Answer:
0.2036
Step-by-step explanation:
u = arcsin(0.391) ≈ 23.016737°
tan(u/2) = tan(11.508368°)
tan(u/2) ≈ 0.2036
__
You can also use the trig identity ...
tan(α/2) = sin(α)/(1+cos(α))
and you can find cos(u) as cos(arcsin(0.391)) ≈ 0.920391
or using the trig identity ...
cos(α) = √(1 -sin²(α)) = √(1 -.152881) = √.847119
Then ...
tan(u/2) = 0.391/(1 +√0.847119)
tan(u/2) ≈ 0.2036
__
Comment on the solution
These problems are probably intended to have you think about and use the trig half-angle and double-angle formulas. Since you need a calculator anyway for the roots and the division, it makes a certain amount of sense to use it for inverse trig functions. Finding the angle and the appropriate function of it is a lot easier than messing with trig identities, IMO.
I need help please.
Answer:2
4 th root of 1024 is 5
Since 4 x4x4x4x4=1024
So 1+2x=5
-1 PN both sides
2x= 4
Divide by 2
X=2
Step-by-step explanation:
A department store wants to know what fraction of its customers in a certain market have store credit cards, and what their average balance might be. Of the 120 customers surveyed, 30 had store credit cards. Amongst those customers, the average balance was $600, with a sample standard deviation of $80. Find the 98% confidence interval for the average credit card balance. ( , ) Round your answers to two decimal places.
Answer:
The 98% confidence interval for the average credit card balance is
(564.04, 635.96).
Step-by-step explanation:
We have to calculate the 98% confidence interval on the average credit card balance.
The sample will consist of the n=30 customers that have credit card.
The sample has a mean of $600 and a standard deviation of $80.
As the population standard deviation is estimated from the sample standard deviation, we will use a t statistic.
The degrees of freedom are:
[tex]df=n-1=30-1=29[/tex]
The critical value for a 98% CI and 29 degrees of freedom is t=2.463 (this can be looked up in a t-table).
Then, the margin of error is:
[tex]E=t\cdot s/\sqrt{n}=2.463*80/\sqrt{30}=197.04/5.48=35.96[/tex]
Then, the upper and lower bounds of the confidence interval are:
[tex]LL=\bar X-E=600-35.96=564.04\\\\UL=\bar X+E=600+35.96=635.96[/tex]
Find the median, first quartile, third quartile, and interquartile range of the data.
132, 127, 106, 140, 158, 135, 129, 138
Please hurry
Median: 133.5
Lower/First quartile: 128
Upper/Third quartile: 139
Interquartile range: 139 - 128 = 11
so your interquartile range is 11
Rachel poured 4/5 of a gallon of water into a bucket. Later, she added 3/10 of a gallon more. How much water is in the bucket now?
Answer:
1 1/10 gallons
Step-by-step explanation:
Add 4/5 gallon + 3/10 gallon
Get a common denominator of 10
4/5*2/2 + 3/10
8/10 +3/10
11/10
Change from an improper fraction to a mixed number
10/10 + 1/10
1 1/10 gallons
Answer:
1.1
Step-by-step explanation:
If she added the first 4/5 then she added the 3/10 then you have to add them to figure out how much water is in the bucket.
A survey is to be conducted to determine the average driving in miles by Minnesota State University, Mankato students. The investigator wants to know how large the sample should be so that he/she can be 92% confident on the estimate and the estimate is within 1.5 miles of the true average. A similar study conducted in past and it was found that the standard deviation of the students’ driving distances was 8.2 miles.
Answer:
[tex]n=(\frac{1.75(8.2)}{1.5})^2 =91.52 \approx 92[/tex]
So the answer for this case would be n=92 rounded up to the nearest integer
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
[tex]\bar X[/tex] represent the sample mean for the sample
[tex]\mu[/tex] population mean (variable of interest)
s represent the sample standard deviation
n represent the sample size
Solution to the problem
The margin of error is given by this formula:
[tex] ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}[/tex] (a)
And on this case we have that ME =1.5 and we are interested in order to find the value of n, if we solve n from equation (b) we got:
[tex]n=(\frac{z_{\alpha/2} \sigma}{ME})^2[/tex] (b)
The critical value for 92% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.04;0;1)", and we got [tex]z_{\alpha/2}=1.75[/tex], replacing into formula (b) we got:
[tex]n=(\frac{1.75(8.2)}{1.5})^2 =91.52 \approx 92[/tex]
So the answer for this case would be n=92 rounded up to the nearest integer
Erin spent $15.30 on ingredients for cookies she's making for the school bake sale. How many cookies must she sell at $0.35 apiece to make a profit
Answer:
She would have to sell 44 cookies or more.
Step-by-step explanation:
Answer:
She would have to sell 44 cookies or more
Step
C is the center of a circle. Find the length of arc AB to two decimal points
Answer:
d
Step-by-step explanation:
C is the center of a circle. Find the length of arc AB to two decimal points
Answer:
d
Step-by-step explanation:
s=13.68
Suppose task B follows task A. The likelihood that a problem will occur with task A is 0.5, and the time to correct the problem would be 2 months. The likelihood that a problem will occur with task B is 0.2, and the time to correct the problem would be 3 months. The risk consequence of both activities is 3.5 months 5.7 months 1.6 months cannot be determined. True or false?
Answer:
The risk consequence of both activities is 1.6 months.
Step-by-step explanation:
We can define a randome variable D: total delay time for the project, and calculate its expected value.
This would be the risk consequence of both activities.
The expected delay time for the project is the sum of the expected delay for task A plus the expected delay for task B. It is assumed the likelihood of a problem in any task is independent of the other.
Then, each expected delay for a task is equal to the probability of a problem multiplied by the consequence (delay time).
[tex]E(D)=E(D_a)+E(D_b)=p_aT_a+p_bT_b\\\\E(D)=0.5*2+0.2*3=1+0.6=1.6[/tex]
The risk consequence of both activities is 1.6 months.
2 dot plots. Both number lines go from 0 to 10. Plot 1 is titled Middleton. There is 1 dot above 1, 4 dots above 2, 5 dots above 3, 4 dots above 4, 4 dots above 5, 1 dot above 6, 0 dots above 7, 0 dots above 8, 1 dot above 9, 0 dots above 10. Plot 2 is titled Westwood. There are 0 dots above 0, 0 dots above 1, 4 dots above 2, 5 dots above 3, 4 dots above 4, 4 dots above 5, 3 dots above 6, and 0 dots above 7, 8, 9, and 10.
The two dot plots represent a sample of the number of people in households in two towns. Which statements are true about the data sets?
Check all that apply.
Both have the same number of data points.
Both means are between 3 and 4.
Both have the same median.
Both have the same range.
Westwood has less variability than Middleton.
Answer:
It is A,B,and E.
I just did the question and it was right
The true statements about the dot plots are (A) Both have the same number of data points, (B) Both means are between 3 and 4. and (C) Westwood has less variability than Middleton.
What is Mean?Mean of a set of data is defined as the average of all the values. It gives the exact middle point of the data set.
Given are two plots, Middleton and Westwood.
Data points in plot 1 are 1, 2, 2, 2, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 6, 9
Total number of data points in plot 1 or Middleton = 20
Data points in plot 2 are 2, 2, 2, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 6, 6, 6
Total number of data points in plot 2 or Westwood = 20
So, both have the same number of data points.
Mean of Middleton = Sum of the data points / Total number of data points
= [1 + (4×2) + (5×3) + (4×4) + (4×5) + 6 + 9] / 20
= 75/20
= 3.75
Similarly,
Mean of Westwood = 77/20 = 3.85
So both means are between 3 and 4.
Median is the exact middle element when arranged in increasing or decreasing order.
Exact middle point is the average of 10th and 11th element.
Median of Middleton = (3 + 4)/2 = 3.5
Median of Westwood = (4 + 4)/2 = 4
Both have different medians.
Range of the data set is the difference of maximum point and minimum point.
Range of Middleton = 9 - 1 = 8
Range of Westwood = 6 - 2 = 4
Both have different ranges.
Range is a measure of variation.
Range of Westwood is less than range of Middleton.
So, Westwood has less variability than Middleton.
Hence the true statements are A, B and C.
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Two-digit natural numbers are formed, with replacement, from the digits 0 through 9.
How many numbers are greater than 45?
There are 54 two-digit numbers greater than 45. This is calculated by finding the range of valid two-digit numbers (46 to 99) or carefully counting possible combinations without including 45.
Explanation:The two-digit numbers greater than 45 are any numbers from 46 to 99. We can find the amount of these numbers by subtracting 45 from 99. So, there are 54 two-digit numbers greater than 45.
Another way to visualize this is by considering the two-digit possibilities. The first digit can range from 4 to 9 (six possibilities), and the second digit can range from 0 to 9 (ten possibilities). However, since 40-45 are not included, we subtract 5 from the total possibilities, resulting in 60 (=6*10) -5 = 55. Therefore, it seems that we have one number too many, but we must not forget that 45 itself is not included, hence the total numbers exceeding 45 are 54 (55-1).
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please answer tyty :)
Answer:
3
Step-by-step explanation:
0 indicates no relationship. must be full number.
In 2010 as part of the General Social Survey, 1295 randomly selected American adults responded to this question: "Some countries are doing more to protect the environment than other countries are. In general, do you think that America is doing more than enough, about the right amount, or too little?" Of the respondents, 473 replied that America is doing about the right amount. What is the 95% confidence interval for the proportion of all American adults who feel that America is doing about the right amount to protect the environment. Group of answer choices (0.352, 0.378) (0.343, 0.387) (0.339, 0.391) (0.331, 0.400)
Answer:
(0.339, 0.391)
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
For this problem, we have that:
[tex]n = 1295, \pi = \frac{473}{1295} = 0.365[/tex]
95% confidence level
So [tex]\alpha = 0.05[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.365 - 1.96\sqrt{\frac{0.365*0.635}{1295}} = 0.339[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.365 + 1.96\sqrt{\frac{0.365*0.635}{1295}} = 0.391[/tex]
So the correct answer is:
(0.339, 0.391)
Coin Toss Results H = Heads T = Tails T H T H T H T T T T H T H T T Find the experimental probability of tossing heads.
Answer:
1/3
Step-by-step explanation:
Answer:
1/3
Step-by-step explanation:
took a test and its correct.
Which choices are equivalent to the quotient below? Check All That Apply.
Answer:
A, E
Step-by-step explanation:
brainliest please
The culinary herb cilantro, Coriandrum sativum, is very polarizing; some people love it and others hate it. A genetic component is suspected to be at play. A survey of 12087 American adults of European ancestry asked whether they like or dislike the taste of cilantro. A total of 3181 said that they dislike the taste of cilantro.
(a) Estimate with 95% confidence (and interpret) the proportion of all American adults of European an- cestry who dislike the taste of cilantro
(b) Estimate with 95% confidence (and interpret) a lower confidence bound for the proportion of all Amer- ican adults of European ancestry who dislike the taste of cilantro
Answer:
The 95% confidence (and interpret) the proportion of all American adults of European an- cestry who dislike the taste of cilantro
( 0.2552 , 0.2709)
b) The lower bound for the proportion of all American adults of European ancestry who dislike the taste of cilantro is 0.2552
Step-by-step explanation:
Explanation:-
Given data a survey of 12087 American adults of European ancestry asked whether they like or dislike the taste of cilantro.
large sample size 'n' = 12087 American adults
in survey A total of 3181 said that they dislike the taste of cilantro.
so The sample proportion 'p' = [tex]\frac{3181}{12087} = 0.2631[/tex]
a) Estimate with 95% confidence (and interpret) the proportion of all American adults of European ancestry who dislike the taste of cilantro.
[tex](p - 1.96 \sqrt{\frac{pq}{n} } ,p + 1.96\sqrt{\frac{pq}{n} } )[/tex]
[tex](0.2631 - 1.96 \sqrt{\frac{0.2631 X 0.7369}{12087} } ,0.2631 + 1.96\sqrt{\frac{0.2631 X 0.7369 }{12087} } )[/tex]
(0.2631 - 0.00784 , 0.2631 + 0.00784 )
( 0.2552 , 0.2709)
b) The lower bound for the proportion of all American adults of European ancestry who dislike the taste of cilantro is 0.2552
We are 95% confident that the proportion of all American adults of European ancestry who dislike the taste of cilantro is between 25.5% and 27.1%, and at least 25.5% dislike the taste.
Explanation:This question is related to confidence intervals in statistics. To compute a confidence interval for a population proportion, we mainly need the sample proportion and the size of the sample. Here, the proportion is the number of respondents that dislike cilantro (3181) divided by the total number of respondents (12087).
Thus, the sample proportion (value of p) is 3181/12087 = 0.263 or 26.3%.
The formula for a confidence interval is:
CI = p +/- Z * sqrt[ (p(1-p)) / n ],
where Z is the Z-score (for 95% confidence, Z = 1.96), p is the sample proportion, and n is the sample size.
Applying the values, we get:
CI = 0.263 +/- 1.96 * sqrt[ (0.263)(1 - 0.263) / 12087 ]
After calculation, the 95% confidence interval is about (0.255, 0.271). This means we are 95% confident that the proportion of all American adults of European ancestry who dislike the taste of cilantro is between 25.5% and 27.1%.
For the lower bound, we can take the lower limit of our confidence interval, which is 0.255 or 25.5%. This means we are 95% confident that at least 25.5% of all American adults of European ancestry dislike the taste of cilantro.
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Suppose that $7,000 is invested at an interest rate of 6%, compounded continuously. Find the amount in the account after five years if no withdrawals are made
Answer:
9100
Step-by-step explanation:
I=Prt
I=7,000(.06)5
I=420(5)
I=2,100
2,100+7,000=9,100
These are the means and standard deviations for samples of prices from two
different brands of shoes
Brand A
Mean: $50
Standard deviation: $5
Brand B
Mean: $40
Standard deviation: $8
Select the two true statements,
A. Brand A has a higher average price than brand B.
B. Brand A's prices are more spread out than brand B's prices.
C. Brand A has a lower average price than brand B.
D. Brand A's prices are less spread out than brand B's prices,
Answer:
A. Brand A has a higher average price than brand B.
D. Brand A's prices are less spread out than brand B's prices.
Step-by-step explanation:
We are given the means and standard deviations for samples of prices from two different brands of shoes below;
Brand A Brand B
Mean : $50 Mean : $40
Standard deviation : $5 Standard deviation : $8
Now, from the given statements;
Statement A is correct that Brand A has a higher average price than brand B because as given above Mean of Brand A ($50) > Mean of Brand B ($40).
Also, Statement D is correct that Brand A's prices are less spread out than brand B's prices because the Variance of Brand A is less than the variance of Brand B, i.e.;
Variance of Brand A = [tex]5^{2}[/tex] = $25
Variance of Brand B = [tex]8^{2}[/tex] = $64
Clearly, $25 < $64, so statement D is also correct.
Therefore, the two true statements are Statement A and Statement D.
Final answer:
A. Brand A has a higher average price than brand B.
D. Brand A's prices are less spread out than brand B's prices.
Explanation:
The true statements are that Brand A has a higher average price and less variability in prices than Brand B, which is represented by a lower standard deviation for Brand A.
To expand on these points:
Brand A has a mean price of $50 which is higher than Brand B's mean price of $40, confirming that Brand A has a higher average price (Statement A).
Brand A's standard deviation is $5, while Brand B's standard deviation is $8. A standard deviation is a measure of spread or variability in a set of data. The fact that Brand A's standard deviation is lower indicates that its prices are less variable and more closely clustered around the mean, hence less spread out compared to Brand B (Statement D).
7. The ruler below has eleven marks and can be used to measure lengths
from one unit to twelve units.
Design a ruler which can be used to measure all the lengths from one
unit to twelve units but this time put the minimum possible number
of marks on the ruler.
Answer:
use 6cm twice and that adds up to 12cm .six is the minimal possible number
A ruler designed to measure lengths from one unit to twelve units with the minimum number of marks would only have marks at every unit. This results in only eleven markings (from 1 to 11), as the 0 marks the start and the twelfth unit marks the end.
Explanation:The subject of the student's question pertains to the design of a ruler with the minimum possible number of marks that can measure lengths from one to twelve units. To achieve this, the ruler should only be marked at every unit. This way, there would be only eleven marks (1-11), as the 0 marks the start of the ruler and the twelfth unit is considered the end of the ruler but does not require a mark. Therefore, only the spaces between these numbers need to be marked to enable measurement all the way up to twelve units.
In practice, such a ruler is less precise than a ruler with more marks as the latter can measure smaller lengths more accurately. However, the task demands the bare minimum for a measure from 1 to 12, thus we have eleven marks.
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If a six-sided die is rolled 30 times, how many times can you expect to get a 6?
5 times,I hoped this helped you out,if not sorry
S is directly proportional to the fifth power of t
[tex]\[ s = kt^5 \][/tex]
This equation represents the model for the statement "s is directly proportional to the fifth power of t".
When two variables [tex]\( s \)[/tex] and [tex]\( t \)[/tex] are directly proportional to each other, it means that as one variable increases, the other variable also increases by a constant factor. Mathematically, we can express this relationship as:
[tex]\[ s = kt^n \][/tex]
Where:
- [tex]\( s \)[/tex] is the dependent variable.
-[tex]\( t \)[/tex] is the independent variable.
- [tex]\( k \)[/tex] is the constant of proportionality.
- [tex]\( n \)[/tex] is the exponent representing the power to which the independent variable is raised.
In this case, the statement says that s is directly proportional to the fifth power of t . So, we have:
[tex]\[ s = kt^5 \][/tex]
This equation represents the model for the statement "s is directly proportional to the fifth power of t".
Complete correct question:
Write a model for the statement
s is directly proportional to the fifth power of t.
An ant arrives at the snail’s starting position at time minutes and follows the snail’s path. During the interval minutes, the ant travels in the same direction as the snail with a constant acceleration of 2 inches per minute per minute. The ant catches up to the snail at time minutes. The ant’s velocity at time is B inches per minute. Find the value of B.
QUESTION BEGINNING
Given a snail is traveling along a straight path. The snail’s velocity can be modeled by [tex]v(t)=1.4ln(1+t^2)[/tex] inches per minute for 0 ≤ t ≤ 15 minutes.
Answer:
B=22.35 Inches per minutes
Step-by-step explanation:
If the snail's velocity is [tex]v(t)=1.4ln(1+t^2)[/tex] per minute, its displacement for 0 ≤ t ≤ 15 minutes is given by the integral:
[tex]\int v(t) dt=\int (1.4ln(1+t^2))dt=76.04307[/tex]
The constant acceleration of the ant is 2 Inches per minute.
The velocity of the ant therefore, twill be:
[tex]\int 2 dt=2t+K, $where K is a constant of integration$[/tex]
For the interval, 12≤t≤15, the displacement of the ant is:
[tex]\int_{12}^{15}(2t+K) dt=81+3K[/tex]
Since the snails displacement and that of the ant are equal in 12≤t≤15.
81+3K=76.04307
3K=76.04307-81
3K=-4.95693
K=-1.65231
At t=12, the velocity of the ant is therefore:
2t+K=2(12)-1.65231=22.348 Inches per minutes
B=22.348 Inches per minutes
Final answer:
The question examines a scenario involving an ant accelerating to catch up with a snail, focusing on determining the ant's velocity at the catch-up point. Utilizing the principle of kinematics and acceleration, the answer lies in relating the acceleration to the final velocity, dependent on the time variable, which underscores the direct relationship between acceleration and velocity increase.
Explanation:
The question essentially deals with kinematics, specifically with the scenario of an ant accelerating from rest to catch up with a snail. Given the ant accelerates at 2 inches per minute per minute, and eventually matches velocities with the snail, the goal is to find the ant's velocity (B inches per minute) at the moment it catches up.
Firstly, we know the acceleration (a) is 2 inches/minute2. From kinematic equations, specifically v = u + at, where 'u' is the initial velocity (0 in this case since the ant starts from rest), 'a' is acceleration, and 't' is time, we can plug in our values. The time variable 't' here represents the duration from when the ant starts until it catches up with the snail, which is not explicitly given but is critical in understanding the rate of acceleration's contribution to velocity.
For the purpose of solving this problem, without explicit time or distances, we focus on the principle that the ant's final velocity (B) is a product of its acceleration over a given period: B = 0 + (2)t. Thus, the value of 'B' entirely depends on the time 't', demonstrating a direct correlation between acceleration duration and velocity increase.
The square below represents one whole.
What percent is represented by the shaded area?
Answer:
13%
Step-by-step explanation:
There are 100 squares and 13 are shaded so
13/100=
13%
Answer:
13%
Step-by-step explanation:
Suppose a batch of metal shafts produced in a manufacturing company have a standard deviation of 22 and a mean diameter of 200200 inches. If 8383 shafts are sampled at random from the batch, what is the probability that the mean diameter of the sample shafts would differ from the population mean by less than 0.20.2 inches? Round your answer to four decimal places. Answer
Answer:
The probability that the mean diameter of the sample shafts would differ from the population mean by less than 0.2 inches is 0.5319.
Step-by-step explanation:
According to the Central Limit Theorem if we have a population with mean μ and standard-deviation σ and appropriately huge random-samples (n > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.
Then, the mean of the distribution of sample mean is given by,
[tex]\mu_{\bar x}=\mu[/tex]
And the standard deviation of the distribution of sample mean is given by,
[tex]\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}[/tex]
The information provided is:
[tex]\mu=200\\\sigma=22\\n=83[/tex]
Since n = 83 > 30, the Central Limit Theorem can be used to approximate the sampling distribution of sample mean diameter of the shafts.
Then:
Mean: [tex]\mu_{\bar x}=\mu=200[/tex]
Standard deviation: [tex]\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{22}{\sqrt{83}}=2.415[/tex]
Compute the probability that the mean diameter of the sample shafts would differ from the population mean by less than 0.2 inches as follows:
[tex]P(\bar X-\mu_{\bar x}<0.20)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}<\frac{0.20}{2.415})[/tex]
[tex]=P(Z<0.08)\\=0.53188\\\approx0.5319[/tex]
*Use a z-table.
Thus, the probability that the mean diameter of the sample shafts would differ from the population mean by less than 0.2 inches is 0.5319.
Which point do The graphs F and G have in common
Answer:
1,0
Step-by-step explanation:
Answer:
1,0
Step-by-step explanation:
What are the zeroes of the function y=3(x-a)(x+b) in terms of a and b?
Answer:
a, -b
Step-by-step explanation:
When x is a, the function becomes
[tex]f(a)=3(a-a)(a+b)[/tex]
as you see, a-a is 0, and as your whole function is multiplied by this, it makes it 0.
[tex]f(-b)=3(-b-a)(-b+b)[/tex]
As you see -b+b is 0, and once again, this would make the whole function 0.
An SRS of 2,500 individuals was taken from a city with population 1 million, to estimate the percentage of city residents with a graduate degree. 555 people in the sample had a graduate degree. The proportion of individuals in the city with a graduate degree is estimated as 23%. Say the true percentage of individuals in the city who have a graduate degree is 22%. In this case, the standard error of the sample proportion is closest to:
Answer:
The standard error of the sample proportion is closest to 1%
Step-by-step explanation:
Standard error of the sample proportion is given as
σₓ = √[p(1-p)/n]
where
p = sample proportion = estimated to be 23% = 0.23
n = Sample size = 2500
σₓ = √[p(1-p)/n]
σₓ = √[0.23×0.77/2500]
σₓ = 0.0084166502 = 0.00842
σₓ = 0.00842 = 0.842%
Hence, it is easy to see that the standard error of the sample proportion is closest to 1%.
Hope this Helps!!!
An experiment that claimed to show that meditation reduces anxiety proceeded as follows. The experimenter interviewed the subjects and rated their level of anxiety. Then the subjects were randomly assigned to two groups. The experimenter taught one group how to meditate and they meditated daily for a month. The other group was simply told to relax more. At the end of the month, the experimenter interviewed all the subjects again and rated their anxiety level. The meditation group now had less anxiety. What property of good experiments is missing from the study? control group randomization using enough subjects blinding
Answer:
Experiement lacked blindness concept
Step-by-step explanation:
In good experiments, the results are totally unbiased and unknown to anyone, even to those conducting the experiment.
In the given case, the interviewer had an idea about which group had gone for meditation so it was obvious that they would yield less anxiety.
Here the concept of blinding was missing, which is essential for a good and fair experiment. A good experiemnt is a double blinded experiement or atleast it should be single blinded
A study conducted by the Toledo police at the intersection of Byrne and Heatherdowns for the 7 to 9 AM drive time revealed the follwoing number of vehicles that proceeded through the intersection after the light changed. The information reported is for a SAMPLE of 6 days during a 1 month period.6 12 7 12 8 9Find the mean, median, mode and standard deviation for the SAMPLE.
Answer:
(a)Mean=9
(b)Median=9.5
(c)Mode=12
(d)Standard Deviation=2.53
Step-by-step explanation:
The sample of the number of vehicles that proceeded through the intersection after the light changed for 6 days during a 1 month period is given below:
6 12 7 12 8 9
(a)Mean
[tex]Mean=\frac{6+12+ 7+ 12+ 8+ 9}{6} \\=\frac{54}{6} \\Mean=9[/tex]
(b)Median
First, arrange in ascending order
6,7,8,9,12,12
Since we have two terms in the middle, we take the average.
[tex]Median=\frac{8+9}{2}\\Median=8.5[/tex]
(c)Mode
The mode is the number with the highest frequency. The mode number of cars is 12.
(d)Standard Deviation
[tex]S.D.=\sqrt{\dfrac{\sum_{i=1}^{n}(x-\bar{x})^2}{n-1}}[/tex]
[tex]S.D.=\sqrt\frac{(6-9)^2+(7-9)^2+(8-9)^2+(9-9)^2+(12-9)^2+(12-9)^2}{6-1}[/tex]
[tex]=\sqrt{6.4} \\S.D.=2.53[/tex]
Compare to the graph f(x)=x^2 the graph of g(x)=(x-2)+3 is the result of translating f(x)
1.2 units up 3 units to the right
2. 2 units down and 3 units up
3. 2 units right and 3 units up
4 2 units left and 3 units right
Answer:
i believe it is 4 but i'm not so sure
Step-by-step explanation:
:)
The graph of g(x)=(x-2)^2+3 compared to the graph of f(x)=x^2 is translated 2 units to the right and 3 units upwards.
Explanation:To understand the transformation of graphs in mathematical terms, consider the initial function f(x) = x^2. The transition to the new function g(x)=(x-2)^2+3 is a result of a shift or translation of the graph. This transformation behaves as per the following rule: g(x) = f(x-h)+k where 'h' units is the horizontal displacement and 'k' units is the vertical displacement.
In the function g(x), x shifts two units to the right (as indicated by (x-2)) and three units upward (as indicated by +3).
So, the correct answer is 2 units right and 3 units up.
Learn more about graph transformation here:https://brainly.com/question/19040905
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Help me answer please.
Answer:
see explanation
Step-by-step explanation:
(a)
For the graph to display direct proportion it must pass through the origin.
The graph shown does not pass through the origin thus does not represent direct proportion.
(b)
Given that q is directly proportional to r then the equation relating them is
q = kr ← k is the constant of proportion
To find k use the condition q = 76 when r = 20, thus
76 = 20k ( divide both sides by 20 )
3.8 = k
q = 3.8r ← equation of proportion
When r = 45, then
q = 3.8 × 45 = 171