Select all that apply.
Which of the following are appropriate acceleration units?
-km/hr2
-m/s/s
-ft/s
-miles/hr/min
-sec/km/m

Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.

(a) The resistance of the hairdryer will be 9.6 ohms.

(b)the current in the hairdryer will be 12.5 A.

When all physical parameters and temperature are constant,

Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.

This current-voltage connection may be expressed mathematically as,

The Equation of Ohm's Law

V=IR

(a)

The following data are given as

P = 1500 w

v = 120 v

The power generated in the hairdryer

[tex]\rm{P = vI}\\\\I=\frac{P}{v} \\\\I=\frac{1500}{120}\\\\I=12.5 A}[/tex]

To obtained the resistance

[tex]\rm R=\frac{v}{I} \\\\\rm R=\frac{120}{12.5} \\\\R= 9.6 ohm}[/tex]

Hence the resistance of the hairdryer will be 9.6 ohms.

(b)

The Equation of Ohm's Law

V=IR

[tex]\rm I =\frac{V}{R} \\\\\rm I =\frac{120}{9.6}\\\\\ I= 12.5 A[/tex]

Hence the current in the hairdryer will be 12.5 A.

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Answer:

Observed lifetime [tex]= 3.0\mu s[/tex]

Explanation:

The lifetime of muon in the muon’s reference frame.

[tex]t^{_{0}}=2.2\mu s[/tex]

The lifetime of muon in observer’s rest frame.

[tex]t=\gamma t_{0}[/tex]

Here the  

[tex]\gamma =\dfrac{1}{\sqrt{1-\frac{V^2}{C^2}}}[/tex]

[tex]\gamma[/tex] is the relativistic factor.  

V = Speed of muon

C = Speed of light

The muon’s speed of 70% of light speed.  

Hence,

[tex]V=\dfrac{70}{100}C[/tex]

V = 0.7C

[tex]=\dfrac{1}{\sqrt{1-\frac{(0.7C)^2}{C^2}}}[/tex]

[tex]=\dfrac{1}{\sqrt{1-0.49}}[/tex]

[tex]=\dfrac{1}{\sqrt{0.51}}[/tex]

[tex]=\dfrac{1}{0.71}[/tex]

= 1.4

The lifetime of muon in observer’s rest frame.

[tex]t=\gamma t_{0}[/tex]

[tex]t=1.4\times 2.2\mu s[/tex]

[tex]t=3.0\mu s[/tex]

Further explanation:

The muon is a lepton which decays to form an electron or positron. The lifetime of the muon is 2.20 microseconds. The muon lifetime in the muon reference frame is .  

But the observed lifetime [tex]= \gamma =\frac{1}{\sqrt{1-\frac{V^2}{C^2}}}[/tex]

Learn more:

1. Speed of muon https://brainly.com/question/10048817 (answer by skyluke89)

2. Muon https://brainly.com/question/13198853 answer by skyluke89 )

Keywords: Muon, Speed of light, life time.

The maximum theoretical efficiency of a steam turbine operating at a boiler temperature of 450 K and an exhaust temperature of 300 K, as calculated by the Carnot efficiency, is approximately 33%.

The efficiency of a heat engine like a steam turbine can be evaluated using the Carnot efficiency formula. The Carnot efficiency formula is 1 - Tc/Th where Tc is the cold reservoir temperature (exhaust temperature) and Th is the hot reservoir temperature (boiler temperature). Given in the problem, Tc=300K and Th=450K:

Efficiency = 1 - Tc/Th

= 1 - 300 K / 450 K = 1 - 0.67 approximately

So, the maximum theoretical efficiency of the steam turbine would be about 33% according to the Carnot efficiency.

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Making a mental picture of the way a volcano erupts to remember how a volcano functions is called visualization.

Visualization is the process whereby a person makes or forms a mental picture of a particular situation or occurrence in order to better understand that occurrence.

Picturing the way a volcano erupts to remember how a volcano functions is a process of visualization.

A mental picture of the volcano is made by the individual.

Therefore, Picturing the way a volcano erupts to remember how a volcano functions is called visualization.

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Other forms of energy.

The step in an investigation of arson that help the insurance claims the most is the samples of ignition sources or the processing of evidence at the scene. The people with the insurance claims are careful in gathering investigation data for they will used it as a basis for their claim.

Answer:

Since it is for insurance purposes, inventory would be required.

Explanation: inventory is needed to file a claim. Also, I took the test and got it correct ;)

Cyclonic storm -gradpoint

The time in which the ball will reach the ground is about 1.10 s

Acceleration is rate of change of velocity.

[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]

[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem !

This problem is about Kinematics.

We will solve it in the following way

Given:

initial speed = u = 1.53 m/s

initial height = H = 4.21 m

Unknown:

time taken = t = ?

Solution:

[tex]H = ut - \frac{1}{2}gt^2[/tex]

[tex]-4.21 = 1.53t - \frac{1}{2}(9.8)t^2[/tex]

[tex]-4.21 = 1.53t - 4.9t^2[/tex]

[tex]4.9t^2 - 1.53t - 4.21 = 0[/tex]

We will solve the above equation using the following quadratic function formula:

[tex]t = \frac{1.53 + \sqrt{1.53^2 - 4(4.9)(-4.21)}}{2(4.9)}[/tex]

[tex]t \approx 1.10 ~ s[/tex]

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

The work done by two moles of an ideal gas compressed isothermally in a cylinder can be calculated using the formula W = nRT ln(V1/V2). The work is generally negative as the gas does work on its surroundings during the process.

When an ideal gas is compressed in a cylinder, the work done by the gas can be calculated using the principles of thermodynamics. Specifically, if the gas is compressed isothermally (at a constant temperature), the work done by the gas during this process can be calculated using the formula W = nRT ln(V1/V2), where n represents the number of moles of gas, R is the universal gas constant, T is the temperature in Kelvin, and V1 and V2 are the initial and final volumes of the gas respectively.

In the scenario presented, we have 2 moles of gas, a temperature of 80.0°C, and the original pressure being tripled during the compression. This tripling of pressure corresponds to reduction in volume to one third. From these values, we can calculate the work done by the gas during compression. However, we do not have specific information about the volumes or pressures, so we cannot calculate a numerical value. In general, though, we can say the work done by the gas during an isothermal process is negative, as it is compressed and does work on its surroundings.

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Answer:

C) a powerful magnet

Explanation:

The electric current running through the wire coil in an electric motor exerts force directly onto A) the battery. B) an aluminum axle. C) a powerful magnet. D) a rubber insulator.

when current is pass to the coil, an electromagnetic force field is produced. The electromagnetic force field produced then have an impact on the magnet which drives the shaft to move

Final answer:

The width of the slit when violet light of 415 nm wavelength creates a central diffraction peak of 9.90 cm on a screen 2.53 m away is approximately 10.6 μm.

Explanation:

The wavelength of violet light is given as 415 nm, and it produces a diffraction pattern with a central peak width of 9.90 cm on a screen 2.53 meters away. We can find the width of the slit using the formula for single-slit diffraction:

Δy = λL/a

where Δy is the width of the central peak, λ is the wavelength, L is the distance to the screen, and a is the width of the slit. Rearranging the formula to solve for a, we have:

a = λL/Δy

Substituting the provided values:

a = (415 x 10^-9 m)(2.53 m) / (9.90 x 10^-2 m)

After calculating, we find that the width of the slit (a) is approximately:

a ≈ 1.06 x 10^-5 m or 10.6 μm

Using the single-slit diffraction formula and given values, we calculate the width of the slit to be 21.1 μm.

To solve this problem, we'll use the formula for the width of the central peak in a single-slit diffraction pattern:

Where:

Rearranging the formula to solve for a:

Substituting the given values:

Now, calculate:

Therefore, the width of the slit is 21.1 μm.

The intensity level from a set of quintuplets (five babies) : 56 dB

Wave intensity is the power of a wave that is moved through a plane of one unit that is perpendicular to the direction of the wave

Can be formulated

[tex]\rm I=\dfrac{P}{A}[/tex]

I = intensity, W m⁻²

P = power, watt

A = area, m²

The farther the distance from the sound source, the smaller the intensity

[tex]\rm \dfrac{I_2}{I_1}=\dfrac{(r_1)^2}{(r_2)^2}[/tex]

So the intensity is inversely proportional to the square of the distance from the source

[tex]\rm I\approx \dfrac{1}{r^2}[/tex]

Intensity level (LI) can be formulated

[tex]\rm LI=10\:log\dfrac{I}{I_o}[/tex]

Io = 10⁻¹²

For the level of intensity of several sound sources as many as n pieces can be formulated:

The intensity level of 1 baby is

[tex]\rm LI=10\:log\dfrac{8.10^{-8}}{10^{-12}}[/tex]

LI = 10 log 8.10⁴

LI = 49

The intensity level of 5 babies :

LI5 = LI + 10 log n

LI5 = 49 + 10 log 5

LI5 = 49 + 7

LI5 = 56

The intensity of a laser beam

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electric field

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magnetism

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The hydrogen line at 656.46 nm shifts to about 655.80 nm if a star is traveling 300 km/s toward Earth.

Using the Doppler Effect to Determine the Wavelength Shift

Use the Doppler shift formula for wavelengths:

Plugging in the values:

Calculate the ratio:

Evaluate the square root:

Compute the shifted wavelength:

The 656.46-nm line would shift to approximately 655.80 nm if the star were moving towards Earth at 300 km/s.

Complete question:

Suppose that you'd like to find out if a distant star is moving relative to the earth. The star is much too far away to detect any change in its brightness as it moves toward or away from the earth. Instead we can use the Doppler effect to determine its relative speed. For this problem we are going to look at the spectral lines from hydrogen, specifically the one with a wavelength of 656.46 nm. Even at such low fractions of the speed of light these stars are moving quite quickly (thousands of kilometers a second) compared to the standard velocity dispersion in the Milky Way galaxy (which is around 300 km/s). Suppose the star was actually moving toward the earth at a more reasonable 300 km/s. What wavelength I would the 656.46-nm line move to? Use 299, 792 km/s for the speed of light. Express your answer in nanometers to five significant figures.

The total resistance in the parallel circuit with three 10-ohm resistors and a 15-volt battery is approximately 3.33 ohms. The total current through the circuit is approximately 4.50 amps.

To calculate the total resistance in a parallel circuit with three resistors of 10 ohms each, we use the formula for parallel resistance:

[tex]\frac{1}{R_{\text{total}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}[/tex]

Substituting the values:

1/Rtotal = 1/10 + 1/10 + 1/10

1/Rtotal = 3/10

Therefore, Rtotal = 10/3 = 3.33 ohms

Next, we calculate the total current using Ohm's Law:

I = V/Rtotal

Given the battery voltage is 15 volts:

I = 15/3.33 ≈ 4.50 amps

The total resistance in the parallel circuit with three 10-ohm resistors and a 15-volt battery is approximately 3.33 ohms. The total current through the circuit is approximately 4.50 amps.

Answer:

road erosion, house construction, steep slope cultivation, tourism development, and animal trampling.

Explanation:

The fluid's depth in the cylinder can be determined using the equation for fluid pressure, h = P / (pg), and plugging in given values, resulting in an approximated depth of 20.9 meters.

The total absolute pressure at a point in a fluid is the sum of the atmospheric pressure and the pressure due to the fluid above the point of reference. The latter is given by the equation P = pgh, where p is the density of the fluid, g is the acceleration due to gravity and h is the height (or depth) of the fluid column above the point of reference. In this scenario, we know P (absolute pressure, 115 kPa), p (density, 560 kg/m3), and g (standard gravity, roughly 9.81 m/s2), and we want to find h.

To find h, we can rearrange our equation: h = P / (pxg) . Plugging the given values we have h=115000Pa/(560kg/m3*9.8m/s2), which gives h = 20.9 m.

This means the depth of the fluid in the cylinder is approximately 20.9 meters.

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The pressure exerted by a phonograph needle on a record, if the equivalent of 1g is supported by the needle with a radius of 0.210 mm, is approximately 7.05*10^7 Pa or N/m².

The pressure exerted by a phonograph needle on a record is calculated using the formula for pressure: P = F / A . To obtain the force (F), we multiply the mass of the needle (1g or 0.001 kg) by the acceleration due to gravity (9.8 m/s²). This yields a force of 0.0098 N. The area (A) is calculated using the formula for the area of a circle, A=πr², where r is the radius of the needle tip (0.210 mm or 0.00021 m). So, the area amounts to roughly 0.000000139 m². The resulting pressure (P), when calculated comes out to be approximately 7.05*10^7 Pa or N/m².

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