Ratio that is equivalent to 8:20

b) you could choose :

red, black

black, red

red, red

c) p(black, red) = (6/18)(12/17) = 72/306 = 4/17

Answer:

[tex]\mathrm{Parabola\:focus\:given}\:x^2=-20y:\quad \left(0,\:-5\right)[/tex]

Step-by-step explanation:

Given the equation

[tex]x2 = -20y[/tex]

A parabola is the locus of points such that the distance to a point the focus equals the distance to a line the directrix.

[tex]4p\left(y-k\right)=\left(x-h\right)^2[/tex] is the standard equation for an up-down facing parabola with vertex at (h, k), and a focal length |p|.

so

[tex]x^2=-20y[/tex]

[tex]\mathrm{Switch\:sides}[/tex]

[tex]-20y=x^2[/tex]

[tex]\mathrm{Factor\:}4[/tex]

[tex]4\cdot \frac{-20}{4}y=x^2[/tex]

[tex]4\left(-5\right)y=x^2[/tex]

[tex]\mathrm{Rewrite\:as}[/tex]

[tex]4\left(-5\right)\left(y-0\right)=\left(x-0\right)^2[/tex]

[tex]\left(h,\:k\right)=\left(0,\:0\right),\:p=-5[/tex]

Parabola is symmetric around the y-axis and so the focus lies a distance\ p from the center (0, 0) along the y-axis.

[tex]\left(0,\:0+p\right)[/tex]

[tex]=\left(0,\:0+\left(-5\right)\right)[/tex]

[tex]\mathrm{Refine}[/tex]

[tex]\left(0,\:-5\right)[/tex]

Therefore,

[tex]\mathrm{Parabola\:focus\:given}\:x^2=-20y:\quad \left(0,\:-5\right)[/tex]

Please check the attached figure too.

The focus of the parabola given by the equation x2 = -20y is at the coordinates (0,-5). This is calculated by finding the value of 'p' in the standard form x2 = 4py.

The equation x2 = -20y is notably a form of the parabola equation known as standard form. This version of a parabola equation is defined in the form x2 = 4py (or it could be y2 = 4px), where p is the distance from the vertex to the focus (and also to the directrix).

In the given equation, x2 = -20y, comparing it with the standard form, we find 4p = -20 by observing the coefficient of 'y'. Solving for 'p', we get p = -20/4 = -5. This means the focus of the parabola is (0,-5), because for a parabola that opens downwards (since 'p' is negative), the focus is located at the coordinates (h, k-p), where 'h' and 'k' are the coordinates of the vertex (which is the origin (0,0) in this case).

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Answer:

I am pretty sure that the answer is  

y = 3x -2

Step-by-step explanation:

given a line with slope m then the slope of a line  perpendicular to it is

 where m is the slope and b the y-intercept

I hoped this helped!!!

Answer: y=3x-5

Step-by-step explanation:

Got ot right on my test!!

Answer:

B

Step-by-step explanation:

Because the height is only used once (not squared) in the cone volume formula, the volume is only multiplied by 4.

The volume of the right circular cone must be multiplied by 4.

The correct answer is option (B). 4

[tex]V=\frac{1}{3}\times \pi \times r^{2} \times h[/tex], where 'r' is the radius of circular base and 'h' is the height of the right circular cone.

For given example,

The height of the right circular cone is multiplied by 4, but its radius remains fixed.

From the formula of the volume of the right circular cone,

[tex]V\propto h[/tex]

This means,  as height of the cone increases, the volume of the cone increases at the same rate.

As the height of a right circular cone is multiplied by 4, the volume of the cone must be multiplied by factor 4.

Therefore, the correct answer is option (B). 4

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Answer:

6b - 8 = 58

6b = 66

b = 11

Each book costs $11.

Lashonda bought 11 books.

To solve this problem, we can set up an equation based on the information given. Let [tex]\( b \)[/tex] represent the number of books Lashonda bought. Each book costs $6, so the total cost before the discount is [tex]\( 6b \)[/tex]. Lashonda received a discount of $8 off of her total purchase, and she spent $58 after the discount. Therefore, the equation representing the total cost before the discount minus the discount equals the amount she spent is:

[tex]\[ 6b - 8 = 58 \][/tex]

Now, we solve for [tex]\( b \)[/tex]:

[tex]\[ 6b = 58 + 8 \][/tex]

[tex]\[ 6b = 66 \][/tex]

[tex]\[ b = \frac{66}{6} \][/tex]

[tex]\[ b = 11 \][/tex]

So, Lashonda bought 11 books.

Answer:

530.66 cm squared

Step-by-step explanation:

c = 2(3.14)r

81.64 = 2(3.14)r

Divide both sides by 6.28

The radius is 13

a = 3.14(13 squared)

a = 530.66

Answer: 530.39 cm²

Step-by-step explanation:

C=2πr, Substitute 81.64 in for C then divide 2π t get 12.99. A=πr². Plug in 12.99 for r, solve, and get 530.39 cm

Answer:

153.3

Step-by-step explanation:

154-0.7

Answer:

153.3

Step-by-step explanation:

154.0-0.7=153.3

The location of the point Q is  (4,3)

The coordinates are given as:

R'(4,4), S (4,1), P(-3, 1), and Q'(-3, 4)

The transformation rule is given as:

90 degrees counterclockwise

The above rule is represented as:

(x,y) -> (-y,x)

So, we have:

(x,y) -> (-3,4)

Solve for x and y

(x,y) = (4,3)

Hence, the location of the point Q is  (4,3)

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Answer: 187.2

Step-by-step explanation:

Answer:

187.2

Step-by-step explanation:

Answer:

1/2 gallon=2 quarts plus 3 quarts so 5 quarts then 11/4 would be 11 quarts so 11+2+3=16 quarts

Step-by-step explanation:

If the 11/4 part is confusing you on how many quarts it actually is it simply means that for every 4 quarts you get a gallon and you have 11 quarts so you can also look at it as 2 3/4 gallons if that somehow clarifies it.

Answer:

6³

Step-by-step explanation:

Answer:

6^3

Step-by-step explanation:

6*6*6

The base is 6

There are 3 sixes multiplied together so the exponent is 3

Answer:

Part A) The length of a straight line between the school and the Fire Station is [tex]4.6\ miles[/tex]

Part B) The length of a straight line between the school and the hospital is [tex]2.1\ miles[/tex]

Step-by-step explanation:

The complete question in the attached figure

Let

The positive x-coordinates ----> East

The positive y-coordinates ----> North

The negative x-coordinates ----> West

The negative y-coordinates ----> South

take the point A (0,0) as the Middle School (reference point)

Part A) we have

Town Hall is located 4.3 miles directly east of the Middle School

so

The coordinates of Town Hall are B(4.3,0)

The Fire Station is located 1.7 miles directly North of Town Hall

so

The coordinates of Fire Station are C(4.3,1.7)

What is the length of a straight line between the school and the Fire Station?

Remember that

the formula to calculate the distance between two points is equal to

[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]

we have

A(0,0) and C(4.3,1.7)

substitute

[tex]d=\sqrt{(1.7-0)^{2}+(4.3-0)^{2}}[/tex]

[tex]d=\sqrt{(1.7)^{2}+(4.3)^{2}}[/tex]

[tex]d=4.6\ miles[/tex]

Part B) we have that

The hospital is 3.1 miles west of the fire station

so

The coordinates of the hospital are D(4.3-3.1,1.7)

D(1.2,1.7)

What is the length of a straight line between the school and the hospital?

Remember that

the formula to calculate the distance between two points is equal to

[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]

we have

A(0,0) and D(1.2,1.7)

substitute

[tex]d=\sqrt{(1.7-0)^{2}+(1.2-0)^{2}}[/tex]

[tex]d=\sqrt{(1.7)^{2}+(1.2)^{2}}[/tex]

[tex]d=2.1\ miles[/tex]

Answer:

it would be can D

Step-by-step explanation:

Can C have greater volume.

The amount of space inside a cylinder is its volume. You can find it by dividing the base area by the height. V =πr²h, is the formula for the volume of a cylinder with base radius r and height h.

Given:

a) Volume of Cylinder = πr²h

                                    = 3.14 x 2 x 2 x 6

                                    = 75.36 cube inches.

b) Volume of Cylinder = πr²h

                                    = 3.14 x 2.5 x 2.5 x 5

                                    = 98.125 cube inches.

c) Volume of Cylinder = πr²h

                                    = 3.14 x 3 x 3 x 4

                                    = 113.04 cube inches.

d) Volume of Cylinder = πr²h

                                    = 3.14 x 3.2 x 3.2 x 3

                                    = 94.4608 cube inches.

Hence, can C have greater volume.

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Answer: -2.25

Step-by-step explanation:

-2 4/9 or -2.25

Convert this to decimal

-2 4/9

4/9=0.4444

Add to the 2

-2.4444

-2.444 or -2.25

In negative rule,the lower the value,the greater the number

Therefore,

-2.25 is greater than -2.444

Answer:

the area would be 7x7x7= 343 would be the answer length times width times height

please please please mark brainliest

Step-by-step explanation:

Answer:

49 square feet

Step-by-step explanation:

length, l = 7 feet

Area of the square, A = l^2

Slot in the value of l

= 7^2

= 49 square feet

Answer:

5/4k^2

Step-by-step explanation:

P=5\dfrac{k}{6}\times \dfrac{3}{2k^3}.

We will be using the following property of exponents:

\dfrac{a^x}{a^y}=a^{x-y}.

We have

P\\\\\\=5\dfrac{k}{6}\times\dfrac{3}{2k^3}\\\\\\=\dfrac{5}{6}\times\dfrac{3}{2}k^{1-3}\\\\\\=\dfrac{5}{4}k^{-2}=\dfrac{5}{4k^2}.

Thus, the required product is \dfrac{5}{4k^2}.

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Answer: 5/4k^2

Step-by-step explanation:

Just multiply the fractions then simplify by a common factor of 3, then cancel out the common variable of k

Answer:

The area surrounding the parallelogram can be found by subtracting 63 from 128

Step-by-step explanation:

Parallelograms can be said to be shapes which has four sides including two pairs of sides that are parallel and the four shapes are square, rectangle, rhombus, and rhomboid. Although rhombus is said to look exactly like a slanted square, while rhomboid is said to looks like a slanted rectangle.

Therefore when solving the problem she should apply the area surrounding the parallelogram which can be found by subtracting 63 from 128 since

She needs to find the area of the fabric surrounding the parallelogram pattern.

Answer:

B, C, E

Step-by-step explanation:

On e2020

B-The area of the parallelogram is (9) (7) = 63.

C-The total area of the block is 128 square inches.

E-The area surrounding the parallelogram can be found by subtracting 63 from 128.  

Answer:

   x = 2/5 = 0.400

Step-by-step explanation:

Step  1  :

           1

Simplify   —

           4

Equation at the end of step  1  :

  5         1

 (— • x) -  —  = 0  

  8         4

Step  2  :

           5

Simplify   —

           8

Equation at the end of step  2  :

  5         1

 (— • x) -  —  = 0  

  8         4

Step  3  :

Calculating the Least Common Multiple :

3.1    Find the Least Common Multiple

     The left denominator is :       8  

     The right denominator is :       4  

       Number of times each prime factor

       appears in the factorization of:

Prime  

Factor   Left  

Denominator   Right  

Denominator   L.C.M = Max  

{Left,Right}  

2 3 2 3

Product of all  

Prime Factors  8 4 8

     Least Common Multiple:

     8  

Calculating Multipliers :

3.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 1

  Right_M = L.C.M / R_Deno = 2

Making Equivalent Fractions :

3.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      5x

  ——————————————————  =   ——

        L.C.M             8  

  R. Mult. • R. Num.      2

  ——————————————————  =   —

        L.C.M             8

Adding fractions that have a common denominator :

3.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

5x - (2)     5x - 2

————————  =  ——————

   8           8    

Equation at the end of step  3  :

 5x - 2

 ——————  = 0  

   8    

Step  4  :

When a fraction equals zero :

4.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 5x-2

 ———— • 8 = 0 • 8

  8  

Now, on the left hand side, the  8  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  5x-2  = 0

Solving a Single Variable Equation :

4.2      Solve  :    5x-2 = 0  

Add  2  to both sides of the equation :  

                     5x = 2

Divide both sides of the equation by 5:

                    x = 2/5 = 0.400

One solution was found :

                  x = 2/5 = 0.400

Answer:

(2x + 7)(2x + 7)

Step-by-step explanation:

[tex]4 {x}^{2} + 28x + 49 \\ = 4 {x}^{2} + 14x + 14x + 49 \\ = 2x(2x + 7) + 7(2x + 7) \\ = (2x + 7)(2x + 7)[/tex]

Answer:

3) (2x+7)(2x+7)

Step-by-step explanation:

FOIL (first, outer, inner, last) it back out, you get 4x^2 + 14x + 14x + 49 which simplifies to the original.

Answer:

C) 35

Step-by-step explanation:

[tex]^7C_3 \\ = \frac{7!}{3!(7 - 3)!} \\= \frac{7!}{3! \: 4!} \\ = \frac{7 \times 6 \times 5 \times 4!}{3 \times 2 \times 1 \times 4!} \\ = \frac{7 \times 6 \times 5 \times 4!}{3 \times 2 \times 1 \times 4!} \\ = 35 \\ \huge \red{ \boxed{ \therefore \: ^7C_3 = 35}}[/tex]

Answer:

C=35

Step-by-step explanation:

⁷C₃

These is combination

using the rule it states that

ⁿCₐ= n!/(n-a)!a!

so therefore ⁷C₃= 7!/(7-3)!3! = 7!/4!3!=7x6x5x4x3x2x1/{(4x3x2x1)x(3x2x1)}

4x3x2x1 cancels itself as it appears up and down

7x6x5/6

6 cancels each itself as it appears up and down

7x5 = 35

Answer:

- time = 1second

- maximum height = 16m

Step-by-step explanation:

Given the height of a pumpkin t seconds after it is launched from a catapult modelled by the equation

f(t)=-16t²+32t... (1)

The pumpkin reaches its maximum height when the velocity is zero.

Velocity = {d(f(x)}/dt = -32t+32

Since v = 0m/s (at maximum height)

-32t+32 = 0

-32t = -32

t = -32/-32

t = 1sec

The pumpkin reaches its maximum height after 1second.

Maximum height of the pumpkin is gotten by substituting t = 1sec into equation (1)

f(1) = -16(1)²+32(1)

f(1) = -16+32

f(1) = 16m

The maximum height of the pumpkin is 16m

Answer:

SA = 251.33 yd ^2

V = 301.59 yd ^3

Step-by-step explanation:

Right cylinder   2π  = 6.28318530718

Solve for surface area

A =2πrh+2πr2  = 24 x 2π + 2π x 16

A =150.796447372 + 100.530964915

A ≈251.33 yd^2

Right cylinder π = 3.14159265359

Solve for volume

V = πr2h = 16 x 6 = 96π

V = 3.14159265359 x 96

V = 301.592894745

V= 301.59 yd ^3

Hi!

Answer: 200

The 2 triangles surface area add up to 120

the rectangle on the bottom is 30

The rectangle in the back is 16

And the rectangle on top is 34

So 120+30+16+34 = 200

Hope this is correct and helps!

Answer:

50 ft.

Step-by-step explanation:

It is given that the ratio of width-to-length is 2 : 5.

Let,

Width = 2x ft

Length = 5x ft

Perimeter of the rectangle is

[tex]Perimeter=2(lenght+width)[/tex]

[tex]Perimeter=2(5x+2x)[/tex]

[tex]Perimeter=2(7x)[/tex]

[tex]Perimeter=14x[/tex]

It is given that the perimeter of the rectangle is 140 ft.

[tex]14x=140[/tex]

Divide both sides by 14.

[tex]x=10[/tex]

The value of x is 10.

[tex]Length=5x=5\times 10=50[/tex]

Therefore, the length of the rectangle is 50 ft.