In preparing a certain ointment, a pharmacist used 28.35 g of zinc oxide instead of the 31.1 g called for. Calculate the percentage of error on the basis of the desired quantity.

Answer:

24.39mL of the solution would be given per hour.

Step-by-step explanation:

This problem can be solved by direct rule of three, in which there are a direct relationship between the measures, which means that the rule of three is a cross multiplication.

The first step to solve this problem is to see how many mg of the solution is administered per hour.

Each minute, 200 ug are administered. 1mg has 1000ug, so

1mg - 1000 ug

xmg - 200 ug

[tex]1000x = 200[/tex]

[tex]x = \frac{200}{1000}[/tex]

[tex]x = 0.2mg[/tex]

In each minute, 0.2 mg are administered. Each hour has 60 minutes. How many mg are administered in 60 minutes?

1 minute - 0.2 mg

60 minutes - x mg

[tex]x = 60*0.2[/tex]

[tex]x = 12mg[/tex]

In an hour, 12 mg of the drug is administered. In 250 mL, there is 123 mg of the drug. How many ml are there in 12 mg of the drug.

123mg - 250mL

12 mg - xmL

[tex]123x = 250*12[/tex]

[tex]x = \frac{250*12}{123}[/tex]

[tex]x = 24.39[/tex]mL

24.39mL of the solution would be given per hour.

Final answer:

Approximately 24.39 milliliters of the intravenous solution would be administered per hour to deliver an hourly drug rate of 12 milligrams based on the given concentration.

Explanation:

To calculate how many milliliters of the intravenous solution would be given per hour, first convert the rate of drug administered from micrograms to milligrams: 200 \5g is equal to 0.2 mg. Since the drug administration rate is 0.2 mg per minute, we need to multiply this by 60 minutes to get the hourly rate:

0.2 mg/minute x 60 minutes/hour = 12 mg/hour.

Next, we need to find out how many milliliters of the solution contain 12 mg of the drug. Since we have 123 mg in 250 mL, we can set up a proportion to solve for the volume needed:

(123 mg/250 mL) = (12 mg/V mL)

V = (12 mg x 250 mL) / 123 mg = 24.39 mL.

Therefore, approximately 24.39 mL of the solution would be administered per hour.

Let [tex]m,n[/tex] be any two integers, and assume [tex]m-n[/tex] is even. (This would mean either both [tex]m,n[/tex] are even or odd, but that's not important.)

We have

[tex]m^3-n^3=(m-n)(m^2+mn+n^2)[/tex]

and the parity of [tex]m-n[/tex] tells us [tex]m^3-n^3[/tex] must also be even. QED

Answer: The data are quantitative because they consist of counts or measurements.

Step-by-step explanation:

The definition of quantitative data says that if we can count or measure some thing in our data such as number of apples on each bag , length, width, etc then the data is said to be quantitative.

On the other hand  in qualitative data we can obverse characteristics and features but can't be counted or measured such as honesty , color, tastes etc.

Given : In studying different societies, an archaeologist measures head circumferences of skulls.

Since here we are measuring circumferences of skulls, therefor it comes under  quantitative data.

Hence, the correct answer is : The data are quantitative because they consist of counts or measurements.

The correct answer is D. The data are quantitative because they consist of counts or measurements. Quantitative data is numerical and can be measured and analyzed statistically.

Step by Step Solution:

When an archaeologist measures head circumferences of skulls, they are collecting quantitative data. Quantitative data consists of counts or measurements that are numerical in nature and can be subjected to statistical analysis. Examples of quantitative data in archaeology include measuring the length of projectile points, counting pollen grains, or recording quantities of animal bones at a site.

Therefore, the correct answer is:

D. The data are quantitative because they consist of counts or measurements.

Answer:

There were 49 people that chose chocolate and vanilla twist.

Step-by-step explanation:

This problem can be solved by building a Venn diagram of this set, where:

-A is the number of the people that tasted the vanilla

-B is the number of the people that tasted the chocolate.

The most important information in this problem is that some of those people tasted both. It means that [tex]A \cap B = x[/tex], and x is the value we want to find.

The problem states that 97 people tasted the vanilla sample of frozen yogurt.  This includes the people that tasted both samples. It means that x people tasted the chocolate and vanilla twist and 97-x people tasted only the vanilla twist.

72 people tasted the chocolate, also including the people that tasted both samples. It means that x people that tasted the chocolate and vanilla twist and 72-x that tasted only the chocolate twist.

So, recapitulating, there are 120 people, and

97-x  tasted only the vanilla twist.

72 - x tasted only the chocolate twist

x people tasted both

So

97 - x + 72 - x + x = 120

-x = 120 - 72 - 97

-x = -49 *(-1)

x = 49

There were 49 people that chose chocolate and vanilla twist.

To find out how many people chose the chocolate and vanilla twist, we need to subtract the number of people who tasted only vanilla and only chocolate from the total number of people who tasted the frozen yogurt.

To find out how many people chose the chocolate and vanilla twist, we need to subtract the number of people who tasted only vanilla and only chocolate from the total number of people who tasted the frozen yogurt. We know that 97 people tasted vanilla and 72 people tasted chocolate. However, some people chose the chocolate and vanilla twist, so we need to subtract the overlapping cases.

To calculate the number of people who chose the chocolate and vanilla twist, we can use the principle of inclusion-exclusion. We add the number of people who tasted only vanilla and the number of people who tasted only chocolate, and then subtract the total number of people who tasted the frozen yogurt.

Using the formula:

(# of people who tasted vanilla) + (# of people who tasted chocolate) - (# of people who tasted both) = Total # of people who tasted the frozen yogurt

97 + 72 - X = 120

X = 97 + 72 - 120

X = 169 - 120

X = 49

Therefore, 49 people chose the chocolate and vanilla twist.

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The sum E (4 + 6 + 8 + 10 + 106) is greater than the sum O (-3 + 5 + 7 + 9 + 105) by 11. E equals 134 and O equals 123.

To compare the sums O and E without computing each sum directly, let's analyze each expression:

For O: -3 + 5 + 7 + 9 + 105
For E: 4 + 6 + 8 + 10 + 106

Group the pairs of numbers for simplicity:

Comparing the two:

Therefore, the sum E is greater than the sum O by 11.

Answer:

$64

Step-by-step explanation:

We have been given that a local food mart donates 20% of it's Friday's sales to charity. This Friday the food mart had sales totaling 320.00 dollars.

To find the the amount donated to the charity, we will find 20% of $320.

[tex]\text{The amount donated to the charity}=\$320\times\frac{20}{100}[/tex]

[tex]\text{The amount donated to the charity}=\$320\times0.20[/tex]

[tex]\text{The amount donated to the charity}=\$64[/tex]

Therefore, $64 were donated to the charity.

Answer:

[tex]x = 0[/tex] or [tex]x = \pi[/tex].

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

[tex]\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}[/tex].

[tex]\displaystyle \sec{x} = \frac{1}{\cos{x}}[/tex].

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, [tex]\sin^{2}{x} = 1 - \cos^{2}{x}[/tex]. Therefore, for the square of tangents,

[tex]\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}[/tex].

This equation will thus become:

[tex]\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2[/tex].

To simplify the calculations, replace all [tex]\cos^{2}{x}[/tex] with another variable. For example, let [tex]u = \cos^{2}{x}[/tex]. Keep in mind that [tex]0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1[/tex].

[tex]\displaystyle \frac{1 - u}{u^{2}} + \frac{2}{u} - \frac{1 - u}{u} = 2[/tex].

[tex]\displaystyle \frac{(1 - u) + u - u \cdot (1- u)}{u^{2}} = 2[/tex].

Solve this equation for [tex]u[/tex]:

[tex]\displaystyle \frac{u^{2} + 1}{u^{2}} = 2[/tex].

[tex]u^{2} + 1 = 2 u^{2}[/tex].

[tex]u^{2} = 1[/tex].

Given that [tex]0 \le u \le 1[/tex], [tex]u = 1[/tex] is the only possible solution.

[tex]\cos^{2}{x} = 1[/tex],

[tex]x = k \pi[/tex], where [tex]k\in \mathbb{Z}[/tex] (i.e., [tex]k[/tex] is an integer.)

Given that [tex]0 \le x < 2\pi[/tex],

[tex]0 \le k <2[/tex].

[tex]k = 0[/tex] or [tex]k = 1[/tex]. Accordingly,

[tex]x = 0[/tex] or [tex]x = \pi[/tex].

Answer:

Step-by-step explanation:

a. As described in the problem you will be paying in the bill $0.15 per minute which means you have a linear relationship where both the total cost of the bill and the minutes will grow at the same rate (the price of the minute times the minutes) like this

[tex]C(t)=0.15t[/tex]

where C(t) is the total cost of the cell phone bill and t will be the time in minutes

b. The domain of the function will be the values that we can enter to the function. It is defined in the problem that this cost of the minutes its only up to 600 minutes so there is our limitation for the values that will enter the function. The domain will be between 0 and 600 both included because if he calls 0 minutes the bill will be 0 and if he calls 600 he would pay 0.15 for this last minute as well.

[tex][0,600][/tex]

Answer:

The level curves F(t,z) = C for any constant C in the real numbers

where

[tex]F(t,z)=z^3t^2+e^{tz}-4t+2z[/tex]

Step-by-step explanation:

Let's call

[tex]M(t,z)=2tz^3+ze^{tz}-4[/tex]

[tex]N(t,z)=3t^2z^2+te^{tz}+2[/tex]

Then our differential equation can be written in the form

1) M(t,z)dt+N(t,z)dz = 0

To see that is an exact differential equation, we have to show that

2) [tex]\frac{\partial M}{\partial z}=\frac{\partial N}{\partial t}[/tex]

But

[tex]\frac{\partial M}{\partial z}=\frac{\partial (2tz^3+ze^{tz}-4)}{\partial z}=6tz^2+e^{tz}+zte^{tz}[/tex]

In this case we are considering t as a constant.

Similarly, now considering z as a constant, we obtain

[tex]\frac{\partial N}{\partial t}=\frac{\partial (3t^2z^2+te^{tz}+2)}{\partial t}=6tz^2+e^{tz}+zte^{tz}[/tex]

So, equation 2) holds and then, the differential equation 1) is exact.

Now, we know that there exists a function F(t,z) such that

3) [tex]\frac{\partial F}{\partial t}=M(t,z)[/tex]  

AND

4) [tex]\frac{\partial F}{\partial z}=N(t,z)[/tex]

We have then,

[tex]\frac{\partial F}{\partial t}=2tz^3+ze^{tz}-4[/tex]

Integrating on both sides

[tex]F(t,z)=\int (2tz^3+ze^{tz}-4)dt=2z^3\int tdt+z\int e^{tz}dt-4\int dt+g(z)[/tex]

where g(z) is a function that does not depend on t

so,

[tex]F(t,z)=\frac{2z^3t^2}{2}+z\frac{e^{tz}}{z}-4t+g(z)=z^3t^2+e^{tz}-4t+g(z)[/tex]

Taking the derivative of F with respect to z, we get

[tex]\frac{\partial F}{\partial z}=3z^2t^2+te^{tz}+g'(z)[/tex]

Using equation 4)

[tex]3z^2t^2+te^{tz}+g'(z)=3z^2t^2+te^{tz}+2[/tex]

Hence

[tex]g'(z)=2\Rightarrow g(z)=2z[/tex]

The function F(t,z) we were looking for is then

[tex]F(t,z)=z^3t^2+e^{tz}-4t+2z[/tex]

The level curves of this function F and not the function F itself (which is a surface in the space) represent  the solutions of the equation 1) given in an implicit form.

That is to say,

The solutions of equation 1) are the curves F(t,z) = C for any constant C in the real numbers.

Attached, there are represented several solutions (for c = 1, 5 and 10)

Answer:

P(cell has at least one of the positive nickel-charged options) = 0.83.

P(a cell is not composed of a positive nickel charge greater than +3) = 0.85.

Step-by-step explanation:

It is given that the Nickel Charge Proportions found  in the battery are:

0 ==> 0.17

.

+2 ==> 0.35

.

+3 ==> 0.33

.

+4 ==> 0.15.

The numbers associated to the charge are actually the probabilities of the charges because nickel is an element that has multiple oxidation states that is usually found in the above mentioned states.

a) P(cell has at least one of the positive nickel-charged options) = P(a cell has +2 nickel-charged options) + P(a cell has +3 nickel-charged options) + P(a cell has +4 nickel-charged options) = 0.35 + 0.33 + 0.15 = 0.83.

Or:

P(a cell has at least one of the positive nickel-charged options) = 1 - P(a cell has 0 nickel-charged options) = 1 - 0.17 = 0.83.

b) P(a cell is not composed of a positive nickel charge greater than +3) = 1 - P(a cell is composed of a positive nickel charge greater than +3)

= 1 -  P(a cell has +4 nickel-charged options)  '.' because +4 is only positive nickel charge greater than +3      

= 1 - 0.15

=  0.85

To summarize:

P(cell has at least one of the positive nickel-charged options) = 0.83!!!

P(a cell is not composed of a positive nickel charge greater than +3) = 0.85!!!

The probability of a cell having at least one positive nickel-charge is 0.83 and the probability that a cell is not composed of a positive nickel charge greater than +3 is 0.85; This was calculated based on probabilities of Nickel in different charge states.

For this problem, you're basically being asked to interpret a probability distribution of Nickel charge proportions, which involves summing probabilities.

(a) The probability that a cell has at least one of the positive nickel-charged options is the sum of the probabilities of Nickel in the +2, +3, and +4 states. From the given data, we simply add: 0.35 (for +2), 0.33 (for +3), and 0.15 (for +4). So, the total probability is 0.83.

(b) The probability that a cell is not composed of a positive nickel charge greater than +3 means we're looking for the probability of Nickel in the 0, +2, and +3 states. Here, we add: 0.17 (for 0 state), 0.35 (for +2 state), and 0.33 (for +3 state) to get a total probability of 0.85.

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Answer: 38760

Step-by-step explanation:

Given : The number of employees in the company = 20

The number of employees will be selected by company owner to give bonus = 6

We know that the combination of n things taking r at a time is given by :-

[tex]^nC_r=\dfrac{n!}{r!(n-r)!}[/tex]

Then, the number of different sets of employees could receive bonuses is given by :-

[tex]^{20}C_6=\dfrac{20!}{6!(20-6)!}\\\\=\dfrac{20\times29\times18\times17\times16\times15\times14!}{(720)14!}=38760[/tex]

Hence, the number of different sets of employees could receive bonuses is  38760.

Answer:

P= -0.05q+22

Step-by-step explanation:

To find the linear equation that relates price with quantity demanded, first we must find the slope. Because the independent variable is the quantity demanded and the dependent variable is the price, the slope represents how the price changes when there is an extra unit of quantity demanded. The problem gives this information: "for every additional card (extra unit) they need to drop the price by $0.05". The slope (m) in this case is negative because an extra unit, reduces the price: -0.05

The second step is to use this formula:

Y-y1= m*(X-x1)

y1 and x1 is a point of the demand curve, in this case it is y1= $7 and x1=300

Y-$7= -$0.05*(X-300)

Y-7=-0.05X+15

Y= -0.05X+15+7

Y= -0.05X-22

Price= -0.05 quantity demanded +22

Answer:

R = { (2,2), (2, 4), (2, 6), (2,8), (4, 2), (4, 6), (6, 2), (6, 8) }

Step-by-step explanation:

Given,

A = { 0, 1, 2, 3, 4, 5, 6 }

B = { 0,1, 2, 3, 4, 5, 6, 7, 8 }

Also, R is the relation from A to B as follows,

R = { (a, b) : HCF ( a, b ) = 2 ∀ a ∈ A, b ∈ B }

Since,

HCF ( 2, 2 ) = HCF ( 2, 4 ) = HCF ( 2, 6 ) = HCF ( 2, 8 ) = HCF ( 4, 2 ) = HCF ( 4, 6) = HCF ( 6, 4) = HCF ( 6, 2 ) =HCF ( 6, 8 ) = 2

Where, 2, 4, and 6 belong to A,

And, 2, 4, 6 and 8 belong to B,

Hence,

R = { (2,2), (2, 4), (2, 6), (2,8), (4, 2), (4, 6), (6, 2), (6, 4), (6, 8) }

Answer:

Area: 180 units2 (units 2 is because since the are no specific unit given but every area should have a unit  of measurement)

Step-by-step explanation:

The area enclosed by the graph of the function, the horizontal axis, and vertical lines is the integral of the function between thos two points (x=2 and x=4)

So , let's solve the integral of f(x)

Area =[tex]\int\limits^2_4 3{x}^3 \, dx = 3*x^4/4[/tex]+C

C=0

So if we evaluate this function in the given segment:

Area= 3* (4^4)/4-3*(2^4)/4= 3*(4^4-2^4)/4=180 units 2

Goos luck!

Step-by-step explanation:

Perfect number is the positive integer which is equal to sum of proper divisors of the number.

Aliquot part is also called as proper divisor which means any divisor of the number which isn't equal to number itself.

Number : 6

Perfect divisors / Aliquot part = 1, 2, 3

Sum of the divisors = 1 + 2 + 3 = 6

Thus, 6 is a perfect number.

Number : 28

Perfect divisors / Aliquot part = 1, 2, 4, 7, 14

Sum of the divisors = 1 + 2 + 4 + 7 + 14 = 28

Thus, 28 is a perfect number.

Answer:

you need 100ml of 5X TAE and 400ml of water.

Step-by-step explanation:

You need to use a rule of three:

[tex]C_1V_1=C_2V_2[/tex]

where:

[tex]\left \{ {{C_1= 5X} \atop {C_2=1X}} \right.[/tex]

and

[tex]\left \{ {{V_1 = V_{TAE}} \atop {V_2=500ml}} \right.[/tex]

Therefore:

[tex]V_{TAE} = \frac{V_2*C_2}{C_1}[/tex]

[tex]V_{TAE} = 100ml[/tex]

Then just rest the TAE volume to the final Volume and you get the amount of water that you need to reduce the concentration.

Answer:

Step-by-step explanation:

It shall be 100xl times the number of 1x tae

Answer:

840

Step-by-step explanation:

Total number of gifts (teddy bears)= 4

Total number of nieces = 7

We need to find the number of ways to give the 4 teddy bears to 4 of the 7 nieces, where no niece gets more than one teddy bear.

Number of possible ways to give first teddy = 7

It is given that no niece gets more than one teddy bear.

The remaining nieces are = 7 - 1 = 6

Number of possible ways to give second teddy = 6

Now, the remaining nieces are = 6 - 1 = 5

Similarly,

Number of possible ways to give third teddy = 5

Number of possible ways to give fourth teddy = 4

Total number of possible ways to distribute 4 teddy bears is

[tex]Total=7\times 6\times 5\times 4=840[/tex]

Therefore total possible ways to distribute 4 teddy bears are 840.

Final answer:

There are 35 different ways to give 4 identical teddy bears to 4 of the 7 nieces where no niece receives more than one teddy bear. The calculation is done using combinations formula C(7, 4).

Explanation:

To determine the number of different ways the 4 teddy bears can be given to 4 out of 7 nieces where each niece gets only one teddy bear, we use combinations. Combinations are a way of selecting items from a group, where the order does not matter. In mathematics, this is denoted as C(n, k), which represents the number of combinations of n items taken k at a time.

In this case, we want to find C(7, 4), because we have 7 nieces (n=7) and we are choosing 4 of them (k=4) to each receive one teddy bear. This is calculated by:

C(7, 4) = 7! / (4! * (7-4)!) => C(7, 4) = (7 * 6 * 5 * 4!) / (4! * 3!). Since 4! in the numerator and denominator cancel each other out, it simplifies to:

C(7, 4) = 7 * 6 * 5 / (3 * 2 * 1) = 35

Therefore, there are 35 different ways to give the 4 identical teddy bears to 4 of the 7 nieces when no niece gets more than one teddy bear.

Answer:

2/6 or 1/3 so color 2 out of the six squares

Step-by-step explanation:

1/2 - 1/6 is equal to 3/6 - 1/6 so 2/6

Answer: The required value would be 0.000013.

Step-by-step explanation:

Since we have given that

0.001 % of [tex]\dfrac{4}{3}[/tex]

As we know that

To remove the % sign we should divide it by 100.

Mathematically, it would be expressed as

[tex]\dfrac{0.001}{100}\times \dfrac{4}{3}\\\\=\dfrac{0.004}{300}\\\\=0.000013[/tex]

Hence, the required value would be 0.000013.

Answer:

Standard Deviation = 9.75        

Step-by-step explanation:

We are given the following data:

n = 25

Ages: 60, 61, 62, 63, 64, 65, 66, 68, 68, 69, 70, 73, 73, 74, 75, 76, 76, 81, 81, 82, 86, 87, 89, 90, 92

Formula:

For sample,

[tex]\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}[/tex]

where [tex]x_i[/tex] are data points, [tex]\bar{x}[/tex] is the mean and n is the number of observations.

[tex]Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}[/tex]

Mean = [tex]\frac{1851}{25} = 74.04[/tex]

Sum of square of differences = 2278.96

S.D = [tex]\sqrt{\diplaystyle\frac{2278.96}{24} } = 9.74[/tex]

To calculate the standard deviation of the given ages, we find the mean, subtract it from each age to find deviations, square these, find their mean, and take the square root to get the standard deviation, which is 6.96.

The question is asking to calculate the standard deviation of the ages of 25 senior citizens. To find the standard deviation, we need to follow these steps:

Calculate the mean (average) age of the senior citizens.

Subtract the mean from each age to find the deviation of each value.

Square each deviation.

Calculate the mean of these squared deviations.

Take the square root of the mean of the squared deviations to get the standard deviation.

Performing these calculations, we find that the mean (average) age is 73.24. The sum of the squared deviations is 1210. After dividing this sum by the number of values (25), we get the variance, which is 48.4. Finally, taking the square root of the variance gives us the standard deviation, which to two decimal places is 6.96.

This measure of standard deviation is crucial in understanding the spread of ages among senior citizens in the sociologist's survey.

Answer:

The EMV of the project is $25,500.

Step-by-step explanation:

The EMV of the project is the Expected Money Value of the Project.

This value is given by the sum of each expected earning multiplied by each probability

So, in our problem

[tex]EMV = P_{1} + P_{2} + P_{3}[/tex]

The problem states that the project has a 60% of super success earning $50,000. So

[tex]P_{1} = 0.6*50,000 = 30,000[/tex]

The project has a 15% chance of mediocre success earning $20,000. So

[tex]P_{2} = 0.15 * 20,000 = 3,000[/tex]

The project has a 25% probability of failure losing $30,000. So

[tex]P_{3} = 0.25*(-30,000) = -7,500[/tex]

[tex]EMV = P_{1} + P_{2} + P_{3} = 30,000 + 3,000 - 7,500 = 25,500[/tex]

The EMV of the project is $40,500.

Answer:

The resultant velocity of the airplane is 213.41 m/s.

Step-by-step explanation:

Given that,

Velocity of an airplane in east direction, [tex]v_1=210\ mph[/tex]

Velocity of wind from the north, [tex]v_2=38\ mph[/tex]

Let east lies in the direction of the positive x-axis and north in the direction of the positive y-axis.

We need to find the resultant velocity of the airplane. Let v is the resultant velocity. It can be calculated as :

[tex]v=\sqrt{v_1^2+v_2^2}[/tex]

[tex]v=\sqrt{(210)^2+(38)^2}[/tex]

v = 213.41 m/s

So, the resultant velocity of the airplane is 213.41 m/s. Hence, this is the required solution.

Final answer:

The resultant velocity of the airplane, combining its eastward direction and the northward wind, is approximately 213.4 miles per hour at an angle of 10.3 degrees north of east.

Explanation:

The student's question relates to the concept of resultant velocity, which is a fundamental topic in Physics. When two velocities are combined, such as an airplane's velocity and wind velocity, the outcome is a vector known as the resultant velocity. To calculate this, one must use vector addition.

The airplane has a velocity of 210 miles per hour due east, which can be represented as a vector pointing along the positive x-axis. The wind has a velocity of 38 miles per hour from the north, represented as a vector along the positive y-axis. To find the resultant velocity, these two vectors must be combined using vector addition.

Mathematically, the resultant vector [tex]\\(R)[/tex] can be found using the Pythagorean theorem if the vectors are perpendicular, as in this case:
[tex]\[ R = \sqrt{V_{plane}^2 + V_{wind}^2} \][/tex]

Where \\(V_{plane}\\) is the velocity of the airplane and [tex]\(V_{wind}\)[/tex] is the velocity of the wind.

The direction of the resultant vector can be determined by calculating the angle [tex]\(\theta\)[/tex] it makes with the positive x-axis using trigonometry, specifically the tangent function:
[tex]\[ \theta = \arctan\left(\frac{V_{wind}}{V_{plane}}\right) \][/tex]

By substituting the given values:

The resultant velocity (magnitude) is then calculated by:

[tex]\[ R = \sqrt{(210)^2 + (38)^2} = \sqrt{44100 + 1444} = \sqrt{45544} \][/tex]

This yields a resultant speed of approximately 213.4 miles per hour.

The direction \\(\theta\\) will be:

[tex]\[ \theta = \arctan\left(\frac{38}{210}\right) \][/tex]

Using a calculator, one finds that [tex]\(\theta\)[/tex] is approximately 10.3 degrees north of east.

Answer:

The value of q are 0.781,-1.281.

Step-by-step explanation:

Given : Two vectors [tex]A=i+j+kq[/tex] and [tex]B=iq-2j+2kq[/tex] are perpendicular to each other.

To find : The value of q ?

Solution :

When two vectors are perpendicular to each other then their dot product is zero.

i.e. [tex]\vec{A}\cdot \vec{B}=0[/tex]

Two vectors [tex]A=i+j+kq[/tex] and [tex]B=iq-2j+2kq[/tex]

[tex](i+j+kq)\cdot (iq-2j+2kq)=0[/tex]

[tex](1)(q)+(1)(-2)+(q)(2q)=0[/tex]

[tex]q-2+2q^2=0[/tex]

[tex]2q^2+q-2=0[/tex]

[tex]2q^2+q-2=0[/tex]

Using quadratic formula,

[tex]q=\frac{-1\pm\sqrt{1^2-4(2)(-2)}}{2(2)}[/tex]

[tex]q=\frac{-1\pm\sqrt{17}}{4}[/tex]

[tex]q=\frac{-1+\sqrt{17}}{4},\frac{-1-\sqrt{17}}{4}[/tex]

[tex]q=0.781,-1.281[/tex]

Therefore, The value of q are 0.781,-1.281.

Answer:  a)   2.27 g     and     b)  15384

Step-by-step explanation:

Given : An effervescent tablet has the following formula:

acetaminophen 325 mg,

calcium carbonate 280 mg,

citric acid 900 mg,

potassium bicarbonate 300 mg, and

sodium bicarbonate 465 mg.

a) When we add all quantities together , we get

The total weight of the ingredients in each tablet = [tex]325 +280+900+300+465=2270[/tex]

Since, 1 gram = 1000 mg

Then, [tex]1\ mg=\dfrac{1}{1000}\ g[/tex]

Now, [tex]2270\ mg=\dfrac{2270}{1000}\ g=2.27\ g[/tex]

∴ The total weight of the ingredients in each tablet = 2.27 g

b. 1 kg = 1000g and 1 g = 1000 mg

Then, 1 kg = [tex]1000\times1000=1000,000\ mg[/tex]

⇒ 5 kg = 5000,000 mg

Now, The number of  tablets could be made with a supply of 5 kg of acetaminophen will be :

[tex]\dfrac{5000000}{325}=15384.6153846\approx15384[/tex]

Hence, the number of  tablets could be made with a supply of 5 kg of acetaminophen= 15384

The total weight of the ingredients in the effervescent tablet is 2.27 g. With a supply of 5 kg of acetaminophen, you could produce approximately 15,385 tablets.

To answer the student's questions, we start by calculating the total weight of the tablet:
acetaminophen: 325 mg, calcium carbonate: 280 mg, citric acid: 900 mg, potassium bicarbonate: 300 mg, and sodium bicarbonate: 465 mg.
Adding all these quantities together gives a total of 2270 mg or 2.27 g per tablet.

Now for the second question, to find out how many tablets you can make from 5 kg of acetaminophen, we need to determine how much acetaminophen is in a single tablet. We know that each tablet contains 325 mg of acetaminophen, so if we have 5 kg of it, we first convert the 5 kg into milligrams (since the amount in each tablet is given in milligrams).
There are 1,000,000 milligrams in a kilogram, so 5 kg = 5 x 1,000,000 = 5,000,000 mg.
We then divide this total quantity by the amount of acetaminophen in each tablet: 5,000,000 mg / 325 mg/tablet = approximately 15,385 tablets.

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Answer:

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

Step-by-step explanation:

The problem states that the monthly cost of a celular plan is modeled by the following function:

[tex]C(x) = 4 + 0.10(x-70)[/tex]

In which C(x) is the monthly cost and x is the number of calling minutes.

How many calling minutes are needed for a monthly cost of at least $7?

This can be solved by the following inequality:

[tex]C(x) \geq 7[/tex]

[tex]4 + 0.10(x - 70) \geq 7[/tex]

[tex]4 + 0.10x - 7 \geq 7[/tex]

[tex]0.10x \geq 10[/tex]

[tex]x \geq \frac{10}{0.1}[/tex]

[tex]x \geq 100[/tex]

For a monthly cost of at least $7, you need to have at least 100 calling minutes.

How many calling minutes are needed for a monthly cost of at most 8:

[tex]C(x) \leq 8[/tex]

[tex]4 + 0.10(x - 70) \leq 8[/tex]

[tex]4 + 0.10x - 7 \leq 8[/tex]

[tex]0.10x \leq 11[/tex]

[tex]x \leq \frac{11}{0.1}[/tex]

[tex]x \leq 110[/tex]

For a monthly cost of at most $8, you need to have at most 110 calling minutes.

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

Answer:

0.681

Step-by-step explanation:

Let's define the following events:

S: a Carter office worker is rated satisfactory

U : a Carter office worker is rated unsatisfactory

ND: a Carter office worker is placed by Nancy Dwyer

DN: a Carter office worker is placed by Darla Newberg

We have from the original text that

P(S | ND) = 0.8, this implies that P(U | ND) = 0.2.

P(S | DN) = 0.65, this implies that P(U | DN) = 0.35. Besides

P(DN) =  0.55 and P(ND) = 0.45, then we are looking for

P(DN | U), using the Bayes' formula we have

P(DN | U) = [tex]\frac{P(U | DN)P(DN)}{P(U | DN)P(DN) + P(U | ND)P(ND)}[/tex] = [tex]\frac{(0.35)(0.55)}{(0.35)(0.55)+(0.2)(0.45)}[/tex]=0.681

Final answer:

The probability that a Carter office worker rated unsatisfactory was placed by Darla is approximately 0.346.

Explanation:

To find the probability that a Carter office worker rated unsatisfactory was placed by Darla, we can use Bayes' theorem. Let's denote the event that the worker is placed by Darla as D and the event that the worker is rated unsatisfactory as U. We are given the following probabilities:

P(Darla places) = 55% = 0.55

P(Nancy places) = 45% = 0.45

P(Satisfactory | Nancy places) = 80% = 0.80

P(Satisfactory | Darla places) = 65% = 0.65

We want to find P(D | Unsatisfactory), which is the probability that the worker was placed by Darla given that they are rated unsatisfactory. Using Bayes' theorem, we have:

P(D | U) = (P(D) * P(U | D)) / (P(D) * P(U | D) + P(N) * P(U | N))

Substituting the given probabilities, we get:

P(D | U) = (0.55 * (1 - 0.65)) / (0.55 * (1 - 0.65) + 0.45 * (1 - 0.80))

P(D | U) ≈ 0.346

Therefore, the probability that a Carter office worker rated unsatisfactory was placed by Darla is approximately 0.346.

Answer:

PROPORTION.

Step-by-step explanation:

The relative frequency in a relative frequency histogram refers to                                  PROPORTION.

A relative frequency histogram uses the same information as a frequency histogram but compares each class interval with the number of items. The difference between frequency and relative frequency histogram is that the vertical axes uses the relative or proportional frequency rather than simple frequency

Answer:

1052.944 g

Step-by-step explanation:

Given:

Initial temperature of water = 15° C

Final temperature of water = 1° C

Mass of ice = 185 grams

Now,

Heat of fusion of ice = 333.55 J/g

Thus,

The heat required to melt ice = Mass of ice × Heat of fusion

or

The heat required to melt ice = 185 × 333.55 = 61706.75 J

Now,

for water the specific heat capacity= 4.186 J/g.°C

Heat provided = mass × specific heat capacity × Change in temperature

or

61706.75 = mass × 4.186 × (15 - 1)

or

61706.75 = mass × 58.604

or

mass = 1052.944 g

Hence, the mass that can be heated 1052.944 g

Answer:

The angle that the ramp makes with the ground is 11.54°

Step-by-step explanation:

From the image attached, we can see that the length of 17 1/2 ft corresponds to the hypotenuse in a right triangle, the length of 3 1/2 ft corresponds to the opposite side.

We can use the fact that the sin(θ) = [tex]\frac{Opposite}{Hypotenuse}[/tex] to find the angle that the ramp makes with the ground.

[tex]sin(\theta)=\frac{3.5}{17.5}[/tex]

The angle is equal to

[tex]\theta = sin^{-1}(\frac{3.5}{17.5} )\\\theta = 11.54\°[/tex]

The angle that the ramp makes with the ground can be found using the concept of tangent in trigonometry. By dividing the height of the loading platform by the length of the ramp and taking the inverse tangent of the result, we find the angle to be approximately 11.3 degrees.

This question can be solved by using trigonometric principles, specifically the tangent of an angle in a right triangle. The tangent of an angle θ (theta) can be defined as the ratio of the side opposite the angle to the side adjacent to it.

In this scenario, the ramp forms a right triangle with the ground and the vertical line from the loading platform to the ground directly below it. The height of the platform, or the 'opposite' side, is 3 1/2 feet, and the ramp, or the 'adjacent' side, is 17 1/2 feet.

Therefore, we can say that: tan θ = (3.5 / 17.5)

To find the value of θ, we take the inverse tangent (or arc tangent) of the quotient. Using a calculator to do this (remember to set your calculator to degree mode), we find θ to be approximately 11.3 degrees.

Thus, the angle that the ramp makes with the ground is about 11.3 degrees.

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Answer:

(B) 0.0588

Step-by-step explanation:

The probability is calculated as a division between the number of possibilities that satisfy a condition and the number of total possibilities. Then, the probability that the first card is diamonds is:

[tex]P_1=\frac{13}{52}[/tex]

Because the deck has 52 cards and 13 of them are diamonds.

Then, if the first card was diamonds, the probability that the second card is also diamond is:

[tex]P_2=\frac{12}{51}[/tex]

Because now, we just have 51 cards and 12 of them are diamonds.

Therefore, the probability that both cards are diamonds is calculated as a multiplication between [tex]P_1[/tex] and [tex]P_2[/tex]. This is:

[tex]P=\frac{13}{52}*\frac{12}{51}=\frac{1}{17}=0.0588[/tex]