[tex]A\cap B=\{x:x\in A \wedge x\in B\}[/tex]
[tex]A\cap B=\{2,4\}[/tex]
For this case we have the following sets:
A = {1,2,3,4,5}
B = {2,4}
We must find the intersection of both sets, the symbol ∩ denotes intersection. That is, the numbers in common of both.
We have to:
A∩B = {2,4}
Answer:
The insterseccion of both sets is:
A∩B = {2,4}
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At a grocery store, blueberries come packaged in 8-ounce containers for $2.80 At a farmer's market, blueberries cost $4.20
for 14 ounces. There are 16 ounces in one pound. Which statement accurately compares the cost of blueberries?
$0.30 (farmer's market) < $0.35 (grocery store), the farmer's market offers blueberries at a lower price per ounce.
To compare the cost of blueberries from a grocery store and a farmer's market below:-
Cost of blueberries at the grocery store:
Price for an 8-ounce container: $2.80 Price per ounce = [tex]\frac{2.80}{8} = 0.35[/tex]Cost of blueberries at the farmer's market:
Price for a 14-ounce container: $4.20 Price per ounce = [tex]\frac{4.20}{14} = 0.30[/tex]Thus,
The cost of blueberries at the grocery store is $0.35 per ounce.The cost of blueberries at the farmer's market is $0.30 per ounce.An athletics coach states that the distribution of player run times (in seconds) for a 100-meter dash is normally distributed with a mean equal to 13.00 and a standard deviation equal to 0.2 seconds. What percentage of players on the team run the 100-meter dash in 13.30 seconds or faster? (Round your answer to two decimal places.)
Answer:
6.68%
Step-by-step explanation:
First find the z-score:
z = (x − μ) / σ
z = (13.30 − 13.00) / 0.2
z = 1.50
Look the value up in a z-score table, or use a calculator.
P(z>1.50) = 1 − 0.9332
P(z>1.50) = 0.0668
6.68% of players on the team run the 100 meter dash in 13.30 seconds or faster.
2x2 + 14x- 4 = - x2 + 3x
first, lets solve by factoring:
Let's solve your equation step-by-step.
2x2+14x−4=−x2+3x
Step 1: Subtract -x^2+3x from both sides.
2x2+14x−4−(−x2+3x)=−x2+3x−(−x2+3x)
3x2+11x−4=0
Step 2: Factor left side of equation.
(3x−1)(x+4)=0
Step 3: Set factors equal to 0.
3x−1=0 or x+4=0
x=
1
3
or x=−4
we can also solve using the quadratic formula:
2x2+14x−4=−x2+3x
Step 1: Subtract -x^2+3x from both sides.
2x2+14x−4−(−x2+3x)=−x2+3x−(−x2+3x)
3x2+11x−4=0
Step 2: Use quadratic formula with a=3, b=11, c=-4.
x=
−b±√b2−4ac
2a
x=
−(11)±√(11)2−4(3)(−4)
2(3)
x=
−11±√169
6
x=
1
3
or x=−4
lastly, we can complete the square.
2x2+14x−4=−x2+3x
Step 1: Add x^2 to both sides.
2x2+14x−4+x2=−x2+3x+x2
3x2+14x−4=3x
Step 2: Subtract 3x from both sides.
3x2+14x−4−3x=3x−3x
3x2+11x−4=0
Step 3: Add 4 to both sides.
3x2+11x−4+4=0+4
3x2+11x=4
Step 4: Since the coefficient of 3x^2 is 3, divide both sides by 3.
3x2+11x
3
=
4
3
x2+
11
3
x=
4
3
Step 5: The coefficient of 11/3x is 11/3. Let b=11/3.
Then we need to add (b/2)^2=121/36 to both sides to complete the square.
Add 121/36 to both sides.
x2+
11
3
x+
121
36
=
4
3
+
121
36
x2+
11
3
x+
121
36
=
169
36
Step 6: Factor left side.
(x+
11
6
)2=
169
36
Step 7: Take square root.
x+
11
6
=±√
169
36
Step 8: Add (-11)/6 to both sides.
x+
11
6
+
−11
6
=
−11
6
±√
169
36
x=
−11
6
±√
169
36
x=
1
3
or x=−4
Answer:
x=
1
3
or x=−4
Final answer:
The equation [tex]2x^2 + 14x - 4 = -x^2 + 3x[/tex] is a quadratic equation, which can be solved by standard methods such as factoring, completing the square, or applying the quadratic formula and then validated by substituting the solutions back into the original equation.
Explanation:
To solve the quadratic equation, [tex]2x^2 + 14x - 4 = -x^2 + 3x[/tex], first combine like terms by getting all terms on one side of the equation, resulting in [tex]3x^2 + 11x - 4[/tex] = 0. This is a standardized quadratic equation [tex]ax^2[/tex] + bx + c = 0. To find the solutions for this equation, you can either factorize it, complete the square or use the quadratic formula, (-b ± √([tex]b^2[/tex] - 4ac)) / (2a). After finding the roots (values for x), verify them by plugging them back into the original equation to ensure they satisfy it.
Solve and graph the absolute value inequality: |2x + 4| > 14.
number line with open circles on negative 9 and 5, shading going in the opposite directions.
number line with open circles on negative 9 and 5, shading in between.
number line with closed circles on negative 9 and 5, shading going in the opposite directions.
a number line with open circles on negative 5 and 5, shading going in the opposite directions.
Answer:
"number line with open circles on negative 9 and 5, shading going in the opposite directions."
Step-by-step explanation:
Your inequality doesn't include an equal sign so there will be no closed holes. It will only be open holes.
|u|>14 means that the number u has to be greater than 14 or less than -14. These numbers I describe just now all have a distance greater than 14 from 0.
So |u|>14 implies u>14 or u<-14.
But we are solving |2x+4|>14 so this implies we have 2x+4>14 or 2x+4<-14.
2x+4>14
Subtract 4 on both sides:
2x >10
Divide both sides by 2:
x >5
2x+4<-14
Subtract 4 on both sides:
2x <-18
Divide both sides by 2:
x <-9
So our solution is x>5 or x<-9.
Graphing!
~~~~~~~O O~~~~~~~~
-----------(-9)---------------------------------(5)---------------
So we shaded to the right of 5 because our inequality says x is bigger than 5.
We shaded to the left of -9 because our inequality says x is less than -9.
Which simplifications of the powers of i are correct? There may be more than one correct answer. Select all correct answers.
A) i^6=1
B) i^18=1
C) i^7=-i
D) i^16=1
Answer:
Option C and D are correct options
Step-by-step explanation:
The correct options are C and D.
We know that i = √-1
i² = -1
i³ = -i
and i^4 = 1
Lets solve the options one by one:
i^6 =1
Break the power:
i² *i ² * i² = (-1)(-1)(-1)
= -1
Therefore A is wrong
B) i^18 = 1
Lets break the power:
i²* i² *i² *i²*i²*i²*i²*i²*i²
put the value of i^2
= (-1) (-1) (-1) (-1) (-1) (-1) (-1) (-1)(-1)
= -1
Therefore option B is incorrect.
C) i^7 = -i
= i² * i² *i² *i
=(-1) (-1) (-1) * √-1
= - √-1
We know that √-1 = i
So,
- √-1 = -i
Therefore option C is correct.
D) i^16 = 1
= i² * i² * i² * i² * i² * i² *i² *i²
= (-1) (-1) (-1) (-1) (-1) (-1) (-1) (-1)
= 1
Therefore option D is correct.
Thus option C and D are correct option....
Answer: Option C and Option D
Step-by-step explanation:
Remember that by definition we have to:
[tex]i=\sqrt{-1}[/tex] and [tex]i^2=-1[/tex]
So for the option A we have to:
[tex]i^6=(\sqrt{-1})^2*(\sqrt{-1})^4\\\\i^6=-1*(-1)^2\\\\i^6=-1[/tex]
Option A is false
So for the option B we have to:
[tex]i^{18}=(i^6)^3[/tex]
We know that [tex]i^6=-1[/tex]
So
[tex]i^{18}=(-1)^3[/tex]
[tex]i^{18}=-1[/tex]
Option B is false
So for the option C we have to:
[tex]i^7=(i)^6*i^1[/tex]
[tex]i^7=-i[/tex]
Option C is true
Finally for the option D we have to:
[tex]i^{16}=(i^4)^4[/tex]
[tex]i^{16}=((-1)^2)^4[/tex]
[tex]i^{16}=(1)^4[/tex]
[tex]i^{16}=1[/tex]
Option D is true
p (a) =0.60, p(b) = 0.25, and p(a and b) =0.15 what is p(a or b) ?
a.) 0.40
b.) 0.85
c.) 0.70
d.) 0.75
Answer:
C is the correct option
Step-by-step explanation:
To find the probability of P(a or b) we will use the formula:
P(a or b)= P(a)+ P(b) - P(a-b)
Now put the given values in the formula:
P(a or b)= 0.60+0.25-0.15
P(a or b)=0.85 - 0.15
P(a or b)= 0.70
Thus the correct option is C....
Answer: Option C
[tex]P (A\ or\ B) = 0.70[/tex]
Step-by-step explanation:
If A and B are events that are not mutually exciting, then it is true that:
[tex]P (A\ or\ B) = P (A) + P (B) - P (A\ and\ B)[/tex]
In this case we know [tex]P(A)[/tex], [tex]P(B)[/tex] and we also know [tex]P (A\ and\ B)[/tex]
[tex]P(A)=0.60[/tex]
[tex]P(B) = 0.25[/tex]
[tex]P(A\ and\ B)=0.15[/tex]
Therefore we have that:
[tex]P (A\ or\ B) = 0.60 + 0.25 - 0.15[/tex]
[tex]P (A\ or\ B) = 0.60 + 0.1[/tex]
[tex]P (A\ or\ B) = 0.70[/tex]
Which of the following inequalities matches the graph?
[tex]x > - 3[/tex]
[tex]x < - 3[/tex]
[tex]y > - 3[/tex]
[tex]y < - 3[/tex]
which one is it 1,2,3,or 4 one
Answer:
y < -3Step-by-step explanation:
<, > - dotted line
≤, ≥ - solid line
x ≤ a or x < a - the region below the horizontal line x = a
x ≥ a or x > a - the region above the horizontal line x = a
y ≤ a or y < a - the region on the left side of the vertical line y = a
y ≥ a or y > a - the region to the right of the vertical line y = a
=========================================
We have dotted line (<, >).
The vertical line (y).
The region on the left side of the vertical dotted line y = -3
Which of the following polynomials has a remainder of -11 when divided by x+1? A. −2x3+4x2+3x−2 B. 3x3+6x−2 C. x3−2x2−4x+1 D. 4x3+2x2+5
Answer:
B. 3x3+6x−2
Step-by-step explanation:
When you divide 3x3+6x−2 by x+1 we get a remainder of -11.
6 friends are going to sit together in a rollercoaster that has 6 seats. In how many different arrangements can they sit?
Answer:
36
Step-by-step explanation:
I think it may be 36. I did 6×6, but I'm not fully positive
There are 720 different arrangements in which the 6 friends can sit in the 6 seats of the rollercoaster.
To calculate the number of different arrangements in which the 6 friends can sit in the 6 seats of the rollercoaster, we can use the concept of permutations.
Since each friend occupies one seat and no two friends can occupy the same seat, we have 6 choices for the first seat, 5 choices for the second seat, 4 choices for the third seat, and so on until 1 choice for the last seat.
So, the total number of arrangements is the product of these choices:
[tex]\[ 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 720 \][/tex]
given sin theta = -3/5 and csc theta -5/3 in quadrant 3, find the value of other trigonometric functions using a Pythagorean Identity. Show your work.
Answer:
cos theta = -4/5.
sec theta = -5/4.
tan theta = 3/4.
cot theta = 4/3.
Step-by-step explanation:
sin^2 theta + cos^2 theta = 1
(-3/5)^2 + cos^2 theta = 1
cos^2 theta = 1 - 9/25
cos^2 theta = 16/25
cos theta = -4/5 (negative because it is in Quadrant 3).
sec theta = 1 / cos theta = -5/4.
tan theta = sin theta / cos theta = -3/5 / - 4/5
= -3/5 * -5/4
= 3/4.
cot theta = 1 / tan theta = 4/3.
The other trigonometric functions can be found using the Pythagorean Identity and the definitions of the trigonometric functions. The values are cos theta = -4/5, tan theta = 3/4, csc theta = -5/3, sec theta = -5/4, and cot theta = 4/3.
Explanation:The given values are sin theta = -3/5 and cos theta = -5/3, which are located in quadrant 3. In this quadrant, sine and cosine are both negative. To find the values of the other trigonometric functions, we will use the Pythagorean Identity and the definitions of the trigonometric functions.
We can find cosine through the Pythagorean Identity, sin² theta + cos² theta = 1. Solving for cos theta, we get cos theta = sqrt(1 - sin² theta) = sqrt(1 - (-3/5)²) = -4/5. Note the negative sign since we are in quadrant 3.
Next, we can find tan theta = sin theta/cos theta = (-3/5) / (-4/5) = 3/4.
For the reciprocal functions, we have csc theta = 1/sin theta = -5/3, sec theta = 1/cos theta = -5/4, and cot theta = 1/tan theta = 4/3.
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Plz help!!!!!!!!!
Pre-calulus
Answer:
1
Step-by-step explanation:
We are to find the value of the following:
[tex] log _ 3 5 \times log _ { 2 5 } 9 [/tex]
[tex] \log _ { 3 } 5 \times \log _ { 2 5 } 9 =\dfrac{1}{\log_{5}3}\times\log_{25}9=\dfrac{1}{\log_{5}3}\times\log_{5^2}9=\dfrac{1}{\log_{5}3}\times\dfrac{1}{2}\log_{5}9[/tex]
[tex] \dfrac { 1 } { \log _ { 5 } 3 } \times \dfrac { 1 } { 2 } \log_ { 5 } 9 = \dfrac{1}{\log_{5}3}\cdot\dfrac{1}{2}\log_{5}3^2=\dfrac{1}{\log_{5}3}\cdot\dfrac{2}{2}\log_{5}3=\dfrac{1}{\log_{5}3}\cdot\log_{5}3=\dfrac{\log_{5}3}{\log_{5}3}=[/tex] 1
Answer:
The value is: 1
Step-by-step explanation:
Use the Change of base formula. This is:
[tex]log_a(x)=\frac{log_b(x)}{log_b(a)}[/tex]
Using base 10:
[tex]log_3(5)*log_{25}(9)=\frac{log(5)}{log(3)}*\frac{log(9)}{log(25)}[/tex]
We know that:
[tex]9=3^2\\25=5^2[/tex]
And according to the logarithms properties:
[tex]log(x)^n=nlog(x)[/tex]
Then, we can simplify the expression:
[tex]=\frac{log(5)}{log(3)}*\frac{log(3)^2}{log(5)^2}=\frac{log(5)}{log(3)}*\frac{2log(3)}{2log(5)}=\frac{log(5)}{log(3)}*\frac{log(3)}{log(5)}=\frac{log(5)*log(3)}{log(3)*log(5)}=1[/tex]
2. Find the distance between -18 and 8
using the ruler postulate.
Step-by-step explanation:
1 1-5 Measuring Segments Find the distance between two points using the Ruler Postulate Determine the length of a segment using the Segment Addition Postulate.
Answer:
26.
Step-by-step explanation:
We are asked to find the distance between -18 and 8 using the ruler postulate.
The ruler postulate states that the distance between two pints on a ruler is the absolute value of the difference between the numbers shown on ruler.
So the distance between -18 and 8 would be [tex]|-18-8|=|-26|=26[/tex].
Therefore, the distance between -18 and 8 is 26.
based only on the information given in the diagram which congruence theorems or postulates could be given as reason why ABC=DEF
Answer:
HL
SAS
SSS
Step-by-step explanation:
Since these are right triangles, and you have the two hypotenuses are congruent to each other and two legs that are also congruent to each other, then HL can be applied.
For HA to work we must have been given something else about one of those angle (besides the 90 degree one).
Since you have two corresponding sides that are congruent, then the 90 degree angles in both are congruent, and then the sides right after that 90 degree angle are also congruent to each other, so SAS can be applied.
We can't use AAS. We only know something about one angle per each triangle due to the markers.
LA? Needed another angle besides the 90 degree one.
All three corresponding sides are congruent. The markers tell us this. So we can apply SSS.
Answer:
HL
SAS
SSS
Step-by-step explanation:
complete the point slope equation of the line through(-1,-10)and(5,2).
y-6=
Answer:
y - 6 = 2(x - 7)Step-by-step explanation:
The point-slope of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the poinys (-1, -10) and (5, 2). Substitute:
[tex]m=\dfrac{2-(-10)}{5-(-1)}=\dfrac{12}{6}=2[/tex]
Put the value of the slope and the coordinateso f the point (5, 2), to the equation of a line:
[tex]y-2=2(x-5)[/tex]
In the question we have y - 6 = ...
Therefore
[tex]y-2=2(x-5)[/tex] subtract 4 from both sides
[tex]y-6=2(x-5)-4[/tex] use the distributive property
[tex]y-6=2x-10-4[/tex]
[tex]y-6=2x-14[/tex] distributive
[tex]y-6=2(x-7)[/tex]
solve the equation -9x+1=-x+17
Answer:
x=-2
Step-by-step explanation:
-9x+1=-x+17
Add 9x on both sides:
1=8x+17
Subtract 17 on both sides:
-16=8x
Divide both sides by 8:
-2=x
Check x=-2!
-9x+1=-x+17 with x=-2
-9(-2)+1=-(-2)+17
18+1=2+17
19=19
19=19 is a true equation so x=-2 is correct.
Answer: b
Step-by-step explanation:
There are 200 counters in a bag.
50 of them are taken out and have a dab of white paint placed on them.
These 50 marked counters are now put back in the bag which is given
a good shake to ensure even distribution of the marked counters.
80 counters are now taken out of the bag.
About how many of them would you expect to be marked with a
dab of white paint?
Out of those 80 counters, 20 counters may have a white dab on them.
Given to usTotal number of counters in the bag = 200
counters that have a white dab = 50
counters that are now taken out of the bag = 80
Let's first take the ratio of counters that have a white dab to the total number of counters in the bag.
The ratio of bag[tex]\rm{=\dfrac{counters\ that\ have\ a\ white\ dab}{Total\ number\ of\ counters\ in\ the\ bag}[/tex]
[tex]=\dfrac{50}{200} = \dfrac{1}{4} = 0.25[/tex]
Therefore, the ratio of counters that have a white dab to the total number of counters in the bag is 0.25.
80 countersAs the bag is given a good shake to ensure even distribution of the marked counters.
Those 80 counters will follow the same ratio of the bag, so, the number of tokens with white dab will be,
Number of tokens taken out x ratio of the bag
= 80 x 0.25
= 20
Hence, out of those 80 counters, 20 counters may have a white dab on them.
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How do you graph this and know if it is continuous or not?
Answer:
Continuous because there are no breaks.
The graph is included as an attachment.
Step-by-step explanation:
Alright we want to graph:
y=x-4 for x<2
y=-2x+2 for x=2 or x>2
So let's graph the first piece y=x-4 for x<2.
I'm going to plug in 2 for x: y=2-4=-2. So this one line is going to contain an open circle at (2,-2). I say open circle because we did not have that we could actually include x=2 here because it says for x less than 2.
Now we are going to enter in one more number less than 2....your choice.
Let's go with x=0. When you plug in 0 for x into y=x-4 you get y=0-4=-4. So our line is going to include (0,-4).
So we are going to graph the points (0,-4) and (2,-2) again where (2,-2) is an open circle. Connect these points. You may extend your line left because we have x<2, but do not extend it right of x=2.
Let's look at the other piece now: y=-2x+2 for x=2 or x>2.
I'm going to plug in 2 for x: y=-2(2)+2=-4+2=-2 so we are going to include the point (2,-2) on our line. This was actually a point we used from above that we didn't want to include. We do now want to include because of the x=2 in our inequality so the dot can now be filled in. We need one more point to graph this line. Let's plug in a number greater than 2 since our inequality say x=2 or x>2. You choose. How about x=3?
y=-2(3)+2=-6+2=-3. So we are going to include the point (3,-3). So starting at (2,-2) and going right to connect it to (3,-3), you could extend passed the (3,-3) to the right.
I will show you my graph.
There are no breaks in the "curve", so it is continuous for all real numbers.
Figure ABCD is transformed to figure , as shown: Which of the following sequences of transformations is used to obtain figure from figure A'B'C'D?
You need a picture deficiencies did that for 20 characters
how do you calculate this
Answer:
Step-by-step explanation:
Josh has to drive at least 6 hours. d≥ 6 Answer 2
Amelia walking 35 min or less b ≤ 35 Answer 3
Nancy < 35 hours = part time y < 35 Answer 1
Sarah at least 6 hours math f > 6 Answer 4
write the equation of the lines that passes through the points (-3, -2) and (0, -3)
Answer:
[tex]-\frac{1}{3}[/tex]
Step-by-step explanation:
To find the slope of a line using two points, employ the use of the slope formula.
[tex]\frac{y_{2}-y_{1}}{x_{2}- x_{1}}[/tex]
Your y1 term is -2, your y2 term is -3.
Your x1 term is -3, your x2 term is 0.
[tex]\frac{-3-(-2)}{0-(-3)} \\\\\\\frac{-3+2}{0+3} \\\\\frac{-1}{3} \\[/tex]
Identify the mapping diagram that represents the relation and determine whether the relation is a function. {(–3, –6), (–1, –6), (5, –6), (8, –6)} Which of the following is true?
Answer:
This relation is a function.
Step-by-step explanation:
A function is a process or a relation that associates each element x of a set X, to a single element y of another set Y.
We have
{(-3, -6), (-1, -6), (5, -6), (8, -6)}
x = -3 → y = -6
x = -1 → y = -6
x = 5 → y = -6
x = 8 → y = -6
YES. This relation is a function.
/each x has one value of y/
Answer: Yes, it is a function
Step-by-step explanation:
need help with 1-5 , please!!!!!!
Answer:
1)
[tex] \frac{26 + 16 + 11 + 13 + 24}{5} = \frac{90}{5} = 18[/tex]
2)
[tex] \frac{51 + 20 + 32 + 18 + 45 + 8}{6} = \frac{174}{6} = 29[/tex]
3)
[tex] \frac{17 + 39 + 15 + 42 + 37 + 61 + 19 + 40}{8} = \frac{270}{8} = 33.75[/tex]
4)
[tex] \frac{62 + 21 + 18}{3} = \frac{101}{3} = 33.67[/tex]
5)
[tex] \frac{9.2+8.6+9.4+9.2}{4} = \frac{36.4}{4} = 9.1[/tex]
Which statements are always true regarding the diagram?
Select three option. (Picture included)
m<5+m<3=m<4
m<3+m<4+m<5=180
m<5+m<6=180
m<2+m<3=m<6
m<2+m<3+m<5=180
Answer:
m∠5+m∠6=180°
m∠2+m∠3=m∠6
m∠2+m∠3+m∠5=180°
Step-by-step explanation:
Verify each option
case A) we have
m∠5+m∠3=m∠4 ----> equation A
we know that
m∠3+m∠4=180° -----> by supplementary angles
m∠4=180°-m∠3 ----> equation B
substitute equation B in equation A
m∠5+m∠3=180°-m∠3
m∠5+m∠3+m∠3=180°
This equation is true when m∠2=m∠3
therefore
Is not always true
case B) we have
m∠3+m∠4+m∠5=180° ----> equation A
we know that
m∠3+m∠4=180° -----> by supplementary angles
m∠4=180°-m∠3 ----> equation B
substitute equation B in equation A
m∠3+(180°-m∠3)+m∠5=180°
m∠5=0°
This option is not true
case C) we have
m∠5+m∠6=180°
we know that
m∠5 and +m∠6 are supplementary angles
so
Their sum is always 180 degrees
therefore
This option is always true
case D) we have
m∠2+m∠3=m∠6 -----> equation A
we know that
m∠5+m∠6=180° ----> by supplementary angles
m∠6=180°-m∠5 ----> equation B
substitute equation B in equation A
m∠2+m∠3=180°-m∠5
m∠2+m∠3+m∠5=180°
Remember that the sum of the interior angles of a triangle must be equal 180 degrees
therefore
This option is always true
case E) we have
m∠2+m∠3+m∠5=180°
Remember that the sum of the interior angles of a triangle must be equal 180 degrees
therefore
This option is always true
Answer:
CDE
Step-by-step explanation:
Please help I’m stuck!
Answer:
1. the value of x can equal 25
the shortest length can equal 7
the longest length can equal 30
2. 2x+2.1=7.5
Step-by-step explanation:
Given:
1.
A scalene triangle with sides y, 4y and x
and perimeter,p= 60cm
As per perimeter formula:
p= sum of all sides
Putting values we get
60=x+4y+y
60=x+5y
so correct options are
the value of x can equal 25
the shortest length can equal 7
the longest length can equal 30
2. An isosceles triangle with sides y=2.1, x and x
and perimeter,p = 7.5
As per perimeter formula:
p= sum of all sides
Putting values we get
7.5=2.1 + x +x
7.1=2.1+2x !
Which algebraic expression has a term with a coefficient of 3?
A. 3y+1
B. -2y + 5+ 3
C. 5y-7
D. 3(y-6)
The algebraic expression 3y+1 has a term with a coefficient of 3.
What is a coefficient?A coefficient is a constant value accompanying a variable that is multiplied by it. For example, 2 is the coefficient of x in 2x.
We can find the algebraic expression as shown below:We can evaluate the given options.
In Option A, we have 3y+1. Here the expression has a term with a coefficient of 3.
In Option B, we have -2y + 5+ 3. Here the expression does not have a term with a coefficient of 3.
In Option C, we have 5y-7. Here the expression does not have a term with a coefficient of 3.
In Option D, we have 3(y-6). Here the expression does not have a term with a coefficient of 3.
Therefore, we have found that the algebraic expression 3y+1 has a term with a coefficient of 3.
Learn more about coefficients here: https://brainly.com/question/3189867
#SPJ2
Look at the diagram below. If JM = LM, then angles JKM are congruent.- From Apex
True or False
Answer:
The answer to this question is True
Answer: true
Step-by-step explanation:
I really need help with this
Answer:
[tex]\frac{1}{x^2y^6}[/tex]
Step-by-step explanation:
We are given [tex](xy^3)^2 \cdot (xy^3)^{-4}[/tex]
First rule I'm going to use is [tex](m^rn^p)^s=m^{r \cdot s}n^{p \cdot s}[/tex].
This gives us:
[tex](xy^3)^2 \cdot (xy^3)^{-4}[/tex] is
[tex](x^2y^6) \cdot (x^{-4}y^{-12})[/tex].
Now pair up the bases that are the same:
[tex](x^2x^{-4}) \cdot (y^6y^{-12})[/tex].
Add the exponents when multiplying if the bases are the same:
[tex]x^{-2} \cdot y^{-6}[/tex]
Now usually teachers don't like negative exponents.
To get rid of the negative exponents just take the reciprocal:
[tex]\frac{1}{x^2} \cdot \frac{1}{y^6}[/tex]
[tex]\frac{1}{x^2y^6}[/tex]
Suppose that you want to design a cylinder with the same volume as a given cylinder, but you want to use a different radius and height. In general
terms, how can you changer and h to produce the same wolume for both cylinders?
volume of a cylinder = pi×r^2×h
Answer:
I can increase r and decrease h, or I can decrease r and increase h.
Step-by-step explanation:
answer given in edmentum
The tax on a property with an assessed value of $67,000 is $975. Using a proportion, find the tax on a property with an assessed value of $96,000
Answer:
1,440
Step-by-step explanation:
1.5 percent of 96k
Solve: ^3 sqrt x^2-8=2
Answer:
∛x²-8 = 2
-2∛x² = 2
∛x² = 2+2
x² = 4³
x = √64
x = 8
Answer:
C. x = –4 or x = 4
Step-by-step explanation:
B. s = 7 (for the second one)