Answer:the answer is energy is released from the nuclei of atoms
Explanation:
A 0.50-kg block attached to an ideal spring with a spring constant of 80 n/m oscillates on a horizontal frictionless surface. the total mechanical energy is 0.12 j. the greatest extension of the spring from its equilibrium length is:
The greatest extension of the spring from its equilibrium length is calculated through the formula for total energy in harmonic motion, given as 0.5 * k * x^2. When rearranged for displacement(x), and values substituted, the extension is found to be 0.155 meters or 15.5 cm.
Explanation:In this problem, we are dealing with a block attached to an ideal spring and on a frictionless surface. The total mechanical energy, E, is given as 0.12 joules. We can use this information to find the peak displacement or the greatest extension, x, of the spring (amplitude) from its equilibrium length, using the formula E = 0.5*k*x^2.
The total energy of the system is the potential energy at the position of the greatest extension or amplitude, which means the block is momentarily at rest and has zero kinetic energy. Therefore, E = 0.5 * k * x^2, where E is the total energy, k is the spring constant, and x is the displacement.
Here, rearranging the formula to solve for the extension (x) we get x = sqrt((2*E)/k).
Substitute E = 0.12 joules and k = 80 N/m, into the equation. Therefore the greatest extension of the spring from its equilibrium length is x = sqrt((2*0.12 J)/80 N/m) = 0.155 meters or 15.5 cm.
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The greatest extension of the spring from its equilibrium length, which correlates to the amplitude A, is calculated from the given mechanical energy and spring constant. This can be determined by solving the equation for total mechanical energy, ETotal = (1/2)kA² for A. The calculation gives a maximum extension of approximately 15.5 cm.
Explanation:The total mechanical energy of a block and spring system is equal to the potential energy stored in the spring at the maximum extension/compression because at these points all of the energy is potential and none is kinetic. The total mechanical energy is given by ETotal = (1/2)kA², where k is the spring constant and A is the amplitude, which is the maximum extension or compression of the spring from its equilibrium length.
In this circumstance, the total mechanical energy is 0.12 Joules, and the spring constant 'k' is 80 N/m. So we can solve the above equation for A, the maximum extension:
A = sqrt( (2 * ETotal) / k ) = sqrt( (2 * 0.12 J) / 80 N/m ) = 0.15494 meters,
which is about 15.5 cm (since 1 m = 100 cm).
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A howler monkey is the loudest land animal and under some circumstances, can be heard up to a distance of 5.0 km. Assume the acoustic output of a howler to be uniform in all directions and that the threshold of hearing is 1.0*10^-12 W/m^2. The acoustic power emitted by the howler is closest to
a) 3.2 mW b) 0.11 mW c) 11 mW d) 1.1 mW e) .31 mW
A silver wire has a cross sectional area a = 2.0 mm2. a total of 9.4 × 1018 electrons pass through the wire in 3.0 s. the conduction electron density in silver is 5.8 × 1028 electrons/m3 and e = 1.60 × 10-19
c. what is the drift velocity of these electrons?
The drift velocity of electrons in a silver wire given an electron density of 5.8 x 10^28 electrons/m3, a cross-sectional area of 2.0 mm2, and a total of 9.4 x 10^18 electrons passing through in 3.0 s, is approximately 1.08 x 10^-4 m/s.
Explanation:The drift velocity of electrons is a term used in physics to describe the average velocity that free charges such as electrons traverse in a material due to an externally applied electric field. Given the cross-sectional area (A), the number of electrons (Q), the time (t), the charge of an electron (e), and the electron density (n), you can determine the drift velocity (v) using the formula:
v = Q / (n * A * t)
Firstly, convert the cross-sectional area to m² since the electron density is given in 1/m³. So, the area would be 2.0 mm² = 2.0 x 10^-6 m².
To determine the number of electrons passing through during the given time period (3.0 s), we substitute what we know into the formula giving:
v = (9.4 x 10^18) / (5.8 x 10^28 x 2.0 x 10^-6 x 3.0)
This yields a drift velocity of 1.08 x 10^-4 m/s.
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According to the Doppler affect what happens when a light surfaceMoves further away from an observer
Place the notebook on a table, and push it a few inches with your finger. When it moves, it has kinetic energy. Which kind of force opposed the motion of the notebook?
Answer:
The force of friction opposed the motion of the notebook.
Explanation:
Plato answer
The fundamental frequency of a pipe that is open at both ends is 564 hz . part a how long is this pipe?
The length of the pipe, if The fundamental frequency of a pipe that is open at both ends is 564 Hz, is 82 cm.
What is the frequency?Frequency is defined as the no of waves that are passing from the point in respect to a given time. Frequency can be measured in Hertz. Humans, whose capacity to hear is normal, can hear between the frequency of 20 Hertz to 20000 Hertz.
Given:
The frequency, f = 564 Hz,
Calculate the length by the formula given below,
[tex]l= k / 2[/tex]
2l = k
Calculate the length of the pipe by the formula given below,
[tex]f = v k[/tex]
f = v (2l) [Substitute the value of k]
l = f / 2v
l = 564 / (2 × 344)
l= 564 / 688
l = 0.82 m or 82 cm
Therefore, the length of the pipe, if The fundamental frequency of a pipe that is open at both ends is 564 Hz, is 82 cm.
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Physics 1315, what is faster speed; red light or gamma rays?
In the circuit diagram, what does the line segment with two circles at the ends represent?
an electrical conductor
a source of electrical energy
an electrical resistor
a closed switch
That is a symbol for a closed switch meaning that current flows through the wire. If the line between the two circles wasn't connected to one of the circles, then it would be an open circuit in which current doesn't flow through the wire.
Answer: closed switch
Explanation:
Closed switch is when current is allowed to flow freely without hindrance.
Name each type of symbiosis and explain how the two species are affected
To what potential should you charge a 3.0 μf capacitor to store 1.0 j of energy?
To store 1.0 J of energy in a 3.0 μF capacitor, you should charge it to approximately 816.5 V.
To determine the potential (V) needed to charge a 3.0 μF capacitor to store 1.0 J of energy, we can use the formula for the energy stored in a capacitor:
Energy (E) = 0.5 × C × V²
Where:
E is the energy stored (1.0 J in this case)C is the capacitance (3.0 μF or 3.0 × 10⁻⁶F)V is the potential difference we need to findRearranging the formula to solve for V:
V² = (2E)/C
Substituting the given values:
V² = (2 × 1.0 J) / (3.0 × 10⁻⁶ F)
V² = 2.0 J / 3.0 × 10⁻⁶ F
V² = 666666.67 V²
Taking the square root of both sides:
V ≈ 816.5 V
Therefore, you should charge the 3.0 μF capacitor to approximately 816.5 V to store 1.0 J of energy.
Find the ratio of the new/old periods of a pendulum if the pendulum were transported from earth to the moon, where the acceleration due to gravity is 1.63 m/s2 .
The period of a pendulum on the Moon is roughly 2.45 times longer than the period of a similar pendulum on Earth. This is due to the difference in gravitational forces on the two celestial bodies.
Explanation:A pendulum's period is influenced by the acceleration due to gravity. On Earth, this is approximately 9.80 m/s². On the Moon, the gravitational pull is significantly weaker, approximating at about 1.63 m/s². Therefore, if a pendulum were taken from Earth to the Moon, its period would change due to the variance in gravitational forces.
The ratio of the new period (Tmoon) to the old period (Tearth) is determined by the square root of the ratio of the gravities: Tmoon/Tearth = sqrt(g earth / g moon)
Substituting values, we get Tmoon/Tearth = sqrt(9.80 / 1.63) = 2.45 (rounded).
So, the period of a pendulum on the Moon is about 2.45 times longer than that of the same pendulum on Earth.
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What form does the signal take while it is broadcast from a transmitting station to your radio or television, regardless of whether it is a digital or analog wave?
The answer is transverse waves.
An electron in the n = 5 level of an h atom emits a photon of wavelength 1282.17 nm. to what energy level does the electron move?
The electron moves to energy level n = 3
[tex]\texttt{ }[/tex]
Further explanationThe term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is :
[tex]\large {\boxed {E = h \times f}}[/tex]
E = Energi of A Photon ( Joule )
h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )
f = Frequency of Eletromagnetic Wave ( Hz )
[tex]\texttt{ }[/tex]
The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.
[tex]\large {\boxed {E = \frac{1}{2}mv^2 + \Phi}}[/tex]
[tex]\large {\boxed {E = qV + \Phi}}[/tex]
E = Energi of A Photon ( Joule )
m = Mass of an Electron ( kg )
v = Electron Release Speed ( m/s )
Ф = Work Function of Metal ( Joule )
q = Charge of an Electron ( Coulomb )
V = Stopping Potential ( Volt )
Let us now tackle the problem !
[tex]\texttt{ }[/tex]
Given:
initial shell = n₁ = 5
wavelength = λ = 1282.17 nm = 1.28217 × 10⁻⁶ m
Unknown:
final shell = n₂ = ?
Solution:
We will use this following formula to solve this problem:
[tex]\Delta E = R (\frac{1}{(n_2)^2} - \frac{1}{(n_1)^2})[/tex]
[tex]h \frac{c}{\lambda} = R (\frac{1}{(n_2)^2} - \frac{1}{(n_1)^2})[/tex]
[tex]6.63 \times 10^{-34} \times \frac{3 \times 10^8}{1.28217 \times 10^{-6}} = 2.18 \times 10^{-18} \times ( \frac{1}{(n_2)^2} - \frac{1}{5^2})[/tex]
[tex]1.55128 \times 10^{-19} = 2.18 \times 10^{-18} \times ( \frac{1}{(n_2)^2} - \frac{1}{5^2})[/tex]
[tex]( \frac{1}{(n_2)^2} - \frac{1}{5^2}) = \frac{16}{225}[/tex]
[tex]\frac{1}{(n_2)^2} = \frac{1}{25} + \frac{16}{225}[/tex]
[tex]\frac{1}{(n_2)^2} = \frac{1}{9}[/tex]
[tex](n_2)^2 = 9[/tex]
[tex]n_2 = \sqrt{9}[/tex]
[tex]\boxed{n_2 = 3}[/tex]
[tex]\texttt{ }[/tex]
Learn morePhotoelectric Effect : https://brainly.com/question/1408276Statements about the Photoelectric Effect : https://brainly.com/question/9260704Rutherford model and Photoelecric Effect : https://brainly.com/question/1458544[tex]\texttt{ }[/tex]
Answer detailsGrade: College
Subject: Physics
Chapter: Quantum Physics
We can use the Rydberg formula to find out to which energy level an electron will move after emitting a certain wavelength of photon. Inserting the given values of photon wavelength and initial energy level will provide us the final energy level to which the electron moves. In this case, it moves to energy level n = 2.
Explanation:The subject of this question involves examining the transition of an electron in a hydrogen atom after emitting a photon. Given we know the wavelength of the emitted photon, we can determine the initial and final energy levels, then calculate the transition the electron undergoes. We can use the Rydberg formula, R = 1.097373 x 107 m-1, which relates the wavelength of light emitted to the energy levels in an atom.
We find:
1/λ = R x (1/nf2 - 1/ni2)
Where:
λ = wavelength of lightR = Rydberg constantnf = final energy levelni = initial energy level
By inserting the given data, we see:
1/1282.17 x 10-9 m = R x (1/nf2 - 1/52)
Solving this equation gives nf = 2. Therefore, the electron moves to the energy level n = 2 after emitting the photon.
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Which of these is a cultural service—a non material benefit people get from the environment
Answer: providing national parks
Explanation:
What keeps an inflated balloon from falling down if you rub it against your hair and place it against a wall? 1. rubbing distorts the atoms inside the ballon and polarizes it. 2. rubbing leaves a balloon electrically charged; the charged balloon polarizes the wall. 3. when you rub the balloon against your hair, it will remove some m?
The answer is: rubbing leaves a balloon electrically charged; the charge polarizes the wall
there is no friction here
A balloon sticks to a wall after being rubbed on your hair because the friction causes electrons to move from your hair to the balloon, giving it a negative charge that attracts to the slightly positively charged surface.
When you rub a balloon against your hair, the balloon becomes electrically charged due to the transfer of electrons. This process is known as the triboelectric effect, where friction causes electrons to be transferred from your hair to the balloon. As a result, the balloon holds a negative charge while your hair holds a positive charge.
Due to this, the charged balloon can polarize the wall's molecules, causing the opposite charges to attract, which keeps the balloon stuck to the wall temporarily.
A magnetic field of 0.55 g is directed straight down, perpendicular to the plane of a circular coil of wire that is made up of 550 turns and has a radius of 20 cm. 1) if the coil is stretched, in a time of 35 ms, to a radius of 50 cm, calculate the emf induced in the coil during the process.
Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. You have determined that the football would travel 15.1 m before landing. How would this value change if the football was kicked at an angle of 35.0°?Complete all equations without rounding and then round to the nearest tenth at the end.
Answer:
If the football is kicked at a 35.0º angle, it will travel 18.5 m before landing. This is farther than if it were kicked at a 25° angle.
Explanation:
what it says on edge
Which of these is most likely to produce wastewater containing benzene and other hydrocarbons
An Oil Refinery (APEX)
What are (a) the lowest frequency, (b) the second lowest frequency, and (c) the third lowest frequency for standing waves on a wire that is 10.9 m long, has a mass of 55.8 g, and is stretched under a tension of 253 n?
A particle is attached to a spring and is pushed so that the spring is compressed more and more. As a result, the spring exerts a greater and greater force on the particle. Similarly, a charged particle experiences a greater and greater force when pushed closer and closer to another particle that is fixed in position and has a charge of the same polarity. In spite of the similarity, the charged particle will not exhibit simple harmonic motion on being released, as will the particle on the spring. Explain why not.
What is the freezing point of radiator fluid that is 50% antifreeze by mass? k f for water is 1.86 ∘ c/m?
Answer:
-30.02 ºC
Explanation:
Assuming the antifreeze to be ethylene glycol (C₂H₆O₂) which is popular antifreeze.
Molar mass of ethylene glycol (C₂H₆O₂) = 62g/mol
Step 1: calculate the freezing point depression of the solution
ΔT = -Kf*M
where,
ΔT= depression in the freezing point.
M = the molarity of the solution (mol solute / Kg solvent)
Kf = molar freezing point constant of water = 1.86°C/m
To determine depression in the freezing point (ΔT), first we need to calculate;
molarity of solute (ethylene glycol) in mol mass of solvent (water) in kgmolarity of the solution (water +ethylene glycol)Step 2: calculate the molarity of the solute (ethylene glycol)
Molar mass ethylene glycol = 62 g/mol
molarity of ethylene glycol in mol = 50 g / 62g/mol = 0.807 mol
Step 3: calculate mass of solvent in kg
There is 1kg of ethylene glycol which is present in 1kg of water
mass of solvent (water) in kg= 50 g/ 1000 g/ Kg = 0.050 Kg
Step 4: calculate the molarity of the solution (M)
M = 0.807 mol / 0.050 Kg = 16.14 m
Step 5: calculate the freezing point depression of the solution (ΔT)
ΔT = - Kf*M = -1.86 ºC/m x 16.14 m
= -30.02 ºC
A neutral copper ball is suspended by a string. a positively charged insulating rod is placed near the ball, which is observed to be attracted to the rod. why is this? 1. the ball becomes positively charged by induction. 2. the string is not a perfect conductor. 3. there is a rearrangement of the electrons in the ball. 4. the ball becomes negatively charged by induction. 5. the number of electrons i
The copper ball is attracted to the rod because the electrons in the ball rearrange themselves, making one side of the ball negative and the other positive. This process is known as electrostatic induction. Thus, option 3 is correct.
A neutral copper ball is observed to be attracted to a positively charged insulating rod due to electrostatic induction. Here's a step-by-step explanation:
Rearrangement of Electrons: When the positively charged rod is brought close to the neutral copper ball, the electrons in the copper ball are attracted towards the rod because opposite charges attract each other.Induced Polarization: This movement causes the side of the ball closer to the rod to become slightly negative due to the accumulation of electrons, while the side farther from the rod becomes slightly positive due to the lack of electrons.Attraction: The negatively charged side of the copper ball is attracted to the positively charged rod, causing the ball to move towards the rod.Therefore, the correct reason for the observed attraction is the rearrangement of the electrons in the ball, making option 3 the correct answer.
What method of forecasting uses the effects of past weather conditions as part of its forecasting method
the method is analog forecasting method
analog forecasting method uses the past weather data and compares it with the existing one to forecast. it is a complex method since it involves remembering previous data for whether that can be triggered by a specific event.
For an isolated system, the law of conservation of momentum is valid: A. for inelastic collisions. B. for elastic collisions. C. only when there are no collisions. D. for all types of collisions.
The law of conservation of momentum is valid in isolated systems for all types of collisions, both elastic and inelastic.
The law of conservation of momentum is valid for an isolated system, meaning that no net external force is acting on the system. This principle applies to both types of collisions: elastic collisions and inelastic collisions. In elastic collisions, not only is momentum conserved, but kinetic energy is also conserved. In inelastic collisions, however, while kinetic energy is not conserved, the conservation of momentum still holds true. Therefore, for an isolated system, the law of conservation of momentum is valid for all types of collisions, regardless of whether they are elastic or inelastic.
A feather of mass 0.001 kg falls from a height of 2 m under realistic conditions it experiences air resistance based on what you know about friction what can you say about the kinetic energy of the feather as it reaches the ground
Answer:
KE < 0.0196 J
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What is gravity? Gravity is the force (2 points) Select one: a. of attraction between two objects; it is not related to the object's mass. b. of attraction between two objects; it is related to the object's mass. c. that acts on objects when they are pushed d. that repels objects that have like charges
Recall that the differential equation for the instantaneous charge q(t) on the capacitor in an lrc-series circuit is l d 2q dt 2 + r dq dt + 1 c q = e(t). see this excerpt about lrc-series circuits. use the laplace transform to find q(t) when l = 1 h, r = 20 ω, c = 0.005 f, e(t) = 160 v, t > 0, q(0) = 0, and i(0) = 0. q(t) =
The Laplace transform can be used to solve the differential equation for the charge on the capacitor in an LRC-series circuit.
Explanation:The Laplace transform can be used to solve the differential equation for the charge on the capacitor in an LRC-series circuit.
The Laplace transform transforms the differential equation into an algebraic equation, which can be solved to find q(t). First, we substitute the given values of L, R, C, and e(t) into the differential equation.
Then, we take the Laplace transform of both sides of the equation. Finally, we solve for Q(s) and take the inverse Laplace transform to find q(t).
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Ryan is experimenting with core materials for an electromagnet. he slides different for materials to a quail of current caring wire. sort the court materials based on whether they will or will not increase the strength of Ryan's electromagnet.
True or false: the coefficient of thermal expansion governs the way a substance expands or contracts when it is heated or cooled
Please help 10 points