Johnny was playing baseball with his friends and they noticed a bolt of lightning. They heard thunder seven seconds later. How far away is the storm?

Answers

Answer 1

That particular strike was very roughly 2.4 km (1.5 miles) away from them.

That's if you use 340 m/s (1120 ft/sec) for the speed of sound. 
But the air in the region for several thousand feet around a thunderstorm
is doing weird things to sounds that pass through it, so you can't use any
exact number for the speed of sound in a stormy area.

The only thing you can be absolutely sure of is that Johnny and his friends
need to round up their equipment and get in the house.  NOW ! 
Answer 2

2,317 meters on edg!!


Related Questions

Air is contained in a cylinder device fitted with a piston-cylinder. the piston initially rests on a set of stops, and a pressure of 200 kpa is required to move the piston. initially, the air is at 100 kpa and 238c and occupies a volume of 0.25 m3. determine the amount of heat transferred to the air, in kj, while increasing the temperature to 700 k. assume air has constant specific heats evaluated at 300 k.

Answers

A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
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A skier moving at 4.75 m/s encounters a long, rough, horizontal patch of snow having a coefficient of kinetic friction of 0.220 with her skis. how far does she travel on this patch before stopping?

Answers

First we need to find the acceleration of the skier on the rough patch of snow.
We are only concerned with the horizontal direction, since the skier is moving in this direction, so we can neglect forces that do not act in this direction. So we have only one horizontal force acting on the skier: the frictional force, [tex]\mu m g[/tex]. For Newton's second law, the resultant of the forces acting on the skier must be equal to ma (mass per acceleration), so we can write:
[tex]ma=-\mu m g[/tex]
Where the negative sign is due to the fact the friction is directed against the motion of the skier.
Simplifying and solving, we find the value of the acceleration:
[tex]a=-(0.220)(9.81 m/s^2)=-2.16 m/s^2[/tex]

Now we can use the following relationship to find the distance covered by the skier before stopping, S:
[tex]2aS=v_f^2-v_i^2[/tex]
where [tex]v_f=0 [/tex] is the final speed of the skier and [tex]v_i=4.75 m/s[/tex] is the initial speed. Substituting numbers, we find:
[tex]S=- \frac{v_i^2}{2a}=- \frac{(4.75 m/s)^2}{2(-2.16 m/s^2)}=5.23 m [/tex]

After the sun exhausts its nuclear fuel, its ultimate fate may be to collapse to a white dwarf state. in this state, it would have approximately the same mass as it has now, but its radius would be equal to the radius of the earth. (a) calculate the average density of the white dwarf.

Answers

To calculate the density of the white dwarf we need the mass of the Sun and the radius of the Earth:
- Sun mass: [tex]M=1.99 \cdot 10^{30}kg[/tex]
- Earth radius: [tex]r=6.37 \cdot 10^6 m[/tex]
Assuuming the dwarf to be a perfect sphere, its volume is [tex]V= \frac{4}{3} \pi r^3[/tex].
The average density is given by
[tex]d= \frac{M}{V} [/tex]
so, substituting we find
[tex]d= \frac{M}{ \frac{4}{3}\pi r^3 }=1.83 \cdot 10^9 kg/m^3 [/tex]

Based on what you have read, explain the advantages of digital signals over analog signals.

Answers

Digital signals do not pass noise along, so the sound heard is likely very close to the signal that was sent. Digital signals also can be stored more easily than analog signals. Recorded analog signals degrade over time, while recorded digital signals do not.

Sample Response: Digital signals do not pass noise along, so the sound heard is likely very close to the signal that was sent. Digital signals also can be stored more easily than analog signals. Recorded analog signals degrade over time, while recorded digital signals do not.

Julius competes in the hammer throw event. The hammer has a mass of 7.26 kg and is 1.215 m long. What is the centripetal force on the hammer when it has a tangential speed of 31.95 m/s? The answer is rounded off to the nearest whole number. 190 N 840 N 1,400 N 6,100 N

Answers

In the circular motion of the hammer, the centripetal force is given by
[tex]F=m \frac{v^2}{r} [/tex]
where m is the mass of the hammer, v its tangential speed and r is the distance from the center of the motion, i.e. the length of the hammer.
Using the data of the problem, we find:
[tex]F=m \frac{v^2}{r}=(7.26 kg) \frac{(31.95 m/s)^2}{1.215 m}=6100 N [/tex]

Answer:

6,100 N

Explanation:

Forces are _______ which means they need to be determined by not only their numeric value (amount of force in Newton's) but also their _______.


please help this is a science question

Answers

Forces are vectors, which means they need to be determined by not only their numeric value (amount of force in Newton's) but also their direction.

Some other examples of vector quantities include displacement, acceleration,  velocity, and momentum.  Each of these isn't complete until you know its size and direction.

There are other quantities that have size but no direction.  They include distance, speed, volume, temperature, cost, and loudness.  These are called "scalars".

What condition occurs when the eyeball is too long?

Answers

Hello!

Myopia, also known as nearsightedness, occurs when the eyeball is too long. This condition is very common in the U.S and throughout the world. It can be corrected by wearing glasses or contact lenses.

Explanation :

There can be many eye defects in the human eye. Some of them are Myopia, Hypermetropia, Astigmatism etc.

In Myopia the size of the eyeball is too long and the image is formed in front of the retina. A person suffering from this defect is not able to see far objects clearly but can see nearby objects normal.

Concave lenses are used to correct this defect so that the image is focused on the retina.

A 150 g baseball is traveling horizontally at 50 m/s. If the ball takes 20 ms to stop once it is in contact with the catcher’s glove, what average force did the ball exert on the catcher?

Answers

To solve for force, you need to get the product of mass and acceleration. 
F = ma

Your given is:
m = 150g
a = ?
v = 50 m/s
t = 20ms

As you can see, you do not have acceleration yet. But if you read the problem you can come up with the formula of acceleration. 
Acceleration is the change in velocity over a period of time.

a = change in velocity/time

To get the change in velocity, you get the difference between the initial velocity and final velocity:

[tex]a = \frac{vf-vi}{t} [/tex]

The ball was moving initially at a velocity of 50 m/s and it came to a stop. This is your clue. If a ball comes to a stop then that means that the final velocity of the ball is 0 m/s. 

So we can put it into our formula now:

[tex]a = \frac{0m/s-50m/s}{20ms} [/tex]

WAIT! As you can see, the units do not match. We have ms and s into our equation and that means you cannot proceed till they are the same. First we need to convert ms to s. 

[tex]20ms[/tex] x [tex] \frac{1s}{1000ms} [/tex] = [tex] \frac{20s}{1000} = 0.02s [/tex]

So your new time is 0.02s. Now we put this time into the formula:


[tex]a = \frac{0m/s-50m/s}{0.02s} [/tex]
[tex]a = \frac{-50m/s}{0.02s} = -2,500 m/ s^{2} [/tex]

As you can see our acceleration is a negative value, this indicates that it decelerated or slowed down which makes sense because it was brought to a stop. 

So now we have our acceleration. Now using this, we can get our force. 

[tex]F= ma[/tex]

Before we start doing this, you need to take note that the unit of force is N, but when you expand it, it is [tex]kg.m/ s^{2} [/tex] but as you can see our mass given is in grams. So again, before you put them into the equation we need to change it into kg first. 

[tex]150g = \frac{1kg}{1,000g} = \frac{150kg}{1,000} = 0.150kg[/tex]

Our new mass is 0.150kg. 

To make things clearer, let us write down all our new values:

m = 0.150kg
a = -2,500 [tex]m/ s^{2} [/tex]

Now that all our units match, we can put that into our formula:

[tex]F= ma[/tex]
[tex]F= (0.150kg)(-2,500m/s^{2})[/tex]
[tex]F = -375kg.m/ s^{2} or -375N[/tex]

The value again is negative because it is going against the initial direction of the ball. But if your instructor just wants to get the value of force or the magnitude of the force, just disregard the sign. 



A 2.00 kg block is placed against a spring on a frictionless 36° incline. the spring, whose spring constant is 19.8n/cm, is compressed 22.8 cm and then released. what is the elastic potential energy of the compressed spring?

Answers

Final answer:

The elastic potential energy of the compressed spring with a spring constant of 19.8 N/cm and compressed 22.8 cm is approximately 51.5 Joules.

Explanation:

The elastic potential energy (EPE) stored in a spring is calculated using the formula EPE = 1/2 k x², where k is the spring constant, and x is the displacement from the spring's equilibrium position. Given that the spring constant is 19.8 N/cm and the spring is compressed 22.8 cm, we must first convert the spring constant to N/m by multiplying by 100, giving us 1980 N/m. Using the formula, the elastic potential energy is thus EPE = 1/2 (1980 N/m) (0.228 m)² = 1/2 (1980) (0.051984) J = 51.504 J. Therefore, the potential energy of the compressed spring is approximately 51.5 Joules.

An eagle that has a mass of 4.5 kg is spotted 5 m above a lake. It flies up to its nest in a tree at a height of 25m

Answers

I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
 
PLEASE SEE ATTACHED IMAGE.  
 Let's  define potential energy:
 By definition, the potential energy is given by:
 Ep = m * g * h
 Where,
 m: mass
 g: gravity
 h: height.
 The potential energy change is:
 Delta Ep = Epf- Epi
 Delta Ep = m * g * hf  -  m * g * hi
 Delta Ep = m * g * (hf - hi) 
 The, we have
 Substituting values:
 Delta Ep = (4.5) * (9.8) * (25 - 5)
 Delta Ep = 882 J
 Answer:
 the eagle gain: 
 Delta Ep = 882 J

Answer:

c

Explanation:

just took test on edge but not sure if i was right :) goodluck gs

A strong lightning bolt transfers about 25 c to earth. how many electrons are transferred? the elementary charge is 1.60218 × 10−19
c.

Answers

The total charge transferred is [tex]Q=25 C[/tex]. This total charge consists of N electrons, each one with charge [tex]e=1.6 \cdot 10^{-19}C[/tex]. To find N, the number of electrons transferred, we must simply divide the total charge by the charge of a single electron:
[tex]N= \frac{Q}{e}= \frac{25 C}{1.6 \cdot 10^{-19}C}=1.56 \cdot 10^{20} [/tex]
Final answer:

To determine how many electrons are transferred in a lightning strike, you divide the total charge transferred (in this case, 25 coulombs) by the elementary charge which is the charge per electron. The result approximates to 1.56 × 1020 electrons.

Explanation:

The number of electrons transferred during a lightning strike can be determined by dividing the total charge transferred by the charge of a single electron. The charge of a single electron, also known as the elementary charge, is approximately 1.60218 × 10-19 Coulombs. Therefore, if a lightning bolt transfers about 25 Coulombs to the ground, the number of electrons transferred can be calculated as follows:

Number of electrons = Total charge transferred / Charge per electron

= 25 Coulombs / 1.60218 × 10-19 Coulombs

Therefore, a lightning bolt that transfers about 25 Coulombs to the earth transfers approximately 1.56 × 1020 electrons.

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the lowest pitched sounds humans can generally hear have a frequency of roughly 20 Hz. What is the approximate wavelength of these sound waves if their wave speed is 340 m/A?

Answers

V = Frequency x Wavelength.

V = 340;
340 = 20 x Wavelength; divide both sides by 20.
Wavelength = 17

The wavelength is 17m.

I hope this helps!

"V = Frequency x Wavelength.

V = 340;

340 = 20 x Wavelength; divide both sides by 20.

Wavelength = 17"

Explanation:

An object in motion will stay in motion unless acted upon by what type of force

Answers

An object will stay in motion unless acted upon by an UNBALANCED force. 
The answer Is unbalanced On USATESTPREP

You are given a cylinder of outer radius 3.27 cm and length of 11.5 cm. along the axis of the cylinder is a hole of diameter 2.47 cm. find the volume of this cylindrical shell.

Answers

  Required Volume (V) = Area of the base * Height

Area of the base = Pi [ 3.27² - (2.47/2)² ] since 2.47 is diameter and not radius. = Pi ( 9.981675 )

Therefore Volume (V) = Pi ( 9.981675) * 15.9 = 498.5978739 cm³ = 498.6 cm³.

What is the kinetic energy of a 3000 lb car traveling at 60 mph?

Answers

5 × 12 = 60 I got 60mph I multiply and that's how I get 60

The uniform bar of mass m and length l is balanced in the vertical position when the horizontal force p is applied to the roller at
a. determine the bar's initial angular acceleration and the acceleration of its top point
b.

Answers

Which of the following is NOT a factor in efficiency?A.metabolismB.type of movementC.muscle efficiencyD.digestion

An amusement park ride raises people high into the air, suspends them for a moment, and then drops them at a rate of free-fall acceleration. Is a person in this ride experiencing apparent weightlessness, true weightlessness, or neither? Explain.

Answers

An object experiences true weightlessness when the net force of all gravitational forces acting upon the object is zero. In this case, the gravitational force exerted by the earth on the people that are on the park ride while it's free falling never ceases to act on the people. If the person on the ride were in a case of true weightlessness then they would not fall in any direction in the first place. The answer is the apparent weightlessness.

Answer: apparent weighlessness.


Explanation:


1) Balance of forces on a person falling:


i) To answer this question we will deal with the assumption of non-drag force (abscence of air).


ii) When a person is dropped, and there is not air resistance, the only force acting on the person's body is the Earth's gravitational attraction (downward), which is the responsible for the gravitational acceleration (around 9.8 m/s²).


iii) Under that sceneraio, there is not normal force acting on the person (the normal force is the force that the floor or a chair exerts on a body to balance the gravitational force when the body is on it).


2) This is, the person does not feel a pressure upward, which is he/she does not feel the weight: freefalling is a situation of apparent weigthlessness.


3) True weightlessness is when the object is in a place where there exists not grativational acceleration: for example a point between two planes where the grativational forces are equal in magnitude but opposing in direction and so they cancel each other.


Therefore, you conclude that, assuming no air resistance, a person in this ride experiencing apparent weightlessness.

For a sine wave depicting simple harmonic motion, the smaller the amplitude of the wave, the smaller the of the pendulum from the equilibrium position. The shorter the period, the the pendulum’s rod.

Answers

displacement   , shorter 

Answer:

The smaller the amplitude of the wave, the smaller the displacement of the pendulum from the equilibrium position. The shorter the period, the shorter the pendulum’s rod.

To find the right answer, we could look the analysis of a simple pendulum movement. The relation that defines this movement is:

[tex]T=2 \pi \sqrt{\frac{l}{g} }[/tex]

[tex]T: \ period\\l: \ pendulum's \ rod \ length\\g: \ gravity[/tex]

From the equation, we can see the relation between the period and the length of the pendulum's rod. They are directly proportional, this means that if the period increases, the length increases, or vice versa. So, the shorter the period, the shorter the pendulum's rod, because they are directly proportional.

On the other hand, the amplitude of the harmonic motion refers to the displacement of the object from the equilibrium point which is in the center of the periodic movement. This allow us to deduct that if the amplitude is small, the displacement of the object is small, if the amplitude is big, the displacement from the equilibrium point is bid.

When Trinity pulls on the rope with her weight, Newton's Third Law of Motion tells us that the rope will _____

Answers

When Trinity pulls on the rope with her weight, Newton's Third Law of Motion tells us that the rope will "pull back".


Newton's third law of motion expresses that, at whatever point a first question applies a power on a second object, the first object encounters a power meet in extent however inverse in heading to the power that it applies.  

Newton's third law of movement reveals to us that powers dependably happen in sets, and one question can't apply a power on another without encountering a similar quality power consequently. We once in a while allude to these power matches as "action-reaction" sets, where the power applied is the activity, and the power experienced in kind is the response (despite the fact that which will be which relies upon your perspective).

What is the Milgram experiment?

Answers

Answer:

The study was unethical

Explanation:

The study was deceptive to the participants, It failed to protect the participants involved and it denied them the right to withdraw from the experiment.

If a violin string vibrates at 195 hz as its fundamental frequency, what are the frequencies of the first four harmonics? first harmonic hz second harmonic hz third harmonic hz fourth harmonic hz

Answers

The frequency of the nth-harmonic is n times the fundamental frequency f1:
[tex]f_n = n f_1[/tex]
The first harmonic is the fundamental frequency: [tex]f_1 = 195 Hz[/tex], then the following harmonics are
[tex]f_2 = 2 f_1 = 2 \cdot 195 Hz = 390 Hz[/tex]
[tex]f_3 = 3 f_1 = 3 \cdot 195 Hz = 585 Hz[/tex]
[tex]f_4 = 4 f_1 = 4 \cdot 195 Hz = 780 Hz[/tex]

Answer:

A violin is a both ends fixed, and so successive harmonics are simply multiples of the fundamental:

Therefore, f1 = 440Hz (fundamental frequency)

f2 = 2f1 = 2 x 440 = 880 Hz

f3 = 3f1 = 3 x 440 = 1320 Hz

f4 = 4f1 = 4 x 440 = 1760 Hz

what are 3 adjectives that describe a super bowl crowd

Answers

Loud
Crazed
Herd-like
Irrational
Deafening
Primitive
Possessed
Tribal

A particle moving in the x direction is being acted upon by a net force f(x)=cx2, for some constant
c. the particle moves from xinitial=l to xfinal=3l. what is δk, the change in kinetic energy of the particle during that time? express your answer in terms of c and l.

Answers

The work-energy theorem states that the change in kinetic energy of the particle is equal to the work done on the particle:
[tex]\Delta K = W[/tex]
The work done on the particle is the integral of the force on dx:
[tex]W= \int\limits^{3L}_L {F(x)} \, dx = \int\limits^{3L}_L {cx^2} \, dx = \frac{26}{3}cL^3 [/tex]
So, this corresponds to the change in kinetic energy of the particle.

The change in kinetic energy during that time is : [tex]\frac{26}{3} cl^{3}[/tex]

Given data :

Direction of particle = x

Net force = F(x) = cx²

Initial position = l

Final position = 3l

Determine the change in kinetic energy during this time

we will apply the work energy theorem which is : ΔK = W

To determine change in kinetic energy we have to determine the work done on the particle.

Work done on particle ( W ) =  [tex]\int\limits^3_l F({x}) \, dx[/tex] =  [tex]\int\limits^3_l c{x^{2} } \, dx =[/tex] [tex]\frac{26}{3} cl^{3}[/tex]

Hence the change in kinetic energy during that time is : [tex]\frac{26}{3} cl^{3}[/tex]

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The n = 2 to n = 6 transition in the bohr hydrogen atom corresponds to the ________ of a photon with a wavelength of ________ nm.

Answers

The energy levels of the hydrogen atom are quantized and their energy is given by the approximated formula
[tex]E=- \frac{13.6}{n^2} [eV] [/tex]
where n is the number of the level.

In the transition from n=2 to n=6, the variation of energy is
[tex]\Delta E=E(n=6)-E(n=2)=-13.6 ( \frac{1}{6^2}- \frac{1}{2^2} )[eV]=3.02 eV[/tex]
Since this variation is positive, it means that the system has gained energy, so it must have absorbed a photon.

The energy of photon absorbed is equal to this [tex]\Delta E[/tex]. Converting it into Joule,
[tex]\Delta E=3.02 eV=4.84 \cdot 10^{-19}J[/tex]
The energy of the photon is
[tex]E=hf[/tex]
where h is the Planck constant while f is its frequency. Writing [tex]\Delta E=hf[/tex], we can write the frequency f of the photon:
[tex]f= \frac{\Delta E}{h}= \frac{4.84 \cdot 10^{-19}J}{6.63 \cdot 10^{-34}m^2 kg/s}=7.29 \cdot 10^{14}Hz [/tex]

The photon travels at the speed of light, [tex]c=3 \cdot 10^8 m/s[/tex], so its wavelength is
[tex]\lambda = \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{7.29 \cdot 10^{14}Hz}=4.11 \cdot 10^{-7}m=411 nm [/tex]

So, the initial sentence can be completed as:
The n = 2 to n = 6 transition in the bohr hydrogen atom corresponds to the "absorption" of a photon with a wavelength of "411" nm.
Final answer:

The transition of an electron from n = 2 to n = 6 in a hydrogen atom in the Bohr model involves the absorption of a photon. The wavelength of this photon can be calculated using the Rydberg formula, but a specific value cannot be provided without additional information.

Explanation:

The student's question relates to the Bohr model of the hydrogen atom and specifically to the transition of an electron from the n = 2 energy level to the n = 6 energy level. According to Bohr's model, when an electron in a hydrogen atom transitions between two energy levels, it either absorbs or emits a photon whose energy equals the difference in energy between the two levels.

To find the wavelength of the photon associated with the transition, you can use the Rydberg formula:


   Calculate the energy involved in the transition using the formula
   E = hc/λ where E is the energy of the photon, h is Planck's constant, c is the speed of light, and λ is the wavelength.
   Rearrange to find the wavelength: λ = hc/E.

The exact calculations require substituting the values of h, c, and E (with E determined by the specific energy levels involved in the transition - here from n = 2 to n = 6).

Because this question does not provide all the numerical values needed for the calculation, such as Planck's constant and the speed of light, and does not specify whether the transition represents absorption or emission, we cannot provide a specific value for the wavelength. However, it's important to note that transitions to higher energy levels (n > 2) correspond typically to absorption, and the wavelength would fall into a specific region of the electromagnetic spectrum depending on its energy.

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As the army approached the bridge into the city, the commander told them to break step. He did not want the soldiers to march in cadence. Why did the commander give this order?

Answers

At a definite point, the bridge would begin oscillating to the matching rhythm as that of the marching footsteps. This oscillation would touch a determined peak when the bridge can no longer tolerate its own power and later collapses. So, soldiers are systematic to break their steps while passing a bridge.

Soldiers are ordered to 'route step' across a bridge to prevent forced oscillations and resonance that can lead to structural failure if marching is synchronized.

The reason soldiers are usually ordered to "route step" or walk out of step across a bridge has to do with forced oscillations and resonance. When soldiers march in cadence, their synchronized steps act as a periodic force that can cause the bridge to oscillate at its natural frequency if the cadence matches this frequency. This can amplify the oscillations to dangerous levels, potentially leading to structural failure of the bridge. By breaking step, the soldiers apply random forces to the bridge, which decreases the chances of resonance occurring, thus maintaining the structural integrity of the bridge.

Which of the following puts the MOST demand on water supplies? Question 18 options: A) flood B) overpopulation C) drought D) pollution

Answers

option (b) is correct.

Overpopulation puts the most demand on water supplies.The reservoirs of the water are fixed but the human population is ever increasing. The needs of water for drinking, washing,industrial use like medicines, construction etc are thus increasing with every passing day.So, we are continuously running out of the water supplies. Because of the overpopulation. the pollution of water is also increasing, thus rendering the water unfit for drinking.

Thus overpopulation puts the most demand on water supplies.

Answer:

option (b) overpopulation is the  correct option for this question

Explanation:

Overpopulation is the reason  in increasing demand on water supplies.Overpopulation is a bothersome condition where the quantity of existing human populace surpasses the conveying limit of Earth. Overpopulation is brought about by number of variables. Decreased death rate, better restorative offices, consumption of valuable assets are few of the causes which results in overpopulation. Because of the overpopulation. the pollution of water is also increasing, thus rendering the water unfit for drinking


A bird lands on a bare copper wire carrying a current of 51
a. the wire is 8 gauge, which means that its cross-sectional area is 0.13 cm2. (a) find the difference in potential between the bird's feet, assuming they are separated by a distance of 5.1 cm.

Answers

The resistance of the piece of wire is
[tex]R= \frac{\rho L}{A} [/tex]
where
[tex]\rho = 1.68 \cdot 10^{-8}\Omega m[/tex] is the resistivity of the copper
[tex]L=5.1 cm=0.051 m[/tex] is the length of the piece of wire
[tex]A=0.13 cm^2 = 0.13 \cdot 10^{-4} m^2[/tex] is the cross sectional area of the wire
By substituting these values, we find the value of R:
[tex]R= \frac{\rho L}{A}=6.6 \cdot 10^{-5} \Omega [/tex]

Then, by using Ohm's law, we find the potential difference between the two points of the wire:
[tex]V=IR=(51 A)(6.6 \cdot 10^{-5} \Omega )=3.4 \cdot 10^{-3} V[/tex]

Eddie and Val observed the picture of an athlete running in a race. Eddie stated the picture shows potential energy being transformed to kinetic energy. Val stated that it shows chemical energy being transformed to mechanical energy. Which best explains who is correct?

Only Eddie is correct because the picture does not show a transformation that starts with chemical energy.

Only Eddie is correct because the picture does not show a transformation that ends with mechanical energy.

Both Eddie and Val are correct because chemical energy is a type of potential energy and mechanical energy includes kinetic energy.

Both Eddie and Val are correct because chemical energy is a type of kinetic energy and mechanical energy includes potential energy.


ITS NOT THE LAST ONE I GOT THAT ONE WRONG LAST TIME

Answers

Answer:

"Both Eddie and Val are correct because chemical energy is a type of potential energy and mechanical energy includes kinetic energy."

Explanation:

Answer:

C

Explanation:

now give me brainly please

Which statement best describes the characteristics of white light? A. White light is composed of a spectrum of many different colors. B. White light is composed of radiation with a wide range of amplitudes. C. White light is composed of various wavelengths of light not seen by the naked eye. D. White light is composed of radiation that travels at different speeds producing various colors

Answers

a white light is, by definition, apparently colorless light, for example ordinary daylight. It contains all the wavelengths of the visible spectrum at equal intensity.

so A.

White light is composed of a spectrum of many different colors (Option A).

What is the spectrum?

The spectrum is the variety of colors created when light travels through a glass prism or a drop of water.

White light is a mixture of all the colors of the visible spectrum, which includes red, orange, yellow, green, blue, indigo, and violet. When light passes through a prism, it is separated into its individual colors, creating a rainbow-like effect.

This is because different colors of light have different wavelengths, and a prism bends the light of different wavelengths by different amounts, causing them to spread out and form a spectrum.

So, white light is actually composed of many different colors of light, each with its own unique wavelength.

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The charge within a small volume dv is dq=ρdv. the integral of ρdv over a cylinder of length l is the total charge q=λl within the cylinder. use this fact to to determine the constant ρ0 in terms of λ and r. hint: let dv be a cylindrical shell of length l, radius r, and thickness dr. what is the volume of such a shell?

Answers

The volume of the shell that you described would be:
[tex]dV=2L\pi r dr[/tex]
Now we can rewrite the given integral:
[tex]\lambda L=\int\rho dV=L\rho\int2\pi r dr \\ \lambda L =L\rho \pi r^2\\ \rho=\frac{\lambda}{\pi r^2}[/tex]
I have attached the picture explaining how we got the formula for the volume.
On the picture, I marked the rectangle. You can of this rectangle as the base, and the height would be the circumference of the cylinder.

Answer:

Given

dq=density*dv

q=lamda*I

Taking double integration

density=lamda/2*pi*r^2

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