Answer:
Two terms might apply for this situation: "jump dispersion" and "human-assisted invasions".
Explanation:
Dispersion: It refers to the change in an organism's range or distribution area. Different ecological and biogeographical processes might be involved in organisms' dispersion. The term "jump dispersion" refers to a few individuals in a short time that can cross a barrier and occupy a new area. In this situation, the establishment is not always for sure. For this to happen, they must reproduce and start a new population of a certain size that can survive to the new conditions. Biologic Invasions: It refers to new species that establish in a new area far or out of their original distribution range. Once established, these species might be considered exotic or invasive, according to their reproductive rate, population growth, and interaction with native species. Biologic invasions are natural processes, that occur in small groups of individuals that can expand to other ecosystems, and the appearing or despairing of barriers promotes their expansion. But these biologic invasions have accelerated by human beings, referring to this as "human-assisted invasions". These are the cases in which men transport species from one place to the other for different uses or purposes.It is very common for these species to scape and start new populations in the new area, where they have less environmental pressure -fewer predators, more resources, better nitches- than in their origin area, which favors their establishment.
The exposed situation in the example is a case of "human-assisted invasions". It might also be considered as jump dispersion (because a few individuals of the species crossed a barrier and established in a new area) but assisted by humans.
Megan's mother suffered from the flu during her pregnancy with Megan. Statistically, this increases Megan's risk of developing schizophrenia later. This is an example of a(n) _____ factor, meaning a heritable change that is not due to DNA.
Answer:
Epigenetic
Explanation:
Epigenetic factors are factors that cause heritable changes in the expression of genes and not as a result of the DNA sequence of an individual. Factors such as lifestyle, age, complications during pregnancy etc, can have influence on the expression of genes as there is a change in a phenotype rather than the genotype being influenced.
Statistically, several studies have shown that complications during pregnancy increases the chance of a baby developing schizophrenia later on in life. Megan’s mother having suffered from flu during her pregnancy with Megan is an epigenetic factor that increases Megan’s chances of suffering from schizophrenia later.
Identify the structure that allows light to first enter the eye.
Answer:
Cornea
Explanation:
The first part of eye through which light enters into the eyes is cornea. Cornea comes in front of the pupil and iris and is made up of transparent layer. It is a curved structure just like a normal glass lenses and hence is able to focus light on retina. It also protects the eyes. Cornea along with anterior chamber is responsible for 67 percent of the optical power of eye and sends the light towards the pupil.
NEED HELP ASAP PLEASE WITH #16!!
Answer:
The correct option is D. 97%
Explanation:
Global warming can be described as the increase in the Earth's temperature over time. With the advancements in science and technology and with humans trying to make there lives on Earth better, one has to agree that humans have been destroying the Earth widely and increasing its temperature to cause global warming. Hence, no doubt that 97% of the climate scientists believe humans to be the cause of global warming.
The brain area that regulates activities that control the state of wakefulness or alertness of the cerebral cortex is the :a. reticular formationb. pyramidsc. limbic systemd. thalamus
Answer:
a. reticular formation
Explanation:
The reticular formation is the functional system that spans the brain stem. It is composed of loosely clustered neurons present in white matter. The function of reticular formation is to regulate sensory input to the cerebral cortex and cortical arousal. It is also involved in the control of motor behavior.
Some of the neurons of the part of the reticular formation are known as the reticular activating system (RAS). These neurons send a continuous stream of impulses to the cerebral cortex and thereby keep the cortex alert and conscious. The impulses from RAS of reticular formation enhance the excitability of the cerebral cortex.
The impulses coming from all the great ascending sensory tracts also synapse with RAS neurons and serve to keep them active and enhance their stimulating effect on the cerebral cortex.
True / False: The peripheral receptors located under the skin are very sensitive to to temperature changes and only provide feedback on to the hypothalamus (select one word answer only please).
Answer:
True
Explanation:
There are several specialized peripheral sensory neurons that are present beneath the skin known as nociceptors that are responsible for producing impulses whenever a dangerous stimulus such as extremely high or low temperature or pressure, chemical exposure, etc. is felt at the skin. The impulses produced are converted to long-range electrical signals and then transmitted to the brain cells for action
Hence, the given statement is true
The _______ of a phylogenetic tree represents the common ancestor, the _______ represent events where lineages diverged, and the _______ axis represents time. Assume that the tree is oriented as described in the textbook.
Answer:
a. root
b. nodes
c. horizontal
Explanation:
Systematics, as we have already indicated, is the part of science that tries to find out the degree of diversity and differentiation of organisms, as well as the kinships and affinities between them. This is based on the results of other disciplines such as Cytology, Anatomy, Palinology, Embryology, Phytochemistry, Genetics, Geobotany, etc. On the other hand, taxonomyi the part of the Systematics that deals with the theoretical study of classification (ordering of beings in class hierarchies), including in it its bases, principles, methods and laws; vegetable taxonomy, therefore, deals with the description, nomenclature and arrangement of living plants
In humans, a widow's peak is caused by a dominant allele (W), and a continuous hairline is caused by a recessive allele (w). Short fingers are caused by a dominant allele (S), and long fingers are caused by a recessive allele (s). Suppose a woman with a continuous hairline and short fingers and a man with a widow's peak and long fingers have three children. One child has a widow's peak and short fingers, one has a widow's peak and long fingers, and one has a continuous hairline and long fingers. What are the genotypes of the parents?
The woman has the genotype wwSS, and the man has the genotype WWss. The children have the genotypes WwSs, Wwss, and wwSs.
Explanation:The genotypes of the parents can be determined using the information given. A woman with a continuous hairline and short fingers must have the genotype wwSS, as continuous hairline is caused by the recessive allele w and short fingers are caused by the dominant allele S. A man with a widow's peak and long fingers must have the genotype WWss, as widow's peak is caused by the dominant allele W and long fingers are caused by the recessive allele s.
Using Punnett squares to cross these genotypes, we can determine the genotypes of the three children.
The child with a widow's peak and short fingers must have the genotype WwSs, as they inherited the dominant Widow's peak allele (W) from the father and the recessive Short fingers allele (s) from the mother.
The child with a widow's peak and long fingers must have the genotype Wwss, as they inherited the dominant Widow's peak allele (W) from the father and the recessive long fingers allele (s) from the mother.
The child with a continuous hairline and long fingers must have the genotype wwSs, as they inherited the recessive continuous hairline allele (w) from the mother and the dominant long fingers allele (S) from the father.
The genes for miniature wings (m) and garnet eyes (g) are approximately 8 map units apart on chromosome 1 in Drosophila. Phenotypically wild-type females (m + g / mg +) were mated to miniature-winged males with garnet eyes.
Part A
Which of the following phenotypic classes reflect offspring that were generated as a result of a crossover event?
Select all that apply.
garnet eyes
wild type
miniature wings
miniature wings, garnet eyes
Part B
If 800 offspring were produced from the cross, in what numbers would you expect the following phenotypes?
__wild type : __ miniature wings : __ garnet eyes : __ miniature wings, garnet eyes
Enter your answer as the number of flies of each phenotype separated by a colon (example: 100:300:100:300).
The following phenotypic classes reflect offspring that were generated as a result of a crossover event
wild typeminiature wingsgarnet eyesExplanation:
When the miniature wings and garnet eyes links up with the 8 map unit that are present between them. After that the presence of two recombinant classes must complement together and make 8% of total i.e. they contribute 4% each. together the parental classes make up to 92% by contributing 46% one.
This can be understood through a phenotypic ratio calculation, which can be expected from it.
wild type: 4% x 800 = 32
miniature wings: 46% x 800 = 368
garnet eyes: 46% x 800 = 368
miniature wings, garnet eyes: 4% x 800 = 368
In garden peas, the yellow seed trait is dominant over green seeds. Also, the round seed trait is dominant over the wrinkled-seed trait. These genes are on separate chromosomes. Suppose that two plants that are heterozygous for both traits are crossed and 720 offspring are produced. About how many progeny will be yellow with round seeds?Select one:
a. 405
b. 180
c. 360
d. 60
e. 540
Answer:
405
Explanation:
Gregor Mendel worked with pea plant and observed the inheritance of seed colour and shape in the plant. This is a dihybrid cross involving two genes; one coding for seed colour and the other for seed shape. The allele for yellow seed (Y) is dominant over green (y) in the first gene, while the allele for round seed (R) is dominant over wrinkled seed (r) in the second gene.
When Mendel crossed truebreeds i.e. homozygous parents, he got a F1 generation which is heterozygous for both traits (YyRr). He crossed two heterozygous plants, and according to the law of independent assortment, four possible chromosome combinations of gametes were produced viz: YR, Yr, yR, yr.
Mendel discovered that from a cross involving two hybrid genes, 16 variations were possible. In the genetic make-up, the kinds of F2 offsprings possible from this dihybrid cross are; Yellow round, Yellow wrinkled, Green round and Green wrinkled in a theoretical ratio 9:3:3:1 respectively.
According to the question, 720 offsprings were produced. Therefore, to get the number of progeny with yellow round seeds, the ratio will be used.
The ratio of yellow round seeds in Mendel's dihybrid cross is 9/16, hence, among 720 offsprings, we will have about- 9/16 × 720 = 405 pea plants with yellow and round seeds.
Final answer:
Approximately 405 out of 720 offspring from a dihybrid cross of heterozygous garden pea plants (for yellow and round seed traits) are expected to exhibit both dominant yellow and round seed traits, based on the 9:3:3:1 Mendelian phenotypic ratio.
Explanation:
In the scenario where garden peas that are heterozygous for both yellow seed (dominant) and round seed (dominant) traits are crossed, we are looking at a dihybrid cross. Based on the principles of Mendelian genetics, we can predict the phenotypic ratios of the offspring's traits. For such a cross, the phenotypic ratio is typically 9:3:3:1 for the combinations of the two traits when both parents are heterozygous.
When we have a dihybrid cross (RrYy × RrYy), the proportion of offspring that are expected to express both dominant traits (yellow and round seeds) is 9/16. Given that 720 offspring are produced, we calculate the number expected to have yellow and round seeds by multiplying the total number of offspring by the expected proportion:
(9/16) × 720 = 405
Thus, the correct answer is option (a), which is approximately 405 progeny with yellow and round seeds.
In bacteria, the antibiotic erythromycin prevents ribosomes from functioning. The MOST likely reason that bacteria die from treatment with erythromycin is because the antibiotic____________
Answer:
inhibits translation
Explanation:
Bacteriostatic macrolide antibiotic produced by Streptomyces erythreus. Erythromycin A is considered its main active component. In sensitive organisms, it inhibits protein synthesis by binding to 50S ribosomal subunits. This binding process that inhibits peptidyl transferase activity and interferes with the translocation of amino acids during translation and protein assembly.
The bacteriostatic effect consists in producing the inhibition of bacterial growth; Meanwhile, immunogenesis is expected to provide the necessary defensive elements for disease control. Therefore, these antimicrobials should not be indicated to the immunocompromised patient. They act in the stationary phase of bacterial growth.
Some antibiotics have a bactericidal or bacteriostatic effect depending on whether the drug acts in vivo or in vitro, and depending on the dose administered. For example, Amphotericin B, has fungistatic effect in vivo and fungicide in vitro; Streptomycin and erythromycin have bactericidal effect when administered at high doses and bacteriostatic effect if administered at low doses.
In 1883, Theodor Engelmann devised an experiment to find out which wavelengths of light were most used by photosynthetic organisms. He placed a strip of algae on a microscope slide, and then projected a spectrum of light on the slide. A suspension of oxygen-loving" bacteria was also placed on the slide. Based on an understanding of the light reactions of photosynthesis, predict the most likely outcome of the experiment."
Answer:
Oxygen loving bacteria are accumulated only in two areas in the slide, at its ends, areas rich in oxygen
Explanation:
A prism decomposed the light in different wavelengths between 400 and 700 nm. Plants only absorbed some wavelenghts, one that peaks at about 440nm and the other around the 660 nm, as their particular Chlorophyls used to work.
Electrons from a reaction center from a photosystem (PSII) containing a particular chlorophyl , are launched to higher levels of energy when this is excited by light wavelength (680 nm) and travel by a molecular chain to an acceptor of electrons, forming ATP. To refill the electrons in the reaction center, H2O is hydrolyzed, and their e- reach the reaction center. In this step O2 is also produced.
A second photosystem (PSI) is also excited from another similar reaction center, whose electrons are used to produce reducing power in the form of NADPH. This photosystem I also acts as acceptor of the electrons coming from PSII
"The isolation of cell-cycle mutations in yeast was greatly facilitated by the use of _______________ mutations, which allow investigators to study the effects of mutations that would be lethal if expressed constantly"
Answer:
The correct answer is - conditional mutation.
Explanation:
Conditional mutation is a type of mutation that has less severe or wild-type phenotype or traits that physically appears under particular permissive environmental conditions and a mutant phenotype under particular restrictive environmental conditions.
Thus, the correct answer is a conditional mutation.
What would most likely be the outcome to planar cell polarity if calcium were removed from the tissue?
Answer:
If calcium were removed from the tissue then the polarity will be established within the cell but polarity will be lost in the tissue.
Explanation:
Cell polarity is the cellular components like cytoplasm, plasma membranes and other various cell organelles in the asymmetric order. The coordinated arrangement of this cell polarity in tissue plane is called as planar cell polarity (PCP). Calcium is the major component in the tissues that helps in formation of bones and other parts of body, if it is removed then the polarity will not be seen in the tissue, but in the cell the polarity will be established.Which of the following descriptions accurately describes Boyle’s law?View Available Hint(s)Which of the following descriptions accurately describes Boyle’s law?The partial pressure of a gas in the air you breathe in is equal to the total atmospheric pressure times the fractional concentration of the gas.How well a gas dissolves in a liquid such as blood depends on both its partial pressure and its solubility.The pressure of gas in your lungs is inversely proportional to the volume in your lungs.
Answer:
The answer is The pressure of gas in your lungs is inversely proportional to the volume in your lungs.
Explanation:
Because Boyle's law describes how air moves in and out of your lungs during inspiration and expiration. By the changing the volume inside the thoracic cavity, the pressure changes in the lungs. Increasing volume of thoracic cavity leads to a decreased pressure, causing air to flow into the lungs, down its pressure gradient and thus causing inspiration.
Boyle’s law states that the pressure of a gas is inversely proportional to its volume, at a constant temperature.
Explanation:Boyle's law states that the pressure of a gas is inversely proportional to its volume, at a constant temperature.
For example, if the volume of a gas is doubled while the temperature remains constant, the pressure of the gas would be halved.
This relationship can be expressed mathematically as: P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
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Boyle's law can be defined as the principle that states the pressure of a gas is inversely proportional to its volume, when the temperature is constant. This principle is applicable to the behavior of gases and is accurately described by the third statement provided in the question.
Explanation:Boyle's law is accurately represented by the third statement provided: 'The pressure of gas in your lungs is inversely proportional to the volume in your lungs.' In more general terms, Boyle's law states that the pressure and volume of a gas have an inverse relationship, when temperature is held constant. If the volume of the gas increases, the pressure decreases and vice versa. This law is fundamental in many chemical and physical processes we observe, particularly in understanding the behavior of gases.
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If corn #1 comes from a parental generation composed of homozygous purple kernels and homozygous yellow kernels then, the monohybrid cross will produce a generation that is heterozygous color purple dominant. If generation 1 is crossed with generation 1again, then the result will be dominant for the purple trait ¾ to ¼ in F2 generation. If corn # 2 comes from a parental generation composed of purely homozygous purple and smooth kernels and purely homozygous yellow and wrinkled kernels then a cross of the parental generation will cause alleles to segregate during gamete formation. The F1 generation will be heterozygous for both traits of color and texture. F1 crossed with itself will result in an F2 generation with mostly purple smooth kernels, some purple wrinkled, some yellow smooth and some yellow wrinkled.
Answer:
For corn#1 the punnet square can be shown as follows
p p
P Pp Pp
P Pp Pp
P p
P PP Pp
p Pp pp
The results from Corn # 1 and corn No #2 show that alleles assort independently into gametes. Due to this genetic variations occur.
Homozygous means that the alleles for a gene are similar. Heterozygous means that the alleles for a gene are different.
A dominant trait is the one in which the dominant allele suppresses the effect of the recessive allele. The recessive allele gets masked by the dominant allele.
A client with urine retention related to a complete prostatic obstruction requires a urinary catheter to drain the bladder. Which type of catheter is most appropriate for a client that has an obstructed urethra?
Answer:
A) Suprapubic catheter
Explanation:
The complete question is :
A client with urine retention related to a complete prostatic obstruction requires a urinary catheter to drain the bladder. Which type of catheter is most appropriate for a client that has an obstructed urethra?
A) Suprapubic catheter
B) Indwelling urethral catheter
C) Intermittent urethral catheter
D) Straight catheter
Explanation:
A Suprapubic catheter is used for the drainage of urine from the bladder and it consists of a hollow flexible tube. A suprapubic catheter is used for long-term continuous drainage and is inserted through a small incision above the pubic area. Suprapubic bladder drainage diverts urine from the urethra when injury, stricture, prostatic obstruction, or abdominal surgery has compromised the flow of urine through the urethra.How did the 1977 drought on daphne major cause evolutionary change in the medium ground finch population?
Answer:
the atmospheric changes generated very rapid changes in body size and peak in response to changes in the food supply are led to natural selection, since this type of bird easily adapts to weather conditions and your body assumes these changes for survival
Explanation:
A researcher is studying a population of mutant fibroblasts that fail to flatten and attach to extracellular matrix proteins on a flat surface. This is likely the result of mutations in genes encoding:__________
Answer: Components of cell junctions
Explanation:
Fibroblasts are cells located in the dermis, responsible for the formation and remodeling of tissue. They synthesize fibers and maintains the extracellular matrix of the tissue of animals. So, the extracellular matrix is a structurally complex entity that surrounds and supports the cells found in tissues.
A cell junction a structure that exists within the tissues of animals and they consist of protein complexes that provide contact between cells or between a cell and the extracellular matrix. So if the cells do not appear flattened and do not attach to the extracellular matrix, then there is a problem with the components of cell junctions, which are mostly proteins as it was said before. And since proteins are coded by genetic information stored in DNA, then if there is a mutation in any of those genes, the fibroblast will fail to attach because the protein of the cell junction will be abnormal.
Two species of cuckoo doves live in a group of islands off the coast of New Guinea. Of 33 islands, 14 have one species, 6 have the other, 13 have neither, and none has both. What might best explain this? The two species of birds could _____. (see textbook sections 37.1-13 for reference)
A. be on different trophic levels
B. have a mutualistic relationship
C. have similar niches
D. have different niches
Answer:
hgyuhkcftucty
Explanation:
The best explanation for why two species of cuckoo doves are found on separate islands is that they have similar niches and cannot coexist due to competition for resources. This situation aligns with the competitive exclusion principle.
Explanation:Given the information that two species of cuckoo doves live in separate islands and none of the islands have both species, the best explanation might be that these two species of birds have similar niches. A niche includes all the factors necessary for a species' way of life, such as food sources, habitat, and behavior. Since none of the islands contain both species alongside each other, it is likely that these species cannot coexist on the same island because of niche overlap leading to competition. If both species have similar requirements for resources such as food and nesting areas, they would likely compete until one species outcompetes the other, leading to exclusion from the island.
Therefore, the most likely scenario explaining why each species is found exclusively on separate islands is because they have similar niches and cannot coexist due to competition for resources. Thus, the correct answer to the question is (C). This is consistent with the competitive exclusion principle, which states that two species with identical niches cannot coexist in the same territory.
What was rudolf virchow’s contribution to the cell theory?
Answer:
The credit of formulating cell theory is usually credited to two scientists that are Matthias Schleiden and Theodor Schwann but Rudolf Virchow was a well-known scientist who is known for his contribution to the cell theory.
In 1855 in his publication the statements were based on the observation about the cells that arise from pre-existing cells which he called Omnis cellula e cellula. Therefore after this publication, all accepted that new cell comes from the old cell which was early thought that new cells comes from fluid known as blastema.
So Rudolf Virchow contributed in the cell theory by popularizing the last theory of cell theory that says that new cells come from pre-existing cells.
He concluded that all cells come from preexisting cells.
Which statements are true of anticlines? Choose one or more: A. The limbs dip toward the hinge. B. They have an arch-like shape. C. They are the result of ductile deformation. D. They form from compressional stress.
Answer:
B. C. and D.
Explanation:
Anticlines are a type of fold in our earth that are shaped like an arch. From the answers provided it can be said that the Anticlines the result of ductile deformationand they form from compressional stress. The one answer that is provided that is false would be that the limbs dip toward the hinge. The truth is that the limbs are the sides of the fold that dip away from the hinge.
Homologous structures (Group of answer choices):
A. are also called analogous structures.
B. have identical functions.
C. are shared by organisms of the same genus.
D. have fully divergent functions.
E. are often shared by organisms in the same line of descent.
The fossil record resembles the living species in the same geographic area. How does this pattern support the theory of evolution by natural selection?
Answer:
The correct answer will be- species can change over time (assuming options are present)
Explanation:
The theory of evolution by natural selection by Charles Darwin suggests that species adapt to the changing environment and as a result changes over time.
The remnants of the organism that lived on the Earth gets buried under the earth and gets preserved. These preserved remnants of the organism are called the fossils which are collected and studied to understand the history of life on earth.
If the fossils collected on earth in a geographic area resembles the living species of the same geographic area provides a clue to the theory of natural selection suggesting that species can change over time as a result of natural selection.
Density-dependent inhibition is a phenomenon in which crowded cells stop dividing at some optimal density and location. This phenomenon involves binding of a cell-surface protein to its counterpart on an adjoining cell's surface. A growth inhibiting signal is sent to both cells, preventing them from dividing. Certain external physical factors can affect this inhibition mechanism.
Select the statement that makes a correct prediction about natural phenomena that could occur during the cell cycle to prevent cell growth.
A) As cells become more numerous, they begin to squeeze against each other, restricting their size and ability to allow cell growth.
B) As cells become more numerous, the protein kinases they produce begin to compete with each other until only one cell has the proteins necessary for growth.
C) As cells become more numerous, the amount of required growth factors and nutrients per cell becomes insufficient to allow for cell growth.
D) As cells become more numerous, more and more of them enter the synthesis part of the cell cycle and duplicate DNA to inhibit cell growth.
Answer: C) As cells become more numerous, the amount of required growth factors and nutrients per cell becomes insufficient to allow for cell growth.
Explanation:
Growth factors are proteins that stimulate cell division.Two of the most important internal factors are kinases and cyclins. In most mammal cells stop dividing once they touch other cells this means that when a cell population reaches a certain density, the amount of required growth factors and nutrients available to each cell becomes insufficient to allow continued cell growth.
The correct prediction about a phenomenon that could occur to prevent cell growth during the cell cycle due to density-dependent inhibition is that as cells proliferate, they may not have enough growth factors and nutrients to support further growth.
C is correct
Explanation:Density-dependent inhibition is a key regulatory mechanism during the cell cycle that ensures cells stop dividing when they become overly crowded. This process involves the interaction of cell-surface proteins between adjacent cells which signal each other to halt division. One accurate prediction about natural phenomena that could prevent cell growth as a result of density-dependent inhibition is: C) As cells become more numerous, the amount of required growth factors and nutrients per cell becomes insufficient to allow for cell growth.
When cells reach a certain density, they may compete for limited resources such as nutrients and growth factors. The scarcity of these essential elements acts as a natural inhibitor of cell proliferation. This is distinct from the process wherein cells enter the synthesis phase of the cell cycle to duplicate DNA, or from the competition among protein kinases, which are not direct consequences of cell crowding. It is important to note that signaling pathways that involve proto-oncogenes and tumor suppressor genes are complex and include not only growth-promoting signals but also signals for inhibition of cell division, demonstrating that multiple factors can impact the cell cycle.
Reabsorption of filtered glucose from the filtrate into the cells of the proximal tubule is by: Reabsorption of filtered glucose from the filtrate into the cells of the proximal tubule is by: a) secondary active transport. b) diffusion. c) antiport. d) facilitated diffusion.
Answer: A(secondary active transport)
Explanation:
Secondary active transport, is transport of molecules across the cell membrane which utilizes energy created by co-transporter pumping of ions across the membrane in an electrochemical gradient.
The reabsorption of glucose from the proximal tubule occurs via secondary active transport.
The reabsorbption of glucose does not depend the concentration gradient but on the reabsorption of sodium a co-transporter.
ATP is used in the movements of Na+/K+. Energy is also produced from sodium electrochemical gradient concentration and it is enough energy to transport glucose across the membrane into the epithelial cells.
DNA analysis of organisms can explain homologous structures in related species, but cannot explain analogous structures in seemingly unrelated species. Natural selection better explains analogous structures because_____________.
Answer:
To support the evolution, the anatomical features acts as the best evidence supporting the theory of evolution and its mechanism.
Studying the anatomical features led to the concept of homology which shows that organisms share homology in their structures independent of their habitat due to divergent evolution and analogy which evolved in different organisms sharing similar habitat resulting ion convergent evolution.
The analogous structures are considered better evidence to support the process of natural selection as the analogous organs represent the changes in the organs in response to the environment species is surviving and shows how species have changed compared to their ancestors.
Thus, analogous organs better explain natural selection.
Which of the following properties of transposable elements allows them to contribute to the C-value paradox?A. Their copy number can increase from one generation to the next.B. Their replication is controlled by genes found on the transposable element itself.C. Copies of transposable elements can appear on multiple chromosomes.D. All of these choices are correct.
Answer:
All of these choices are correct.
Explanation:
Transposons are the DNA sequences that can move from one location to another in the genome. The transposon genes are also known as jumping genes.
The C value paradox of the transposable elements depends on the different factors. The transposons can increase their number by copy and paste mechanism. The genes can be controlled by the enzyme transposase and their copies may exist at the different site of the chromosome.
Thus, the correct answer is option (D).
A client with a history of chronic alcohol use but without visible jaundice comes to the clinic reporting nausea and weakness. She admits to taking acetaminophen for persistent headaches but denies exceeding the recommended daily dose; she has not taken any other medications. She is suspected of having acetaminophen toxicity. Which diagnostic test finding would suggest a different cause of her symptoms?
Answer: malnutrition
Explanation:
It has been evident in chronic alcohol users to be be malnourished due to loss of appetite and irregularities in their feeding.
This kind of patients might suffer acetaminophen toxicity from ingestion of acetaminophen for her headaches because malnutrition causes depletion of glutathione stores in the system.
"Outline the process of_________.a. in vitro fertilisation including down-regulation.b. superovulation".c. harvesting.d. fertilization.e. implantation.
Answer:
The answer is letter A.
Explanation:
In virto fertilisation is a reproductive process, in which, embryos are produced after the extraction of the egg and the sperm from the childless couple.
First the woman is submited to a threatment to stop her menstrual cycle, then the doctor puts her under hormones threatment to estimulate her ovaries to develop follicles. After this step, a HCG is injected at her, so that the doctor can collect the eggs.
The man provide his semen after ejaculating in a dispenser. The physicians mix the egg and the semen and check if the fertilisation has been successful.
If the result is positive, the embryos are implanted inside of the woman's uterus.
After a few weeks the woman should take a pregancy test to confirm the pregnancy.
A true-breeding black rabbit is crossed with a true-breeding white rabbit to produce an F1 generation of 16 individuals. If the black color trait is dominant, which of the outcomes represents the expected phenotype of an F1 generation cross?
a. 9 black rabbits, 3 white rabbits, 3 gray rabbits, and 1 spotted rabbit.
b. 0 black rabbits, 16 white rabbits, 0 gray rabbits.
c. 16 black rabbits, 0 white rabbits, 0 gray rabbits.
d. 0 black rabbits, 0 white rabbits, 16 gray rabbits.
e. 5 black rabbits, 4 white rabbits, 7 gray rabbits.
Answer:
c. 16 black rabbits, 0 white rabbits, 0 gray rabbits.
Explanation:
Let dominant black allele be = B
Let recessive white allele be = b
True breeding rabbit would mean that they are homozygous in their genotype hence true breeding black rabbit will be BB and true breeding white rabbit will be bb.
BB X bb :
B B
b Bb Bb
b Bb Bb
All the offspring are heterozygous with one dominant B allele so the phenotype black colour will be produced and all 16 individuals of F1 generation will be black in colour.
Answer:
c. 16 black rabbits, 0 white rabbits, 0 gray rabbits.
Explanation:
I took a test on this once