In a reaction, a gas being produced is

Visible light waves have specific properties, including wavelength, that allow them to be detected by the human eye and reach Earth's surface effectively.

Visible light consists of electromagnetic waves that behave like other waves. One important property of light waves is the wavelength, which is the distance between one peak of a wave and the next peak. In the case of visible light, the wavelengths range from about 400 to 700 nanometers (nm). This range of wavelengths is found within the visible light spectrum because these are the waves that human vision can perceive. Human eyes have evolved to see these waves most effectively, and visible light also readily reaches Earth's surface, penetrating the atmosphere effectively.

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The substance that cannot be broken down by chemical change is [tex]\boxed{{\text{C) gold}}}[/tex].

Further Explanation:

Substance is the pure form of matter while a combination of atoms or molecules is termed as a mixture.

Types of substances:

1. Element

The simplest form of substance that cannot be further decomposed by any chemical means is called an element. Carbon, sulfur, and cobalt are some of the examples of elements.

2. Compound

When two or more different elements are held together by chemical methods, compounds are formed. These can further be decomposed into their corresponding constituents. The properties of compounds are very different from those of their constituent elements. NaCl, [tex]{\text{C}}{{\text{H}}_{\text{4}}}[/tex] and [tex]{{\text{H}}_{\text{2}}}{\text{O}}[/tex] are examples of compounds.

A) Butanal [tex]\left( {{{\text{C}}_4}{{\text{H}}_8}{\text{O}}} \right)[/tex] is made up of four carbon atoms, eight hydrogen atoms, and an oxygen atom so it is a compound. Therefore it can be broken down by chemical change.

B) Propene [tex]\left( {{{\text{C}}_{\text{3}}}{{\text{H}}_{\text{6}}}} \right)[/tex] is made up of three carbon atoms and six hydrogen atoms so it is a compound. Therefore it can be broken down by chemical change.

C) Gold [tex]\left( {{\text{Au}}} \right)[/tex] is an element so it is present in its simplest form. Therefore it cannot be broken down by chemical change.

D) Water [tex]\left( {{{\text{H}}_{\text{2}}}{\text{O}}} \right)[/tex] is made up of one oxygen and two hydrogen atoms so it is a compound. Therefore it can be broken down by chemical change.

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Answer details:

Grade: High School

Subject: Chemistry

Chapter: Elements, compounds, and mixtures

Keywords: substance, butanal, propene, gold, water, element, compound, chemical change, decomposed, simplest form, NaCl, CH4, carbon, sulfur, cobalt.

Gold, being an element, cannot be broken down further by a chemical change whereas butanal, propene, and water, being compounds, can be.

The substance which cannot be broken down by a chemical change is gold. This is because gold is an element. Elements are pure substances that are made from a single type of atom and cannot be broken down further by chemical methods. On the other hand, butanal, propene, and water are all compounds, which are substances formed when two or more chemical elements are chemically bonded together. Compounds can be decomposed into simpler substances, or their constituent elements, by chemical change.

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we have been given the [OH⁻] therefore we can first find the pOH value

pOH scale is used to determine the basicity of a solution

pOH = - log [OH⁻]

pOH = - log (1 x 10⁻¹¹ M)

pOH = 11

after knowing the pOH we can calculate pH using following equation

pH + pOH = 14

since pOH = 11

pH = 14 - 11

pH = 3

pH scale is used to determine how acidic a solution is

once pH is known we can can calculate Hydrogen ion concentration

pH = - log [H⁺]

[H⁺] = antilog (-pH)

[H⁺] = antilog(-3)

[H⁺] = 1 x 10⁻³ M

if pH is less than 7 - solution is acidic

pH = 7 the solution is neutral

pH more than 7 - solution is basic

pH of solution is 3 which is less than 7

therefore solution is acidic

and hydrogen ion concentration is 1 x 10⁻³ M

Protons and neutrons are held together rather closely in the center of the atom. Together they make up the nucleus, which accounts for nearly all of the mass of the atom.

Electrons move rapidly around the nucleus and constitute almost the entire volume of the atom. Although quantum mechanics are necessary to explain the motion of an electron about the nucleus, we can say that the distribution of electrons about an atom is such that the atom has a spherical shape.

Ans: D) 7930 g

Given:

Moles of H2SO4 = 60.0 mol

NH3 in excess

To determine:

The amount in grams of (NH4)2SO4 produced

Explanation:

The chemical reaction is as follows:

2NH3 + H2SO4 → (NH4)2SO4

Since, NH3 is in excess, H2SO4 will be the limiting reagent and will influence the amount of product formed

Based on the reaction stoichiometry:

1 mole of H2SO4 forms 1 mole of (NH4)2SO4

Therefore, 60.0 mol of H2SO4 will produce 60.0 mol of (NH4)2SO4

Now:

[tex]moles = \frac{mass}{molar mass} \\[/tex]

molar mass (NH4)2SO4 = 132.14 g/mol

[tex]mass of (NH4)2SO4 = moles * molar mass\\\\= 60.0 mol * 132.14 g/mol = 7928.4 g[/tex]

The given chemical reaction is:

Mg + Cl₂ → Mg²⁺ + 2Cl⁻

The reaction can be broken down into two half-reactions as follows:

Mg → Mg²⁺ + 2e⁻  ------(1)

Cl₂ + 2e⁻ → 2Cl⁻   ------(2)

Reaction (1) is an oxidation reaction as it involves loss of electrons.

Reaction (2) is reduction reaction as it involves gain of electrons.

The oxidation state of Mg changes from 0 (Mg) to +2 (Mg2+). Hence, Mg is the oxidized substance

Answer:

Mg

Explanation:

Edge

Final answer:

Evaporation happens when surface liquid molecules gain enough kinetic energy to break free from intermolecular forces, turning into gas and creating vapor pressure.

Explanation:

Evaporation occurs when the molecules at the surface of a liquid gain enough kinetic energy to overcome the intermolecular forces of other molecules in the liquid phase. This physical process, known as vaporization or evaporation, involves molecules absorbing enough energy to enter the gas or vapor phase, creating what is called vapor pressure. The escape of molecules from the liquid phase to the gas phase is dependent on the molecules having a kinetic energy greater than a certain threshold. This energy helps them to overcome the attractive forces that hold them in the liquid. As temperature increases, the average kinetic energy of the molecules increases as well, leading to more molecules having the energy to vaporize.

On a practical level, we experience the effects of evaporative cooling in everyday life. For example, on a hot day, the water molecules in perspiration absorb body heat and evaporate from the surface of your skin, leaving behind a cooling sensation.

Answer:

F

Explanation:

edg

At equilibrium, the pH of the solution is 3.48; [H2A] = 0.0496 and [A2-] = 8.2 × 10^-9 M

H2A <----> H+ + HA- ;Ka1 = 2.2 × 10^-6

Ka1 = 2.2x10^-6 = [H+][HA-]/[H2A]

At equilibrium:

Substituting in the equation of Ka1

2.2 × 10^-6 = X^2/0.050 - X

X^2 = 1.1 × 10^-7

X = 3.31 × 10^-4

Since Ka1 <<< Ka2 and [H+] = X

[H+] = 3.31 × 10^-4

pH = - log 3.31 × 10^-4

pH = 3.48

[H2A] = 0.05 - 3.31 × 10^-4

[H2A] = 0.0496

HA- <------> H+ + A- Ka2 = 8.2 × 10^-9

Ka2 = 8.2 × 10^-9 = [H+][A2-]/[HA-]

HA- ------> H+ + A2-

3.31 × 10^-4 3.31 × 10^-4 0 Initial

-y +y +y Change

{3.31 ×10^-4 -y} {3.31 x10^-4+y} {+y} Equilibrium

Assuming y is very small:

Substituting in the equation of Ka2

8.2 × 10^-9 = (3.31x10^-4) × y /3.31 ×10^-4

y = 8.2 × 10^-9

Since [A2-] = y

[A2-] = 8.2 × 10^-9 M

Therefore, at equilibrium, the pH of the solution is 3.48; [H2A] = 0.0496 and [A2-] = 8.2 × 10^-9 M

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The balanced chemical reaction between [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex] and [tex]{\text{AgN}}{{\text{O}}_3}[/tex] is

[tex]\boxed{{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( {aq} \right) + 2{\text{AgN}}{{\text{O}}_3}\left( {aq} \right) \to 2{\text{NaN}}{{\text{O}}_3}\left( {aq} \right) + {\text{A}}{{\text{g}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( s\right)}[/tex]

Further Explanation:

The chemical reaction that contains an equal number of atoms of the different elements in the reactant as well as in the product side is known as a balanced chemical reaction. The chemical equation is required to be balanced to follow the Law of the conservation of mass.

The steps to balance a chemical reaction are as follows:

Step 1: Complete the reaction and write the unbalanced symbol equation.

In this reaction, [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex] reacts with [tex]{\text{AgN}}{{\text{O}}_3}[/tex] to form [tex]{\text{NaN}}{{\text{O}}_{\text{3}}}[/tex] and [tex]{\text{A}}{{\text{g}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex]. The unbalanced chemical equation is as follows:

[tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( {aq} \right) + {\text{AgN}}{{\text{O}}_3}\left( {aq} \right) \to {\text{NaN}}{{\text{O}}_3}\left( {aq} \right) + {\text{A}}{{\text{g}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left(s\right)[/tex]

Step 2: Then we write the number of atoms of all the different elements that are present in a chemical reaction in the reactant side and product side separately.

• On reactant side,

Number of sodium atoms is 2.

Number of carbon atoms is 1.

Number of oxygen atom is 6.

Number of silver atom is 1.

Number of nitrogen atom is 1.

• On product side,

Number of sodium atom is 1.

Number of carbon atoms is 1.

Number of oxygen atom is 6.

Number of silver atoms is 2.

Number of nitrogen atom is 1.

Step 3: Initially, we try to balance the number of other atoms of elements except for carbon, oxygen, and hydrogen by multiplying with some number on any side. But nitrogen atoms on both sides of the equation are already equal. To balance the number of sodium and silver atoms, multiply [tex]{\text{AgN}}{{\text{O}}_{\text{3}}}[/tex] and [tex]{\text{NaN}}{{\text{O}}_{\text{3}}}[/tex] by 2. So the equation is,

 [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( {aq} \right) + \boxed2{\text{AgN}}{{\text{O}}_3}\left( {aq} \right) \to \boxed2{\text{NaN}}{{\text{O}}_3}\left( {aq} \right) + {\text{A}}{{\text{g}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left(s\right)[/tex]

Step 4: After this, we balance the number of atoms of carbon and then hydrogen atom followed by oxygen atoms. But these are already balanced. Now the reaction is,

[tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( {aq} \right) + 2{\text{AgN}}{{\text{O}}_3}\left( {aq} \right) \to 2{\text{NaN}}{{\text{O}}_3}\left( {aq} \right) + {\text{A}}{{\text{g}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left(s\right)[/tex]  

Step 5: So the balanced chemical equation is given as follows:

 [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( {aq} \right) + 2{\text{AgN}}{{\text{O}}_3}\left( {aq} \right) \to 2{\text{NaN}}{{\text{O}}_3}\left( {aq} \right) + {\text{A}}{{\text{g}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left(s\right)[/tex]

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1. Balanced chemical equation: https://brainly.com/question/1405182

2. Identification of all of the phases of the reaction: https://brainly.com/question/8926688

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: balanced chemical reaction, reactant side, product side, AgNO3, NaNO3, Ag2CO3, Na2CO3, nitrogen atom, sodium atoms, oxygen atoms, carbon atoms, silver atoms.

The arrangement of particles in a gas differs from that in a solid in that they are farther apart, allowing gases to fill their containers' volume and shape.

How does the arrangement of the particles in a gas compare to that of a solid? The correct answer is that the particles in a gas are farther apart than the particles in a solid (Option C). This difference in particle arrangement is crucial for understanding the distinct physical properties of solids, liquids, and gases.

Solids and liquids are considered condensed phases because their particles are very close together, which leads to them having definite volumes. Conversely, the particles in a gas phase are much more spread out, allowing them to move freely at high speeds. This significant separation between particles in a gas means that a gas can expand to fill the shape and volume of its container, differentiating it notably from solids and liquids.

Answer:

The entropy change for combining the two temperatures of water is 2.9 J/K.  

Hope I helped!!! :)

To calculate the equilibrium constant (Kc) for a reaction, detailed information about the reaction and the concentrations of all species at equilibrium is essential, which is not fully provided in the question.

The question at hand requires calculating the value of the equilibrium constant (Kc) for a given chemical reaction. However, from the information provided, it looks like there might be a mix-up or missing data. For calculating Kc, information about the reaction itself and the concentrations of all reactants and products at equilibrium is essential. Without knowing the specific reaction or having the concentrations of other species besides O2, it's impossible to directly calculate Kc. In a typical calculation, if the reaction were known, and assuming O2 participates in the reaction, its concentration along with those of other species involved would be used in the formula for Kc, which usually follows the form: Kc = [Products]coefficients / [Reactants]coefficients. Precision in these values is crucial for determining the reaction's dynamic equilibrium accurately.

Final answer:

The energy required to heat a 5.63 g sample of solid gold from 21.0 °C to 32.0 °C is approximately 8.0239 J or 1.9174 cal, using the specific heat capacity of gold (0.129 J/g°C).

Explanation:

To calculate the energy required to heat the sample of solid gold, we can use the formula: q = mcΔT, where q is the heat energy in joules (J), m is the mass of the substance in grams (g), c is the specific heat capacity (J/g°C), and ΔT is the change in temperature in degrees Celsius (°C).

The mass m of solid gold is 5.63 g, and the specific heat capacity c of gold is given as 0.129 J/g°C. The change in temperature ΔT is (32.0 °C - 21.0 °C) = 11.0 °C.

Therefore, the energy required in joules is:
q = (5.63 g) × (0.129 J/g°C) × (11.0 °C) = 8.0239 J.

To convert joules to calories, we use the conversion factor: 1 cal = 4.184 J. Therefore,
q in calories is: q = 8.0239 J × (1 cal / 4.184 J) = 1.9174 cal.

The energy required to heat the sample of gold from 21.0 °C to 32.0 °C is approximately 8.0239 J or 1.9174 cal.

Answer:

The gravitational pull of the moon on the water near the coast (option A) can explain the daily change in sea level observed along a coast.

Explanation:

The tides are rising and falling from sea level that occur several times a day. These periodic changes in the level of the sea are produced by the gravitational forces of attraction of the Sun and the Moon with respect to the Earth. But the force of attraction of the Moon is greater than that of the Sun, due to the proximity of the satellite.

High tide or high tide is the time when the sea reaches its maximum height. Low tide or low tide is the time when the sea reaches its minimum height.

The tide is noticed on the beaches because the coastline can go forward or backward many meters.

Finally, the gravitational pull of the moon on the water near the coast (option A) can explain the daily change in sea level observed along a coast.

Answer:

nitrite ion is NO2- and nitrate ion is NO3-

Explanation:

The nitrite ion has two oxygen atoms and one nitrogen atom while nitrate ion has three oxygen atoms and one nitrogen atom. They are both univalent negative anions that form compounds with metallic cations as shown below;

Na+ + NO3- ⇒ NaNO3 (sodium nitrate)

Na+ + NO2- ⇒ NaNO2 (sodium nitrite)

Ca2+ + NO3- ⇒ Ca(NO3)2 (calcium nitrate)

Ca2+ + NO2- ⇒ Ca(NO2)2 (calcium nitrite)

You can deduce from the above ionic equations that nitrate ion is NO3- while nitrite ion is NO2-.

To make it easier, assume that we have a total of 100 g of aegirine. Hence, we have 10g of Na, 24.2g of Fe, 24.3g of Si and 41.5g of O. Know we will convert each of these masses to moles by using the atomic masses of Na, Fe, Si, and O:

[tex] \frac{10g Na}{23g/mole} = 0.43 mole Na[/tex]

[tex]( \frac{24.2g Fe}{55.9g/mole} ) = 0.43 mole Fe[/tex]

[tex] ( \frac{24.3g Si}{28.1g/mole} ) = 0.86 mole Si[/tex]

[tex] ( \frac{41.5g O}{16g/mole} ) = 2.59 mole O[/tex]

Now, we will divide all the mole numbers by the smallest among them and get the number of atoms in the mineral:

Na = 0.43/0.43 = 1

Fe = 0.43/0.43 = 1

Si = 0.86/0.43 = 2

O = 2.59/0.43 = 6

So, the empirical formula of the compound NaFeSi2O6