Answer:
Mg is the symbol for Magnesium. Atomic #- 12
Explanation:
differentiate between a cation and an anion.
Answer:
The positively charged ions are called cations and negatively charged ions are called anions.
Explanation:
When an atom releases an electron to form the nearest rare gas configuration, it forms a positive ion. Similarly, an atom receives an electron to form the nearest electronic configuration, it forms negative ions. The positive ions have an affinity towards the negative electrode and moves towards it. So it is called cations. The negative charge ions have an affinity towards the positive electrode and moves towards it. So, it is called anions. Hence, the positively charged ions are called cations and negatively charged ions are called anions.a steeper incline plane will require _____ Force
Answer:
wind
Explanation:
A steeper incline plane will require more force to move an object up. This is because the component of the gravitational force acting parallel to the incline increases with the steepness, necessitating a greater force to oppose it. The force required to move objects up an incline plane, therefore, increases with the steepness of the incline.
Explanation:When analyzing an object at rest on an inclined plane, the force of gravity acting on the object is divided into two crucial components - a force acting perpendicular to the plane and a force acting parallel to the plane. The perpendicular force of weight is typically equal in magnitude, but opposite in direction to the normal force. However, the force that impacts the effort needed to move an object up an incline directly is the component of force acting parallel to the plane.
As the slope of an incline plane gets steeper, this parallel component of the gravitational force increases, and it requires more force to oppose this component and move the object up the incline. Therefore, a steeper incline plane will require more force to move an object up.
In simpler terms, think of it as pushing a cart up a steep hill versus a gentle slope - the steeper hill requires more effort, or force, to push the cart up.
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A 388 Hz tuning fork is resonating in a closed tube on a warm day when the speed of sound is 346 m/s. What is the length of the closed tube?
A. 0.89m
B. 1.12 m
C. 0.28m
d. 0.22m
Please help!
Answer:
A
Explanation:
because u are subtracting if this is from flvs that is what i did and it was right
Answer:
A 0.89m
Explanation:
V= fλ
λ= V/f
λ=346/358
λ=0.89m
Add the vector 12.0 cm at 45 degrees from the x axis to the vector 8.5 cm 105 degrees from the x axis.
Answer:
Magnitude 17.85 cm
Angle: 69.36 degrees
Explanation:
Analytical sum of vectors
We have the vector 1 with magnitude 12 cm and angle 45 degrees. We'll find its cartesian components by using
[tex]v1_x=12cos45^o=8.49\ cm[/tex]
[tex]v1_y=12sin45^o=8.49\ cm[/tex]
Now we find the components of v2
[tex]v2_x=8.5cos105^o=-2.2\ cm[/tex]
[tex]v2_y=8.5sin105^o=8.21\ cm[/tex]
To add both vectors, we add their components separately
[tex]\vec{v3}=\vec{v2}+\vec{v1}[/tex]
[tex]v3_x=v1_x+v2_x=8.49\ cm-2.2\ cm=6.29\ cm[/tex]
[tex]v3_y=v1_y+v2_y=8.49\ cm+8.21\ cm=16.7\ cm[/tex]
Magnitude of [tex]\vec{v3}[/tex]:
[tex]\left \| \vec{v3} \right \|=\sqrt{v3_x^2+v3_y^2}[/tex]
[tex]\left \| \vec{v3} \right \|=\sqrt{(6.29)^2+(16.7)^2}[/tex]
[tex]\left \| \vec{v3} \right \|=17.85\ cm[/tex]
Angle of [tex]\vec{v3}[/tex]:
[tex]\theta_3=atan\left ( \frac{16.7}{6.29} \right )=69.36^o[/tex]
If the airman had a mass of 80 kg, find the magnitude of the air drag acting on him when he reached terminal velocity of 54 m/s.
The magnitude of the air drag is 784 N
Explanation:
When the airman is falling down, there are two forces acting on him:
- The force of gravity, downward, of magnitude
[tex]F=mg[/tex]
where
m = 80 kg is the mass of the airman
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
- The air drag, upward, of magnitude [tex]F_D[/tex], whose value is proportional to the speed of the airman
At the beginning of the fall, the speed is zero, so the air drag is also zero and therefore the airman starts accelerating due to the presence of the force of gravity, which is unbalanced. However, as the airman falls down, he gains speed, so the magnitude of the air drag increases up to a point where it becomes equal to the magnitude of the force of gravity. When this occurs, the airman no longer accelerates and continues its motion at constant velocity, which is called terminal velocity.
Therefore, at terminal velocity, the air drag is equal to the force of gravity on the airman (the weight), so we can write:
[tex]F_D = mg = (80)(9.8)=784 N[/tex]
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Questions to consider:
1. If the skater has a mass of 60 kg, what is her gravitational potential energy at the top of the 4 m high
half-pipe?
Answer: 2352 J
Explanation:
A body's gravitational potential energy [tex]U[/tex] depends on its position and is mathematically expressed as follows:
[tex]U=mgh[/tex]
Where:
[tex]m=60 kg[/tex] is the mass of the skater
[tex]g=9.8 m/s^{2}[/tex] is the acceleration due gravity
[tex]h=4 m[/tex] is the skater's current height
Solving:
[tex]U=(60 kg)(9.8 m/s^{2})(4 m)[/tex]
[tex]U=2352 J[/tex]
a bullet is dropped from the same height when another bullet is fired horizontally they will hit the ground
Answer:
At the same time.
Explanation:
In the first case ,
intial velocity = 0
displacement = -h
acceleration = -g
Using second equation of motion,
s = ut + .5a[tex]t^{2} \\[/tex]
- h = - 0.5g[tex]t^{2} \\[/tex]
t = [tex]\sqrt{\frac{2h}{g} }[/tex]
In the second case, consider only motion along y axis,
intial velocity = 0 ( all the velocity is along x axis)
displacement = -h ( height is same in both cases)
acceleration = -g
Using second equation of motion,
s = ut + .5a[tex]t^{2} \\[/tex]
- h = - 0.5g[tex]t^{2} \\[/tex]
t = [tex]\sqrt{\frac{2h}{g} }[/tex]
In both cases time is same.
Hence, they will reach the ground simultaneously.
An external torque is applied to a flywheel which is a solid cylinder of mass m = 100 kg and radius
R = 1.2 m with a magnitude τ = 450 N · m. What is the angular acceleration of the flywheel?
The angular acceleration is [tex]6.25 rad/s^2[/tex]
Explanation:
To solve this problem we can use the equivalent of Newton's second law for rotational motions:
[tex]\tau = I \alpha[/tex] (1)
where
[tex]\tau[/tex] is the torque acting on the body
I is the moment of inertia of the body
[tex]\alpha[/tex] is the angular acceleration
In this problem we have:
[tex]\tau = 450 Nm[/tex] is the torque
The moment of inertia of a solid cylinder about its axis is
[tex]I=\frac{1}{2}MR^2[/tex]
where
M = 100 kg is the mass
R = 1.2 m is the radius
Substituting,
[tex]I=\frac{1}{2}(100)(1.2)^2=72 kg m^2[/tex]
And solving eq.(1) for [tex]\alpha[/tex], we find the angular acceleration:
[tex]\alpha = \frac{\tau}{I}=\frac{450}{72}=6.25 rad/s^2[/tex]
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Three forces act on an object. If the object is moving to the right in translational equilibrium, which of the following must be true?
If an object is moving to the right in translational equilibrium, it means the sum of all the forces acting on the object is zero indicating a state of balanced forces. Translational equilibrium indicates the body is moving in a straight line at a constant speed or at rest. Equilibrium does not mean the absence of forces, but the balance of forces.
Explanation:When an object is moving to the right in translational equilibrium, it means it is in a state of steady motion, either at rest or moving at a constant velocity, with no acceleration. This equilibrium occurs when the sum of all the forces acting on the object is zero, indicating the forces are balanced. If we consider three forces acting on the object: F1, F2, and F3, for it to be in translational equilibrium, the vector sum of the three forces must be zero. This can be represented mathematically as: F1 + F2 + F3 = 0. If any of the forces change its magnitude or direction, it would disrupt the equilibrium status.
Translational equilibrium stands for a body moving in a straight line at a constant speed or being at rest, while rotational equilibrium refers to objects rotating at a constant rotation or being steady.
An important point to remember is that an equilibrium state does not necessarily mean the absence of forces but signifies that forces are equally balanced.
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Which term describes energy stored in the bonds between atoms?
Answer:Kinetic Energy. Kinetic energy is motion — of waves, molecules, objects, substances, and objects. Chemical Energy is energy stored in the bonds of atoms and molecules.
please give me brainliest...
Answer:
Chemical Energy
Explanation:
Energy is the ability to perform work, it is usually stored in many forms. A body at rest has potential energy, a car moving has kinetic energy while boiling water posses thermal energy. Energy is usually transformed from one form to another, it cant be destroyed.
Chemical EnergyChemical energy is the type of energy that is stored in the bonds of the atom of chemical substances. This is the potential energy that is released when the bonds of molecules are broken. For example, the human digestive system breaks down a molecule of food and release mechanical energy for our day to day activities.
The energy stored in between bonds of atoms is chemical energy that are released and converted to another form of energy when it is broken down.
wave is traveling at 60 cm/second and has a wavelength of 15 cm, what is the frequency?
The frequency of the wave is 4 Hz
Explanation:
The relationship between wave, frequency and speed of a wave is given by the equation:
[tex]v=f \lambda[/tex]
where
v is the speed of the wave
f is the frequency
[tex]\lambda[/tex] is the wavelength
For the wave in this problem, we have:
[tex]v=60 cm/s[/tex] is the speed
[tex]\lambda=15 cm[/tex] is the wavelength
Solving the equation for f, we find its frequency:
[tex]f=\frac{v}{\lambda}=\frac{60 cm/s}{15 s}=4 s^{-1} = 4 Hz[/tex]
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A block is pulled across a flat surface at a constant speed using a force of 50 newtons at an angle of 60 degrees above the horizontal. The magnitude of the friction force acting on the block is:
The magnitude of the friction force is 25 N
Explanation:
To solve this problem, we just have to analyze the forces acting on the block along the horizontal direction. We have:
The horizontal component of the pulling force, [tex]F cos \theta[/tex], where F = 50 N is the magnitude and [tex]\theta=60^{\circ}[/tex] is the angle between the direction of the force and the horizontal; this force acts in the forward directionThe force of friction, [tex]F_f[/tex], acting in the backward directionAccording to Newton's second law, the net force acting on the block in the horizontal direction must be equal to the product between the mass of the block and its acceleration:
[tex]\sum F_x = ma_x[/tex]
where
m is the mass of the block
[tex]a_x[/tex] is the horizontal acceleration
However, the block is moving at constant speed, so the acceleration is zero:
[tex]a_x = 0[/tex]
So the equation becomes
[tex]\sum F_x = 0[/tex] (1)
The net force here is given by
[tex]\sum F_x = F cos \theta - F_f[/tex] (2)
And so, by combining (1) and (2), we find the magnitude of the friction force:
[tex]F cos \theta - F_f = 0\\F_f = F cos \theta = (50)(cos 60^{\circ})=25 N[/tex]
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7. What mass of water will change its temperature by 3.0°C when 525 J of
heat is added to it?
The mass of the water is 41.9 g
Explanation:
When an amount of energy Q is supplied to a sample of substance of mass m, the temperature of the substance increases by [tex]\Delta T[/tex], according to the equation :
[tex]Q=mC_s \Delta T[/tex]
where :
m is the mass of the substance
[tex]C_s[/tex] is the specific heat capacity of the substance
[tex]\Delta T[/tex] is the change in temperature
In this problem, we have:
Q = 525 J is the amount of heat supplied to the water
[tex]\Delta T = 3^{\circ}C[/tex] is the change in temperature of the water
[tex]C_s = 4.18 J/gC[/tex] is the specific heat capacity of the water
Solving for m, we find the mass of the water:
[tex]m=\frac{Q}{C_s \Delta T}=\frac{525}{(4.18)(3.0)}=41.9 g[/tex]
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Final answer:
Using the specific heat capacity formula, we calculate the mass of water that can have its temperature increased by 3.0° C with the addition of 525 J of heat.
Explanation:
To solve the problem presented, we need to use the concept of specific heat capacity, which is the amount of heat required to raise the temperature of one kilogram of a substance by one degree Celsius. The specific heat capacity of water is commonly accepted as 4,184 J/kg/
°C. We can use the formula q = mcΔT, where q is the heat added (in Joules), m is the mass of the water (in kilograms), c is the specific heat capacity, and ΔT is the change in temperature (in degrees Celsius).
We are given q = 525 J and ΔT = 3.0°C. We need to find the mass m. Rearranging the formula to solve for m, we get m = q / (cΔT). Substituting the given values:
m = 525 J / (4,184 J/kg/
°C
* 3.0°C)
By calculating this, we find the mass of water that can have its temperature raised by 3.0°C with 525 J of heat.
Spaceship 1 and Spaceship 2 have equal masses of 200 kg. They collide.
Spaceship 1's final speed is 2 m/s, and Spaceship 2's final speed is 1 m/s in
the same direction. What is their combined momentum?
O
A. 200 kg-m/s
O
O
O
B. 400 kg-m/s
C. 800 kg-m/s
D. 600 kg-m/s
Answer: 600 kg-m/s
Explanation:
Momentum = mass x velocity
momentum of spaceship 1 = 200 x 2
= 400 kg-m/s
momentum of spaceship 2 = 200 x 2
= 200 kg-m/s
Their combine momentum = 400 + 200 = 600 kg-m/s
The Answer is 600 kg-m/s
Two snowmobiles, Frosty and Snowflake, of equal masses suffer a rear-end collision. Just Before the collision, Frosty's velocity is 25 m/s east and Snowflake's velocity is 10 m/s in the same firection. Just after the collision, Frosty is moving 13m/s towards the east.
A. What is Snow flakes velocity immediately after the collision?
B. Was this an elastic collision? Justify your answer by calculation.
Please. I am sooo lost..
Answer:
A. 22 [tex]ms^{-1}[/tex]
B. NO
Explanation:
A.
During a collision , the net external force on the system is zero .
hence , the total momentum of the system can be CONSERVED .
let the mass of frosty and snowflake be m ;
initial velocity of frosty be [tex]v_{F_{i} }[/tex] = 25 [tex]ms^{-1}[/tex] final velocity of frosty be [tex]v_{F_{f} }[/tex] = 13 [tex]ms^{-1}[/tex]initial velocity of snowflake be [tex]v_{S_{i} }[/tex] = 10 [tex]ms^{-1}[/tex]final velocity of snowflake be [tex]v_{S_{f} }[/tex] = x [tex]ms^{-1}[/tex]therefore from principle of conservation of momentum ,
[tex]m*v_{F_{i} } + m*v_{S_{i} } = m*v_{F_{f} } + m*v_{S_{f} }[/tex]
so ,
[tex]m*25 + m*10 =m*13 +m*x[/tex]
[tex]x = 25+10-13 = 22 ms^{-1}[/tex]
answer for A. 22 [tex]ms^{-1}[/tex]
B.
The collision is NOT ELASTIC.
this is because if it had been elastic , the coefficient of restitution should have been 1 but it isnot i.e
[tex]e =\frac{ v_{F_{f} } - v_{S_{f} } }{ v_{S_{i} } - v_{F_{i} } } \\=\frac{13-22}{10-25} \\=\frac{9}{15} = \frac{3}{5} = 0.6[/tex] ≠ 1
thus it's an inelastic collision.
What does the addition of two vectors give you?
A. A scalar
B. The direction of the vector.
C. A resultant vector
D. The magnitude of the vector
Apex answers needed
Answer: A resultant vector
Explanation: Addition of two vectors can not be a scalar because vectors have a magnitude and a direction. so that they are explained by means of these two chacteristics. If addition is different from zero it will give a vector.
A car is travelling at a speed of 21m/s. It accelerates at an average rate of 3m/s^2 for a time
of 4 seconds. Find the distance it travels.
Answer:
S = 108m
Explanation:
According to Second Law of Motion:
S = Vi*t + 0.5*a*t^2
Vi = 21m/s
a = 3m/s^2
t = 4s
Putting all values in Equation
S = 21*4 + 0.5*3*4^2
S = 84 + 24
S = 108m
Object A and Object B are 100 meters apart. If Object A gains some
mass, how does that affect the gravitational force between the two objects?
O A) It increases.
OB) It decreases.
OC) It remains the same.
The gravitational force between the two objects A) It increases.
Explanation:
The gravitational force between two objects is given by:
[tex]F=G\frac{m_1 m_2}{r^2}[/tex] (1)
where
G is the gravitational constant
[tex]m_1, m_2[/tex] are the masses of the two objects
r is the separation between the objects
In this problem, object A and object B are initially at a distance of
r = 100 m
And at that distance, the force between them is
F
Later, object A gains some mass. We notice from eq.(1) that the gravitational force is directly proportional to the mass: therefore, if the mass of either of the two objects increases, then the gravitational force between them also increases. Therefore, the new force will be larger than the original force:
F' > F
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A 23.7 kg kid slides down a
frictionless water slide at 47.2°.
What is her acceleration?
(Unit = m/s2)
Answer:
[tex]\text { The acceleration of the kid is } 7.18 \mathrm{m} / \mathrm{s}^{2}[/tex]
Explanation:
Mass of the kid 23.7 kg.
[tex]\text { The kid is accelerating down at an angle is } 47.2^{\circ} .[/tex]
[tex]^{\prime \prime} \mathrm{g}^{\prime \prime} \text { acceleration due to gravity is } 9.8 \mathrm{m} / \mathrm{s}^{2}[/tex]
We need to find the acceleration of the kid,
We know that, Parallel force acted on the kid at an angle is
F = m × g × sinθ (F = ma)
m × a = m × g × sinθ
Now, substitute the given values in the above formula to find acceleration of the kid,
[tex]23.7 \times a=23.7 \times 9.8 \times \sin 47.2^{\circ}[/tex]
23.7 × a = 232.26 × 0.733
23.7 × a = 170.24
[tex]a=\frac{170.24}{23.7}[/tex]
[tex]a=7.18 \mathrm{m} / \mathrm{s}^{2}[/tex]
[tex]\text { Therefore, acceleration of the kid is } 7.18 \mathrm{m} / \mathrm{s}^{2}[/tex]
Can a machine be more than 100% efficient?
yes
no
impossible to determine
Answer:
Impossible to determine
Explanation:
In other words, no machine can be more than 100% efficient. Machines cannot multiply energy or work input. ... If a machine were 100% efficient then it can't have any energy losses to friction, so no friction can be present. In that case the theoretical and actual mechanical advantages would be equal.
What is the most likely effect on the life of a plant if a student cuts it’s flowers?
A. The plant can’t absorb more water.
B.The plant can’t produce food
C.The plant cannot support it’s self.
D.The plant cannot reproduce.
Please explain why you picked that answer. Ty
Answer:
D
Explanation:
The reproduction parts of the plant are in the flower and around it so this would eliminate the plants ablity to reproduce.
The resistivity of glass is higher than that of wood. True False
Answer:True
Explanation:
Answer:true
Explanation:because the glass material is template and the wood is natural for SAE convention and normalitation have in chard that glass is more resistive than the wood
Amaya ran around 3 times around a 1 mile track in 45 minutes, what was her average velocity for the trip?
Since Amaya ran around a 1 mile track 3 times we can multiply this to find the total distance she traveled (displacement).
3 x 1 = 3 miles traveled.
-----------
Formula: [tex]V_a_v_g~=~\frac{displacement}{change~in~time}[/tex]
-----------
In this question the variables are classified as:
Displacement = 3 miles
Change in Time = 45 minutes
-----------
Now, fill in the expression to solve.
[tex]V_a_v_g~=~\frac{45}{3}\\V_a_v_g~=~15~[/tex]
-----------
Amayas average velocity is 15 minutes per mile.
______
Best Regards,
Wolfyy :)
Average Velocity = (displacement) / (time)
Displacement = distance and direction between the start-point and end-point, no matter what happens in between.
Amaya ran around the track, so she ended in the same place she started. The distance between her start-point and end-point was zero. So . . .
Average Velocity = zero.
= = = = = = = = = =
Average Speed = (distance covered) / (time to cover the distance)
Amaya's distance = (1 mile/track) x (3 tracks) = 3 miles
Time to cover the distance = (3/4 hour)
Average speed = (3 miles) / (3/4 hour)
Average speed = (3 ÷ 3/4) mi/hr
Average speed = (3 x 4/3) mi/hr
Average speed = 4 miles per hour
Predict using Boyle's law, what will happen to a balloon that an ocean diver takes to a pressure of 202 kPa.
The volume of the balloon will halve
Explanation:
Boyle's law states that for an ideal gas kept at constant temperature, the pressure of the gas is proportional to its volume. Mathematically,
[tex]pV=const.[/tex]
where
p is the gas pressure
V is the volume
The equation can also be rewritten as
[tex]p_1 V_1 = p_2 V_2[/tex]
And if we apply it to the gas inside the balloon in this problem (assuming its temperature is constant), we have:
[tex]p_1 = 101 kPa[/tex] is the initial pressure at sea level (the atmospheric pressure)
[tex]V_1[/tex] is the initial volume
[tex]p_2 = 202 kPa[/tex] is the final pressure
[tex]V_2[/tex] is the final volume
Substituting into the equation, we find:
[tex]V_2 = \frac{p_1 V_1}{p_2}=\frac{(101)V_1}{202}=\frac{V_1}{2}[/tex]
Which means that the volume of the balloon will halve.
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A 15 kg object starts for rest and is pushed across a frictionless surface e with a force of 30 N for 4 seconds
Calculate the final momentum
The final momentum is 120 kg m/s
Explanation:
According to the impuls theorem, the impulse exerted on an object (the product of force applied and time interval) is equal to its change in momentum. Mathematically:
[tex]F \Delta t = \Delta p = p_f - p_i[/tex]
where
F is the average force on the object
[tex]\Delta t[/tex] is the time interval during which the force is applied
[tex]p_f[/tex] is the final momentum
[tex]p_i[/tex] is the initial momentum
In this problem:
F = 30 N is the force applied
[tex]\Delta t = 4 s[/tex] is the time interval
[tex]p_i = 0[/tex] is the initial momentum, since the object starts from rest
Solving for [tex]p_f[/tex], we find the final momentum:
[tex]p_f = F\Delta t=(30)(4)=120 kg m/s[/tex]
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A student sitting in a merry-go-round has an acceleration of 3.6 m/s2. If the tangential velocity of the student is 2.5 m/s, what is the distance of the student from the center of the merry-go-round?
Answer:
The distance of the student from the center of the merry-go-round is, r = 1.74 m
Explanation:
Given,
The acceleration of the student in merry go round, a = 3.6 m/s²
The tangential velocity of the student is, v = 2.5 m/s
The acceleration of the merry go round is given by the formula,
a = v² / r
Therefore,
r = v² / a
= 2.5² / 3.6
= 1.74 m
Hence, the distance of the student from the center of the merry-go-round is, r = 1.74 m
What is a watt a unit of?
power
distance
time
light
Answer:
I think the answer is A) Power
Explanation:
Answer:
The answer A. Power
Explanation:
the volume of ice block is 2400cm^3 and its density is 0.9 g/cm^3. how much part of it remains above the surface of water when it is kept in water?
Answer:
240 cm³
Explanation:
Weight = Buoyancy
mg = ρVg
m = ρV
(0.9 g/cm³ × 2400 cm³) = (1 g/cm³) V
V = 2160 cm³
The submerged volume is 2160 cm³, so the volume above the surface is 240 cm³.
A 30 N force is applied to an object, which then accelerates at 3 m/s2. What
is the mass of the object?
O
A. 10 kg
O B. 3.0 kg
O C. 90 kg
O D. 33 kg
Answer:
the mass of the object is 10 kg
Explanation:
In the image attached, we can see the free body diagram and using the newton's second law of movement, we will have one equation with one unknown value (the mass of the object).
where:
m [kg]
a [m/s^2]
F [N] or [kg*m/s^2]
Answer:
10kg
Explanation:
The information we have is:
Force: [tex]F=30N[/tex]
acceleration: [tex]a=3m/s^2[/tex]
What we need to know is the mass of the object. For this we can use Newton's second law:
[tex]F=ma[/tex]
Where F is the Force applied, m is the mass of the object, and a is its acceleration.
from this equation we clear for the mass [tex]m[/tex]:
[tex]m=\frac{F}{a}[/tex]
and we substitute the known values:
[tex]m=\frac{30N}{3m/s^2}=10kg[/tex]
The mass of the object is 10kg
Investigators are working on a case where they need to know whether a watch will stop when it is dropped. In order to have a verified or reliable answer to this question, what should they do?
Call the manufacturer to ask whether it will stop under these circumstances
Drop a similar watch multiple times and record the results
Consult with more senior forensic scientists for their experiences
Take the watch apart and test the mechanism to see what causes failure
In order to have a verified or reliable answer to this question, they should take the watch apart and test the mechanism to see what causes failure.
Answer: Option D
Explanation:
For dropping a similar watch to record results, we need to buy another one. So, it becomes expensive. And, calling the manufacturer will give accurate results, but no knowledge. It is like getting multiple choices by luck.
Consulting senior faculty won’t result in any progress, because they may not have conducted these. So, one should rip off the watch, and study the mechanism, and its limitations. The testing of mechanism gives the actual results.
Answer: B) Drop a similar watch multiple times and record the results.
Explanation:
In order to have a verified or reliable answer to this question, investigators must drop a similar watch multiple times and record the results. By doing this and repeatedly getting the same result(s), they are able to determine that their answer is in fact true.
*** I would also like to note that I got this question right on a test. Cheers!