Need help with dividing

Combine like terms

4y-2y=24-6

2y=18

y=9

The greatest common factor for these two numbers is 6 because if you divide 24 by 6 you get 4 and if you divide 84 by 6 you get 14.

The system of equations satisfied by the solution shown in the graph are:

x + y = 6 and x − y = -10.

Option D is the correct answer.

We have,

To check which system of equations is satisfied by the solution (-2, 8), we substitute the values x = -2 and y = 8 into each equation of the given systems.

A.

x + 2y = 6

(-2) + 2(8) = 6

-2 + 16 = 6

14 ≠ 6

B.

x + y = 6

(-2) + 8 = 6

6 = 6

x − 2y = 10

(-2) − 2(8) = 10

-2 - 16 = 10

-18 ≠ 10

C.

x + 2y = 10

(-2) + 2(8) = 10

-2 + 16 = 10

14 ≠ 10

x − y = 6

(-2) − 8 = 6

-10 ≠ 6

D.

x + y = 6

(-2) + 8 = 6

6 = 6

x − y = -10

(-2) − 8 = -10

-10 = -10

From the above calculations, we can see that the solution (-2, 8) satisfies the equations in x + y = 6 and x − y = -10.

Therefore,

The system of equations satisfied by the solution shown in the graph are:

x + y = 6 and x − y = -10.

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[tex]0.4=\dfrac{4}{10}=\dfrac{2}{5}[/tex]

Using the place value chart we can see that the decimal 0.4 is four tenths, so we can write 0.4 as the fraction 4 out of 10 or [tex]\frac{4}{10}[/tex]. Notice however that [tex]\frac{4}{10}[/tex] is not in lowest terms so we need to divide both the numerator and denominator by the greatest common factor of 4 and 10 which is 5.

Therefore, 0.4 can be written as the fraction 2/5, which is in lowest terms.

Answer-

Set of constraints to model the problem are,

[tex]12x+9y\geq 510[/tex]

[tex]y \leq 2x[/tex]

[tex]y \geq 25[/tex]

Solution-

x = the number of lawns weeded by Gwen,

y = the number of dogs walked by Fabio.

1.

As, Gwen charges $12 each time she weeds a yard and Fabio charges $9 each time he walks a dog,

[tex]\text{Earnings of Gwen} = 12x[/tex]

[tex]\text{Earnings of Fabio} = 9y[/tex]

[tex]\text{Total earning} = 12x+9y[/tex]

They need at least $510 to purchase the new gaming station, means they need $510 or more than $510.

The equation for this is,

[tex]12x+9y\geq 510[/tex]

2.

The number of dog walks that Fabio has scheduled is no more than twice the number of yards Gwen has scheduled to weed, means

y must be less than or equal to 2x.

The equation for this is,

[tex]y \leq 2x[/tex]

3.

Fabio will walk at least 25 dogs, means y must be greater than of equal to 25.

The equation for this is,

[tex]y \geq 25[/tex]

Explanation:

Lets break the problem into steps and observe the constraints:

So Fabio and Gwen they are trying to save money and altogether they need at least $510.00.

Gwen charges $12.00 each time she weeds a yard.

Fabio charges $9.00 each time he walks a dog.

Fabio will walk at least 25 dogs. Here, 'x' represents the number of lawns weeded and 'y' represents the number of dogs walked.

Now talking about constraints:

Fabio will walk at least 25 dogs, so that implies:

[tex]y>25[/tex]

Also, the number of dog walks that Fabio has scheduled is no more than twice the number of yards Gwen has scheduled to weed, that implies:

[tex]y<2x[/tex]

The total money that they need after doing all the work should be at least $510.00.

[tex]12x+9y>510[/tex]

For this case we have the following equation, in a linear way:

[tex]y + 2 = 3 (x-1)[/tex]

This expression can be written in the form [tex]y = mx + b[/tex]

Where "m" is the slope and "b" is the cut point with the y axis.

Rewriting the given expression we have:

[tex]y + 2 = 3x-3\\y = 3x-3-2\\y = 3x-5[/tex]

Thus, the slope is 3 and the cut point is -5.

To graph, we must find two points through which the line passes, so, we perform the following steps:

Step 1:

We do [tex]x = 0[/tex]

[tex]y = 3 (0) -5\\y = 0-5\\y = -5[/tex]

Thus, the point [tex](x1, y1) = (0, -5)[/tex]

Step 2:

We do[tex]y = 0[/tex]

[tex]0 = 3x-5\\5 = 3x[/tex]

[tex]x =\frac{5}{3}[/tex]

Thus, the point [tex](x2, y2) = (\frac{5}{3},0)[/tex]

Answer:

See attached image

Answer:

AND THE NUMBERS ARE (0,3)IS UP AND (1,1) ARE DOWN

WISH THAT HELP

سبحان الله ,الحمدالله ,الله اكبر

First, identify the digit in the hundreds place.

12,781

Left 1 - ten-thousands place

2 - thousands place

7 - hundreds place - the one we are interested in

8 - tens place

Right 1 - ones place

Now we know the 7 is in the hundreds place.

12,781

To round off to the nearest 100, all digits to the right of the digit in the hundreds place become zero.

12,781 becomes first 12,700, but now we need one more step.

Look in the original number at the digit just to the right of the hundreds digit. It is an 8. Since 8 is greater than or equal to 5, the previous digit goes up by 1, so the 7 becomes an 8, as in 12,800, and the rounded number is 12,800.

Answer: 12,800

The 12,781 rounded to the nearest hundred is 12,800.

Given:

A number - 12,781

To find:

The rounding off the given number to the nearest hundred.

Solution:

12,781

Rounding off 12,781 to nearest tens:

=12,780

Rounding off 12,780 to nearest hundred:

=12,800

12,781 ≈ 12,800

The 12,781 rounded to the nearest hundred is 12,800.

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Step-by-step explanation:

Topic :- Unitary method !!

number 5 is not and number 7 is a function because every input has exactly one output

1) 36

2)8

3)14

4a) 21 4b) 42 4c) 56

5a)22 5b)40 5c)52

6a) 15.5 6b) 17 6c)18

7a)9 7b)18 7c)24

8) 3x +5

3  x 4 +5

=17

s^2 means we're squaring the number s

For example, if s = 3, then s^2 = 3^2 = 3*3 = 9

This is likely a formula to find the area of a square. In the example above, the square would have a side length of 3 leading to an area of 9.

Answer: There are 212,181 pounds of flour extra delivered.

Step-by-step explanation:

Since we have given that

Number of pounds of flour used in his 25 bakeries = 239,021

Number of pounds of flour is delivered = 451,202

we need to find the extra pounds of flour were delivered.

So, Number of extra pounds of flour were delivered is given by

[tex]451202-239021\\\\=212181\ pounds[/tex]

Hence, there are 212,181 pounds of flour extra delivered.

Answer:

The distance formula is an algebraic expression used to determine the distance between two points with the coordinates (x1, y1) and (x2, y2).

D=(x2−x1)2+(y2−y1)2−−−−−−−−−−−−−−−−−−√

D=(x2−x1)2+(y2−y1)2

Example

Find the distance between (-1, 1) and (3, 4).

This problem is solved simply by plugging our x- and y-values into the distance formula:

D=(3−(−1))2+(4−1)2−−−−−−−−−−−−−−−−−√=

D=(3−(−1))2+(4−1)2=

=16+9−−−−−√=25−−√=5

=16+9=25=5

Sometimes you need to find the point that is exactly between two other points. This middle point is called the "midpoint". By definition, a midpoint of a line segment is the point on that line segment that divides the segment in two congruent segments.

If the end points of a line segment is (x1, y1) and (x2, y2) then the midpoint of the line segment has the coordinates:

(x1+x22,y1+y22)

(x1+x22,y1+y22)

Step-by-step explanation:

To find the endpoint B given midpoint M and endpoint A, we use the coordinates of the midpoint formula and solve for the unknown values. Plugging the given values into the formula, we solve for B and find that the coordinates of B are (-5, 7).

In this particular instance, we are working with the concept of midpoints on a coordinate plane. Given that the point M(-3,5) is the midpoint of the segment AB and A(-1,3) is one endpoint, we are tasked to find the coordinates of point B, the other endpoint.

The formula for the coordinates of the midpoint is [(x1+x2)/2 , (y1+y2)/2]. This finds the average of the x-coordinates and y-coordinates of the two endpoints to find the point exactly in between, or the midpoint.

Since we are given one endpoint A(-1,3) and the midpoint M(-3,5) and are asked to find the other endpoint B, we should set up the equation using the known values and solve for the unknown values. We know that (-3,5) should equal [(-1+x2)/2 , (3+y2)/2]. Solving for x2 (x-coordinate of B) gives us x2 = -3*2 + 1 = -5. Solving for y2 (y-coordinate of B) gives us y2 = 5*2 - 3 = 7. Therefore, the coordinates of B are (-5, 7).

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Let Jean's speed while running = x mph

Then Jean's speed while riding will be = x+9 mph

Distance covered by running = 8 miles

Distance covered by riding = 11 miles

Total time taken to complete the race = 1.5 hours

As, [tex]time=\frac{distance}{speed}[/tex]

So, time for running= [tex]\frac{8}{x}[/tex]

And time for riding= [tex]\frac{11}{x+9}[/tex]

Equation becomes:

[tex]\frac{8}{x}+\frac{11}{x+9}=1.5[/tex]

Now, multiply every term by 2x(x+9) to clear denominators:  

[tex]16(x+9)+22x=3x(x+9)[/tex]

Simplifying it we get

[tex]3x^{2}-11x-144=0[/tex]

Solve the quadratic equation using formula

[tex]x= \frac{-b+\sqrt{b^{2}-4ac }}{2a}[/tex]

putting a=3 , b= -11, c= -144

we get (x - 9)(3x + 16) = 0

where x=9 and x=[tex]\frac{-16}{3}[/tex]

Neglect the negative answer as speed cannot be negative, so x = 9 mph

Hence, Jean's running speed is 9 mph and riding speed is x+9 = 9+9 = 18 mph

We can set up a time equation for both running and cycling, which then we add together and set to equal the given total time. Solving this equation reveals Jean's running speed to be approximately 6 mph and cycling speed to be 15 mph.

Given the scenario, we can set up two equations for time. The first equation is time equals distance divided by speed. For running, we have time = 8 mi / speed. For cycling, time = 11 mi / (speed + 9 mph), since her speed on bike is 9 mph faster than her running speed.

The total time spent for both running and cycling is given as 1.5 hours. Therefore, adding the two time equations we have: 8/speed + 11/(speed + 9) = 1.5.

Solving this equation will give us the value of her running speed. Through algebraic calculations, we get that her running speed is about 6 mph. And consequently, her cycling speed is 6 mph + 9 mph = 15 mph.

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larger amount = 630

the smaller amount, that is 5 parts is 450

divide 450 by 5 to find 1 part of the ratio

[tex]\frac{450}{5}[/tex] = 90 ← 1 part

7 parts, the larger amount = 7 × 90 = 630

since there are two bags and theyre equal in weight, you have to subtract 3 then divide by 2.

Answer: Hello!

There are two bags:

you write: "the weight of bag B is 3 pounds more than twice the weight of both bags of potatoes is 27 pounds."

this has no sense, I think you want to write something like:

"The weight of bag B is 3 pounds more than the weight of bag A, and twice the weight of both bags of potatoes is 27 pounds.

If we define B as the wheight of bag B, and A as the wight of bag A; we know that:

B - A = 3lb

2( B + A) = 27lb

in the first equation we can isolate B as: B = 3lb + A, and then replace it in the second equation:

2(B+ A) =27lb

2( (3lb + A) + A) = 27lb

6lb + 3A = 27lb

3A = 27lb - 6lb = 21lb

A= 21lb/3 = 7lb

now we can replace it in the first equation and get:

B - A = 3lb

B - 7lb = 3lb

B = 3lb + 7lb = 10lb

Then Bag A weights 7lb and bag B weights 10lb.

1 cm = (1/100) of a meter

centi is one one hundredth.

(0,6)

y=-2x(0)+6

y=6

(5,4)

y=-2(5)+6

y=-10+6

y=-4

(-7,20)

20=-2x+6

20-6=-2x+6-6

14=-2x

14/-2=-2x/-2

-7=x

Based on the cost of $2 per goldfish, the total price for 7 goldfish would be $14, not $13 as Adrianna claimed.

Adrianna's claim that it costs $13 for 7 goldfish does not seem correct given your statement that goldfish are $2 each. If each goldfish costs $2, then for 7 goldfish, the cost would be $2 x 7 = $14, not $13. It's important to recognize that the cost per goldfish can greatly influence the total cost when purchasing multiple goldfish.

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The statement 'The experimental procedure is to bet on one object. Then, roll three Lucky Dice and count the number of matches. The number of matches will decide your profit.' is an example of empirical probability. Empirical probability is calculated by dividing the number of times an event occurs by the total number of opportunities for the event to occur.

The statement 'The experimental procedure is to bet on one object. Then, roll three Lucky Dice and count the number of matches. The number of matches will decide your profit.' is an example of empirical probability.

Empirical probability is calculated by dividing the number of times an event occurs by the total number of opportunities for the event to occur. In this case, the student is rolling three dice and counting the number of matches, which is an observation-based approach to determining the probability.

An example of empirical probability in action is conducting an experiment to see how many times a specific outcome occurs, such as rolling dice or flipping coins, and then using that data to calculate the probability of that outcome happening.

The statement that represents an example of empirical probability is:

"In order to find the percentage of bass that he had in his pond this spring, Matt decided to spend 5 days catching a total of 15 fish each day and counting how many of those were bass." Option 4 is correct.

What is empirical probability ?

Actual observations or data gathered from studies or observations serve as the foundation for empirical probability.

In this instance, Matt is gathering information by counting the quantity of bass he catches relative to the total amount of fish he catches over time.

36 ft. And you behind on apex btw

Answer: 36 feet

Step-by-step explanation:

Let x be the height of tree

From the question, we can see there is a directly proportional relationship.

therefore, [tex]\frac{\text{height of Jason's eye}}{\text{distance of mirror from Jason}}=\frac{\text{height of tree}}{\text{distance of tree from mirrror}}\\\\\Rightarrow\frac{6}{7}=\frac{x}{42}\\\\\Rightarrow\ x=\frac{42\times6}{7}\\\\\Rightarrow\ x=36\ feet[/tex]

Hence, The height of the tree= 36 feet

I believe the correct answer is D. Since the graph of the parabola has a domain for x < 4, and the line presents a domain for x > = 4, then the only option with these conditions is D!

Hope this helps! :)

V = l*w*h   we divide both sides by l*w and we get

(V / (l*w) ) = h

Answer:

20 students do NOT prefer math over lunch.

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Algebraic Equations.

If nine out of ten students ([tex]\frac{9}{10}[/tex]) prefer math class over lunch, then we can infer that one out of ten students ([tex]\frac{1}{10}[/tex]) do not.

[tex]\frac{1}{10} = 0.10[/tex] or 10%

As we can see, this equals a 10% of the students that were asked. If 200 students were asked, we would need to find what 10% of 200 would be. We can do this by multiplying 200 by the decimal form of 10% like so,

[tex]200 * 0.10 = 20 students[/tex]

So we can see that 20 students do NOT prefer math over lunch.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

The ratio of soccer balls to footballs is 3/5.

To write the ratio of soccer balls to footballs as a fraction in simplest form, you need to divide the number of soccer balls by the number of footballs. In this case, there are six soccer balls and ten footballs. So the ratio can be written as 6/10. To simplify this fraction, you can divide both the numerator and denominator by their greatest common factor, which in this case is 2. Thus, the ratio of soccer balls to footballs as a fraction in simplest form is 3/5.

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12x+1

Hope this helps