Answer:
Packets
Explanation:
Assume Flash Sort is being used on a array of integers with Amin = 51, Amax = 71, N=10, m=5 Items are classified according to the formula: K(A[i]) = 1 + (int) ( (m-1) * (A[i] - Amin) / (Amax - Amin) ) What is the classification for 63?
Answer:
3
Explanation:
= 1 + (int) (4*(63 - 51)/(71-51)))
= 1 + (int) (4*12/20)
= 1 + (int) (48/20)
= 1 + (int)2.4
= 1 + 2
= 3
Each week, the Pickering Trucking Company randomly selects one of its 30 employees to take a drug test. Write an application that determines which employee will be selected each week for the next 52 weeks. Use the Math. random() function explained in Appendix D to generate an employee number between 1 and 30; you use a statement similar to: testedEmployee = 1 + (int) (Math.random() * 30); After each selection, display the number of the employee to test. Display four employee numbers on each line. It is important to note that if testing is random, some employees will be tested multiple times, and others might never be tested. Run the application several times until you are confident that the selection is random.
Answer:
Following are the program to this question:
import java.util.*; //import package
public class Main //defining class
{
public static void main(String[] args) //defining main method
{
int testedEmployee; //defining integer variable
for(int i = 1;i<=52;i++) //defining loop that counts from 1 to 52
{
testedEmployee = 1 + (int) (Math.random() * 30); //using random method that calculate and hold value
System.out.print(testedEmployee+"\t"); //print value
if(i%4 == 0)//defining codition thats checks value is divisiable by 4
{
System.out.println(); //print space
}
}
}
}
Output:
please find the attachment.
Explanation:
In the given java program, a class Main is declared, inside the class, the main method is declared, in which an integer variable "testedEmployee", is declared, in the next line, the loop is declared, that can be described as follows:
Inside the loop, a variable "i" is declared, which starts from 1 and stop when its value is 52, inside the loop a random method is used, that calculates the random number and prints its value. In the next step, a condition is defined, that check value is divisible 4 if this condition is true, it will print a single space.Write a script that creates and calls a stored procedure named test. This procedure should use a transaction that includes the statements necessary to combine two customers. These statements should do the following: Select a row from the Customers table for the customer with a customer_id value of 6. This statement should lock the row so other transactions can’t read or modify it until the transaction commits, and it should fail immediately if the row is locked from another session. Update the Orders table so any orders for the selected customer are assigned to the customer with a customer_id value of 3. Update the Addresses table so any addresses for the selected customer are assigned to the customer with a customer_id value of 3. Delete the selected customer from the Customers table. If these statements execute successfully, commit the changes. Otherwise, rollback the changes.
Answer:
Check the explanation
Explanation:
use `my_guitar_shop`;
#delete the procedure test if it exists.
DROP PROCEDURE IF EXISTS test;
DELIMITER //
CREATE PROCEDURE test ()
BEGIN
#declare variable sqlerr to store if there is an sql exception
declare sqlerr tinyint default false;
#declare variable handler to flag when duplicate value is inserted
declare continue handler for 1062 set sqlerr = TRUE;
#start transaction
start transaction;
delete from order_items where order_id in
(select order_id from orders where customer_id=6);
delete from orders where customer_id=6;
delete from addresses where customer_id=6;
delete from customers where customer_id=6;
if sqlerr=FALSE then
commit;
select 'Transaction Committed' as msg;
else
rollback;
select 'Transaction rollbacked' as msg;
end if;
end //
delimiter ;
call test();
5.6 Look carefully at how messages and mailboxes are represented in the email system that you use. Model the object classes that might be used in the system implementation to represent a mailbox and an email message
Answer:
See explaination for the details of the answer.
Explanation:
A class is a structured diagram that describes the structure of the system.
It consists of class name, attributes, methods and responsibilities.
A mailbox and an email message has some certain attributes such as, compose, reply, draft, inbox, etc.
See attachment for the Model object classes that might be used in the system implementation to represent a mailbox and an email message.
You wish to lift a 12,000 lb stone by a vertical distance of 15 ft. Unfortunately, you can only generate a maximum pushing force of 2,000 lb.
a. What is the amount of work you must input in order to move the stone?
b. What is the actual mechanical advantage (AMA) required by a machine to complete the work above?
c. You build a ramp to create the ideal mechanical advantage. What is the length of the ramp in feet?
Answer:
The answer is "180,000, 6, and 90"
Explanation:
The answer to this question can be described as follows:
[tex]\ force = 12,000 \ lb \\\\\ distance = 15 \ ft \\\\ \ Formula : \\\\ \ total \ work = force \times distance \\\\ \ IMA = \frac{load}{effort} \\\\\ OR \\\\ \ IMA = \frac{\ distance \ move \ by \ load }{\ distance \ moved \ by \ efforts}[/tex]
[tex]a ) \\\\\ total \ work = 12,000 \times 15 \\\\\ total \ work = 180,000 ft \cdot lbf[/tex]
[tex]b) \\\\IMA = \frac{12000}{2000} = 6 \\\\ c) \\\\IMA = \frac{Y}{15} \\\\6= \frac{Y}{15}\\\\Y= 90\\\\X = \sqrt{8100-225}\\\\X = \sqrt{90^2-15^2} \\\\X= \sqrt{7875} \\\\X =88.74 ft\\\\[/tex]
by comparing the length of the ramp is 90 ft.
Explain the term duty cycle and determine the pulse duration of a periodic pulse train whose duty cycle is 15% and frequency is 13.3Mhz. Interprete your results.
Answer:
Duty cycle of a signal measures the fraction of a time of a given transmitter is transmitting that signal. This fraction of a time determines the overall or total power transmitted or delivered by that signal.
More power is possessed by duty cycles with longer signals. This gives the signal the following characteristics such as reliability, strength and easy detection and thus require less efficient receivers.Less power is associated with duty cycles of shorter signals. This gives the signal the following characteristics such as less reliability, lower strength and not easily detected and thus require more efficient receivers.Duty cycle = 15 %
frequency = 13.3Mhz = 13.3 x 10^3 hz = I/T = F
T = period = 1 / F = 1/13.3 x 10^3 hz= 7.5188 x 10 ^-5 s
Duty cycle = pulse duration/ period
15 % = PD/7.5188 x 10 ^-5 s
PD = 15/100 X 7.5188 x 10 ^-5 s = 1.12782 x 10^ -5 s
INTERPRETATION OF RESULTS
With a duty of 15 % and pulse duration of 1.12782 x 10^ -5 s, the strength is low , short signal and less reliable and needs more efficient receiver
Explanation:
Duty cycle of a signal measures the fraction of a time of a given transmitter is transmitting that signal. This fraction of a time determines the overall or total power transmitted or delivered by that signal.
More power is possessed by duty cycles with longer signals. This gives the signal the following characteristics such as reliability, strength and easy detection and thus require less efficient receivers.Less power is associated with duty cycles of shorter signals. This gives the signal the following characteristics such as less reliability, lower strength and not easily detected and thus require more efficient receivers.Duty cycle = 15 %
frequency = 13.3Mhz = 13.3 x 10^3 hz = I/T = F
T = period = 1 / F = 1/13.3 x 10^3 hz= 7.5188 x 10 ^-5 s
Duty cycle = pulse duration/ period
15 % = PD/7.5188 x 10 ^-5 s
PD = 15/100 X 7.5188 x 10 ^-5 s = 1.12782 x 10^ -5 s
INTERPRETATION OF RESULTS
With a duty of 15 % and pulse duration of 1.12782 x 10^ -5 s, the strength is low , short signal and less reliable and needs more efficient receiver
About n processes are time-sharing the CPU, each requiring T ms of CPU time to complete. The context switching overhead is S ms. (a) What should be the quantum size Q such that the gap between the end of one quantum and the start of the next quantum of any process does not exceed M ms? (b) For n = 5, S = 10, and M = 450, M = 90, M = 50, determine: The corresponding values of Q The percentage of CPU time wasted on context switching
Answer:
(a) Q = (M-(1-n)S)/n
(b)
When M = 450,
Q = 82
% CPU time wasted = 8.889%
When M = 90,
Q = 10
% CPU time wasted = 44.44%
When M = 50,
Q = 2
% CPU time wasted = 80%
Explanation:
Given Data:
n = process
T = ms time
Context switch time overhead = S
and M is total overhead
See attached file for the calculation.
Final answer:
To determine the appropriate quantum size Q in a CPU time-sharing system with n processes and context-switching overhead S, one must calculate Q in relation to the maximum allowed gap M between quanta. This will enable scheduling that satisfies the gap constraint and maximizes CPU efficiency. The waste percentage of CPU time due to context switching can then be calculated.
Explanation:
The question involves calculating the appropriate quantum size for CPU time-sharing and the related context switching overhead. Given are the number of processes (n), context switching overhead (S), and the maximum allowed gap (M) between quanta. The quantum size (Q) must be chosen to ensure that a process resumes its next quantum within the specified maximum allowed gap after its last quantum ends, considering the context switching overhead.
For part (a), a general formula must be determined that takes into account S and M to calculate Q. For part (b), the formula will be applied with fixed values of n = 5, S = 10 ms, and varying values for M. Having M = 450, 90, 50 ms, the respective Qs will be calculated. Then, the percentage of CPU time wasted on context switching will be determined using the formula:
Percent CPU time wasted = (
( n * S ) / ( n * ( Q + S ) )
) * 100%
Lastly, the results will highlight how the quantum size influences the efficiency of the system by reducing the relative amount of time spent on context switching.
Write your own unique Python program that has a runtime error. Do not copy the program from your textbook or the Internet. Provide the following.
The code of your program.
Output demonstrating the runtime error, including the error message.
An explanation of the error message.
An explanation of how to fix the error.
Answer:
myVariable = 3 print(myvariable)Runtime error:
NameError: name 'myvariable' is not defined
Explanation:
Runtime error is an error detected when running a program. In the given code example, there is a variable, myVariable initialized with 3 (Line 1). In the second line, we try to print the variable. But instead of placing myVariable in the print function, we put myvariable which is a different variable name (even though the difference is only with one lowercase letter). The Python will capture it as a runtime error as the variable name cannot be defined.
To fix the error, we just need to change the variable name in print statement to myVariable
myVariable = 3 print(myVariable)The runtime error inside a program is the one that happens when the program is being executed after it has been successfully compiled. It's also known as "bugs," which are frequently discovered during the debugging phase first before the software is released.
Code:
Demonstrating the output with a runtime error, including the error message.
a= input("input any value: ")#defining a variable that input value
b= int(input("Enter any number value: "))#defining b variable that input value
s=a+b#defining s variable that adds the inputs value
print(s)#print added value
In the above-given code, when "s" variable "adds" the input values it will give an error message, and to solve these errors we must convert the b variable value into the string, since "a" is a string type variable.
Correction in code:
#Code 1 for demonstrating the output with runtime error, including the error message.
a= input("input any value: ")#defining a variable that input value
b= int(input("Enter any number value: "))#defining b variable that input value
b=str(b)#defining b variable that converts input value into string and hold its value
s=a+b#defining s variable that adds the inputs value
print(s)#print added value
Output:
Please find the attached file.
Learn more:
brainly.com/question/21296934
1. Write a telephone lookup program. Read a data set of 1, 000 names and telephone numbers from a file that contains the numbers in random order. Handle lookups by name and also reverse lookups by phone number. Use a binary search for both lookups.
Answer:
Kindly note that, you're to replace "at" with shift 2 as the brainly text editor can't take the symbol
Explanation:
PhoneLookup.java
import java.io.FileReader;
import java.io.IOException;
import java.util.Scanner;
public class PhoneLookup
{
public static void main(String[] args) throws IOException
{
Scanner in = new Scanner(System.in);
System.out.println("Enter the name of the phonebook file: ");
String fileName = in.nextLine();
LookupTable table = new LookupTable();
FileReader reader = new FileReader(fileName);
table.read(new Scanner(reader));
boolean more = true;
while (more)
{
System.out.println("Lookup N)ame, P)hone number, Q)uit?");
String cmd = in.nextLine();
if (cmd.equalsIgnoreCase("Q"))
more = false;
else if (cmd.equalsIgnoreCase("N"))
{
System.out.println("Enter name:");
String n = in.nextLine();
System.out.println("Phone number: " + table.lookup(n));
}
else if (cmd.equalsIgnoreCase("P"))
{
System.out.println("Enter phone number:");
String n = in.nextLine();
System.out.println("Name: " + table.reverseLookup(n));
}
}
}
}
LookupTable.java
import java.util.ArrayList;
import java.util.Collections;
import java.util.Scanner;
/**
A table for lookups and reverse lookups
*/
public class LookupTable
{
private ArrayList<Item> people;
/**
Constructs a LookupTable object.
*/
public LookupTable()
{
people = new ArrayList<Item>();
}
/**
Reads key/value pairs.
"at"param in the scanner for reading the input
*/
public void read(Scanner in)
{
while(in.hasNext()){
String name = in.nextLine();
String number = in.nextLine();
people.add(new Item(name, number));
}
}
/**
Looks up an item in the table.
"at"param k the key to find
"at"return the value with the given key, or null if no
such item was found.
*/
public String lookup(String k)
{
String output = null;
for(Item item: people){
if(k.equals(item.getName())){
output = item.getNumber();
}
}
return output;
}
/**
Looks up an item in the table.
"at"param v the value to find
"at"return the key with the given value, or null if no
such item was found.
*/
public String reverseLookup(String v)
{
String output = null;
for(Item item: people){
if(v.equals(item.getNumber())){
output = item.getName();
}
}
return output;
}
}
Item.java
public class Item {
private String name, number;
public Item(String aName, String aNumber){
name = aName;
number = aNumber;
}
public String getName(){
return name;
}
public String getNumber(){
return number;
}
}
input.txt
Abbott, Amy
408-924-1669
Abeyta, Ric
408-924-2185
Abrams, Arthur
408-924-6120
Abriam-Yago, Kathy
408-924-3159
Accardo, Dan
408-924-2236
Acevedo, Elvira
408-924-5200
Acevedo, Gloria
408-924-6556
Achtenhagen, Stephen
408-924-3522
Kindly check the attached output image below.
A router receives a packet and determines the outbound link for the packet. When the packet arrives, 2/3 of one other packet is done being transmitted on this outbound link and five other packets are waiting to be transmitted. Packets are transmitted in order of arrival. Suppose all packets are 3,000 bytes, and the link rate is 4 Mbps. What is the queuing delay for the packet
Answer:
Queuing Delay is 0.08 seconds
Explanation:
The answer follows a formula that is relatively easy to use and is detailed below.
Queuing Delay = [(L - x) + (nL)] / R
where,
L is packet length given as 3,000 bytes
x is the currently transmitted packet given as 2/3 * 3,000 = 2,000
n is the number of packets waiting in the Que given as 5
R is the rate of transmission given as 4 Mbps (4 * 10^6 Bps)
We can simply plug in the above information in the equation for computing Queuing Delay.
Lets take the numerator first which would be [(3000 - 2000) + (5 * 3000)]
The numerator would be 16000 bytes. These are being transmitted at 4Mbps. So, 16000*4*5 = 320,000 "bits"
Queuing Delay= 320,000/4000000
Queuing Delay = 0.08 seconds.
As we can see, the formula is quite intuitive to use. You are simply taking the number of packets to be transmitting, incorporating the partially transmitted packet, multiplying by the number of packets and the rate of transmission and then dividing the product by the rate of transmission to compute what the delay in the Que is.
Challenge: Tic-Tac-Toe (Report a problem) Detecting mouse clicks For this step of the challenge you will complete Tile's handleMouseClick method. The handleMouseClick method has two parameters: x and y which represent the coordinates of where the user clicked the mouse. When a user clicks inside a tile, that tile's handleMouseClick method should call that tile's onClick method. To check if the mouse click is inside of the tile, you will need an if statement that checks if: - the mouse click is on, or right of, the left edge of the tile - the mouse click is on, or left of, the right edge of the tile - the mouse click is on, or below, the upper edge of the tile - the mouse click is on, or above, the lower edge of the tile
To detect a mouse click within a tile in a Tic-Tac-Toe game, one must implement a conditional statement in the handleMouseClick method that checks if the click's coordinates fall within the tile's bounds. If the click is valid, the tile's onClick method is called.
Explanation:The student's question concerns a programming task involving the development of a Tic-Tac-Toe game and specifically addresses the implementation of a method to detect mouse clicks within a tile. To accomplish this, the handleMouseClick method needs an if statement to check whether the click occurred within the boundaries of the tile. The if statement must compare the x and y coordinates of the mouse click against the left, right, upper, and lower edges of the tile.
To implement this, the conditional check might look like this:
if (x >= tileLeftEdge && x <= tileRightEdge && y >= tileTopEdge && y <= tileBottomEdge) {This code snippet checks that the mouse click's x coordinate is within the horizontal bounds of the tile and the y coordinate is within the vertical bounds. If both conditions are satisfied, it then calls the onClick method associated with the tile, indicating a valid click.
Expressions Write a console program that prompts the user for 3 double precision floating point values input1, input2, input3. Have the program compute and display the following values. the sum of input1, input2, input3 the average of input1, input2, input3 the log2 of input1 To access the built-in function log2 -- log2(X) computes the base 2 logarithm of X, you need to include the header at the top of your code.
Answer:
See Explaination
Explanation:
#include <iostream>
#include <cmath>
using namespace std;
int main()
{
float input1, input2, input3;
float sum=0.0, avg, l;
cout<<"enter the value for input1: ";
cin>>input1;
cout<<"enter the value for input2: ";
cin>>input2;
cout<<"enter the value for input3: ";
cin>>input3;
sum=input1+input2+input3;
cout<<"sum of three numbers: "<<sum<<endl;
avg=sum/3;
cout<<"average of three numbers: "<<avg<<endl;
l=log2(input1);
cout<<"log2 value of input1 number: "<<l;
return 0;
}
output:
enter the value for input1: 4
enter the value for input2: 5
enter the value for input3: 6
sum of three numbers: 15
average of three numbers: 5
log2 value of input1 number: 2
A binary search algorithm is written (as in the modules, for example) which searches a pre-sorted array for some user-defined value, clientData. If clientData is stored in the array, it returns its array position, and if not found, it returns -1 (again, just like in the modules). Assume the array to be searched has 100 data elements in it. (Check all that apply):[NOTE: due to common off-by-one interpretations when counting such things, if your predicted answer is within one (+1 or -1) of a posted option below, you can assume your prediction and the choice you are looking at are equivalent and check that option.]A. It might return to the client with an answer after only one comparison of data.B. It may require as many as 99 comparisons of data before it returns.C. It will always return with an answer in 7 or fewer comparisons of data.D. It will always return with an answer in 3 or fewer comparisons of data.
Answer:
c) it will always return with an answer of 7 or fewer comparisons of data.
Explanation:
As maximum number of comparison in worst case for sorted binary search is log₂n, here n = 100, so maximum search is at least 6.6 which is approximately 7.
Lab Assignment 7A For the lab this week, you will sort an array - using any of the sort methods discussed in Chapter 23 or the Selection sort. It's your choice. Use the following criteria for your assignment: Write a program that uses a two-dimensional array to store daily minutes walked and carb intake for a week. Prompt the user for 7 days of minutes walked and carb intake; store in the array. Write a sort ( your choice which sort ) to report out the sorted minute values -lowest to highest. Write another to report out the sorted carb intake - highest to lowest. These methods MUST be your original code. Your program should output all the values in the array and then output the 2 sorted outputs. You must use an array to receive credit for this assignment
Answer:
See explaination
Explanation:
import java.util.Scanner;
public class sort {
static void lowestToHighest(float arr[][])
{
float temp;
for(int i=0;i<11;i++)
for(int j=0;j<12-i-1;j++) //Using bubble sort to sort
{
if(arr[j][0]>arr[j+1][0])
{
temp = arr[j][0];
arr[j][0] = arr[j+1][0];
arr[j+1][0] = temp;
}
}
for(int i=0;i<11;i++) //Using bubble sort to sort
{
for(int j=0;j<12-i-1;j++)
if(arr[j][1]>arr[j+1][1])
{
temp = arr[j][1];
arr[j][1] = arr[j+1][1];
arr[j+1][1] = temp;
}
}
System.out.println("Data in the array after sorting lowest to highest: ");
for(int i=0;i<12;i++)
System.out.printf(arr[i][0]+" "+arr[i][1]+"\n");
}
static void highestToLowest(float arr[][])
{
float temp;
for(int i=0;i<11;i++)
for(int j=0;j<12-i-1;j++) //Using bubble sort to sort
{
if(arr[j][0]<arr[j+1][0])
{
temp = arr[j][0];
arr[j][0] = arr[j+1][0];
arr[j+1][0] = temp;
}
}
for(int i=0;i<11;i++) //Using bubble sort to sort
{
for(int j=0;j<12-i-1;j++)
if(arr[j][1]<arr[j+1][1])
{
temp = arr[j][1];
arr[j][1] = arr[j+1][1];
arr[j+1][1] = temp;
}
}
System.out.println("Data in the array after sorting highest to lowest: ");
for(int i=0;i<12;i++)
System.out.printf(arr[i][0]+" "+arr[i][1]+"\n");
}
public static void main(String[] args){
float temperature[][]=new float[12][2];
Scanner input = new Scanner(System.in);
System.out.println("Enter 12 months of highest and lowest temperatures for each month of the year: ");
for(int i=0;i<12;i++)
for(int j=0;j<2;j++)
temperature[i][j]=input.nextFloat();
System.out.println("Data in the array: ");
for(int i=0;i<12;i++)
System.out.printf(temperature[i][0]+" "+temperature[i][1]+"\n");
lowestToHighest(temperature);
highestToLowest(temperature);
}
}
A certain application runs in 30 minutes on a single processor PXY system. A close analysis reveals that 6 minutes of execution is due to inherently sequential code, while the code for the remaining 24 minutes is fully parallelizable. We consider upgrading our system to a multi-core PXY system so as to make the running time at most 10 minutes. What is the minimum number of cores that we should use
Answer:
minimum number of cores required = 6
Explanation:
Time take by parallelizable code = 24 mins
Reduced time of parallelizable code = 4 mins
Speed gained = 24/4 = 6 times
Therefore minimum number of cores required = 6
Coach Kyle has some top athletes who have the potential to qualify for Olympics. They have been training very had for the 5000 and 10000 meters running competition. The coach has been recording their timings for each 1000 meters. In the practice sessions, each athlete runs a distance in multiples of 1000 meters and the coach records their time for every 1000 meters. Put the following in a text file called timings.txt. This is not a Python program. Just open up a text editor and copy the following to a file. Alice,3:15,2:45,3:30,2:27,3:42 Bob, 2:25,3:15,3:20,2:57,2:42,3:27 Charlie, 2:45,3:25,3:50,2:27,2:52,3:12 David,2:15,3:35,3:10,2:47 Write a main function that calls read_data, determines the min and max, calls get_average, and prints as below. a) Function read_data will read the file and returns a dictionary with the athlete information. b) Function get_average will accept a list of times and return the average time in the format min:sec. c) Use the split function to split the timings into individual elements of a list. d) Be sure to handle exceptions for files and incorrect data. Athlete Min Alice 2:27 Bob 2:25 Charlie 2:27 David 2:15 Max 3:42 3:27 3:50 3:35 Average 3:07 3:01 3:05 2:56
Answer:
Check the explanation
Explanation:
Coach Kyle is havaing the following data.
Alice 3:15, 2:45, 3:30, 2:27, 3:42
Bob 2:25, 3:15, 3:20, 2:57, 2:42, 3:27
Charlie 2:45, 3:25, 3:50, 2:27, 2:52, 3:12
David 2:15, 3:35, 3:10, 2:47
let us name it as Athlete. txt
now
1. Use a function to read the data from the file.
To read a file, we can use different methods.
file.read( )
If you want to return a string containing all characters in the file, you can
use file. read().
file = open('Athlete. txt', 'r')
print file. read()
Output:
Alice 3:15, 2:45, 3:30, 2:27, 3:42
Bob 2:25, 3:15, 3:20, 2:57, 2:42, 3:27
Charlie 2:45, 3:25, 3:50, 2:27, 2:52, 3:12
David 2:15, 3:35, 3:10, 2:47
We can also specify how many characters the string should return, by using
file.read(n), where "n" determines number of characters.
This reads the first 5 characters of data and returns it as a string.
file = open('Athlete .txt', 'r')
print file.read(5)
Output:
alice
file. readline( )
The readline() function will read from a file line by line (rather than pulling
the entire file in at once).
Use readline() when you want to get the first line of the file, subsequent calls
to readline() will return successive lines.
Basically, it will read a single line from the file and return a string
containing characters up to .
file = open('athlete .txt', 'r')
print file. readline():
2.Implement the logic using Dictionary, List, and String:
One way to create a dictionary is to start with the empty dictionary and add key-value pairs. The empty dictionary is denoted with a pair of curly braces, {}:
Dictionary operations:
The del statement removes a key-value pair from a dictionary. For example, the following dictionary contains the names of various fruits and the number of each fruit in stock:
>>> inventory = {'apples': 430, 'bananas': 312, 'oranges': 525, 'pears': 217}
>>> print(inventory)
{'oranges': 525, 'apples': 430, 'pears': 217, 'bananas': 312}
If someone buys all of the pears, we can remove the entry from the dictionary:
>>> del inventory['pears']
>>> print(inventory)
{'oranges': 525, 'apples': 430, 'bananas': 312}
Or if we’re expecting more pears soon, we might just change the value associated with pears:
>>> inventory['pears'] = 0
>>> print(inventory)
{'oranges': 525, 'apples': 430, 'pears': 0, 'bananas': 312}
The len function also works on dictionaries; it returns the number of key-value pairs:
>>> len(inventory)
4
The in operator returns True if the key appears in the dictionary and False otherwise:
>>> 'pears' in inventory
True
>>> 'blueberries' in inventory
False
This operator can be very useful, since looking up a non-existant key in a dictionary causes a runtime error:
>>> inventory['blueberries']
Traceback (most recent call last):
File "", line 1, in <module>
KeyError: 'blueberries'
>>>
3. Use maketrans and translate functions to replace commas with spaces
text = text. translate(string. maketrans("",""), string. punctuation)
4. Use split function to split the timings into individual elements of a list
>>> Athlete. split(",")
split reverses by splitting a string into a multi-element list. Note that the delimiter (“,”) is stripped out completely; it does not appear in any of the elements of the returned list.
5. Perform necessary calculations to display min, max, and avg timings of each athlete
_min = None
_max = None
_sum = 0
_len = 0
with open('Athlete .txt') as ff:
for line in ff:
val = int(line. strip())
if _min is None or val < _min:
_min = val
if _max is None or val > _max:
_max = val
_sum += val
_len += 1
_avg = float(_sum) / _len
# Print output
print("Min: %s" % _min)
print("Max: %s" % _max)
print("Avg: %s" % _avg)
for index, row in enumerate(rows):
print "In row %s, Avg = %s, Min = %s" % (index, Avg(row), min(row))
for index, column in enumerate(columns):
print "In column %s, Avg = %s, Min = %s" % (index, Avg(column), min(column))
In class Assignment Setup of Production FacilityJobs Description Duration/ Weeks Predecessors1 Design production tooling 4 - 2 Prepare manufacturing drawings 6 - 3 Prepare production facility 10 - 4 Procure tooling 12 1 5 Procure production parts 10 2 6 Kit parts 2 3,4,5 7 Install tools 4 3,4 8 Testing 2 6,7 1. Draw the network diagram2. What is the critical path
Answer:
See explaination
Explanation:
Critical path method (CPM) is a step-by-step process by which critical and non-critical tasks are defined so that time-frame problems and process bottlenecks are prevented.
please see attachment for the step by step solution of the given problem.
One author states that Web-based software is more likely to take advantage of social networking (Web 2.0) approaches such as wikis and blogs. If this is the case, can we expect more social networking capabilities in all future software? Aside from LinkedIn, how can social media be leveraged by CIT graduates?
Answer:
Yes
Explanation:
I will say Yes. There are very much limitless possible and future we can expect from social media and even more from social networking. Its capabilities from upcoming software in the future. Since the Internet is in its early days of growing and cloud computing being introduced there are way more possibilities in the future.
Social media can be duely applied by CIT (Computer Information Technologies) graduates. It can be used to improve them in their career and also will helps them connect professionally. Quora is one such platform which is not exactly like LinkedIn but pretty much serves the purpose.
Which field in a Transmission Control Protocol header provides the next expected segment?
Answer:
Acknowledgement number
Explanation:
The Acknowledgement number field provides the next expected segment.
TCP packets can contain an acknowledgement, which is the sequence number of the next byte the sender expects to receive this also is an acknowledgement of receiving all bytes prior to that.
Write a function that takes as input an English sentence (a string) and prints the total number of vowels and the total number of consonants in the sentence. The function returns nothing. Note that the sentence could have special characters like dots, dashes, and so on.
Answer:
public static void vowelCount(String word){
int vowelCount =0;
int consonantCount =0;
int wordLen = word.length();
//a,e,i,o,u
for(int i=0; i<word.length(); i++){
if(word.charAt(i)=='a'||word.charAt(i)=='e'||word.charAt(i)=='i'
||word.charAt(i)=='o'||word.charAt(i)=='u'){
vowelCount++;
}
}
System.out.println("Number of Vowels: "+vowelCount);
System.out.println("Number of Consonants: "+ (wordLen-vowelCount));
}
Explanation:
The method vowelCount is implemented in Java
Receives a string as argument
Uses a for loop to iterate the entire string
Uses an if statement to check for vowels
Substract total vowels from the length of the string to get the consonants
See complete code with a main method below:
import java.util.Scanner;
public class num2 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter a String");
String word = in.nextLine();
//Removing all special characters and whitespaces
String cleanWord = word.replaceAll("[^a-zA-Z0-9]", "");
//Calling the Method
vowelCount(cleanWord);
}
//The method
public static void vowelCount(String word){
int vowelCount =0;
int consonantCount =0;
int wordLen = word.length();
//a,e,i,o,u
for(int i=0; i<word.length(); i++){
if(word.charAt(i)=='a'||word.charAt(i)=='e'||word.charAt(i)=='i'
||word.charAt(i)=='o'||word.charAt(i)=='u'){
vowelCount++;
}
}
System.out.println("Number of Vowels: "+vowelCount);
System.out.println("Number of Consonants: "+ (wordLen-vowelCount));
}
}
To count the number of vowels and consonants in an English sentence, you could write a function that iterates through each character in the string, checks whether it is a vowel or a consonant, and updates a count for each. Vowels are a, e, i, o, and sometimes u and y. The function disregards any non-alphabetic characters and returns nothing.
To write this function in Python, for example, you could create a list of vowels, iterate through each letter in the input string, and increment the corresponding count if the letter is a vowel or consonant. Python's str.isalpha() method can determine if a character is a letter, thus ignoring special characters and whitespaces. Note that the function should handle both uppercase and lowercase letters since English is case-insensitive while counting vowels and consonants. This function not only serves a practical coding challenge, but it also incorporates an understanding of the English language and its phonetic components.
[Submit on zyLabs] Please write a function with one input, a matrix, and one output, a matrix of the same size. The output matrix should be the input matrix mirrored on the vertical axis. For instance, theinput:[123456789]Would become: [321654987]And the input:[112221112212]Would become:[221112221121]Note that this functions slightly differently for inputs with odd and even numbers of columns. For an odd number of columns, your centermost column stays the same. For an even number of columns, all columns are moved in the resulting output. You can use the function[yDim, xDim]
Answer:
See explaination for the details.
Explanation:
% Matlab file calculateMirrorMatrix.m
% Matlab function to return a matrix which should be input matrix mirrored
% on the vertical axis
% input is a matrix
% output is a matrix of same size as input matrix
function [mirrorMatrix] = calculateMirrorMatrix(inputMatrix)
mirrorMatrix = zeros(size(inputMatrix)); % create output matrix mirrorMatrix of same size as inputMatrix
fprintf('\n Input Matrix :\n');
disp(inputMatrix); % display the input matrix
[row,col] = size(inputMatrix); % row, col contains number of rows and columns of the inputMatrix
% loop to find the matrix which should be input matrix mirrored
for i = 1:row
mirrorIndex =1;
for j = col:-1:1
mirrorMatrix(i,mirrorIndex)=inputMatrix(i,j);
mirrorIndex=mirrorIndex + 1;
end
end
end
% end of matlab function
Please kindly check attachment for its output.
The function 'mirror_matrix' takes a matrix and returns a new matrix where the columns are reversed. It handles matrices with both odd and even numbers of columns. This solution ensures accurate vertical mirroring of the input matrix.
Mirroring a Matrix on the Vertical Axis
To solve the problem of mirroring a matrix on the vertical axis, we need to create a function that takes an input matrix and outputs a matrix of the same size where the columns are reversed.
Here's a step-by-step explanation:
Matrix Dimensions: Determine the dimensions of the matrix with variables yDim (number of rows) and xDim (number of columns).Initialize Output Matrix: Create an empty matrix of the same size as the input matrix.Reverse Columns: Iterate through each row of the matrix and assign the elements to the new positions in the output matrix such that the columns are reversed.Here's a sample Python function to achieve this:
def mirror_matrix(matrix):For example, an input matrix:
[[1, 2, 3],would result in:
[[3, 2, 1],This solution ensures that the output matrix is mirrored correctly on the vertical axis.
Which of the following statements correctly describe a computer program?
A. It is a robust way to find information
B. It is a set of step by step instructions called coding
C. It is a way to take apart a computer
Answer: A. It’s a robust way to find information
Explanation:
Hope this help.
Answer:
A. It is a robust way to find information
Explanation:
eh
Lab Assignment 3 Phase 1 Create a class named Car, which is supposed to represent cars within a Java program. The following are the attributes of a typical car: - year which indicates the year in which the car was made. - price indicating the price of the car The year attribute is an integer, whereas the price is a double value. The year can only lie between 1970 and 2011. The price can be any value between 0 and 100000. The class Car should be constructed in such a way that any attempt to place an invalid value in the year and/or price, will result in the attribute being set to its lowest possible value. Create the class, which contains the necessary attributes and setter/getter methods: setYear( ), getYear( ), setPrice( ) and getPrice( ). Test all of its public members, which in this case only represents the setter/getter methods. The instructor will provide his/her own testing code to verify that the class is functioning properly
Answer:
Check the explanation
Explanation:
Car.java
//class Car
public class Car {
//private variable declarations
private int year;
private double price;
//getYear method
public int getYear() {
return year;
}
//setYear method
public void setYear(int year) throws CarException {
//check for the year is in the given range
if(year>=1970&&year<=2011)
this.year = year;
//else throw an exception of type CarException
else
throw new CarException("Invalid Year");
}
//getPrice method
public double getPrice() {
return price;
}
//setPrice method
public void setPrice(double price) throws CarException {
//check for the price is in the given range
if(price>=0&&price<=100000)
this.price = price;
//else throw an exception of type CarException
else
throw new CarException("Invalid Price");
}
//default constructor to set default values
public Car(){
this.year=1970;
this.price=0;
}
//overloaded constructor
public Car(int year, double price) {
//check for the year is in the given range
if(year>=1970&&year<=2011)
this.year = year;
//else initialize with default value
else
this.year=1970;
//check for the price is in the given range
if(price>=0&&price<=100000)
this.price = price;
//else initialize with default value
else
this.price=0;
}
//copy constructor
public Car(Car c){
this.year=c.year;
this.price=c.price;
}
//toString method in the given format
public String toString() {
return "[Year:" + year + ",Price:" + (int)price + "]";
}
//finalize method
public void finalize(){
System.out.println("The finalize method called.");
}
public static void main(String args[]) throws CarException{
Car a=new Car();
System.out.println(a.toString());
Car b=new Car(1986,25000.98);
System.out.println(b.toString());
Car c=new Car();
c.setYear(1900);
c.setPrice(23000);
System.out.println(c.toString());
Car d=new Car();
d.setYear(2000);
d.setPrice(320000);
System.out.println(d.toString());
}
}
CarException.java
//exception class declaration
public class CarException extends Exception{
//private variable declaration
private String message;
//constructor
public CarException(String message) {
super();
this.message = message;
}
//return error message
public String getMessage(){
return message;
}
}
java
This lab is intended to give you practice creating a class with
a constructor method, accessor methods, mutator methods, equals
method , toString method and a equals method.
In this lab you need to create two separate classes, one Student class and other Lab10 class.
You need to define your instance variables, accessor methods, mutator methods, constructor,
toString method and equals method in Student class.
You need to create objects in Lab10 class which will have your main method and need to add various
functionalities so that you can get the output as shown in sample output.
// Name:
// Section:
// Lab 10
// CS1113
// Fall 2016
// Class Lab10
public class Lab10
{
//Constants
private final static String NAME = "YOUR NAME"; // replace YOUR NAME with your name
private final static int STUID = 123456789;
private final static double GPA1 = 4.00;
private final static double GPA2 = 2.34;
//main method
public static void main (String[] args)
{
Student stu1;
stu1 = new Student(NAME, STUID, GPA1);
System.out.println("\nName: " + stu1.getName());
System.out.println("Id Number: " + stu1.getIdNum());
System.out.println("GPA : " + stu1.getGPA());
stu1.setGPA(GPA2);
System.out.println(stu1 + "\n");
// Create a second student object
// With a name of Trine Thunder, a
// gpa of 4.00, and a student Id of
// 000000001
// You do not need to declare these at final constants,
// but you can if you want to.
// [Add code here]
// Print out this student similar to above.
// You do not need to reset the gpa of this student.
// [Add code here]
// Check if both objects are same using == and .equals() methods.
// Print the message in both cases, whether same or not as shown in sample output.
// [Add code here]
} // end of main
} // end of class Lab10
// Name:
// Section:
// Lab 10
// CS1113
// Fall 2016
// Class : Student.java
public class Student
{
//class variables
private String name;
private int idNum;
private double gpa;
// Constructor
public Student(String namePar, int idNumPar, double gpaPar)
{
// Save namePar to class variable name
// [Add code here]
// Save idNumPar to class variable idNum
// [Add code here]
// Save gpaPar to class variable gpa
// [Add code here]
}
// Accessor: returns name of student
public String getName()
{
// Return the name of the student
// [Add code here]
}
// Accessor: returns GPA of student
public double getGPA()
{
// Return the gpa of the student
// [Add code here]
}
// Accessor: returns idNum of student
public int getIdNum()
{
// Return the idnum of the Student
// [Add code here]
}
// Mutator: Changes the GPA of the student
public void setGPA(double g)
{
// Set the class variable gpa equal to g
// [Add code here]
}
// toString method: Returns a formatted string
// of student information.
// As shown in sample output.
public String toString()
{
// declare a String variable to store the string value
// then return the formatted String.
// [Add code here]
}
// implement .equals() method which returns a boolean value
// of student information. When you call this method,
// it should print message as shown in sample output.
public boolean equals(Student s)
{
//[Add code here]
}
} // end of class Student
1) Fill in the needed code in the file (class)
Student.java (Student) and Lab10.java.
The program will not compile until you do so.
You will have 2 files, one named Lab10.java
and one named Student.java.
Compile the subsidiary class, Student.java,
first, using
javac Student.java
Once you have eliminated any and all syntax errors
in the student class. Then compile
javac Lab10.java
and eliminate any syntax errors from that class.
Then you can run the program using
java Lab10
2) Run the program and redirect the output to Lab10_out.txt
A Sample output is below:
Name: John Terry
Id Number: 123456789
GPA : 4.0
Student Name: John Terry
Student Id num:123456789
Student GPA: 2.34
Name: Trine Thunder
Id Number: 1
GPA : 4.0
Student Name: Trine Thunder
Student Id num:1
Student GPA: 4.0
Using == .....
Both are different.
Using .equals() method.....
Both are different.
3) Now change your code so that you pass same values for both stu1 and stu2.
Compile and run your program.
Your output should look like:
Name: John Terry
Id Number: 123456789
GPA : 4.0
Student Name: John Terry
Student Id num:123456789
Student GPA: 2.34
Name: Trine Thunder
Id Number: 1
GPA : 4.0
Student Name: Trine Thunder
Student Id num:1
Student GPA: 4.0
Using == .....
Both are different.
Using .equals() method.....
Both are different.
Explain why the result is not as expected?
Revert back to your previous version of your java code.
4) Turn in a printed copy of both Student.java and Lab10.java. Also
turn in a printed copy of your output file created in step 2.
Answer:
public class Lab10
{
//Constants
private final static String NAME = "John Terry"; // replace YOUR NAME with your name
private final static int STUID = 123456789;
private final static double GPA1 = 4.00;
private final static double GPA2 = 2.34;
//main method
public static void main (String[] args)
{
Student stu1;
stu1 = new Student(NAME, STUID, GPA1);
System.out.println("\nName: " + stu1.getName());
System.out.println("Id Number: " + stu1.getIdNum());
System.out.println("GPA : " + stu1.getGPA());
stu1.setGPA(GPA2);
System.out.println(stu1 + "\n");
// Create a second student object
// With a name of Trine Thunder, a
// gpa of 4.00, and a student Id of
// 000000001
// You do not need to declare these at final constants,
// but you can if you want to.
System.out.println("\nName: Trine Thunder" );
System.out.println("Id Number: 000000001");
System.out.println("GPA : 4.00");
Student stu2 = new Student("Trine Thunder",000000001, 4.00 );
// [Add code here]
// Print out this student similar to above.
// You do not need to reset the gpa of this student.
System.out.println(stu2 + "\n");
// [Add code here]
// Check if both objects are same using == and .equals() methods.
// Print the message in both cases, whether same or not as shown in sample output.
System.out.println("Using ==");
if(stu1 == stu2){
System.out.println("Both are same");
}
else{
System.out.println("Both are different");
}
stu1.equals(stu2);
// [Add code here]
} // end of main
} // end of class Lab10
// Name:
// Section:
// Lab 10
// CS1113
// Fall 2016
// Class : Student.java
public class Student
{
//class variables
private String name;
private int idNum;
private double gpa;
// Constructor
public Student(String namePar, int idNumPar, double gpaPar)
{
// Save namePar to class variable name
name = namePar;
// [Add code here]
idNum = idNumPar;
// Save idNumPar to class variable idNum
gpa = gpaPar ;
// [Add code here]
// Save gpaPar to class variable gpa
// [Add code here]
}
// Accessor: returns name of student
public String getName()
{
// Return the name of the student
return name;
// [Add code here]
}
// Accessor: returns GPA of student
public double getGPA()
{
// Return the gpa of the student
return gpa;
// [Add code here]
}
// Accessor: returns idNum of student
public int getIdNum()
{
// Return the idnum of the Student
return idNum;
// [Add code here]
}
// Mutator: Changes the GPA of the student
public void setGPA(double g)
{
// Set the class variable gpa equal to g
gpa = g;
// [Add code here]
}
// toString method: Returns a formatted string
// of student information.
// As shown in sample output.
public String toString()
{
// declare a String variable to store the string value
// then return the formatted String.
String s ="";
s = s + "Student Name: "+name+"\n";
s =s + "Student Id num: "+idNum+"\n";
s =s + "Student GPA: "+gpa+"\n";
return s;
// [Add code here]
}
// implement .equals() method which returns a boolean value
// of student information. When you call this method,
// it should print message as shown in sample output.
public boolean equals(Student s)
{
//[Add code here]
System.out.println("Using .equals() method");
if(this.equals(s.idNum == this.idNum)){
System.out.println("Both are same");
return true;
}
else{
System.out.println("Both are different");
return false;
}
}
} // end of class Student
Explanation:
Output:
Name: John Terry
Id Number: 123456789
GPA : 4.0
Student Name: John Terry
Student Id num: 123456789
Student GPA: 2.34
Name: Trine Thunder
Id Number: 000000001
GPA : 4.00
Student Name: Trine Thunder
Student Id num: 1
Student GPA: 4.0
Using ==
Both are different
Using .equals() method
Both are different
5.11 Of these two types of programs:a. I/O-boundb. CPU-boundwhich is more likely to have voluntary context switches, and which is more likely to have nonvoluntary context switches? Explain your answer
Answer:
The answer is "both voluntary and non-voluntary context switch".
Explanation:
The description to this question can be described as follows:
Whenever processing requires resource for participant contextual switch, it is used if it is more in the situation of I/O tied. In which semi-voluntary background change can be used when time slice ends or even when processes of greater priority enter.
In option a, It requires voluntary context switches in I /O bound.In option b, it requires a non-voluntary context switch for CPU bound.Consider an unpipelined or single-stage processor design like the one discussed in slide 6 of lecture 17. At the start of a cycle, a new instruction enters the processor and is processed completely within a single cycle. It takes 2,000 ps to navigate all the circuits in a cycle (including latch overheads). Therefore, for this design to work, the cycle time has to be at least 2,000 pico seconds. What is the clock speed of this processor? (5 points) What is the CPI of this processor, assuming that every load/store instruction finds its instruction/data in the instruction or data cache? (5 points) What is the throughput of this processor (in billion instructions per second)? (10 points)
Answer:
a. Clock Speed of Processor = 0.5 GHz
b. Cycles per Instruction (CPI) = 1 Clock per Instruction
c. Throughput = 1 billion Instruction per Second
Explanation
Given Data
Time Take to complete the single Cycle = 2000ps = 2000 x 10⁻¹²
To Find
a. Clock Speed of Processor = ?
b. Cycles per Instruction (CPI) = ?
c. Throughput = ?
Solution:
a. Clock Speed of Processor = ?
Clock Speed = 1/Time to complete the cycle
= 1/2000 x 10⁻¹² Hz
= 0.0005 x 10¹² Hz
= 0.5 x 10⁹ Hz as 10⁹ = 1 Giga so,
= 0.5 GHz
b. Cycles per Instruction (CPI) = ?
It is mentioned that, each instruction should start at the start of the new cycle and completely processed at the end of that cycle so, we can say that Cycles per Instruction (CPI) = 1
for above mentioned processor.
c. Throughput = ?
Throughput = CPI x Clock Speed
where
CPI = 1 cycle per instruction
Clock Speed = 1 billion Instructions per Second
as
Clock Speed = 1 billion Cycles per Second
Throughput = 1 cycle per instruction x 1 billion Cycles per Second
Throughput = 1 billion Instruction per Second
In previous counters that you have created, you set the upper limit as the value just past the last digit you wanted displayed. That is not the case with this design. Why is how you set the range different for this design?
Answer:
The Synchronous load is synchronous and the Asynchronous load input is delayed with the counter pulse by one when it counts up.
Explanation:
The Synchronous load is synchronous and when it goes through the input load then the count from the Q outputs will stay the same. The Asynchromous load input is bit different and it delays the counters pulse by one when it counts up. it adds 1 to the pulse when it counts down. This means that it will either add or subtract 1 to the restart/maximum binary count.
Final answer:
The number of digits displayed in calculations holds significance for accuracy and precision.
Explanation:
When working with numbers, the number of **digits** you decide to display or consider is crucial. It is essential to be aware of the **accuracy**, **precision**, and **significant figures** in your calculations.
In terms of displayed values, setting the range differently in certain designs may be to highlight the **significance** of the last digit. This last digit often indicates the level of **error** in the calculation and is crucial for conveying the **precision** of the result. The question posed relates to the design of counters in engineering and why the range setting differs in the given design compared to previous ones. In engineering designs, especially those involving counters that detect voltage changes and display them, the precision of measurement and display is crucial. The decision on how to set the range, or the number of digits displayed, is influenced by the principles of accuracy, precision, and significant figures
A _________ does not act like a computer virus, instead it consumes bandwidth, processor, and memory resources slowing down your system
Answer:
The correct answer to the following question will be "Worms".
Explanation:
Worms represent malicious programs that repeatedly render variations of themselves on a shared drive, networking shares respectively. The worm's aim is to replicate itself over and over again.
It doesn't function like a piece of malware but uses bandwidth, CPU, as well as storage assets that slow the machine down.It requires a lot of additional storage throughout the drive because of its duplication nature or requires further CPU uses which would in effect make the device too sluggish and thus requires more bandwidth utilization.Assume that two computers are directly connected by a very short link with a bandwidth of 125 Mbps. One computer sends a packet of 1000 Bytes to the other computer. What’s the end-to-end delay (ignoring the propagation delay)?
Answer:
End to End Delay = 64 micro second
Explanation:
Given
Bandwidth = 125Mbps
A packet = 1000 bytes
Converting bandwidth from Mbps to bit/s
Bandwidth = 125* 10^6 bits/s
Bandwidth = 125,000,000 bit/s
End to End delay is calculated as
Length of Packet ÷ Bandwidth
Length of Packet = 1,000 byte --- convert to bits
Length of Packet = 1000 * 8
Length of Packet = 8,000 bits
So, End to End delay = 8,000/125,000,000
End to End Delay = 0.0000064 seconds --- convert to micro second
End to End Delay = 64 micro second
Write two Get statements to get input values into first Month and first Year. Then write three Put statements to output the month, a slash, and the year. Ex: If the input is 1 2000, the output is:
Answer:
// Scanner class is imported
import java.util.Scanner;
// InputExample class to hold the program
public class InputExample {
// main method to begin program execution
public static void main(String args[]) {
// Scanner object scnr is created
Scanner scnr = new Scanner(System.in);
// variable birthMonth is declared
int birthMonth;
// variable birthYear is declared
int birthYear;
// birthMonth is initialized to 1
birthMonth = 1;
// birthYear is initialized to 2000
birthYear = 2000;
// birthday is displayed
System.out.println("1/2000");
// prompt is displayed asking user to enter birthMonth
System.out.println("Enter birthMonth:");
// birthMonth is received using Scanner object
birthMonth = scnr.nextInt();
// prompt is displayed asking user to enter birthYear
System.out.println("Enter birthYear:");
// birthYear is received using Scanner object
birthYear = scnr.nextInt();
// the birthday format is displayed
System.out.println(birthMonth + "/" + birthYear);
}
}
Explanation:
The program is written in Java as required and it is well commented.
An image depicting the full question is attached.