Solve for x: 2 over 10 equals 3 over quantity x minus 9

Answers

Answer 1

Answer:

24

Step-by-step explanation:

2/10=3/x-9

2(x-9)=30

2x-18=30

2x=30+18

2x=48

x=24

Answer 2

Answer:

The value of x in the given phrase is 24.

Step-by-step explanation:

Given phrase,

2 over 10 equals 3 over quantity x minus 9

[tex]\frac{2}{10}=\frac{3}{x-9}[/tex]

By cross multiplication,

[tex]2x-18=30[/tex]

Adding 18 on both sides,

[tex]2x=48[/tex]

Divide both sides by 2,

[tex]x=24[/tex]

Hence, the value of x is 24.


Related Questions

I’ve been stuck on this for a while now can someone please help me out please

Answers

Step-by-step explanation:

i think its 4.2m^2+1.5n

Answer:

4.2m^2+1.5n

Step-by-step explanation:

1.7m^2 + 6.5n - 4n + 2.5m^2 - n

First, rearrange the numbers so that they can be added or subtracted with their like terms.

It would look like this:

(1.7m^2 + 2.5m^2) + (6.5n - 4n - n)

All you have to do is solve from here

this would simplify into:

4.2m^2+1.5n

Hope this helped!

(-6,5)
(-3,3)
(0,1)
what are the intercepts

Answers

Answer:

(0, 1)

Step-by-step explanation:

y-intercept: (0, y)

x-intercept: (x, 0)

Therefore the y-intercept is only (0, 1).

Angles 4 and 5 form what type of angles?



complementary angles
supplementary angles
vertical angles
obtuse angles

Answers

Answer:

the answer will be verticle angles

Step-by-step explanation:

∠4 and ∠5 form vertical angles.

What is vertical angles?

When two lines intersect each other, then non-adjacent opposite angles are called vertical angles.

Vertical angles are always equal in measurement.

If line AB and CD intersect each other at point O, ∠AOC and ∠BOD are vertical angles, similarly, ∠AOD and ∠BOC are also vertical angles.

Here lines 1 and 2 intersect each other.

So ∠4 and ∠5 are formed which are non-adjacent and opposite also.

Therefore ∠4 and ∠5 form vertical angles.

Learn more about vertical angles

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Please help me I have to turn in by 8:00

Answers

Answer:

A 2

Step-by-step explanation:

When we divide x by 9 there is some whole number we will call y plus a remainder of 4

x/9 = y  remainder 4

Writing this in fraction form

x/9 = y + 4/9

Multiplying each side by 9

9*x/9 = 9* y + 4/9 *9

x = 9y +4

Multiply each side by 2

2x = 2*(9y+4)

2x = 18y +8

Add 3 to each side

2x+3 = 18y +8+3

2x+3 = 18y +11

Divide each side by 9

(2x+3)/9 = 18y/9 +11/9

              = 2y + 9/9 +2/9

               =(2y+1 + 2/9)

  We know y is a whole number and 1 is a whole number so we can ignore 2y +1 when looking for a remainder)

2/9 is a fraction

Taking this back from fraction form to remainder from

                 (2y+1) remainder 2

which set represents the domain of function shown? {(-3,6),(0,2),(4,7),(11,15)}

Answers

Answer:

{-3,0,4,11}

Step-by-step explanation:

{(-3,6),(0,2),(4,7),(11,15)}

The domain is the input values, or x coordinates

{-3,0,4,11}

QUESTION 3

In the set of ordered pairs {(4, 7), (4, -3), (-5, -9)}, the range is:



{(4, 7), (4, -3), (-5, -9)}


{(7, 4), (-3, 4), (-9, -5)}


{-5, 4}


{-9, -3, 7

The function consists of three points, as shown in the graph below. Determine the range of the function.

graph of three points, (negative 4, negative 2), (2, 1), and (4, 1)



{-4, 2, 4}


{-2, 1}


{-2, 0, 1}


none of these

QUESTION 5

Select the table that represents the following graph.

line through the points (negative 4, 4), (negative 2, 2), (1, negative 1), (3, negative 3), and extends beyond in both directions



x y
-3 2
-1 1
0 -1
2 -3



x y
-4 3
-2 2
1 -2
3 -4






x y
-2 3
0 1
2 -3
4 -5






x y
-4 4
-2 2
1 -1
3 -3







QUESTION 6

Select the table that represents the function. f (x) = x^2 -4x



x y
-1 5
1 -3
2 -4
5 5



x y
-3 -3
-1 0
1 1
2 3






x y
-4 1
-3 2
0 3
2 4






x y
0 -5
1 -3
3 1
4 3




QUESTION 7

Which graph is represented by the following table?

x f(x)
-2 0
0 -4
1 -3
3 5




coordinate graph of a parabola that opens up with minimum at (0, negative 4) and goes through the points (5, 1) and (negative 5, 1)


coordinate graph of a parabola that opens up with minimum at (0, negative 4) and goes through the points (4, 4) and (negative 4, 4)


coordinate graph of a parabola that opens up with minimum at (0, negative 4) and goes through the points (2, 0) and (negative 2, 0)


coordinate graph of a parabola that opens up with minimum at (0, negative 4) and goes through the points (2, 4) and (negative 2, 4)


QUESTION 8

Collette’s Superstore is having a sale on desk lamps. The following graph shows the number of desk lamps left in the store t minutes after opening. How many minutes after opening will the store only have 40 desk lamps remaining?

Graph with t in minutes on the x axis and number of desk lamps remaining on the y axis. Graph shows line hitting points (0, 120), (5, 110), (10, 100), (15, 90), (20, 80), (25, 70), and (30, 60)



30 minutes


35 minutes


40 minutes


45 minutes

3 points



Answers

Answer:

see explanation

Step-by-step explanation:

The range is the set of y- values of the ordered pairs without repeats.

3

given

(4, 7), (4, - 3), (- 5, - 9)

Then the values of y are 7, - 3, - 9

hence range is { - 9, - 3, 7 }

For

(- 4, - 2), (2, 1), (4, 1)

Then the values of y are - 2, 1, 1

Hence range is { - 2, 1 }

Simplify 4(x - 3) - 2x + 9.

Answers

Answer:

2x-3

Step-by-step explanation:

4(x - 3) - 2x + 9

Distribute the 4

4x -12 -2x+9

Combine like terms

4x-2x  -12+9

2x -3

First you distribute: 4x-12-2x+9

Combine like terms: 2x-3

Final answer: 2x-3

What is the perimeter of AYXZ?
3.5 in.
5.3 in.
6.4 in.
7.8 in.

Answers

Answer:   The perimeter of ΔYXZ6.4

Answer:6.4

Step-by-step explanation:

what is the eqaution of a vertical line passing through (-5,-2)?​

Answers

Answer:

x=-5

Step-by-step explanation:

Vertical lines have the same x value all the time.  They are of the form x=

Since it passes through the point (-5,-2) the x value must be -5

x=-5

Find the length of KB¯¯¯¯¯¯¯¯+AK¯¯¯¯¯¯¯¯.
A. 28
B. 33
C. 21
D. 35

Answers

Intersecting chord rule:

DK x KB = AK x CK

12 x 4x+1 = 14 x 3+3x

Simplify:

48x +12 = 42x +42

Subtract 12 from each side:

48x = 42x + 30

Subtract 42x from each side:

6x = 30

Divide both sides by 6:

x = 5

Now find the length of KB: 4x +1 = 4(5) +1 = 20 +1 = 21

Now add KB and AK:

21 + 14 = 35

The answer is D. 35

The required length of KB(21) + AK(14) is 35. Option D is correct.

The figure is given,
where AK = 14. DK = 12, KB = 4x+1 and  KC =3+3x.
KB + AK to be determined.

What is the ratio?

The ratio can be defined as the relativeness of the fraction of one quantity towards others.

Here,
The ratio of AK: DK = KB:KC

[tex]14/12= 4x+1/3+3x\\14*(3+3x) = 12*(4x+1)\\2+42x = 48x+12\\42-12=48x-42x\\6x= 30\\x = 5[/tex]

Now,
= KA + KB
= 14 + 4x+1
= 14+ 4(5)+1
= 35

Thus, the required length of KB + AK is 35.

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Mischa wrote the quadratic equation 0 = –x2 + 4x – 7 in standard form. What is the value of c in her equation?

Answers

C is -7. Hope this helps!

Answer:

-7

Step-by-step explanation:

Mischa's equation is   -x² + 4x - 7 = 0

The standard form is ax² + bx + c = 0

c is the constant term in the quadratic equation.

If we compare terms, we find that c = -7.

Which ordered pair is a solution of this equation x-7y=-3

Answers

Answer:

-3,0

Step-by-step explanation:

this is the answer hope u like it

Solve the equation by completing the square. Round to the nearest hundredth if necessary. x^2 + 2x = 17
need the awnswer now!!

Answers

Answer:

x = -5.24 or x = 3.24

Step-by-step explanation:

[tex](a+b)^2=a^2+2ab+b^2\qquad(8)\\\\x^2+2x=17\\\\x^2+(2)(x)(1)=17\qquad\text{add}\ 1^2\ \text{to both sides}\\\\\underbrace{x^2+(2)(x)(1)+1^2}_{(*)}=17+1^2\\\\(x+1)^2=18\iff x+1=\pm\sqrt{18}\qquad\text{subtract 1 from both sides}\\\\x=-1\pm\sqrt{18}\\\\x\approx-1-4.24=-5.24\ \vee\ x\approx-1+4.24=3.24[/tex]

5(2x-3) in distributive property

Answers

The answer would be 10x-15

5 times 2x is 10x and 5 times -3 is -15

Thus, 10x-15

Answer:

The answer is (5*2x) - (5*3)

Step-by-step explanation:

You just have to multiply the coefficient by the individual numbers and variables inside the parentheses. :)

Francesca drew point (-2,-10) on the terminal ray of angle x which is in standard position she found values for the six trigonometric functions using the steps below

Answers

Answer:

She made her first error in step 3 because the sine, cosine, and tangent ratios are incorrect, which also results in incorrect cosecant, secant, and tangent functions.

Step-by-step explanation:

Francesca made her first error in step 3 because her sine, cosine, and tangent trigonometric ratio values are incorrect.

How to work with trigonometric ratios?

The correct steps to use in this regards are as follows;

Step 1;

A unit circle is shown. A ray intersects point (-2, -10) in quadrant 3. θ is the angle formed by the ray and the x-axis in quadrant 1.

Step 2;

r = √[(-2)² + (-10)²] = √104 = 2√26

Step 3;

cos θ = -2/(2√26) = -1/√26 = -(√26)/26

sin θ = -10/(2√26) =-5/√26 = -5(√26)/26

tan θ = -10/-2 = 5

sec θ = 1/sin θ = 1/-(√26)/26 = -26/√26

cosec θ = 1/cos θ = 1/-5(√26)/26 = -(√26)/5

cot θ = 1/tan θ = 1/5

Thus, Francesca made her first error in step 3 because the correct sine, cosine, and tangent ratios above differ from hers which was incorrect which lead to incorrect values of cosecant, secant, and tangent functions.

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Which expression is equivalent to (7+4i) +(8+I)?

Answers

Answer: B) 15 + 5i

Step-by-step explanation:

(7 + 4i) + (8 + i)

Add like terms: (7 + 8) + (4i + i)

Simplify: 15 + 5i.

The length of a rectangle is three times its width. The perimeter is 160 cm. What is the number of square centimeters in the area of the rectangle?

Answers

Answer:

1200 cm²

Step-by-step explanation:

width = x cm

length = 3x  cm

perimeter = 160 cm

2(x + 3x) = 160

4x = 160/2

4x = 80

x = 80/4

x = 20  cm  - width

length = 3x = 3 · 20 = 60 cm

Area = length · width = 60 · 20 = 1200 cm²

Final answer:

The rectangle's width is 20 cm and its length is 60 cm. Thus, the area of the rectangle is 1200 square centimeters.

Explanation:

We are given that the length of a rectangle is three times its width. Let's denote the width as 'w'. Consequently, the length would be '3w'.

The perimeter of a rectangle is given by the formula: 2*(length + width). Given that the perimeter is 160 cm, we can substitute our variables into the formula: 2*(w + 3w) = 160. This simplifies to 8w = 160. Therefore, the width (w) equals 20 cm, and the length is 60 cm (3w).

The area of a rectangle is calculated by multiplying its length and width. Hence, the area of our rectangle is: 60 cm * 20 cm = 1200 square centimeters.

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The sales of lawn mowers t years after a particular model is introduced is given by the function y = 5500 ln (9t + 4), where y is the number of mowers sold. How many mowers will be sold 4.5 years after a model is introduced?

Answers

Answer:

20875

Step-by-step explanation:

Given:

y = 5500 ln (9t + 4

y is number of mowers sold

t is years after a particular model is introduced

f(t)= 9t+4

How many mowers will be sold 4.5 years after a model is introduced?

t=4.5

putting t=4.5 in given function we get,

y= 5500ln(9(4.5) +4)

       = 20875.19

20875 mowers will be sold 4.5 years after a model is introduced!

I need help!!!!
Which represents the inverse of the function f(x)=4x?

Answers

Answer:

[tex]h(x)=\frac{1}{4}x[/tex].

Step-by-step explanation:

The inverse is basically you just swapping x and y.  People want to solve it for y to make it a function of x.

[tex]y=4x[/tex]

Swap x and y:

[tex]x=4y[/tex]

Now solve for y by dividing y on both sides:

[tex]\frac{x}{4}=y[/tex]

[tex]\frac{1}{4}x=y[/tex]

[tex]y=\frac{1}{4}x[/tex].

.
In which quadrants do solutions for the inequal
the inequality
[tex]y \leqslant \frac{2}{3}x - 4[/tex]
exist.


A.I, III, and IV
B.I, II, and III
C.I and IV
D.All four quadrants​

Answers

Answer:

A.I, III, and IV

Step-by-step explanation:

The slope-intercept form of an equation of a line:

[tex]y=mx+b[/tex]

m - slope

b - y-intercept → (0, b)

If m > 0, then the function is increased

If m < 0, then the function is decreased

We have

[tex]m=\dfrac{2}{3}>0[/tex] - the function is increased

[tex]b=-4[/tex] - the y-intercept is -4 → (0, -4)

Therefore the line passes through III, IV and I quadrant.

========================================

<, ≤ - shaded region below the line

>, ≥ - shaded region above the line

========================================

We have [tex]y\leq\dfrac{2}{3}x-4[/tex] → ≤ - shaded region below the line.

Therefore the inequal the inequality exist in I, III and IV quadrant.

Look at the picture.

The inequality exists in quadrants A.I, III, and IV.

The answer is option A

What is a straight line graph?

The graph follows a straight line equation shows a straight line graph.equation of a straight line is   y=mx+cy represents vertical line y-axis.x represents the horizontal line x-axis.     m is the slope of the line

            slope(m)=tan∅=y axis/x axis.

If m > 0, then the function is increased

If m < 0, then the function is decreased

=function is increased

=y-intercept is -4 = (0, -4)

    Therefor the line passes through III, IV and I quadrant.

c represents y-intercepts (it is the point at which the line cuts on the y-axis)Straight line graphs show a linear relationship between the x and y values.

     

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Are the triangles similar? if so, what postulate or theorem proves their similarity?
A. yes, by SSS Similarity Theorem
B. yes, by SAS Similarity Theorem
C. yes, by AA Similarity Theorem
D. no the triangles are not similar

Answers

The answer is A. Yes, by SSS Similarity Theorem

Answer: A. yes, by SSS Similarity Theorem

Step-by-step explanation:

From the given picture, it can be seen that we have all the sides of bothe the triangles.

SSS Similarity Theorem says that if the ratio of lengths of the corresponding sides of two triangles are then the triangles must be similar.

From the given picture , the ratio of the sides is given by :-

[tex]\dfrac{10}{35}=\dfrac{2}{7}\\\\\dfrac{12}{42}=\dfrac{2}{7}\\\\\dfrac{11}{36.5}=\dfrac{2}{7}[/tex]

Thus, the ratio of lengths of the corresponding sides of two triangles are equal.

Hence, the triangles must be similar by SSS similarity theorem.

In ∆ABC, m<A = 72 and m<B = 83. What is the measure of <C?​

Answers

Answer:

25 degrees.

Step-by-step explanation:

The 3 angles in a triangle  add up to 180 degrees therefore:

m < C = 180 - 72 - 83

=  180 - 155

= 25 degrees.

Answer:

25

Step-by-step explanation:

Theorem:

The sum of the measures of the interior angles of a triangle is 180 degrees.

The theorem is can be written as the equation below.

m<A + m<B + m<C = 180

We know the measures of angles A and B, so we substitute the values for those measures, and we solve for the measure of angle C.

72 + 83 + m<C = 180

Add like terms on the left side.

155 + m<C = 180

Subtract 155 from both sides.

m<C = 25

Answer: m<C = 25

A car wash had to make their soap last 8 days .If they only have one-seventh of a gallon of soap ,how many should they use each day so it lasts 8 days ?

Answers

Answer:

1/56 gallon

Step-by-step explanation:

The car wash has 1/7 gallons of soap and they can use 1/8th of it each day. So, you would set up [tex]\frac{1}{7}[/tex] x [tex]\frac{1}{8}[/tex] = [tex]\frac{1}{56}[/tex].

Approximately how many milligrams of sodium
remain after 8.4 years?

Answers

5.592619485929173859100MG

no your wrong its 85.2

Could you guys please help me with number 1

Answers

Answer:

Option B 6 30 am

Step-by-step explanation:

step 1

Sum all the times

(45+5+10+30+15)=115 minutes

Convert minutes to hours

we know that

60 minutes = 1 hour

so

115 minutes=60+55= 1 hour 55 minutes

Subtract 1 hour 55 minutes from 8 25 am

(8 25 am)-(1 hour 55 minutes)=(8 25 am-1 hour)-(55 minutes)

=7 25 am-55 minutes

=7 25 am-(25+30) minutes

=(725 am-25 minutes)-(30 minutes)

7 00 am-30 minutes

=6 30 am

You need to catch two different buses to get to the shops Bus 1 is due to leave at 2 o'clock and arrive at 2.30. You have a half hour wail between getting off the first bus and getting on the second bus.

Bus 2 is due to arrive at the shops at 3.15.

(a) What time is bus 2 scheduled to leave? Bus 2 leaves 15 minutes early
(b) What time does it leave? () What time does it anive?
Bus 1 is 15 minutes late.
(c) What time does it arrive?​

Answers

Answer:

rxch.ace_

Step-by-step explanation:

Final answer:

Bus 2 is scheduled to leave at 3:00 pm, but if it leaves 15 minutes early, it departs at 2:45 pm and arrives at the shops at 3:00 pm. If Bus 1 is 15 minutes late, it arrives at 2:45 pm, the same time Bus 2 leaves, preventing the transfer.

Explanation:

To solve the question regarding bus schedules and arrival times, let's break down each part of the problem step by step.

Part (a): Scheduled Departure Time of Bus 2

Bus 1 arrives at the first stop at 2:30 pm. There is a half-hour wait, so the earliest you can board Bus 2 is at 3:00 pm. Since Bus 2 arrives at the shops at 3:15 pm, and it leaves 15 minutes before its scheduled arrival time, Bus 2 is scheduled to leave at 3:00 pm.

Part (b): Bus 2 Leaves Early

Bus 2 is supposed to leave 15 minutes early. If its scheduled departure was 3:00 pm, it actually leaves at 2:45 pm. Since it leaves 15 minutes early and the travel time remains unchanged, Bus 2 would still arrive at 3:00 pm at the shops.

Part (c): Bus 1 is Late

Bus 1 is 15 minutes late. Instead of leaving at 2:00 pm, it leaves at 2:15 pm and arrives at the first stop at 2:45 pm. Since Bus 2 leaves at 2:45 pm, you would not be able to transfer from Bus 1 to Bus 2 since their arrival and departure times coincide.

Find the area of the image.​

Answers

See the attached picture:

How would you find f(-3)?

Answers

Answer:

f(-3) = 12

Step-by-step explanation:

-3 < 2; 9 + 3 = 12 [(-3)² - -3 (double negative)]; DO NOT change -3 to 3.

I hope this helps, and as always, I am joyous to assist anyone at any time.

Subtract
(6x^2 + 5) - (4x-3)

Answers

[tex](6x^2+5)-(4x-3)=6x^2+5-4x+3=6x^2-4x+8[/tex]

ANSWER B

I took the test and that was the correct answer

The graph of f(x) = |x| is transformed to g(x) = [X + 11-7. On which interval is the function decreasing?

Answers

Answer:

The interval of the decreasing function is (-∞ , -1) ⇒ g(x)

The interval of the decreasing function is (-∞ , 0) ⇒ f(x)

Step-by-step explanation:

* Lets explain how to solve it

- Decreasing function means a function with a graph that moves

 downward as it is followed from left to right.

- For example, any line with a negative slope is decreasing function

- Lets look to the attached graph to understand the meaning of the

 decreasing function

f(x) = IxI ⇒ green graph

g(x) = Ix + 1I - 7 ⇒ purple graph

- From the graph f(x) translated 1 unit to the left and 7 units down to

 form g(x)

- The domains of f(x) and g(x) are all real numbers {x : x ∈ R}

- The range of f(x) is {y : y ≥ 0}

- The range of g(x) is {y : y ≥ -7}

# For f(x)

- The slope of the green line from (-∞ , 0) is negative

- The slope of the green line from (0 , ∞) is positive

# For g(x)

- The slope of the purple line from (-∞ , -1) is negative

- The slope of the purple line from (-1 , ∞) is positive

∵ The line with negative slope represent decreasing function

The interval of the decreasing function is (-∞ , -1) ⇒ g(x)

∴ The interval of the decreasing function is (-∞ , 0) ⇒ f(x)

The function g(x) = |x+11|-7 is a transformed absolute value function, which is decreasing on the interval (-infinity, -11) due to the horizontal shift to the left by 11 units.

The question is asking about the transformation of the absolute function f(x) = |x| into a new function g(x). The function provided, g(x) = |x+11|-7, is a transformed version of f(x) where the graph has been shifted horizontally and vertically. To determine on which interval g(x) is decreasing, we need to consider the properties of the absolute value function and its transformations.

The graph of the standard absolute value function, f(x) = |x|, is shaped like a 'V', increasing for x > 0 and decreasing for x < 0. When we introduce a horizontal shift to the function (such as adding 11 to x), this shifts the vertex of the 'V' horizontally. For g(x), the graph is shifted to the left by 11 units due to the '+11' inside the absolute value. Therefore, the function will be decreasing on the interval (-infinity, -11) since the function will decrease to the left of the vertex (which is now located at x = -11). The vertical shift (subtracting 7) simply moves the graph down but does not affect the intervals of increasing or decreasing behavior.

Other Questions
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