(II) A 20.0-kg box rests on a table. (a) What is the weight of the box and the normal force acting on it? (b) A 10.0-kg box is placed on top of the 20.0-kg box, as shown in Fig. 4–43. Determine the normal force that the table exerts on the 20.0-kg box and the normal force that the 20.0-kg box exerts on the 10.0-kg box.
Answers
*Fig is Attached with answer*
Answer:
(a) Weight = Normal Force = 196.2 N
(b) Normal force table on 20 kg box = 294.3 N
Normal force 20 kg box on 10 kg box = 98.1 N
Explanation:
(a) Mass = m = 20 kg g = 9.81 m/s²
Weight = w = mg
w = 20 × 9.81
w = 196.2 N
As the box rests on the table so, normal force (NF) must be equal to the weight of the box.
NF = w = 196.2 N
(b)
m₁ = 20 kg m₂ = 10 kg
total mass = M = 30 kg
Total Weight = W = Mg
= 30 × 9.81
= 294.3 N
As both the boxes rest on the table so, normal force (NF) must be equal to the total weight of the boxes.
NF = W = 294.3 N
Weight of 10 kg box = 10 × 9.81 = 98.1 N
As the 10 kg box is placed on the top of 20 kg box, So 20 kg box must exert a normal force that is equal to the weight of 10 kg box.
Normal Force = Weight of 10 kg box = 98.1 N
The normal force acting on the body is equal to its weight, hence;
N = W = 196N
The normal force that the 20.0-kg box exerts on the 10.0-kg box is 98N
The formula for calculating the weight of an object is expressed as:
W = mg
m is the mass of the object
g is the acceleration due to gravity.
Given the following parameters
Mass of the box = 20.0kg
a) The weight of the box = 20 * 9.8
Weight of the box = 196N
Hence the weight of the box is 196N
Note that the normal force acting on the body is equal to its weight, hence;
N = W = 196N
b) if a 10.0-kg box is placed on top of the 20.0-kg box, the total mass will be;
M = 10 + 20 = 30kg
total weight = 30 * 9.8
Total weight = 294N
Since the normal force is equal to the weight, hence W = N = 294N
Weight of the 10kg box = 10 * 9.8 = 98N
Since the 10kg box is on top of the 20kg box, hence the normal force that the 20.0-kg box exerts on the 10.0-kg box is 98N
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Related Questions
A bird can fly at 32 km/h. How long does it take to fly 22 km?
Answers
Answer:
It takes the bird 0.6875 hour to fly 22 km
Explanation:
Lets revise the relation between the distance, speed and time
→ Distance = speed × time
→ Speed = distance ÷ time
→ Time = distance ÷ speed
A bird can fly at 32 km/h
The speed of the bird is 32 km/h
The bird will fly 22 km
We need to find the time it takes the bird to fly this distance
The speed = 32 km/h
The distance 22 km
Lets use the rule:
→ Time = distance ÷ speed
→ Time = 22 ÷ 32 = 0.6875 hour
It takes the bird 0.6875 hour to fly 22 km
Why does a heavier object fall faster
Answers
Explanation:
In a vacuum (no air resistance), it doesn't. All falling objects, regardless of mass, accelerate at the same rate.
However, when air resistance is taken into account, heavier objects indeed fall faster than lighter objects, provided they have the same shape and size. For example, a lead ball falls faster than a styrofoam ball.
To understand why, first look at what factors affect air resistance:
D = ½ρv²CA
where ρ is air density,
v is velocity,
C is drag coefficient,
and A is cross sectional area.
As falling objects accelerate, they eventually reach a maximum velocity where air resistance equals weight. This is called terminal velocity.
D = W
½ρv²CA = mg
v = √(2mg/(ρCA))
If we increase m while holding everything else constant, v increases. So two objects with the same size and shape but different masses will have different terminal velocities, with the heavier object falling faster.
Before you ask why, you need to know whether.
On the moon, or any other airless body, all objects fall together, no matter how much each one weighs. We've known this for a good 500 years.
On Earth, if one object falls slower, it's only because the air caught it and held it back.
____ are formed where bumps from two surfaces come into contact.
Answers
the answer is Friction.
hope this heslp
Micro welds are formed where bumps from two surfaces come into contact.
Explanation:
The surface of all existing objects or elements, have some bumps and dips. Whenever the surfaces of two different bodies with bumps and dips come into contact with each other, sticking occur.
This causes the production of micro welds between the two surfaces that inhibit the smooth motion. These micro welds create a static force that opposes the smooth motion between the surfaces. This is called “friction”.
This friction force can be stopped only when it can either be dominated with the equal opposite force or inhibited with lubricating agents that reduce its effect on the surfaces of the two respective objects.
11. Ionization energy is the amount of energy necessary to
form an anion
remove an electron from an atom
to fill the outer energy level with electrons
form an ionic bond
Answers
Answer: Ionization energy is the amount of energy necessary to remove an electron from an atom
Explanation:
Ionization consists of the production of ions, which are electrically charged atoms or molecules due to the excess or lack of electrons with respect to a neutral atom or molecule.
In this sense, ionization energy is the energy necessary to separate (remove) an electron from a gaseous atom, isolated and in a fundamental state. This is because electrons are strongly attracted to the nucleus and it is necessary to provide energy to separate them. However, where the atom always loses electrons is in the last layer, which is where the weakest electrons are attracted to the nucleus.
A family wants to determine how much of the total monthly income is going to various expenditures (food, housing, utilities, etc.). Which of the following would be most helpful in displaying this data?
circle graph
line graph
bar graph
frequency table
I NEED THIS ANWSER ASAP 98 POINTS
Answers
Answer:
circle graph
Explanation:
A circle graph it is a statistical resource that is used to represent percentages and proportions. The number of elements compared within this graph can range from two to as many as required. Thus, Using this graph you can visualize the proportion of each expense, like food and housing, with respect to the total monthly income.
Answer:
circle graph
Explanation:
did the test
Which of the following can be natural sources of water pollution? a. volcanic activity b. earthquakes c. algae blooms d. all of the above Please select the best answer from the choices provided A B C D
Answers
The natural sources of water pollution are algae blooms.
Answer: Option C
Explanation:
The natural form of water pollution is due to water erosion, the composition of minerals, leaves, human/animal droppings, etc. Algae blooms are the development of phytoplankton (a tiny floating plants in fresh and salt water).
Algae bloom also causes problems in the aquatic ecosystem. The excessive algae can block sun rays and hence affect important aquatic habitats.
This can also be seen in the fish gills and inhibit their breathing. When a significant bloom of algae dies, they can damage the available oxygen in the water and make it uninhabitable for other life forms.
Answer:
C. Algae blooms
Explanation:
Algae blooms grow largely and rapidly in fresh and marine water. It discolors the water. These can produce toxins in water and are very harmful for marine life as it blocks the sunlight from reaching the depth. Also, marine life struggles to find food and eventually leaves the area. It also badly impacts the local economy. It is the natural source of water pollution.
A rider on a water slide goes through three different kinds of motion, as illustrated in the figure below. Use the data and the details from the figure to answer the following questions. Remember, when an object is in a circular motion it is accelerated toward the center of the circle with acceleration a = v2/r
a) At the end of the first section of the motion, riders are moving at approximately what speed? Show your work for partial credit.
A. 3 m/s B. 6 m/s C. 9 m/s D. 12 m/s
b) Suppose the acceleration during the second section of the motion is too large to be comfortable for the riders. What change could be made to decrease the acceleration during this section?
A. Reduce the radius of the circular segment
B. Increase the radius of the circular segment
C. Increase the angle of the ramp.
D. Increase the length f the ramp.
c) What is the vertical component of the velocity of the rider as he hits the water? Show your work for partial credit.
A. 2.4 m/s B. 3.4 m/s C. 5.2 m/s D. 9.1 m/s
d) Suppose the designers of the water slide want to adjust the height h above the water so that the riders land twice as far away from the bottom of the slide. What would be the necessary height above the water? Show your work for partial credit.
A. 1.2 m B. 1.8 m C. 2.4 m D. 3.0 m
e) During which section of the motion is the magnitude of the acceleration experienced by the rider the greatest?
A. The first B. The second C. The third D. It is the same in all sections
Answers
a) C. 9 m/s
First of all, let's calculate the difference in height between the starting point of the motion and the end point of the first section. It is given by:
[tex]\Delta h = L sin \theta[/tex]
where
L = 6.0 m
[tex]\theta=45^{\circ}[/tex]
Substituting,
[tex]\Delta h = (6.0)(sin 45^{\circ})=4.2 m[/tex]
Assuming the rider starts from rest, its initial speed is zero. For the law of conservation of energy, the decrease in gravitational potential energy of the rider will be equal to its gain in kinetic energy, so we can write:
[tex]mg\Delta h = \frac{1}{2}mv^2[/tex]
where m is the rider's mass, g = 9.8 m/s^2 is the acceleration of gravity, and v is the speed at the end of the first section. Solving for v, we find:
[tex]v=\sqrt{2g\Delta h}=\sqrt{2(9.8)(4.2)}=9.1 m/s \sim 9 m/s[/tex]
b) B. Increase the radius of the circular segment
In fact, the acceleration during the second section of the motion (circular motion) is given by the formula for the centripetal acceleration:
[tex]a=\frac{v^2}{r}[/tex]
where
v is the speed at the end of the first section
r is the radius of the circle
We notice that the acceleration is
- Proportional to the square of the speed
- Inversely proportional to the radius
So, we immediately see that if we increase the radius of the circle (choice B), the acceleration will decrease.
c) B. 3.4 m/s
When the rider exits the second section of the motion, he has a speed (completely horizontal) of 9.1 m/s (calculated in part (a); it didn't change, because the speed during the second section does not change).
The vertical component of his velocity is instead zero, since his motion is completely horizontal. Therefore, we can use the following SUVAT equation along the vertical direction:
[tex]v_y^2 - u_y^2 = 2g\Delta h[/tex]
where
[tex]v_y[/tex] is the vertical component of the velocity as the rider hits the water
[tex]u_y=0[/tex] is the vertical component of the velocity as the rider starts the 3rd section
[tex]\Delta h = 0.60 m[/tex] is the difference in height
Solving for [tex]v_y[/tex],
[tex]v_y = \sqrt{2g\Delta h}=\sqrt{2(9.8)(0.60)}=3.4 m/s[/tex]
d) C. 2.4 m
We want here the rider to land twice as far compared to before.
The horizontal distance travelled by the rider in section 3 is entirely determined by his horizontal motion. The horizontal component of the velocity, which is constant, is
[tex]v_x = 9.1 m/s[/tex]
calculated at part (a) and remained unchanged during section 2. The horizontal distance travelled during section 3 is
[tex]d=v_x t[/tex] (1)
where t is the time of the fall. This can be rewritten as
[tex]t=\frac{d}{v_x}[/tex]
We also know that the vertical displacement is:
[tex]h=\frac{1}{2}gt^2[/tex]
Substituting t from (1) into this equation, we find
[tex]h=\frac{gd^2}{2v_x^2}[/tex]
So we see that the height needed is proportional to the square of the distance: [tex]h \propto d^2[/tex]. Therefore, in order to land at twice the previous distance, the height must be 4 times the previous one, so:
[tex]h=4 (0.6 m)=2.4 m[/tex]
e) B. The second
We need to calculate the acceleration in each section.
In section 1 (motion along the slope), it is:
[tex]a=g sin \theta = (9.8)(sin 45^{\circ})=6.9 m/s^2[/tex]
In section 2 (circular motion), the acceleration is the centripetal acceleration:
[tex]a=\frac{v^2}{r}=\frac{9.1^2}{1.5}=55.2 m/s^2[/tex]
In section 3, the motion is free fall, so the acceleration is equal to the acceleration of gravity:
[tex]a=g=9.8 m/s^2[/tex]
Therefore, the rider experiences the largest acceleration in section 2.
This answer explains how to calculate the speed, acceleration, and vertical component of velocity for a rider on a water slide, as well as how to adjust the height to change the landing distance and determine the section with the greatest acceleration.
Explanation:To answer these questions about the rider on the water slide, we need to use the formula for acceleration in circular motion, which is a = v2/r. For question a, we can use the given information to calculate the speed at the end of the first section of motion. For question b, reducing the radius of the circular segment would decrease the acceleration during the second section. For question c, we need to calculate the vertical component of the rider's velocity as he hits the water. For question d, we can use the concept of projectile motion to determine the necessary height above the water to land twice as far away. Finally, for question e, we need to determine during which section of the motion the magnitude of the acceleration experienced by the rider is the greatest.
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? Help
How does your mass on the Moon compare to your mass on Earth?
OA) Your mass is less on the Moon.
O B) Your mass is greater on the Moon.
OC) Your mass is the same on the Moon and Earth.
Answers
Answer:
your mass is the same in the moon as on earth
Explanation:
on the monn there is less gravity than in the earth gravity determines the weight of an object but it can't change mass as mass is the amount of contents inside with out gravity
Final answer:
C) Your mass remains the same on the Moon as it is on Earth because mass is a measure of the amount of matter and does not change with location. However, your weight would be less on the Moon due to the weaker gravitational force compared to Earth's gravity.
Explanation:
When it comes to your mass on the Moon compared to your mass on Earth, your mass stays exactly the same in both locations. This is because mass is a measure of the amount of matter in an object, which does not change with location. On the other hand, weight is the force exerted on your mass by gravity, and this force does vary with location due to differences in gravitational pull.
Since the gravitational acceleration on the Moon is only about 1.625 m/s², compared to Earth's 9.80 m/s², your weight on the Moon would be significantly less than your weight on Earth, even though your mass remains unchanged. Therefore, if you were to scale, you would see a lower number on the Moon. Remember that while dieting might reduce your mass, simply stepping onto the Moon's surface only affects your weight, not your mass!
To conclude, the correct answer is:C) Your mass is the same on the Moon and Earth
. From the top of a building 85.0 meters tall a ball is dropped. At the same time another ball is thrown upward from the ground with a speed of 46.0 m/s. a. How long after the balls are released will they hit? b. How high above the ground will these two balls hit?
Answers
Answer:
a) Both balls are affected by gravity in the same way. The time both balls hit each other is equal to the time the ball thrown up reaches the top of the roof, if there was no gravity. (both balls would be at the same location)
y = v*t = 85m = 46m/s * t
t = 1.85s
Check:
The equation for position is given by:
y(t) = -0.5gt² + v₀t + x₀
The position of the ball on the roof top at time t = 1.85s:
y₁(t) = -4.9t² + 85.0 = 68.3m
The position of the ball thrown up at time t = 1.85s:
y₂(t) = -4.9t² + 46 * 1.85 = 68.3m
b) the two balls hit each other at a hight of 68.3m
The ball dropped from the building hits the ground after approximately 4.16 seconds. The ball thrown upward from the ground hits the ground after approximately 9.39 seconds. Both balls hit at the ground level.
Explanation:This question involves the concepts of motion in Physics. We'll use the formulas for kinematic motion to find out when and where the two balls hit. First, let's consider the ball that's dropped.
The ball drops with an initial speed of 0 m/s as the ball is released from rest and it will cover a distance of 85.0 meters under the acceleration due to gravity. We use the second equation of motion: s = ut + 0.5gt^2. Here, s is the displacement (85 meters), u is the initial speed (0 m/s), g is the acceleration due to gravity (9.8 m/s^2), and t is the time we wish to determine. Plugging the known values, we find t = sqrt(2s/g) which gives us t ≈ 4.16 seconds.
Now for the ball thrown upwards from the ground with an initial speed of 46.0 m/s. The ball goes upwards, then slows down, stops and starts falling down under gravity. The time when the ball hits the ground is twice the time it takes for the ball to reach the highest point. That time is given by t = u/g (since at the highest point, final velocity is 0). Thus, the total time is T = 2u/g, which gives us T ≈ 9.39 seconds.
As for where they hit, the ball dropped from the building hits the ground, and the ball thrown upwards from the ground hits the ground again after it reaches the maximum height and falls back.
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Martin mixed sulfur (a yellow solid) with iron filings (a black solid) in a ceramic dish called a crucible. Then he separated them using a magnet. What kind of a change is this?
A.
change in state
B.
mixing and separation
C.
replacement
D.
synthesis
Answers
Answer:
a. change in state
Explanation:
Separation of iron filings from its mixture with sulphur is an example of mixing and separation.
Answer: B. mixing and separation
Explanation:
Separation techniques exploit various physical and chemical properties of substances. When a mixture undergoes separation it may result in two or more mixtures or even pure substances. Here separation of iron filings is achieved by making use of the magnetic property of iron.
Very few substances occur in pure form in nature. In order to obtain pure substances various separation techniques have to be employed. Examples of separation techniques are chromatographic separation, centrifugation, electrophoresis etc...
Twenty is the _________________ of potassium.
A) charge
B) atomic mass
C) atomic number
D) number of neutrons
Answers
Answer:
I think it's D) Guess why? I searched it up!
An engineer in a locomotive sees a car stuck on the track at a railroad crossing in front of the train. When the engineer first sees the car, the locomotive is 330 m from the crossing and its speed is 25 m/s. If the engineer’s reaction time is 0.29 s, what should be the magnitude of the minimum deceleration to avoid an accident? Answer in units of m/s 2
Answers
Answer:
Explanation:
First, since the engineer is a slowpoke and he reacts a third of a second too late, the train will have 330 - 0.29*25 = 322,75 meters to stop. now, be [tex]x[/tex] (with [tex]x>0[/tex]) the deceleration value for which the train bumps at the car and stops, you have two conditions:
[tex]\left \{ {{25t-\frac12xt^2 = 322.75} \atop {0=25-xt}} \right.[/tex]
First states how much space the train has to stop, and the second tetermines how fast it slows down.
Solving the second for t, substituting in the first, and solving for x gives you a value of approximately [tex]1.94 m/s^2[/tex].
As usual, double check the calculations for yourself, it's always a good practice
Which state of matter has a definite volume but a variable shape?
Answers
Liquid. Liquids have a definite volume but take up the shape of whatever they are in.
Happy to help!
Okay so I have a few questions:
1. An individual has a weight of 735 Newton’s. What is the individual’s mass? Show the appropriate equation and show your work
2. A temperature of a 50kg block increases by 15 degrees Celsius when 337,500 J of thermal energy are added to the block. What is the specific heat of the object? Show your work
(What is the block made of?) (is this block a good material for insulators or conductors)
3. Describe how the velocity and acceleration of a skydiver changes as she falls from the plane back to the ground.
Answers
1.
Answer:
m = 74.9 kg
Explanation:
As we know that weight of the object is force due to gravity
Now we know that
[tex]F_g = mg[/tex]
[tex]m = \frac{F_g}{g}[/tex]
[tex]m = \frac{735}{9.81}[/tex]
[tex]m = 74.9 kg[/tex]
2.
Answer:
[tex]s = 450 J/kg ^oC[/tex]
Explanation:
Heat added to the system is given as
[tex]Q = ms\Delta T[/tex]
so we will have
[tex]337500 = 50 s (15)[/tex]
[tex]s = 450 J/kg ^oC[/tex]
3.
Answer:
Velocity will increase while acceleration will remain constant
Explanation:
When skydiver falls from rest then velocity will increase with time while the acceleration due to gravity will remains constant.
So here we can say that
[tex]a = 9.81 m/s^2[/tex]
while velocity will increase while it falls from certain height
9.7/3.33 round answer to the correct number of significant digits
Answers
Answer:
2.9
Explanation:
9.7 / 3.33 = 2.912912912...
We need to round to the correct number of significant figures. 9.7 has two significant figures, and 3.33 has three significant figures. We need to round to the least number of significant figures available, so we round to two.
2.91 ≈ 2.9
The atmosphere is held together by
A. the greenhouse effect
B. solar radiation
C. ozone
D. gravity
Answers
Answer:
D. gravity
Explanation:
Gravity keeps the atmosphere from escaping into space.
convert the following degree celsius tempture to degree fahrenheit a.40c b.30c
Answers
Answer:
a. 104°F
b. 86°F
Explanation:
To convert Celsius to Fahrenheit, use the equation:
F = 1.8C + 32
where F is the temperature in Fahrenheit and C is the temperature in Celsius.
a. F = 1.8(40) + 32
F = 104
b. F = 1.8(30) + 32
F = 86
(A) [tex]40^{\circ}C[/tex] equals [tex]104^{\circ}F[/tex]and (B)[tex]30^{\circ}C[/tex] equals [tex]86^{\circ}F[/tex].
To convert temperatures from degrees Celsius to degrees Fahrenheit, we can use the following formula:
[tex]F = \left( C \times \frac{9}{5} \right) + 32[/tex]
Let's use this equation to get the specified temperatures:
For [tex]40^{\circ}C[/tex]:[tex]F = \left( 40 \times \frac{9}{5} \right) + 32 \\\\F = 72 + 32 \\\\F = 104^\circ\text{F}[/tex]
For [tex]30^{\circ}C[/tex]:[tex]F = \left( 30 \times \frac{9}{5} \right) + 32 \\\\F = 54 + 32 \\\\F = 86^\circ\text{F}[/tex]
Jack applies a force of 30 and move 90 kg box. What is the acceleration of the box?
Answers
Explanation:
Given , F = 30N and mass m = 90kg
°•° F = ma
=> a = F/m
=> a = 30/90
=> a = 1/3m/s^2
Final answer:
To find the acceleration of a 90 kg box with a force of 30 N applied, use Newton's second law of motion. The acceleration is calculated as 0.333 m/s².
Explanation:
To calculate the acceleration of a 90 kg box when a force of 30 N is applied, we can use Newton's second law of motion, which is F = ma, where F is the force applied, m is the mass of the object, and a is the acceleration of the object. Rearranging the equation for acceleration gives us a = F / m.
In this case, F = 30 N and m = 90 kg. Plugging these values into the equation yields a = 30 N / 90 kg = 0.333 m/s². Therefore, the acceleration of the box is 0.333 meters per second squared (0.333 m/s²).
d A marathon runner runs at a average speed of 5.33 meters per second for the first
73600 seconds and then at a speed of 5.00 meters per second for the next 4200
seconds. What is the average speed of the marathon runner in meters per second?
F
5.1 m/s
G
2.6 m/s
H
0.4 m/s
J 1.06 m/s
Answers
Answer:
The average speed of the marathon runner is 5.15 meters per second
Explanation:
Lets revise the meaning of average speed
The average speed of an object is the total distance traveled by
the object divided by the time taken to cover that distance
A marathon runner runs at a average speed of 5.33 meters per second
for the first 3600 seconds
⇒ His speed = 5.33 m/s
⇒ For time = 3600 seconds
Then he runs at a speed of 5.00 meters per second for the next
4200 seconds
⇒ His speed is 5 m/s
⇒ For time 4200 seconds
Average speed = total distance ÷ total time
Lets find the total distance
Distance = speed × time
⇒ The 1st distance = 5.33 × 3600 = 19188 meters
⇒ The 2nd distance = 5 × 4200 = 21000 meters
⇒ Total distance = 19188 + 21000 = 40188 meters
Lets find the total time
⇒ Total time = 3600 + 4200 = 7800 seconds
⇒ Average speed = 40188 ÷ 7800 = 5.15 m/s
The average speed of the marathon runner is 5.15 meters per second
Since lower case m stands for both the prefix.milli and for unit for length meter, how do we tell which one is meant when they are used?
A: a prefix is never used alone. So a lone m (lower case) would refer to a unit, the meter (the SI metric unit of length.)
B: the prefix Comes before the unit, so mm (both lower case) would stand for millimeter.
C: the prefix comes before the unit, so mg (both lower case) would stand for milligram.
D: all of the other 3 answer choices.
Answers
Answer:
D: all of the other 3 answer choices
Explanation:
Milli- is a prefix, so a lowercase m in front of any other letter means milli-. For example, mm = millimeter and mg = milligram.
An m by itself means meters.
Answer:
D: all of the other 3 answer choices.
Explanation:
A: a prefix is never used alone. So a lone m (lower case) would refer to a unit, the meter (the SI metric unit of length.)
Above statement is true because here we can see that when prefix is placed before any SI unit then only we use it let say if we use only unit "m" then it is clearly assumed to be meter
B: the prefix Comes before the unit, so mm (both lower case) would stand for millimeter.
TRUE
Since prefix is always used before SI unit then we have to use the prefix like it is shown here for length. when we give unit as "mm" then it will show millimeter.
C: the prefix comes before the unit, so mg (both lower case) would stand for milligram.
TRUE
Since prefix is always used before SI unit then we have to use the prefix like it is shown here for mass. when we give unit as "mg" then it will show milligram.
calculate the weight of a 65 kg person on earth
Answers
Answer:
143.325 pounds (rounded to 8 digits, but you can round it to a lower amount of digits if you need to!)
Explanation:
So 1 kg = 2.205 lbs, so 65 kg = 2.205lbs * 65kg, which is equal to approximately 143.325 lbs.
( 1kg = 2.205lbs; 65 kg = ? lbs)
If Joey ran 60 meters in 10 seconds, then his velocity is ________ m/s.
Answers
Answer:
6 m/s
Explanation:
An exposure is made at 200 cm SID and has an intensity of 5 milliroentgens (mR), and a second exposure is made is at 100 cm SID. Calculate the intensity of the x-ray beam of the second exposure.
Answers
The intensity of X-ray beam of second exposure made at 100 cm SID is 20 mR.
Solution:
By using inverse square law formula, intensity of X-Ray beam made at different distances can be found.
[tex]\frac{I_{1}}{I_{2}}=\left(\frac{D_{2}}{D_{1}}\right)^{2}[/tex]
Where [tex]I_1[/tex] is the intensity of first exposure of X-ray-beam.
[tex]I_2[/tex] is the intensity of second exposure of X-ray beam.
[tex]D_1[/tex] is the distance at which first exposure is made.
[tex]D_2[/tex] is the distance at which second exposure is made.
[tex]\begin{array}{l}{\frac{I_{1}}{I_{2}}=\left(\frac{100}{200}\right)^{2}} \\\\ {\frac{5}{I_{2}}=\frac{1}{4}} \\\\ \bold{{I_{2}=20\ \mathrm{mR}}\end{array}}[/tex]
What are balanced forces?
Answers
Answer:
Balance forces are two forces acting in opposite directions on an object, and equal in size. Anytime there is a balanced force on an object, the object stays still or continues moving continues to move at the same speed and in the same direction.
Explanation:
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Answer:
Balance forces are two forces acting in opposite directions on an object, and equal in size.
If two vectors are not perpendicular to each other, how should you add them?
Answers
Answer:
First you have to determine the angle of the vectors. Based on this angle, you separate the horizontal and vertical components using the trigonometric functions sine and cosine. The horizontal component is solved independently from the vertical, and finally using the Pythagorean Theorem, you solve the combined answer of the vertical and horizontal components to reach your final answer.
Answer:
Resolve each vector into it's x and y components
The black mamba is one of the world’s most poisonous snakes, and with a maximum speed of 18.0 km/h, it is also the fastest. Suppose a mamba waiting in a hide-out sees prey and begins slithering toward it with a velocity of +18.0 km/h. After 2.50 s, the mamba realizes that its prey can move faster than it can. The snake then turns around and slowly returns to its hide-out in 12.0 s. Calculate the mamba's average velocity for the complete trip.
Answers
From hide-out toward prey:
Speed = 18 km/hr=5 m/s. ... Time = 2.5 sec. ... Distance= s*t = 12.5 meters
From turn-around back to hide-out:
Distance = 12.5 m. ... Time = 12.0 sec
Average speed = (total distance covered) / (time to cover the distanced)
total distance = (12.5 + 12.5) = 25 meters
total time = (2.5 + 12.0) = 14.5 sec
Average speed = (25 m) / (14.5 sec) = 1.72 m/s
Average velocity = displacement / time
The creature ended up where it started, so its displacement is zero.
Average velocity = ( 0 / 14.5 sec )
Average velocity = zero
The snake then turns around and slowly returns to its hide-out in 12.0 s, mamba's average velocity for the complete trip is approximately 1.72 m/s.
By taking into account both the mamba's initial speed towards the prey and its subsequent motion back to the hiding place, the average velocity of the entire journey can be computed.
First, let's convert the velocities to meters per second (m/s):
[tex]\[ \text{Initial velocity} = 18.0 \, \text{km/h} \\\\= \frac{18.0 \times 1000}{3600} \, \text{m/s}\\\\ \approx 5.0 \, \text{m/s} \][/tex]
The distance traveled towards the prey can be calculated using the formula [tex]\( \text{Distance} = \text{Velocity} \times \text{Time} \)[/tex]:
[tex]\[ \text{Distance towards prey} = 5.0 \, \text{m/s} \times 2.50 \, \text{s} \\\\= 12.5 \, \text{m} \][/tex]
The distance traveled back to the hide-out is the same as the distance towards the prey:
[tex]\[ \text{Distance back to hide-out} = 12.5 \, \text{m} \][/tex]
The total distance traveled for the complete trip is twice the distance towards the prey:
[tex]\[ \text{Total distance} = 2 \times 12.5 \, \text{m} \\\\= 25.0 \, \text{m} \][/tex]
The total time taken for the complete trip is the sum of the time towards the prey and the time back to the hide-out:
[tex]\[ \text{Total time} = 2.50 \, \text{s} + 12.0 \, \text{s} \\\\= 14.5 \, \text{s} \][/tex]
[tex]\[ \text{Average velocity} = \frac{25.0 \, \text{m}}{14.5 \, \text{s}}\\\\ \approx 1.72 \, \text{m/s} \][/tex]
Thus, the mamba's average velocity for the complete trip is approximately [tex]\(1.72 \, \text{m/s}\)[/tex].
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how long does it usually take a hypothesis to become a theory
Answers
Answer:
If enough evidence accumulates to support a hypothesis, it moves to the next step (known as a theory) in the scientific method and becomes accepted as a valid explanation of a phenomenon.
Answer:
Hypothesis is usually referred as an assumption or an observation made without much proof to support the statement. Hence scientists and experimental physicists uses hypothesis and perform experiments and observations to support the theory.
The hypothesis will get transformed into a theory only when there is enough evidence to support the cause and the science behind the set of events. It is dependent upon a number of scientific tests an hence it is not possible to define a time period. It may varies from years to forever (or never).
How do a neutron and a proton compare?
O A. The neutron has much less mass.
O
B. The neutron is farther from the nucleus.
O
C. They are equal in number in a neutral atom.
D. The proton has a positive charge, while the neutron has no charge.
Answers
Answer:
it would be d
Explanation:
because the neutron has a neutral charge so it has no charge at all
A neutron is electrically neutral and has a similar mass to a proton, which has a positive charge. While they both are part of the nucleus and contribute to an atom's mass, only the proton's charge affects the atom’s chemical properties. So the correct option is D.
Explanation:Comparing a neutron and a proton, option D is the correct answer: The proton has a positive charge, while the neutron has no charge. Both neutrons and protons reside in the nucleus of an atom and have approximately the same mass, which is about 1.67 × 10-24 grams, also known as one atomic mass unit (amu) or one Dalton. However, they differ significantly in terms of their electric charge. A proton has a positive charge (+1), essential in determining the atomic number and the chemical properties of an element. In contrast, a neutron is electrically neutral, carrying no charge at all, and contributes to the mass of an atom without affecting its electric charge. The number of protons and neutrons in the nucleus can vary; in a neutral atom, the number of electrons, which are negatively charged, is equal to the number of protons, balancing the net charge to zero.
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Compare and contrast the two main branches of physical science - please help meeeeeeeeee
Answers
Answer:
Physics
Chemistry
Explanation:
Physical science is science which studies non-living things.This covers things on earth to the universe.The main branches are physics and chemistry.The other sub-branches are Astronomy, meteorology and Geology.Physics is concerned with the basic principals of matter and energy.It covers concepts in motion, energy, force, pressure , light and many other areas we encounter in our day to day life.Chemistry is concerned with composition of matter and how it reacts.Material in chemistry is understood through observing molecules, atoms, elements and their interaction in nature including their properties.Chemistry is further divided into organic chemistry and natural chemistry sub-branches.
What is the molality of a solution that contains 54 grams of NaOH dissolved in 1.50 kg of water? (The molar mass of NaOH 40.00 grams/moles.)
Answers
Answer:
0.900 mol/kg
Explanation:
Molality is moles of solute per kilograms of solvent.
Converting 54 grams of NaOH to moles:
54 g NaOH × (1 mol NaOH / 40.00 g NaOH) = 1.35 mol NaOH
So the molality is:
m = (1.35 mol) / (1.50 kg)
m = 0.900 mol/kg
Convert grams of NaOH to moles:
The formula to convert grams to moles is:[tex]\text{moles of NaOH} = \frac{\text{mass of NaOH (g)}}{\text{molar mass of NaOH (g/mol)}}[/tex]
Given that the mass of NaOH is 54 grams and its molar mass is 40.00 g/mol:
[tex]\text{moles of NaOH} = \frac{54 \text{ g}}{40.00 \text{ g/mol}} = 1.35 \text{ moles}[/tex]
Determine the mass of the solvent (water):
The mass of water is given as 1.50 kg.
Convert this mass into kilograms (if necessary):
Since 1.50 kg is already in the correct unit, no conversion is needed here.
Calculate molality (m):
The formula for molality is:
[tex]\text{molality (m)} = \frac{\text{moles of solute}}{\text{mass of solvent (kg)}}[/tex]
Substitute the values into the formula:
[tex]\text{molality} = \frac{1.35 \text{ moles}}{1.50 \text{ kg}} = 0.90 \text{ m}[/tex]