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Electric force is the attractive or reflective force of interception between two charged object.

Given information-

The mass of first object is 6 kg.

The mass of second object is 17 kg.

The charge on both the object is 0.027 C.

The distance between the two object is 3 m.

Electric force is the attractive or reflective force of interception between two charged object. It can be calculated using the Coulomb's law as,

[tex]F=k_e\dfrac{q_1\q_2}{r^2}[/tex]

Here, [tex]q[/tex] is the charge on the object and [tex]r[/tex] is the distance between the objects. [tex]k_e[/tex] is coulombs constant [tex](8.987\times 10^9)[/tex] N-m squared per C squared.

Put the values in above formula to find out the electric force between given objects-

[tex]F=8.987\times10^9\dfrac{(-0.027)\times(-0.027)}{3^2}\\F=7.28\times 10^5[/tex]

Hence the electric force that these objects exert on one another is [tex]7.28\times 10^5[/tex] N.

Gravitational force between two object with mass [tex]m_1[/tex] and [tex]m2[/tex] can be given as,

[tex]F_g=G\dfrac{m_1m_2}{r^2}[/tex]

Here [tex]G=6.67\times 10^{-11}[/tex] N-m squared per kg squared.

Put the values,

[tex]F_g=6.67\times 10^{-11}\times\dfrac{6\times17}{3^2}\\F_g=7.56\times10^{-10}[/tex]

Thus, the gravitational force between them is [tex]7.56\times10^{-10}[/tex] N.

Hence,

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Final answer:

The electric force and gravitational force between two objects can be calculated using specific laws involving charge, mass, and distance.

Explanation:

The electric force between two objects can be calculated using Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The gravitational force between the two objects can be determined using Newton's Law of Universal Gravitation, where the force is proportional to the product of the masses and inversely proportional to the square of the distance between them.

The detected frequency f1 can be calculated using the Doppler effect formula, which leads to the conclusion that option 3 is the correct answer (f1 = vs / (vs + vbat) * f0). This equation allows to determine the actual speed of the bat.

This question can be addressed using the Doppler effect principle, which describes how the frequency of sound changes for an observer moving in relation to a sound source.

Given that the bat is moving perpendicular to the wall with the speed vbat and since the night is clear and air is still (meaning no additional obstructions in the sound path), the detected frequency f1 can be calculated using the Doppler effect formula:

f1 = vs / (vs + vbat) * f0.

Therefore, option 3 is the correct answer. To measure the actual speed of the bat, you can install a detector on the wall and make use of the fact that frequencies f0 and f1 are known and the speed of sound vs is also known or can be easily determined from the conditions (e.g., air temperature).

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The question pertains to the Doppler Effect, and the formula for the detected frequency of the bat's echo, considering the bat's speed, is f1 = vs / (vs + vbat) * f0.

The question deals with the concept of the Doppler Effect in physics. This effect relates to the change in frequency or wavelength of a wave in relation to an observer who is moving relative to the wave source. In this specific scenario, a mechanical bat emits a sound with a frequency of f0 and moves towards a wall. The sound wave reflects off the wall and returns to the bat. The frequency that the bat hears is affected by its own velocity (vbat) and the speed of sound (vs) in the air around it.

Based on the formulas listed, the correct one is number 3, f1 = vs / (vs + vbat) * f0, based on the standard equation for Doppler Effect when the observer (in this case, the bat) is moving towards a stationary source (in this case, the reflected sound wave). When this happens, the observed frequency increases, since the bat is chasing the sound wave that it emitted.

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The frequency of a photon can be determined by relating its momentum to the speed of a neutron. The resulting frequency is 4.8 × 10¹4 Hz.

The frequency of a photon can be calculated using the relation between momentum and speed. Given that the speed of a neutron is 1.90 × 103 m/s, the frequency of the photon with the same momentum would be 4.8 × 10¹4 Hz.

The calculation of escape speed from a charged glass sphere involves principles from electrostatics and classical mechanics, requiring an understanding of how kinetic and electric potential energies equate as an electron moves away from the sphere. Unfortunately, without detailed formulae specific to this electrostatic scenario, a precise answer cannot be provided here.

The question involves calculating the escape speed of an electron from a charged glass sphere, which is a task that falls under the domain of electrostatics and classical mechanics in physics. Generally, the escape speed from a celestial body like Earth is determined by its mass and the gravitational forces involved. However, in this electrostatic context, the key forces are electrical, not gravitational. The escape speed in this scenario would depend on the electric potential energy and kinetic energy equivalence. Given the unique nature of the question which combines concepts from electrostatics with classical escape velocity calculations, a straightforward formula application from physics textbooks might not directly apply without considering the electric force on the electron due to the charged sphere. Nonetheless, the principle remains that to calculate escape speed, one would need to equate the kinetic energy of the electron with the work done against the electric force as it moves to infinity (where the electrical potential energy becomes zero).

The escape speed of an electron from the surface of a charged sphere can be found using the formula, yielding approximately 162 meters per second. This is derived considering the charge of the sphere, its radius, and Coulomb's constant.

To find the escape speed of an electron from a charged sphere, you need to use the concept of electric potential energy and kinetic energy. The escape speed, vesc, is given by:

where Q is the charge of the sphere, r is the radius of the sphere, and k is Coulomb's constant (k = 8.99 × [tex]10^9[/tex] N [tex]m^2[/tex]/[tex]C^2[/tex]).

Given:

Using the formula:

Thus, the escape speed of the electron from the surface of the charged sphere is approximately 162 meters per second.

Answer:

The acceleration of this skateboarder is 2.61 m/s^2.

Explanation:

120=46*a

/46   /46

2.61 m/s^2=a

The diameter of the air bubble when it reaches the surface is about 1.7 cm

[tex]\texttt{ }[/tex]

The basic formula of pressure that needs to be recalled is:

Pressure = Force / Cross-sectional Area

or symbolized:

[tex]\large {\boxed {P = F \div A} }[/tex]

P = Pressure (Pa)

F = Force (N)

A = Cross-sectional Area (m²)

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

In this problem , we will use Ideal Gas Law as follows:

Given:

initial diameter of bubble = d₁ = 1.0 cm

initial depth of the diver = h = 40 m

initial temperature = T₁ = 10 + 273 = 283 K

atmospheric pressure = Po = 1.0 atm = 10⁵ Pa

final temperature = T₂ = 20 + 273 = 293 K

density of water = ρ = 1000 kg/m³

Unknown:

final diameter of bubble = d₂ = ?

Solution:

[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}[/tex]

[tex]\frac{P_1 (\frac{1}{6} \pi (d_1)^3)}{T_1} = \frac{P_2(\frac{1}{6} \pi (d_2)^3)}{T_2}[/tex]

[tex]\frac{P_1 (d_1)^3}{T_1} = \frac{P_2 (d_2)^3}{T_2}[/tex]

[tex]\frac{(P_o + \rho g h ) (d_1)^3}{T_1} = \frac{P_o (d_2)^3}{T_2}[/tex]

[tex]\frac{(10^5 + 1000(9.8)(40) ) (1.0)^3}{283} = \frac{10^5(d_2)^3}{293}[/tex]

[tex]\frac{(492000 ) (1.0)^3}{283} = \frac{10^5(d_2)^3}{293}[/tex]

[tex]d_2 \approx 1.7 \texttt{ cm}[/tex]

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Physics

Chapter: Pressure

By applying the ideal gas law, we find the diameter at the surface to be approximately 1.7 cm.

To determine the bubble's diameter when it reaches the surface, we use the ideal gas law. Since temperature and volume are directly proportional under constant pressure, we can express this relationship as:

(V₁/T₁) = (V₂/T₂)

where,

Given that V₁ is π(0.005 m)² * h (since the volume of a sphere is directly proportional to the radius cubed), we know the final volume V₂ will change due to both temperature and the reduction in pressure as the bubble rises.

Hydrostatic pressure P₁ at 40 meters depth is given by:

P₁ = P₀ + ρgh

P₁ ≈ 1 + (1000 * 9.8 * 40) / 101325 ≈ 4.93 atm

At the surface, the only pressure is P₀ (1 atm).

Using the combined gas law P₁V₁/T₁ = P₂V₂/T₂:

4.93V₁/283 = 1V₂/293

Solving for V₂ we get:

V₂ = 4.93 * V₁ * 293 / 283

V₂ ≈ 5.09 * V₁

Since the volume ratio (D₂/D₁)³ = 5.09, taking the cube root:

D₂ ≈ 1.71 * D₁

So, if initial diameter D₁ is 1.0 cm:

D₂ = 1.71 * 1.0 cm ≈ 1.7 cm

Therefore, the bubble's diameter at the surface is approximately 1.7 cm.

Answer:

Any charged body has the capacity to effect any test charge that comes inside its field or region. It can be also defined as,

"The total amount or magnitude of force,F or intensity felt by any unit test charge when it enters an electromagnetic or electric field."

Explanation:

A unit test charge inside an electric field:

When a unit test charge enters a given parameters or area set by the charged particle then it will surely experience a force,F equal to the magnitude of that charge body and it will be different as it continues to move closer or far inside the field.

Answer:

Carbon dioxide is a greenhouse gas that traps heat on eath increasing the global average temperature. This for example is melting the arctic ice faster and more than usual. This is leading many arctic species to loose their habitats.

Answer:

Carbon dioxide is a greenhouse gas that traps heat on eath increasing the global average temperature. This for example is melting the arctic ice faster and more than usual. This is leading many arctic species to loose their habitats

Explanation:

twas correct ed2022

The total number of electrons removed from the neutral silver dollar is [tex]1.5 \times 10^{13}[/tex] electrons.

A charge can be defined as a property of any matter that causes it to experience a force when it's placed in an electric or magnetic field. The electron is negatively charged. The value of an electron charge is [tex]1.6\times 10^{-19}\;\rm C[/tex]

Given that the neutral silver dollar has a charge [tex]q = +2.4 \mu \rm C[/tex] .

The charge can be given as,

[tex]q=ne[/tex]

Where n is the number of electrons. Thus,

[tex]n =\dfrac { q}{e}[/tex]

[tex]n = \dfrac {+2.4 \times 10 ^{-6}}{1.6\times 10^{-19}}[/tex]

[tex]n = 1.5 \times 10^{13}[/tex]

Hence we can conclude that the total number of electrons removed from the neutral silver dollar is [tex]1.5 \times 10^{13}[/tex] electrons.

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Violet waves have the most energy of the visible spectrum.

Remember:  c=fλ

Therefore:  f=c/λ

Here c is the speed of light in a vacuum.

So:

As wavelength decreases, frequency increases and, as E=hf, where h is constant (Planck's constant), so does the energy that the waves carry. Waves with a short wavelength have the most energy.

Violet is the color in the visible spectrum that has the highest frequency. (option b)

The visible spectrum consists of various colors that we can see with our eyes, ranging from red to violet. Each color corresponds to a specific wavelength of light. Wavelength is the distance between consecutive peaks (or troughs) of a wave. The frequency of a wave, on the other hand, refers to how many waves pass a particular point in space per unit of time.

The relationship between frequency (f), wavelength (λ), and the speed of light (c) can be described by the equation:

c = f × λ

where c is the speed of light in a vacuum (approximately 3 × 10^8 meters per second), f is the frequency, and λ is the wavelength.

As per this equation, the higher the frequency of light, the shorter the wavelength. Conversely, the lower the frequency, the longer the wavelength.

Hence the correct option is (b),

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Complete Question:

Which color in the visible spectrum has the highest frequency?

a) Blue

b) Violet

c) Green

d) Red

The work done by the teacher in pushing the desk is calculated by multiplying the force exerted (20 newtons) by the distance covered (5 meters), which gives a total work done of 100 joules.

To calculate the amount of work done in moving an object, we use the formula: Work = Force x Distance.

In this case, the teacher exerted a force of 20 newtons across a distance of 5 meters. Therefore the work is calculated as: 20N x 5m = 100 joules.

To summarise, the teacher did 100 joules of work on the desk when pushing it through a 5 meter distance.

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The complete question is here:

A teacher pushed a 98 newton desk across a floor for a distance of 5 meters. She exerted a horizontal force

of 20 newtons. How much work was done?

The current through the wire is of 0.00012 amperes.

By definition, current will be equal to the quotient between the total charge that flows and the time in which it flows.

Here we have 3.0*10^15 electrons, each one with charge:

e = 1.6*10^(-19) C

Then the total charge that we have is:

Q = (1.6*10^(-19) C)*(3.0*10^15) = 0.00048 C

Finally, the current is:

I = Q/T

where:

I = (0.00048 C)/(4s) = 0.00012 A

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