Answer:
$2268
Step-by-step explanation:
Luna's total mortgage payments for the year would be
... (monthly payment)×(number of months in a year)
... = $2100×12 = $25,200
Of that, 9% went to interest, so the interest amount is ...
... $25,200×9% = $2268
_____
About percentages
Your calculator may do percentages directly. If not, it can be helpful to realize that the percent symbol (%) means the same thing as /100 (divided by 100). So, 9% = 9/100 = 0.09
Answer:
$2268
Step-by-step explanation:
did it on apXX
I need to prove that A’B’= A’D’ but i keep going in circles.
You have the figure in the picture, the hypothesis are:
AA’= (1/2)AB
BB’=(1/2)BC
CC’=(1/2)CD
DD’=(1/2)DA
These are all vectors!
It can't be proven because it isn't so.
You can show that A'B' = C'D' because each is half of AC (from the midsegment theorem).
Is it possible to find an edge length that would be perfect for a cube with a volume of 30 cubic units? Explain!
Yes ,
side ×side×side= side^3 =volume of cube
=>side^3=30
=>side = 30^1/3-answer
im quite confused, please help :((
You need to pick from each column depending on what makes sense - they are mixed (some numbers are roots, some cubes, in the same column).
On the order:
3 - 27
4 - 64
5 - 125
512 - 8
8 - 2
729 - 9
216 - 6
1 - 1
Answer:
as>JDKFas;lkdjfsa;lkdfjas;kldfjlakdjfalsdkfjakdkdkdlddd
Step-by-step explanation:
PLS HELP Will give Brainliest!
Five hot dogs and four hamburgers cost $12. Four hotdogs and five hamburgers cost 12.75. How much does one hot dog and one hamburger cost?
If you add the two purchases, you find 9 hotdogs and 9 hamburgers cost 24.75. One hotdog and one hamburger will cost 1/9 of that total, or 2.75.
... One hotdog and one hamburger costs $2.75.
_____
This is what your question asks. Usually, we want to know the individual costs of the items. If we multiply this total by 5, then we have the cost of 5 hotdogs and 5 hamburgers: 13.75. This $1.75 more than the cost of 5 hotdogs and 4 hamburgers, so the cost of a hamburger must be $1.75
... One hotdog costs $1.00
... One hamburger costs $1.75
Please solve this and show work.
Angles DCE and ACB are vertical angles, hence equal. Both have the value 3x.
Angles ACH and HCB (x) add to give ange ACB, so they sum to 3x. That makes ACH have the value 2x. (2x +x = 3x)
The angles in triangle ACH add to 180°. This sum is ...
... 2x +2x +100° = 180°
... 4x = 80° . . . . . . . . subtract 100°, then divide by 4 to get ...
... x = 20°
If s = 1/4 unit and A = 80s^2, what is the value of A, in square units? ____ square unit(s). (Input whole number only.)
If s = 1/4 unit and A = 80s^2
A = 80 (1/4)^2
A = 80 (1/16)
A = 5
Answer
5 square units
5 square units
substitute s = [tex]\frac{1}{4}[/tex] into the equation
A= 80 × ([tex]\frac{1}{4}[/tex])² = 80 × [tex]\frac{1}{16}[/tex] = [tex]\frac{80}{16}[/tex]= 5 square units
Jordan and Sharla are saving money to go on a study abroad trip. They must provide a down payment of $650 to sign up for the trip, and they can pay the remaining balance later. Jordan raises money by mowing lawns in his neighborhood and charges $25 per lawn. Sharla raises money by selling handmade necklaces for $15 each. Sharla raises less money than Jordan does because Sharla 3. only has enough materials to make 40 necklaces. (A) write two constraints to model the problem. Let x respresent the number of lawns Jordan mows and y represent the number of necklaces Sharla sells. (B) can sharla afford the down payment with the money she earns selling her necklaces? Explain your answer . PLEASE HELP ITS DUE TODAY AND I DON’T UNDERSTAND!!!
Amount of down payment = $650.
Jordan gets money by mowing lawns = $25 per lawn.
Sharla gets money by selling handmade necklaces for = $15 each necklace.
The number of lawns Jordan mows = x.
The number of necklaces Sharla sells = y.
A) Total money raised by Jordan to move x lawns at the rate $25 per lawn = 25x.
Total money raised by Sharla by selling y handmade necklaces for $15 per necklace = 15y.
Total money Sharla can raise by selling 40 necklaces at the rate $15 each = 40 × 15 = $600.
B) Because Sharla can raise maximum $600, therefore sharla can not afford the down payment with the money she earns selling her necklaces.On spring break, Mirna went to Florida. She collected 6 seashells. The following set of data shows the weight of each seashell in ounces. 16, 17, 13, 12, 18, 20 What is the mode of this set of data?
The set of seashell weights that Mirna collected (12, 13, 16, 17, 18, 20) does not have a mode because all values appear only once.
The mode of a set of data refers to the number that appears most frequently. In the case of the weights of the seashells Mirna collected in Florida, the data set is: 12, 13, 16, 17, 18, 20. To find the mode, we look for the value that occurs the most:
12 ounces - occurs once13 ounces - occurs once16 ounces - occurs once17 ounces - occurs once18 ounces - occurs once20 ounces - occurs onceSince all numbers occur only once, there is no number that appears more frequently than the others. Therefore, this set of data does not have a mode.
Solve the inequality. 7x − 9 > 2x + 6
We can treat inequalities like standard algebraic equations.
7x - 9 > 2x + 6
Add 9 to both sides.
7x > 2x + 15
Subtract 2x from both sides.
5x > 15
Divide both sides by 5.
x > 3
Answer:
x>3 is the answer
Step-by-step explanation:
We are given one inequality
7x-9>2x+6
To solve this we can do additions and subtraction as we do for equations.
Only for multiplication if negative number is used inequality changes
So let us add 9 to both the sides
7x>2x+6+9
Now subtract 2x from both the sides
7x-2x >15
5x>15
We divide by a positive number 5 without disturbing inequality sign.
X>3 is the answer
In interval notation we can write this as open interval
(3,∞)
In number line this is the region to the right of 3, not includig 3
Find the slope of the tangent line to the graph of f at the given point. f(x) = x√ at (36,6) 1/3 1/12 3 12
slope = [tex]\frac{1}{12}[/tex]
the slope is the value of f' (36)
f(x) = √x = [tex]x^{\frac{1}{2} }[/tex]
f'(x) = [tex]\frac{1}{2}[/tex] [tex]x^{-\frac{1}{2} }[/tex] = [tex]\frac{1}{2\sqrt{x} }[/tex]
f'(36) = [tex]\frac{1}{2(6)}[/tex] = [tex]\frac{1}{12}[/tex]
Answer:
[tex]slope = \frac{1}{12}[/tex]
Step-by-step explanation:
Here is another method to solve your problem. I am showing this method because this is the first method normally taught and a student might not of had the chance yet to learn the other methods
We can solve this problem by using limits and the following function
[tex]\lim_{h\to 0} \frac{f(x+h) - x}{h}[/tex]
[tex]\lim_{h\to 0} \frac{\sqrt{x+h} - \sqrt{x}}{h}[/tex]
Next multiply by the conjugate of the numerator.
[tex]\lim_{h\to 0} \frac{\sqrt{x+h} - \sqrt{x}}{h} * \frac{\sqrt{x+h} + \sqrt{x}}{\sqrt{x+h} + \sqrt{x}}[/tex]
[tex]\lim_{h\to 0} \frac{x + h - x}{h(\sqrt{x+h} + \sqrt{x})}[/tex]
Cancel the x - x
[tex]\lim_{h\to 0} \frac{h}{h(\sqrt{x+h} + \sqrt{x})}[/tex]
Divide out the h
[tex]\lim_{h\to 0} \frac{h}{h(\sqrt{x+h} + \sqrt{x})}[/tex]
[tex]\lim_{h\to 0} \frac{1}{(\sqrt{x+h} + \sqrt{x})}[/tex]
Plugin 0 where h is located
[tex]\lim_{h\to 0} \frac{1}{(\sqrt{x+h} + \sqrt{x})}[/tex]
[tex]\lim_{h\to 0} \frac{1}{(\sqrt{x+0} + \sqrt{x})}[/tex]
[tex]\lim_{h\to 0} \frac{1}{(\sqrt{x} + \sqrt{x})}[/tex]
Combine Like terms in denominator
[tex]\lim_{h\to 0} \frac{1}{(\sqrt{x} + \sqrt{x})}[/tex]
[tex]\lim_{h\to 0} \frac{1}{2\sqrt{x}}[/tex]
Now lets use our derivative and plugin 36 where x is located and solve
[tex]\frac{1}{2\sqrt{x}}[/tex]
[tex]\frac{1}{2\sqrt{36}}[/tex]
[tex]\frac{1}{2(6)}[/tex]
[tex]\frac{1}{12}[/tex]
Note, this is a harder method but it is normally the first method taught in Calculus 1.
Jack is using a ladder to hang lights up in his house.he places the ladder 5 feet from the base of his house and leans it so it reaches a window 14 feet above the ground
The angle of elevation of the ladder is approximately 70.35°
How do we find the angle of elevation?
To find the angle of elevation of the ladder, we can use trigonometric functions.
The angle of elevation can be found using the tangent function, which is the ratio of the opposite side to the adjacent side in a right triangle.
opposite side is the height from the ground to the window = 14 feet,
adjacent side is the distance from the house to the base of the ladder= 5 feet.
tan(θ) = opposite/adjacent
tan(θ) = 14/5
θ = arctan(14/5)
θ = 70.35 degrees
Full question
Jack is using a ladder to hang lights up on his house. He places the ladder 5 feet from the base of his house and leans It so it reaches a window 14 feet above the ground. Find the angle of elevation of the ladder.
A) 65.5
B) 68.4
C) 70.3
D) 71.5
E) 72.9
You plan to build a cylindrical container with no top. The material used for the lateral sides costs $6 per square foot while the material for the bottom costs $9 per square foot. (a) Express the surface area of the open cylinder in terms of the cylinder's radius, r, and height, h. S = (b) Express the cost of building the open cylinder in terms of the cylinder's radius, r, and height, h. C = (c) If the volume of the cylindrical container is 500 cubic feet, express the cost of building the cylinder, C in terms of the cylinder's radius, r. C(r) = (d) If the volume of the cylindrical container is V cubic feet, express the cost of building the cylinder, C in terms of the cylinder's radius, r. Note - Your answer will have V in it, but V is a constant here. Use an upper case V. C(r) =
The surface area of an open cylinder can be expressed as 2πrh + πr^2. The cost of building the open cylinder can be calculated using the surface area and the cost per square foot. If the volume of the cylindrical container is known, the cost of building the cylinder can be expressed in terms of the cylinder's radius.
Explanation:(a) The surface area of an open cylinder consists of the sum of the lateral surface area and the area of the bottom. The lateral surface area is given by the formula 2πrh, and the area of the bottom is πr^2. Therefore, the surface area of the open cylinder, S, can be expressed as:
S = 2πrh + πr^2
(b) The cost of building the open cylinder can be calculated by multiplying the surface area by the cost per square foot. Let C be the cost of building the cylinder:
C = 6(2πrh + πr^2) + 9πr^2
(c) If the volume of the cylindrical container is 500 cubic feet, we can express the cost of building the cylinder, C, in terms of the cylinder's radius, r. We already know that the volume of a cylinder is given by the formula V = πr^2h, so we can solve for h and substitute it into the equation for C:
C(r) = 6(2πr(V/πr^2) + πr^2) + 9πr^2
(d) If the volume of the cylindrical container is V cubic feet, we can express the cost of building the cylinder, C, in terms of the cylinder's radius, r:
C(r) = 6(2πr(V/πr^2) + πr^2) + 9πr^2
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Surface area S of the open cylinder is 2πrh + πr². The cost C to build the cylinder is 12πrh + 9πr². Given the volume V, cost C(r) can be expressed as 12V/r + 9πr².
Building a Cylindrical Container without a Top
The problem involves calculating the surface area and cost of a cylindrical container with no top. Here are the detailed steps:
(a) Surface Area Calculation
The surface area S of a cylindrical container with radius r and height h (with no top) includes:
The lateral surface area: 2πrh
The bottom area: πr²
Thus, the total surface area S is given by:
S = 2πrh + πr²
(b) Cost Calculation
The cost C to build the cylindrical container is calculated as:
Cost of lateral sides: $6 per square foot
Cost of the bottom: $9 per square foot
Therefore, the cost C is:
C = 6(2πrh) + 9(πr²) = 12πrh + 9πr²
(c) Cost in Terms of Radius r (Volume = 500 cubic feet)
Given the volume V = 500 cubic feet, we have:
Volume V = πr²h = 500
Rearranging for h, we get:
h = 500 / (πr²)
Now, substitute h in the cost equation:
C(r) = 12πr(500 / πr²) + 9πr² = 6000/r + 9πr²
(d) Cost in Terms of Radius r (Volume = V cubic feet)
For a general volume V, we have:
Volume V = πr²h = V
Rearranging for h, we get:
h = V / (πr²)
Now, substitute h in the cost equation:
C(r) = 12πr(V / πr²) + 9πr² = 12V/r + 9πr²
Graph −7y+8=21x−6 . Use the line tool and select two points on the line.
The two points on the graph of the function - 7y + 8 = 21x - 6 are;
⇒ (0, 2) and (2, -4)
What is Coordinates?
A pair of numbers which describe the exact position of a point on a cartesian plane by using the horizontal and vertical lines is called the coordinates.
Given that;
The function is,
⇒ - 7y + 8 = 21x - 6
Now,
We can draw the graph of the function - 7y + 8 = 21x - 6 as shown in figure.
And, The points on the graph are;
⇒ (0, 2) and (2, -4)
Thus, The two points on the graph of the function - 7y + 8 = 21x - 6 are;
⇒ (0, 2) and (2, -4)
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Solve the following equation. Then place the correct number in the box provided. 2x < 6
Answer:
x can take any value less than 3.
Step-by-step explanation:
This is an inequality.
[tex]2x < 6[/tex]
Lets solve the inequality for x
[tex]x < 3[/tex]
This means x can take any value less than 3.
We can show this by using a number line.
Notice how number 3 is not fully shaded, this means x cannot be 3. And all the numbers less than 3 to infinity is shaded, meaning x can take any value in that range.
what is the midpoint of line segment EF
E is located at (-2,-4)
F is located at (2,2)
To find the midpoint, add the 2 X values together and divide by two, then do the same with the y values:
X = -2 + 2 = 0/2 = 0
Y = -4 + 2 = -2/2 = -1
The midpoint is located at (0,-1)
Divide. −3/8÷−6/7 A−7 1/6 B−9/28 C9/28 D7/16
D
to divide 2 fractions
• leave the first fraction
• change division to multiplication
• turn the second fraction upside down
• simplify if possible
= - [tex]\frac{3}{8}[/tex] × - [tex]\frac{7}{6}[/tex] = [tex]\frac{3(7)}{8(6)}[/tex] = [tex]\frac{7}{16}[/tex]
How do i find the domain and the range of the function ????
Note that the graph shows 8 dots with associated x-values 1 through 8. The domain is the set of integers {1, 2, 3, 4, 5, 6, 7, 8}. The range is the set of all y-values associated with this domain, a bit harder to read off the graph. One by one, I will approximate the y-value associated with each x value and present these 8 y-values as the range: {7.5, 9, 12, 15. 18, 22, 23}.
Write an expression to represent the situation.Then solve. In recent years, tennis club has lost 15 students each year.If this continues for 6 more years,what will the loss of students be for those 6 years
In y years, the loss is ...
... loss = 15y
Then in 6 years, the loss will be ...
... loss = 15·6 = 90
The loss of students for those 6 years will be 90 students.
solve the equation. 2m/3-1=3/4+m (please show work)
How do you graph these?
Answer:
See the attached.
Step-by-step explanation:
A graph of f' is a graph of the slope of the function. Your function f(x) is piecewise linear, so different sections of its graph have different constant values of slope.
In the intervals (-5, -2) and (0, 2), the slope is -1. (The graph has a "rise" of -1 for each "run" of 1.) So, in those intervals, the graph of f' looks like a graph of y=-1.
In the interval (-2, 0), the rise is 2 for a run of 2, so the slope is 2/2 = 1. The graph of f' in that interval will look like a graph of y=1.
In the interval (2, 5), the rise of f(x) is 1 for a run of 3, so the slope in that interval is 1/3. There, the graph of f' will look like a graph of y=1/3.
If you want to get technical about it, the slope is undefined at x=-2, x=0, and x=2. Therefore, the line segments that make up the graph of f' ought to have open circles at those points, indicating that f' is not defined.
We are given with width 20 cm length = 28 cm volume = 1848 cm3 We are asked how deep is the cake batter.
depth = 3.3 cm
the volume (V ) of a cuboid is
V = Ah ( A is the area and h the depth )
A = 20 × 28 = 560 cm², thus
h = [tex]\frac{V}{A}[/tex] = [tex]\frac{1843}{560}[/tex] ≈ 3.3 cm
7/3 as a decimal rounded to the nearest hundredth.
7/3 = 2 1/3. Rounded to the nearest hundredth, we get 2.33.
A quadrilateral has vertices at A (-5, 5), B (1, 8), C (4, 2), and D (-2, -2). Use slope to determine if the quadrilateral is a rectangle. Show your work. (Try to use point slope form)
Answer:
not a rectangle
Step-by-step explanation:
There are several ways to determine whether the quadrilateral is a rectangle. Computing slope is one of the more time-consuming. We can already learn that the figure is not a rectangle by seeing if the midpoint of AC is the same as that of BD. (It is not.) A+C = (-5+4, 5+2) = (-1, 7). B+D = (1-2, 8-2) = (-1, 6). (A+C)/2 ≠ (B+D)/2, so the midpoints of the diagonals are different points.
___
The slope of AB is ∆y/∆x, where the ∆y is the change in y-coordinates, and ∆x is the change in x-coordinates.
... AB slope = (8-5)/(1-(-5)) = 3/6 = 1/2
The slope of AD is computed in similar fashion.
... AD slope = (-2-5)/(-2-(-5)) = -7/3
The product of these slopes is (1/2)(-7/3) = -7/6 ≠ -1. Since the product is not -1, the segments AB and AD are not perpendicular to each other. Adjacent sides of a rectangle are perpendicular, so this figure is not a rectangle.
___
Our preliminary work with the diagonals showed us the figure was not a parallelogram (hence not a rectangle). For our slope calculation, we "magically" chose two sides that were not perpendicular. In fact, this choice was by "trial and error". Side BC is perpendicular to AB, so we needed to choose a different side to find one that wasn't. A graph of the points is informative, but we didn't start with that.
determine whether each number is real or not real and rational or irrational. you must be able to support your answer with a rule.
All the numbers shown are real.
The answers to problems 4, 7, 11 are irrational, because they are square roots of numbers that are not perfect squares.
The remaining numbers are rational because they are terminating decimals or the square root of a square number.
Find the value of z such that 0.9544 of the area lies between −z and z. Round your answer to two decimal places.
Hello...
Z = total area (1)
___-z___0.9544___z
z = 0.0288
Normal,
z = 2
The value of z is 2. the probability that is closest to 0.0228, where the outliner is a -2 and z equals 2.
How to find the value of z?The decimal numeral system is widely used to express both integer and non-integer numbers. It is the expansion of the Hindu-Arabic numeral system to non-integer values. Decimal notation is the term used to describe the method of representing numbers in the decimal system.
A number that has been divided into a whole and a fraction is called a decimal. Between integers, decimal numbers are used to express the numerical value of complete and partially whole quantities.
The word decimus, which means tenth in Latin, is derived from the base word decem, or 10. As a result, the decimal system, often known as a base-10 system, has 10 as its fundamental unit. A number expressed using the decimal method is also referred to as being "decimal."
Given ,
0.9544/2= 0.4772
.5- 0 .4772=0.0228
the probability that is closest to 0.0228, where the outliner is a -2 and z equals 2.
Therefore value of z is 2.
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Solve the quadratic equation. Show all of your steps.
x^2 + 3x - 5 = 0
The roots of equation are: x= -3+ √29/2 and x= -3-√29/2.
What is Quadratic Equation?Quadratic equation's roots The roots of a quadratic equation are the values of the variables that fulfil the equation. In other words, if f(a) = 0, then x = a is a root of the quadratic equation f(x). The x-coordinates of the sites where the curve y = f(x) intersects the x-axis are the real roots of an equation f(x) = 0.
given:
x² + 3x - 5 = 0
So, solving for x
x² + 3x - 5 = 0
D= (3)² - 4(1)(-5)= 9 + 20= 29
Now, using the quadratic equation
x= -b ± √ b² -4ac/ 2a
x= -3 ±√(3)² -4(1)(-5) / 2
x= -3±√29/2
x= -3+ √29/2 and x= -3-√29/2
Hence, the roots of equation are: x= -3+ √29/2 and x= -3-√29/2.
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If a number’s composite form is 256, which of the following shows its exponential form as a product of prime numbers? 2^8 256 4 · 64 24 · 8
The only answer choice involving powers of prime numbers is ...
... 2^8
if a class skip counted by 100's. how many counted to get to 2, 000
Divide 100 from 2000
2000/100 = 20
20 counted to get to 2000 by skip counting by 100
hope this helps
A parking meter in downtown Seattle takes dollar coins and quarters only. When the machine was last emptied, there were 250 coins in it, with a total value of $137.50. Which of the following systems of equations gives the number of quarters, q, and the number of dollar coins, d ? A. d + q = 250 and 100d + 25q = 137.50 B. d + q = 250 and 0.1d + 0.25q = 137.50 C. d + q = 250 and d + 0.25q = 137.50 D. d + q = 137.50 and d + 0.25q = 250 E. d + q = 137.50 and 100d + 25q = 250 Question 2 of 3 For two consecutive integers, the result of adding double the smaller integer and triple the larger integer is 153. What are the two integers? F. 29, 30 G. 30, 31 H. 49, 50 J. 50, 51 K. 76, 77 Question 3 of 3 In a certain triangle, the longest side is twice as long as the shortest side, and the shortest side is 4 inches shorter than the middle side. If the perimeter of the triangle is 52 inches, how long is the longest side? A. 10 inches B. 12 inches C. 16 inches D. 20 inches E. 24 inc
(1)
C
d + q = 250 ( total number of coins ) and
d + 0.25q = 137.50 ( total value of coins )
(2)
G
consecutive integers have a difference of 1 between them
let the integers be n and n + 1 then
2n + 3(n + 1) = 153 (distribute and simplify )
2n + 3n + 3 = 153
5n + 3 = 153 ( subtract 3 from both sides )
5n = 150 ( divide both sides by 5 )
n = 30 and n + 1 = 31
the 2 consecutive integers are 30 and 31
(3)
E
let x be the shortest side then longest side = 2x and middle side = x + 4
2x + x + 4 + x = 52
4x + 4 = 52 ( subtract 4 from both sides )
4x = 48 ( divide both sides by 4 )
x = 12
the longest side = 2x = 2 × 12 = 24
The system of equations for a parking meter are -
d + q = 250
100d + 25q = 137.50
What is Equation Modelling?
Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.
We have a a parking meter in downtown Seattle takes dollar coins and quarters only.
Assume that there are [d] dollar coins and [q] quarter coins. Then, we can write the system of equations as -
d + q = 250
100d + 25q = 137.50
Therefore, the system of equations for a parking meter are -
d + q = 250
100d + 25q = 137.50
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For what value(s) of k will the relation not be a function?
A = {(3k−4, 16), (4k, 32)}
We won't have a function if for same value of x in (x,y) we get different values y.
So first step: figure out k so that the first coordinate (x) is the same:
3k-4=4k | solve for k
k = -4
no check the values y for the elements of the relation
x = 3k-4 = -12-4=-16
so at -16 we get (-16,16) and (-16, 32), which mean for k=-4 the relation is not a function.
Let me know if you have any questions.
Answer:
K= -4
Step-by-step explanation:
Since it isn't possible that (3k-4, 16) is going to be equal to (4k, 32) in terms of positive numbers, you will have to go to the negative side of the number line.
K has to equal 4 because 3 · -4 = -12, and -12 minus 4 is equal to -16.
And since 4 · -4 = -16, K has to equal - 4.