Nonpolar molecules that cluster away from water molecules are called __________ molecules.

Answers

Answer 1
the answer is hydrophobic
Answer 2
Final answer:

Hydrophobic molecules are nonpolar molecules that cluster away from water molecules. They have nonpolar covalent bonds and examples include oil, fats, and waxes.

Explanation:

Nonpolar molecules that cluster away from water molecules are called hydrophobic molecules. Hydrophobic molecules typically have nonpolar covalent bonds, which means the electronegativity difference between the bonded atoms is minimal. This leads to an absence of partial charges on the atoms, resulting in overall nonpolarity. Examples of hydrophobic molecules include oil, fats, and waxes.

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Related Questions

Using the periodic table determine the atomic mass of Na2C2O4

Answers

masses of atoms are the sum of neutrons and protons. Atomic mass given for the element is the weighted atomic masses of the isotopes depending on the abundance of the isotopes.
Atomic masses of the elements making up Na₂C₂O₄ are as follows;
Na - 22.98 a.m.u
2 atoms of Na - 22.98 x 2 = 45.96
C - 12.01 a.m.u
2 atoms of C - 12.01 x 2 = 24.02
O - 15.99 a.m.u
4 atoms of O - 15.99 x 4 = 63.96
Sum of the atomic masses = 45.96 + 24.02 + 63.96 = 133.94 
Mass is 133.94 g/mol

A manganese atom is pictured below.



How many electrons would be free floating and able to form a metallic bond?

1
2
15
24

Answers

Manganese   has  2 (two) electron  that   would  free  floating   and   able  to  form  a  metallic  bond.

  The    electronic  configuration  of  manganese  is  (Ar)  3d5 4s2.  The   two   electron  in  4s  orbital  are  the  valence    electron  which  can  freely  move  from  one  place  to  another.



The correct answer is 2

How many molecules are in 2.10 mol CO ?

A.) 2.53 x 10^24
B.) 3.49 x 10^-24
C.) 3.79 x 10^24
D.) 1.26 x 10^24

Answers

d) 1.26 x 10^24

Hope this helped!

The number of molecules present in 2.10 moles of CO₂ is 1.264×10²⁴ molecules. Therefore, option D is correct.

What do you mean by mole ?

The mole is the amount of substance in a system that contains as many elementary entities as there are atoms in 0.012 kilogram of carbon 12; its symbol is "mol".

In the International System of Units, the mole (symbol mol) is the unit of substance amount (SI). The amount of substance is a measurement of how many elementary entities of a given substance are present in an object.

From Avogadro's hypothesis as follows;

1 mole of any substance = 6.023×10²³ molecules.

This implies that:

1 mole of CO₂ = 6.023×10²³ molecules

With the above information, we can obtain the number of molecules in 2.10 moles of CO₂. This can be obtained as given below:

1 mole of CO₂ = 6.023×10²³ molecules

Then,

2.10 moles of CO₂ = 2.10 × 6.02×10²³

2.10 moles of CO₂ = 1.264×10²⁴ molecules

Thus, the number of molecules present in 2.10 moles of CO₂ is 1.264×10²⁴ molecules., option D is correct.

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The change of state from a gas to a liquid is called _____.
a. deposition
b. sublimation
c. condensation
d. evaporation

Answers

the answer is
C. condensation
ANSWERC. CondensationCould you mark me brainliest, please?

An experiment requires 54.6 g of ethylene glycol, a liquid whose density in SI units is 1114 kg/m3. Rather than weigh the sample on a balance, a chemist chooses to dispense the liquid using a graduated cylinder. What volume in milliliters of the liquid should be used?

Answers

Answer: 49.0 cm^3

Explanation:

1) formula: density = mass / volume

=> volume = mass / density

2) mass (given) = 54.6 g

3) density (given) = 1114 kg / m^3

conversion of units: 1114 kg/ m^3 * 1000 g/kg * 1 m^3 / (1,000,000 cm^3) = 1.114 g/cm^3

4) calculation:

volume = 54.6 g / 1.114 g/cm^3 = 49.0 cm^3

Answer:

Volume in milliliters of the liquid should be used is 49 mL.

Explanation:

Mass of the ethylene glycol = 54.6 g = 0.0546 kg

Density = [tex]1114 kg/m^3[/tex]

Volume of ethylene gylcol = V

[tex]Density=\frac{Mass}{Volume}[/tex]

[tex]1114 kg/m^3=\frac{0.0546 kg}{V}[/tex]

[tex]V=\frac{0.0546 kg}{1114 kg/m^3}=4.90\times 10^{-5} m^3[/tex]

[tex]1 m^3=1000 L[/tex]

[tex]4.90\times 10^{-5} m^3=4.90\times 10^{-5}\times 1000=4.90\times 10^{-2} L=49 ml[/tex]

1 L = 1000 mL

Volume in milliliters of the liquid should be used is 49 mL.

A liquid that evaporates at a slow rate exhibits __________.

strong intermolecular forces

weak intermolecular forces

no intermolecular forces

a low volatility

Answers

strong internolecurar forces (A) hope it helps

Substances with weaker intermolecular forces evaporate faster due to higher vapor pressure and volatility.

Substances with weaker intermolecular forces evaporate faster than substances with stronger intermolecular forces.

Weak intermolecular forces lead to a higher vapor pressure and increased volatility in substances, causing them to evaporate at a faster rate.

#1: Which of the following is an exothermic reaction?

A. dissolving ammonium nitrate in water to cool the water

B. condensation

C. melting ice

D. dissolving sugar in water


**my answer; C

is that right? @aaronq :)

Answers

An exothermic reaction is one in which heat is released from the reagents into the ambient environment. Perhaps somewhat counterintuitively, condensation is in fact an example of such a reaction. During the process of the gas-to-liquid phase change, water goes from a higher-energy to lower-energy state of matter, and, as such, releases heat into the environment.

Why is carbon added to iron to make nails?

Answers

Carbon atoms can distort the well-arranged atoms of iron, adding some amount of strength and toughness to it. Nails are often small in cross-section, so higher strength is valued in steel. Different grades of steel have different amounts of carbon (and other additives). These are often dependent on the final application.

How is the reaction quotient used to determine whether a system is at equilibrium? a at equilibrium, the reaction quotient is undefined. b the reaction is at equilibrium when q>keq. c the reaction is at equilibrium when q=keq. d the reaction is at equilibrium when q

Answers

The correct answer is C the reaction is at equilibrium when q = Keq
1-As when q > Keq :
the reaction is not at equilibrium, the reaction will move towards the left to increase the reactants and decrease the products to achieve equilibrium, and the reaction is preferring the reverse reaction to achieve the equilibrium.

2- and when q< Keq:
the reaction is not at equilibrium, the reaction will move towards the right to increase the products and decrease the reactants to achieve equilibrium, and the reaction is preferring the forward reaction to achieve the equilibrium.

3-and when q= Keq
This means that the reaction is at equilibrium, and there is no shift to right or to the left to make equilibrium, and the forward and reverse reaction is at the same rate. 
So the correct answer is C the reaction is at equilibrium when q = Keq

The process by which a gas is converted to a liquid is called

Answers

solution:

These phase changes can be brought about by heating or cooling. ... This kind of phase change--liquid to gas--is called evaporation or vaporization. Water vapor can in turn be cooled to form liquid water. This kind of phase change--from gas to liquid--is referred to as condensation vaporization.  

Condensation is the change of the physical state of matter from gas phase into liquid phase, and is the reverse of vaporization. The word most often refers to the water cycle.

This is required answer


6.5 moles AlCl3 reacts with 57.0g of NaOH. how many grams of Al(OH)3 will be produced

Answers

the equation for the reaction between NaOH and AlCl₃ is as follows;
3NaOH + AlCl₃ ---> 3NaCl + Al(OH)₃
the stoichiometry of NaOH : AlCl₃ is 3:1
3 moles of NaOH reacts with 1 mol of AlCl₃ to produce 1 mol of Al(OH)₃
the number of AlCl₃ moles reacted - 6.5 mol
molar mass of NaOH -(23 +16 +1) = 40 g/mol
the number of NaOH moles reacted = 57.0 g / 40 g/mol
 NaOH moles = 1.425 mol
either NaOH or AlCl₃ is in excess and other is the limiting reactant.
limiting reactant is the reactant whose number of moles are fully consumed during the reaction. the reactant that is in excess will have leftover moles that are remaining after the reaction.
If AlCl₃ is the limiting reactant, number of NaOH moles would be thrice the amount of AlCl₃ present,
then number of NaOH moles that should be present - 6.5 * 3 = 19.5 mol
however there are only 1.425 mol of NaOH present, therefore AlCl₃ is in excess.
Then NaOH is the limiting reactant,
the amount of products formed depends on the amount of the limiting reactant present.
stoichiometry of NaOH : Al(OH)₃ is 3:1
the number of Al(OH)₃ moles produced = number of NaOH moles reacted / 3
 number of Al(OH)₃ moles are - 1.425 mol /3  = 0.475 mol
molar mass of Al(OH)₃ = (27 +3*16 + 3*1) = 78 g/mol
mass of Al(OH)₃ produced = 78 g/mol * 0.475 mol = 37.05 g

Ozone, O3(g), is a form of elemental oxygen produced during electrical discharge. Is ΔH∘f for O3(g) necessarily zero? Yes or no question?

Answers

The answer for your question is No. This is because in given conditions, it is not the most stable form of oxygen's element. It will not equate into zero because there will be charge remained after balancing the equation. 

Answer: ΔH°f is not zero

Explanation:

the change in enthalpy formation is zero when elements are pure.when they are zero it is mainly  because they are most basic,where you cannot form an element with an element.

Molecular formulas: You find that 7.36 g of a compound has decomposed to give 6.93 of oxygen. The rest of the compound is hydrogen. If the molar mass of the compound is 34.0, what is its molecular formula?

Answers

2OH is the molecular formula and the imperial cal formula is OH.

Which of the following separation methods is used to separate plant pigments?
(Points : 3)
chromatography

simple distillation

fractional distillation

filtration

Answers

Chromatography is the technique used to separate mixtures into the components that make up those mixtures. In chromatography the different pigments are separated into bands of pigment through their differences in intermolecular forces.

Answer: chromatography

Explanation:

Chromatography : It is a type of separation process in which the liquid or gas is separated into components at different rate. The principle of chromatography is that the substance of molecule are distributed between the liquid phases. It involves a stationary and a mobile phase.  Hence,chromatography is a laboratory technique that is used to  separate plant pigments.

Distillation : It is a type of separation process in which the mixture of liquid separated or evaporated at different temperatures.

Fractional distillation is separation of a liquid mixture into fractions which differ in boiling points by means of distillation by use of a fractionating column.

Filtration : It is a type of mechanical separation process in which the solid is separated from the liquid through the filter paper.

How mary significant igures are in the messurement 20,500 liters?

Answers

Answer:  "3 (three) " .
_______________________________________________________
The, "2" , "0" , and "5" , are the three (3) significant figures.
_______________________________________________________

if an object 18 millimeters high is placed 12 millimeters from a diverging lens and the image is formed 4 mm in front of the lens what is the height of the image

Answers

I think the answer is 7mm but I'm not sure.

Have a great day!

The answer is 6mm

You're welcome!

A 10.0-L rigid container holds 3.00 mol H2 gas at a pressure of 4.50 atm. What is the temperature of the gas?

Answers

We can approach this problem using the ideal gas law which is as follows:

PV = nRT

P = pressure
V = volume
n = number of moles
R = gas constant, 0.08206 Latm/Kmol
T = temperature

We are asked to solve for temperature and can rearrange the equation to solve for T:

PV = nRT
T = PV/nR

Now we simply plug in the data to solve for T:

T = (4.50 atm)(10.0 L)/(3.00 mol)(0.08206 Latm/Kmol)
T = 183 K

The temperature of the gas is 183 K.

Answer. A. 183

B. 142

C. 0.03

D.11.3

E.24.5

Explanation:

The following chemical equation is not balanced: C3H8 + O2 CO2 + H2O When this chemical equation is correctly balanced, what is the coefficient of the carbon dioxide molecule?

Answers

C3H8 +5O2 -> 3CO2+4H2O

3 would be the answer to your question...

What describes the change in oxidation states of the following reaction?

2Cl- + F2 > 2F- + Cl2

a. Cl– reduces to Cl and F oxidizes to F–.
b. Cl– oxidizes to Cl and F reduces to F–.
d. Cl is the reducing agent and F– is the oxidizing agent.

Answers

The answer is B, Cl- oxidizes to Cl and F reduces to F-.An oxidizing agent, gains electrons and is reduced in a chemical reaction. While reduction Reductio is the loss of oxygen atom from a molecule which results to gaining electrons.

What is the mass of 1.50 mol C5H12

Answers

Final answer:

The mass of 1.50 mol of C₅H₁₂ is calculated to be 108.09 g using the molar mass of the compound.

Explanation:

The molar mass of a compound is the total mass of all the atoms in the molecule. The compound C₅H₁₂ consists of 5 carbon atoms and 12 hydrogen atoms. Given that the atomic mass of carbon (C) is 12.01 g/mol and the atomic mass of hydrogen (H) is 1.01 g/mol, the molar mass of C₅H₁₂can be calculated as: (5 x 12.01 g/mol) + (12 x 1.01 g/mol) = 72.06 g/mol. Therefore, the mass of 1.50 mol C₅H₁₂ would be (1.50 mol x 72.06 g/mol) = 108.09 g.

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Final answer:

The mass of 1.50 mol of C5H12 (pentane) is 108.2247 grams. First, the molar mass of C5H12 is calculated by summing the atomic masses of carbon and hydrogen, then this molar mass is multiplied by the number of moles given (1.50 mol) to find the mass.

Explanation:

To calculate the mass of 1.50 mol of C5H12, we need to first determine its molar mass. The molar mass of a compound is the sum of the masses of all the atoms in one mole of that compound. For C5H12, which is pentane, the molar mass can be calculated as follows:

(5 atoms × 12.011 g/mol for Carbon) + (12 atoms × 1.0079 g/mol for Hydrogen)(5 × 12.011) + (12 × 1.0079) = 60.055 + 12.0948 = 72.1498 g/mol

Now that we have the molar mass, we can find the mass for 1.50 mol:

1.50 mol × 72.1498 g/mol = 108.2247 grams

This calculation assumes that the molar mass has been rounded to four significant figures to match the precision of 1.50 mol, thus the mass of 1.50 mol C5H12 is 108.2247 grams with four significant figures.

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Which of the following represents a chemical change. A water to boiled
B Paper is torn
C Glass is shattered
D Wood is burned

Answers

Hello,

Here is your answer:

The proper answer to this question is option D "wood is burned". Its a chemical change because its changing forms wood to ash.

Your answer is D.

If you need anymore help feel free to ask me!

Hope this helps!

to answer your second question, it is D

1.this substance is a natural non-living material with a uniform structure throughout


A) Mineral

B) Rock


2. Any rock can become a/an (igneous, metamorphic, or sedimentary)_______rock by melting and reforming


3.A sedimentary rock can become a metamorphic rock by exposure to high heat and great__________

Answers

1.Mineral
2.Igneous
3.Composition

(1) The nonliving material with uniform structure has been Mineral. Thus, option A is correct.

(2) The rock formed by the cooling of volcanic eruption and lava has been the igneous rock.

(3) A sedimentary rock can become a metamorphic rock by exposure to high heat and great pressure.

The rock and minerals are the nonliving compositions of the nature that are rich source of many fuels, and natural gases.

The varying form of rocks are present in the nature, and are converted from one form to another.

Rock and Rock cycle

(1) Rocks have been defined as the material with nonuniform structure and composition. Rocks are the rich mineral source. They are the uniform structure throughout the material.

Thus, the nonliving material with uniform structure has been Mineral. Thus, option A is correct.

(2) The rock has been converted from one form to another in the rock cycle. The sedimentary rocks are formed by the deposits from the sea. The breakdown of sedimentary rock result in the metamorphic rocks.

The metamorphic rocks are deep inside the crust.

The rock formed by the cooling of volcanic eruption and lava has been the igneous rock.

(3) The sedimentary rocks are converted to the metamorphic rocks by the application of high heat and pressure to the sediments.

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Jose’ has a circular rug on the floor of his bedroom. If the area of the rug is 16π square feet, what is the diameter of the rug? The diameter of the rug is feet.

Answers

Answer: 8 feet

Explanation:

1) The diameter and the area of a circle are related by this formula:

Area = π (radius)^2 = π (diameter / 2) ^2 = π (diameter)^2 / 4

2) Since you know the area you can find the formula for the diameter:

(diameter)^2 = 4 * area / π

=> diamter = √ [4*area / π]

3) Replace the value of the area

area = 16π (feet)^2

=> diameter = √ [ 4 * 16 π (feet)^2 / π ] = √ 64 feet = 8 feet

Answer: diameter = 8 feet

Enriched weapons-grade uranium consists of 80% uranium-235 (235.044 amu) and 20% uranium-238 (238.051 amu). what is the average atomic mass of weapons-grade uranium, assuming the percentages are exact?

Answers

Final answer:

To find the average atomic mass of weapons-grade uranium, calculate the weighted average based on the percentages of each isotope: 80% of 235.044 amu (uranium-235) and 20% of 238.051 amu (uranium-238), yielding an average atomic mass of 235.6454 amu.

Explanation:

To calculate the average atomic mass of weapons-grade uranium, which consists of 80% uranium-235 and 20% uranium-238, you multiply the mass of each isotope by its relative percentage (expressed as a decimal) and then sum the results. The atomic mass unit (amu) for uranium-235 is 235.044 and for uranium-238 is 238.051.

The average atomic mass can be calculated as follows:

(80% of uranium-235) 80/100 × 235.044 amu = 188.0352 amu

(20% of uranium-238) 20/100 × 238.051 amu = 47.6102 amu

Add these values together: 188.0352 amu + 47.6102 amu = 235.6454 amu

Therefore, the average atomic mass of weapons-grade uranium is 235.6454 amu.

#1: A material has a density of 8.9 g/cm^3. You have six cubic centimeters of the substance. What is the material’s mass in grams?

A. 3.0 g

b. 5.9 g

C. 27 g

D. 53 g
**Idk i think it is either C. 27 g or D. 53 g :/

Answers

The density of a material = mass/ volume From the question, volume = 6 cm^3. Since the density = 8.9 g/cm^3 We have that 8.9 = mass/ 6 So mass = 8.9 * 6 = 53.4 So it follows that our mass = 53.4g. Hence option D which is 53g.

What is the empirical formula of a compound composed of 32.9g of potassium and 6.73 g of oxygen

Answers

The  empirical   formula   is  calculated  as   follows
   step 1 ;  calculate   the   moles  of   each  element

K =  32.9 g/39  g/mol  (molar  mass of   potassium)   =  0.84  moles
 
O =  6.73 g  /16  g/mol  (  molar   mass   of  oxygen)  =  0.42  moles

step 2 ;  calculate  the  mole  ratio     by  dividing  by  smallest  number  of  mole
K=  0.84 /0.42=2 
O=   0.42/0.42=  1

therefore  the  empirical    formula  =  K2O

Hi, I can't seem to answer the letter b.--> An empty vial weighs 55.32 g. (a) If the vial weighs 185.56 g when filled with liquid mercury (d 13.53 g/cm3), what is its volume? (b) How much would the vial weigh if it were filled with water (d 0.997 g/cm3 at 25°C)?,

Answers

Subtract the mass when full from the mass when empty.
185.56 - 55.32 = 130.26 g. 
Divide by the density of liquid mercury to find the volume.
130.26 g / 13.53g/cm^3 = 9.62601626 cm, the volume of the vial.

If water was used instead of mercury, the fluid mass would be
9.62601626 cm * .997 g/cm^3 = 9.597 g

Adding this to the empty vial mass of 55.32 gives a final mass of 64.916 g.

Which
molecule has the same shape and hybridization as methane

Answers

Hi, the answer is CF2Cl2 :)

Answer:

cfcl2

Explanation:edg

Stoichiometry
---
Use the following reaction to determine the number of liters of hydrogen that must react with 20 L of oxygen to form water vapor.
---
Equation:
---
2H2  +  O2   ->   2H2O
---

Answers

stoichiometry is the ratio of reactants to products in a balanced chemical reaction equation. 
the stoichiometry in this case of H₂ to O₂ is 2:1.
This means that 2 moles of H₂ reacts with 1 mol of O₂.
we have been asked to calculate the volume of H₂ gas.
Since both O₂ and H₂ are gases, at standard conditions its stated that molar volume of gases is 22.4 L
This means that at standard temperature and pressure, 1 mol of any gas occupies a volume of 22.4 L
first we need to calculate the number of O₂ moles reacted;
22.4 L of gas - 1 mol of O₂
1 L of gas - 1/22.4 mol/L 
then 20 L of O₂ - 1/22.4 mol/L * 20 L = 0.89 mol
stoichiometry of H₂ to O₂ is 2:1
the number of H₂ moles = 0.89*2 = 1.79 mol
1 mol occupies 22.4 L
Therefore 1.79 mol = 22.4 L/mol * 1.79 mol = 40 L
Therefore it can be seen that stoichiometry applies to volumes as well.
volume of H₂ : O₂ = 40 L : 20 L = 2:1
volume and moles both can be determined by stoichiometry.
Volume of H₂ reacted = 40 L

The partial pressure of carbon dioxide in systemic arterial blood is __________. the partial pressure of carbon dioxide in systemic arterial blood is __________. 100 mm hg 40 mm hg 104 mm hg 45 mm hg

Answers

In the systemic arteries, the partial pressure of carbon dioxide is  40 mm Hg.  Partial pressure of a gas is the contribution of one gas to the total pressure exerted by all gases. Partial pressure of carbon dioxide in arterial blood is the portion of total blood gas pressure that is exerted by carbon dioxide. It decreases during heavy exercise, during rapid breathing, or in association with severe diarrhea, uncontrolled diabetes or the diseases of the kidney. It increases with chest injuries and respiratory disorders. In the systemic arteries, the partial pressure of  oxygen is 100 mm Hg.

The partial pressure of carbon dioxide (PCO2) in systemic arterial blood is approximately 40 mm Hg.

The partial pressure of a gas in a mixture, like blood, is a measure of the pressure that gas exerts independently, assuming ideal behavior. In the context of blood gases, PCO2 is a crucial parameter reflecting the concentration of dissolved carbon dioxide in the bloodstream.

Normal systemic arterial blood PCO2 levels typically range from 35 to 45 mm Hg. This range is maintained within a very narrow margin as part of the body's acid-base balance, regulated by the respiratory system and the kidneys.

A PCO2 value significantly higher than 45 mm Hg can indicate respiratory acidosis, a condition where the blood becomes too acidic due to excess carbon dioxide. On the other hand, a PCO2 value below 35 mm Hg may indicate respiratory alkalosis, where the blood becomes too alkaline due to insufficient carbon dioxide.

Therefore, a PCO2 of 100 mm Hg, 104 mm Hg, or 45 mm Hg does not represent the typical PCO2 in systemic arterial blood and would suggest an abnormal condition. A PCO2 of 40 mm Hg is within the normal range for systemic arterial blood PCO2.

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