Object A has a density of 10 g/cm3 and a mass of 9 g. Object B has a density of 10 g/cm3 and a mass of 4 g. Which object has a greater volume and by how much?

Answers

Answer 1
mass=Density * volume
volume=mass/Density
volume A=mass A/Density A=9g/10g/cm³=0.9 cm³

volume B=mass B/Density B=4g/10g/cm³=0.4 cm³

0,9 cm³>0.4 cm³
volume A>volume B

Related Questions

When 0.440 mol of aluminum are allowed to react with an excess of chlorine gas, cl2, how many moles of aluminum chloride are produced? when 0.440 mol of aluminum are allowed to react with an excess of chlorine gas, cl2, how many moles of aluminum chloride are produced? 0.880 mol 0.440 mol 0.330 mol 0.220 mol 0.110 mol?

Answers

Final answer:

When 0.440 mol of aluminum react with excess chlorine gas, 0.440 mol of aluminum chloride are produced according to the 1:1 stoichiometric ratio in the balanced chemical equation.

Explanation:

When 0.440 mol of aluminum are allowed to react with an excess of chlorine gas (Cl2), to determine how many moles of aluminum chloride (AlCl3) are produced, we look at the stoichiometry of the balanced equation:

2 Al (s) + 3 Cl2 (g) → 2 AlCl3 (s)

This reaction shows that 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride. Given the stoichiometry is a 1:1 ratio between aluminum and aluminum chloride, if you start with 0.440 mol of aluminum, you would end up producing 0.440 mol of aluminum chloride as well, provided chlorine is in excess.

Lithium hydroxide is used to purify air by removing carbon dioxide. a 25.00ml sample of lithium hydroxide solution is titrated to an end point by 15.22 ml of a 0.3340m hydrochloric acid solution. what is the molarity of the lioh solution

Answers

the balanced reaction between LiOH and HCl is as follows
LiOH + HCl ----> LiCl + H₂O
stoichiometry of LiOH to HCl is 1:1
number of moles of HCl reacted = concentration of HCl x volume 
number of HCl moles = 0.3340 mol/L x (15.22 x 10⁻³ L) = 5.083 x 10⁻³ mol 
according to molar ratio
number of HCl moles = number of LiOH moles
number of LiOH moles in 25.00 mL = 5.083 x 10⁻³ mol 
therefore LiOH moles in 1 L = 5.083 x 10⁻³ mol / (25.00 x 10⁻³ L) = 0.2033 mol/L
molarity of LiOH - 0.2033 M

What most determines the entropy of a solid? A. The mobility of electrons in the solid B. The crystalline structure of the solid C. The specific heat capacity of the solid D. The enthalpy of formation of the solid

Answers

the correct answer is B.
The crystalline structure of solid is the most to determine the entropy of a solid. Entropy can be termed as disorder or chaos in a closed system.
The densest solid is Osmium. To determine the solubility products in solids in water is tabulated in specified pressure and temperature. 

Answer:

The crystalline structure of the solid

Explanation:

The third law of thermodynamics has to do with entropy. It states that the entropy of a perfectly ordered crystal lattice is zero at the absolute zero temperature.

Let us be reminded that entropy is the degree is disorderliness in a system. Hence, atoms of a crystal lattice stop moving as the system approaches absolute zero, the entropy also tends to a constant value.

This clearly shows that the crystalline structure of a solid material determines the degree of entropy of the solid.

What is the melting point of a solution in which 3.5 grams of sodium chloride is added to 230 mL of water?

Answers

we are going to use this equation:

ΔT = - i m Kf

when m is the molality of a solution 

i = 2

and ΔT is the change in melting point = T2- 0 °C

and Kf is cryoscopic constant = 1.86C/m

now we need to calculate the molality so we have to get the moles of NaCl first:

moles of NaCl = mass / molar mass

                         = 3.5 g / 58.44 

                         = 0.0599 moles


when the density of water = 1 g / mL and the volume =230 L

∴ the mass of water = 1 g * 230 mL = 230 g = 0.23Kg 

now we can get the molality = moles NaCl / Kg water

                                                =0.0599moles/0.23Kg

                                                = 0.26 m

∴T2-0 =  - 2 * 0.26 *1.86

∴T2 = -0.967 °C

Answer:

0.952 °C

Explanation:

The change in melting point is computed as:

ΔT = k*m*i

where ΔT is the difference between the melting point of water and of solution, k is a constant (1.86 °C*kg/mol for water), i is the van't Hoff factor (equal to 2 for sodium chloride because 2 ions are obtained after its dissolution), and m is the molality of the solution.

Molar mass of sodium chloride: 58.44 g/mol

Moles of of sodium chloride: mass / molar mass 3.5/58.44 = 0.059 mol

Density of water 1 kg/L

230 mL of water are equivalent to 0.23 L

mass of water: density * volume = 1*0.23 = 0.23 kg

Molality of the solution: m = moles of solute/ kg of solvent = 0.059/0.23 = 0.256

Finally:

ΔT = 1.86*0.256*2 = 0.952 °C

Water melting point: 0 °C

So, the solution melting point is: 0 - 0.952 = 0.952 °C

Which of these formulas is the expanded structural formula for an alkane with three carbon atoms? which of these formulas is the expanded structural formula for an alkane with three carbon atoms? c– c– c ch3–ch2–ch3 c3h6 c3h8?

Answers

Final answer:

The expanded structural formula for a three-carbon alkane is CH3-CH2-CH3, which represents propane (C3H8) following the general alkane formula CnH2n+2.

Explanation:

The expanded structural formula for an alkane with three carbon atoms is CH3-CH2-CH3. In the alkanes series, each molecule follows the general formula CnH2n+2, indicating that for three carbon atoms, the molecular formula is C3H8. Thus, the correct choice from the options provided is CH3-CH2-CH3, which is the condensed structural formula for propane.

What is the value of n when the empirical formula is c3h5 and the molecular mass is 205.4?

Answers

empirical formula is the simplest ratio of whole numbers of components in a compound.
the empirical formula - C₃H₅
mass of empirical formula - (12 g/mol x 3) + (1 g/mol x 5) = 41 g
we have to find how many empirical units make up the molecular formula 
number of empirical units = molecular mass / mass of empirical formula 
empirical units = 205.4 g/mol / 41 g = 5.00
molecular formula - n (C₃H₅)
n - number of empirical units 
therefore n = 5 

Which property of gases allows you to smell popcorn when you walk into a movie theater? compressibility of gas particles diffusion definite shape effusion

Answers

Diffusion. When you smell something you are actually smelling the gas it lets off

if 24500 J is applied to 125g of water at 35 C, what will the final temperature of the water be?

Answers

The  final  temperature  of  water  is calculated  using the below  equation

Q= MC delta  T
Q= heat  energy (24500  j)
m= mass( 125 g)
c= specific   heat capacity (  4.18  j/g/c)
delta T = change  in temperature ( final temperature -initial  temperature)=(T-35)

final  temperature  is therefore=24500 j =125 g x 4.18 g/j/c  x (T- 35)
24500 j=522.5 (T-35 c)
24500 j = 522.5T -18287.5

like  terms  together  24500 + 18287.5 =522.5 T
42787.5j =522.5 T
divide both  side  by  522.5 T

T=81.9 c


A cube of iron (Cp = 0.450 J/g•°C) with a mass of 55.8 g is heated from 25.0°C to 49.0°C. How much heat is required for this process?

Answers

Q=c(p)*m*Δt
c(p)=0.450 J/g•°C
m= 55.8 g
Δt = t(final)-t(initial)=49.0⁰-25.0⁰ = 24.0⁰C

Q=c(p)*m*Δt = 0.450 J/g•°C *  55.8 g*24.0⁰C ≈ 603 J
Q≈ 603 J

is h2c2o4 an Arrhenius base or arrhenius acid

Answers

Answer:
            Oxalic Acid is and Arrhenius Acid.

Explanation:
                   According to Arrhenius Theory of acid and base, "Acid is any substance which when dissolved in water produces H⁺ Ions".

Therefore, Oxalic Acid is a diprotic substance, which is capable of donating protons in water. This acidity of oxalic acid can be dedicated to the stability of conjugate base, this stability comes from resonance of the negative charges on Oxalate ion. Below reaction shows the dissociation of Oxalic Acid into Protons and Oxalate Ion.

H₂C₂O₄, or oxalic acid, is an Arrhenius acid because it dissociates in water to produce hydrogen ions.

H₂C₂O₄, also known as oxalic acid, is an Arrhenius acid, not an Arrhenius base. An Arrhenius acid is defined as a compound which ionizes to yield hydrogen ions (H+) in aqueous solution, whereas an Arrhenius base ionizes to yield hydroxide ions (OH-). Since H₂C₂O₄ dissociates in water to produce two H+ ions and the oxalate ion (C₂O₄-), it increases the H+ ion concentration, making it an acid according to Arrhenius's definition.

Which of the following describes the strong nuclear force? A. A strong repelling force between protons and electrons B. A strong attractive force between protons and neutrons C. A strong repelling force between protons and neutrons D. A strong attractive force between neutrons and electrons

Answers

Answer:

The correct answer is option B.

Explanation:

Strong nuclear force is defined as strong force of an attraction which binds the quarks together to form a cluster of subatomic particles like protons and neutrons in the nucleus. This is the force which keeps the nucleus intact.

So, we can say that is an strong attractive force between the proton and neutron.

Answer:

B. A strong attractive force between protons and neutrons.

Explanation:

Correct answer for APEX quiz.

How to make sulfur hexafluoride?

Answers

sulfer and fluorine but you need special equipment to get it

Question 6 the chemical formula ch2o can be classified as: empirical only. molecular only. empirical, possibly molecular. not enough information none of the above

Answers

The chemical formula CH2O can be classified as Empirical formula and possibly a molecular formula. The empirical formula of a compound is the simplest formula that indicates the simplest ratio of atoms in the compound, while the molecular formula is the representation of the actual whole number ratio between the elements of the compound. 

The ratios of volumes of the gaseous reactants and products in a chemical reaction at constant temperature and pressure can be determined from the

Answers

The ratios of volumes of the gaseous reactants and products in a chemical reaction at constant temperature and pressure can be determined from the ratios of the mole (or coefficients) of the gaseous reactants and products.

How many kilojoules of heat are needed to completely vaporize 42.8 grams of c4h10o at its boiling point given that c4h10o has a heat of vaporization (δhvap) of +26.5 kj/mol and a molar mass of 74.12 g/mol?

Answers

Answer is: 15.30 kilojoules of heat are needed to completely vaporize C₄H₁₀.
m(C₄H₁₀) = 42.8 g.
M(C₄H₁₀) = 74.12 g/mol.
n(C₄H₁₀) = m(C₄H₁₀) ÷ M(C₄H₁₀).
n(C₄H₁₀) = 42.8 g ÷ 74.12 g/mol.
n(C₄H₁₀) = 0.577 mol.
Q = n(C₄H₁₀) · ΔHvap.
Q = 0.577 mol · 26.5 kJ/mol.
Q = 15.30 kJ, heat of butane.

Which of these changes would cause a decrease in the pressure of a contained gas?

Answers

The equation is pv=nrt. So to decrease pressure, one would increase volume, decrease moles, or decrease temperature.

If sodium loses 1 electron, it will have the same number of valence electrons as which noble gas?

Answers

atomic number of Na -11
 electronic configuration of Na - 2,8,1
outermost shell of Na has one electron. To become stable and to have a complete octet in the outermost shell, it loses that electron in the outermost shell and becomes positively charged.
Then electronic configuration is 2,8 with 10 electrons . Noble gas with atomic number 10 is Neon.Therefore it will have the same number of valence electrons as B) Neon

A 25.0 ml sample of 0.105 m hcl was titrated with 31.5 ml of naoh. what is the concentration of the naoh?

Answers

the balanced equation for the above reaction is 
NaOH + HCl ---> NaCl + H₂O
stoichiometry of NaOH to HCk is 11:
number of HCl moles reacted - 0.105 mol/L x 0.0250 L = 0.00263 mol
according to molar ratio, number of HCl moles = number of NaOH moles 
therefore number of NaOH moles - 0.00263 mol
number of moles in 31.5 mL - 0.00263 mol
therefore number of NaOH moles in 1000 mL = 0.00263 / 31,5 mL x 1000 mL
molarity of NaOH - 0.0835 M

The concentration of the NaOH: 0.083 M

Further explanation

Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution). Determination of the endpoint / equivalence point of the reaction can use indicators according to the appropriate pH range

Titrations can be distinguished including acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases is used.

An acid-base titration there will be a change in the pH of the solution.

From this pH change a Titration Curve can be made which is a function of acid / base volume and pH of the solution

Acid-base titration formula

Ma Va. na = Mb. Vb. nb

Ma, Mb = acid base concentration

Va, Vb = acid base volume

na, nb = acid base valence

Neutralization Reaction:

NaOH + HCl ⇒ NaCl + H₂O

25.0 ml, 0.105 M HCl was titrated with 31.5 ml of NaOH

Acid-base titration formula

Ma Va. na = Mb. Vb. nb

a = HCl, b = NaOH (both have valence 1)

0.105 M. 25 = Mb. 31.5. 1

[tex]\rm Mb = \dfrac {0.105 \times 25} {31.5} \\\\ Mb = \boxed {\bold {0.083 \: M}}[/tex]

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Which of the following processes is exothermic? which of the following processes is exothermic? the chemical reaction in a "cold pack" often used to treat injuries the vaporization of water?

Answers

Given the choices;
A) A candle flame
B) Baking bread
C) The chemical reaction in a "cold pack" often used to treat injuries
D) The vaporization of water
The correct answer would be A, a candle flame.
An exothermic reaction is a type of reaction where energy is lost from the system to the surroundings in form of heat and light energy. The opposite of exothermic reaction is the endothermic reaction where energy is absorbed from the surrounding to the system.

Answer:

Among the processes given i.e. Burning of candle, baking of bread, the reaction in a cold pack, and vaporization of water. The burning of the candle is an exothermic reaction.

Explanation:

The exothermic reactions are the ones in which there is an emission of energy.

In the baking of bread, the process grasps the energy and utilized it for the baking process. This is the form of an endothermic reaction.

The reaction of a cold pack for the treatment of injuries requires the heat from the surroundings and convert it to heat for recovery. So this requires energy and there is no loss in surroundings. It can't be the exothermic reaction.

The vaporization of water requires heat energy for transmission to the vapor state. This does not emit energy. This can't be the exothermic reaction.

The burning of Candle emits heat energy in the surroundings. This is considered an exothermic reaction.

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A 98.0°C piece of cadmium (c=.850J/g°C) is placed in 150.0g of 37.0°C water. After sitting for a few minutes, both have a temperature of 38.6°C. What was the mass of the cadmium sample?

Answers

The answer is 19.9 grams cadmium. 
Assuming there was no heat leaked from the system, the heat q lost by cadmium would be equal to the heat gained by the water:
     heat lost by cadmium = heat gained by the water
     -qcadmium = qwater
Since q is equal to mcΔT, we can now calculate for the mass m of the cadmium sample:
     -qcadmium = qwater
     -(mcadmium)(0.850J/g°C)(38.6°C-98.0°C)) = 150.0g(4.18J/g°C)(38.6°C-37.0°C)
     mcadmium = 19.9 grams


Which of the following equations can be used to determine the change in enthalpy of a system?

Answers

The answer for Plato will be letter A

A gas sample occupies 3.50 liters of volume at 20.°c. what volume will this gas occupy at 100°c (reported to three significant figures)?

Answers

Based on Charle's Law, we have
[tex] \frac{V1}{V2} = \frac{T1}{T2} [/tex]
where, V and T are volume and temperature respectively. 

Now, given that, V1 = 3.5 L, T1 = [tex] 20 ^{0}C[/tex] = 293 K and T2 = [tex] 100^{0}C[/tex] = 373 K

∴ V2 = [tex] \frac{(T2)X(V1)}{T1} = \frac{373 X 3.5}{293} = 4.556l [/tex]

Calculate the mass of sodium chloride produced when 5.50 moles of sodium reacts in excess chlorine gas

Answers

the mass of NaCl produced is calculated  as below

write the reacting equation

that is  2 Na + Cl2 =2 NaCl

by use of mole ratio between Na :NaCl which is 2 :2 t he moles of NaCl is also = 5.50 moles

mass  of NaCl= moles x molar mass

=5.50 moles  x58.5 g/mol = 321.75 grams

What is a functional group? A-a group of organs in the body that work together to perform a certain function B-a group of living things that are made up of organic compounds C-a group of atoms bonded to carbon that determines how the molecule will react D-a group of organic molecules that work together to speed up reactions

Answers

C-a group of atoms bonded to carbon that determines how the molecule will react

The answer to your question is C.

an aqueous solution of NaOh is used as a drain cleaner.If the concentration of OH^- ions in this solution is 1×10^-5,the concentration of H^+ ions in it would be?

Answers

[OH⁺][OH⁻}= 10 ⁻¹⁴
1*10⁻⁵*[H⁺]=10⁻¹⁴
[H⁺]= 10⁻¹⁴/10⁻⁵=10⁻⁹

[H⁺] = 10⁻⁹ M

An electrochemical cell is made up of two half-cells connected by a salt bridge and an external conductor. What is the function of the salt bridge?

Answers

The salt bridge prevents the direct mixing of one half-cell solution with the other and allows ions to migrate from one half-cell to another.

Salt bridge is used to maintain the electrical neutrality in a cell as migration of ions from half cell to other half cell occurs to keep the balance in charges. In the absence of the salt bridge, the charges get imbalanced. After that, the cell stops working because ions will collected in both the electrolytes until the potential difference due to ions and potential difference from the reaction is just opposite to each other. Due to this, flow of electrons doesn't takes place and no current will flow.

Therefore, the function of salt bridge is to maintain the electrical neutrality in a cell.

A sample of O2 occupies a volume of 600 mL. If the pressure exerted on the O2 is tripled with the temperature remaining constant, the new volume of the oxygen is

Answers

For 1 mole of an ideal gas, we have PV=RT............(Eq. 1)
where, P = pressure
V= volume
R = universal gas constant
T = Temperature

Let, P1, V1 and T1 be initial pressure, volume and temperature of [tex] O_{2} [/tex] respectively

Let, P2, V2 and T2 be pressure, volume and temperature of [tex] O_{2} [/tex] respectively, after application of pressure.

Using Eq. 1 we get, [tex] \frac{P1V1}{P2V2} = \frac{T1}{T2} [/tex] ....... (Eq. 2)

Now, since that T1=T2 and P2=3(P1)

∴ Eq. 2 becomes P1V1=P2V2
∴ [tex] \frac{V2}{V1} = \frac{P1}{P2} = \frac{1}{3} [/tex]
∴ V2 = [tex] \frac{1}{3} [/tex] V1

Thus, final volume V2 will be 1/3 of initial volume V1

In the word equation, sodium oxide water sodium hydroxide, the formula for sodium hydroxide is represented by

Answers

Answer:
            Formula for sodium hydroxide is represented by NaOH.

Explanation:
                     The reaction of Sodium oxide with water is as follow,

                               Na₂O  +  H₂O    →    2 NaOH

Na₂O is considered as a strong basic oxide as it contains O²⁻ which has high tendency to bind with hydrogen atoms. This reaction is an exothermic reaction and is conducted in cold water to produce NaOH.

The correct formula for sodium hydroxide in the given word equation is NaOH.

The word equation provided is:

[tex]\[ \text{sodium oxide} + \text{water} \rightarrow \text{sodium hydroxide} \][/tex]

To represent this equation with chemical formulas, we need to know the formulas for each compound:

- Sodium oxide (Na2O) is an ionic compound composed of sodium ions (Na+) and oxide ions (O2-).

- Water (H2O) is a molecular compound composed of two hydrogen atoms and one oxygen atom.

- Sodium hydroxide (NaOH) is an ionic compound composed of sodium ions (Na+) and hydroxide ions (OH-).

The balanced chemical equation for the reaction is:

[tex]\[ \text{Na}_2\text{O} + \text{H}_2\text{O} \rightarrow 2\text{NaOH} \][/tex]

This equation shows that sodium oxide reacts with water to form sodium hydroxide. The formula for sodium hydroxide is NaOH, which consists of one sodium ion (Na+) and one hydroxide ion (OH-). The coefficient 2 in front of NaOH indicates that two moles of sodium hydroxide are produced for every mole of sodium oxide and water that react.

Determine the molarity of a solution made by dissolving 11.7 g of NaNO3 in water where the final volume of the solution is 250.0 mL.

Answers

Molarity is defined as the number of moles of solute in 1 L solution.
we have been given the mass of NaNO₃ dissolved in 250.0 mL
number of moles of NaNO₃ - 11.7 g / 85 g/mol = 0.138 mol 
number of NaNO₃ moles in 250.0 mL - 0.138 mol 
since molarity is the number of moles in 1 L
number of NaNO₃ moles in 1000 mL - 0.138 mol / 250.0 mL x 1000mL/L = 0.552 mol 
molarity of NaNO₃ is 0.552 M

Answer:

[tex]0.552~M[/tex]

Explanation:

For the calculation of molarity "M" we have start with the molarity equation:

[tex]M=\frac{mol}{L}[/tex]

So, we have to calculate the moles of [tex]NaNO_3[/tex] and the L of [tex]NaNO_3[/tex].

For the calculations of moles we have to use the molar mass of [tex]NaNO_3[/tex].

Na=23 g/mol

N=14 g/mol

O= 16 g/mol

[tex]molar~mass~=~(23*1)+(14*1)+(16*3)=85~g/mol[/tex]

or

[tex]1~mol~NaNO_3=85~g~NaNO_3[/tex]

Now, we can find the moles of  [tex]NaNO_3[/tex]:

[tex]11.7~g~NaNO_3*\frac{1~mol~NaNO_3}{85~g~NaNO_3} =0.138~mol~NaNO_3[/tex]

The next step would be the converstion from mL to L:

[tex]250.0~mL~*\frac{1~L}{1000~mL} =~0.25~L\\[/tex]

Finally, we have to plug both values in the molarity equation:

[tex]M=\frac{0.138~mol}{0.25~L}=~0.552~M[/tex]

When a nucleus undergoes nuclear decay by gamma rays the atomic number of the element?

Answers

I believe that when a nucleus undergoes a nuclear decay by gamma rays the atomic number of element remains the same. Atomic number is the number of protons of a given atom of an element. Gamma decay unlike alpha and beta decay does not have an effect on the mass number and atomic number of an atom.

When a nucleus undergoes nuclear decay by gamma rays the atomic number of the element remains unchanged

When a nucleus undergoes nuclear decay by gamma rays, the atomic number of the element remains unchanged. This type of decay involves the emission of high-energy gamma ray photons, which reduces the nucleus's energy state but does not alter the number of protons or neutrons.

For instance, an isotope in an excited state, such as technetium-99m, undergoes gamma decay to release a gamma photon and becomes technetium-99, but both have the same atomic number of 43.

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