On the provided graph, select the locations of the x-intercepts of the following polynomial function. x^3-7x^2-26x+72

Area of the given polygon is required.

The area of the polygon is A. [tex]147\ \text{square units}[/tex]

The polygon is a rectangle with one corner of the rectangle removed.

The removed area is a square.

The area of the complete rectangle is

[tex]13\times 12=156\ \text{square units}[/tex]

Area of the removed square

[tex]3\times 3=9\ \text{square units}[/tex]

The area of the polygon is

[tex]156-9=147\ \text{square units}[/tex]

Learn more:

https://brainly.com/question/11466123?referrer=searchResults

Answer:

M<A is less than or equal to 90°

Step-by-step explanation:

If it is less than or equal to, then the first statement has to be false, that it is greater. This means the statement is negated because they can't work together.

Final answer:

To find the new interest rate compounded quarterly, divide the annual interest rate by the number of compounding periods per year.

Explanation:

To rewrite the equation to find the new interest rate, we need to consider the compounding frequency. Currently, the interest is compounded annually. To find the new interest rate compounded quarterly, we need to divide the annual interest rate by the number of compounding periods per year.

So, for an interest rate of 10%, the quarterly interest rate would be 10% divided by 4, which is 2.5%.

Therefore, the approximate new interest rate, compounded quarterly, would be 2.5%.

The new interest rate when compounded quarterly that would keep the future value (A) and the present value (P) the same is approximately 9.38%.

To find the new interest rate when the interest is compounded quarterly instead of annually, we need to use the compound interest formula and equate the two expressions for A.

Given:

[tex]A = 250(1.1)^_t[/tex] (interest compounded annually)

[tex]A = P(1 + r/m)^_(mt)[/tex] (compound interest formula)

Where:

A = Future value

P = Present value (250)

r = Annual interest rate

m = Number of times interest is compounded per year

t = Time in years

Step 1: Equate the two expressions for A.

[tex]250(1.1)^t = 250(1 + r/m)^_{(mt)}[/tex]

Step 2: Substitute m = 4 (interest compounded quarterly).

[tex](1.1)^t = (1 + r/4)^_{(4t)}[/tex]

Step 3: Solve for r.

[tex](1 + r/4)^4 = 1.1[/tex]

[tex]1 + r/4 = (1.1)^_{(1/4)}[/tex]

[tex]r/4 = (1.1)^_(1/4)} -1[/tex]

[tex]r= 4((1.1)^_(1/4)} -1)[/tex]

r ≈ 0.0938 or 9.38%

Answer:

5 sqrt2.

Step-by-step explanation:

sqrt8 = sqrt4 * sqrt2 = 2 sqrt2

sqrt18 = sqrt9 * sqrt2 = 3 sqrt2

So simplifying:

5sqrt 8 - sqrt18 - 2 sqrt2

= 5*2sqrt2 - 3 sqrt 2 - 2 sqrt2

= 10 sqrt2 - 5 sqrt2

= 5 sqrt2 (answer).

For this case we must simplify the following expression:

[tex]5 \sqrt {8} - \sqrt {18} -2 \sqrt {2}[/tex]

Rewriting we have:

[tex]8 = 2 * 2 * 2 = 2 ^ 2 * 2\\18 = 9 * 2 = 3 ^ 2 * 2\\5 \sqrt {2 ^ 2 * 2} - \sqrt {3 ^ 2 * 2} -2 \sqrt {2} =[/tex]

We have that by definition of properties of roots and powers it is fulfilled:

[tex]\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}[/tex]

So:

[tex]5 * 2 \sqrt {2} -3 \sqrt {2} -2 \sqrt {2} =\\10 \sqrt {2} -3 \sqrt {2} -2 \sqrt {2} =\\10 \sqrt {2} -5 \sqrt {2} =\\5 \sqrt {2}[/tex]

Answer:

[tex]5 \sqrt {2}[/tex]

Answer:

20) 30°; 21) 21,1; 22) 6,2

Step-by-step explanation:

For the first image, you have to do csc⁻¹ 2 [OR sin⁻¹ ½] because you are solving for an angle measure. When evaluated, you get 30°.

For the second image, you have to do 13sec 52° = x [OR 13\cos 52° = x]. When evaluated, you get an approximate measure of 21,1.

For the third image, you have to do 6csc 75° = x [OR 6\sin 75° = x]. When evaluated, you get an approximate measure of 6,2.

Extended information on Trigonometric Ratios

O\H = sin θ

A\H = cos θ

O\A = tan θ

H\A = sec θ

H\O = csc θ

A\O = cot θ

I am joyous to assist you anytime.

[tex]\tan a-1=0\\\tan a =1\\\\a=\dfrac{\pi}{4}+k\pi, k\in\mathbb{Z}[/tex]

Answer:

answer is D

Step-by-step explanation:

3x-4=4x+10

3x=4x+14

-1x=14

x= -14

Answer:

-14

Step-by-step explanation:

It's multiple choice so we could plug in values of x and see which makes f(x)=g(x) true.

What I mean is would could plug in values of x to see which gives us

3x-4=4x+10 is true.

Or we could just solve it.

3x-4=4x+10

Subtract 3x on both sides:

-4=1x+10

-4=x+10

Subtract 10 on both sides:

-14=x

So x=-14 would make f(x)=g(x) hold.

Let's check it and see!

f(-14)=3(-14)-4=-42-4=-46.

g(-14)=4(-14)+10=-56+10=-46.

They have the same value of -46 so x=-14 is certainly going to make f(x)=g(x) be true.

let's firstly convert the mixed fractions to improper fractions and then add.

[tex]\bf \stackrel{mixed}{2\frac{7}{10}}\implies \cfrac{2\cdot 10+7}{10}\implies \stackrel{improper}{\cfrac{27}{10}}~\hfill \stackrel{mixed}{8\frac{1}{2}}\implies \cfrac{8\cdot 2+1}{2}\stackrel{improper}{\cfrac{17}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{27}{10}+\cfrac{17}{2}\implies \stackrel{\textit{using an LCD of 10}}{\cfrac{(1)27+(5)17}{10}}\implies \cfrac{27+85}{10}\implies \cfrac{112}{10}\implies \cfrac{56}{5}\implies 11\frac{1}{5}[/tex]

The perfect square [tex](x-a)^2[/tex] can be expanded as follows:

[tex](x-a)^2=x^2-2ax+a^2[/tex]

So, we have to think of the term [tex]-8x[/tex] as [tex]-2ax[/tex], which implies [tex]a=4[/tex].

Thus, we have to add [tex]a^2[/tex], i.e. 16, to complete the perfect square:

[tex](x-4)^2 = x^2-8x+16[/tex]

Answer:

Overlapping events

Step-by-step explanation:

Note that in the question, it specifically specifies that there is only a number cube (or 1 number cube). Note that the two events asked for us to solve is does not conflict at all.

Event A is asking for the probability of you rolling a prime number (1 , 3 , 5), while Event B is asking for the probability of you rolling a number larger than 4 (5 , 6). These two can occur at the same time, and both events can be confirmed by rolling the number 5.

~

Answer:

overlapping events

Step-by-step explanation:

Event A: Rolling a prime

The following are the prime numbers from 1 to 6 (inclusive):

2,3,5

Event B: Rolling a number larger than 4

The following are larger than 4 from 1 to 6 (inclusive):

5,6

Do you see any overlap?

The overlap is 5.

These are overlapping events.

Answer:

option D

Step-by-step explanation:

As per the contract:

"All rentals are due back by midnight of the due date as printed on the transaction receipt. "

In given case clerk did not give any transaction receipt.

so option D is correct

The clerk completed the transaction without giving Susan a receipt or otherwise informing her of the due date !

Answer:

d

Step-by-step explanation:

i just did the test

Answer:

The answer is Region C

Step-by-step explanation:

Region C has total population of Zebra as 16,400 divided by the area occupied in square km which is 625. This gives population density of approximately 26 zebras/km square

[tex] \frac{16400}{625} = 26.24[/tex]

If you follow the same procedure for other regions, you will discover that region C has the highest number of Zebras/square km which is 26.

I hope this helped?

The region that would have the greatest competition for resources is Region C.

Population density is the amount of organisms that live in a square feet of an area.

Population density = population / area

To learn more about population density, please check:

https://brainly.com/question/3704320

Answer:

63 donuts

Step-by-step explanation:

210 donuts -> 10 hours

  x  donuts -> 3 hours

This is already setup for a proportion:

[tex]\frac{210}{x}=\frac{10}{3}[/tex]

Cross multiply:

[tex]3(210)=10x[/tex]

Simplify:

[tex]630=10x[/tex]

Divide both sides by 10:

[tex]\frac{630}{10}=x[/tex]

Simplify:

[tex]63=x[/tex]

63 donuts can be made in hours.

The division is one of the four fundamental arithmetic operations. The number of donuts that can be made in 3 hours time period is 63 donuts.

The division is one of the four fundamental arithmetic operations, which tells us how the numbers are combined to form a new one.

Given that 210 donuts can be made in 10 hours. Therefore, the number of donuts that can be made per hour are:

Number of donuts per hour = 210 donuts / 10 hour

                                              = 21 donuts / hour

Now, the number of donuts that can be made in 3 hours are,

Number of donuts = 21 donuts / hour × 3 donuts

                               = 63 donuts

Hence, the number of donuts that can be made in 3 hours time period is 63 donuts.

Learn more about Division:

https://brainly.com/question/369266

#SPJ2

Answer:

4

Step-by-step explanation:

−36−9+14−31−(−66)

=−45+14−31−(−66)

=−31−31−(−66)

=−62−(−66)

=4

Answer:

False

Step-by-step explanation:

What the attached image says that if two solids with equal heights and base areas are cut by any parallel plane to their bases then sections of equal area (volume) would be produced in them

Answer:

8

Step-by-step explanation:

We are given the following expression and we are to find the simplest form of this expression:

[tex] - 3 2 ^ { \frac { 3 } { 5 } } [/tex]

First of all, we will factor the coefficient:

[tex] 3 2 = 2 ^ 5 [/tex]

Rewriting it as:

[tex] - ( 2 ^ 5 ) ^ { \frac { 3 } { 5 } }[/tex]

Applying the exponent rule [tex](a^b)^c = a^{bc}[/tex] to get:

[tex]-2^{5.\frac{3}{5}}=-2^3[/tex]

[tex]-2^3=-8[/tex]

Answer:

[tex]WY=42.8\ units[/tex]

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

In the right triangle WYS

Applying the Pythagoras Theorem

[tex]WY^{2}=WS^{2}+YS^{2}[/tex]

we have that

[tex]WS=XZ=42\ units[/tex]

[tex]YS=YZ-WX=19-11=8\ units[/tex]

substitute

[tex]WY^{2}=42^{2}+8^{2}[/tex]

[tex]WY^{2}=1,828[/tex]

[tex]WY=42.8\ units[/tex]

Answer:

Step-by-step explanation:

Use FOIL: (a + b)(c + d) = ac + ad + bc + bd

and i² = -1

(2 + 2i)(5 + 3i) = (2)(5) + (2)(3i) + (2i)(5) + (2i)(3i)

= 10 + 6i + 10i + 6i² = 10 + 6i + 10i + 6(-1)

= 10 + 6i + 10i - 6             combine like terms

= (10 - 6) + (6i + 10i)

= 4 + 16i

Answer:

[tex]\displaystyle 4+16i[/tex]

Step-by-step explanation:

Distributive property: ⇒ A(B+C)=AB+AC

A=2, B=2, C=5, and D=3

[tex]\displaystyle (2*5-2*3)+(2*3+2*5)i[/tex]

Simplify and refine to find the answer.

[tex]\displaystyle2*3+2*5=2*3=6, 2*5=10, 10+6=16[/tex]

[tex]\displaystyle2*5-2*3=2*5=10-2*3=2*3=6, 10-6=4[/tex]

[tex]\displaystyle 4+16i[/tex] , which is our correct answer.

Answer:

See below in bold.

Step-by-step explanation:

Convert the equation into slope-intercept form:

7x - 6y = -5

6y = 7x + 5

y = (7/6) x + 5/6

- so the slope is 7/6.

The slope of a line parallel to this has the same slope 7/6.

The slope of a line perpendicular to this has a slope of - 1 / 7/6

= -6/7.

Answer:

Step-by-step explanation:

calculate the slope of given line :

7X-6Y=-5

6y = 7x+5

y=7/6 x +5/6

the slope is : 7/6

the slope of a line parallel to this lineis 7/6 ( same slope )

the slope of a line perpendicular to this line is : a    when : a× 7/6= - 1

so : a = -6/7

Answer:

Is an acute triangle

Step-by-step explanation:

we have

[tex]G(7, 3),H(9, 0),I(5, -1)[/tex]

so

The polygon is a triangle

we know that

the formula to calculate the distance between two points is equal to

[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]

Remember that

If applying the Pythagoras Theorem

[tex]c^{2}=a^{2}+b^{2}[/tex] -----> is a right triangle

[tex]c^{2}>a^{2}+b^{2}[/tex] -----> is an obtuse triangle

[tex]c^{2}<a^{2}+b^{2}[/tex] -----> is an acute triangle

where

c is the greater side

step 1

Find the distance GH

[tex]G(7, 3),H(9, 0),I(5, -1)[/tex]

substitute

[tex]d=\sqrt{(0-3)^{2}+(9-7)^{2}}[/tex]

[tex]d=\sqrt{(-3)^{2}+(2)^{2}}[/tex]

[tex]GH=\sqrt{13}\ units[/tex]

step 2

Find the distance HI

[tex]G(7, 3),H(9, 0),I(5, -1)[/tex]

substitute

[tex]d=\sqrt{(-1-0)^{2}+(5-9)^{2}}[/tex]

[tex]d=\sqrt{(-1)^{2}+(-4)^{2}}[/tex]

[tex]HI=\sqrt{17}\ units[/tex]

step 3

Find the distance GI

[tex]G(7, 3),H(9, 0),I(5, -1)[/tex]

substitute

[tex]d=\sqrt{(-1-3)^{2}+(5-7)^{2}}[/tex]

[tex]d=\sqrt{(-4)^{2}+(-2)^{2}}[/tex]

[tex]GI=\sqrt{20}\ units[/tex]

step 4

Let

[tex]c=GI=\sqrt{20}\ units[/tex]

[tex]a=HI=\sqrt{17}\ units[/tex]

[tex]b=GH=\sqrt{13}\ units[/tex]

Find [tex]c^{2}[/tex] ------> [tex]c^{2}=(\sqrt{20})^{2}=20[/tex]

Find [tex]a^{2}+b^{2}[/tex] ----> [tex](\sqrt{17})^{2}+(\sqrt{13})^{2}=30[/tex]

Compare

[tex]20 < 30[/tex]

therefore

Is an acute triangle

Answer:

x ≈ 20.42, y ≈ 11.71

Step-by-step explanation:

Using the cosine ratio on the right triangle on the right, that is

cos20° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{11}{y}[/tex]

Multiply both sides by y

y × cos20° = 11 ( divide both sides by cos20° )

y = [tex]\frac{11}{cos20}[/tex] ≈ 11.71

Using the sine ratio on the right triangle on the left, that is

sin35° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{y}{x}[/tex] = [tex]\frac{11.71}{x}[/tex]

Multiply both sides by x

x × sin35° = 11.71 ( divide both sides by sin35° )

x = [tex]\frac{11.71}{sin35}[/tex] ≈ 20.42

Answer:

x = 20.41 units, y = 11.71 units to the nearest hundredth.

Step-by-step explanation:

Consider the small triangle:

cos 20 = 11/y

y = 11 / cos 20

= 11.706 units.

Now the larger triangle:

sin 35 = 11.706 / x

x = 11.706 / sin 35

x = 20.409 units.

The square root of 9 is 3, but the negative square root of 9, which is -3, is less than 2 squared (4). Therefore, the answer to the question is -3.

The square root of 9 is 3. We denote the square root symbolically as √9 = 3. However, if we're looking for which square root of 9 is less than 2 squared (which is 4), we consider that every positive number has two square roots: one positive and one negative. The negative square root of 9 is -3, which is indeed less than 4. Therefore, the square root of 9 that is less than 2 squared is -3.

Learn more about Square Root here:

https://brainly.com/question/1540542

#SPJ2

Check the picture below.

now we simply plug all those three sides in Heron's Area Formula.

[tex]\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=5.8\\ b=9.75\\ c=7.39\\ s=11.47 \end{cases} \\\\\\ A=\sqrt{11.47(11.47-5.81)(11.47-9.75)(11.47-7.39)} \\\\\\ A=\sqrt{11.47(5.66)(1.72)(4.08)}\implies A\approx \sqrt{455.5839955} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill A\approx 21.3444~\hfill[/tex]

Answer:

area of triangle ABC is 21.39 square units.

C is the correct option.

Step-by-step explanation:

We know the formula for the area of the triangle ABC in terms of sine. The formulas are

[tex]A=\frac{1}{2}ab\sin C\\\\A=\frac{1}{2}ac\sin B\\\\A=\frac{1}{2}bc\sin A[/tex]

In the given triangle, we hae

b = 9.75

c = 7.39

A = 36.43°

Therefore, area of triangle ABC is given by

[tex]A=\frac{1}{2}bc\sin A\\\\\frac{1}{2}\cdot9.75\cdot7.39\sin36.43\\\\A=21.39[/tex]

Hence, area of triangle ABC is 21.39 square units.

C is the correct option.

Answer: no

Step-by-step explanation:

Answer:

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y = mx + b

m - slope

b - y-intercept

Parallel lines have the same slope.

===========================================

We have y= -6x - 9 → m = -6

Put the value of a slope and the coordinates of the point (-2, 3) to the equation of a line:

3 = -6(-2) + b

3 = 12 + b        subtract 12 from both sides

-9 = b → b = -9

Finally:

y = -6x - 9

Answer: Yes it is.

Step-by-step explanation: So we are already told that segment AC is congruent to segment DC. They both have a right angle, as indicated by the angle symbol, and they share side-length BC.

According to the Hypotenuse-Leg Theorem, two right triangles that have a congruent hypotenuse and a corresponding, congruent leg are congruent triangles. AC and DC are hypotenuses and they are congruent. And BC, the shared side, is a corresponding congruent leg. And since they are both right triangles, we then know that the HL Theorem applies.

Add all of the number of pizzas together

93+67+78+44+123

160+245

405

Divide by 5 because there are 5 numbers

405/5=81

81 pizzas

Answer: 81 pizzas -C.

[tex]\bf (\stackrel{x_1}{10}~,~\stackrel{y_1}{8})~\hspace{10em} slope = m\implies \cfrac{2}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-8=\cfrac{2}{5}(x-10) \\\\\\ y-8=\cfrac{2}{5}x-4\implies y=\cfrac{2}{5}x+4[/tex]