Mr. Baker’s fifth grade class of buried a time capsule in the field behind the school they drew a map and mark the location of the capsule with an ax so that his class can dig it up in 10 years what could Mr. Baker’s class have done to make the capsule easier to find

Answers

Answer 1
They could have added measurements on the map so they know the exact distance of the capsule from other objects around the school.

The could have create an actual physical marker on the ground at the location of a capsule, like a sign, rock or flag.

Related Questions

There are 453.592 grams in one pound . A semi slick , Kevlar tire weighs about 520 grams . What is the tires weighs in pounds ?

Answers

Convert 520 gr to lb:

520 gr        1 lb
--------- * -------------- = 1.15 lb (answer)
     1        453.6 gr

"What is the tire's weight in pounds?"

Math Financial Literacy HELP

Answers

It should be 211 B
Since her taxabnle income is at least 39,250 but less than 38300 her tax is 5944 but she paid 6155. 6155-5944=211

4.05E+9 In scientific notation ?

Answers

Hewooo 

the picture below should help you :>

4.05E+9 in scientific notation is 4.05 x 10^9.

4.05E+9 in scientific notation is 4.05 × 109. When a number is given in scientific notation, the coefficient is multiplied by 10 raised to the power of the exponent.

which types of triangles can be formed by taking the cross section of a cube

Answers

Equilateral, isosceles, and scalene are the type of triangles that can be formed by taking the cross section of a cube.


Hope this helps!!

For the equation, y= -x - 4, tell whether it’s graph passes through the first quadrant. Explain how you know.

A.) No; for x<0 the y-values are negative.

B.) Yes; for x>0 some y-values are positive.

C.) No; for x>0 the y-values are negative.

D.) Yes; for x<0 some y-values are positive.

Answers

Final answer:

The graph of the equation y = -x - 4 does not pass through the first quadrant because for x < 0, the y-values are negative.

Explanation:

The given equation is y = -x - 4. To determine whether its graph passes through the first quadrant, we need to assess the values for x and y. In the first quadrant, both x and y values are positive.

If we substitute any positive value for x into the equation, we will obtain a negative value for y. Therefore, the graph does not pass through the first quadrant. Hence, the correct answer is option A.

Please need some help on this

Answers

13/90
Because he got 5 thirteen times out 90 times

Ricardo just received a shipment of 50 tool sheds for his garden supply store. Each shed costs him $40. Which of the following could Ricardo use to find the total amount he will pay for the tool sheds?

Answers




50• 40= $2000
The answer is multiply 50 and 40

Ricardo will calculate the total amount he will pay for the 50 tool sheds by multiplying the quantity (50 sheds) by the cost per shed ($40), which equals $2,000.

To calculate the total amount Ricardo will pay for the 50 tool sheds he received, he needs to multiply the number of sheds by the cost per shed. Since each shed costs him $40, the calculation to find the total cost is as follows:

Multiply the quantity of tool sheds by the cost per shed: 50 sheds imes $40 per shed.

Calculate the product to find the total cost: 50 imes $40 = $2,000.

Therefore, Ricardo will pay a total of $2,000 for the 50 tool sheds.

Ken's cafe serves hot cocoa.each serving has 9 grams of chocolate.how many grams of chocolate are in 8 servings of hot cocoa?

Answers

multiply 9 * 8

answer = 72 grams

30 deciliters he already has 1 liter.How many liters of milk will he need to buy?

Answers

STEP 1:
find number of liters in 30 deciliters

1 deciliter= 0.1 liter

multiply total number of deciliters (30) by liters in one deciliter (0.1).

=30 * 0.1 liter
=3 liters


STEP 2:
subtract 1 liter from step 1 answer because he already has one liter

= 3 liters - 1 liter
= 2 liters still needed


ANSWER: He needs to buy 2 liters

Hope this helps! :)

The table shows summary statistics for guests' ages at two parties.

Party Median age (years) Range (years)
1 17 27
2 19 20
Which conclusion is true?


A. A typical guest at Party 1 was younger than a typical guest at Party 2, and guests' ages were more variable at Party 1 than at Party 2.

B. A typical guest at Party 1 was younger than a typical guest at Party 2, and guests' ages were less variable at Party 1 than at Party 2.

C. A typical guest at Party 1 was older than a typical guest at Party 2, and guests' ages were more variable at Party 1 than at Party 2.

D. A typical guest at Party 1 was older than a typical guest at Party 2, and guests' ages were less variable at Party 1 than at Party 2.

Answers

median age of 1 is 17, median age of 2 is 19 so the average age of party 1 is younger

the range of 1 is 27, the range of 2 is 20 so the range of 1 is larger, which means there is more variance
 the answer should be 

A. A typical guest at Party 1 was younger than a typical guest at Party 2, and guests' ages were more variable at Party 1 than at Party 2.
The answer is A... A typical guest at Party 1 was younger than a typical guest at Party 2, and guests' ages were more variable at Party 1 than at Party 2.

Pedro’s Father is building a shed how many square feet of wood are needed

Answers

I can't see the figure entirely. To solve for the perimeter you need to know the height!
Use the formula for the triangle A= 1/2bh
For the rectangle A= lw
Use the formulas and add the answer you got for both formulas. Remember b stands for base, h stands for height, l stands for length, and w stands for width. When the when the “letters” are next to each other, like bh, that means to multiply.
The answer should be 2 _ _ ft squared
Try to figure out what the other two missing numbers are! The answer begins with 2, good luck!

find the limit of (sqrt(x+5)-4)/(x-11) as x approaches 11

Answers

[tex] \lim\limits_{x\to11}\dfrac{\sqrt{x+5}-4}{x-11}=\lim\limits_{x\to11}\dfrac{(\sqrt{x+5}-4)(\sqrt{x+5}+4)}{(x-11)(\sqrt{x+5}+4)}\\\\=\lim\limits_{x\to11}\dfrac{(\sqrt{x+5})^2-4^2}{(x-11)(\sqrt{x+5}+4)}=\lim\limits_{x\to11}\dfrac{x+5-16}{(x-11)(\sqrt{x+5}+4)}\\\\=\lim\limits_{x\to11}\dfrac{x-11}{(x-11)(\sqrt{x+5}+4)}=\lim\limits_{x\to11}\dfrac{1}{\sqrt{x+5}+4}=\dfrac{1}{\sqrt{11+5}+4}\\\\=\dfrac{1}{\sqrt{16}+4}=\dfrac{1}{4+4}=\dfrac{1}{8}\\\\Answer:\ d.\ \dfrac{1}{8} [/tex]

write and solve an inequality to represent the situation

Answers

You can use the inequality:

9.5 + 3.75e < 25

9.5 is for the necklace, 3.75e is for every earring, and 25 is the amount Dani wants to stay under. Make everything she spends less than, <, 25.

Roy borrows $42,000 to purchase a new truck. How much will Roy need to pay in all if the interest is compounded annually at 3.5% for 10 years? (5 points) $43,125.00 $63,624.00 $59,245.15 $51,709.00

Answers

The formula to determine yearly compound interest is 

[tex]a= p(1+r) ^{t} [/tex]

a- amount 
p- Is the principal the principal is the amount borrowed
r- is the rate
t- is the time

We will input all the numbers from our question into the formula. 

[tex]a= 42,000(1+0.035) ^{10} [/tex]

Our rounded calculation is 59245.15

Roy will have to pay 59245.15 

Match the trinomials with their factors. Tiles a2 + a − 20 a2 − 9a + 20 a2 − 8a − 20 a2 − 12a + 20 a2 − 19a − 20 Pairs Factors Trinomials (a − 4)(a − 5) arrowBoth (a − 10)(a − 2) arrowBoth (a − 4)(a + 5) arrowBoth (a − 10)(a + 2) arrowBoth

Answers

For this case we have to factorize the following trinomials as the product of two binomials.
 We have then:
 a2 + a - 20
 (a + 5) (a-4)

 a2 - 9a + 20
 (a-5) (a-4)

 a2 - 8a - 20
 (a-10) (a + 2)

 a2 - 12a + 20
 (a-10) (a-2)

 a2 - 19a - 20
 (a-20) (a + 1)

Trinomial [tex]a^2 + a - 20[/tex] with factors (a + 5)(a - 4)
Trinomial [tex]a^2 - 9a + 20[/tex] with factors (a - 4)(a - 5)
Trinomial [tex]a^2 - 8a - 20[/tex] with factors (a - 10)(a + 2)
Trinomial [tex]a^2 - 12a + 20[/tex] with factors (a - 10)(a - 2)

To match the trinomials with their factors, we can factor each trinomial and compare the factors given:
1. Factorizing trinomial [tex]a^2 + a - 20:[/tex]
The factors are (a + 5)(a - 4).
This matches with the pair (a - 4)(a + 5).
2. Factorizing trinomial [tex]a^2 - 9a + 20:[/tex]
The factors are (a - 4)(a - 5).
This matches with the pair (a - 4)(a - 5).
3. Factorizing trinomial [tex]a^2 - 8a - 20[/tex]:
The factors are (a - 10)(a + 2).
This matches with the pair (a - 10)(a + 2).
4. Factorizing trinomial [tex]a^2 - 12a + 20:[/tex]
The factors are (a - 10)(a - 2).
This matches with the pair (a - 10)(a - 2).
Therefore, the correct matches are:
- Trinomial [tex]a^2 + a - 20[/tex] with factors (a + 5)(a - 4)
- Trinomial [tex]a^2 - 9a + 20[/tex] with factors (a - 4)(a - 5)
- Trinomial [tex]a^2 - 8a - 20[/tex] with factors (a - 10)(a + 2)
- Trinomial [tex]a^2 - 12a + 20[/tex] with factors (a - 10)(a - 2)

Monica measures 91 milliliters of water into 9 tiny beakers. she measures an equal amount of water into the first 8 beakers. she pours the remaining water into the ninth beaker.It measures 19 milliliters. how many milliliters of water are in each of the first eight beakers

Answers

To determine the amount of water in the first 8 beakers, you will subtract the 19 ml that are in the 9th beaker from the total to see how much water was actually put into the first 8 beakers.

91 ml - 19 ml = 72 ml.

The 72 ml are divided evenly between 8 beakers.

72/8 = 9 ml

There would be 9 ml of water in each of the first 8 beakers.

What is the solution to this system of equations?

2/3x + y = 6

-2/3x - y = 2

A. (1, -1)
B. (0, 8)
C. infinitely many solutions
D. no solution

Answers

D. No solution since the two lines have the same slope. 
Final answer:

When the given system of equations is added together, it simplifies to '0=8', which is a contradiction. Therefore, the system of equations has no solution.

Explanation:

You can simply add the two equations together. Adding the two equations eliminates the variables x and y:

(2/3x - 2/3x) + (y - y) = 6 + 2

This simplifies to 0 = 8, which is a contradiction. Therefore, this system of equations has no solution. That means the correct answer is D. 'No solution'.

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Sharon is paving a rectangular concrete driveway on the side of her house. The area of the driveway is 5x^2 + 43x - 18, and the length of the driveway is x + 9.

Additionally, Sharon plans to install a carport over a small portion of the driveway. The volume that the carport can enclose is 48x^3 + 68x^2 - 8x - 3, and the area of driveway beneath the carport is 8x^2 + 10x - 3.

Determine the width of the entire driveway and height of the carport in terms of x. Replace the values of m and b to complete the expression that represents the width of the entire driveway on the first line, and then replace the values of m and b to complete the expression that represents the height of the carport on the second line.

You have to type the answer in mx+b
im just trying to graduate....

Answers

The width of the driveway is 5x-2.
The height of the carport is 6x+1.

We complete polynomial long division for both of these.  

For the driveway:
Dividing 5x²+43x-18 by x+9, we first see how many times x will go into 5x².  It goes in 5x times; we write this in the division problem above 43x.  Multiplying back through, 
5x(x+9) = 5x²+45x.  This goes below 5x²+43x.  We now subtract:
5x²+43x-(5x²+45x)= -2x; this goes below the 45x we wrote earlier.  Bring down the -18.
Now we see how many times x goes into -2x; it goes -2 times.  This goes beside our 5x in our answer at the top.  Multiplying back through,
-2(x+9) = -2x-18.  This goes below our -2x-18 we had, and gives us an answer of 5x-2 with a remainder of 0.

For the carport:
To divide 48x³+68x²-8x-3 by 8x²+10x-3, we see how many times 8x² will go into 48x³.  It will go 6x times; write this above -8x.  Multiplying back through,
6x(8x²+10x-3) = 48x³+60x²-18; write this below 48x³+68x²-8x.  Now subtract:
48x³+68x²-8x-(48x³+60x²-18) = 8x²+10x; this goes below our 48x³+60x²-18.  Bring down the -3.
Now we want to see how many times 8x² will go into 8x².  It goes 1 time; write this beside our 6x at the top.  Multiplying back through, 
1(8x²+10x-3) = 8x²+10x-3; write this below the 8x²+10x-3 we have already down.  When we subtract these, we get a remainder of 0, with our answer up top as 6x+1.

Answer:

Width: 5x-2

Height: 6x+1

Step-by-step explanation:

Write the standard form of the equation of the circle with the radius of 12 and center at the origin.

Answers

a circle is written as x^2+y^2=r^2. if the center is at the origin, it doesnt need to be vertically or horizontally. you would square the radius, 12, and set it equal to x^2+y^2. the final equation is x^2+y^2=144

The standard form of the equation of the circle with the radius of 12 and center at the origin is,

⇒ x² + y² = 144

What is mean by Circle?

The circle is a closed two dimensional figure , in which the set of all points is equidistance from the center.

Given that;

the radius of circle is, 12 and center at the origin.

Now, We know that;

Standard form of circle with center origin and radius r is,

⇒ x² + y² = r²

Here, r = 12

Hence, The standard form of the equation of the circle with the radius of 12 and center at the origin is,

⇒ x² + y² = 12²

⇒ x² + y² = 144

Thus, The standard form of the equation of the circle with the radius of 12 and center at the origin is,

⇒ x² + y² = 144

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Simplify the expression. (3.14×107)×(1.3×10−3)÷0.2
Scientific notation PLS!

Answers


[tex]3.14 \times 107 = 335.98[/tex]
[tex](335.98) \times (1.3 \times 10 - 3) \div 0.2[/tex]
[tex]1.3 \times 10 = 13 - 3 = 10[/tex]
[tex](335.98) \times (10) \div 0.2[/tex]
[tex]335.98 \times 10 = 3359.8[/tex]
[tex]3359.8 \div 0.2 = 16799[/tex]
[tex]1.6799 \times {10}^{4} [/tex]


Solve for x (Round to the nearest hundredth)

Answers

[tex]\tan37^o=\dfrac{x}{48}\\\\\tan37^o\approx0.78\\\\\dfrac{x}{48}=0.78\ \ \ |\cdot48\\\\\boxed{x=37.44}[/tex]

The diameter of a DVD is 12 centimeters. The hole in the center of a DVD has a diameter of 1.5 centimeters. Find the area of the DVD. Round to the nearest hundredth if necessary.

Answers

111.27 centimeter squared.

The area of the circular DVD is given by A = 111.33 cm²

What is a Circle?

A circle is a closed figure in which the set of all the points in the plane is equidistant from a given point called “center”. Every line that passes through the circle forms the line of reflection symmetry. Also, the circle has rotational symmetry around the center for every angle

The circumference of circle = 2πr

The area of the circle = πr²

where r is the radius of the circle

The standard form of a circle is

( x - h )² + ( y - k )² = r²,

where r is the radius of the circle and (h,k) is the center of the circle.

The equation of circle is ( x - h )² + ( y - k )² = r²

For a unit circle , the radius r = 1

x² + y² = r² be equation (1)

Now , for a unit circle , the terminal side of angle θ is ( cos θ , sin θ )

Given data ,

Let the area of the circular DVD be A

Let the diameter of the DVD = 12 cm

So , the radius of the DVD = 6 cm

Now , the diameter of the hole = 1.5 cm

So , the radius of the hole = 0.75 cm

And , area of the circular DVD be A = π [ ( 6 )² - ( 0.75 )² ]

On simplifying , we get

The area of circular DVD is A = π ( 36 - 0.5625 )

The area of circular DVD is A = π ( 35.4375 )

The area of circular DVD is A = 111.33 cm²

Hence , the area of the circular DVD is 111.33 cm²

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30 POINTS - The tables below represent the profits earned by a merchandiser from four new consignments of t-shirts. Each consignment contained t-shirts of five different sizes. If we were to plot each of the t-shirt sizes and the profit earned on each new size, we would get a different graph for each consignment. Almost all the graphs showed some association between the two variables, except one consignment, which showed no association. Which of the following consignments shows no association?

Answers

The answer is the 2nd graph having a profit of 5, 15, 6, 18, and 10.
Graph 1, 3, and 4 showed a similar linear association, with the exception of graph 3 having a negative slope. In graph 2, however, the data is scattered which showed no association between the two variables.

Note: Refer to the attached pictures.

Can someone please help me with this.

Answers

V=πr²h/3

V4,3= 50.27

V2,12= 150.80

V3,10= 94.25

9. F is correct.

10. A= 4/3πr³

A=4/3(3.14)(7inch)³= 1436.03 inch³

11.
(w+7)+(-5)

w+(7-5)

(w+2)

So A is a correct simplification (w+2)

12. V=πr²h

V=(3.14)(8in)²(7inch)= 1406.72 inch³





Plz help identify the slope of 8x-3y=12 without graphing the line.

Answers

The slope of x or y?

Will mark as Brainliest.

The number of wild flowers growing each year in a meadow is modeled by the function f(x).

f(x)=[tex] \frac{1000}{1+9e^{-0.4x} } [/tex]

Which statements are true about the population of wild flowers?


Select each correct answer.


A. Initially there were 100 wild flowers growing in the meadow.

B. 42 more wildflowers will grow in the 11th year than in the 10th year.

C. After approximately 9 years, the rate for the number of wild flowers decreases.

D. In the 15th year, there will be 1050 wild flowers in the meadow.

Answers

b i hope this works !!!
I think it might be B if not I'm super sorry have a good day/night

convert: 7 tons 500 lb to lb

Answers

7 tons 500 lb equals 14500 lbs

Final answer:

7 tons and 500 pounds equals 14,500 pounds, which is calculated by converting tons to pounds and adding the additional pounds.

Explanation:

To convert 7 tons and 500 pounds to pounds only, follow these two steps:

Convert tons to pounds. Since 1 ton is equal to 2,000 pounds, you multiply the number of tons by 2,000. For 7 tons, it would be 7 × 2,000 = 14,000 pounds.

Add the additional pounds to the converted weight. So, you would add 500 pounds to 14,000 pounds, resulting in 14,500 pounds.

Therefore, 7 tons and 500 pounds is equivalent to 14,500 pounds.

Find the diameter of a sphere with the volume 7776pi in^3

Answers

Answer:

The diameter is 36 inches

Step-by-step explanation:

The volume of a sphere is

[tex] \frac{4}{3} \pi {r}^{3} [/tex]

The given sphere has volume

[tex]7776\pi {in}^{3} [/tex]

We can now equate the formula to the given volume and solve for r.

[tex]\frac{4}{3} \pi {r}^{3} = 7776\pi[/tex]

[tex] {r}^{3}= 7776\pi \times \frac{3}{4\pi} [/tex]

[tex] {r}^{3} = 5832[/tex]

[tex]r = \sqrt[3]{5832} [/tex]

[tex]r = 18[/tex]

The diameter of the sphere is twice the radius.

Hence

[tex]diameter = 2 \times 18 = 36in[/tex]

The list shows the scores made be each member of Jaime's discussion group on the last test. 69 79 62 93 73 81 73 78 Which box-and-whiskers plot correctly displays the information? f Box-and-whiskers plot G g Box-and-whiskers plot J h Box-and-whiskers plot F j Box-and-whiskers plot H

Answers

While I cannot see your plots to choose from, the correct box plot is attached.

Explanation
We first order the data from least to greatest:

62, 69, 73, 73, 78, 79, 81, 93

The median is the middle data value.  Since there is an even number of values, the median is between 73 and 78:
(73+78)/2 = 151/2 = 75.5

The Upper Quartile (UQ) is the median of the upper half of data, cut by the median.  This half has an even number of data points, so the UQ is between 79 and 81:
(79+81)/2 = 160/2 = 80

The Lower Quartile (LQ) is the median of the lower half of data, cut by the median.  This half has an even number of data points, so the LQ is between 69 and 73:
(69+73)/2 = 142/2 = 71

The center line of the box will be at 75.5, the median.  The left edge of the box is at the LQ, 71.  The right edge of the box is at the UQ, 80.  There is a whisker extending from the right side of the box to the highest value, 93.  There is a whisker extending from the left side of the box to the lowest value, 62.

Final answer:

To choose the correct box-and-whiskers plot for Jaime's discussion group scores, we must calculate the five key statistics and match them with a plot displaying those exact values, factoring in the majority of scores in the 70-89 range.

Explanation:

To determine which box-and-whiskers plot correctly displays Jaime's discussion group scores, we need to calculate five key statistics: the minimum, lower quartile (Q1), median (Q2), upper quartile (Q3), and the maximum. These statistics help us create an accurate box plot representation of the dataset.

First, we organize the scores in ascending order: 62, 69, 73, 73, 78, 79, 81, 93. From here, we can identify the minimum (62) and maximum (93) scores directly. The median score will be the average of the fourth and fifth scores since we have an even number of observations, which is (73+73)/2 = 73. The lower quartile (Q1) is the median of the lower half of the data, which would be (69+73)/2 = 71. The upper quartile (Q3) is the median of the upper half of the data, which is (79+81)/2 = 80.

Now that we have all the necessary statistics, we can select the box plot that matches these values. Jaime's scores are mostly within the 70-89 range, reflecting a majority of C and B grades, with a few scores in the 60-69 and 90-100 ranges, which correspond to D/F and A ranges respectively. The correct box-and-whiskers plot will show a box ranging from Q1 (71) to Q3 (80), a median line at 73, a whisker extending to the minimum score of 62, and another whisker extending to the maximum score of 93.

Your friend Zoe is very earnest about the benefits of her special diet. She believes that having kale for breakfast every day will lower your cholesterol.

4a. What's the best method for testing Zoe's claim: a survey, an observational study, or an experiment? Give at least one reason to support your answer. (4 points)

4b. Describe how you would set up a test to determine how much truth there is to Zoe's claims. In particular, what steps would you take to make sure the results were unbiased and valid?

Answers

- The best method to test Zoe's claim is an observational study, as with this method it is possible to observe if the claim presents some truth to it. Observational studies are often used in testing claims like Zoe's as they allowed to have a great access to the variable that are behind a claim of that type, and so they are also more accessible.

- The set up I would use is an observational study of a great number of people, over a long period of time, that have to have kale for breakfast every day, with a measurement of their cholesterol over the time. the great number and the long period of study assured that the variable subject of study is statistically represented in an optimal way. 
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