24336/145
x²/a²-y²/b²=1
145x²/24336 + 145y²/169=1
The equation of the conic section is [tex]\frac{145x\²}{24336} - \frac{145y\²}{169}=1[/tex]
The foci of the hyperbola are given as: (13,0) and (-13,0)
The asymptote is given as [tex]y =\pm 12x[/tex]
Divide both sides of [tex]y =\pm 12x[/tex] by x.
[tex]\frac yx = \pm 12[/tex]
Where y/x = a/b.
So, we have:
[tex]\frac ab = \pm 12[/tex]
Make a the subject
[tex]a = \pm 12b[/tex]
Recall that
[tex]c\²=a\²+b\²[/tex]
Where:
[tex]c = \pm13[/tex]
[tex]c\²=a\²+b\²[/tex] becomes
[tex](\pm 13)^2 = (\pm 12b)^2 +b^2[/tex]
[tex]169 = 144b^2 +b^2[/tex]
Evaluate like terms
[tex]169 = 145b^2[/tex]
Make b^2 the subject
[tex]b^2 = \frac{169}{145}[/tex]
Recall that [tex]a = \pm 12b[/tex]
Square both sides
[tex]a^2 = 144b^2[/tex]
Substitute [tex]b^2 = \frac{169}{145}[/tex]
[tex]a^2 = 144 \times \frac{169}{145}[/tex]
[tex]a^2 = \frac{24336}{145}[/tex]
The equation of the conic section is represented as:
[tex]\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1[/tex]
Substitute known values
[tex]\frac{x^2}{24336/145} - \frac{y^2}{169/145} = 1[/tex]
Rewrite as:
[tex]\frac{145x\²}{24336} - \frac{145y\²}{169}=1[/tex]
Hence, the equation of the conic section is [tex]\frac{145x\²}{24336} - \frac{145y\²}{169}=1[/tex]
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N a class, 20% of the students are male and 80% female. among male students, 40% wears eyeglasses; among female students, 30% wear eye glasses. if we select a student from the class at random, what is the probability that the student wears eyeglasses
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Can someone help with this math question
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[tex]y=mx+b[/tex]
being m the slope of the line and b the y-intercept of it.
On the other hand, if x = 0 then y = b.
We will order the equations above without inequalities like this:
[tex]y=-x-6[/tex]
So, the G and J are straight lines with negative slope. We need to find the one that matches the inequality. Taking a point, for example (0, 0), we will analyze Figure J, so in the inequality:
[tex]0+0\ \textless \ -6[/tex]
This is false, so this statement doesn't match the Figure J. Therefore, the answer is G.
The area of the parallelogram is 65 square miles. Find its base and height.
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(base 5) (height 13)
Base = 13
Height = 5
Or:
Base = 5
Height = 13
Hope this helped☺☺
Ted researched the price of airline tickets and discovered a correlation between the price of a ticket and the number of miles traveled. After recording his data on a scatter plot, he determined the equation for the line of best fit is y = 300 + 0.45x. What does 0.45 represent in the equation? A) the lowest ticket price B) the number of miles traveled C) the expected change in the price of multiple tickets Eliminate D) the expected change in price of the ticket for each mile traveled
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Because it is a coloration between the two
Because it is a coloration between the two
Find an equation in standard form for the ellipse with the vertical major axis of length 16 and minor axis of length 4
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Given the lengths of the major and minor axes of an ellipse, one can derive the standard form equation of the ellipse. In this example, the lengths were 16 and 4, yielding a standard form equation of x²/4 + y²/64 = 1.
Explanation:The subject of this question is about finding the standard form equation for an ellipse given the lengths of the major and minor axes. To find the equation of the ellipse, we need to identify the semi-major axis (a) which is half the length of the major axis, and the semi-minor axis (b), which is half the length of the minor axis.
In this case, the lengths of the major and minor axes are 16 and 4 respectively, which gives us a semi-major axis of 8 and a semi-minor axis of 2. The standard form equation of an ellipse with a vertical major axis is given by:
(x-h)²/b² + (y-k)²/a² = 1
Where (h, k) is the center of the ellipse. In this case, since the center of the ellipse is at the origin (0,0), the equation becomes:
x²/4 + y²/64 = 1
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if an object is propelled upward from a height of s feet at an initial velocity of v feet per second h=-16t^2+96t+8 after how many seconds is the height 116 feet?
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The perimeter of the base of a regular quadrilateral prism is 60 cm, the area of a lateral face is 105 cm2. Find: the volume of the prism
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s = P/4
s = (60 cm)/4 = 15 cm
The area of one lateral face is the product of side length and height.
A = s×h
105 cm² = (15 cm)×h
Then the height of the prism is
h = (105 cm²)/(15 cm) = 7 cm
The area of the base is then
B = s²
B = (15 cm)² = 225 cm²
The volume of the prism is the product of its base area and height.
V = Bh
V = (225 cm²)×(7 cm) = 1575 cm³
The volume is 1575 cm³.
What is is the equation of the line perpendicular to y = 3x-7 that contains the point (6,8)?
A. 1/3x - 7
B. 1/3x + 6
C. -1/3x - 7
D. -1/3x + 10
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m = -1/(3) = -1/3
Only choices C and D have this slope. Only choice D goes through the given point. (-1/3)*6 +10 = -2 +10 = 8.
The appropriate selection is ...
D. (-1/3)x + 10
The equation of the line perpendicular to y = 3x -7 that passes through the point (6, 8) is Option D. y = -1/3x + 10. The slope of the perpendicular line is -1/3. Using point-slope form, we determine the final equation.
To find the equation of a line perpendicular to y = 3x - 7 that passes through the point (6, 8), we must determine the slope of the perpendicular line first.
The slope of the given line is 3. The slope of a line perpendicular to this one is the negative reciprocal of 3, which is -1/3.
We now use the point-slope form of the linear equation, which is:
y - y₁ = m(x - x₁)
Substitute m = -1/3 and the point (6, 8):
y - 8 = -1/3(x - 6)
Distribute -1/3:
y - 8 = -1/3x + 2
Add 8 to both sides:
y = -1/3x + 10
Thus, the equation is Option D. -1/3x + 10.
Someone please help.
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In this case the common ratio is -3.
As,
- 3.49 x -3 = 10.47
10.47 x - 3 = -31.41
and so on...
So, the next number of the series will be:
94.23 x - 3= -282.69
Thus, the answer to this question is - 282.69
What situation should be used to rewrite 16(x^3+1)^2 -22(x^3+1)-3=0 as a quadratic equation
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Use substitution: [tex]x^3+1=t[/tex]
[tex]16t^2-22t-3=0\\\\16t^2-24t+2t-3=0\\\\8t(2t-3)+1(2t-3)=0\\\\(2t-3)(8t+1)=0\iff2t-3=0\ \vee\ 8t+1=0[/tex]
[tex]2t-3=0\ \ \ |+3\\\\2t=3\ \ \ |:2\\\\t=\dfrac{3}{2}\\..............................\\8t+1=0\ \ \ \ |-1\\\\8t=-1\ \ \ \ |:8\\\\t=-\dfrac{1}{8}[/tex]
we're going back to substitution:
[tex]x^3+1=\dfrac{3}{2}\ \vee\ x^3+1=-\dfrac{1}{8}\ \ \ \ |subtract\ 1\ from\ both\ sides\ of\ the\ equations\\\\x^3=\dfrac{1}{2}\ \vee\ x^3=-\dfrac{9}{8}\\\\x=\sqrt[3]{\dfrac{1}{2}}\ \vee\ x=\sqrt[3]{-\dfrac{9}{8}}[/tex]
[tex]x=\dfrac{1}{\sqrt[3]2}\ \vee\ x=-\dfrac{\sqrt[3]9}{2}\\\\\boxed{x=\dfrac{\sqrt[3]4}{2}\ \vee\ x=-\dfrac{\sqrt[3]9}{2}}[/tex]
solve the system using substitution method
3x+y=6
2x-4y=10
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[tex]\boxed{\left\{\begin{array}{ccc}x=\dfrac{17}{7}\\\\y=-\dfrac{9}{7}\end{array}\right}[/tex]
Multiply 4 to the first equation:
[tex]\begin{cases}&12x + 4y = 24 \\&2x - 4y = 10\end{cases}[/tex]
ADD Equation 1 to Equation 2 and find x:
[tex]\begin{aligned}&14x =34 \\&x= 34/14 \\& x = 17/7\end{aligned} [/tex]
Substitute x = 17/7 and find y:
[tex]\begin{aligned}&3x + y = 6 \\&3 (17/7) + y = 6 \\& 51/7 + y = 6 \\&y = -9/7\end{aligned} [/tex]
Answer: x = 17/7, y = -9/7
If the volume is 56 1/4 cubic feet and the length is 7 1/2ft and the width is 3 3/4ft what is the height?
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What is the value of x in the equation –6 + x = –2?
8
4
–4
–8
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2.
Find the annual percentage rate, using the annual percentage rate table.
Amount Financed: $8,900
Finance Charge: $1,030.62
Number of Payments: 24
Answers
Finance Charge: $1,030.62
Number of Payments: 24
(Finance Charge)/(Amount Financed)*100$=($1,030.62)/($8,900)*100$
(Finance Charge)/(Amount Financed)*100$=(0.1158)*100$
(Finance Charge)/(Amount Financed)*100$=$11.58
In the row of number of Payments 24, we look for:
(Finance Charge)/(Amount Financed)*100$=$11.58, and we to which annual porcentage rate it corresponds in the first row
Answer: The annual percentage rate is 10.75%
5u exponent 7 - 21u exponent 7
Simply
Answers
Since both algebraic terms are identical (both are using u^7), we can subtract the coefficients directly, as in: 5 - 21 = -16
Therefore, 5u^7 - 21u^7 = -16u^7
hello can you please help me posted picture of question