Select the point that satisfies y ≤ x2 - 3x + 2. A. (3, 3) B. (4, 4) C. (2, 2) D. (1, 1)

Answers

Answer 1
To answer this question, you will substitute in the first number in the ordered pair for x and the second number in the ordered pair for y.  For the first ordered pair, it is 3<3^2- 3 x 3 + 2.  Simplified, it would say that 3<2 which is not true!  For b. it would be 3<4^2- 3 x 4 + 2.   Simplified, it would say that 4<6 which is true!   For c. it would be 2<2^2- 3 x 2 + 2.   Simplified, it would say that 2<0 which is NOT true! For d. it would be 1<1^2- 3 x 1 + 2.   Simplified, it would say that 1<0 which is also NOT true!
Answer 2

Answer:

the answer is (4,4)

Step-by-step explanation:



Related Questions

you leave your house and walk for half an hour at a speed of 3 miles per hour. Then you run for 15 minuets at a speed of 7 miles per hour. You are now halfway to town. Write and solve an equation to find the distance from your house to town

Answers

Final answer:

To find the total distance to town, the distance walked (1.5 miles) and run (1.75 miles) were calculated, and it was found that the student is 3.25 miles away from home. This is halfway to town, so the total distance to town is 6.5 miles.

Explanation:

To solve the problem, we will calculate the distance traveled by walking and running and then use these to find the total distance to town.

Step 1: Calculate the distance walked

First, we convert the walking time into hours since the speed is given in miles per hour. Half an hour of walking at 3 miles per hour will cover:

Distance walked = Speed × Time = 3 mph × 0.5 hours = 1.5 miles

Step 2: Calculate the distance run

Since 15 minutes is a quarter of an hour, we can calculate the distance run at 7 miles per hour as:

Distance run = Speed × Time = 7 mph × 0.25 hours = 1.75 miles

Step 3: Determine the total half distance

Now, we combine the distances to find the halfway point to town:

Total half distance = Distance walked + Distance run = 1.5 miles + 1.75 miles = 3.25 miles

Step 4: Find the full distance to town

Since this is half the distance, the full distance to town is:

Full distance = Total half distance × 2 = 3.25 miles × 2 = 6.5 miles

Conclusion

Therefore, the total distance from the student's house to town is 6.5 miles.

Final answer:

The total distance from the house to town is found by doubling the sum of the distances walked and run, which were 1.5 miles and 1.75 miles, respectively. The full distance to town is 6.5 miles.

Explanation:

To solve for the distance from your house to town, we will use the information provided about your walking and running times and speeds. Since you walked for half an hour (0.5 hours) at a speed of 3 miles per hour and ran for 15 minutes (0.25 hours) at a speed of 7 miles per hour, and this brought you halfway to town, we can set up the following equation:

Distance walked = Speed walked × Time walked
= 3 mph × 0.5 hours
= 1.5 miles

Distance run = Speed run × Time run
= 7 mph × 0.25 hours
= 1.75 miles

The total distance you traveled to get halfway to town is the sum of the distance walked and the distance run:

Total distance halfway = Distance walked + Distance run
= 1.5 miles + 1.75 miles
= 3.25 miles

Since 3.25 miles is only halfway to town, the full distance to town is twice that amount:

Full distance to town = 2 × Total distance halfway
= 2 × 3.25 miles
= 6.5 miles

Therefore, the total distance from your house to town is 6.5 miles.

An inheritance of ​$30,000 will be divided between sisters hannah and taylor. if hannah is to receive ​$4000 less than​ taylor, how much does each sister​ receive?

Answers

Taylor gets 1,900, and Hannah get's 1,100. How unfair
Hannah receives $13,000.
Taylor receives $17,000.

Factor to find the zeros of the function defined by the quadratic expression.
7x2 + 14x − 105

Answers

Answer:

{-5, 3}

Step-by-step explanation:

7 is a factor common to all three terms of this polynomial function.  Thus, after the first attempt to factor it, we have 7(x^2 + 2x - 15).  The quadratic factors into (x + 5)(x - 3).  Setting these = to zero individually, we get

x + 5 = 0, or x = -5, and

x - 3 + 0, or x = 3

Thus, the zeros of the given f(x) =7x2 + 14x − 105 are {-5, 3}.

Find, to the nearest tenth, the area of the region that is inside the square and outside the circle. The diameter of the circle is 14 in

Answers

Assuming you mean that the circle touches the sides of the square,  the area of the square would be 14 x 14 = 196 sq in

The area of the circle inside of the square is   π (7)² =  153.9

Therefore 196 - 153.9 = 42.1 

Answer:

Option [tex]42.1\ in^{2}[/tex]

Step-by-step explanation:

we know that

The area of the region that is inside the square and outside the circle is equal to the area of the square minus the area of the circle

see the attached figure to better understand the problem

Step 1

Find the area of the square

Remember that

The area of the square is

[tex]A=b^{2}[/tex]

where

b is the length side of the square

we have

[tex]b=14\ in[/tex]

substitute

[tex]A=14^{2}=196\ in^{2}[/tex]

Step 2

Find the area of the circle

Remember that

The area of the circle is equal to

[tex]A=\pi r^{2}[/tex]

we have

[tex]r=14/2=7\ in[/tex]

substitute

[tex]A=\pi(7^{2})=153.9\ in^{2}[/tex]

Step 3

Find the area of the region

[tex]196\ in^{2}-153.9\ in^{2}=42.1\ in^{2}[/tex]



If quadrilateral ABCD rotates 90° counterclockwise about the origin, what are the coordinates of A′ in quadrilateral A′B′C′D′ ?


(2, 1)



(-2, -1)



(-2, -2)



(-2, 0)

Answers

I believe the answer is (-2,-1)   after the original point (2,1) goes through the change of -y,x

Answer:

Option B is correct.

The coordinate of A' is (-2 , -1)

Explanation:

The coordinates of ABCD are A = (-1,2) , B(1,1) , C =(1,-1) and D(-2,-2).

Rotation means moving the shape  around a fixed point clockwise or anticlockwise, and by a certain number of degrees.

Rule for 90° counterclockwise rotation about the origin: [tex](x,y) \rightarrow (-y,x)[/tex]

or we can say that switch x and y in the coordinates and make y value opposite.

Then, the coordinate of A' :

[tex]A(-1,2) \rightarrow A'(-2 ,-1) [/tex]

Therefore, the coordinate of A' in the quadrilateral A'B'C'D' is, (-2 ,-1)


Crystal has 81/100 of a dollar. What could be the coins crystal has?

Answers

eight dimes and one penny
She could have 3 quarters, a nickel, and a penny...

8 dimes and a penny

16 nickels and a penny

81 pennies


What is the approximate length of arc s the Circle? o

Answers

[tex]arc \ length= \pi r ( \frac{C}{180} ) \ \ \ \ [C= central \ angle, \ r=radius, \pi \approx3.1415] \\ \\ arc \ S=3.1415\cdot15 \cdot\frac{200}{180}\approx 52.36 \ in [/tex]

Answer:

c!

Step-by-step explanation:

Emma created the poster shown below: A rectangle is shown. The length of the rectangle is labeled as length equal to 36 cm, and the width is labeled as width equal to 24 cm. What would be the dimensions of the poster at fraction 1 over 4 times its current size?

Answers

Divide the numerator and denominator by 4 to find the answer.
36/24 = 9/6
If the poster was 1/4 its current size, it would be 9 centimeters long and 6 centimeters wide.

Hope this helps =)

Answer:

Length = 6 cm, width = 9 cm

Step-by-step explanation:

Yolanda paid for her movie ticket using 28 coins, all nickels and quarters. The ticket cost $4. Which system of linear equations can be used to find the numberof nickels, n, and the number of quarters, q, Yolanda used?

Answers

If nickels and quarters add up to 28 coins then it would be
n + q = 28

If nickels are .05 and quarters are .25 and the total is $4 then it would be
.05n + .25q = 4

Answer:

[tex]\left \{ {{n+q=28} \atop {n(0.05)+q(0.25)=4}} \right.[/tex]

And the pair [tex](n,q)=(15,13)[/tex] is the solution.

Step-by-step explanation:

We know that Yolanda paid for her movie ticket using 28 coins. She only paid with nickels and quarters.

We also know that the ticket cost $4.

We need to form a linear equation system that solves this problem.

We have the following variables :

n : number of nickels

q : number of quarters

We know that she used 28 coins ⇒ the number of nickels plus the number of quarters must be equal to 28.

We have our first equation :

[tex]n+q=28[/tex] (I)

For the second equation we need to use the ticket price information.

We know that the ticket cost $4 and she only paid with nickels and quarters.

Therefore we can write the following equation that relates the variable ''n'' and the variable ''q'' :

[tex]n(0.05)+q(0.25)=4[/tex] (II)

This equation represents that the number of nickels ''n'' per its value plus the number of quarters ''q'' per its value is equal to $4 that it is the value of the movie ticket.

With (I) and (II) we form the linear equation system :

[tex]\left \{ {{n+q=28} \atop {n(0.05)+q(0.25)=4}} \right.[/tex]

This linear equation system can be used to find the value of ''n'' and ''q''.

For example, in equation (I)

[tex]n+q=28[/tex]

we can solve it in terms of ''n'' :

[tex]n=28-q[/tex] (III)

If we use (III) in (II) :

[tex](28-q)(0.05)+q(0.25)=4[/tex]

[tex]1.4-(0.05)q+(0.25)q=4[/tex]

[tex]q(0.2)=2.6[/tex]

[tex]q=\frac{2.6}{0.2}=13[/tex]

[tex]q=13[/tex]

Now replacing this value of q in (III) :

[tex]n=28-13=15[/tex]

[tex]n=15[/tex]

We find that Yoland used 15 nickels and 13 quarters to paid the movie ticket .

what is the measure of BC

Answers

the BC is measure by 4, and also if you wanna add this the AB is measure by 3.

What is the measure of BC


Solution:

As per Inscribed Angle Theorem: If an angle is inscribed in a circle, then the measure of the intercepted arc is twice the value of the measure of the inscribed angle.

So, as we can see in the diagram the angle inscribed in the circle is 65°.

So, the measure of intercepted arc BC is twice ∠BDC

Or, BC=2*65°

BC=130° Answer


What is the x-intercepts of the graph of y = 12x-5x-2

Answers

y = 12x - 5x - 2

first simplify the equation by subtracting like terms (in this case):

12x - 5x = 7x

y = 7x - 2

Since you are finding the x, you must isolate the x. Do the opposite of PEMDAS.(Note: because there is a equal sign, what you do to one side, you do to the other)

y = 7x - 2

y (+2) = 7x - 2 (+2)
y + 2 = 7x
(y + 2)/7 = 7x/7

x = (y + 2)/7


x = (y + 2)/7 is your answer

hope this helps
x intercept = when the graph cuts the x-axis = when y = 0


y = 12x^2 -5x -2

when y = 0
12x^2 -5x -2 = 0
(3x - 2) (4x + 1) = 0
x = 2/3 or x = 1/4

So the x-intercept are (2/3, 0) and (1/4, 0)

△ABC∼△DEF , △ABC has a height of 20 inches, and △DEF has a height of 24 inches. What is the ratio of the area of △ABC to the area of △DEF ?

Answers

Let
b1-------------> base △ABC
b2-------------> base △DEF
A1-----------> area △ABC
A2-----------> area △DEF

we know that
h1=20 in
h2=24 in
A1=b1*20/2-------------> A1=10b1
A2=b2*24/2 ------------> A2=12 b2

if  △ABC∼△DEF
then 
b1/20=b2/24------------> b1=b2*[20/24]-----> b1=b2*[5/6]

What is the ratio of the area of △ABC to the area of △DEF?
A1=10b1
A2=12b2
A1/A2=(10/12)*(b1/b2)-------> (10/12)*(b2*(5/6)/b2)-----> (10/12)*(5/6)=50/72

A1/A2=50/72--------> 25/36

the answer is (25/36)

Find the dimensions of a rectangle whose area is 221 cm2 and whose perimeter is 60 cm. (enter your answers as a comma-separated list.)

Answers

Final answer:

The dimensions of a rectangle with an area of 221 cm² and a perimeter of 60 cm are found by solving a system of equations derived from the definitions of area and perimeter. The dimensions are 13 cm by 17 cm, or equivalently, 17 cm by 13 cm.

Explanation:

To find the dimensions of a rectangle with an area of 221 cm2 and a perimeter of 60 cm, we will let the length be x and the width be y. The area of a rectangle is found by multiplying the length and width, so we have the equation x * y = 221. The perimeter is twice the sum of the length and width, so we have 2x + 2y = 60, which simplifies to x + y = 30.

To solve these equations, divide the perimeter equation by 2 to find y = 30 - x. Substituting this into the area equation gives x(30 - x) = 221. Expanding this and bringing all terms to one side provides a quadratic equation: x2 - 30x + 221 = 0. Solving this quadratic equation by factoring or using the quadratic formula gives the dimensions of the rectangle.

The solutions to the quadratic equation are x = 13 and x = 17. Since x and y are interchangeable as length and width, the two sets of possible dimensions for the rectangle are 13 cm by 17 cm and 17 cm by 13 cm.

The dimensions of the rectangle are [tex]17\ cm , 13\ cm[/tex]

To find the dimensions [tex]\( l \)[/tex] (length) and [tex]\( w \)[/tex] (width) of the rectangle given its area and perimeter, we start with the following equations:

1. Area equation:

[tex]\[l \times w = 221\][/tex]

2. Perimeter equation:

[tex]\[ 2l + 2w = 60 \][/tex]

Step-by-Step Solution:

The dimensions of the rectangle are [tex]{{17, 13} \) cm.[/tex]

From the perimeter equation, divide everything by [tex]2[/tex] to simplify:

[tex]\[l + w = 30\][/tex]

Now we have a system of equations:

[tex]\[\begincases}l \times w = 221 \\l + w = 30\end{cases}\][/tex]

Let's solve this system using substitution or elimination:

From [tex]\( l + w = 30 \)[/tex], we can express [tex]\( w \)[/tex] in terms of [tex]\( l \)[/tex]

[tex]\[w = 30 - l\][/tex]

Substitute [tex]\( w = 30 - l \)[/tex] into the area equation:

[tex]\[l \times (30 - l) = 221\][/tex]

[tex]\[30l - l^2 = 221\][/tex]

Rearrange this equation to form a quadratic equation:

[tex]\[l^2 - 30l + 221 = 0\][/tex]

Now, solve this quadratic equation using the quadratic formula [tex]\( l = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = 1 \), \( b = -30 \), and \( c = 221 \)[/tex]

[tex]\[l = \frac{-(-30) \pm \sqrt{(-30)^2 - 4 \times 1 \times 221}}{2 \times 1}\][/tex]

[tex]\[l = \frac{30 \pm \sqrt{900 - 884}}{2}\][/tex]

[tex]\[l = \frac{30 \pm \sqrt{16}}{2}\][/tex]

[tex]\[l = \frac{30 \pm 4}{2}\][/tex]

Calculate both possible values of [tex]\( l \)[/tex]

[tex]\[l = \frac{30 + 4}{2} = 17 \quad \text{or} \quad l = \frac{30 - 4}{2} = 13\][/tex]

Corresponding values of \( w \)

[tex]If\ \( l = 17 \), then \( w = 30 - 17 = 13 \)[/tex]

[tex]If\ \( l = 13 \), then \( w = 30 - 13 = 17 \)[/tex]

Therefore, the dimensions of the rectangle are [tex]\( 17 \) cm[/tex] by [tex]\( 13 \) cm.[/tex]

Verification:

[tex]Area: \( 17 \times 13 = 221 \) cm\(^2\)[/tex]

[tex]Perimeter: \( 2 \times (17 + 13) = 2 \times 30 = 60 \) cm[/tex]

Both conditions match the given area and perimeter, confirming that the dimensions are correct.

(Economics) Select all that apply.

Select the items that apply to calculating the Gross Domestic Product.

a. final goods and services

b. intermediate goods and services

c. last year's products

d. new products

Answers

Final answer:

GDP calculations should include 'final goods and services' and 'new products' to reflect a nation's current economic activity accurately while preventing double counting.

Explanation:

The question pertains to what should be included when calculating the Gross Domestic Product (GDP). The options given were a. final goods and services, b. intermediate goods and services, c. last year's products, and d. new products. According to the principles of economics, GDP is the market value of all final goods and services produced within a country in a given period of time.

It is crucial to understand that GDP calculations include only new products that are produced within the current year to reflect the nation's current economic activity. This method helps statisticians avoid the mistake of double counting, which would inflate GDP figures inaccurately. Consequently, the correct selections are a. final goods and services and d. new products.

Help I'm taking a k12 quiz 2.04: composite figures but, I can't figure these out can anyone help me?

Question. 1 What is the area of this polygon? (Picture 1)
Question. 2 What is the area of this polygon? 42.5 Units? 41.5 Units? 35.5 Units? 29.5 Units? (Picture 2)
Question. 3 This figure is made up of a rectangle and parallelogram.

What is the area of this figure? (Picture 3)
Question. 4 What is the area of this composite shape? (Picture 4)

Thank you angels who help me with these

Answers

All of these can be solved by separating complex figur into simpler one.
Needed formulas are:
Area of rectangle A=a*b
Area of triangle A=a*h/2
Area of paralelogram A= a*h

QUESTION 1.
When we connect points F and S we get a rectangle and a triangle.
Dimensions of sides of a rectangle are a=9 and b=2. 
A=9*2=18 [tex]units^{2} [/tex]
For a triangle we need to take one side and it's height. Let's take side FS because it's easiest to find the height.
a=9
h=6
A=9*6/2=27[tex]units^{2} [/tex]

Tot+al area of a figure: 
A=18+27=45[tex]units^{2} [/tex]

QUESTION 2.
We connect point (1,1) with (1,-2) and (-6,1). This way we get a rectangle and three triangles.
Rectangle:
a=3
b=4
A=3*4=12[tex]units^{2} [/tex]

Top right triangle:
a=4
h=3
A=4*3/2=6[tex]units^{2} [/tex]

Top left triangle:
a=7
h=2
A=7*2/2=7[tex]units^{2} [/tex]

Bottom left triangle:
a=7
h=3
A=7*3/2=10.5[tex]units^{2} [/tex]

Total area of a figure:
A=12+6+7+10.5=35.5[tex]units^{2} [/tex]

QUESTION 3.
We connect points (-4,2) and (-1,3). This way we get a paralelogram and a rectangle.

Paralelogram:
a=6
h=1
A=6*1=6[tex]units^{2} [/tex]

Rectangle:
a=distance between (-4,2) and (-1,3) = [tex] \sqrt{ (-1-(-4))^{2} + (3-2)^{2} } = \sqrt{10} [/tex]
b = distance between (-4,2) and (-2,-4) = [tex] \sqrt{ (-2-(-4))^{2} + (-2-2)^{2} } = \sqrt{20} [/tex]
A=a*b=[tex] \sqrt{10} * \sqrt{20} = \sqrt{200} =10 \sqrt{2} [/tex][tex]units^{2} [/tex]

Paralelogram:
a=6
h=1
A=6*1=6[tex]units^{2} [/tex]

Total area of a figure:
A=[tex]10 \sqrt{2} [/tex] + 6 [tex]units^{2} [/tex]

QUESTION 4.
We coonect missing side of a triangle. That side has a length of: 6in-3in=3in. Vertical side of triangle is: 13in-7in=6in
Area:
a=3
h=6
A=3*6/2=9[tex] in^{2} [/tex]

Rectangle:
a=7in
b=6in
A=7*6=42[tex] in^{2} [/tex]

Total area of a figure:
A=9+42=51[tex] in^{2} [/tex]

Julia bought name tags for a party. Each name tag is 334 inches wide and 213 inches high. The formula for the area of a rectangle is A=bh. What is the area of one name tag?

Answers

the correct answer is 71142 just multiply 334 and 213

Answer:the correct answer is 71142 just multiply 334 and 213

Step-by-step explanation:

Given the inequality below: x + 2y ≥ 10

Answers

x+2y≥10
(x+2y)+(-10)≥10+(-10)
x+2y-10≥10-10
(x+2y-10)+(-x+10)≥-x+10
x+2y-10-x+10≥-x+10
2y≥-x+10
2y over 2 ≥ -x +10 over 2
y≥-1 over 2x + 10 over 2
y≥-1/2x+5

please help asap !! ill mark brainliest but be corrrecct

Answers

Answer:

k=4

Step-by-step explanation:

Given

A line x=7

The line has only y-intercept which means that it is a vertical line.

As the two points are

A(10,2) and B(k,2)

The y-intercepts of both the points are same i.e. y=2 which means that the line fomed by joining A and B is a horizontal line.  

As x=7 is a vertical line and bisects the horizontal line, the mid-point of line AB will be the point where first line (x=7) bisects the second which is (7,2).

The x-coordinate of mid-point is 7 because the vertical line has 7 as x-intercept and y-intercept is two because the horizontal line has y-intercept 2.

So,

Mid-point=((10+k)/2  ,2)=(7,2)

Comparing the x-coordinate

(10+k)/2=7

10+k=7*2  

10+k=14

k=14-10

k=4

How much greater will Jennifer’s January finance charge be if the finance charge is calculated using the previous balance method than if it is calculated using the adjusted balance method? a. $0.48 b. $1.15 c. $0.67 d. $0.85

Answers

the answer to this is C
its c. just took the test 

The width (l) of a sheet of plywood that is one half the length l

Answers

L=2+4W
W=L/2
f=3d

hope this is the right question????

Kelly mixes the letters S E L E C T E and D thoroughly. Alex picks one letter. WHat is the probability that Alex will not select a consonant.

A. 3/8
B.3/5
C.5/8
D.1/2

Answers

Answer: A) 3/8

There are 3 non-consonants (aka vowels) out of 8 letters total. That's why the answer is simply 3/8. It's the fraction of the number of things we want out of the number of things total.

Dan has to carry 285 apples from a farm to the market. How many baskets will he need, given that each basket can hold 37 apples?

Answers

divide number of apples by how many fit I a basket:

285 / 37 = 7.70

 so he will need 8 baskets

Given f(x)=3x^2+5 and g(x)=x−2 .

What is (fg)(x) ?


Answers

the correct answer is the second on
A is the correct answer

How many points determine a unique line?






A.

1 point





B.

2 points





C.

any 3 points





D.

3 noncollinear points


I say 2 points!

Answers

I would say 2 points for a unique line

Answer:

B. 2 points

Step-by-step explanation:

1 point is a dot in space, 2 can make a line

helpppppppppppppppppppppppppppppppppppppppppp

Answers

Answer:
First choice is the correct one

Explanation:
The given is:
[(x+5) / (x+2)] - [(x+1) / x(x+2)]
First, we will need to have a common denominator and then we will solve the subtraction normally. To get a common denominator, we will have to multiply both numerator and denominator of first term by x.

Therefore:
[(x+5) / (x+2)] - [(x+1) / x(x+2)] = [x(x+5) / x(x+2)] - [(x+1) / x(x+2)]
                                                 = [x(x+5)-(x+1)] / [x(x+2)]
                                                 = (x^2 + 5x - x - 1) / [x(x+2)]
                                                 = [(x^2 + 4x - 1)] / [x(x+2)]

Hope this helps :)

The base and the height of sail b are x times greater than the base and the height of sail

a. how many times greater is the area of sail b? write your answer as a power.

Answers

Sail A has base equal to b and Height equal to h. Since sail B has base and height x times that of A, the base of B is bx and the height is hx

Since your sail has a base and a height it can be a triangle, a square, a rectangle or a rhombus, but I believe most sails are either triangles or rectangle so let's explore those. That should be enough to see that the answer is the same for the shapes listed.

TRIANGLE
The area of a triangle is (1/2)(b)(h). This is the area of sail A. The area of sail B is (1/2)(bx)(hx) = [tex]( \frac{1}{2} bh) x^{2} [/tex]. That makes the area of B [tex] x^{2} [/tex] times greater.

RECTANGLE
The area of a rectangle is (b)(h). This is the area of sail A. The area of sail B is (bx)(hx) = [tex]bh x^{2} [/tex]That makes the area of B [tex] x^{2} [/tex] times greater.



Final answer:

When both the base and height of a shape are multiplied by x, the area increases by a factor of x^2. Therefore, the area of Sail B is x^2 times greater than that of Sail A.

Explanation:

The area of a shape with a base and height is commonly found using the formula Area = 1/2 * Base * Height. If the base and the height of Sail B are x times greater than those of Sail A, then both the base and height of Sail B are multiplied by x, resulting in an area that is x^2 (x squared) times greater. This is because, in the formula, base and height are multiplied together, so if both are multiplied by x, the overall multiplication is by x*x, or x^2. Therefore, the area of Sail B is x^2 times greater than the area of Sail A.

Learn more about Area Multiplication here:

https://brainly.com/question/29156658

#SPJ11

**Giving away 20 points**. I need to know the arc length for EF and the area of sector EOF please:) (also plz show work thanks!!)

Answers

let us for a few seconds nevermind there's a circle at all, so we only really have a triangle by itself.

now, EF = 18, wait a second!  EF is the base of the triangle, and h = 10.725, wait a minute!!  "h" is the height of the triangle.

so, what's the area of a triangle whose base is 18 and has a height of 10.725?  yeap, we knew you'd know that one.

what's the length of the arcEF?  well, we know the central angle of ∡FOE is 80°, well, arc's get their angle measurement from the central angle they're in, so if ∡FOE is 80°, so is arcEF then.

) how many ways are there to divide a group of 10 kids into two groups of 5 to play soccer?

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Hello,

C(5,10)= 10!/(5!*(10-5)!)=36

x+2/x+8 divided by 2x/3

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the answer will be B.

frank purchased a boat for $7,525. he made a down payment of $475. he applied for a six year installment loan with an interest rate of 8.4% in the amount of $7,050. what is the total cost of the boat after six years?

Answers

Answer:

  $9474.40

Step-by-step explanation:

A spreadsheet can be used to calculate the amortization of the loan. The one attached uses rounding to the penny for all dollar amounts. The result is that the payment amount is rounded down, and the final payment is about 12¢ short. The total repaid on the loan will be slightly more than the product of payment amount ($124.99) and number of payments (72).

The total cost of the boat is the sum of down payment, loan amount, and interest amount. That sum is $9474.40.

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