Answers
When you use postulates and theorems, you need to make sure to only use the given information that you know. Look for the given statements, and congruence marks on the figure. Those are also considered given.
By looking, you are given an angle and a side. The side comes first. SU=TV.
So, that makes it so Side-Angle-Side would be the best option.
I hope this helps!
When you use postulates and theorems, you need to make sure to only use the given information that you know. Look for the given statements, and congruence marks on the figure. Those are also considered gives
Related Questions
want 100p and brainiest answer first, ((((please))))
what is 2 1
1__ - 2__ = ?
3 3
Answers
In july in seattle, the grass grows 1/2 inch a day on a sunny day and 1/4 inch a day on a cloudy day. in seattle, in july, 75% of the days are sunny and 25% of the days are cloudy.
a.find the expected value of grass growth for the day
b.find the expected value of grass growth for the month of july ( 31 days ) -- round both to 2 decimal placees
Answers
a.
1/2×75％＋1/4×25％=0.4375
the expected value of grass growth for the day is 0.4375
b.
0.4375×31=13.5625
the expected value of grass growth for the month of july is 13.5625
Final answer:
Calculate the expected grass growth in Seattle based on the daily growth rates for sunny and cloudy days, then find the expected growth for the month of July.
Explanation:
a. Expected value of grass growth for the day:
Expected growth = (0.75 x 0.5) + (0.25 x 0.25) = 0.4375 inches
b. Expected value of grass growth for the month of July:
Expected growth for July = 31 days x Expected growth per day = 31 x 0.4375 = 13.56 inches
PLEASE HELP ASAP! BRAINLIEST TO BEST/RIGHT ANSWER
Answers
first term, you substitute 1 into n
-3 * 2^(1-1)
-3 * 2^0
-3 * 1= -3
fourth term, you substitute 4 into n
-3 * 2^(4-1)
-3 * 2^3
-3 * 8 = -24
eighth term, you substitute 8 into n
-3 * 2^(8-1)
-3 * 2^7
-3 * 128 = -384
What is another way to write this number 300+70+5/10+8/100
Answers
Your answer is 370 [tex] \frac{29}{50} [/tex]
I hope this helped! :-)
The difference of two numbers is 44 1/2 . If the smaller of the two numbers increases 7 times then the difference will be 10 3/14 . Find the numbers.
The numbers are: ___ ,___ or ____,___
Answers
To find these answer you have to write the following two equations.
x - y = 44 and 1/2
7y - x = 10 and 3/14
Then, you can use the substitution method to solve them. Change the first equation to: x = 44 + y. Substitute that into the second equation and solve for y. Once you have that, plug it back into the first equation and solve for x.
The smaller number is 11 and the larger number is [tex]55 \frac{1}{2}[/tex].
Let's denote the two numbers as x and y, where x is the smaller number. We're given that [tex]y - x = 44 \frac{1}{2}[/tex] and [tex]7x - y = 10 \frac{3}{14}[/tex].
To solve this system of equations, we can use substitution or elimination. Let's use elimination:
1. Multiply the second equation by 2 to clear fractions: [tex]14x - 2y = 20 \frac{6}{14}[/tex].
2. Add the modified second equation to the first equation:
[tex](y - x) + (14x - 2y) = 44 \frac{1}{2} + 20 \frac{6}{14}[/tex]
[tex]13x - y = 64 \frac{11}{14}[/tex]
Now, we have a simpler equation: [tex]13x - y = 64 \frac{11}{14}[/tex].
3. Add this equation to the original second equation to find x:
[tex]7x - y + 13x - y = 10 \frac{3}{14} + 64 \frac{11}{14}[/tex]
[tex]20x - 2y = 75[/tex]
4. Now, we can solve this equation along with the first equation to find x and y.
After solving, we get x = 11 and [tex]y = 55 \frac{1}{2}[/tex].
The smaller number is 11 and the larger number is [tex]55 \frac{1}{2}[/tex].
Thus, the numbers are [tex]{11 \text{ and } 55 \frac{1}{2}}[/tex].
Correct Question:
The difference of two numbers is 44 1/2 . If the smaller of the two numbers increases 7 times then the difference will be 10 3/14 . Find the numbers.
Will give brainliest answer!!
Answers
5:8
Explanation:
First, we will compute the ratio between the two volumes as follows:
1000 / 4096 = 125 / 512
which is equivalent to 125 : 512
Then, we will get the cubic root of the ratio. This is because volume of cube is computed by cubing its side length.
Therefore, similarity ratio iR³ will be:
125 : 512
(5)³ : (8)³
5 : 8
Hope this helps :)
Find the measure of each angle please?
Answers
The measure of angle x is 60 degrees so the measure of angles 2x is 120 degrees.
Since both interior angles are supplementary to congruent angles, they are congruent.
Let z be the measure of each upper interior angle.
2x + z = 180
z = 180 - 2x
Each upper interior angle measures 180 - 2x.
The sum of the measures of the interior angles of a triangle is 180.
180 - 2x + 180 - 2x + x = 180
-3x + 360 = 180
-3x = -180
x = 60
One interior angle measures x, so it measures 60 deg.
The other two interior angles measure 180 - 2x = 180 - 2(60) = 180 - 120 = 60
Answer: all interior angle measure 60 deg.
The exterior angles shown measure 120 deg each.
If AB is a tangent then point b must be the point of tangency true or false
Answers
HELP:
Whic reformer was not a journalist who investigated corruption in business or government?
(Points : 3)
Ray Stannard Baker
Upton Sinclair
Lincoln Steffens
William Booth
i wend with D
Answers
1. Add or subtract.
a. (x^2 - 4 x + 5) + (7x^2 + 2x + 3)
b. (7x^2 + 4x - 6) - (2x^2 - 3x + 1)
Answers
1a.
Answer is 8x² - 2x + 8
(x² - 4x + 5) + (7x² + 2x + 3)
The parentheses can go away since this is all addition (associative property of addition)
x² - 4 x + 5 + 7x² + 2x + 3
Combine like terms.
(x^2 + 7x²) + (-4x + 2x) + (5 + 3) = 8x² - 2x + 8
======
1b.
Answer is 5x^2 + 7x - 7
(7x² + 4x - 6) - (2x² - 3x + 1)
Distribute the negative into the right parentheses.
(7x² + 4x - 6) - (2x² - 3x + 1)
= 7x² + 4x - 6 - 2x² + 3x - 1
= (7x² - 2x²) + (4x + 3x) + (-6 - 1)
= 5x^2 + 7x - 7
Two 6-sided dice are rolled. what is the probability that the sum of the two numbers on the dice will be greater than 9?
Answers
It can be:
• First die is 6 , second die is 3
• First die is 3 , second die is 6
• First die is 4 , second die is 5
• First die is 5 , second die is 4
How many possible combinations are made? Yep, 4 possible combinations.
Recall the formula for probability
[tex]Probability = \frac{Number of desired outcomes}{Number of all possible outcomes} [/tex]
There are 4 desired number of outcomes.
How about the total possible outcomes?
• How many numbers are possible to appear when the first die is rolled?
Answer: 6
• What about the second die?
Answer: Also 6
• Therefore, total possible outcomes = 6 * 6 = 36 outcomes
You can now solve for the probability.
[tex]Probability = \frac{4}{36} = \frac{1}{9} [/tex] or approximately 11.11%
a(t) = (t - k)(t - 3)(t - 6)(t + 3) is a polynomial function of t, where k is a constant. Given that a(2) = 0, what is the absolute value of the product of the zeros of a?
Answers
(2)*(3)*(6)*(-3) = -108
The absolute value of the product of zeros of a(t) is 108.
t-k=0, t=k
t-3=0, t=3
t-6=0, t=6
t+3=0, t=-3
abs value of the product= abs value of (t*3*6*-3)=54t
John rolls a number cube twice. What is the probability that the sum of the 2 rolls is less than 7, given that the first roll is a 1?
one over six
one over three
one over two
five over six
Answers
There are 6 ways we can roll two dice and have the first number be a 1:
1, 1
1, 2
1, 3
1, 4
1, 5
1, 6
Out of these, 5 possibilities give us a sum less than 7:
1, 1
1, 2
1, 3
1, 4
1, 5
Thus we have 5/6.
Answer: The correct option is (d) five over six.
Step-by-step explanation: Given that John rolls a number cube twice. We are to find the probability that the sum of the 2 rolls is less than 8 given that he first roll is a 1.
The sample space of an event of rolling a cube is
S = {1, 2, 3, 4, 5, 6}.
That is, n(S) = 6.
Now, let 'A' be the event that the sum of the two rolls is less than 7, then
A = {1, 2, 3, 4, 5}.
That is, n(A) = 5.
So, the probability of happening of event A is given by
[tex]P(A)=\dfrac{n(A)}{n(S)}=\dfrac{5}{6}.[/tex]
Thus, the required probability is five over six.
Option (d) is correct.
If a family has three children draw a tree diagram representing the possible outcomes for the genders of the children and then list the sample space
Answers
The area of a rectangular classroom is given by the trinomial 10x^2 + 3x - 4 What are the possible dimensions of the classroom? Use Factoring.
Answers
In a rectangle the area is L x W. So if we know the area is 10x^2 + 3x - 4, then all we have to do is factor it to find possible values for the L and W.
If you factor the expression by grouping, you will get (2x - 1) and (5x + 4).
Your questions asks for possible dimensions, you could give the two expressions as dimensions.
If you wanted to select a value for x, you could plug it in and get values that could be dimensions.
For example if you let x = 10, you would have a rectangle that has a width of 19 and a length of 54.
Answer:
(5x + 4) and (2x – 1)
Step-by-step explanation:
Solve the inequality
-40 > -10k
Answers
-40>-10k
Divide both sides by -10, and flip the inequality sign since we are dividing by a negative.
4<k
Have a nice day!
Scarlett is trying to find the height of a dam. She stands 90 meters away from the dam and records the angle of elevation to the top of the dam to be 26º. Scarlett's height is 1.65 meters, so the height of the dam is meters. NextReset
Answers
h = x + 1.65 m,
where:
x = 90 m · tan 26°
x = 90 · 0.4877
x = 43.90
h = 43.90 m + 1.65 m = 45.55 m
Answer:
The height of the dam is 45.5 m.
Answer:
The height of dam =45.5 m.
Step-by-step explanation:
We are given that Scarlett stands 90 m away from the dam and records the angle of elevation to the top of the dam to be [tex]26^{\circ}p[/tex]
Scarelett's height is 1.65 meters.
We have to find the height of the dam.
Let h be the height of dam
AC=AB+BC
BC=x
h=1.65+x
CD=EB=90 m
In triangle ABE
[tex]\theta=26^{\circ}[/tex]
[tex]tan\theta=\frac{perpendicular\;side}{Base}[/tex]
[tex]tan26^{\circ}=\frac{AB}{90}[/tex]
[tex]0.4877=\frac{x}{90}[/tex]
[tex]x=0.4877\times 90[/tex]
[tex]x=43.893 m[/tex]
Therefore, the height of dam=1.65+43.893=45.543 m
Answer: The height of dam =45.5 m
Find the inverse function for the function f(x) = mx + b?
Answers
The inverse is created by interchanging x and y like this.
x = my + b and solving for y
(x - b) = my Now divide by m
(1/m) * (x - b) = y
20 POINTS! What is the slope of the line through the points (2, 5) and (6, 13)?
Answers
[tex] \frac{13-5}{6-2} [/tex]
[tex] \frac{8}{4} [/tex]
Slope = 2
So the slope of the line that passes through that point is 2.
Hope this helps :)
Help please on properties of exponents? will give a medal!
A rectangle has a length of the cube root of 81 inches and a width of 3 to the 2 over 3 power inches. Find the area of the rectangle.
a. 3 to the 2 over 3 power inches squared
b. 3 to the 8 over 3 power inches squared
c. 9 inches squared
d.9 to the 2 over 3 power inches squared
2.)Explain how the Quotient of Powers was used to simplify this expression.
2 to the fifth power, over 8 = 2 to the 2nd power
a.By finding the quotient of the bases to be one fourth and cancelling common factors
b. By finding the quotient of the bases to be one fourth and simplifying the expression
c. By simplifying 8 to 23 to make both powers base two and subtracting the exponents
d. By simplifying 8 to 23 to make both powers base two and adding the exponents
3.)the cube root of 2 to the seventh power
a. 2 to the 3 over 7 power
b. 2 to the 7 over 3 power
c. 2^21
d. 2^4,
Answers
1) c. 9 inches squared
2) c. By simplifying 8 to 23 to make both powers base two and subtracting the exponents
3) b. 2 to the 7 over 3 power
Explanation.
Question 1
The area of a rectangle is given by
area=l×w
=〖81〗^(1/3)×3^(2/3)
3^(4/3)×3^(2/3)=3^(4/3+2/3)
=3^(6/3)=3^2=9 inches squared
Question 2
Finding the 2^5/8=2^2
The steps for finding this is first to write 8 as 23. Then divide.
2^5/8=2^5/2^3
When dividing exponents with the same base you subtract the powers.
=2^(5-3)=2^2
Question 3
The question wants us to solve, ∛(3^7 ).the cube root of a number can be written as a power of a third.
So,
∛(3^7 )=3^(7×1/3 )
=3^(7/3)
Ques 1)
Option: C is the correct answer.
c. 9 inches square.
Ques 2)
Option: c
c. By simplifying 8 to 2^3 to make both powers base two and subtracting the exponents.
Ques 3)
Option: b
b. 2 to the 7 over 3 power
Step-by-step explanation:Ques 1)
A rectangle has a length of the cube root of 81 inches and a width of 3 to the 2 over 3 power inches.
i.e. let 'l' and 'b' denote the length and width of the rectangle.
i.e.[tex]l=\sqrt[3]{81}\\\\l=(3^4)^{\dfrac{1}{3}}\\\\l=3^{\dfrac{4}{3}[/tex]
since,
[tex](a^m)^n=a^{mn}[/tex]
and
[tex]w=3^{\dfrac{2}{3}}[/tex]
Hence, the area of rectangle is given by:
[tex]Area=l\times w\\\\\\Area=3^{\dfrac{1}{3}}\times3^{\dfrac{4}{3}}\\\\\\Area=3^({\dfrac{1}{3}+\dfrac{4}{3}})\\\\\\Area=3^{\dfrac{6}{3}}\\\\\\Area=3^2\\\\\\Area=9\ square\ inches[/tex]
As we know that:
[tex]a^m\times a^n=a^{m+n}[/tex]
Hence, Area=9 square inches.
Ques 2)
2 to the fifth power, over 8 = 2 to the 2nd power
i.e. we need to prove that:
[tex]\dfrac{2^5}{8}=2^2[/tex]
As we know that:
[tex]\dfrac{2^5}{8}=\dfrac{2^5}{2^3}=2^{5-3}=2^2[/tex]
( since
[tex]\dfrac{a^m}{a^n}=a^{m-n}[/tex] )
Hence, the correct answer is: Option: c
Ques 3)
The cube root of 2 to the seventh power.
i.e.
[tex]\sqrt[3]{2^7}\\\\=(2^7)^{\dfrac{1}{3}}\\\\=2^{\dfrac{7}{3}}[/tex]
Since,
[tex]\sqrt[n]{x}=x^{\dfrac{1}{n}}[/tex]
and
[tex](a^m)^n=a^{mn}[/tex]
Hence, the correct answer is: option: b
x/10=2/4?
or x over 10
equals to 2 over 4
Answers
_______________________________________________
Note the following:
_______________________________________________
2/4 = 1/2 ;
1/2 = (1*5) / (2*5) = 5/10 ;
2/4 = 1/2 = 5 / 10 .
or: 2/4 = 1/2 = 0.5 = 5/ 10 .
The answer: " x = 5 " .
___________________
Or: x/ 10 = 2/4 ;
Cross-multiply:
4x = (2)(10) ;
4x = 20 ;
Divide each side by "4" ;
4x / 4 = 20/4 ;
" x = 5 " ;
_____________________
Or: x/10 = 2/4 ;
Note: "2/4 = 1/2" ; so rewrite as:
x/10 = 1/2 ; and cross-multiply:
2x = (10)(1) ;
2x = 10 ;
Divide each side of the equation by "2" ;
2x / 2 = 10 / 2 ;
" x = 5 " .
______________________________________
Find m∠A given ΔABC where a=4, b=6, c=3.
Answers
The law of cosines is the following equation:
[tex]a^2=b^2+c^2-2(b)(c) \cos(A)[/tex]
We know the values of a, b, and c. We want to find the measure of angle A.
[tex]a=4[/tex]
[tex]b=6[/tex]
[tex]c=3[/tex]
Now, plug in these values into the equation.
[tex]4^2=6^2+3^2-2(3)(6) \cos(A)[/tex]
[tex]16=45-36 \cos(A)[/tex]
Add both sides by [tex]36 \cos(A)[/tex] and subtract both sides by 16
[tex]36 \cos(A)=29[/tex]
Divide both sides by 36
[tex]\cos(A)= \dfrac{29}{36}[/tex]
Take the inverse cosine, or arc cosine, of both sides.
Using a calculator, you'll get the following result.
[tex]A \approx 36.3^O[/tex]
The measure of angle A should be 36.3 degrees. Hope this helps! :)
Write the equation, in slope-intercept form, of the line passing through the origin and the point $(-4,3)$.
Answers
From our two points we can infer that [tex]x_{1}=0[/tex], [tex]y_{1}=0[/tex], [tex]x_{2}=-4[/tex], [tex]y_{2}=3[/tex]. Lets replace those values in the slope formula:
[tex]m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}} [/tex]
[tex]m= \frac{3-0}{-4-0} [/tex]
[tex]m= \frac{3}{-4} [/tex]
[tex]m=- \frac{3}{4} [/tex]
Now that we have our slope, we can use the slope-intercept formula:
[tex]y-y_{1}=m(x-x_{1})[/tex]
[tex]y-0=- \frac{3}{4} (x-0)[/tex]
[tex]y=- \frac{3}{4} x[/tex]
We can conclude that the equation of the line passing trough the points (0,0) and (-4,3) is [tex]y=- \frac{3}{4} x[/tex].
A population has size 25 at time t = 0, with t measured in years. (a) if the population decreases by 4 people per year, find a function for the population size, p, at time t. enter your answer as an equation with p on the left side, and an expression involving t on the right
Answers
p = population
t: time in years
The equation that best fits this problem is a linear equation of the form:
p = -4t + 25
Note that for t = 0 the value of p is 25, which represents the initial population.
Answer:
a function for the population size, p, at time t is:
p = -4t + 25
why is 5 a rational number?
Answers
5 is a rational number because it can be expressed as the quotient of two integers: 5÷ 1
Hope this helps!! ;))
Have a grat day!! <3
**NEED HELP!!!
Bo’s gross annual income is $45,408. He is paid semimonthly and has 6% deducted from his paychecks for his 403(b). His employer matches his deduction, up to 3%.
How much is deposited into Bo’s 403(b) each payday?
Answers
Answer:
170.28
Step-by-step explanation:
I just took the test and am reviewing the correct answers.
90% * x = 50 pounds of money
Answers
x = £55.56
HELP PLEASE
Find the value of x, if you know the hypotenuse is 10 and 1 of the sides is 5. X is the other side.
Answers
[tex]a^2+b^2=c^2[/tex]
Solve for b (c is the hypotenuse and it doesn't matter which side is a or b):
[tex]b = \sqrt{c^2-a^2} = \sqrt{10^2-5^2} = \sqrt{100-25} = \sqrt{75} [/tex]
We can simplify this:
[tex] \sqrt{75} = \sqrt{25*3} = 5 \sqrt{3} [/tex]
So, your answer is, b = [tex]5 \sqrt{3} [/tex]
For questions like these, where you are given the hypotenuse & one side of a triangle, then we can very simply use the Pythagorean Theorem to find x.
Pythagorean Theorem : a² + b² = c²
Where :
a = side length
b = another side length
c = hypotenuse
Since we are given 10 as the hypotenuse and 5 as a side length, we can very simply plug these into the Pythagorean theorem.
a² + b² = c²
We'll plug 10 into 'c' and 5 into 'a.'
(5²) + b² = (10²)
Simplify.
25 + b² = 100
Now, subtract 25 from both sides.
b² = 100 - 25
Simplify.
b² = 75
Now, find the square root of b² and 75.
[tex] \sqrt{b^2} = \sqrt{75} [/tex]
Simplify.
[tex]b = 5 \sqrt{3} [/tex]
Therefore, our final side length is : [tex]5 \sqrt{3} [/tex]
~Hope I helped!~
What are the zeros of the quadratic function f(x) = 8x2 – 16x – 15? x = –1 – and x = –1 + x = –1 – and x = –1 + x = 1 – and x = 1 + x = 1 – and x = 1 +
Answers
To find the zeros of the quadratic function [tex]\( f(x) = 8x^2 - 16x - 15 \)[/tex], you need to solve for [tex]\( x \) when \( f(x) = 0 \)[/tex].
So, you set \( f(x) \) equal to zero:
[tex]\[ 8x^2 - 16x - 15 = 0 \][/tex]
To solve this quadratic equation, you can use the quadratic formula:
[tex]\[ x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}} \]where \( a = 8 \), \( b = -16 \), and \( c = -15 \).[/tex]
Plugging these values into the quadratic formula:
[tex]\[ x = \frac{{-(-16) \pm \sqrt{{(-16)^2 - 4(8)(-15)}}}}{{2(8)}} \]\[ x = \frac{{16 \pm \sqrt{{256 + 480}}}}{{16}} \]\[ x = \frac{{16 \pm \sqrt{{736}}}}{{16}} \][/tex]
Now, you simplify the expression under the square root:
[tex]\[ \sqrt{736} = \sqrt{16 \times 46} = 4\sqrt{46} \][/tex]
So, the expression becomes:
[tex]\[ x = \frac{{16 \pm 4\sqrt{46}}}{{16}} \][/tex]
Now, you can simplify further:
[tex]\[ x = \frac{{4(4 \pm \sqrt{46})}}{{4 \times 4}} \]\[ x = \frac{{4 \pm \sqrt{46}}}{{4}} \][/tex]
This gives you two solutions:
[tex]\[ x = \frac{{4 + \sqrt{46}}}{{4}} \]\[ x = \frac{{4 - \sqrt{46}}}{{4}} \][/tex]
These are the zeros of the quadratic function [tex]\( f(x) = 8x^2 - 16x - 15 \).[/tex]
Complete question :
What are the zeros of the quadratic function f(x) = 8x2 - 16x - 15?
help please
integral of sqrt (x^2+6x) dx
Answers
Because this is not an integration with specific bounds, you must include a constant at the end. In general, to integrate, add 1 to the exponent of x and then whatever number is the exponent of x, divided the number in front of x by that.