Answer:
Number of species and their relative abundances in the community over multiple years
Explanation:
Community stability measures the rate of increase or decrease of species in an environment over a period of time.
When studies are made and the species are in a low quantity then we refer to such species as being unstable and potentially becoming extinct whereas if there is a rise or uniform amount of species then stability is attained.
You have made random-sequence synthetic RNA molecules that contains only A and G, and which contain 5 times as much A as G. You use these RNAs to perform in vitro translation. How many different amino acids would you expect to find in the resulting polypeptides? And at what frequency would you expect to find Glutamic acid (Glu) in the resulting polypeptides?
The resulting polypeptide will contains Glycine, arginine ,lysine , and glutamic acid. The probabilities to form a glutamic acid in the coding sequence is 2/9 for each codon.
Genetic code:
It is a three letter code of base pairs in the nucleic acid that code for an specific amino acid.
Here, mRNA is made up of only A and G. Nine code are possible in a mRNA sequence that contains only A and G.
GGC, GGA and GGG code for Glycine. AGA and AGG code for Arginine.AAA and AAG code for Lysine.GAA and GAG code for Glutamic acid.
Therefore, the resulting polypeptide will contains Glycine, arginine ,lysine , and glutamic acid. The probabilities to form a glutamic acid in the coding sequence is 2/9 for each codon.
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Final answer:
In the resulting polypeptides from the random-sequence synthetic RNA molecules, we can expect to find a variety of amino acids. The number of different amino acids will depend on the specific codons present in the RNA. The frequency of Glutamic acid (Glu) will be higher due to the higher frequency of the codon GAA.
Explanation:
In this case, we have made random-sequence synthetic RNA molecules that contain only A and G, with 5 times as much A as G. In terms of translating these RNAs into polypeptides, we can expect to find a variety of amino acids in the resulting polypeptides. However, the frequency of each amino acid will depend on the specific codons that are present in the RNA.
Since there are 61 codons that specify the addition of an amino acid to the polypeptide chain and 3 codons that specify termination, we can expect to find a maximum of 61 different amino acids in the resulting polypeptides. However, it is important to note that some of these codons may code for the same amino acid, so the actual number of different amino acids may be lower.
As for the frequency of Glutamic acid (Glu) in the resulting polypeptides, it will depend on the specific codons present in the RNA. Glutamic acid is encoded by the codons GAA and GAG. Since we have made random-sequence RNA molecules with 5 times as much A as G, we can expect a higher frequency of the codon GAA, and thus a higher frequency of Glutamic acid in the resulting polypeptides.
how do you classify organisms as eukaryotes?
Answer:
A eukaryote is an organism with complex cells, or a single cell with a complex structures. In these cells the genetic material is organized into chromosomes in the cell nucleus. Animals, plants, algae and fungi are all eukaryotes. There are also eukaryotes amongst single-celled protists.
Answer: Eukaryotic cells contain membrane-bound organelles, such as the nucleus, while prokaryotic cells do not
Explanation: so if cells contain membrane-bound organelles in the organism then their classified as eukaryotes
RNA polymerase from E. coli does not function at 0ºC, whereas in vitro experiments determined that RNA polymerase from Pseudomonas syringae strain Lz4W functions at about 10%–15% of its optimum, which is 37ºC. Which of the following best explains the difference?
Answer:
Since there is no distinction in the measure of the RNA polymerases yet rather their movement, the distinction lies in their structure and not their grouping. Adjustments are made to widen the states of endurance. Thus E. coli would not constrain it's endurance by restricting its development to hotter temperatures. Thus the appropriate response is "the RNA polymerase sub-units of the P. syringe strain most likely have additional adaptability with the goal that they can move all the more openly in colder temperatures".
Which of the following statements about the anatomy of a mollusk are correct?
a. Gills are used for respiration.
b. Mollusks have a radula for grinding food.
c. The digestive system includes a gizzard, a stomach, a digestive gland, and the intestine.
d. The tissue beneath the shell is called the mantle.
The anatomy of mollusks can be stated by the presence of gills, which have gradual for grinding food and tissues beneath the shells are called a mantel.
What is a mollusk?A mollusk is an invertebrate organism and there exist about 85,000 extant species and a number of fossils range from 60,000 to 100,000. They represent the largest marine phylum and consist of 235 of the species.
The mollusks are the organism that has a soft body and the outer body has an exoskeleton that is hard.
Find out more information about the mollusk.
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While most statements about the anatomy of a mollusk are correct, the assertion that all mollusks' digestive systems include a gizzard is less accurate. Mollusks typically feature gills for respiration, a radula for grinding food, and a mantle beneath the shell, but a gizzard is not universal among them. Hence, the correct options are a, b and d.
The anatomy of a mollusk is quite complex and diverse across the different species within the phylum. However, looking at the common characteristics shared among most mollusks, we can address the statements provided:
Gills are indeed used for respiration, especially in aquatic mollusks. They allow for the exchange of gases between the mollusk's blood and the surrounding water.Most mollusks have a radula for grinding or scraping food. This unique structure functions somewhat like a tongue covered in tiny teeth and is not found in any other group of animals.The mantle is the tissue beneath the shell in many mollusks, playing a crucial role in shell secretion and protection of the mollusk’s soft body.Concerning the digestive system, it is accurate that it typically includes a stomach, a digestive gland (which aids in digestion and absorption), and the intestine. However, not all mollusks have a gizzard. This part of the statement can be misleading as gizzards are more common in birds for grinding food and might be present in some mollusks for the same purpose, but it's not a universal feature of the phylum.Largest planet in our Solar system with faint rings.
A.Saturn
B.Jupiter
C.Venus
D.Neptune
Answer: Jupiter
Explanation: No explanation.
Answer:
Jupiter
explanation:
Jupiter is the 5th planet in our Solar system and is the largest planet in the Solar System. Jupiter has a narrow and faint ring. Jupiter's rings are dark and are made up of dust and tiny pieces of rock. So The largest planet with faint rings in our Solar System is the planet Jupiter.
During ____, homologous chromosomes pair up forming tetrads.
Answer: meiosis
Explanation:
Los Angeles has a serious problem with smog, particularly photochemical smog. All of these EXCEPT which contributes to the excessive smog in the Los Angeles area?
Answer:
A) Longitude of the city
Explanation:
An ecosystem generally requires solar energy, nutrients, decomposers, consumers and ____. Select one: a. conformers b. decontaminators c. directors d. producers e. concentrators
Answer:
Producers
Explanation:
They are the food for the consumers.
Answer:
D. Producers
Explanation:
They are an important link in the ecosystem. They produce food by photosynthetic processes through the help of soil nutrients, sunlight(solar energy) and Carbon dioxide.
The food they produce are eaten by the consumers such as animals and other small organisms. The animals/ organisms also serve as food for larger animals(carnivores)e.g lion, whale, tiger and omnivores e.g. Man
What is the first stage of protein synthesis?
a. the assembly of transcription factors at the promoter elongation, in which amino acids are joined to the polypeptide chain
b. setting the reading frame, where the initiation codon is recognized by RNA polymerase
c. tRNA charging, in which the tRNAs bind to amino acids initiation, in which the components necessary for translation are assembled at the ribosome
Answer:
Option C.
tRNA charging, in which the tRNAs bind to amino acids initiation, in which the components necessary for translation are assembled at the ribosome.
Explanation:
During the transcription phase of protein synthesis, before an amino acid can even be incorporated into a growing polypeptide, it must first be attached to a molecule called the transfer RNA (tRNA). This process is known as tRNA charging.
After this, the charged RNA can now carry the activated amino acid to the ribosome, where the protein synthesis can now take place.
The tRNA charging process is the first stage in protein synthesis
Answer:
b. setting the reading frame, where the initiation codon is recognized by RNA polymerase.
Explanation:
The first step in protein synthesis is called transcription. Transcription is the process wherein DNA is used to create messenger RNA, or mRNA. The mRNA is produced using DNA's code, which is contained within the cell's nucleus. The steps include:
RNA polymerase, together with one or more general transcription factors, binds to promoter DNA. RNA polymerase creates a transcription bubble, which separates the two strands of the DNA helix. This is done by breaking the hydrogen bonds between complementary DNA nucleotides.
RNA polymerase adds RNA nucleotides (which are complementary to the nucleotides of one DNA strand).
RNA sugar-phosphate backbone forms with assistance from RNA polymerase to form an RNA strand.
Hydrogen bonds of the RNA–DNA helix break, freeing the newly synthesized RNA strand. The RNA may remain in the nucleus or exit to the cytoplasm through the nuclear pore complex.
2 Points
Humans have become dominant in the last ____
_ years.
O
A. 65 million
O
B. 1.8 billion
O
C. 1 million
O
D. 2,000
€ PREVIOUS
Did you mean 200,000?
Explanation:
Humans have domimated the planet for the last 200,000 years.
Answer: 1 million
Explanation: 200,000 is wrong!!
Fermentation has a relatively low ATP yield compared to aerobic respiration because a. more reducing equivalents are used for anaerobic catabolism. b. less ATP is consumed during the first stage of aerobic catabolism. c. oxidative phosphorylation yields a lot of ATP. d. substrate-level phosphorylation yields a lot of ATP.
Answer:
c. Oxidative phosphorylation yields a lot of ATP
Explanation:
Fermentation is an anaerobic process that takes place in the anaerobic bacteria to produce an energy molecule called ATP. The process of fermentation involves the breakdown of the glucose through glycolysis which produces 2 ATP molecules, NADH and Pyruvate molecules.
The process does not undergo further steps like the Citric acid cycle and the oxidative phosphorylation which forms the high number of ATP molecules. Since the organism which performs the fermentation does not undergo oxidative phosphorylation therefore the yield of ATP in the cell is very less.
Thus, Option-C is correct.
The allele for tay-sachs is a recessive allele that causes death in early childhood. The tay-sachs' prgram has enabled Tim McGraw to determine that he is a carrier and that his wife is not. What are the chances they could have a child with Tay-Sachs?
Answer:
There are no chances for this couple to have a child with Tay-Sachs disease. 0% of the possibilities.
Explanation:
Tay-Sachs disease affects the nervous system and is potentially mortal. It is transmitted from parents to progeny. Tay-Sachs is caused by a defective gene in the 15 chromosome.
The child that recesives two coppies of this defective gene, one from the mother and one from the father, results sick. But if only one of the parents transmits the gene, then the child will be a carrier. This child won't be sick but will transmit the gene to his/her own progeny.
Available data:
The allele for tay-sachs is a recessive allele, "t" Tim McGraw to determine is a carrier, TtTim´s wife is not a carrier, TTCross:
Parental) TT x Tt
Gametes) T T T t
Punnet square) T T
T TT TT
t Tt Tt
F1) Progeny genotype: 2/4= 1/2 normal, TT
2/4= 1/2 Carrier, Tt
0/4= 0 Sick, tt
What are the chances they could have a child with Tay-Sachs?
There are 0% of the possibilities that this family will get a sick child.
Answer:
The chances they would have a child with Tay-sach's is zero
Explanation:
Since Tim McGraw is a carrier; possessing just one copy of the recessive allele and the normal copy being dominant and his wife is neither a carrier nor a tay-sach's, there is zero percent chance of producing a child with Tay-sach's. This is because the condition is expressed when an individual has two copies of the recessive allele.
The gene for petal color in a flower has incomplete dominance, so that individuals with two A1 alleles (A1A1) are black, individuals with two A2 alleles (A2A2) are white, and individuals with one of each allele (A1A2) are mottled. In a cross between two black flowers, what is the probability of getting a mottled offspring? (2
Answer:
The probability of getting a mottled offspring is 0%. There is no A2 allele involved in the cross.
Explanation:
Available data:
The gene for petal color in a flower has incomplete dominance Two A1 alleles (A1A1) express black colorTwo A2 alleles (A2A2) express white color One of each allele (A1A2) express mottled colorIn a cross between two black flowers, there is no allele A2, there are just two alleles A1. So, the cross is:
Parental) A1A1 x A1A1
Gametes) A1 A1 A1 A1
Punnet Square) A1 A1
A1 A1A1 A1A1
A1 A1A1 A1A1
F1 Phenotypes: 100% black flowers
F1 Genotype: 100% A1A1
There are 0% of probabilities of getting a mottled offspring.
Answer:
The probability is 0%.
Explanation:
We know that an individual with two A1 alleles (A1A1) are black, so if two black flowers are crossed that means two flowers with A1 (black)alleles, as these flowers do not have any A2 allele to give a mottled flower, the only type of flower that will come out from this cross is a black one.
We can see this with a Punnett square.
║A1 ║ A1
A1║ A1A1 ║ A1A1
A1║ A1A1 ║ A1A1
A batch culture of E. coli was initiated with a medium containing 10 g/L of glucose, 2 g/L of ammonia, and 0.1 g/L of cells. At the end of culture, 0.1 g/L of glucose remained in the medium. A total of 5.1 g/L of E. coli were recovered. The elemental composition of the cells was determined to be (by mass) 53% C, 7.3% H, 12.0% N, and 19.0% O, with the remaining balance being ashes.
a) Calculate the yield (by mass) of biomass based on glucose and nitrogen.
b) Write down the stoichiometric equation for biomass formation from glucose and ammonia.
c) Assume all the carbon that was not incorporated into biomass was used for energy generation and was completely oxidized to carbon dioxide. Also, assume that each mole of glucose produces 38 moles of ATP when completely oxidized to carbon dioxide. Calculate the biomass yield coefficient based on ATP.
Answer:
c
Explanation:
Use the template of a replication fork to draw arrows that represent both continuous and discontinuous DNADNA synthesis. Draw one long arrow to show continuous DNADNA synthesis and three arrows to show discontinuous DNADNA synthesis. The arrows should point in the direction of nucleotide addition, and the three arrows showing discontinuous synthesis should be numbered 1, 2, and 3, in the order of fragment synthesis.
The replication fork is the structure formed during the DNA replication. The fork is created by the enzymes, which break the hydrogen bonds between nitrogenous base pairs.
DNA replication is a vital process in which genetic information is copied from the template strand to the complementary strand.
The mechanism of DNA replication follows the central dogma, such that it involves transcription then translation.
Find the image of the replication fork in the below attachment.
The steps are:
The enzyme helicase unwinds the DNA molecule by breaking the bonds. The SSBs or single-stranded binding proteins stabilize the DNA.The DNA polymerase synthesizes the leading strand in a 5' to 3' direction in a continuous pattern. The lagging strand is synthesized in the form of Okazaki fragments.These Okazaki fragments are then sealed by DNA ligase.Therefore, the replication fork runs parallelly, but in opposite direction.
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Explain the importance of plasma membranes and name 3 functions of membrane.
Answer:
Explanation: plasma membranes are the wall that surround the cell i.e the outer covering . They act as a protective covering.
Plasma members control exchange of material between the cell and environment.
Cell are kept in shape by plasma membrane, they are sites for Chemical reaction and cellular process and activities such as conductivity.
Membrane help to remove toxins out of the cell
They contain receptors and permit the flow of Ion and other molecules between cells.
They separate metabolism activities that are not compatible in body organelles.
The lab you work in has discovered a previously unidentified extracellular signal molecule called QGF, a 75,000-dalton protein. You add purified QGF to different types of cells to determine its effect on these cells. When you add QGF to heart muscle cells, you observe an increase in cell contraction. When you add it to fibroblasts, they undergo cell division. When you add it to nerve cells, they die. When you add it to glial cells, you do not see any effect on cell division or survival.
A. How can the same signaling molecule cause such diverse affects? Why do the glial cells not respond at all?
B. Devise a signaling pathway that QGF could use to increase contractions in in the heart. (Hint: Ca2+ is very important for muscle contraction)
C. Devise a signaling pathway that QGF could use to lead to apoptosis of nerve cells.
D. Devise a signaling pathway that QGF could use to induce cell division in the fibroblasts?
Answer:
A- It is because said molecule presents binding to different receptors and in the case of glia cells it does not present an answer because they do not have a specific receptor for said molecule.
b-in the case of muscle, this molecule could bind to calcium channels or to the REL itself, generating the opening of said channels or the release of calcium found in REL. In this way, by increasing the intracellular concentration of calcium, it activates the actin head, causing the topoisomerase to move and promoting binding with myosin. Once the activated actin will perform a "rowing" movement to generate the drag of the myosin and the union of the Z lines.
c-In the process of neuronal apoptosis, the cell itself generates biochemical signals (either by positive induction in which the receptors and receptors of the membrane bind to certain substances, or by negative or mitochondrial induction in which the ability to suppress certain substances is lost. substances that would generate the activity of apoptotic enzymes) that cause them to condense and alter the cytoplasm, the cell membrane, the cell nucleus to collapse and DNA to fragment. Finally, the microglial cells end up phagocytizing and eliminating the remains of the dead neurons, so that they do not generate interference for the normative functioning of the brain.
d- This molecule could fulfill a path similar or similar to that of growth factors, that is how they are associated with heparan sulfate of the extracellular matrix, which serves as a warehouse for inactive factors. FCFs contribute to different types of responses, such as wound healing, hematopoiesis, angiogenesis, or embryonic development
Explanation:
Regarding the explanation, it is important to keep in mind that this molecule can play a role both in the nervous system and in other organs, that is why in case it is sought that it does not have this apoptotic effect on neurons, some coarse, macro compound that allows the blood-brain barrier to not allow passage.
The most plausible evidence that the development of cancer is a multistep process can be:
A) development of a cancer as a result of activation of a single oncogene by any of a variety of mechanisms
B) usual occurrence of retinoblastoma at a young age
C) fact that proto-oncogenes are widely conserved in evolution
D) observation that certain tumor-suppressor genes and oncogenes are involved in a sequential manner in the development of colon cancer
Answer:
D) observation that certain tumor-suppressor genes and oncogenes are involved in a sequential manner in the development of colon cancer
Explanation:
Cancer is defined as the abnormal growth of cells of the body. These cells multiply/replicate without control thereby forming a lump or tumor.
Cancer growth has 5 stages and they go though different multi level steps.Different finding backs this up and it includes observation about certain tumor-suppressor genes and oncogenes being involved in a sequential manner in the development of colon cancer.
Answer:
option d: observation that certain tumor-suppressor genes and oncogenes are involved in a sequential manner in the development of colon cancer
Explanation:
Cancer is known to be a form of genetic disease/ailment that occurs as a result of mutation (one to many). the mutations embedded in the cell undergoes several cellular multiplication which therefor lead to the large growth of the size of tumor, malignant and disorganization.
The development of cancer undergoes a multi-step process. due to the fact that the cells of the human/ animal is abnormal in in it cancerous growth, they gain new potentials and capabilities. The cells undergoes division thereby affecting the closeby normal cells . some cancers do have similar characteristics while other cancers most times has different steps,
5. A s-shaped curve is shown when a period of growth is followed by a leveling off as the
population approaches carrying capacity. True or false
Answer:
population expansion decreases as resources become scarce, leveling off when the carrying capacity of the environment is reached, resulting in an S-shaped curve.
Explanation:
A. Globin is a red blood cell protein that is responsible for oxygen transport. The amino acid
sequence for a portion of the globin protein is Proline, Glutamic Acid, Glutamic Acid, Lysine. Write
the mRNA sequence of the amino acids for these amino acids in the space below (note, you don't
have to write all possible mRNA combinations for each amino acid, simply choose one correct codon
each amino acid specified above).
B. How many nucleotides would it take to code for the four amino acids in the above question.
Explain your answer.
Answer: A
Explanation:
Proline:CCG
Glutamic Acid: GAG,GAA
Lysine: AAG
Answer: B
Explanation: Each group of three nucleotides code for one amino acid. This means it would take 12 (3 times 4 equals 12) nucleotides to code for, four amino acids.
The mRNA sequences for Proline, Glutamic Acid, Glutamic Acid, and Lysine could respectively be CCU, GAA, GAA, AAA. Twelve nucleotides are needed to code these four amino acids.
Explanation:A. The mRNA sequences for the amino acids Proline, Glutamic Acid, Glutamic Acid, Lysine could be CCU, GAA, GAA, AAA respectively.
B. Each amino acid is coded for by a set of three nucleotides known as a codon, therefore to code for four amino acids, one would need 3 x 4 = 12 nucleotides. This is because in the genetic code, every sequence of three nucleotide bases corresponds to one specific amino acid.
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Darwin recorded distinct species of finches on different islands in the Galapagos. The images below show two species of finches he observed.
On island X, he saw both species of finches. On island Y, he only saw the finch on the right. Based on these observations, what is the most likely conclusion Darwin would have made?
Answer:
On island y the other finch cant eat the food do to the shape and hardness of his beak therefor he would not survive
Explanation:
Answer:
On island y the other finch cant eat the food do to the shape and hardness of his beak therefor he would not survive.
Explanation:
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In Escherichia coli (E. coli), the tryptophan operon encodes structural genes, including trpC, trpB, and trpA, that encode the tryptophan synthetase protein complex. A repressor protein encoded by the trpR gene regulates the trp operon. In the presence of high levels of tryptophan, tryptophan molecules bind the repressor protein and allow the repressor to recognize and bind to the operator, called trpO, and repress the expression of the structural tryptophan synthetase genes. In the absence of tryptophan, the repressor is unable to bind the operator and gene expression can occur. Assume any minus symbol represents a null mutant. What is the type of expression of each functional structural gene for the three bacterial strains?
The type of expression of each functional structural gene for the three bacterial strains is as follows:
Strain trpC trpB trpA
Wild type On On On
trpR- Off On On
trpO- On On On
Wild type: The trpR gene and trpO operator are both functional, so the trp operon is regulated by the presence of tryptophan. In the presence of high levels of tryptophan, the trp repressor will bind to the trpO operator and repress the expression of the structural tryptophan synthetase genes. In the absence of tryptophan, the trp repressor will not be able to bind to the trpO operator, and the structural tryptophan synthetase genes will be expressed.
trpR-: The trpR gene is mutated, so the trp repressor protein is not produced. This means that the trp operon is not regulated by the presence of tryptophan, and the structural tryptophan synthetase genes will always be expressed.
trpO-: The trpO operator is mutated, so the trp repressor protein cannot bind to it. This means that the trp operon is not regulated by the presence of tryptophan, and the structural tryptophan synthetase genes will always be expressed.
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The trp operon in E. coli is a repressible operon. It is regulated through a negative feedback mechanism where the accumulation of tryptophan, the end product, leads to the repression of its further production.
Explanation:In Escherichia coli (E. coli), the tryptophan operon, known as the trp operon, is a fundamental mechanism of gene regulation. It encodes structural genes, including trpC, trpB, and trpA, which contribute to the tryptophan synthetase protein complex. The expression of these genes is regulated by a repressor protein encoded by the trpR gene. When levels of tryptophan are high, tryptophan molecules bind to the repressor, allowing it to recognize and attach to the operator region, called trpO, and subsequently, inhibiting the expression of the structural genes. However, in the absence of tryptophan, the repressor does not bind to the operator region, allowing for gene expression to occur.
This type of operon system is termed a repressible operon, as the regulatory gene produces a repressor that can bind to the operator and prevent transcription of the structural genes. Thus, trp operon regulation is dependent on the negative feedback mechanism, where an abundance of the end product (tryptophan) leads to the repression of further production.
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Overlearning information hinders deep processing. Please select the best answer from the choices provided T F
Answer:
False
Explanation:
As per the levels of processing, the deep processing of information leads to long-term memory.
In order to remember a piece of information, a person must think about it more deeply (over learning) and must link it with memories in order to make it more meaningful.
However, interference lead to forgetting in long term memory when recalling is interfered.
Hence, the given statement is false
The European model was the first weather model to correctly predict that Hurricane Sandy would _____, while the American model's early prediction was that Hurricane Sandy would _____.
Choices:
Weakening Before Heading South
Turn Left Towards the Coast
Strengthen Before Moving Away from shore
Turn Right and Head Out to Sea
Answer:
The correct answer is "Turn Left Towards the Coast; Turn Right and Head Out to Sea".
Explanation:
During the Hurricane Sandy disaster of 2012, the European model was famous for predicting that Hurricane Sandy would turn left towards the coast, which was what happened on October 29. This was a disaster for the United States because the hurricane hit the East Coast. The American model had an opposite prediction, it predicted that the Hurricane Sandy would turn right and head out to sea.
The correct answer is "Turn Left Towards the Coast; Turn Right and Head Out to Sea".
The following information should be considered:
At the time of the Hurricane Sandy disaster of 2012, the European model was famous for estimating that Hurricane Sandy would turn left towards the coast, that was happened on October 29. This developed the disaster for the United States since hurricane hit the East Coast. The American model had an inverse estimation it predicted that the Hurricane Sandy would turn right and head out to sea.Learn more: https://brainly.com/question/10309631?referrer=searchResults
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Planet B has a tilt of 45 degrees. What seasonal changes would be expected on this planet Group of answer choices
A. Extreme temperature changes between seasons
B. Little to no change in temperatures between seasons
C. Seasonal changes along the equator only
D. Seasonal changes at the poles only
Answer:
A. extreme temperature changes between seasons
which of the following represents a genotype that is homozygous recessive
There are many, and since you didn't specify the choices, some examples include "ff" or "dd" or just two lowercase letters.
Explanation:
Final answer:
A genotype that represents a homozygous recessive condition would consist of two identical recessive alleles, typically represented by two lowercase letters, such as 'aa'.
Explanation:
The genotype that represents a homozygous recessive condition would consist of two identical recessive alleles. In genetic notation, this is often represented by two lowercase letters (e.g., aa). This is because a recessive trait will only be observed when an individual has two copies of the recessive allele, as dominant alleles, if present, will mask the expression of recessive alleles.
For instance, if we consider a gene with two alleles - one dominant (A) and one recessive (a) - the homozygous recessive genotype would be aa for that trait. A homozygous dominant genotype would be AA and a heterozygous genotype would be Aa. Only in the homozygous recessive genotype does the recessive trait get expressed because there is no dominant allele to dominate over the recessive allele.
The four gas giants are
(Planets should be in correct sequence)
A. Jupiter, Saturn, Mars and Neptune
B. Jupiter, Neptune, Saturn, and Uranus
C. Mercury, Jupiter, Mars and Earth
D. Jupiter, Saturn, Uranus, and Neptune
A young entomologist is trying to increase body hairs in Drosophila. His original population has a mean of 7.5 hairs, and he selects flies with a mean of 10 hairs to inter-mate and produce his next generation. The mean number of hairs in the resulting population was 9.
1. What is the narrow-sense heritability (h2) for number of body hairs in this Drosophila population (show your work)?
2. What would have been the mean number of body hairs in the next population if she had selected individuals with a mean of 8.5 hairs?
3. If she wanted a mean of 10 hairs in the progeny, what should have been the mean number of hairs in the individuals selected as parents?
Answer:
Explanation:
1) homologous features:
these are the features or structures that have a similar structure in several different organisms but function in a unique way in all of them. these structures indicate anatomical similarities as well as the same ancestry of different organisms. for example, the forelimb of birds, humans, dogs, and whales, perform different functions in all these organisms. but when we analyze the layout of bones or layout of the arrangement, we find that it is very similar across all of them. this indicates that, the ancestor of all these organisms was, but with the passage of time when organism dispersed, and environmental conditions changed, it was evolved into different organisms as per favorable conditions.
2) molecular biology:
as we know that all living organisms are a compilation of billions and trillions of unique biological molecules, that group in a unique fashion to constitute the whole organism. interestingly, some biological molecules and the process of their formation can provide sound evidences of evolution. for example, DNA, a sequence of nucleotides in DNA, amino acids, the process of transcription, translation, etc.
the study of evolution through molecular uniformity has led to the foundation of a novel branch of evolution called phylogenetics. the sequence of nucleotides in DNA is used to find the best possible ancestor of any organism. for example, phylogenetic analysis has found that the origin of eukaryotes is from prokaryotes over the period of time.
3) fossil records:
fossils are the preserved remains of previously living organisms or their traces, dating from the distant past. this doesn't mean that fossils represent the complete skeleton of an organism because many organisms don't even fossilize and those who fossilize don't have complete remains. nonetheless, the fossils that humans have collected offer unique insights into evolution over long timescales. for example, the study of horse fossils has enabled the scientists to reconstruct a large, branching "family tree" for horses and their now-extinct relatives.
In a laboratory experiment, C. elegans and B. thuringiensis were cultured individually (control) or together (experimental) for 150 days. Under optimal conditions, the generation time of C. elegans is approximately 3.5 days and the generation time of B. thuringiensis is approximately 25 minutes. At the end of the experiment, the change in virulence of B. thuringiensis and the change in resistance of C. elegans to BT toxin were determined. (a) Calculate the maximum number of generations that is possible in individual cultures of C. elegans AND the maximum number of generations that is possible in individual cultures of B. thuringiensis in 150 days.
Given 150 days, the maximum number of generations for C. elegans is approximately 4,114 generations, and for B. thuringiensis is approximately 8,640 generations, calculated based on their respective generation times.
Explanation:To calculate the maximum number of generations for C. elegans and B. thuringiensis, we will need the total time frame of 150 days and their generation times. The generation time for C. elegans is about 3.5 days, and for B. thuringiensis, it’s approximately 25 minutes.
C. elegans: First, convert the total experiment time from days to the same time unit for generation time. There are 150 days * 24 hours/day * 60 minutes/hour = 216,000 minutes. Then, divide this total available time by the organism's generational cycle: 216,000 minutes / (3.5 days/generation * 24 hours/day * 60 minutes/hour) = about 4,114 generations.
B. thuringiensis: Similarly, we calculate the number of generations: 216,000 minutes / (25 minutes/generation) = approximately 8,640 generations.
The reason behind this large difference in number of generations is the stark difference in generation times of these organisms. The comparatively shorter generation time of B. thuringiensis allows it to produce more generations within the same timeframe.
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discuss the genetic diagram to show a cross between a man heterozygous for brown eyes (Bb) and a woman with blue eyes (bb)