Part A (7 points): How many grams of iron (Fe) will be produced if you start with 3.65 liters of carbon monoxide gas (CO) at STP?

Part B (3 points): Jacob performed the above experiment in his chemistry class, and collected 4.23 grams of iron. What is the percent yield?

Fe2O3 + 3 CO --> 2 Fe + 3 CO2

Answer:

The element will be represented as : [tex]Ba_{56}^{130}[/tex]

Explanation:

The identity of an element (isotope) is with its atomic number.

The atomic number is the number of protons in the element.

Irrespective of the number of electrons / neutrons the atomic number will be equal to the number of protons only.

atomic number of the isotope is 56.

The element with 56 atomic number is Barium

The mass number of Barium = protons + neutrons = 56 + 74 = 130

The element will be represented as : [tex]Ba_{56}^{130}[/tex]

100 g of corn chips has 17.69 calories

1 g of corn chips has 17.69/100 or 0.1769 calories

Therefore, 1 g of tomatoes has 0.1769 x 10⁻³ kilocalories

100 g of corn chips has 518 calories

1 g of corn chips has 518/100 or 5.18 calories

Therefore, 1 g of corn chips has 5.18 x 10⁻³ kilocalories

To balance the equation for the decomposition of barium chlorate into barium chloride and oxygen, ensure that there are equal numbers of each atom on both sides of the equation. The balanced equation is 2 Ba(ClO₃)₂ → 2 BaCl₂ + 3 O₂.

To balance the chemical equation for the decomposition of barium chlorate into barium chloride and oxygen, we must ensure that the number of each type of atom is the same on both sides of the equation. The formula for barium chlorate is Ba(ClO₃)₂, barium chloride is BaCl₂, and oxygen is O₂ (since oxygen is a diatomic molecule).

The unbalanced equation is as follows:

Ba(ClO₃)₂ → BaCl₂ + O₂

To balance this equation:

The balanced equation is:

2 Ba(ClO₃)₂ → 2 BaCl₂ + 3 O₂

ck(CH₃COOH) = 0,5 M.

V = 1 L.

Ka = 1,8·10⁻⁵.

pKa = -logKa = 4,75.

pH = 5,675.

Henderson–Hasselbalch equation: pH = pKa + log(cs/ck).
5,675 = 4,75 + log(cs/ck).
log(cs/ck) = 5,675 - 4,75 = 0,925.
cs/ck = 10∧(0,925) = 8,4.

cs = 8,4 · 0,5 M = 4,2 M.

n(CH₃COONa) = 4,2 mol/L · 1 L = 4,2 mol.

the answer is 9. took the test and got it correct

The pressure of the gas increases when its volume is reduced from 4 L to 0.5 L at constant temperature, according to Boyle's Law, which dictates an inverse relationship between volume and pressure for a given amount of gas.

When the volume of a gas is reduced from 4 L to 0.5 L while the temperature is held constant, according to Boyle's Law, the pressure of the gas increases. Boyle's Law states that at constant temperature, the volume of a fixed number of moles of a gas is inversely proportional to the pressure applied to it. This means that if you decrease the volume of the gas, the pressure must increase to compensate, assuming the amount of gas does not change.

Therefore, in this case where the volume decreases by a factor of 8 (from 4 L to 0.5 L), the pressure must increase by the same factor, assuming that no gas escapes and the temperature remains constant. It's important to note that these principles assume ideal gas behavior and may not perfectly model real gases under all conditions.

Final answer:

The standard enthalpy change (ΔH°) for the reaction of ammonia with O2 to yield nitric oxide and H2O(g) is calculated using standard enthalpies of formation and is found to be -633.2 kJ.

Explanation:

To calculate the standard enthalpy change (ΔH°) for the reaction of ammonia (NH3) with O2 to yield nitric oxide (NO) and H2O(g), we can use the standard enthalpies of formation (ΔH°f) for the reactants and products. Unfortunately, the provided information contains several elements that are not relevant to this question. Let us use the correct ΔH°f values to find the ΔH° for this reaction. Assuming we have balanced the equation and it is:

4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g)

The formula to calculate ΔH° is:

ΔH° = [∑ (ΔH°f products) × (moles of product)] - [∑ (ΔH°f reactants) × (moles of reactant)]

Using the values given for ΔH°f:

ΔH°f NH3 = -46.1 kJ/mol
ΔH°f NO = 91.3 kJ/mol
ΔH°f H2O(g) = -241.8 kJ/mol

For the reaction:

ΔH° = [4×91.3 kJ/mol + 6×(-241.8 kJ/mol)] - [4×(-46.1 kJ/mol) + 5×0 kJ/mol]

ΔH° = (365.2 kJ - (-1448.8 kJ)) - (-184.4 kJ + 0 kJ)

ΔH° = -817.6 kJ + 184.4 kJ

ΔH° = -633.2 kJ

Therefore, the standard enthalpy change for the reaction is -633.2 kJ.

elements is the same group have similar chemical properties

The answer is false.

Within the extracellular fluid (ECF), the major cation is sodium (Na⁺) while the major cation in the intracellular fluid is potassium (K⁺). Sodium-potassium pump, is a solute pump that pumps three sodium ions out of the cell in exchange for two potassium ions pumped in the cell, both against their concentration gradients.These electrolytes play an important role in maintaining homeostasis. The ECF, in particular the interstitial fluid, is surrounding all of the cells in the body and therefore is crucial for their normal functions. The ECF is maintained by a number of homeostatic mechanisms including regulation of sodium concentration.

Photosynthesis is a chemical process used by plants where solar energy is used to transform carbon dioxide and water into carbohydrates and oxygen.

It is the biochemical process by which plants convert inorganic matter (carbon dioxide and water) into organic matter (sugars), taking advantage of energy from sunlight.

This process constitutes one of the most important biochemical mechanisms on the planet since it involves the manufacture of organic nutrients that store light energy from the Sun.

Therefore, we can conclude that photosynthesis is the process carried out by plants to transform inorganic matter (Carbon dioxide, water and solar energy) into organic substances.

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Answer:

Electrons in the outermost shell are called valence electrons, because it is their interactions that determine the chemical properties of an element. The columns that were set up to group elements by similar chemical properties turn out to be the exact same columns defined by the number of valence electrons.

The valence electron of an element determines the group of the element and elements in the same group have similar chemical properties.

The valence electron of an element indicates its the group of the element in the periodic table. Elements found within the same group in the periodic table have similar chemical properties.

For example:

Thus, we can conclude that valence electron of an element determines the group of the element and elements in the same group have similar chemical properties.

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Acids and bases are similar in that they conduct electricity in aqueous solutions and both react to form salt and water. Their differences lie in taste, color changes in litmus paper, and pH values where acids have pH lower than 7 and bases have pH greater than 7.

Acids and bases are both types of compounds that chemists often deal with. They are similar in that they both conduct electricity when in aqueous solution and they both react with each other to form salt and water, a reaction known as neutralization. However, they are also distinctly different. The first difference is that acids have a sour taste and can turn blue litmus paper red, while bases have a bitter taste and can turn red litmus paper blue. Additionally, acids tend to have a pH less than 7, whereas bases have a pH greater than 7.

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The helium flash, a nearly explosive ignition in a red giant star's core, converts helium into carbon through the triple-alpha process. This marks a crucial step in stellar evolution involving the production of heavier elements. Recognized by two protons in its nucleus, helium exists as the second most abundant element in the universe.

The helium flash refers to a nearly explosive ignition of helium as a part of the triple-alpha process in the dense core of a red giant star. During the helium flash, helium (a lighter element) is converted into a heavier element, specifically, carbon. Managed through a sequence called the triple-alpha process, three helium-4 nuclei combine to form a carbon-12 nucleus.

The process of forming helium from hydrogen involves addition of another proton to create the helium nucleus, emitting significant energy. As a part of stellar evolution, the complete exhaustion of helium in the core leads to the production of heavier elements like oxygen, neon, and magnesium, by the fusion of carbon.

For context, helium is the second-most abundant element in the universe, discovered in 1868, and is defined by its two protons within the nucleus. This element is most commonly known as the light gas used to inflate balloons.

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Answer:

Only Test 2 will indicate a chemical property of sodium bicarbonate. Tests 1 and 3 will show a physical property of the substance.

Explanation:

1) In test 1 we are dissolving sodium bicarbonate and here there is no chemical change in the property of sodium bicarbonate if it dissolved so it is a pure physical process.

2) In test 2 we are reacting sodium bicarbonate with vinegar (acetic acid).

The reaction is:

[tex]NaHCO_{3}+CH_{3}COOH--->CH_{3}COONa+H_{2}O+CO_{2}[/tex]

Due to formation of carbon dioxide it fizzes. Thus this is a chemical property of sodium bicarbonate to acts as base.

3) In test 3, we are heating and testing the melting point of sodium bicarbonate, which is again a physical property.

The oxidation number of Cu in CuSO₄ is +2 and 0 in Cu, the free elemental form. As the oxidation of Cu decreases from +2 to 0, we are looking at the reduction half-reaction for the given redox reaction:

Cu²⁺ + 2e⁻ → Cu

The correct answer is option B.

Answer:

A: They evaporate

Explanation:

Where do the OH- ions go as additional acid is added? They evaporate. They combine with excess H+ ions to form more water. They remain in the solution at the same concentration.

Answer is: nitrogen(N₂), oxygen(O₂), hydrogen(H₂), carbon monoxide(CO), calcium oxide(CaO), hydrogen chloride(HCl), sodium hydride(NaH).

Diatomic molecules are molecules made of two atoms.

They can be homonuclear (molecule made of two atoms of the same element) and heteronuclear (molecule made of two different atoms).

The answer is C. Subduction