Answers
Lx = 180° - (90+90)
Lx is 70°
Lx = 180° -(64+71)
= 180° - 13J°
= 45°
By using sine law
21/siny = length of pole/ sin 64
∴Length of pole = 21 sin 64/sin u5 = 26.69
Then the length of pole = 27ft
Answer:
Length of the pole is 27ft. ( rouding up to the nearest foot)
Explanation:
To solve this problem you need to understand that the the shadow cast by the pole on the ground connected to the pole itself and to the imaginary line of sun light forms a triangle with 3 different angles, please see the drawing to a better understanding.
* The sum of the internal angles of any triangle must be 180° then;
α: angle of the elevation of the sun= 64°
angle of the pole to the ground= (90-19)= 71°
β = 180 - ( 64+71) = 45°
*To find the length of the pole we can use the law of Sines;
|BC| / sin (α) = |AC| / sin (β)
|BC|= Length of the pole
|AC|= shadow of the pole on the ground which is known to be 21 ft
|BC| / sin (64°) = 21 / sin (45°)
|BC|= 21 x [sin (64°)/ sin (45°)]
|BC|= 21 x 1.27≅ 26.67 ft
Related Questions
Two long parallel wires carry currents of 20 a and 5.0 a in opposite directions. the wires are separated by 0.20 m. what is the magnitude of the magnetic field midway between the two wires?
Answers
The magnitude of the magnetic field midway between two long parallel wires carrying currents of 20 A and 5.0 A in opposite directions and separated by 0.20 m is 4.5 x 10⁻⁵ T.
Explanation:To find the magnitude of the magnetic field midway between the two long parallel wires carrying currents of 20 A and 5.0 A in opposite directions and separated by 0.20 m, we can use the formula for the magnetic field due to a long straight wire. The magnitude of the magnetic field at a distance r from the wire is given by: B = (μ₀ * I) / (2π * r). Since we are looking for the magnetic field midway between the wires, the distance from each wire to the point is half of the total separation, which is 0.10 m. Plugging in the values, we get: B = (4π * 10⁻⁷ T·m/A * (20 A + 5.0 A)) / (2π * 0.10 m) = 4.5 x 10⁻⁵ T.
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The magnitude of the magnetic field midway between two parallel wires carrying currents of 20 A and 5 A in opposite directions and separated by 0.20 m is 3 * 10^-6 T.
Explanation:To find the magnitude of the magnetic field midway between the two wires, we can use the formula for the magnetic field produced by a long straight wire:
B = (μ0 * I) / (2πr)
where B is the magnetic field, μ0 is the permeability of free space, I is the current, and r is the distance from the wire. In this case, we have two wires with currents of 20 A and 5 A, and they are separated by 0.20 m. Since we are interested in the magnetic field midway between the wires, the distance r will be half of the separation between the wires, which is 0.20 m / 2 = 0.10 m.
Plugging in the values, we get:
B = (4π * 10-7 T·m/A * (20 A - 5 A)) / (2π * 0.10 m) = (4 * 10-7 T·m/A * 15 A) / (0.20 m) = 3 * 10-6 T
So, the magnitude of the magnetic field midway between the two wires is 3 * 10-6 T.
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Which of these is most likely to produce wastewater containing benzene and other hydrocarbons
Answers
An Oil Refinery (APEX)
which step makes proteins by binding amino acids together
Answers
A howler monkey is the loudest land animal and under some circumstances, can be heard up to a distance of 5.0 km. Assume the acoustic output of a howler to be uniform in all directions and that the threshold of hearing is 1.0*10^-12 W/m^2. The acoustic power emitted by the howler is closest to
a) 3.2 mW b) 0.11 mW c) 11 mW d) 1.1 mW e) .31 mW
Answers
[tex]I=1.0 \cdot 10^{-12}W/m^2[/tex]
and in order to hear the howler at a distance of 5 km, its sound should have at least this intensity.
The sound wave is emitted uniformly in all directions, so the area we should consider to calculate the power is the area of a sphere with radius
r=5 km=5000 m:
[tex]A=4 \pi r^2 = 4 \pi (5000 m)^2 =3.14 \cdot 10^8 m^2[/tex]
And by using these data, we can calculate the power emitted by the howler:
[tex]P=IA=(1.0 \cdot 10^{-12} W/m^2)(3.14 \cdot 10^8 m^2)=3.1 \cdot 10^{-4} W=0.31 mW[/tex]
So, the correct answer is E) 0.31 mW.
Name each type of symbiosis and explain how the two species are affected
Answers
snakes if there food chain is mesesed up it dont work no more
A neutral copper ball is suspended by a string. a positively charged insulating rod is placed near the ball, which is observed to be attracted to the rod. why is this? 1. the ball becomes positively charged by induction. 2. the string is not a perfect conductor. 3. there is a rearrangement of the electrons in the ball. 4. the ball becomes negatively charged by induction. 5. the number of electrons i
Answers
3. there is a rearrangement of the electrons in the ball.
In fact, the ball is made by copper, which is a good conductor, therefore its electrons are free to move on the surface of the ball. When the positively charged rod is placed near to the ball, the electrons in the ball re-arrange, in particular they are attracted from the positive charges of the rod so they move closer to it. And since opposite-sign charges attract each other, the ball is then attracted by the rod.
The copper ball is attracted to the rod because the electrons in the ball rearrange themselves, making one side of the ball negative and the other positive. This process is known as electrostatic induction. Thus, option 3 is correct.
A neutral copper ball is observed to be attracted to a positively charged insulating rod due to electrostatic induction. Here's a step-by-step explanation:
Rearrangement of Electrons: When the positively charged rod is brought close to the neutral copper ball, the electrons in the copper ball are attracted towards the rod because opposite charges attract each other.Induced Polarization: This movement causes the side of the ball closer to the rod to become slightly negative due to the accumulation of electrons, while the side farther from the rod becomes slightly positive due to the lack of electrons.Attraction: The negatively charged side of the copper ball is attracted to the positively charged rod, causing the ball to move towards the rod.Therefore, the correct reason for the observed attraction is the rearrangement of the electrons in the ball, making option 3 the correct answer.
PLEASE PLEASE HELP!?!?!!?
What is gravity? Gravity is the force (2 points) Select one: a. of attraction between two objects; it is not related to the object's mass. b. of attraction between two objects; it is related to the object's mass. c. that acts on objects when they are pushed d. that repels objects that have like charges
Answers
Good Luck ^-^
What are (a) the lowest frequency, (b) the second lowest frequency, and (c) the third lowest frequency for standing waves on a wire that is 10.9 m long, has a mass of 55.8 g, and is stretched under a tension of 253 n?
Answers
[tex]f_1 = \frac{1}{2L} \sqrt{ \frac{T}{m/L} } [/tex]
where
L is the wire length
T is the tension
m is the wire mass
In our problem, L=10.9 m, m=55.8 g=0.0558 kg and T=253 N, therefore the fundamental frequency of the wire is
[tex]T= \frac{1}{2L} \sqrt{ \frac{T}{m/L} }= \frac{1}{2 \cdot 10.9 m} \sqrt{ \frac{253 N}{0.0558 kg/10.9 m} }= 10.2 Hz[/tex]
b) The frequency of the nth-harmonic for a standing wave in a wire is given by
[tex]f_n = n f_1[/tex]
where n is the order of the harmonic and f1 is the fundamental frequency. If we use n=2, we find the second lowest frequency of the wire:
[tex]f_2 = 2 f_1 = 2 \cdot 10.2 Hz=20.4 Hz[/tex]
c) Similarly, the third lowest frequency (third harmonic) is given by
[tex]f_3 = 3 f_1 = 3 \cdot 10.2 Hz = 30.6 Hz[/tex]
1. Which of the following statements about mechanical waves is true?
a. mechanical waves require a medium to travel through
b. mechanical waves do not have amplitude and wavelength
c. mechanical waves do not have frequency
d. mechanical waves can travel through blank space
2. Which waves have the shortest wavelength and highest energy on electromagnetic spectrum?
a. microwaves
b. x-rays
c. infrared
c. gamma rays
3. What is true about infrared and X-Rays?
a. X-Rays have greater longer wavelength than infrared
b. Infrared have shorter wavelength than x-rays
c. x-rays have lower energy than infrared
d. Infrared have lower frequency than x-rays
4. In a longitudinal wave (compression wave_ the particles of a matter move ______
a. perpendicular (at right angles)
b. in a circular direction
c. backwards
d. parallel
5. In regard to spend of sound, sound travels slowest in ____
a. solids
b.liquids
c. gases
Answers
In fact, mechanical waves cannot travel trough empty space, but they always require a medium for their propagation. (on the contrary, electromagnetic waves can also travel through empty space)
2) d. gamma rays
In fact, gamma rays are the radiations with shortest wavelength on the electromagnetic spectrum (range in the picometer). Correspondingly, this is the radiation with highest energy, because the energy of the radiation is inversely proportional to its wavelength, according to:
[tex]E=h \frac{c}{\lambda} [/tex]
where h is the planck constant, c the speed of light and [tex]\lambda[/tex] the wavelength.
3) d. Infrared have lower frequency than x-rays
In fact, infrared radiation has frequency in the range of the THz (terahertz, [tex]10^{12} Hz[/tex]), while x-rays have frequency in the range of hundreds of PHz (Petahertz, [tex]10^{15}Hz[/tex]).
4) d. parallel
In longitudinal waves, the oscillations of the wave (such as the motion of the particles in a compression wave) occur in the direction parallel to the direction of propagation of the wave itself.
5) c. gases
Sound travels slowest in gases. In fact, the speed of sound is proportional to the density of the medium: the more dense the medium is, the faster is the sound in that medium, and vice-versa. Since gases are less dense than liquids and solids, sound travels slowest in gases. The reason is that sounds propagates through the oscillations of the molecules of the medium; if the medium is less dense (such as in gases), it takes more time to transmit the sound through the medium itself.
Mechanical waves require a medium to travel, gamma rays have the highest energy and shortest wavelength on the electromagnetic spectrum, x-rays have higher frequency than infrared, particles in a longitudinal wave move in parallel, and sound travels slowest in gases.
Explanation:1. The correct statement about mechanical waves is 'a. mechanical waves require a medium to travel through'. Unlike electromagnetic waves, mechanical waves, such as sound or seismic waves, need a medium like air, water, or solids to propagate or move.
2. The waves with the shortest wavelength and highest energy on the electromagnetic spectrum are 'c. gamma rays'.
3. The true statement about infrared and X-Rays is 'd. Infrared has lower frequency than x-rays'. X-rays have a higher frequency and shorter wavelength compared to infrared waves, which directly impacts their energy levels, with X-rays having higher energy.
4. In a longitudinal wave (compression wave), the particles of matter move 'd. parallel' to the direction of the wave's propagation. This is different from transverse waves where particles move perpendicular to the wave direction.
5. Sound travels slowest in 'c. gases'. Sound waves travel the fastest through solids, slower through liquids, and slowest through gases.
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How many new elements (fission fragments, or daughter nuclei) are typically presented as a result of fission?
1
3
2
5
Answers
Nuclear fission refer to a nuclear reaction in which the nucleus of a single radioactive element is split into two different smaller nuclei, which are different from the parent element accompany with the release of energy. Nuclear fission is typically used to produce energy. The two smaller nuclei are called fission products.
True or false: the coefficient of thermal expansion governs the way a substance expands or contracts when it is heated or cooled
Answers
which form of energy is involved in weighting fruit on a spring scale ?
Answers
I hoped this helped!
Hope that helps!!!!
Place the notebook on a table, and push it a few inches with your finger. When it moves, it has kinetic energy. Which kind of force opposed the motion of the notebook?
Answers
Answer:
The force of friction opposed the motion of the notebook.
Explanation:
Plato answer
If the building absorbed so much heat that it turned into a liquid, then it would have undergone a phase change known as _____.
freezing
vaporizing
condensing
melting
Answers
Answer:
Melting
Explanation:
If the building absorbed so much heat that it turned into a liquid, then it would have undergone a phase change known as:
freezing. NO. Freezing is the process in which a liquid turns into a solid.vaporizing. NO. Vaporizing is the process in which a liquid turns into a gas.condensing. NO. Condensing is the process in which a gas turns into a liquid.melting. YES. Melting is the process in which a solid turns into a liquid.At what speed does the classical momentum, p=mv, give an error, when compared with the relativistic momentum, of 1.35 % ?
Answers
[tex]p_c=mv[/tex]
where m is the particle mass and v its velocity, while the relativistic momentum is given by:
[tex]p_r=\gamma mv[/tex]
where
[tex]\gamma = \frac{1}{ \sqrt{1- \frac{v^2}{c^2} } } [/tex] (1)
is the relativistic factor, with c being the speed of light.
The condition given by the problem (error of 1.35%) can be rewritten as
[tex] \frac{p_r - p_c}{p_r} = 0.0135 [/tex]
which means
[tex]p_r = \frac{p_c}{0.9865} [/tex]
and since [tex]p_r = \gamma p_c[/tex], this also means that
[tex]\gamma = \frac{1}{0.9865}=1.0137 [/tex]
Now let's re-arrange eq.(1), and we get
[tex]v=c \sqrt{1- \frac{1}{\gamma^2} } [/tex]
and if we use [tex]\gamma=1.0137[/tex] as we found before, and [tex]c=3 \cdot 10^8 m/s[/tex], we find the corresponding velocity:
[tex]v=(3 \cdot 10^8 m/s) \sqrt{1- \frac{1}{(1.0137)^2} } = 4.9 \cdot 10^7 m/s[/tex]
To calculate the speed at which the classical momentum gives an error compared to the relativistic momentum, we need to find the ratio of the two different momenta. This can be done by solving for the velocity using the given equations and approximations.
Explanation:The classical momentum, p=mv, gives an error when compared with the relativistic momentum. The error can be calculated by finding the ratio of the relativistic momentum to the classical momentum. In this case, the error is 1.35%. To find the velocity at which this error occurs, we need to solve for the velocity using the given equations and approximations.
(a) Find the momentum of a 1.00 × 10⁹ kg asteroid heading towards the Earth at 30.0 km/s.
(b) Find the ratio of this momentum to the classical momentum. (Hint: Use the approximation that y = 1+(1/2)v²/c² at low velocities.)
For an isolated system, the law of conservation of momentum is valid: A. for inelastic collisions. B. for elastic collisions. C. only when there are no collisions. D. for all types of collisions.
Answers
D. for all types of collisions.
In fact, for an isolated system, the law of conservation of momentum is always valid. Instead, kinetic energy is conserved only when the collision is elastic, while for inelastic collisions kinetic energy is not conserved.
The law of conservation of momentum is valid in isolated systems for all types of collisions, both elastic and inelastic.
The law of conservation of momentum is valid for an isolated system, meaning that no net external force is acting on the system. This principle applies to both types of collisions: elastic collisions and inelastic collisions. In elastic collisions, not only is momentum conserved, but kinetic energy is also conserved. In inelastic collisions, however, while kinetic energy is not conserved, the conservation of momentum still holds true. Therefore, for an isolated system, the law of conservation of momentum is valid for all types of collisions, regardless of whether they are elastic or inelastic.
What is the resistance of a resistor if the potential differences across the resistor is 4v when a cirrent of 10 a flow through the resistor?
Answers
Three 1.2 ohm lamps are connected in series and connected to a 3 volt battery. Calculate the total current in the circuit
Answers
[tex]R_{eq} =R_1+R_2+R_3=1.2 \Omega + 1.2 \Omega +1.2 \Omega = 3.6 \Omega[/tex]
And the total current flowing in the circuit can be calculated by using Ohm's law:
[tex]I= \frac{V}{R_{eq}} [/tex]
where V is the voltage of the battery. By using V=3 V, we find
[tex]I= \frac{3 V}{3.6 \Omega}= 0.83 A[/tex]
A feather of mass 0.001 kg falls from a height of 2 m under realistic conditions it experiences air resistance based on what you know about friction what can you say about the kinetic energy of the feather as it reaches the ground
Answers
Answer:
KE < 0.0196 J
Many __________ cause poor pupil function more quickly than alcohol does.
A. Pain relievers
B. Antihistamines
C. Tranquilizers
D. Benzodiazepines
Answers
Answer:
B. Antihistamines
Explanation:
Whenever you have an allergy, your body creates a chemical called histamines. For a short term treatment against there allergies, you can take antihistamines. However, among the side effects of this treatment is poor pupil function.
So the correct answer is:
B. Antihistamines
Ryan is experimenting with core materials for an electromagnet. he slides different for materials to a quail of current caring wire. sort the court materials based on whether they will or will not increase the strength of Ryan's electromagnet.
Answers
The bigger the strength of Ryan's electromagnet, the better the conductivity of the material.
The material is as follows,
1. Silver and it is the best conductor.
2. Iron.
3. Nickel
4. Steel.
5. Glass which is an insulator, and
6. wood which is an insulator, and we thoroughly know that insulators they don't conduct electricity.
Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. You have determined that the football would travel 15.1 m before landing. How would this value change if the football was kicked at an angle of 35.0°?Complete all equations without rounding and then round to the nearest tenth at the end.
Answers
R = [v^2* Sin 2Ф]/g, where R = horizontal range, Ф = angle, v = initial velocity, g=gravitational acceleration.
The missing value is the exact gravitational acceleration. Therefore,
g = [v^2*Sin 2Ф]/R = [13.9^2*Sin (2*25)]/15.1
At Ф = 35°;
R = [13.9^2*Sin (2*35)]/ {[13.9^2*Sin (2*25)]/15.1} = [15.1*Sin 70]/[Sin 50] ≈ 18.5 m
Therefore, if the ball was kicked at 35.0°, it would travel to 18.5 m before landing.
Answer:
If the football is kicked at a 35.0º angle, it will travel 18.5 m before landing. This is farther than if it were kicked at a 25° angle.
Explanation:
what it says on edge
Calculate the quantity of energy produced per gram of reactant for the fusion of h-3 (atomic mass = 3.016049 amu) with h-1 (atomic mass = 1.007825 amu) to form he-4 (atomic mass = 4.002603 amu).
Answers
There is a mass difference because it is being converted into energy.
Mass difference is 0.021271 amu
If it is converted to equivalent to grams per mole.
Equal to 0.000021271 kg
By using the Einsteins equation, E= mc∧2.
Per mole is
E=0.000021271 × 299792458∧2J
E = 1.91174 × 10∧12 J per mole
The reactant of one mole is 4.02387 grams
The energy which is being released per gram of reactant is 4.751 × 10∧11J/g
The energy produced per gram of reactant for the fusion of H-1 with H-3 to form He-4, can be calculated using the difference of total initial and final masses, which is then used in Einstein's mass-energy equivalence principle (E=mc²). The number of such reactions in 1 gram of reactant is used to convert the energy per reaction to energy per gram of reactant.
Explanation:To calculate the energy produced per gram of reactant in fusion reaction, first let's understand what's happening in the fusion reaction of H-3 with H-1. A helium nucleus is formed with a mass that is 0.7% less than that of four hydrogen nuclei. This mass loss is converted into energy.
The masses of the reactants are 3.016049 u for H-3 and 1.007825 u for H-1, giving us a total initial mass of 4.023874 u. The mass of the helium atom produced, He-4, is 4.002603 u. The mass loss during the reaction equals initial mass minus final mass, which is 0.021271 u.]
Applying Einstein's mass-energy equivalence principle E=mc², where E is energy, m is the lost mass and c is the speed of light, the energy produced in the reaction, can be calculated. To convert amu to kilograms, multiply by 1.66054 x 10⁻²⁷. So, the mass lost is 3.53 x 10⁻²⁹ kg.
As speed of light c = 3 x 10^8 m/s, using the equation we get E = 3.53 x 10⁻²⁹ kg x (3 x 10⁸m/s)² = 3.18 x 10⁻¹²Joules.
Finally, to get the energy per gram, we calculate the number of such reactions in 1 gram of reactants. That would be (1 g)/(4.023874 g/mol) x Avogadro's number (6.02 x 10^23). Multiply this number with the energy produced per reaction to get the energy produced by 1 gram of reactant.
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Please help 10 points
Answers
The intensity of the sun's radiation incident upon the earth is about i=1.4kw/m2. suppose this is the value for the intensity of sunlight incident upon the satellite's solar panels. what is the total solar power p absorbed by the panels?
Answers
⇒ Power absorbed = 1× A ⇒ 1.4 × 10∧3 ×(10)
= 14000 Watt = 14 kWatt
time - averaged intensity divided by speed of light in free space is the radiation pressure
P = (1.4 × 1000)/c
Force = pressure × area ⇒ ((1.4× 1000)/(10∧8)) × 10
= 0.00004666666N
0.000047N
The fundamental frequency of a pipe that is open at both ends is 564 hz . part a how long is this pipe?
Answers
l= k / 2
l= length of the pipe
k=wave length of the pipe
there fore 2l = k
we have
f = v k
f = frequency of the wave
v = velocity of the wave
k = wave length of the pipe
f = v k
f = v (2l)
l = f / 2v
l= 564 / (2 * 344)
l= 564/ 688
l =.82m
l=82m
The length of the pipe, if The fundamental frequency of a pipe that is open at both ends is 564 Hz, is 82 cm.
What is the frequency?Frequency is defined as the no of waves that are passing from the point in respect to a given time. Frequency can be measured in Hertz. Humans, whose capacity to hear is normal, can hear between the frequency of 20 Hertz to 20000 Hertz.
Given:
The frequency, f = 564 Hz,
Calculate the length by the formula given below,
[tex]l= k / 2[/tex]
2l = k
Calculate the length of the pipe by the formula given below,
[tex]f = v k[/tex]
f = v (2l) [Substitute the value of k]
l = f / 2v
l = 564 / (2 × 344)
l= 564 / 688
l = 0.82 m or 82 cm
Therefore, the length of the pipe, if The fundamental frequency of a pipe that is open at both ends is 564 Hz, is 82 cm.
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An automotive research facility is testing a new design on bumpers to determine the force at which it will break. The formula for Force is F = 1 2 m v 2 Where m is the mass (weight) and v is the velocity (speed)What is the effect on the force if the velocity changes from 5 miles per hour to 10 miles per hour?
What is the effect on the force if the velocity changes from 5 miles per hour to 10 miles per hour?
Same
Twice as much
Four times as much
Five times as much
Answers
Call (F2) the force produced with a speed of 10 miles per hour.
To know what the effect on force is, change the speed from 5 miles per hour to 10 miles per hour, divide F2 / F1 to find the relation.
So:
F2 / F1 = (12m * 10²) / (12m * 5²)
F2 / F1 = 4.
Therefore, the answer is option 3.
Strength increases 4 times more
In the circuit diagram, what does the line segment with two circles at the ends represent?
an electrical conductor
a source of electrical energy
an electrical resistor
a closed switch
Answers
That is a symbol for a closed switch meaning that current flows through the wire. If the line between the two circles wasn't connected to one of the circles, then it would be an open circuit in which current doesn't flow through the wire.
Answer: closed switch
Explanation:
Closed switch is when current is allowed to flow freely without hindrance.
Organ pipe a, with both ends open, has a fundamental frequency of 340 hz. the third harmonic of organ pipe b, with one end open, has the same frequency as the second harmonic of pipe
a. how long are (a) pipe a and (b) pipe b? (take the speed of sound to be 343 m/s.)
Answers
Length 'L₀' is, f₀ = U/2L₀ = 340 H₂
the speed of sound in air V= 343m/s
∴343/2L₀ = 340 → length L₀ = 343/2 ×340 = 0.5044 = 50.44
The third harmonic of closed pipe 'B' is
F3₀ = 3V/4LC
The second harmonic of open pipe 'A' is
f2₀ = 2V/2L₀
∴ 3V/4LC = 2V/2L →L₀ = 3L₀/4
⇒ The length of closed pipe B is
Lc = 37.83cm
What is the pressure of the gas in this mercury manometer if h = 63 mm and atmospheric pressure is 773 mmhg?
Answers
In fact, if the pressure of the gas was equal to the atmospheric pressure:
[tex]p_a = 1.01 \cdot 10^5 Pa[/tex]
we know that the height in the mercury manometer would have been
[tex]h_a = 773 mm[/tex]
Therefore, if the heigth in the mercury manometer is
[tex]h=63 mm[/tex]
Then the pressure of the gas is given by the following proportion
[tex]h_a : p_a = h: p[/tex]
From which we find
[tex]p= \frac{h p_a}{h_a}= \frac{(63 mm)(1.01 \cdot 10^5 Pa)}{773 mm}=8231 Pa [/tex]