Given:
Given that Mr. McBride asks students to find the volume of the triangular pyramid.
The two students wrote the expression for the value of B, the area of the base of the pyramid which is attached in the picture below.
We need to determine the student who correctly wrote the value of B.
Expression for value of B:
The area of the base of the triangular prism can be determined using the formula,
[tex]B=\frac{1}{2}bh[/tex]
where b is the base of the triangle and h is the height of the triangle.
From the figure, the base of the triangle is 9 inches and the height of the triangle is 12 inches.
Substituting in the above formula, we get;
[tex]B=\frac{1}{2}(9 \cdot 12)[/tex]
Thus, the correct expression for the area of the base is [tex]B=\frac{1}{2}(9 \cdot 12)[/tex]
Hence, the expression wrote by MAE is correct.
What is the measure of
Answer:
C: 107
Step-by-step explanation:
135-28 = 107
Answer:
it would have to be 107 bro
Step-by-step explanation:
what are the two sides of a ray called??
A random poll of 800 working men found that 11% had taken on a second job to help pay the bills. a) Estimate the true percentage of men that are taking on second jobs by constructing a 95% confidence interval. b) A pundit on a TV news show claimed that only 8% of working men had a second job. Use your confidence interval to test whether his claim is plausible given the poll data.
Answer:
a) 95% Confidence Interval = (8.832%, 13.168%)
b) The 8% claim for the pundit falls outside the range of the confidence interval, hence, it isn't a very plausible claim given the poll data.
Step-by-step explanation:
Confidence Interval for the population proportion is basically an interval of range of values where the true population proportion can be found with a certain level of confidence.
Mathematically,
Confidence Interval = (Sample proportion) ± (Margin of error)
Sample proportion = 11% = 0.11
Margin of Error is the width of the confidence interval about the mean.
It is given mathematically as,
Margin of Error = (Critical value) × (standard Error of the sample proportion)
Critical value will be obtained using the z-distribution. This is because the sample size is large enough for the t-distributoon valur to approximate the z-distribution value
Critical value for 95% confidence = 1.960 (from the z-tables)
Standard error = σₓ = √[p(1-p)/n]
where
p = sample proportion = estimated to be 11% = 0.11
n = Sample size = 800
σₓ = √[p(1-p)/n]
σₓ = √[0.11×0.89/800]
σₓ = 0.0110623234 = 0.01106
95% Confidence Interval = (Sample proportion) ± [(Critical value) × (standard Error)]
CI = 0.11 ± (1.960 × 0.01106)
CI = 0.11 ± 0.02168
95% Confidence Interval = (0.08832, 0.13168)
95% Confidence Interval = (8.832%, 13.168%)
b) The 8% claim for the pundit falls outside the range of the confidence interval, hence, it isn't a very plausible claim given the poll data.
Hope this Helps!!!
Find the median, range, and interquartile range of both sets:
Set 1: 65, 66, 77, 79, 81, 93, 104, 105
Set 2: 56, 1, 29, 72, 67, 59, 74, 60
Which is true about the two sets?
Set 1 has a range of 40 and a median of 85.
Set 2 has a range of 74 and a median of 62.
Both sets have an interquartile range of 27.
Set 2 has data that is closer to its median than Set 1.
Answer:
C) Both sets have an interquartile range of 27.
Step-by-step explanation:
Sorted data
Set 1: 65, 66, 77, 79, 81, 93, 104, 105
Set 2: 1, 29, 56, 59, 60, 67, 72, 74
Median position: (8+1)/2 = 4.5th value
Ranges:
Set 1: 105 - 65 = 40
Set 2: 74 - 1 = 73
Medians:
Set 1: (79+81)/2 = 80
Set 2: (59+60)/2 = 59.5
IQR:
Set 1: (93+104)/2 - (66+77)/2
= 27
Set 2: (67+72)/2 - (29+56)/2
= 27
Answer:
c
Step-by-step explanation:
(4 × 6) ÷ (2 + 4) ÷ (8 ÷ 4) =
Answer:
2
Step-by-step explanation:
24÷ 6÷ 2=2
temperatures in f can be converted in c using the formula c=5(f-32)/9
Make F the subject of the formula.
give your answer in the form aC+b/c where a, b and c are all positive intergers.
To make F the subject of the formula in the Celsius to Fahrenheit conversion, multiply by 9, divide by 5, and then add 32, resulting in F = (9/5)C + 32.
Explanation:To make F the subject of the formula when given the Celsius to Fahrenheit conversion formula c = 5(f - 32)/9, we start by isolating Fahrenheit on one side of the equation. Here's a step-by-step process:
Multiply both sides of the equation by 9: 9c = 5(f - 32).Divide both sides by 5: (9/5)c = f - 32.Add 32 to both sides to isolate f: f = (9/5)c + 32.Now the formula for F in terms of C is in the form aC + b with a = 9/5, b = 32, and there's no c as in the denominator since the conversion is direct.
[tex]\( F = \frac{9c + 160}{5} \).[/tex] In form [tex]\( aC + \frac{b}{c} \), \( a = 9 \), \( b = 160 \),[/tex] and [tex]\( c = 5 \).[/tex]
Let's break down the process of rearranging the formula step by step.
Given formula: [tex]\( c = \frac{5(F - 32)}{9} \)[/tex]
We want to isolate [tex]\( F \)[/tex] on one side of the equation.
1. Multiply both sides by [tex]\( \frac{9}{5} \):[/tex]
[tex]\[ \frac{9}{5} \cdot c = \frac{9}{5} \cdot \frac{5(F - 32)}{9} \][/tex]
This cancels out the fraction on the right side.
[tex]\[ \frac{9}{5} \cdot c = F - 32 \][/tex]
2. Add 32 to both sides to isolate [tex]\( F \):[/tex]
[tex]\[ \frac{9}{5} \cdot c + 32 = F \][/tex]
Now, [tex]\( F \)[/tex] is isolated on the right side of the equation.
3. Rewrite [tex]\( F \)[/tex] in the required form [tex]\( aC + \frac{b}{c} \):[/tex]
[tex]\[ F = \frac{9}{5}c + 32 \][/tex]
To express [tex]\( F \)[/tex] in the required form, we can rewrite [tex]\( \frac{9}{5}c \) as \( \frac{9c}{5} \),[/tex]so the form becomes [tex]\( aC + \frac{b}{c} \).[/tex]
So, [tex]\( a = 9 \), \( b = 32 \), and \( c = 5 \).[/tex]
4. Final Form:
[tex]\[ F = \frac{9c + 160}{5} \][/tex]
So, in the form [tex]\( aC + \frac{b}{c} \),[/tex] we have [tex]\( a = 9 \), \( b = 160 \), and \( c = 5 \).[/tex]
What is the slope of the line that passes through the points (5, -10) and (11,−12)? Write your answer in simplest form.
Answer:
[tex]slope=-\frac{1}{3}[/tex]
Step-by-step explanation:
Use the slope formula for two points:
[tex]\frac{y(2)-y(1)}{x(2)-x(1)}=\frac{rise}{run}[/tex]
Insert values
[tex]\frac{-12-(-10)}{11-5}[/tex]
Simplify
[tex]\frac{-12+10}{11-5} \\\\\\\frac{-2}{6} \\\\-\frac{2}{6}[/tex]
Simplify
[tex]-\frac{1}{3}[/tex]
The slope of the linear equation will be negative 1/3.
What is a linear equation?A connection between a number of variables results in a linear model when a graph is displayed. The variable will have a degree of one.
The linear equation is given as,
y = mx + c
Where m is the slope of the line and c is the y-intercept of the line.
The points are given below.
(5, -10) and (11,−12)
The equation of the line that passes through (5, -10) and (11,−12) will be given as,
(y + 10) = [(-12 + 10) / (11 - 5)](x - 5)
y + 10 = - (1/3)x + 5/3
y = -(1/3)x + 5/3 - 10
y = -(1/3)x - 25/3
The slope of the linear equation will be negative 1/3.
More about the linear equation link is given below.
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The two cones are congruent
Determine the unknown measures of the cones.
A= units
B = units
C = units
Du units
5.2/B
6.2
V.42 units
Va
units
Answer:
3.1
4.2
5.2
42
Step-by-step explanation: They’re congruent so just copy what the other triangle has all you had to do was find the radius.
A company has determined that when x hundred dulcimers are built, the average cost per dulcimer can be estimated by C(x)=0.3x^(2)-2.7x+7.775, where C(x) is hundreds of dollars. What is the mimimum average cst per dulcimer and how many dulcimers should be built to achieve that minimum?
Answer:
4.5 hundreds dulcimers should be build to achieve the minimum average cost per dulcimer $ 1.7 hundreds.
Step-by-step explanation:
The average cost per dulcimer can be estimated by
C(x)=0.3x² -2.7x+7.775
where C(x) is hundreds of dollar, x hundred dulcimers are built.
C(x)=0.3x² -2.7x+7.775
Differentiating with respect to x
C'(x)=0.6x-2.7
Again differentiating with respect to x
C''(x)=0.6
For maximum or minimum C'(x)=0
0.6x-2.7=0
⇒0.6x=27
[tex]\Rightarrow x=\frac {2.7}{0.6}[/tex]
⇒ x= 4.5
Now [tex]C''(x)|_{x=4.5}= 0.6>0[/tex]
Since at x= 4.5 , C''(x)>0, So, the average cost per dulcimer is minimum.
C(4.5)= 0.3(4.5)²-2.7×4.5 +7.775×
=1.7
4.5 hundreds dulcimers should be build to achieve the minimum average cost per dulcimer $ 1.7 hundreds.
2.6-,2.061,2.601,2.34,2.7 order the following from least to greatest
Answer:
2.061, 2.34, 2.6, 2.601, 2.7
Step-by-step explanation:
Hello!
This is a bit hard to explain! If you want me to try, just comment.
I have arranged the sequence in ascending order below:
[tex]2.061,\:2.34,\:2.6,\:2.601,\:2.7[/tex].
Hope this helps!
Answer:
2.061, 2.34, 2.6, 2.601, 2.7
Step-by-step explanation:
Because the numbers all have a 2 in the ones place, you need to evaluate the numbers in the tenths place and the numbers with the lowest go first and so on :)
The vertex form of a function is g(x)=(x-3)^2+9. How does the graph of g(x) compare toe the graph of the function f(x)=x^2
The graph of g(x) compare to the graph of the function[tex]f(x)=x^2[/tex] is; identical.
What is a solution to a system of equations? (SOLUTION GRAPHICALLY)For a solution to be the solution to a system, it must satisfy all the equations of that system, and as all points satisfying an equation are in their graphs, the solution to a system is the intersection of all its equation at a single point.
We are given that;
[tex]g(x)=(x-3)^2+9[/tex] and [tex]f(x)=x^2[/tex]
The vertex form of a quadratic function is given by:
[tex]g(x) = a(x - h)^2 + k[/tex]
where (h, k) is the vertex of the parabola.
Now Comparing [tex]g(x)=(x-3)^2+9[/tex] to [tex]f(x)=x^2[/tex]we can see that g(x) is the result of translating the graph of f(x) horizontally by 3 units to the right and vertically by 9 units upward.
The vertex of g(x) is (3, 9), that is obtained by shifting the vertex of f(x) at the origin (0, 0) to the right by 3 units and up by 9 units.
Since the coefficient is positive in both functions, both parabolas open upwards.
The shape of the parabolas is the same since both have the same coefficient [tex]x^2[/tex].
Therefore, the graph of g(x) is identical to the graph of f(x), its shape, but it is shifted horizontally and vertically with respect to f(x).
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Hurry late work! Consider the reduction of the rectangle. Rounded to the nearest 10th, what is the value of X?
Answer:
0.6 feet
Step-by-step explanation:
The first rectangle to scaled down. Therefore, the scale factor will be less than 1.
[tex]\frac{4.5}{16.8}=\frac{15}{56}[/tex]
Therefore, the scale factor is [tex]\frac{15}{56}[/tex].
[tex]\frac{15}{56}*2.3=\frac{69}{112}[/tex]
[tex]\frac{69}{112}[/tex] ≈ 0.6, so the value of x is 0.6 feet.
*ignore selected answer haha* just need help answering
Answer:
[tex]x^2+8x+15[/tex]
Step-by-step explanation:
[tex]f(x)=x+4\\g(f(x))=g(x+4)\\g(x+4)=(x+4)^2-1\\(x+4)^2-1=x^2+8x+15[/tex]
Create a list of steps, in order, that will solve the following equation.
5(x-3)^2+4=1295(x−3)
2
+4=129
Answer:
subtract 4 from both sides
divide both sides by 5
take the square roots of both sides
add 3 to both sides
Step-by-step explanation:
Who knows the answer?
Answer:
t
Step-by-step explanation:
Line [tex] \purple{\boxed{\bold{t}}} [/tex] is the transversal.
Power +, Inc. produces AA batteries used in remote-controlled toy cars. The mean life of these batteries follows the normal probability distribution with a mean of 38 hours and a standard deviation of 5.8 hours. As a part of its quality assurance program, Power +, Inc. tests samples of 9 batteries.a. What can you say about the shape of the distribution of the sample mean?
b. What is the standard error of the distribution of the sample mean? (Round your anser to 4 decimals places.)
c. What proportion of the samples will have a mean useful life of more than 39.5 hours? (Round z value to 2 decimal places and final answer to 4 decimal places)
d. What proportion of the sample will have a mean useful life greater than 37.5? (Round z value to 2 decimal places and final answer to 4 decimal places.)
Answer:
a) For this case we select a sample size of n=9. And we know that the distribution of X is normal so then the distribution for the sample mean is given by:
[tex]\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})[/tex]
b) [tex] SE = \frac{\sigma}{\sqrt{n}} =\frac{5.8}{\sqrt{9}} =1.9333[/tex]
c) [tex] P\bar X >39.5)[/tex]
And we can use the z score given by:
[tex] z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
And if we find the z score for 39.5 we got:
[tex] z = \frac{39.5-38}{\frac{5.8}{\sqrt{9}}}= 0.78[/tex]
And using the complement rule we got:
[tex] P(z >0.78) =1-P(Z<0.78) = 1-0.7823= 0.2177[/tex]
d) [tex] P\bar X >37.5)[/tex]
And we can use the z score given by:
[tex] z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
And if we find the z score for 37.5 we got:
[tex] z = \frac{37.5-38}{\frac{5.8}{\sqrt{9}}}= -0.26[/tex]
And using the complement rule we got:
[tex] P(z >-0.26) =1-P(Z<-0.26) = 1-0.3974= 0.6026[/tex]
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the life of batteries of a population, and for this case we know the distribution for X is given by:
[tex]X \sim N(38,5.8)[/tex]
Where [tex]\mu=38[/tex] and [tex]\sigma=5.8[/tex]
Part a
For this case we select a sample size of n=9. And we know that the distribution of X is normal so then the distribution for the sample mean is given by:
[tex]\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})[/tex]
Part b
The standard error is given by:
[tex] SE = \frac{\sigma}{\sqrt{n}} =\frac{5.8}{\sqrt{9}} =1.9333[/tex]
Part c
We want this probability:
[tex] P\bar X >39.5)[/tex]
And we can use the z score given by:
[tex] z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
And if we find the z score for 39.5 we got:
[tex] z = \frac{39.5-38}{\frac{5.8}{\sqrt{9}}}= 0.78[/tex]
And using the complement rule we got:
[tex] P(z >0.78) =1-P(Z<0.78) = 1-0.7823= 0.2177[/tex]
Part d
We want this probability:
[tex] P\bar X >37.5)[/tex]
And we can use the z score given by:
[tex] z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
And if we find the z score for 37.5 we got:
[tex] z = \frac{37.5-38}{\frac{5.8}{\sqrt{9}}}= -0.26[/tex]
And using the complement rule we got:
[tex] P(z >-0.26) =1-P(Z<-0.26) = 1-0.3974= 0.6026[/tex]
The distribution of the mean life of Batteries produced by Power+, Inc. follows Normal distribution. The standard error is calculated to be 1.9333. Using Z scores, it's discovered that approximately 21.77% of samples will have a mean life more than 39.5 hours while around 60.26% samples will have a mean useful life more than 37.5 hours.
Explanation:Understanding the Distribution of the Mean Life of Batteries
a. The distribution of the sample mean should approximate a normal distribution because we know the distribution of the population (life of the batteries) is normal. The expectation is that the sample mean should also follow normal distribution, based on the Central Limit Theorem.
b. The standard error of the distribution of the sample mean, is calculated as the standard deviation divided by the square root of the number of samples. Therefore, the standard error is 5.8 / sqrt(9), that is approximately 1.9333.
c. To find the proportion of samples with a mean useful life of more than 39.5 hours, we first find the Z score for 39.5. The Z score is calculated by (sample mean - population mean) / standard error. Therefore, Z = (39.5 - 38) / 1.9333 = approximately 0.78 (rounded to 2 decimal places). Looking this up on a Z table gives us 0.7823. However, because we want the proportion where it is more than 39.5 hours, we need to subtract this from 1. So, 1-0.7823 = 0.2177 (i.e., 21.77% samples will have a mean useful life more than 39.5 hours).
d. Following the same procedure, the Z score for a sample mean of 37.5 is approx negative -0.26 (rounded to 2 decimal places) using the same calculation as above. Looking this up on a Z table gives us 0.3974. But, because we want the proportion greater than 37.5 hours, we need to subtract this from 1. So, 1-0.3974 = 0.6026 (i.e., 60.26% samples will have a mean useful life more than 37.5 hours).
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Researchers studying the acquisition of pronunciation often compare measurements made on the recorded speech of adults and children. One variable of interest is called "voice onset time" (VOT), the length of time between the release of a consonant sound (such as "p") and the beginning of an immediately following vowel (such as the "a" in "pat"). For speakers of English, this short time lag can be heard as a period of breathiness between the consonant and the vowel. Here are the results for some randomly selected 4-year-old children and adults asked to pronounce the word "pat". VOT is measured in milliseconds and can be either positive or negative.
Children: n = 10, mean = 60.67, standard deviation = 39.89
Adults: n = 20, mean = 88.17, standard deviation = 24.74
You are interested in whether there is a difference in the VOT of adults and children, so you plan to test H0:μa−μc=0 against Ha:μa−μc≠0, where μa and μcare the population mean VOT for adults and children, respectively.
A. What additional information would you need to confirm that the conditions for this test have been met?
B. Assuming the conditions have been met, calculate the test statistic and p-value for this test.
C. Interpret the p-value in the context of this study and draw the appropriate conclusion at
α = 0.05.
D. Given your conclusion in part C, which type error, Type I or Type II, is it possible to make? Describe that error in the context of this study.
Answer:
(A) The additional information that is needed to confirm about the conditions for this test have been met is ‘Population is approximately normal.
(B) The test statistic = 1.9965
(C1) P-value = 0.0556
(C2) There is no significant difference between mean VOT for children and adults.
D1) It is possible to make type II error.
(D2) There should be a difference in the VOT of adults and children.
Step-by-step explanation:
Let na be the number of adults = 20
xa mean VOT for adults = 88.17
sa standard deviatiation of VOT for adults = 24.74
Let nc be the number of children = 10
xc mean VOT for children =60.67
sc standard deviatiation of VOT for children = 39.89
(A) From the information the population variances are unknown and the two sample are assumed to be independent and the sample the sample size are smaller that is (n<30).
This indicates that the additional information that is required for the conditions of the test to be satisfied is 'distribution of the population'. the addition assumption to be made is, that the population distribution is normal.
(b) Calculating the test statistics using the formula;
t = (xa -xc)/SE - d
where SE = standard deviation , d= hypothesized difference = 0
But SE = √sa²/na +sc²/nc
= √24.74 ²/20 + 39.89²/10
= √189.72559
= 13.774
Substituting into test statistics equation, we have
t = (xa -xc)/SE - d
= (88.17 - 60.67/13.774
= 1.9965
Therefore the test statistic is 1.9965
(c) Calculating the p-value, we have;
Degree of freedom = na + nc -2
= 10+ 20 -2
= 28
The p-value for t=1.9965 at 28 degrees of freedom and 0.05 level of significance is 0.0556.
The p-value 0.0556 is greater than given level of significance 0.05 hence we fail to reject the null hypothesis and conclude that there is no significant difference between mean VOT for children and adults.
(D1) From the information in part (C) the null hypothesis is not rejected.
Since the null hypothesis is not rejected, there might be a chance that not rejecting null hypothesis would be wrong. In this type of situation the error that can occur would be type II error.
(D2) The type of error describe in the context of this study is obtained by the concept of the type II error which tells that the null hypothesis is not rejected when it is actually false.
The equation h(t)=-16t^2+32t+12 gives the height of a baseball, in feet, t seconds after it is thrown from a platform. What is the height of the platform? What is the initial velocity when the baseball is thrown?
Answer:
(a) 12 m
(b) 32 m/s
Step-by-step explanation:
(a) The height of the platform is h(0) i.e. the height, h, at time t = 0 secs, since the ball would not have been thrown at that time.
Therefore, h(0) is:
[tex]h(0) = -16(0^2) + 32(0) + 12\\\\\\h(0) = 0 + 0 + 12\\\\\\h(0) = 12 m[/tex]
The height of the platform is 12 m.
(b) The initial velocity when the baseball is thrown will be v(0) that is velocity when t = 0 secs.
We obtain velocity, v, by differentiating height, h, with respect to time:
[tex]v(t) = \frac{dh}{dt} = -32t + 32[/tex]
Therefore, at time t = 0 secs:
[tex]v(0) = -32(0) + 32\\\\\\v(0) = 32 m/s[/tex]
The initial velocity of the baseball when it is thrown is 32 m/s.
70 points- help ASAP, please.
1. Is a^2 - 39 prime...
a. Over the set of polynomials with rational coefficients?
b. over the set of polynomials with real coefficients?
c. Explain your answers to Parts a and b
2. The Discriminant Theorem Factoring Quadratics applies to quadratics with ___ coeffecients.
Answer:
1) a) yes
b) no
c) a² - 39
(a)² - (sqrt(39))²
(a - sqrt(39))(a + sqrt(39))
This quadratic can be split into real factors, but not rational
sqrt(39) is a real number, but not rational
2) real
Solve for a and d
6x^2+14x+4=(ax+b)(cx+d)
b=1 and c=2
Answer:
a = 3
d = 4
Step-by-step explanation:
6x^2+14x+4 = (ax+1)(2x+d)
6x^2+2x+12x+4
2x(3x+1)+4(3x+1)
(3x+1)(2x+4)
3 = a
4 = d
Answer:
Step-by-step explanation:
a=3, d=4
Todd wants to buy a new video game for $43.31. He has $55.50. The sales tax is 8.5% of the total purchase. Does Todd have enough money to purchase the game?
Answer:
yes
Step-by-step explanation:
We can estimate* that the total price including tax of the game will be less than ...
$43.31 +10% of 43.31 = $43.31 +4.33 = $47.61
Todd easily has enough to pay for the game, including tax.
_____
You can work this more exactly a couple of ways.
1. Price + tax = 1.085×$43.31 = $46.99 . . . less than Todd's budget
2. Most Todd can afford: $55.50/1.085 = $51.15 . . . more than the game price
_____
* For estimating purposes, we like to use numbers that are easy to compute with. 10% is one such number, as it only requires moving the decimal point.
Determine the zeroes of 10x2−5=35
Answer:
x = +2, x = -2
Step-by-step explanation:
The equation to solve in this problem is
[tex]10x^2-5=35[/tex]
The first step we do is to subtract 35 on both sides of the equation, so we get:
[tex]10x^2-5-35=0\\10x^2-40=0[/tex]
Now we simplify the equation by dividing both terms by 10:
[tex]\frac{10x^2-40}{10}=0\\x^2-4=0[/tex]
Now we observe that the term on the left is the difference between two squares, so it can be rewritten using the property:
[tex]a^2-b^2=(a+b)(a-b)[/tex]
Where here,
a = x
b = 2
So we can rewrite the equation as:
[tex]x^2-4=0\\(x+2)(x-2)=0[/tex]
And this equation is zero when either one of the two factors is zero, so the two solutions are:
[tex]x+2=0\rightarrow x=-2\\x-2=0 \rightarrow x=+2[/tex]
Find the unit price of 60lbs of honey for $123.99. Round your answer to the nearest cent if necessary.
Answer:
$2.07 per pound
Step-by-step explanation:
price divided by amount will get you the unit price. $123.99/60 equals 2.0665.
For what values of x and y must the figure have in order to be a parallelogram
Given:
Given that the parallelogram with the lengths 5x, 3x + 1, 2y - 5 and y.
We need to determine the values of x and y.
Values of x and y:
We know the property that the opposite sides of a parallelogram are congruent.
Thus, we have;
[tex]5x=2y-5[/tex] ------- (1)
[tex]3x+1=y[/tex] ------- (2)
The value of x and y can be determined using the substitution method.
Substituting equation (2) in equation (1), we have;
[tex]5x=2(3x+1)-5[/tex]
[tex]5x=6x+2-5[/tex]
[tex]5x=6x-3[/tex]
[tex]-x=-3[/tex]
[tex]x=3[/tex]
Thus, the value of x is 3.
Substituting x = 3 in equation (2), we have;
[tex]3(3)+1=y[/tex]
[tex]9+1=y[/tex]
[tex]10=y[/tex]
Thus, the value of y is 10.
Solve negative 7 over 3, the whole multiplied by x minus 3 equals negative 52.
Answer:
x= [tex]\frac{135}{7}[/tex]
Step-by-step explanation:
1. [tex]-\frac{7}{3} (x-3)=-52[/tex]
2. combine -7/3(x - 3)
= [tex]-\frac{7}{3}x-7 = -52[/tex]
3. Do combine like terms on both sides
= -52 + -7 = -45
4. left with, [tex]-\frac{7}{3}x = -45[/tex]
5. divide -45 by -7/3
6. left with, [tex]x = \frac{135}{7}[/tex]
Answer:
21
Step-by-step explanation:]
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Paul observes that AB=AC and concludes that AB abd AC must be tangent to the circle. What is wrong with pauls reasoning?
Answer:
C
Step-by-step explanation:
Answer:
The answer should be C
Step-by-step explanation:
we know that
the triangle AOB is congruent with triangle AOC
because
AB=AC
OB=OC-----> the radius of the circle
The OB side is common
but
there is no additional information that allows me to calculate the OBA angle to determine if it is a right angle
therefore
the answer is the option
C.There is no indication that AB and AC are perpendicular to the radii at the points of intersection with the circle.
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A researcher studying reaction time of drivers states that, "A 95% confidence interval for the mean time (8.1) it takes for a driver to apply the brakes after seeing the brake lights on a vehicle in front of him is 1.2 to 1.8 seconds. What are the point estimate and margin of error for this interval?
Answer:
For this case we know that the confidence interval is given by (1.2 , 1.8) and the point of estimate for [tex]\mu[/tex] would be:
[tex]\bar X = \frac{1.2+1.8}{2}= 1.5[/tex]
And the margin of error is given by:
[tex] ME = \frac{1.8-1.2}{2}= 0.3[/tex]
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
[tex]\bar X[/tex] represent the sample mean for the sample
[tex]\mu[/tex] population mean (variable of interest)
s represent the sample standard deviation
n represent the sample size
Solution to the problem
The confidence interval for the mean is given by the following formula:
[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (1)
For this case we know that the confidence interval is given by (1.2 , 1.8) and the point of estimate for [tex]\mu[/tex] would be:
[tex]\bar X = \frac{1.2+1.8}{2}= 1.5[/tex]
And the margin of error is given by:
[tex] ME = \frac{1.8-1.2}{2}= 0.3[/tex]
Each wall in Keith's room is 12 meters long and seven and 7 7/8 meters wide. He plans to paint one wall blue. Each can of paint covers 15 square meters. How many cans of paint does kids need to cover the bedroom wall?
Answer:
7 cans
Step-by-step explanation:
6 cans of paint kids need to cover the bedroom wall.
What is area of a rectangle?The formula for calculating the area of a rectangle with dimensions l and w is: A = lw (rectangle). In other words, the length times the width equals the area of a rectangle.
Given
length = 12 m
width = 7.875 m
area = 12 * 7.875 = 94.5 sq. m
area 1 can can fill = 15 sq. m
no. of cans that can fill 94.5 = 6
therefore, 6 cans of paint kids need to cover the bedroom wall.
To learn more about area of rectangle refer to :
https://brainly.com/question/25292087
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wyatt bought a jacket that cost 12 dollers and a scarf that costs 18 dollers he recived a discount at the counter if he only paid 21 dollers total how many dollers was the discount?
Answer:
$9
Step-by-step explanation:
12 + 18 = $30 Total
30 - 21 = $9 Discount
30 - 9 = $21 After discount
The area of a regular polygon is 216cm2. The perimeter is 48cm, what is the
length of the apothem?
Answer:
The answer to your question is Apothem = 9 cm
Step-by-step explanation:
Data
Area = 216 cm²
Perimeter = 48 cm
Formula
Area = Perimeter x apothem / 2
Perimeter = length of the side x number of sides
Process
Substitute the values in the area formula and simplify it.
1.- Substitution
216 = 48a/2
-Solve for a
216 x 2 = 48a
432 = 48a
a = 432 / 48
-Result
a = 9 cm