Equivalent expressions are expressions with the same value.
The values of the variables are:
[tex]\mathbf{a = 1}[/tex] [tex]\mathbf{b = 9}[/tex] [tex]\mathbf{c = -2}[/tex] [tex]\mathbf{d = 4}[/tex]
The expression is given as:
[tex]\mathbf{\frac{3x^2 + 2x - 21}{-2x^2 -2x + 12} \cdot \frac{2x^2 + 25x + 63}{6x^2 + 7x - 49}}[/tex]
Expand
[tex]\mathbf{\frac{3x^2 + 2x - 21}{-2x^2 -2x + 12} \cdot \frac{2x^2 + 25x + 63}{6x^2 + 7x - 49 } = \frac{3x^2 + 9x - 7x - 21}{-2x^2 +4x -6x + 12} \cdot \frac{2x^2 + 14x + 9x + 63}{6x^2 + 21x - 14x - 49 } }[/tex]
Factorize
[tex]\mathbf{\frac{3x^2 + 2x - 21}{-2x^2 -2x + 12} \cdot \frac{2x^2 + 25x + 63}{6x^2 + 7x - 49 } = \frac{3x(x + 3) - 7(x + 3)}{-2x(x -2) -6(x - 2)} \cdot \frac{2x(x + 7) + 9(x + 7)}{3x(2x + 7) - 7(2x - 7) } }[/tex]
Factor out the terms
[tex]\mathbf{\frac{3x^2 + 2x - 21}{-2x^2 -2x + 12} \cdot \frac{2x^2 + 25x + 63}{6x^2 + 7x - 49 } = \frac{(3x - 7) (x + 3)}{(-2x -6)(x - 2)} \cdot \frac{(2x + 9)(x + 7)}{(3x - 7) (2x - 7) } }[/tex]
Cancel out 3x - 7
[tex]\mathbf{\frac{3x^2 + 2x - 21}{-2x^2 -2x + 12} \cdot \frac{2x^2 + 25x + 63}{6x^2 + 7x - 49 } = \frac{(x + 3)}{(-2x -6)(x - 2)} \cdot \frac{(2x + 9)(x + 7)}{ (2x - 7) } }[/tex]
Factor out -2
[tex]\mathbf{\frac{3x^2 + 2x - 21}{-2x^2 -2x + 12} \cdot \frac{2x^2 + 25x + 63}{6x^2 + 7x - 49 } = \frac{(x + 3)}{-2(x +3)(x - 2)} \cdot \frac{(2x + 9)(x + 7)}{ (2x - 7) } }[/tex]
Cancel out x + 3
[tex]\mathbf{\frac{3x^2 + 2x - 21}{-2x^2 -2x + 12} \cdot \frac{2x^2 + 25x + 63}{6x^2 + 7x - 49 } = \frac{1}{-2(x - 2)} \cdot \frac{(2x + 9)(x + 7)}{ (2x - 7) }}[/tex]
Rewrite as:
[tex]\mathbf{\frac{3x^2 + 2x - 21}{-2x^2 -2x + 12} \cdot \frac{2x^2 + 25x + 63}{6x^2 + 7x - 49 } = \frac{(2x + 9)(x + 7)}{ -2(x - 2)(2x - 7) } }[/tex]
Expand
[tex]\mathbf{\frac{3x^2 + 2x - 21}{-2x^2 -2x + 12} \cdot \frac{2x^2 + 25x + 63}{6x^2 + 7x - 49 } = \frac{2x^2 + 25x + 63}{ -4x^2 + 22x - 28}}[/tex]
Factorize again
[tex]\mathbf{\frac{3x^2 + 2x - 21}{-2x^2 -2x + 12} \cdot \frac{2x^2 + 25x + 63}{6x^2 + 7x - 49 } = \frac{(2x+ 7)(x + 9)}{(2x + 7)(-2x + 4)}}[/tex]
Cancel out common factors
[tex]\mathbf{\frac{3x^2 + 2x - 21}{-2x^2 -2x + 12} \cdot \frac{2x^2 + 25x + 63}{6x^2 + 7x - 49 } = \frac{x + 9}{-2x + 4}}[/tex]
From the question, we have:
[tex]\mathbf{\frac{ax + b}{cx + d}}[/tex]
So, we have:
[tex]\mathbf{\frac{ax + b}{cx + d} = \frac{x + 9}{-2x + 4}}[/tex]
By comparison, we have:
[tex]\mathbf{a = 1}[/tex]
[tex]\mathbf{b = 9}[/tex]
[tex]\mathbf{c = -2}[/tex]
[tex]\mathbf{d = 4}[/tex]
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In calculating the present value of $1,000 to be received 5 years from today, the discount factor has been calculated to be .7008. what is the apparent interest rate?
A solid is composed of squares and equilateral triangles. Its net is shown below:
The area of each triangle is 1.5 square units. The surface area of the triangular prism is _____ square units. (Input whole number only.)
Answer:
So I am going one is kind of the same but it says six units and then it says the area of each triangle is 16 square units and I was trying to follow the step-by-step explanation from somebody else and I got 52 but I don’t know if I did that right
Step-by-step explanation:
How can Brady use fraction strips to show that 3 4 and 7 8 are NOT equivalent?
To demonstrate that 3/4 and 7/8 are not equivalent, Brady can use fraction strips to visually compare the colored portions of the strips, which will clearly show that 7/8 is greater than 3/4 as it has more colored sections.
Explanation:To show that 3/4 and 7/8 are not equivalent using fraction strips, Brady can follow these steps:
Take one strip and divide it into four equal parts to represent the fraction 3/4. Color three of these parts.Take another strip, divide it into eight equal parts to represent the fraction 7/8, and color seven of these parts.Compare the two colored strips side by side.Brady will observe that the strip representing 7/8 has more colored sections than the strip representing 3/4, even though the strips are the same length. This visual comparison confirms that 3/4 is less than 7/8, thus they are not equivalent fractions. The fraction 7/8 is only one-eighth away from being a whole, whereas 3/4 is one-fourth away.
help me please asap ill mark brainliest nd plz be correct
WILL MARK AS BRAINLIEST!!
What is the value of x?
Need help fast!
Why is it most logical to let x represent Dianna’s current age?
Diannas current age is what your being asked to find
Diannas age is the unknown in the problem
The given relatioships can be written in terms of diannas current age
Solve the system shown.
Do 1.5 cm, 3 cm, 1.5 cm make a triangle and what kind
The lengths 1.5 cm, 3 cm, and 1.5 cm cannot form a triangle because the sum of the lengths of the two shorter sides is equal to the length of the longest side, which does not satisfy the Triangle Inequality Theorem.
The question asks if lengths 1.5 cm, 3 cm, and 1.5 cm can form a triangle, and if so, what kind of triangle it would be. To determine whether these lengths can form a triangle, we use the Triangle Inequality Theorem, which states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.
For these lengths:
1.5 cm + 1.5 cm = 3 cm1.5 cm + 3 cm > 1.5 cm1.5 cm + 3 cm > 1.5 cmWe see that when we add the lengths of the two shorter sides (1.5 cm + 1.5 cm), it equals the length of the longest side (3 cm). According to the Triangle Inequality Theorem, the lengths do not meet the condition for forming a triangle because the sum must be greater than, not equal to, the length of the third side. Therefore, these lengths cannot form a triangle.
Anybody have a correct answer?
Answer:
100
Step-by-step explanation:
What is 5/15 written as a decimal???
What is 4/15 written as a decimal???
What is 3/15 written as a decimal???
Need quick help please?! Using the Angle Bisector Theorem solve for x.
Show all work.
Answer:
[tex]x=6[/tex]
Step-by-step explanation:
We have been given a triangle and we are asked to solve for x using angle bisector theorem.
Angle bisector theorem states that if a ray bisects an angle of a triangle, then it divides the opposite side of triangle into segments that are proportional to the other two sides.
Using angle bisector theorem we can set an equation as:
[tex]\frac{4x+1}{5}=\frac{15}{3}[/tex]
Let us solve for x by multiplying both sides of our equation by 5.
[tex]\frac{4x+1}{5}*5=\frac{15}{3}*5[/tex]
[tex]4x+1=5*5[/tex]
[tex]4x+1=25[/tex]
Let us subtract 1 form both sides of our equation.
[tex]4x+1-1=25-1[/tex]
[tex]4x=24[/tex]
Upon dividing both sides of our equation by 4 we will get,
[tex]\frac{4x}{4}=\frac{24}{4}[/tex]
[tex]x=6[/tex]
Therefore, the value of x is 6 units.
solve for x in the equation x^2+10x+12=36
Answer: The required value of x is 2 or -12.
Step-by-step explanation: We are given to solve for x in the following equation :
[tex]x^2+10x+12=36~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
We will be solving the given equation by the method of factorization.
From equation (i), we have
[tex]x^2+10x+12=36\\\\\Rightarrow x^2+10x+12-36=0\\\\\Rightarrow x^2+10x-24=0\\\\\Rightarrow x^2+12x-2x-24=0\\\\\Rightarrow x(x+12)-2(x+12)=0\\\\\Rightarrow (x-2)(x+12)=0\\\\\Rightarrow x-2=0,~~~~~~x+12=0\\\\\Rightarrow x=2,~-12.[/tex]
Thus, the required value of x is 2 or -12.
I WILL GIVE BRAINLIEST, PLS HELP-A farmer has 300 ft of fencing with which to enclose a rectangular pen next to a barn. The barn itself will be used as one of the sides of the enclosed area.
What is the maximum area that can be enclosed by the fencing?
Enter your answer in the box.
ft²
which numerical expression would provide the solutions to the equation 7x^2 + 4x - 8 = 14
The quadratic equation 7x^2 + 4x - 8 = 14 does not have any real solutions.
Explanation:The given equation is a quadratic equation of the form at² + bt + c = 0, where a = 7, b = 4, and c = -22. To find the solutions, we can use the quadratic formula:
x = (-b ± √(b² - 4ac)) / (2a)
Substituting the values, we get:
x = (-4 ± √(4² - 4(7)(-22))) / (2(7))
Simplifying further, we get:
x = (-4 ± √(16 - 616)) / 14
x = (-4 ± √(-600)) / 14
The expression inside the square root is negative, which means there are no real solutions to the equation.
Help please !!!!!!!!!!!!!!!!!???!?
Which concept can be used to prove that the diagonals of a parallelogram bisect each other?
a)congruent triangles
b)similar triangles
c)congruent rectangles
d)similar rectangles
Answer: Jiren is too strong. (congruent triangles)
Answer:
Option: A is correct (congruent triangles)
Step-by-step explanation:
To prove that he diagonals of a parallelogram bisect each other we have to go through the following steps:
Angle DBA is congruent to angle BDC. Angle CMD is congruent to angle AMB. Triangle CMD is congruent to triangle AMB. Segment AM is congruent to segment MC. M is the midpoint of segment AC. Segment BD bisects segment AC. Segment BM is congruent to segment MD. M is the midpoint of segment BD. Segment AC bisects segment BD.Hence we have to use the concept of congruent triangles in order to prove that the diagonals of a parallelogram bisect each other.
Hence, option A is correct
Cody graphed a quadratic equations, y = -(x+3)^2 + 1. What were cody's mistakes?
Answer:
the answer is d
Step-by-step explanation:
The vertex and the axis of symmetry are graphed incorrectly.
The digits 8,7,6,5,4,3,2,1 are written in a pattern over and over again. what will be the 5479th digit
The 5479th digit is 2.
What is Division?One of the fundamental mathematical operations is division, which involves breaking a bigger number into smaller groups with the same number of components.
How many groups will be created, for instance, if 30 students need to be separated into groups of five for a sporting event? The division operation can be used to quickly and easily fix such issues. In this case, we must divide 30 by 5.
given:
8 digits written in that same order ( 8,7,6,5,4,3,2,1 ) over and over again
So, we have to find 5479th digit
= 5479/8
= 684 7/8
Now, The 684 quotient tells us how many complete times the sequence goes through the cycle of 8,7,6,5,4,3,2,1, and the 7 remainder tells us which member of the cycle is the 5479 digit.
Since the 7th member of the cycle is 2.
Hence, the 5479th digit is 2.
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Please HELP NEEDED ASAP APPRECIATED !! Brainlestwill be given
In a homicide case 33 different witnesses picked the same man from a line up. the line up contained 5 men. if the identifications were made by random guesses, find the probability that all 33 witnesses would pick the same person. round to seven decimal places.
Final answer:
The probability that Nancy is a robber given Bob's identification is around 33.2%, considering Bob's accuracy and the base rate of robbers in the population.
Explanation:
Probability Calculation:
To find the probability that Nancy is a robber given Bob's identification, we use Bayes' Theorem. Given that Bob is 99% accurate in identifying suspects, the calculation reveals that the probability that Nancy is a robber is around 33.2%.
Base Rate Fallacy: It is crucial to consider the base rate of robbers in the population to avoid common statistical errors in interpreting the probability of an event.
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World’s Busiest Airports
Airport
Total Passengers (millions)
Atlanta, Hatfield
80.2
Chicago, O’Hare
72.1
Los Angeles
68.5
Dallas/Ft Worth
60.7
London, Heathrow
64.6
Find the mean number of passengers in the world’s five busiest airports.
a.
69.22 million
c.
80.2 million
b.
346.1 million
d.
60.7 million
In the diagram, AB = 12, DX = 2.5, and BX = 5. Find CD. Show all work.
helpppppppppppppppppppppppppppppppp
one face of a cube an area of 49 square centimeters. what is the volume of the cube
Force exerted by the ball on the kickers foot.
Find a second-degree polynomial p such that p(1) = 5, p'(1) = 7, and p''(1) = 10.
The given conditions suggest a second-degree polynomial of form p(x) = ax^2 + bx + c. By solving the given conditions a = 5, b = -3, and c = 3, yielding the polynomial p(x) = 5x^2 - 3x + 3.
Explanation:The question is asking for a second-degree polynomial, which can generally be written in the form p(x) = ax^2 + bx + c. Given that p(1) = 5, that means a + b + c = 5. The derivative of p(x), p'(x) = 2ax + b, and p'(1) = 7, so 2a + b = 7. The second derivative, p''(x) = 2a, and p''(1) = 10, so 2a = 10 or a = 5. We can substitute a = 5 into the first two equations to find the values of b and c. So, b = -3 and c = 3. Therefore, the original function is p(x) = 5x^2 - 3x + 3.
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Quadrilateral ABCD is inscribed in this circle. what is the measure of angle C?
Answers...........................?
A Hummingbird moves its wings at a rate of 5520 wingsbeats a minute. Write this rate in wingbeats per second?
The required rate of wingbeats per second is 92.
A Hummingbird moves its wings at a rate of 5520 wingsbeats a minute. Write this rate in wingbeats per second?
Rate of change is defined as the change in value with rest to the time is called rate of change.
given rate = 5520 wingsbeats a minute.
now to convert it in seconds divide it by 60
= 5520/60
= 92 wingsbeats a second
Thus, The required rate wingbeats per second is 92.
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What is the area of the polygon