Mathematics High School

Solve for x under the assumption that x > 0. Enter your answer in interval notation using grouping symbols.

x−24/x<10,

Answers

Answer 1
Starting with x−24/x<10 multiply everything by x. x^2-24<10x Subtract 10x from both sides. x^2-10x-24 < 0 Factor. (x-12)(x+2) < 0 (x+2) is always positive since x > 0, but (x-12) is negative when x is a value between 0 and 12. This negative value for (x-12) satisfies that the left side is less than 0. Thus the solution set for x is (0,12).
Answer 2

The solution for the set would be: x is (0,12).

What is the solution?

To arrive at the solution, we would first move the constant term to the right side as follows;

x - 24/x < 10

x < 10 + 24/x

We then multiply both sides by x to eliminate the fraction:

x² < 10x + 24

Collect all terms to one side;

x² - 10x - 24 < 0

Factorize

(x - 12)(x + 2) < 0

So, x - 12 is positive when x > 12 and negative when x < 12.

x + 2 is positive for all values of x > 0.

Related Questions

Find the least common multiple of x² + x – 12 and x² + 2x – 15.

A) (x + 4)(x - 3)(x + 5)
B) (x – 3)(x + 5)(x – 4)
C) (x – 4)(x – 3)(x – 5)
D) (x + 4)(x – 5)(x – 3),

Answers

1.(x+4)(x-3)(x+5) 
2. w+4/w-5
3.b-10/b-1

The least common multiple of x² + x – 12 and x² + 2x – 15 is (x + 4)(x – 3)(x + 5), Option A is correct.

What is quadratic equation?

A quadratic equation is a second-order polynomial equation in a single variable x , ax2+bx+c=0. with a ≠ 0 .

We need to find the least common multiple of x² + x – 12 and x² + 2x – 15.

Let us find the factor of x² + x – 12

x² + 4x -3x – 12

x(x+4)+3(x+4)

(x + 4)(x – 3)

Now let us factorize x² + 2x – 15.

x² + 5x-3x – 15.

x(x+5)-3(x+5)

(x-3)(x+5)

So, the least common multiple of x² + x – 12 and x² + 2x – 15 is (x + 4)(x – 3)(x + 5).

Hence, the least common multiple of x² + x – 12 and x² + 2x – 15 is (x + 4)(x – 3)(x + 5), Option A is correct.

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A customer buys an apple pie for $8.04, 6 cloves of garlic for $0./9 each, and a quarts of milk for $1.31. You are working the cash register. The customer gives you a $5 bill, six $1 bills, and a quarter. The register tells you that you ow the customer $0.16 . Round the price of each item to the nearest $0.10 to estimate how much the customer owes.

Answers

Round 0.30 each (or $1.80 for all 6 of them), the milk is $1.30. Total of estimates is $11.10
 
 The customer gave you 5 + 6 + 0.25 or $11.25, which is very close (and slightly higher) than the total of your estimates. I'd guess the register is correct.
 
Actual value is $8.04 + 6*0.29 + 1.31 = 8.04 + 1.74 + 1.31 = $11.09. The register is definitely correct.

Final answer:

To estimate the total cost, round each item to the nearest $0.10, sum them up, and subtract from the amount given by the customer. The estimated total cost is $9.80, and the estimated change to be returned is $1.45.

Explanation:

To estimate the total amount the customer owes after rounding to the nearest $0.10, we need to perform the following calculations:

Apple pie: $8.04, rounded to $8.00

6 cloves of garlic: $0.09 each, so $0.09 x 6 = $0.54, rounded to $0.50

Quart of milk: $1.31, rounded to $1.30

The estimated total cost is $8.00 (apple pie) + $0.50 (garlic) + $1.30 (milk) = $9.80.

The customer gives a total of $5 + $6 + $0.25 = $11.25.

Subtracting the estimated total cost from the amount given by the customer:
$11.25 - $9.80 = $1.45, which is the estimated change to be returned to the customer.

In a class, every student knows French or German (or both). 15 students know French, and 17 students know German. What is the largest possible number of students in that class?

Answers

Solution:

we are given that

In a class, every student knows French or German (or both).

15 students know French, and 17 students know German.

Suppose there are x student who knows both French and German.

Then Total number of student in the class will be [tex] (15+17-x)=32-x [/tex]

But to guess the largest possible number of student in the class we can assume x=0

Hence the largest Possible number of Student in the class=32

The sum of 3 consecutive even numbers of 78

Answers

26, 24, 28 could be the answer
x+x+2+x+4=78
3x+6=72
3x=72
x=72/3
x=24

Answer each question (5 points each). the sample space of a probability experiment is ???? = {????, ????, ????,????, ????, ????, ????, ????} and three events are ???? = {????, ????, ????,????} ???? = {????,????, ????, ????} ???? = {????, ????, ????, ????} (a) what are the outcomes in the event ???? ???????? ????? (b) what are the outcomes in the event ???? ???????? ???? ???????? ????? (c) what are the outcomes in the event ???? ???????????? ????? (d) what are the outcomes in the event ???? ???????????? ?????

Answers

D.

Hope this helps!!!!


:) :) :)

Solve the system of equations and choose the correct ordered pair. 2x + 6y = 6 3x – 2y = 20

Answers

(6,-1)
Multiply each equation by the value that makes the coefficients of xx opposite.(−3)⋅(2x+6y)=(−3)(6)(-3)⋅(2x+6y)=(-3)(6)(2)⋅(3x−2y)=(2)(20)(2)⋅(3x-2y)=(2)(20)Simplify.−6x−18y=−18-6x-18y=-186x−4y=406x-4y=40Add the two equations together to eliminate xx from the system.Divide each term by −22-22 and simplify.Tap for more steps...y=−1y=-1Substitute the value found for yy into one of the original equations, then solve for xx.Tap for more steps...x=6x=6The solution to the independent system of equations can be represented as a point.(6,−1)

Answer:

solution is (6,-1)

Step-by-step explanation:

[tex]2x + 6y = 6[/tex]

[tex]3x – 2y = 20[/tex]

WE use elimination method to solve for x  and y

Multiply the second equation by 3

[tex]3x – 2y = 20[/tex] times 3

[tex]9x – 6y = 60[/tex]

[tex]2x + 6y = 6[/tex] , add both equations

------------------------------

[tex]11x = 66[/tex]

Divide both sides by 11

[tex]x=6[/tex]

Plug in 6 for x in first equation

[tex]2x + 6y = 6[/tex]

[tex]2(6) + 6y = 6[/tex]

[tex]12 + 6y = 6[/tex], subtract 12 on both sides

[tex]6y = -6[/tex]

divide both sides by 6

[tex]y=-1[/tex]

[tex]x=6  \ and \ y= -1[/tex]

if (1+sina)(1+sinb)(1+sinc)=(1-sina)(1-sinb)(1-sinc)=k then value of k=?
a. (cosacosbcosc)
b.(sinasinbsinc)
c. (3sinasinbsinc),

Answers

k = (1+sina)(1+sinb)(1+sinc) = (1-sina)(1-sinb)(1-sinc) Multiply both entities, k x k = (1+sina)(1+sinb)(1+sinc) x (1-sina)(1-sinb)(1-sinc) That gives k^2 = (1 - sin^2a)(1 - sin^2b)(1 - sin^2c) k^2 = (cos^2a) x (cos^2b) x (cos^2c) k = sqrt ((cos^2a) x (cos^2b) x (cos^2c)) k = cosacosbcosc option a is correct.

Describe the vertical asymptotes and holes for the graph of y=x-4/x^2+3x+2,

Answers

You have a vertical asymptote at those points where the denominator is equal to zero, you have holes at those points where both the nominator and the denominator are equal to zero at the same time.

Therefore:
x - 4 = 0  
x = 4

x² + 3x + 2 = 0
(x + 2)(x + 1) = 0
x = -2 and x = -1

There are no points in which both numerator and denominator are equal to zero, therefore there are no holes, while x = -2 and x = -1 are vertical asymptotes.


A ball made out of a special material is inflated such that its diameter changes from 12inches to 15 inches. What is the approximate change in the volume of the ball?

Answers

A ball should give you the idea that we’re dealing with spheres. The volume of a sphere is:

V = (4/3) • π • r^3

The initial radius is 6 inches (radius is half of diameter)
Plug in to get its volume:

V = (4/3) • π • (6)^3

V is about 904.7787 in^3

Now do the same for the enlarged sphere, with radius 7.5 inches

V = (4/3) • π • (7.5)^3

V is about 1767.1459 in^3

To find the change, get the difference between the two volumes:

(New Volume) - (Old Volume)

1767.1459 - 904.7787

The change is around 862.3672 in^3

If x = 12.8, what is the value of 2(z - 4)? [Type your answer as a number.]
need help

Answers

If the z is supposed to be an x then the answer is 17.6

"Hope this is your question, if not I think you will, still be able to find an answer of your question based on this solution"

The expression is :

2(z-4)

so we may think that the given value is z = 12.8 instead of x=12.8, then only we can plug it in given expression.

so plugging z=12.8 in the expression:

2(12.8-4)

We will use PEMDAS rule here,

So simplifying parenthesis first,

12.8-4 = 8.8

Now multiplying the result 8.8 with 2 to get the answer,

8.8 *2 = 17.6

Answer : 2(z-4) = 17.6 for z=12.8

"hope this helps"

Which set of side lengths can form a triangle?
a. 6cm, 8cm, and 16cmB. 6cm, 8cm, and 10cmC. 6cm, 7cm, and 14cmD. 6cm, 7cm, and 20cm

Answers

the only one would be B because the rest don't follow the rules to create a triangle

Using the law of cosines, in triangle RST, if r=14 yd, s=9 yd, t=16 yd find m angle s


Help? Thank you

Answers

check the picture below.

[tex]\bf \textit{Law of Cosines}\\\\ c^2 = a^2+b^2-(2ab)cos(C)\implies c = \sqrt{a^2+b^2-(2ab)cos(C)} \\\\\\ \cfrac{a^2+b^2-c^2}{2ab}=cos(C)\implies cos^{-1}\left(\cfrac{a^2+b^2-c^2}{2ab}\right)=\measuredangle C\\\\ -------------------------------[/tex]

[tex]\bf s^2=r^2+t^2-2rt\cdot cos(S)\implies s^2-r^2-t^2=-2rt\cdot cos(S) \\\\\\ \cfrac{s^2-r^2-t^2}{-2rt}=cos(S)\implies \cfrac{r^2+t^2-s^2}{2rt}=cos(S) \\\\\\ cos^{-1}\left( \cfrac{r^2+t^2-s^2}{2rt} \right)=\measuredangle S\implies cos^{-1}\left( \cfrac{14^2+6^2-9^2}{2(14)(6)} \right)=\measuredangle S[/tex]

make sure your calculator is in Degree mode if you need ∡S in degrees.
10.05 I’m pretty sure

15 4/5% of 50

A. .79 B. 79

C. 790 D. 7.9

Answers

15 4/5 is 15.8.  The word "of" means to multiply, and of course we have to change that percent into a decimal to use it in an equation.  .158 × 50 = x is our equation.  Doing the multiplication on the left will give us our x.  x = 7.9, D from above.

"The correct answer is B. 79.

To solve the given problem, we need to calculate 15 4/5 percent of 50. First, let's convert the mixed number to an improper fraction to make the calculation easier.

 15 4/5% as a fraction is 15 + 4/5, which can be written as 75/5 + 4/5 = 79/5.

Now, to find the percentage of 50, we multiply 50 by the fraction representing the percentage:

[tex]\[ \frac{79}{5} \times 50 = \frac{79 \times 50}{5} \][/tex]

Next, we simplify the multiplication:

[tex]\[ \frac{79 \times 50}{5} = \frac{3950}{5} \][/tex]

Now, we divide 3950 by 5:

[tex]\[ \frac{3950}{5} = 790 \][/tex]

However, since we are looking for 15 4/5 percent and not 15 4/5 times 50, we need to adjust our calculation by dividing by 100 to get the correct percentage:

[tex]\[ \frac{790}{100} = 79 \][/tex]

Therefore, the final answer is B. 79."

A plane flies round-trip to Philadelphia. It flies to Philadelphia at 220 miles per hour and back home with a tailwind at 280 miles per hour. If the total trip takes 6.5 hours, how many miles does the plane fly round-trip? 560 miles 800.8 miles 1,300 miles 1,601.6 miles

Answers

 1,601.6 miles is correct

f is between e and g, EF=7 and FG=6. find EG

Answers

------- (EF)
------   (FG)
------ + ------- =
6 + 7 =
13

The measure of line segment EG is 13 cm.

Given that, F is between E and G, EF=7 and FG=6.

We need to find the measure of EG.

What is a line segment?

A line segment is a part of a line that has two endpoints and a fixed length. It is different from a line that does not have a beginning or an end and which can be extended in both directions. In this lesson, we will learn more about a line segment, its symbol, and the way to measure a line segment.

Now, EG=EF+FG

⇒EG=7+6=13 cm

Therefore, the measure of line segment EG is 13 cm.

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If exy = 3, then what is dy/dx at the point (1, ln3)?

Answers

if exy=3, then dy/dx will be found as follows:
differentiating our expression implicitly we get:
(x(dy/dx)+y)e^(xy)=0
N/B
when differentiating e^(xy) we apply chain rule. When differentiating xy, we use product rule. 
next, we substitute (1, ln(3)) and solve for dy/dx
(1(dy/dx)+ln(3))^(1ln(3))=0
((dy/dx)+ln(3))e^(ln(3))=0
but
e^(ln3)=3, this is because e and ln  are inverse of each other.

3((dy/dx)+ln(3))=0
dy/dx+ln (3)=0
dy/dx=-ln(3)
The answer is :
dy/dx=-ln(3)

In a billiards game, Pete hits a ball that is 20in. from a wall. The ball travels 34 in. until it hits the wall and bounces to a position that is 16 in. from the wall. What proportion can be used to find the distance, x, the ball traveled after it bounces off the wall to get to the ending position? CHECK ALL THAT APPLY!

options

34/x =20/16

20/16 = 34/x

16/20 = x/34

20/16 = x/34

Answers

Hello,

Using Thales, 34/x=20/16

Answer A

To find the distance the ball traveled after it bounces off the wall, we can use the proportion 34/x = 20/16, which simplifies to x = 27.2 inches.

To find the proportion that can be used to find the distance, x, the ball traveled after it bounces off the wall, we can use the equation:

34/x = 20/16

After cross multiplying, we get:

34 × 16 = 20x

Simplifying further:

544 = 20x

Dividing both sides by 20, we find:

x = 27.2

Therefore, the distance the ball traveled after it bounces off the wall is 27.2 inches.

Carlos’s credit card has an APR of 14.78% and a grace period of 18 days, and Carlos pays his balance in full every month. If his last billing cycle ended on March 28, 2010, and he made his payment on April 13, 2010, Did he owe any interest on his last statements balance?

Answers

If Carlo’s last billing cycle ended on March 28, 2010, and he made his payment on April 13, 2010, he didn’t owe any interest on his last statement's balance because he paid within the grace period. 
THE ANSWER IS ......no, because he paid within the grace period

50 POINTS!!!!!!! Soybean meal is 16% protein; cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320-lb mixture that is 14% protein?

How many pounds of cornmeal should be in the mixture?

How many pounds of soybean meal should be in the mixture?

Answers

S + C = 320 --> C = 320 -S 0.16S + 0.08C = 0.13*320 = 41.6 16S + 8C = 4160 16S + 8(320 - S) = 4160 16S + 2560 - 8S = 4160 8S + 2560 = 4160 8S = 4160 -2560 8S = 1600 S = 1600/8 = 200 200 pounds of Soybean and 120 pounds of cornmeal

Describe the graph of the following inequality: 2x - 5y ≤ 6

Answers

Final answer:

To graph the inequality 2x - 5y ≤ 6, plot the line 2x - 5y = 6 with a solid boundary, test a point to determine the solution region, and shade the region that satisfies the inequality, which is below and to the right of the boundary line.

Explanation:

To graph the inequality 2x - 5y ≤ 6, you must first draw the boundary line of the inequality. This line is created by graphing the equation 2x - 5y = 6.

Start by finding the intercepts. For the x-intercept, set y to 0 and solve for x, which gives x = 3. For the y-intercept, set x to 0 and solve for y, which gives y = -6/5. These two points can be used to draw the boundary line. Since the inequality is '≤', this line will be solid to show that points on the line satisfy the inequality.

Now you must determine which side of the line contains the solutions to the inequality. You can do this by choosing a test point that is not on the line, like (0,0). Substitute this point into the inequality: 2(0) - 5(0) ≤ 6 is true, so the area containing (0,0), which is below and to the right of the line, is the solution region. Shade this area to show all points that satisfy the inequality 2x - 5y ≤ 6.

Bars of soap come in packages of 6 and packages of 8. The 6-bar pack costs $7.86, and the 8-bar pack costs $8.88. Which is the better deal? What is the
price per bar of the better deal?

Answers

7.86 / 6 = 1.31 per unit
8.88 / 8 = 1.11 per unit

the 8-bar pack is the better deal

sum of 2x 2 + 3x - 4, 8 - 3x, and -5x 2 + 2.

Answers

 (2x² + 3x - 4) +  (8 - 3x) + (-5x² + 2)

=  2x² + 3x - 4 +  8 - 3x - 5x² + 2

= -3x² + 6

= 3(-x² + 2)

Final answer:

To sum the given polynomials, you combine like terms, resulting in the final expression of -3x^2 + 6.

Explanation:

The sum of the polynomials 2x2 + 3x - 4, 8 - 3x, and -5x2 + 2 can be found by combining like terms. This process involves adding the coefficients of terms with the same power of x.

Step 1: Identify and arrange like terms.

Terms with x2: 2x2 and -5x2Terms with x: 3x and -3xConstant terms: -4, 8, and 2

Step 2: Combine like terms.

For x2 terms: 2x2 + (-5x2) = -3x2For x terms: 3x - 3x = 0x (This term will cancel out)For constant terms: -4 + 8 + 2 = 6

Step 3: Write the sum of the polynomials.
The sum is: -3x2 + 6.

Raj is 3 years older than Zia. The sum of the squares of their ages is 369. How old are they?

Answers

Let
x--------------> ages of Raj
y--------------> age of Zia

we know that
x=y+3-------------> equation 1
x²+y²=369-----------> equation 2

I substitute 1 in 2

(y+3)²+y²=369----------> y²+6y+9+y²=369---------> 2y²+6y-360=0
2y²+6y-360=0
using a graph tool-----------> to calculate the quadratic equation
see the attached figure

the solution is
y=12
x=y+3--------> x=12+3--------> x=15

the answer is
Raj is 15 years old
Zia is 12 years old

Final answer:

Zia's age is 12 and Raj's age is 15

Explanation:

To solve this problem, we can set up two equations using the given information. Let's assume Zia's age is x. Since Raj is 3 years older than Zia, Raj's age can be represented as x + 3.

The first equation is [tex]x^2 + (x + 3)^2 = 369.[/tex]

Simplifying this equation, we get [tex]x^2 + x^2 + 6x + 9 = 369.[/tex]

Combining like terms, we have [tex]2x^2 + 6x + 9 = 369.[/tex]

Next, we can rearrange the equation by subtracting 369 from both sides and combining like terms to get [tex]2x^2 + 6x - 360 = 0.[/tex]

Now, we can solve this quadratic equation for x using factoring, completing the square, or the quadratic formula. The solutions are x = -15 and x = 12.

Since age cannot be negative, Zia's age is 12 and Raj's age is 12 + 3 = 15.

Multiple Choice
You can model the population of a certain city between 1945-2000 by the radical function P(x)=55,000 sqrt x-1945. Using this model, in which year was the population of that city 165,000?
A)1948
B)1951
C)1954
D)1957,

Answers

The answer is 1954. Letter C is correct
Solution:
If P(x) =  165,000
Then 
165,000 = 55,000(x - 1945)^(1/2)
 x= 1954

to check it, substitute x
165,000 = 55,000(1954 - 1945)^(1/2)
165,000 =165,000 

HELPP needed due today !!

Answers

1. Negative linear association

Which equation has a slope of 3 and a y intercept of 4?

A.y = 3x - 4
B.y = 3x + 4
C.y = 4x - 3
D.y = 4x + 3

Answers

the answer to this question is B

The general equation in slope intercept form is given by:

[tex] y=mx+b [/tex]

where m is the slope and b is the y intercept.

Now we are given slope as 3 and y intercept as 4, plugging these values in the slope intercept form, we get

[tex] y=3x+4 [/tex]

Now if we compare the two equations, we see that option (b) y=3x+4 matches our requirement.

So answer is the equation with slope 3 and y intercept 4 is y=3x+4.

Triangle ABC is undergoing a series of transformations. Which of the following transformations will NOT cause the resulting triangle A'B'C' to maintain congruence with triangle ABC? A. reflection over the x-axis B. translation 6 units to the right C. dilation with a scale factor of 3 D. rotation of 180 degrees clockwise

Answers

C is the correct answer
dilation will change the shape and it will not be congruent

Answer:

The image triangle compare to the pre-image triangle will be similar due to dilation.

Step-by-step explanation:

How to find the measure of an interior angle of an irregular polygon?

Answers




Exterior Angles of a Polygon Definition: the angle formed by any side of a polygon and the extension of its adjacent side Try this Adjust the polygon below by dragging any orange dot. Click on "make regular" and repeat. Note the behavior of the exterior angles and their sum. Regular polygons In the figure above check "regular". As you can see, for regular polygons all the exterior angles are the same, and like all polygons they add to 360° (see note below). So each exterior angle is 360 divided by the n, the number of sides. As a demonstration of this, drag any vertex towards the center of the polygon. You will see that the angles combine to a full 360° circle. Convex case In the case of convex polygons, where all the vertices point "outwards" away form the interior, the exterior angles are always on the outside of the polygon. In the figure above, check "regular" and notice that this is the case. Although there are two possible exterior angles at each vertex (see note below) we usually only consider one per vertex, selecting the ones that all go around in the same direction, clockwise in the figure above. Taken one per vertex in this manner, the exterior angles always add to 360° This is true no matter how many sides the polygon has, and regardless of whether it is regular or irregular, convex or concave. In the figure above, adjust the number of sides, switch to irregular and drag a vertex to see that this is true. In the figure above click on 'reset' and check "both". You will see that both angles at each vertex are always congruent (same measure). This is because they form a pair of vertical angles, which are always congruent. Drag the vertices around and convince yourself this is true. Concave case If the polygon is concave, things are a little trickier. A concave polygon has one or more vertices "pushed in" so they point towards the interior. In the figure above, uncheck "regular" and drag a vertex in towards the interior of the polygon. Notice that the exterior angle flips over into the inside of the polygon and becomes negative. If you add the exterior angles like before, they still add to 360°, you just have to remember to add the negative angles correctly. Exterior and Interior angles are supplementary At any given vertex, the interior angle is supplementary to an exterior angle. See Interior/Exterior angle relationship in a polygon. Walking the polygon In the figure above, imagine the polygon drawn on the ground. Stand on one of the sides and face along the line. Now if you walk around the polygon along each line in turn, you will eventually wind up back where you started, facing the same way. So you must have turned through a total of 360°, a full circle. This confirms that the exterior angles, taken one per vertex, add to 360° The sum of exterior angles - watch out! In most geometry textbooks they say flatly that the exterior angles of a polygon add to 360° This is only true if: You take only one per vertex, and Take all the angles that point in the same direction around the polygon. But in many cases they fail to state these conditions. In the figure at the top of the page, check the "Both" checkbox. You will see there are two per vertex and they actually add to 720° (360 times 2) So if you are asked "What is the sum of the exterior angles of a polygon?" without any conditions, you will have to guess which one they mean. Usually they mean taking one per vertex, and the answer is 360°, although strictly speaking this is wrong.

HELP!! ASAP!!!!! Which system of equations below has infinitely many solutions?
a) y = –3x + 4 and y = –3x – 4
b) y = –3x + 4 and 3y = –9x + 12
c) y = –3x + 4 and y = -1/3+ 4
d) y = –3x + 4 and y = –6x + 8

Answers

Hello,

Answer B since
(y=-3x+4)* 3==> 3y=-9x+12 which is the second equation ==>infinity many solutions.

Answer:

The correct option is B. [tex]y=-3x+4 \ \text{and}\ \ 3y=-9x+12[/tex]

Step-by-step  explanation:

Consider the two linear equation:

[tex]a_1x+b_1y+c_1=0\ \text{and}\ \ a_2x+b_2y+c_2=0[/tex]

The pair of linear equation has infinitely many solutions when:

[tex]\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}[/tex]

Now consider the option.

Option a) [tex]y=-3x+4 \ \text{and}\ \ y=-3x-4[/tex]

The above equation can be written as:

[tex]y+3x-4=0 \ \text{and}\ \ y+3x+4=0[/tex]

Therefore,

[tex]\frac{1}{1}=\frac{3}{3}\neq\frac{-4}{4}[/tex]

Thus, this pair has no solution.

Now consider the option B. [tex]y=-3x+4 \ \text{and}\ \ 3y=-9x+12[/tex]

The above equation can be written as:

[tex]y+3x-4=0 \ \text{and}\ \ 3y+9x-12=0[/tex]

Therefore,

[tex]\frac{1}{3}=\frac{3}{9}=\frac{-4}{-12}[/tex]

Thus, this pair has infinitely many solution.

Hence, the correct option is B. [tex]y=-3x+4 \ \text{and}\ \ 3y=-9x+12[/tex]

What do you ask about if you want to know the price of an item?
A. el dependiente
B. el vestido
C. el precio
D. la tienda
Please help thank you

Answers

Answer:

1. C el precio

2. C mil

3. C El abrigo y las botas cuestan doscientos dolares

4. A maya

5. C blouse


Step-by-step explanation:


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